ML17335A157
| ML17335A157 | |
| Person / Time | |
|---|---|
| Site: | Cook  |
| Issue date: | 10/13/1997 |
| From: | Feliciano A, Mccroy W INDIANA MICHIGAN POWER CO. |
| To: | |
| Shared Package | |
| ML17335A147 | List: |
| References | |
| ENSM970919AF, NUDOCS 9808100117 | |
| Download: ML17335A157 (42) | |
Text
NUCLEAR ENGINEERING DEPARTMENT Calculation Cover Sheet Cook Nuclear Plant SHEET 1 OF ~A(
/(AIS1 CALCULATIONNo.
INDIANAMZCHZGAN POWER COMPANY SAFETY RELATED NO SYSTEM 8 C TITLE C ~ P P Pcs+
DCP/RFC/MM/PM/PR/CR/TM No.
A FILE LOCATION CQtsJ Q es<C
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C UNIT No.
CALCULATED BY:
VERIFIED BY:
APPROVED BY:
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DATE /~p/ y DATE 4~<</iran CALCULATION DESCRIPTION:
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NE'SHOD OF VERZFZCATZON:
ALTERNATE CALCDZATZON~
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NO.
REASON FOR CHANGE Calculated By REVZSION Date Verified By Date Approved By Date 9808i00iiT 9'808iT PDR ADOCK 050003i5 H!
Bcc0 From:
Subject:
Date:
Attach:
Certify:
'riority:
Defer until:
Expires:
Forwarded by:
Gordon C AllenQNEPPQCOOK DON R HAFERQNEDQAEPSC Kenneth R BakerQManagerialQCOOK Zohn Z RipakQNESMQCOOK,Gary Z ProulxQNESBQCOOK Quinton S.
LiesQNESMQCOOK Paul G SchoepfQNESMQCOOK Calc Peer Review
- Tuesday, October 14, 1997 23:30:19 EDT N
Normal
, Ripak, Proulx and I reviewed calc ENSM970926QSL (CCW pressure gradient following a thermal barrier rupture).
A CR will be written on Wednesday, and this will be a restart issue.
Most comments were admin, however, there were a few that would impact the calculation result.
While we don'. expect the end conclusion to change, we felt they were technical enough to warrant making it a restart issue to redo the calc.
Comments:
Ci Page 1.
Condition Report reference not indicated on cover sheet.
2.
Page number not listed on cover sheet.
Purpose 1.
Purpose statement refers to CCW design pressure, however, the calculation never indicated what the design pressure is.
2.
Purpose statement should also refer to the CR that caused the calculation to be performed.
Xnputs Should state CCW system design pressure and source, so there is a clear objective for the calculation results.
?.
Inputs discuss Pressurizer Safety Valve uncertainty of 34'which is the Unit 1 value, Unit 2 is 1%), however, safety valve accumulation should also be included.
Should cknowledge the difference in the uncertainties between the
- its, and use the more conservative one..
Calculation refers to RCP suction temperature of 541.27F and ultimately uses a "conservative" temperature of'547F.
There is no basis given for either of these
- numbers, and why the
gl
Problem:
The Westinghouse cooldown analysis uses a maximum CCW supply temperature of 120'F as an input parameter in the analysis.
This parameter is a Westinghouse design basis temperature for all Westinghouse plants (see AEW-640, March 31,1969).
Plant operating procedures set an operating limitof(120'F to ensure that the 120'F limitis not exceeded when instrument uncertainty is considered.
Westinghouse has indicated that during normal operation the design basis CCW supply temperature is 95'F. As a result of this analysis stipulation it is necessary to evaluate the impact on the CCW pump's NPSH available. The results ofthis calculation are to be used to assure that the CCW pumps have adequate NPSH under the higher temperature conditions.
This calculation will include instrument uncertainty for the surge tank level and CCW pump flow instrumentation.
These results could potentially impact plant operating procedures and as such the results willbe provided to I&Cand the Operations Department for their use and implementation.
The CCW supply temperature originates from the outlet ofthe CCW heat exchanger. The pump circulates the fluidthrough the CCW heat exchanger, for cooling, prior to supplying the cooling flowto the equipment cooled by the CCW system.
On this basis, the return fluidto the CCW pump suction is at a higher temperature in excess ofthe 120'F CCW heat exchanger outlet temperature.
This calculation willevaluate the impact on the CCW pump's NPSH requirements at the design flowof8000 gpm, and also at the maximum normal flowof9000 gpm allowed by the plant operating procedure 1,2 OHP 4021.016.003.
