ML17335A157
| ML17335A157 | |
| Person / Time | |
|---|---|
| Site: | Cook  |
| Issue date: | 10/13/1997 |
| From: | Feliciano A, Mccroy W INDIANA MICHIGAN POWER CO. |
| To: | |
| Shared Package | |
| ML17335A147 | List: |
| References | |
| ENSM970919AF, NUDOCS 9808100117 | |
| Download: ML17335A157 (42) | |
Text
NUCLEAR ENGINEERING DEPARTMENT Calculation Cover Sheet Cook Nuclear Plant SHEET 1 OF ~A( /(AIS1 CALCULATION No. INDIANA MZCHZGAN POWER COMPANY UNIT No. y(~/ip SAFETY RELATED NO CALCULATED BY:
DATE 7
SYSTEM 8 C /~p/
y TITLE C ~ PP Pcs+ VERIFIED BY:
DATE 4~<</iran DCP/RFC/MM/PM/PR/CR/TM No. A APPROVED BY: /o FILE LOCATION CQtsJ Q es<C / I s C CALCULATION DESCRIPTION: S zV4<
Ma Z~ cr /Zc) -W J s ~ cd W CVQ 9 4p NJ 4 ~54 s. /A-Jj'C.OK C ia C. is ZWS i+ AV"W< s.. lr 6' Z PZ NE'SHOD OF VERZFZCATZON:
4.
ALTERNATE CALCDZATZON es rm
~ CON I0//0/ f7~~
s REVZEW REVZ SION Calculated Verified Approved NO. REASON FOR CHANGE By Date By Date By Date 9808i00iiT 9'808iT PDR ADOCK 050003i5 H! PDR
Gordon C AllenQNEPPQCOOK
' DON R HAFERQNEDQAEPSC Kenneth R BakerQManagerialQCOOK Zohn Z RipakQNESMQCOOK,Gary Z ProulxQNESBQCOOK Quinton S. LiesQNESMQCOOK Bcc0 From: Paul G SchoepfQNESMQCOOK
Subject:
Calc Peer Review Date: Tuesday, October 14, 1997 23:30:19 EDT Attach:
Certify: N
'riority:
Normal Defer until:
Expires:
Forwarded by:
Ripak, Proulx and I reviewed calc ENSM970926QSL (CCW pressure gradient following a thermal barrier rupture). A CR will be written on Wednesday, and this will be a restart issue. Most comments were admin, however, there were a few that would impact the calculation result. While we don'. expect the end conclusion to change, we felt they were technical enough to warrant making it a restart issue to redo the calc.
Comments:
Ci Page
- 1. Condition Report reference not indicated on cover sheet.
- 2. Page number not listed on cover sheet.
Purpose
- 1. Purpose statement refers to CCW design pressure, however, the calculation never indicated what the design pressure is.
- 2. Purpose statement should also refer to the CR that caused the calculation to be performed.
Xnputs Should state CCW system design pressure and source, so there is a clear objective for the calculation results.
? . Inputs discuss Pressurizer Safety Valve uncertainty of is the Unit 1 value, Unit 2 is 1%), however, safety 34'which valve accumulation should also be included. Should cknowledge the difference in the uncertainties between the its, and use the more conservative one..
Calculation refers to RCP suction temperature of 541.27F and ultimately uses a "conservative" temperature of'547F. There is no basis given for either of these numbers, and why the
gl Problem:
The Westinghouse cooldown analysis uses a maximum CCW supply temperature of 120'F as an input parameter in the analysis. This parameter is a Westinghouse design basis temperature for all Westinghouse plants (see AEW-640, March 31,1969). Plant operating procedures set an operating limit of (120'F to ensure that the 120'F limit is not exceeded when instrument uncertainty is considered. Westinghouse has indicated that during normal operation the design basis CCW supply temperature is 95'F. As a result of this analysis stipulation it is necessary to evaluate the impact on the CCW pump's NPSH available. The results of this calculation are to be used to assure that the CCW pumps have adequate NPSH under the higher temperature conditions. This calculation will include instrument uncertainty for the surge tank level and CCW pump flow instrumentation. These results could potentially impact plant operating procedures and as such the results will be provided to I&C and the Operations Department for their use and implementation.
The CCW supply temperature originates from the outlet of the CCW heat exchanger. The pump circulates the fluid through the CCW heat exchanger, for cooling, prior to supplying the cooling flow to the equipment cooled by the CCW system. On this basis, the return fluid to the CCW pump suction is at a higher temperature in excess of the 120'F CCW heat exchanger outlet temperature. This calculation will evaluate the impact on the CCW pump's NPSH requirements at the design flow of 8000 gpm, and also at the maximum normal flow of 9000 gpm allowed by the plant operating procedure 1,2 OHP 4021.016.003. Additionally, the NPSH will be determined at a pump runout flow, based on extending the performance curve, of 11,000 gpm Finally, since the maximum flow is a measured parameter, an additional flow margin will be included to address flow instrument uncertainty thereby ensuring that the NPSH available exceeds the NPSH required at the maximum measured flow.
Inputs:
1- Piping configuration &om the surge tank feed line connection on the return piping to the pump suction obtained from the following isometric drawings (copy attached):
Unit 1 E CCW Pp'-CCW-35 Unit 1 W CCW Pp 1-CCW-37 1 of 2, 2 of 2 Unit 2 E CCW Pp 2-CCW-39 Unit 2 W CCW Pp 2-CCW-38 1 of 2,2 of 2 P
2- CCW pump design flow of 8000 gpm and NPSH required of 16 ft abs, 9000 gpm (maximum flow) and NPSH required 18.5 ft abs. CCW pump flow is measured by CFI-410,-420. These flow instruments are 0 to 10000 gpm full span and have the ENSM970919AF pg <of~/
AF 9/19/97
py following uncertainty associated with the flow indications were obtained from ECP WSI-15:
100 % Span +1.93% -3.76%
80% Span + 2.38% -4.68%
Based on the above a 9000 gpm flow reading will be 90% of span and the uncertainty can be determined by interpolation since at these percentages the readings are on the flat portion of the orifice curve. In this case we are only interested in the+
uncertainty since this yields a higher flow requiring a greater NPSH.
Interpolation Results 100% Span +1.93%
90% Span 10 20 x x- 1.93 .45 80% Span + 2.38%
Instrument uncertainty at 90% span, x = 1.93 + .45(10/20) = 2.16%
This results in a flow increase of 194 gpm (9000 x .0216) for a total flow 9194 gpm.
he NPSH required at this flow is 19.0 ft abs.
The NPSH requirements are all obtained from pump characteristic curve number 48839 (copy attached).
3- Resistance coefficient K for friction losses in pipe fittings obtained from Cameron Hydraulic Data Book pg. 3-111 to 3-117.
4- Pipe velocity and head loss per 100 ft flows through pipes obtained from Cameron Hydraulic Data Book pg. 3-12 to 3-31.
