ML20080G515

Procedure AP/1/A/5500/31, Estimate of Failed Fuel Based on I-131 Concentration

ML20080G515
Person / Time
Site:	Catawba
Issue date:	02/07/1984
From:	DUKE POWER CO.
To:
Shared Package
ML20080G507	List: ML20080G504 ML20080G515
References
RTR-NUREG-0737, RTR-NUREG-737, TASK-2.B.3, TASK-TM AP-1-A-5500-31, NUDOCS 8402130422
Download: ML20080G515 (8)

Text

. _ . _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ --

• Form 349h2 (8-82i O O .

PAGE NO.

CNS AP/1/A/5500/31 TABLE OF CONTENTS t

Pace No.

\

l A. Purpose 1 B. Symptoms 1 C. Immediate Actions 2 D. Subsequent Actions 2 Endosure 1 5 Enclosure 2 6 l

l L

i

. 8402130422 840207 PDR ADOCK 05000413 A PDR 7.--.-.,..._ ..

f

. 'Fortn 34913 (8 82)

Q, h PAGE NO.

CNS ESTIMATE OF FAILED FUEL AP/1/A/5500/31 BASED ON 1-131 CONCENTRATION 1 1

ACTION / EXPECTED RESPONSE RESPONSE NOT OBTAINED A. PURPOSE The purpose of this procedure is to provide a means of determining the quantity of failed fuel based on 1-131 Concentration in the NC System.

B. SYMPTOMS

1. Any of the follow;ag EMF's in alarm:

a. 1 EMF 48 " Reactor Coolant Monitor"

b. 1 EMF 18 " Reactor Coolant Filter 1 A"

c. 1 EMF 19 " Reactor Coolant Filter 1B"

2. Any condition in which the operator suspects failed fuel or * '

want an estimate of the amount of failed fuel.

I e i

3

_-.~.~....-._...---Aw

-.--~..n,-- .

-.n. .....e..,__..---,. .

. Form.34013 (8-8h I PAGE NO.

CNS ESTIMATE OF FAILED FUEL AP/1/A/5500/31 BASED ON l-131 CONCENTRATION 2 i

l RESPONSE NOT OBTAINED ACTION / EXPECTED RESPONSE C. IMMEDIATE ACTIONS

1. Have Chemistry Obtain A Sample Of The NC System Coolant and determine temperature of sample.

D. SUBSEQUENT ACTIONS

1. Have Chemistry Sample For 1-131, Krypton, Xenon, Cesium, Ruthenium And Tellurium.

2. Record Concentrations Of Above Radionuclides And Sample Temperature on Enclosure 1.

3. If I-131 Concentration is Greater Than 300 uCl/ml, Refer To RP/1/A/5000/01

, (EMERGENCY CLASS DETERMINATION).

4. If lodine is Present And The Unit is in A Normal Operational Mode, Go To 8.

5. If Krypton Or Xenon Are Present But Only Small Amounts Of Cesium And An Abnormal Transient Or Suspected Mechanical induced Failure (i.e. , Loose Part) Has Occurred, Go To 11.

6. If Krypton Or Xenon And Large Concentrations Of Cesium Are Present But Ruthenium And Tellurium Are Not And Incore Thermocouples Have Read High For A Short Period Of Time, Go To -13.

7. If All Of The Above Radionuclides Are Present And incore Thermocouples Are High For A Long Period, Go To 15.

8. Determine The X And Y Correction Factors From Enclosure 2.

r_

..w.=~ ..-.......w....-.....-- . - . . -....--%,.-..-.~. . _ . . -

' . __ _ _ - - _ _ - _ _ _ - _ _ _ _ _ . _ _ _ _ _ _ _ _ _ _ - _ _ _ _ _ _ _ _ _ _ _ . _ _ _ _ _ __._m_______. _ _ _ _ _ _ _ _ _ _ _ . _

Form.14913 (8%2) .

h .

/ PAGE No.

CNS ESTIMATE OF FAILED FUEL AP/1/A/5500/31 BASED ON 1-131 CONCENTRATION 3 ACTION / EXPECTED RESPONSE RESPONSE NOT OBTAINED

9. Calculate Tite Amount Cf Failed Fuel Using The Following:

Number of _ Measured 1-131 Failed Pins Concentration uCi/mi ' X

• Y + 3.5 x 10-3 Ci/mi

( )* *

+

Percent  : Measured 1-131 Failed Pins Concentration uCi/mi

• X *Y+ 1.8 4Ci/mi

= ( )- . .