Additionally, the NPSH willbe determined at a pump runout flow, based on extending the performance curve, of 11,000 gpm Finally, since the maximum flowis a measured parameter, an additional flowmargin willbe included to address flow instrument uncertainty thereby ensuring that the NPSH available exceeds the NPSH required at the maximum measured flow.
Inputs:
1-Piping configuration &om the surge tank feed line connection on the return piping to the pump suction obtained from the followingisometric drawings (copy attached):
Unit 1 E CCW Pp'-CCW-35 Unit 1 W CCW Pp 1-CCW-37 1 of2, 2 of2 Unit 2 E CCW Pp 2-CCW-39 Unit 2 W CCW Pp 2-CCW-38 1 of2,2 of2 P
2-CCW pump design flowof 8000 gpm and NPSH required of 16 ft abs, 9000 gpm (maximum flow) and NPSH required 18.5 ft abs. CCW pump flowis measured by CFI-410,-420.
These flowinstruments are 0 to 10000 gpm fullspan and have the ENSM970919AF pg <of~/
AF 9/19/97
p y followinguncertainty associated with the flowindications were obtained from ECP WSI-15:
100 % Span 80% Span
+1.93%
+ 2.38%
-3.76%
-4.68%
Based on the above a 9000 gpm flowreading willbe 90% ofspan and the uncertainty can be determined by interpolation since at these percentages the readings are on the flat portion ofthe orifice curve. In this case we are only interested in the+
uncertainty since this yields a higher flowrequiring a greater NPSH.
Interpolation Results 100% Span 90% Span 10 20 80% Span
+1.93%
x x - 1.93
.45
+ 2.38%
Instrument uncertainty at 90% span, x = 1.93 +.45(10/20) = 2.16%
This results in a flowincrease of 194 gpm (9000 x.0216) for a total flow9194 gpm.
he NPSH required at this flowis 19.0 ft abs.
The NPSH requirements are all obtained from pump characteristic curve number 48839 (copy attached).
3-Resistance coefficient K for friction losses in pipe fittings obtained from Cameron Hydraulic Data Book pg. 3-111 to 3-117.
4-Pipe velocity and head loss per 100 ft flows through pipes obtained from Cameron Hydraulic Data Book pg. 3-12 to 3-31.
5-Fluid vapor pressure and temperature conversion obtained from Cameron Hydraulic Data Book pg. 4-4 to 4-5.
6-Elevation &om surge tank low level alarm 6570"; pump suction 610'- 10" results in a difference of46.17 ft (Hg.
Pump suction elevation obtained from isometric drawings 1-CCW-35 and 1-CCW-36. Low level alarm setpoint of657'-0" (CLA-412,-413) and instrument acceptable calibration range of+/- 1" obtained from calibration procedure 12 IHP6030IMP.066. This results in a low level elevation of 656'-l 1" when accounting for instrument uncertainty of-1". Therefore, the Hto account for uncertainty is 656*-11" minus 610'- 10" which results in 46.09 ft elev'ation difference.
ENSM970919AF pgg of >I AF 9/19/97
Formulas:
Allformulas used are obtained from Cameron Hydraulic Data Book page numbers noted by formulas.
Hk = k (V')/2g (pg. 3-110)
I where, H-head loss through valves and fittings, ft k resistance coefficient, dimensionless V-velocity, ft/sec g-gravitational constant, 32 ft/sec'PSH'(
b( = H H~ + H )
Hr (pg 1 10)
Where, NPSH,'i,bt - net positive suction head, ft abs H,
- atmospheric pressure, 34 ft H,~
- liquid vaporpressure, ft H-static head, ft H-friction losses, ft Hpl = Lp x (hV100)
Where, H, - head loss for straight pipe length, ft L, - straightpipelength, ft (hV100) - head loss ft per 100 ft Assumptions:
1-Piping from surge tank to return header piping not included as part of this analysis.
This piping is not included since the CCW system is a closed loop cooling system.
This piping does not provided a flowpath but allows for the volume change in the system inventory due to thermal effects.
2-Piping included is that from the surge tank connection on the return header to the pump suction (see marked isometric drawing).
3-Pump suction temperature of 160'F based on Westinghouse Cooldown analysis (9/15/97 copy pg. 1, 8 through 10 attached) results that indicated maximum CCW temperature of 156.4 'F. At 160'F the vapor pressure and conversion factor are 4.74 psia and 2.361 ft/psi from Cameron pg. 4-4. The vapor pressure in ft is 11.19.
4-Flow through the 14" OD is 5000 gpm based on UFSR table 9.5-2 (copy attached).