5- Fluid vapor pressure and temperature conversion obtained from Cameron Hydraulic Data Book pg. 4-4 to 4-5.
6- Elevation &om surge tank low level alarm 6570"; pump suction 610'- 10" results in a difference of 46.17 ft (Hg. Pump suction elevation obtained from isometric drawings 1-CCW-35 and 1-CCW-36. Low level alarm setpoint of 657'-0" (CLA-412,-413) and instrument acceptable calibration range of+/- 1" obtained from calibration procedure 12 IHP6030IMP.066. This results in a low level elevation of 656'-l 1" when accounting for instrument uncertainty of -1". Therefore, the H to account for uncertainty is 656*-11" minus 610'- 10" which results in 46.09 ft elev'ation difference.
ENSM970919AF pgg of >I AF 9/19/97
Formulas:
All formulas used are obtained from Cameron Hydraulic Data Book page numbers noted by formulas.
Hk = k (V')/2g (pg. 3-110)
I where, H- head loss through valves and fittings, ft k resistance coefficient, dimensionless V- velocity, ft/sec g- gravitational constant, 32 ft/sec'PSH'(
b(
=H H~ + H) Hr (pg 1 10)
Where, NPSH,'i,bt - net positive suction head, ft abs H, - atmospheric pressure, 34 ft H,~ - liquid vaporpressure, ft H- static head, ft H- friction losses, ft Hpl
= Lp x (hV100)
Where, H, - head loss for straight pipe length, ft L, - straightpipelength, ft (hV100) - head loss ft per 100 ft Assumptions:
1- Piping from surge tank to return header piping not included as part of this analysis.
This piping is not included since the CCW system is a closed loop cooling system.
This piping does not provided a flow path but allows for the volume change in the system inventory due to thermal effects.
2- Piping included is that from the surge tank connection on the return header to the pump suction (see marked isometric drawing).
3- Pump suction temperature of 160'F based on Westinghouse Cooldown analysis (9/15/97 copy pg. 1, 8 through 10 attached) results that indicated maximum CCW temperature of 156.4 'F. At 160'F the vapor pressure and conversion factor are 4.74 psia and 2.361 ft/psi from Cameron pg. 4-4. The vapor pressure in ft is 11.19.
4- Flow through the 14" OD is 5000 gpm based on UFSR table 9.5-2 (copy attached).
This pipe represents the return flow from one train of safety pumps and one RHR heat exchanger.
ENSM970919AF pg Cf of 21 AF 9/19/97
5- Flow through the 18" OD pipe will consists of the total flow returned to the pump of 8000gpm, 9000 gpm, and total flow due to instrument uncertainty.
6- For the runout flow of 11000 gpm it is assumed that both safeguards trains are in service. That is, both trains 14" OD pipe is in service each with a flow of 5000 gpm.
The friction loss for this arrangment is the same as the single 14" OD pipe since they are a parallel flow path.
Calculation:
Note: The friction losses required in the NPSH equation willbe determined for both units E and W CCW pps. The largest resultant friction loss will be used to bound the individual pumps NPSH available.
Unit 1 ECCW P Friction Loss at 8000 m The piping to the suction of the pump consists of a 14" and 18" diameter pipes based on I-CCW-35 starting from marked point A to B.
For the 14" OD pipe it consists of the following:
tee run, 90'R elbow, 3.5 ft, 90'R elbow, tee run, 6.23 ft, 45'lbow, 29.67 ft, t run 45'lbow, 8.34 ft, 90'R elbow, 2.33 ft, 90'R elbow, 5.5 fl, 90'R elbow, 13.5 ft, 90'R elbow, 16.17 ft, 45'lbow, 6A& ft, 45'lbow, 58.0& ft, 90'R elbow, 8.0 ft, 90'R elbow, 6.91 ft, 2 90'R elbow, 12.08 ft Based on the above the totals are determined:
176.79 ft straight pipe length, 6 90'lbows, 3 90'R elbow, 5 45'lbows, 3 t-run At 5000 gpm the velocity equals 11.86 ft/sec and the loss is 2.79 ft per 100 ft (pg. 3-26) 90'lbows k =.21 45'lbows k=.21 T-run k =.26 90'R elbow k =.39 k from pg. 3-112 & 3-113 Hpi Lp x (hl/ 1 00) = 1 76.79 x (2.79/ 1 00) = 4. 93 ft Hpo U, =.k (V')/2g = 6 x.21 x (11.86'/64.4) = 2.75 ft Hkpo,= k (V'/2g = 3 x .39 x (11.86'/64.4) = 2.56 ft Hk4s'= k (V )/2g = 5 x.21 x (11.86 /64.4) = 2.29 ft Hk = k (V )/2g = 3 ~ .26 x (11.86'/64.4) = 1.7 ft H,4>> = sum of above = 14.23 ft ENSM970919AF pg 5" of 2/
AF 9/19/97
For the 18" OD pipe it consists of the following:
tee branch, 14x18 increaser, 3.46 ft, 90'R elbow, 4.33 ft, tee branch, 2.67 ft, butterfly valve, tee branch Based on the above the totals are determined:
10.46 ft straight pipe length, 1 90'R elbow, 1 14/1S increaser, 3 T-branches, 1 butterfly valve At 8000 gpm the velocity equals 11.5 ft/sec and the loss is 1.94 ft per 100 ft (pg. 3-27) 90'R elbow k =.36 T-branch k =.72 k for diffuser = (1-(dl/d2)')'/(d1/d2)'rane 25th printing 1991 pg A-26 formula 4, butterfly valve k = .3, k from pg. 3-112 & 3-113 Hpi Lp x (hV1 00) = 10.46 x (1 .94/1 00) = .2 ft H~.,= k (V')/2g =.36 x (11.5'/64.4) =.74 ft H].,~=k (V'/2g = .3 x (11.5'/64.4) = .62 ft Hkr.] d,
= k (V')/2g = 3 x.72 x (11.5'/64.4) = 4.44 ft diffuser = (1-(d1/d2)')') /(dl/d2)' (1-(14/1 8)')' (l4/1S)' .426 Hd;h,, = k (V')/2g =.426 x (11.5'/64.4) = .S75 ft H- =sum ofabove=6.88 ft Hr = H]4" + H]s" 21 11 ft Unit I WCCW P Friction Loss at 8000 m The piping to the suction of the pump consists of a 14" and 18" diameter pipes based on 1-CCW-37 1 of 2, 2 of 2 starting from marked point A to B.