+

10. Go To 16.

11. Determine The X And Y Correction Factors From Enclosure 2.

Calculate the , amount of failed fuel using the following:'

• Number of = Measured 1-131 2

Failed Pins Concentration uCi/mi ' X

• Y + 16.5 x 10' Cl/mi

= ( )* _ +

Percent  : Measured 1-131 Failed Pins Concentration uCi/ml

• X

• Y + 83.7 di/mi

( )* *

+

12. Go To 16.

' ~

Form'34913 (8-82) hi) ,

PAGE NO CNS ESTIMATE OF FAILED FUEL AP/1/A/5500/31 BASED ON 1-131 CONCENTRATION 4 ACTION / EXPECTED RESPONSE RESPONSE NOT OBTAINED

13. Determine The X And Y Correction Factors From Enclosure 2.

Calculate the amount of failed fuel using the following:

Number of = Measured 1-131 Failed Pins Concentration uCi/mi

• X

• Y + 2.5 + Ci/ml

= ( ) __ * +

Percent  : Measured 1-131 Failed Pins Concentration uCi/mi

• X

• Y + 1535 di/ml

( )* __,

• e

14. Go To 16.

15. Determine The X And Y Correction Factors From Enclosure 2.

Calculate the amount of failed fuel using the following:

Number of , Measured 1-131 Failed Pins Concentration uCi/mi

• X

• Y + 5.5 *Ci/ml

( )* *

+

Percent  : Measured 1-131 Failed Pins Concentration uCl/ml

• X

• Y + 2790 .uC1/mi

= ( )* *

16. Refer To Tech Spec 3.4.8 a. Refer to appropriate Tech And Ensure 1-131 Activity Spec Action Statement.

Is Within Guidelines.

17. Inform The Shift Supervisor And Performance Section Duty Engineer of The Results Of This Procedure.

-END-w --9-mem m we -~ww c-m e w e am _ n ,-,..m,.-, . . . . , . - - . .. . ,..w , . , , , , _ , ,

.s

', Ftrm 34912 (8-82) h  ;,

PAGE NO.

CNS AP/1/A/5500/31 ENCLOSUREI 5 l-131 Concentration uCi/mi uCi/ gram Concentration Initial /Date Krypton /

Xenon /

Cesium /

Ruthenium /

Tellurium /

Sample Temperature /

1 e

>"'-Wa*- p 5-***=  % 4 .%.. . . . - -  %,. _.m. .m., .,,,,,__,m,, , , . . , , , ,

---

mm--. _. _ _ _ _ _ . _ _ _ _ _ _ _ _ _ _ _ _ _ _ . . _ _ _ _ _ _ _ _ __ _

Form 14912 (6-82) *

@' @O L- 0 v + j PAGE NO.

CNS AP/1/A/5500/31 ENCLOSURE 2 6

1. X Determination NC SAMPLE TEMPERATURE F 80 90 100 100 .996 .998 1.00 150 .983 .985 .987 NC 200 .966 .968 .970 250 .945 .947 .949 System 300 .921 .923 .924 350 .894 .895 .897 Temperatu re 400 .862 .864 .865 450 .827 .828 .830

• F 500 .787 .788 .790 550 .739 .740 .741 560 .728 .729 .731 570 .717 .718 .719 580 .706 .708 .708 590 .603 .694 .695 600 .680 .681 .683

2. Y Determination if power change is less than 10% within 22 days Y= 100

% F.P. at time of failure Other times Y= 100 OP (e M)+ NP (1 - e-th y Where: .

Y = Correction Factor OP = The % Full Power Before The Power Change NP = The % Full Power After The Power Change At Which Time The Fuel Failurs Has Occured

_.3

o

. Form 349b (8-82) -

n. -

h ,',

PAGE NO.

CNS .

AP/1/A/5500/31 ENCLOSURE 2 7 I

3 = Decay Constant For I-131 --- 0.0864 day 'I t = One Half The Time To Make The Power Change Plus The Time After The Power Change Until Damage is Suspected. (in Days) i.e. 2 Hours For Power Change And 16 Hours To Damage.

t = 2 + 16 = 17 Hours = .708 Days 2

, 1 .

J

+++w.. a *. e.=.w.o== -, m

-me-m

• w- *-ee - * + = + = -* *= * -= = * * * *--N