This pipe represents the return flowfrom one train ofsafety pumps and one RHR heat exchanger.
ENSM970919AF pg Cf of 21 AF 9/19/97
5-Flow through the 18" OD pipe willconsists ofthe total flowreturned to the pump of 8000gpm, 9000 gpm, and total flowdue to instrument uncertainty.
6-For the runout flowof 11000 gpm it is assumed that both safeguards trains are in service. That is, both trains 14" OD pipe is in service each with a flowof5000 gpm.
The friction loss for this arrangment is the same as the single 14" OD pipe since they are a parallel flowpath.
Calculation:
Note: The friction losses required in the NPSH equation willbe determined for both units E and W CCW pps. The largest resultant friction loss willbe used to bound the individual pumps NPSH available.
Unit 1 ECCW P Friction Loss at 8000 m
The piping to the suction ofthe pump consists ofa 14" and 18" diameter pipes based on I-CCW-35 starting from marked point A to B.
For the 14" OD pipe it consists ofthe following:
tee run, 90'R elbow, 3.5 ft, 90'R elbow, tee run, 6.23 ft, 45'lbow, 29.67 ft, t run 45'lbow, 8.34 ft, 90'R elbow, 2.33 ft, 90'R elbow, 5.5 fl,90'R elbow, 13.5 ft, 90'R elbow, 16.17 ft, 45'lbow, 6A& ft, 45'lbow, 58.0& ft, 90'R elbow, 8.0 ft, 90'R elbow, 6.91 ft, 2 90'R elbow, 12.08 ft Based on the above the totals are determined:
176.79 ftstraight pipe length, 6 90'lbows, 3 90'R elbow, 5 45'lbows, 3 t-run At5000 gpm the velocity equals 11.86 ft/sec and the loss is 2.79 ftper 100 ft (pg. 3-26) 90'lbows k =.21 45'lbows k=.21 T-run k =.26 90'R elbow k =.39 k from pg. 3-112 & 3-113 Hpi Lp x (hl/100) =
176.79 x (2.79/ 1 00) = 4.93 ft Hpo U, =.k (V')/2g = 6 x.21 x (11.86'/64.4) = 2.75 ft Hkpo,= k (V'/2g = 3 x.39 x (11.86'/64.4) = 2.56 ft Hk4s'= k (V )/2g = 5 x.21 x (11.86 /64.4) = 2.29 ft Hk
= k (V )/2g = 3 ~.26 x (11.86'/64.4) = 1.7 ft H,4>> = sum ofabove = 14.23 ft ENSM970919AF pg 5" of 2/
AF 9/19/97
For the 18" OD pipe it consists ofthe following:
tee branch, 14x18 increaser, 3.46 ft, 90'R elbow, 4.33 ft, tee branch, 2.67 ft, butterfly valve, tee branch Based on the above the totals are determined:
10.46 ft straight pipe length, 1 90'R elbow, 1 14/1S increaser, 3 T-branches, 1
butterfly valve At 8000 gpm the velocity equals 11.5 ft/sec and the loss is 1.94 ft per 100 ft (pg. 3-27) 90'R elbow k =.36 T-branch k =.72 k for diffuser = (1-(dl/d2)')'/(d1/d2)'rane 25th printing 1991 pg A-26 formula 4, butterfly valve k =.3, k from pg. 3-112 &3-113 Hpi Lp x (hV100) = 10.46 x (1.94/1 00) =.2 ft H~.,=k (V')/2g =.36 x (11.5'/64.4) =.74 ft H].,~=k (V'/2g =.3 x (11.5'/64.4) =.62 ft Hkr.]
d, = k (V')/2g = 3 x.72 x (11.5'/64.4) = 4.44 ft diffuser = (1-(d1/d2)')') /(dl/d2)'
(1-(14/1 8)')' (l4/1S)'
.426 Hd;h,,= k (V')/2g =.426 x (11.5'/64.4) =.S75 ft H- =sum ofabove=6.88 ft Hr = H]4" + H]s" 21 11 ft Unit I WCCW P Friction Loss at 8000 m
The piping to the suction ofthe pump consists ofa 14" and 18" diameter pipes based on 1-CCW-37 1 of2, 2 of 2 starting from marked point A to B.