For the 14" OD pipe it consists of the following:
tee run, 6 ft, 90'R elbow, 24 ft, 90'R elbow, tee branch, 7 ft, 90'R elbow, 9.83 ft, 45'lbow, 3.18 ft, 90'R elbow, 5.18 ft, 45'lbow, 4 ft, 90'R elbow, 13 ft, 90'R elbow, 12.75 ft, 45'lbow, 21.68 ft, 45'lbow, 33.08 ft, 2 90'R elbow, 27.33 ft 1S 6 ot'l-ENSM970919AF AF 9/19/97
<ht Based on the above the totals are determined:
167.03 ft straight pipe length, 8 90'lbows, 4 45'lbows, 1 t-run, 1 t branch At 5000 gpm the velocity equals 11.86 fb'sec and the loss is 2.79 ft per 100 ft (pg. 3-26) 90'R elbows k =.21 45'lbows k=.21 T-run k =.26 T-branch k =.78 k from pg. 3-112 & 3-113 Hpi
= Lp x (hV100) = 167.03 x (2.79/100) = 4.66 A Hpp.= k (V'/2g = 8 x .21 x (11.86'/64.4) = 3.67 ft H4,. = k (V')/2g = 4 x.21 x (11.86'/64.4) = 1.83 ft HT.~ = k (V'/2g = .26 x (11.86'/64.4) = .57 ft HT.b ~ = k (V'/2g = .78 x (11.86'/64.4) = 1.7 ft H,4>> = sum of above = 12.43 ft For the 18" OD pipe it consists of the following:
tee run, 2.67 ft, 3.67 ft, 45'lbow, 4.24 ft, 90'R elbow, 4.33 A, t branch, butterfly valve 90'R elbow, 4.33 ft, tee branch. 2.75 ft, 14x18'increaser Based on the above the totals are determined:
21.99 ft straight pipe length, 2 90'R elbow, 1 45'lbow, 1 14/18 increaser, 2 T-branch, 1 T run, 1 butterfly valve At 8000 gpm the velocity equals 11.5 ft/sec and the loss is 1.94 ft per 100 ft (pg. 3-27) 90'R elbow k = .19 T-branch k = .72 k for difRser = (1-(dl/d2)')'/(d1/d2)'rane 25th printing 1991 pg A-26 formula 4, butterfly valve k ='.3, 45'lbow k =.19 Trunk=.24, k frompg.3-112 Ec3-113 Hp> Lp x (hl/1 00) = 2 1 .99 x (1 .94/1 00) = .43 ft H~.~.= k (V')/2g = 2 x.19 x (11.5'/64.4) =.78 ft Hk4s m = k (V )/2g = . 19 x (1 1.5'/64.4) = .39 ft Hk~~~y k (V )/2g 3 x (1 1 5 /64 4) 62 ft H~~~ = k (V2 )/2g = 2 x .72 x (11.5~/64.4) = 2.96 ft ENSM970919AF pSV cf at AF 9/19/97
Hqq. = k (V')/2g = .24 x (11.5'/64.4) =.49 ft diffuser = (1-(d 1/d2)')') /(dl/d2)' (1-(14/18)')' (14/18)' .426 Hd;,, = k (V )/2g =.426 x (11.5'/64.4) = .875 ft Hip>> = sum of above = 6.55 ft H, =H,4. + H- = 18.98 ft Unit 2 ECCW P Friction Loss at 8000 m The piping to the suction of the pump consists of a 14" and 18" diameter pipes based on 2-CCW-39 starting from marked point A to B.
For the 14" OD pipe it consists of the following:
tee branch, 3.5 ft, 90'R elbow, 2.91 ft, 45'lbow, tee run, 8.06 ft,45'lbow,20.83 ft, 90'R elbow, 6.58 A, 90'R elbow, 15.25 ft, 90'R elbow, 4.59 f}, 45'lbow, 78.91 ft, 45'lbow, 3.67 ft, 45'lbow, 14.16 ft, 90'R elbow, 2.83 ft Based on the above the totals are determined:
161.25 ftstraightpipe length,4 90'Relbows, 1 90'Relbow,5 45'elbows, 1 t-run, 1 t branch At 5000 gpm the velocity equals 11.86 ft/sec and the loss is 2.79 ft per 100 ft (pg. 3-26) 90'R elbows k = .21 45'lbows k=.21 T-run k = .26 90'R elbow k = .39 T branch k = .78 k from pg. 3-112 & 3-113 Hp = L, x (}IV}00)= 161.25 x(2.79/100) = 4.49 ft
~
H~.= k(V')/2g = 4 x.21 x (11.86/64.4) = 1.83 ft H~.~=k(V )/2g= .39x(11.86/64.4) =.85 ft H4,. = k (V')/2g = 5 x .21 x (11.86'/64.4) = 2.29 ft H~. = k (V')/2g = .26 x (11.86'/64.4) = .57 ft H~~ d,
= k (V )/2g = .78 x (11.86 /64.4) = 1.7 ft H,4- = sum of above = 11.73 ft ENSM970919AF pg8 o<~t AF 9/19/97
For the 18" OD pipe it consists of the following:
tee branch, 14x18 increaser, 21.5 ft, 90'R elbow, 9.91 ft, 2.16 ft, tee branch, 2.25 ft, butterfly valve, 90'R elbow, 4.33 ft, tee branch, 2.66 ft Based on the above the totals are determined:
42.81 ft straight pipe length, 1 90'R elbow, 90'R elbow,1 1 14/18 increaser, 3 T-branches, 1 butterfly valve At 8000 gpm the velocity equals 11.5 ft/sec and the loss is 1.94 ft per 100 ft (pg. 3-27) 90'R elbow k =.36 'T-branch k=.72 k for diffuser = (1-(d1/d2)')'/(dl/d2)'rane 25th printing 1991 pg A-26 formula 4, 90'R elbow k = .19, butterfly valve k = .3, k from pg. 3-112 & 3-113 Hpi Lx (hV1 00) = 42.8 1 x (1 .94/1 00) = .83 ft Hh90.s= k (V )/2g = .36 x (11.5 /64.4) = .74 ft Hpo.= k (V'/2g = .19 x (11.5'/64.4) =, .39 ft Hh~ttgggy k (V )/2g 3 x (1 1 5 /64 4) 62 ft Hkr-~ch k (V'/2g = 3 x .72 x (1 1.5'/64.4) = 4.44 ft diffuser = (1-(dl/d2)') ) /(d1/d2) = (1-(14/18) ) / (14/18) = .426 H~~ = k (V')/2g =..426 x (11.5 /64.4) =.875 ft H>> = sum of above = 7.9 ft
,Hrs =Hi4" + Hls" = 1963 ft Unit 2 WCCW P Friction Loss at 8000 m The piping to the suction of the pump consists of a 14" and 18" diameter pipes based on 2-CCW-38 1 of 2, 2 of 2 starting from marked point A to B.
