ML20100B742: Difference between revisions

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{{#Wiki_filter:t aossA - z &l                                             w y f-u<
{{#Wiki_filter:t aossA - z &l w y f-u<
Estimate of DG Daily Air Leakaaem US W Potential Leakage Locationa5 00 20 P 4 .50 f.E                                       Leakage thru .006 orifices to seppor lines 4 Il( M EIING ., U..WiCl Leakage to sensor lines w/o .606 orifices ji j 305 cu. ft.*
Estimate of DG Daily Air Leakaaem US W Potential Leakage Locationa5 00 20 P 4.50 f.E Leakage thru.006 orifices to seppor lines 4
Leakage from vented elements in the control logic 4 Air Receiver                                     Leakage to vented solenoid valves m
Il( M EIING., U..WiCl Leakage to sensor lines w/o.606 orifices ji j 305 cu. ft.*
                                                                                                                '        i Leakage in rrttings in the 60 psig supply 4 Leakage in fittings in the 250 psig supply 4
Leakage from vented elements in the control logic 4
,      Air Comp.             Ne '
Air Receiver i
l Assume 90 F (549.6R) 7                             Supply lines to Control Air                           f l
m Leakage to vented solenoid valves Leakage in rrttings in the 60 psig supply 4 Leakage in fittings in the 250 psig supply 4
Air Comp.
Ne '
Assume 90 F (549.6R) 7 f
Supply lines to Control Air l
305 cu. ft.'
305 cu. ft.'
Air Receiver                                                                                     i l
Air Receiver l
NY..,ST.
NY..,ST. 5.,~ STAG
                                -g  5.,~ STAG Air Com p.
-g Air Com p.
Start 225 psig St:p 250 psig Estimated Air Leakage i'
Start 225 psig St:p 250 psig Estimated Air Leakage i
1 atm = 14.7 psia 225 psig = 239.7 psia = 16.3 atm. , 250 psig = 264.7 psia = 18.0 atm.
1 atm = 14.7 psia 225 psig = 239.7 psia = 16.3 atm., 250 psig = 264.7 psia = 18.0 atm.
,        ccf = standard cubic feet (at STP) ccf per tank @ 225 psig = (16.3 atm) x 305cu. ft.* x 491.6 R / 549.6 R = 4447 scf.
ccf = standard cubic feet (at STP) ccf per tank @ 225 psig = (16.3 atm) x 305cu. ft.* x 491.6 R / 549.6 R = 4447 scf.
ccf per tank @ 250 psig = (18.0 atm) x 305cu. ft.* x 491.6R / 549.6 R = 4911 scf.
ccf per tank @ 250 psig = (18.0 atm) x 305cu. ft.* x 491.6R / 549.6 R = 4911 scf.
Volume added per cycle = 464 scf Compressor capacity = 76 scfm'                                                                                     l Running time per cycle = 464 scf / 76 scfm = 6.1 minutes Assume each compressor cycles on 1 time per 8 hour shift to make up for leakage:
Volume added per cycle = 464 scf Compressor capacity = 76 scfm' Running time per cycle = 464 scf / 76 scfm = 6.1 minutes Assume each compressor cycles on 1 time per 8 hour shift to make up for leakage:
This is 6 additions of 464 scf of air per day = 2784 scfI day                                                     ;
This is 6 additions of 464 scf of air per day = 2784 scfI day
                                                                    = 116 scf / hour                                     )
= 116 scf / hour
9601220291 950919                                         = 1.93 scf / minute PDR       ADOCK 05000424 C                         PDR                             = .032 scf / second                           .        1
)
                ' NUCLEAR REGULATORY COMMIESION ooctoiwo. so.424/425 Ow,                 EXHl83lTNO. T ' 3 I
9601220291 950919
= 1.93 scf / minute PDR ADOCK 05000424 C
PDR
=.032 scf / second 1
' NUCLEAR REGULATORY COMMIESION ooctoiwo. so.424/425 Ow, EXHl83lTNO. T ' 3 I
* Data from FSAR Table 9.5.6-1 (Board Exh. #3)
* Data from FSAR Table 9.5.6-1 (Board Exh. #3)
In the matter of Georoia Kwmr Co. et al Voatie Units 1 & 2 l
In the matter of Georoia Kwmr Co. et al Voatie Units 1 & 2 l
O Staff O Applicant ETTIEenanor O oe=r O Identified @elved O Regte,d               Reporkr fD o.a. 9 / M /W           witnoc. 14 (L L mJ LJAGD}}
O Staff O Applicant ETTIEenanor O oe=r O Identified @elved O Regte,d Reporkr fD o.a. 9 / M /W witnoc.
14 (L L mJ LJAGD}}

Latest revision as of 06:06, 13 December 2024

Intervenor Exhibit I-MOSBA-261,consisting of Estimate of DG Daily Air Leakage
ML20100B742
Person / Time
Site: Vogtle  Southern Nuclear icon.png
Issue date: 09/19/1995
From:
AFFILIATION NOT ASSIGNED
To:
References
OLA-3-I-MOS-261, NUDOCS 9601220291
Download: ML20100B742 (1)


Text

t aossA - z &l w y f-u<

Estimate of DG Daily Air Leakaaem US W Potential Leakage Locationa5 00 20 P 4.50 f.E Leakage thru.006 orifices to seppor lines 4

Il( M EIING., U..WiCl Leakage to sensor lines w/o.606 orifices ji j 305 cu. ft.*

Leakage from vented elements in the control logic 4

Air Receiver i

m Leakage to vented solenoid valves Leakage in rrttings in the 60 psig supply 4 Leakage in fittings in the 250 psig supply 4

Air Comp.

Ne '

Assume 90 F (549.6R) 7 f

Supply lines to Control Air l

305 cu. ft.'

Air Receiver l

NY..,ST. 5.,~ STAG

-g Air Com p.

Start 225 psig St:p 250 psig Estimated Air Leakage i

1 atm = 14.7 psia 225 psig = 239.7 psia = 16.3 atm., 250 psig = 264.7 psia = 18.0 atm.

ccf = standard cubic feet (at STP) ccf per tank @ 225 psig = (16.3 atm) x 305cu. ft.* x 491.6 R / 549.6 R = 4447 scf.

ccf per tank @ 250 psig = (18.0 atm) x 305cu. ft.* x 491.6R / 549.6 R = 4911 scf.

Volume added per cycle = 464 scf Compressor capacity = 76 scfm' Running time per cycle = 464 scf / 76 scfm = 6.1 minutes Assume each compressor cycles on 1 time per 8 hour9.259259e-5 days <br />0.00222 hours <br />1.322751e-5 weeks <br />3.044e-6 months <br /> shift to make up for leakage:

This is 6 additions of 464 scf of air per day = 2784 scfI day

= 116 scf / hour

)

9601220291 950919

= 1.93 scf / minute PDR ADOCK 05000424 C

PDR

=.032 scf / second 1

' NUCLEAR REGULATORY COMMIESION ooctoiwo. so.424/425 Ow, EXHl83lTNO. T ' 3 I

  • Data from FSAR Table 9.5.6-1 (Board Exh. #3)

In the matter of Georoia Kwmr Co. et al Voatie Units 1 & 2 l

O Staff O Applicant ETTIEenanor O oe=r O Identified @elved O Regte,d Reporkr fD o.a. 9 / M /W witnoc.

14 (L L mJ LJAGD