ML20100B746

Intervenor Exhibit I-MOSBA-263,consisting of Amount of Water in Humid Air at 240 PSIG (17.3 Atm)

ML20100B746
Person / Time
Site:	Vogtle
Issue date:	09/19/1995
From:	AFFILIATION NOT ASSIGNED
To:
References
OLA-3-I-MOS-263, NUDOCS 9601220307
Download: ML20100B746 (2)

Text

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l . : .2 p iuosa-25s Kr.m. z-w Amount @f Water in Humid Air at D 240 PSIG (17.3 atm.) "M  :

'95 0:120 P 4 :51 ,

OFFICE 07 SECPETARY CCCKEimG a xRViCE EHANCH ii 1 cubic foot of humid air @ 240 PSIG (17.3 atm.)

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i j DeWDoint 86 F l 1.25 in. Hg.

PPM = x 10 E 6 4

V (17.3 atm. x 29.92 in. Hg./ atm.) - 1.253 in. Hg.

PPM = .0024 x 10E6 4

V 18.01 Mol Wt.

PPM = PPM x = .0024 x .62 x 10E6 = 1488 ppm water W V 29 Mol Wt.

1 Specific voi air * (1 atm) @ 86 F = 13.75 cu. ft. / #

Density of air (1 atm) g 86 F = 1/ 13.75 = .073 # / cu. ft.

4 Density of air (17.3 atm) @ 86 F = 17.3 x .073 = 1.27 # / cu. ft.

Water content = 1.27 # dry air / cu. ft. x 1488 x 10 E-6 # water / # dry air

[ = .00189 # water / cu. R. &v air

=

.030 oz. Water / cu. ft. dar cir j Dewpoint 60 F h

Specific vol air * (1 atm.) @ 60 F = 13.10 cu. ft. / #

Water Content = .522 / 1.253 x 13.75 /13.10 x .030 oz. / cu ft dry air

= .013 oz. I cu. ft. dry air

• Data from Perry's Chemical Engineers Hdbk. ,

, /s M M M COMMISSION i

' Fourth Edition EXHIBITNO. "U"

• T b Docket No. 50-424/425-Ot.A-3 9601220307 950919 in the rnatter of Georala Pr4y Co. et eL Voatie Units 1 & 2 PDR ADOCK 05000424 O Staff O Applic hnterserww O Other O PDR elved [.) ReMted Reporter 5#

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!' Amount of Watar in Humid Air at i 240 PSIG (17.3 atm.) continued ,

i j l 1 cubic foot of humid air 9 240 PSIG ( 17.3 atm. )

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Dewpoint 95 F Water content = .039 oz. / cu. ft. dry air i Dewpoint 86 F Water content = .030 oz. I cu. ft. dry air Dewpoint 60 F Water content = .013 oz. I cu. ft. dry air l

Dewpoint 50 F Water content = .009 oz. I cu ft. dry air I

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l Water condensed in cooling from 86 F to 60 F = (.030 .0130 ) oz. / cu. ft N

= .017 oz. I cu. ft. dry air l Water condensed in cooling from 95 F to 50 F = (.039 .009 ) oz. I cu. ft.

l = .030 oz. ! cu. ft. dry air f

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