For the 14" OD pipe it consists of the following:
tee branch, 7.5 ft, tee run, 90'R elbow, 22.5<<ft, 90'R elbow, 8.5 ft, 90'R elbow, 36.83 ft, 45'lbow, 2.7 ft, 45'lbow, 12.75 ft ENSM970919AF 1g 0 Ot'I AF 9/19/97
I Based on the above the totals are determined:
90.76 ft straight pipe length, 3 90'lbows, 2 45'lbows, 1 t-run, 1 t branch At 5000 gpm the velocity equals 11.86 ft/sec and the loss is 2.79 ft per 100 ft (pg. 3-26) 90'R elbows k =.21 45'lbows k=.21 T-run k =.26 T-branch k =.78 k from pg. 3-112 & 3-113 Hp) Lp x (hV100) 90 76 x (2 79/1 00) 2 53 ft 4
Hp,, = k (V'/2g = 3 x .21 x (11.86'/64.4)
= 1.38 ft H4,. = k (V')/2g = 2 x.21 x (11.86'/64.4) =.92 ft H~. = k (V')/2g = .26 x (11.86'/64.4) =.56 ft HT.b ~ = k (V')/2g = .78 x (11.86'/64.4) = 1.7 ft H,4. =sum ofabove=7.09 ft For the 18" OD pipe it consists of the following:
tee branch,14x18 increaser, 7.83 ft, 90'R elbow, 42.25 ft, 45'lbow, 3.18 ft, 90'R elbow, 33.08 ft, 90'R elbow, 5.66 ft, t branch, 3.33, 90'R elbow, butterfly valve, 90'R elbow, 4.33 A, tee branch. 2.67 ft Based on the above the totals are determined:
102.33 ft straight pipe length, 5 90'R elbow, 45'lbow, 1 1 14/18 increaser, 3 T-branch, 1 butterfly valve, At 8000 gpm the velocity equals 11.5 ft/sec and the loss is 1.94 ft per 100 ft (pg. 3-27) 90'R elbow k = .19 T-branch k = .72 k for diffuser = (1-(dl/d2)')'/(d1/d2)4 Crane 25th printing 1991 pg A-26 formula 4, butterfly valve k = .3, 45'lbow k = .19 k from pg. 3-112 & 3-113 H> = L, x (hl/100) = 102.33 x (1.94/100) = 1.99 ft H~.~ = k (V')/2g = 5 x .19 x (11.5'/64.4) = 1.95 ft Hl,4s m = k (V )/2g = .19 x (11.5'/64.4) .39
= ft H~~tt~y k (V )/2g 3 x (1 1 5 /64 4) 62 ft HkY.l,= k (V'/2g = 3 x .72 x (11.5'/64.4) = 4.44 ft ENSM970919AF pg io of 2.1 AF 9/19/97
ayp a i(,
diffuser = (1-(dl/d2) ) ) /(dl/d2)' (1-(14/18) ) / (14/18)'= .426 Hdi,~, = k (V')/2g =.426 x (11.5'/64.4) =.875 ft H- =sum ofabove= 10.27 ft Hf Hi4 + H- = 17 36 ft Determine NPSH available Based on the preceeding friction loss determinations, the Ul ECCW Pp's suction piping has the highest resistance. The resistance for this piping was detremined as 20.65 ft at 8000 gpm. Therefore, the bounding available NPSH is available Ha Hvpa Hat Hh
= 34-11.19+46.09 -21.11= 47.79 ftabs The available NPSH was determined at a fluid temperature of 160'F.
The NPSH available for the ECCW Pp will additionally be detremined at 9000 gpm and 9194 gpm.
NPSH Available at 9000 m For the 14" OD pipe it consists of the following:
tee run, 90'R elbow, 3.5 ft, 90'R elbow, tee run, 6.23 ft, 45'lbow, 29.67 ft, t run 45'lbow, 8.34 ft, 90'R elbow, 2.33 ft, 90'R elbow, 5.5 ft, 90'R elbow, 13.5 ft, 90'R elbow, 16.17 ft, 45'lbow, 6.48 ft, 45'lbow, 58.08 ft, 90'R elbow, 8.0 ft, 90'R elbow, 6.91 ft, 2 90'R elbow, 12.08 ft Based on the above the totals are determined:
176.79 ft straight pipe length, 6 90'lbows, 3 90'R elbow, 5 45'lbows, 3 t-run At 5000 gpm the velocity equals 11.86 fb'sec and the loss is 2.79 ft per 100 ft (pg. 3-26) 90'lbows k =.21 45'lbows k=.21 T-run k =.26 90'R elbow k=.39 k from pg. 3-112 8c 3-113 Hpi Lp x (hV 1 00) = 1 76.79 x (2.79/ 1 00) = 4.93 ft H~<< = k (V')/2g = 6 x.21 x (11.86'/64.4) = 2.75 ft H~.,= k (V')/2g = 3 x.39 x (11.86'/64.4) = 2.56 ft ENSM970919AF Pg 11 of >I AF 9/19/97
)t4 0
H<<>.
='
(V'/2g = 5 x .21 x (11.86'/64.4) = 2.29 ft Hkr.= k (V'/2g = 3 x .26 x (11.86'/64.4) = 1.7 ft H,4- =sumofabove=14.23 ft For the 18" OD pipe it consists of the following:
tee branch, 14x18 increaser, 3.46 ft, 90'R elbow, 4.33 ft, tee branch, 2.67 ft, butterfly valve, tee branch Based on the above the totals are determined:
10.46 ft straight pipe length, 1 90'R elbow, 1 14/18 increaser, 3 T-branches, 1 butterfly valve .
At 9000 gpm the velocity equals 12.9 ft/sec and the loss is 2.43 ft per 100 ft (pg. 3-27) 90'R elbow k =.36 T-branch k =.72 k for diffuser = (1-(dl/d2)')'/(dl/d2)'rane 25th printing 1991 pg A-26 formula 4, butterfly valve k = .3, k from pg. 3-112 & 3-113 Hpi Lp x (hl/1 00) = 1 0.46 x (2.43/1 00) = .25 ft H~.,~ = k (V')/2g =.36 x (12.9'/64.4) =.93 ft (V )/2g 3 x ( 1 2 9 /64 4) 78 HT.,~~ = k (V'/2g = 3 x .72 x (12.9'/64.4) = 5.58 ft diffuser = (I-(d 1/d2)s)s) /(dl/d2)' (1-(14/18) ) / (14/18)'= .426 H~=k (V'/2g = .426 x (12.9'/64.4) = 1.1 ft H>>- = sum of above = 8.64 ft H=H,4- + H>>" = 22.87 ft Hamldle a ~ + a fa
= 34-11.19+46.09 -22.87 = 46.03 ftabs
/
NPSH Available at 9194 m low Instrument Uncertain For the 14" OD pipe it consists of the following:
ENSM970919AF Pg1g Of 2 /
AF 9/19/97
P 1 tee run, 90'R elbow, 3.5 ft, 90'R elbow, tee run, 6.23 ft, 45'lbow, 29.67 ft, t run 45'lbow, 8.34 ft, 90'R elbow, 2.33 ft, 90'R elbow, 5.5 ft, 90'R elbow, 13.5 ft, 90'R elbow, 16.17 A, 45'lbow, 6.48 A, 45'lbow, 58.08 ft, 90'R elbow, 8.0 ft, 90'R elbow, 6.91 ft, 2 90'R elbow, 12.08 ft Based on the above the totals are determined:
176.79 ft straight pipe length, 6 90'lbows, 3 90'R elbow, 5 45'lbows, 3 t-run At 5000 gpm the velocity equals 11.86 A/sec and the loss is 2.79 it per 100 ft (pg. 3-26) 90'lbows k = .21 45'lbows k=.21 T-run k = .26 90'R elbow k = .39 k from pg. 3-112 & 3-113 Hp> Lp x (hl/I 00) = 1 76.79 x (2.79/1 00) = 4.93 ft Hkc~ ) ~ = k (V )/2g = 6 x 21 x (1 1.86 /64 4) = 2.75 ft H~.,= k (V'/2g = 3 x .39 x (11.86'/64.4) = 2.56 ft H4,. = k (V')/2g = 5 x.21 x (11.86'/64.4) = 2.29 ft H~. = k (V )/2g = 3 x .26 x (11.86 /64.4) = 1.7 ft H,4>> = sum of above = 14.23 ft For the 18" OD pipe it consists of the following:
Interpolation results for velocity and loss, values from Cameron pg 3-26 9000 12.9 2.43 9194 V L 10000 14.3 2.99 V = 13.17 ft/sec L = 2.54 tee branch, 14x18 increaser, 3.46 fl, 90'R elbow, 4.33 ft, tee branch, 2.67 ft, butterfly valve, tee branch Based on the above the totals are determined:
10.46 ft straight pipe length, 1 90'R elbow, 1 14/1 8 increaser, 3 T-branches, 1 butterfly valve At 9194 gpm the velocity equals 13.17 ft/sec and the loss is 2.54 ft per 100 ft (pg. 3-27) 90'R elbow k = .36 T-branch k = .72 k for diffuser = (1-(d1/d2)')'/(d1/d2)'rane 25th printing 1991 pg A-26 formula 4, butterfly valve k = .3, k from pg. 3-112 & 3-113 ENSM970919AF ps iz of al AF 9/19/97
siq Hp] Lp x (hl/ 00) = 1 0.46 x (2.54/1 00) =,27 ft 1
H~.,~ =- k (V')/2g =.36 x (13.17'/64 4) =.97 ft Hb=k (V')/2g =.3 x (13.17/64.4) =.81 ft Hr.b ~ = k (V'/2g = 3 x .72 x (13.17 /64.4) = 5.82 ft diffuser = (1-(d 1/d2) ) ) /(d 1/d2) = (1-(14/18) ) / (14/18) = .426 H~= k (V')/2g =.426 x (13.17'/64.4) = 1.15 ft H- =,sum ofabove=9.02 ft H, =H,4- + H- = 23.25 ft NPSH,, =H, -H + H- H,
= 34 11.19+46.09 -23.25 = 45.65 ftabs NPSH Available at 11000 m Runout Flow For the 14" OD pipe it consists of the following:
tee run, 90'R elbow, 3.5 ft, 90'R elbow, tee run, 6.23 A, 45'lbow, 29.67 ft, t run 45'lbow, 8.34 ft, 90'R elbow, 2.33 ft, 90'R elbow, 5.5 ft, 90'R elbow, 13.5 ft, 90'R elbow, 16.17 ft, 45'lbow, 6.48 ft, 45'lbow, 58.08 ft, 90'R elbow, 8.0 ft, 90'R elbow, 6.91 ft, 2 90'R elbow, 12.08 ft Based on the above the totals are determined:
176.79 ft straight pipe length, 6 90'lbows, 3 90'R elbow, 4 45'lbows, 3 t-run At 5000 gpm the velocity equals 11.86 ft/sec and the loss is 2.79 ft per 100 ft (pg. 3-26) 90'lbows k=.21 45'lbows k=.21 T-run k=.26 90'R elbow k=.39 k from pg. 3-112 & 3-113 Lp x /11/100) 176 79 x (2 79/100) 4 93 ft H~,U, = k (V')/2g = 6 x.21 x (11.86'/64.4) = 2.75 ft Hkpp;= k (V'/2g = 3 x .39 x (11.86'/64.4) = 2.56 ft H4,. = k (V')/2g = 5 x.21 x (11.86'/64.4) = 2.29 ft ENSM970919AF PS lg of AF 9/19/97
H>>.~ = k (V'/2g = 3 x .26 x (11.86'/64.4) = 1.7 ft H,4- = sum of above = 14.23 ft For the l 8" OD pipe it consists of the following:
Interpolation results for velocity and loss, values from Cameron pg 3-26 10000 14.3 2.99 11000 V L 12000 17.2 4.27 V = 15.75 ft/sec L = 3.63 tee branch, 14x18 increaser, 3 46 ft, 90'R elbow, 4.33 A, tee branch, 2.67 ft, butterfly valve, tee branch Based on the above the totals are determined:
10.46 ft straight pipe length, 1 90'R elbow, 1 14/18 increaser, 3 T-branches, 1 butterfly valve At 11000 gpm the velocity equals 15.75 A/sec and the loss is 3.63 ft per 100 ft (pg. 3-27) 90'R elbow k = .36 T-branch k = .72 k for diffuser = (1-(dl/d2)')'/(dl/d2)'rane 25th printing 1991 pg A-26 formula 4, butterfly valve k = .3, k from pg. 3-112. & 3-113 Hpi Lp x (hl/1 00) = 1 0.46 x (3.63/1 00) = .3 8 ft H~,= k (V'/2g = .36 x (15.75'/64.4) = 1.39ft Hb,~= k (V'/2g = .3 x (15.75'/64.4) = 1.16 ft H>>~~,= k (V'/2g =- 3 x .72 x (15.75'/64.4) = 8.32 ft diffuser = (1-(dl/d2)')') /(dl/d2)4 = (1-(14/18)')'/ (14/18)4 = .426 H,=k(V )/2g =.426 x(15.75'/64.4) = 1.64 ft 4
Hip>> = sum of above = 12.89 ft Hrg H)4>> + Hip> 27. 12 ft NPSH, b=H, -H~ + H- H
= 34-11.19+46.09 -27.12 = 41.78 ftabs ENSM970919AF Pg 1~ of 4 I AF 9/19/97
~ l Results:
Design Flow Maximum Flow Uncertainty Runout 8000 gpm 9000 gpm 9194 gpm 11000 gpm NPSH,, 47.79 ft abs 46.03 ft abs 45.65 ft abs 41.78 ft abs NPSHmquiM 16 ft abs 18.5 ft abs 19 ft abs 25 ft abs Margin 31.79 ft abs 27.53 ft abs 26.65 ft abs 16.78 ft abs
==
Conclusions:==
The above tabulation indicates that the available NPSH exceeds the required NPSH under the high temperature CCW conditions. Including the surge tank level and flow instrument uncertainty at the maximum normal procedural CCW flow of 9194 gpm indicates that approximately 26 ft abs of margin exist. However, the maximum flow is not a requirement of the cooldown analysis. The cooldown analysis stipulates a maximum CCW flow of 8000 gpm. Allowing for instrument uncertainty at 8000 gpm of 2.38% results in a flow of 8190 gpm. This is acceptable since the tabulation indicates that margin exist at the higher flows tabulated.
It is noted that the 9000 gpm maximum flow is stated in plant procedure 1,2 OHP 4021.016.003 (normal CCW operation). During normal plant operating conditions the CCW temperature is at the design basis number of 95'F. At this temperature, the CCW fluid temperature supplied to the pump is 114'F from the CCW heat exchanger data .
sheet. The vapor pressure is determined to be 1.25 psia or 2.91 ft. The NPSH requirements at 114'F and maximum flow of 9194 gpm during normal operation is as follows:
NPSH. i*bi.=H. -H~. + H - Hr = 34-291+4609 -23.25 = 53.93 ftabs From the above tabulation the NPSH required at 9194 gpm is 19 ft abs which yields a margin of 34.93 ft abs.
ENSM970919AF Pg lg of Al AF 9/19/97
e t 1 W~nghouse Calculation Cover Sheet P rieta Claws 2C
Title:
Cooldown Runs to Support Startup Page l of l5 project; AEp/AMp Calculation //: SAPJFSE4-AEP/AMP@102 S.O.: ANLF-280 Author/Date: Gary J. Corpora Purpose Perform single and 2-tnin own runs with RHRCOOL usuig parameters agreed upon with AEP.
Results: Both single and 2-train cooldown meet the~ldown times.
Assignment of Verifier: The individual named below is hereby assigned the responsibility of independent reviewer to verify the calculation identified above.
Name: Kenneth 'A. Gamer Minimum Extent of Verification (identified by responsible Manager):
gcA< The minimum extent of verification is idcntified as follows: (l) Verify calculation to the standards of the g u'P Westinghouse ESBU Quality Policy and Procedure Manual. specifically, Procedure WPP. l7.
ll fanager's Signature: Date:
Results of Veri6cation (brief statement by verifier);
The following brieay states how this calculation was verified:
~ Pi)tele css\I l lese $ i es~ l4 WarL r'4s/sc, a a 2
...~al.l .
Verifier's Signature: Date: cy rs-/'y-y Computer Code(s) Used in the Calcuhtion:
Program Name: RHRCOOL Issue/Rev. No.: 2.0 Coinputer Used: PC Release Letter No.: SAE/FSE-MW202, 8/26/97 Date(s) Used: 8/l2,l5/97 Properly Used: (IfNO, list restrictions/exclusions and justifications) yes Program Name: Issue/Rev. No.: Computer Release I~ No.: Date(s) Used: UsecL'roperly Used: (IfNO, list restrictions/exclusions and justifications)
This docsnnent is the property of and contains proprietary information owned by Westinghouse Electric Corporation ssnd/or its
'" '~ "ont>dence and trust, and you agree to treat this document in strict st under whichit was provided to you.
t Fax Note 7671 Lue sctric CoipoPsstioa, All Rights ReMsved W~> c Frssin+
Cn. Mps g ~r g~ qyo t IC~
Jp cer-Far>> FAX X
~
~ I e
e ~
e
4 TIIlE PACE Cooldov(n Runs to Support Startup 90f 15 PROJECT AUTHOR CHK'0. BY VERIFIED BY DATE AEPIAMP 0, J. CaponI K. N, Oa(acr
$ .0. CALC NO FILE NO. GROUP ANU -280 SAFJFSE4 AEPIAMP4I02 117-2 1.81 110.4 ~ Sl 106 6~ 159.6 142 3 112 3
~ ~ 155 7~ 300-0 5.0 114-4 2-05 104 8 1-27 105.8
~ 157 6 140.7 111 4
~ ~ 159 7 ~
~ 250.0 6.0 91.8 2.13 100.3 1.48 100.0 141.6 128.2 104.6 144 9 206.9 7.0 75.0 2.13 96-6 1.48 95.7 124.7:18.9 99.5 132.4 t 183.0 8.0 65.7 2-13 93-S 1.48 93.3 123 I 113.7 96.6 125.4 169.8 9.0 60.3 2.13 90.8 1.48 91.9 119.3 110.6 95.0 121.4 162.l 10.0 54.0 2.13 88-5 1.48 90.3 114.8 '07.1 93.0 116.7 153o2 11-0 48.9 2. 13 86.4 1.48 89.0 111.2 104.2 91,5 112.9 146-0 12.0 45.9 2.13 84.6 1 48 88.2 ~ 109.0 102.5 90.5 110.6 141.6 13.0 44.6 2.13 83.6 1.48 87.9 108.1 101.8 90.1 109.7 139.8 13.
1 ttt*ttt*tt ttttttt+t1ttt0t t*tt t @***a tel tt tt I ttt ttt tt*tfo*ht01 6 REACTOR COOLED TO 139.82 DEGREES IN 13.6 MAX Q >> 120.76 AT 4.0 HRS. HOURS'HRHX RCS FLOW Wl THROTTLED TO NEET 50.0 F/HR CRITERION STARTED THROTTLING AT 4.0 HRS, AND 350.0 DEGR.
STOPPED THROTTLING AT 6.2 HRS, AND 240.0 DEGR.
>>>>>>>>>>SW>>>>>>>>>>>>l>>>>>>a>>>> s>>>>>>>>>>>> 7t>>>> 'x>>>>>> '4>>>>>>s>>>>42>>>>>>
WESTINGHOUSE CONFIGURATION CONTROL Westinghouse Proprietary Informatian Code! RHRCOOL
,Version: 2.0 conf igurations August 1, 1997 Executions September 15, 1997 09:10>18.84 control Number: 299184S696673 Program has not yet been verifiod A record of configured versions exists in the Westinghouse Engineering Technology Configuration Control Department.
>>$ >>%>>>>>>>>>>>>O>>>>>>>>>>>>E>>C+>>>> >>%>>>> >>>>>>>> >>>>>>>>>>>>>>>>S>>>>>>C>>'h>>%>>>>
1 tt t t t*t0 t t*tt t t t t RHRCOOL PC REV 2 QQ* 0 t
- t t t t 1 t t tt t*0 t 1 t t t t t tt + t l 0 + ~ ~ . ~
SPECIAL COMMENTS cook Single Train cooldawn to Support Startup-OUTPUT CONTROL('UTPUT AT N2 HR INTERVALS( N2ll+0 BOP-FR"8( ENTER 1 (ANS 5 ~ 1 1979( ENTER 2 Xl>>lo Q REACTOR POWER, MW>> 3411.0 Ul DESIGN UA CCW HX MBTU/HR/F 4 ~ 000 U2 DESIGN UA RHR HX ~ MBTUII'HR/P 2-126 Wle RCS FLOW THROUGH ONE RHR HX( HLB/HR>> 1.,480 W6>> RHR PUMP MINZFLOW, MLB/HR>> 000 W2 CCW FLOW THROUGH ONE RHR HX( HLB/HR>> 2 '80 W3>> SW PLOW THROUGH ONE CCW HX( MLB/HR>> 3-930 W4>> CCW FLOW THROUGH ONE CCW HX, MLB/HR>> 4.000 Al,A2 AUX HEAT LOAD AT 4.00 HRS AND 20.00 HRS 5.86 5.86 C5>> RCS HEAT CAPACITY, MBTU/F>> 2.13 P= RCP POWER( HBTU/HR>> 17.40 Ti(T2>> SW TEMP AT 4 ~ OOHRS AND 20 00 HRS >> 76 00 76 '0 AUTHOR DATE CHK'0. BY DATE VERIFIED BY DATE
psc5 I is((3r(VrJoc g.rx( vd ~ i wra ice,po PAGF TITU'ooldove Runs to Support Srartup 8 of 15 PROJECT AUTHOR CHK'D. BY DATF. VERIFIED BY DATE AEPIAMP G. J. Corpora K N,Gamer S.Q. CALO NO, Fll E NO. GROUP ANLP-280 SAEIFSEC-AEPIAM P4102 FSG ttttt **tttttt**ttRHRCOOL
~ PC RE) 2 QQtttttttttt*tttkttt*tttttt*tttt*tttt -
SPECIAL COMMENTS Cook Normal Cooldown to SuPPort Startup 3411 MWt OUTPUT CONTROI ) OUTPUT AT N2 HR INTERVALS) N2>>1 ~ 0 BOP-FR 8) ENTER 1 )ANS-5 ~ 1-1979, ENTER 2 -Xl>>1) g<< REACTOR POWER, ~>> 341).0 Uli DESIGN U2= DESIGN UA CCW HX) MBTU/HR/F>>
4 000 2.126 Wl>> RCS FLOW THROUGH ONE RHR HX, MLB/HR>> 1.480 W6>> RHR PUMP MINIFLOW) MLB/HR>> .000 W2>> CCW 'FLOW THROUGH ONE RHR HX, MLB/HR>> 2.480 W3>> SW PLOW THROUGH ONE CCW HX) MLB/HR>> 3.930 W4>> CCW FLOW THROUGH ONE CCW HX, MI 8/HR~ 4)000 Al A2 AUX HEAT LOAD AT 4.00 HRS AND 20.00 HRS 5.86 3.06 CS>> RCS HEAT CAPACITY) MQTU/Ft '.13 '
RCP POWER, MBVV/HR 17.40 T1,T2 SW TEMP AT 4.00HRS AND 20.00 HRS 76.00 76 ~ 00 N3>> NUMBER OF CCW HX<< 2.
N4)t NUMBER OF RHR HX<< 2.
T7>> RCP STOP TEMP, F<< 160)00 T9>> RCS FINAL TEMP) F>> 140.00 T8>> ccW MAX TEMP BEFORE F 00 HRs) F>> 120s00 T10>> CCW MAX TEMP AFTER 8.00 HRS) F>> 120.00 X>> MAX RCS TEMP CRADIENT) F/HR>> 50 ~ 00 B4>> TIME COOLDOWN INITIATED) HR>> 4i0 83>> RCS START TEMP>> 350.0 Ll CCW HX TYPE TWO TUBE PASS <<1, COUNTERFLOW = 0 Ll L2>> g RHR HX SHELL PASSES>>
t ttt*ttttt*tttt*ltt*ttttt tt ttltt 0 tt tttt t**t1 tt t t t tt t t tt*ttt 0 1
k RHR HX INITIAL UA CORRECTION RHRHX DESICN U) BTU/HR/FTttZ/F>> 350.0
- DESIGN UA>> 2.126 RCS DESIGN FLOW >> 1 '80 CCW DESIGN FLOW >> 2.480 CORRECTED UA >> 2 '26 RCS ACTUAL FLOW << 1.480
>> 2.480 ttt*ttt*tttt***ttttttt*t**tttt tttttttttt'tttttttt*ttttttttttttgtt CCW ACTUAL FLOW tttttttttttttttttt*tttttttttttttttttttttfttttttttttt**tttttt*
~
t tt t tt*t'Attytt tt tt tt t t*tt l t t t t t*ttt t t t tt t t*t t*tt t t t*I*t*It t 0
- CCWHX DESIGN U) BTU/HR/FT* 2/P >> 328)0
- t CCW ACTUAL FLOW>> 4 000 t t ttt*ttt tt t**lt*ttt'tt t t 1t tt ~ t*t*t4 1 ttt*ttt t tt tttt t t t t t 't't t*
~
t t**tt tt t tt*tt 1 tt t tttltttt*tltt tt ttt tl*ttt t tt tttt t*tttt tt t*tt*
CCW-T EMPERAT URES t RHRHX RHRHX DECAY RCS SWOUT RHRHX CCWHX CCWHX RCOUT t RCS HEAT Uh HEAT . FLOW TEMP TOUT TIN TOUT TEMP * .TEMP BT/H BT/H/F BT/H P/H DEC F DEG F DEG F DEC F DEG F t DEG F H t 350.0 4.0 AUTHOR DATE CHK'D. BY DATE VERIFIED BY DATE DAlE J
/:&w57yp!%4(<
p) (S etc 4f L.f h ~- ~f(<I<7 (JO
PAGE I 1
Cooi...:-n ibm to Support Startup AUTHOR ~~:K'0 GY VERIFIEO BY IO af 15~OATE 0, J, Corpas I
K.N G~
CALC NO. 'LB NQ GROUP ANLF-23v SAE/FSE4.AEP/AMP@)02 FSE N3>> NUMBER OF CCW HX>> 1.
N4>> NUMBER OF RHR HX>> 1-T7>> RCP STOP TEMPi F>> 160.00 T9>> RCS FINAL TEMP, F>> 200.00 8 CCW MAX TEMP BEFORE 8.00 MRS, F 120.00 T10>> CCW MAX TEMP AFTER 8 QQ HRSi P>> 120 00 X>> MAX RCS TEMP QRADIENTi F/HR>> 50 00 84>> TIME COOLDOWN INITIATEDi HR>> 4 0 83>> RCS START TEMP>> 350.0 L1>> CCW HX TYPE, TWO TUBE PASS \, COUNTERFLOW 0 Ll L2>> P RHR HX SHEIL PASSES>> 1 ktttt*t*ttttttitttt*ttttt**tt\tt*titty ttitttjtt*tttiiiittet 1 RHR HX INITIAL UA CORRECTION RHRHX DESIGN U, BTU/HR/FTtt2/F 350.0 DESIGN UA>> 2 ~ 126 'CS DESZCN FLOW>> 1.480 k
CCW DESIGN FLOW>> 2,480 CORRECTED UA = 2 ~ 126 RCS ACTUAL FLOW >> 1<480 CCW ACTUAL FLOW >> 2.480 tt*t'IRttt**ttt*l*tttt*tttttt**itttt*l*ttttttttttte k k*t ata kk k tt*ttitittttttttttttttttti*tttit*i*tttititit*itttteieiiee
~
~ ~ *
~ S
- i k 1 i t t**t t t t t tt t t t t e ittt II *i*it t >>i t i*tt t t 1
- t t >>* I k r k t t i t k 1 t CCW HX INITIAL UA, CORRECTION CCWHX DESIGN Ui BTU/MR/FTt*2/F>> 328.0 DESIGN UA>> 4-QQQ S'W DESIGN FLOW>> 4.7:,c.
CCW DESIGN FLOW>> 4.000 CORRECTED UA >> 3.835 SV ACTUAL FLOW >> 3.930 k t t t it l*t tt*tttktt+tttttttiitttitt*kt*ttt iii t*i 1~
CCW ACTUAL FLOW >>
tit it ttitt tt*t t it t*titit tttt it it tt t tt tt t t t iiit it it itt 4.000 k
e k tits k >> +
ik t k ~ e ~ ( i CCW- TEMPE TURSS e MRHX RHRMX DECAY RCS'WOUT RHRHX CCWHX RCOUT RCS HEAT UA HEAT FLOW TEMP TOUT TIN TOUT TEMP i TEMP BT/H BT/H/P BT/H P/H DEQ F DEQ F DEQ F DEG F DRQ F ~ DEG F El 3~iC. Q 139. 6 1. 80 110,4 ~ 80 113 0 176.3
~ 156.4 120 i 0 171.5 346 5.0 139. 6 1.83 104.8 .83 113.0 176. 3 120.0 172.2
- 3)>>., 4 6~0 139.6 F 86 l00.3 .89 113.0 176.3 356 ~ 4 120.0 173.2 330.3 7.0 139.6 1.91 96 6 ~ 97 113.0 176. 3 156 ' 120.0 174.6 319 2 ~ B. Q.
139.6 1.96 93.5 1.07 l13.0 176 3 ~ 156.4 120.0 176. 3 306.4 139.7 2.03 90.8 1 23 113. 0 176. 3 156-4 120.0 ,178. 4 t 292,4 IG.Q 139.6 130.5 2 '2 2-13 88.5 86.4 1.45 113.0 176.3 1.48 110.7 l69.8 156s4 120.0 151 ~ 3 117.2 181.0 1/4.5 2 7.1 262 6 11.0 12.0 122.6 2. 13 84.6 1. 48 108.7 164.3 147.Q t14.8 168 ~ 7 i 251.5 13.0 11&.5 2 13 82.9 1 48 107.1 159.9
~ 143.6 1 a3.0 164. 1 442 8 ~ l4.0 111m& 2.13 81 4 1.48 105.9 156.5 140-9 111 ' 160.5 s 236 ~ Q 15.v 107.8 104 7 2 '3 2 13 80.1 18.8 1 48 104.9 153-8
~
1.48 104. 1 151.6 138 8 110 4 157 ~ 7 137. 1 109.4 155.4 t 23' i 226.1 16.0 17.0 102-1 2-13 77.7 1.48 103. 5 149.8 135.6 108. 6 153.5
- 222.4 lA. ~
99.9 2a13 7&.6 1.48 102.9 148. 3 134.4 108.0 151.9 219. 4 ;.9. 0 58-1 2. 13 75.5 1 48 102.4 147aQ
~ 133.4 107.4 150.5 216. 6 20.0 96.4 2.13 74.3 1.48 102.0 l45.8 132. 5 106.9 149. 3 214-4 21-0 94.9 93.6 2
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'i'ABLE COMPONENT COOLING WATER SYSTEM MINIMUM FLOW REQUIREMENTS PER TRAIN (GPM)
Serv4ce Safe uardo Train'okHAI OPfikATIOII LOCA IHJRCTIOH LOCA kfiCIRCULATIOII COttlLQ RHR Heat fixchanger 4950 4950 CCP PP Hx 31 31 SI PP Hx 20 20 ep RHR PP Hx CTS PP Hx Subtotal 5009 5009 Hiocellaneoua Train BA Bvaporator 1442 SPP 2980 42.5 42.5 Hx'aste U<<a Compreoooro Sample Cuulero (Vl/U2) 139/169< 139/169<
Pout Accident S<<mpllng Syotem'etd<un Hx< 984 984 Seal Water Heat 6xchanger 199 Ctmt. Pen. Cooling 300 300 C6Q Pan 15 Htro'CP Hotoro 404 404 Therm<<l Barrier Hxo 140 140 RCP 40 40 Reactor Support Cire Subtotal lUI/U2) 6670.5/6700.5 59/59 59/59 2248.5/2278.5 Totals {Ul/U2) 6701. 5/6'731 ~ 5 59/59 5068/5068 7257.5/7287.5 Hoteo float the uae of one oaf eguard' train. The second oef <<guard tr<<in may be placed in oervice provided the neceoaary eguipment Single train operation results in minimum oafeguard'o re<luiremento and a minimum cooldoun.
por LOCA Recirculation only one CBQ fan io reguired. An analyoio uao performed uhich determined acceptable performance <<t e reduced f lou of 15 gpm II) The 44 gpm flow io baoed on tho uoe of 3 model QC-S6) lip gpm ea.) and 1 model QC-501 (14 gp<a) uample coolero.
33 II) SPP Hx is assumed to be on the non-accident unit.
S. Theo<< flous represent the maximum flouol they may be oignificantly reduced ao necessary to control proceoo temp<<rat le Letdovn Hx lo assumed to be inaervice, The excess letdokn Hx io pl'c Hx's deuign flou rate io 2)0 gpm.
I) 9 ri. l l July, l <J>7
227200-STG-5400-02 REV. 1 PAGE 13 OF 13 Ev<<.,'Oi5) DONALD C. COOK NUCLEAR PLANT Feectie7iafi"-Awee VERIFICATION CHECKLIST CALCULATIONS Calculation Number D+ ) /
<<7 s~
Signature of Verifier Date
1.0 Basis
Mere the inputsjdraTasi'ciiirces and documented into tfie correctly selected, incorporated calculation'? Yes ~ N/A u'.0 Are assumptions necessary to perform the calculation adequately described and reasonable? Yes v N/A Basis:
3.0 Are the applicable codes, standards and regulatory requirements identified and r'equirements for design met? Yes ~N/A Basis:
4.0 Basis
Mas an appropriate design method used? Yes ~ N/A
5.0 Basis
Is the output reasonable compared to input? Yes ~ N/A 6.0 Are t5e results numerically corr'ect? Yes v N(A
'asis:
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