For the 14" OD pipe it consists ofthe following:
tee run, 6 ft, 90'R elbow, 24 ft,90'R elbow, tee branch, 7 ft, 90'R elbow, 9.83 ft, 45'lbow, 3.18 ft, 90'R elbow, 5.18 ft, 45'lbow, 4 ft, 90'R elbow, 13 ft, 90'R elbow, 12.75 ft, 45'lbow, 21.68 ft, 45'lbow, 33.08 ft, 2 90'R elbow, 27.33 ft ENSM970919AF 1S 6 ot'l-AF 9/19/97
<ht Based on the above the totals are determined:
167.03 ft straight pipe length, 8 90'lbows, 4 45'lbows, 1 t-run, 1 t branch At 5000 gpm the velocity equals 11.86 fb'sec and the loss is 2.79 ftper 100 ft (pg. 3-26) 90'R elbows k =.21 45'lbows k=.21 T-run k =.26 T-branch k =.78 k from pg. 3-112 &3-113 Hpi = Lp x (hV100) = 167.03 x (2.79/100) = 4.66 A Hpp.=k (V'/2g = 8 x.21 x (11.86'/64.4) = 3.67 ft H4,. = k (V')/2g = 4 x.21 x (11.86'/64.4) = 1.83 ft HT.~ = k (V'/2g =.26 x (11.86'/64.4) =.57 ft HT.b ~ = k (V'/2g =.78 x (11.86'/64.4) = 1.7 ft H,4>> = sum ofabove = 12.43 ft For the 18" OD pipe it consists ofthe following:
tee run, 2.67 ft, 3.67 ft, 45'lbow, 4.24 ft, 90'R elbow, 4.33 A, t branch, butterfly valve 90'R elbow, 4.33 ft, tee branch. 2.75 ft, 14x18'increaser Based on the above the totals are determined:
21.99 ft straight pipe length, 2 90'R elbow, 1 45'lbow, 1 14/18 increaser, 2 T-branch, 1 T run, 1 butterfly valve At 8000 gpm the velocity equals 11.5 ft/sec and the loss is 1.94 ft per 100 ft (pg. 3-27) 90'R elbow k =.19 T-branch k =.72 k for difRser = (1-(dl/d2)')'/(d1/d2)'rane 25th printing 1991 pg A-26 formula 4, butterfly valve k ='.3, 45'lbow k =.19 Trunk=.24, k frompg.3-112 Ec3-113 Hp>
Lp x (hl/100) = 2 1.99 x (1.94/1 00) =.43 ft H~.~.= k (V')/2g = 2 x.19 x (11.5'/64.4) =.78 ft Hk4s m = k (V )/2g =. 19 x (1 1.5'/64.4) =.39 ft Hk~~~y k (V )/2g 3 x (1 1 5 /64 4) 62 ft H~~~ = k (V2 )/2g = 2 x.72 x (11.5~/64.4) = 2.96 ft ENSM970919AF pSV cf at AF 9/19/97
Hqq.
= k (V')/2g =.24 x (11.5'/64.4) =.49 ft diffuser = (1-(d 1/d2)')') /(dl/d2)'
(1-(14/18)')'
(14/18)'
.426 Hd;,, = k (V )/2g =.426 x (11.5'/64.4) =.875 ft Hip>> = sum ofabove = 6.55 ft H, =H,4. + H- =
18.98 ft Unit 2 ECCW P Friction Loss at 8000 m
The piping to the suction ofthe pump consists ofa 14" and 18" diameter pipes based on 2-CCW-39 starting from marked point A to B.
For the 14" OD pipe it consists ofthe following:
tee branch, 3.5 ft, 90'R elbow, 2.91 ft, 45'lbow, tee run, 8.06 ft,45'lbow,20.83 ft, 90'R elbow, 6.58 A,90'R elbow, 15.25 ft,90'R elbow, 4.59 f},45'lbow, 78.91 ft, 45'lbow, 3.67 ft, 45'lbow, 14.16 ft,90'R elbow, 2.83 ft Based on the above the totals are determined:
161.25 ftstraightpipe length,4 90'Relbows, 1 90'Relbow,5 45'elbows, 1 t-run, 1 t branch At 5000 gpm the velocity equals 11.86 ft/sec and the loss is 2.79 ft per 100 ft (pg. 3-26) 90'R elbows k =.21 45'lbows k=.21 T-run k =.26 90'R elbow k =.39 T branch k =.78 k from pg. 3-112 & 3-113 Hp = L, x (}IV}00)= 161.25 x(2.79/100) = 4.49 ft
~
H~.=k(V')/2g = 4 x.21 x (11.86/64.4) = 1.83 ft H~.~=k(V )/2g=.39x(11.86/64.4) =.85 ft H4,. = k (V')/2g = 5 x.21 x (11.86'/64.4) = 2.29 ft H~.
= k (V')/2g =.26 x (11.86'/64.4) =.57 ft H~~
d, = k(V )/2g =.78 x (11.86 /64.4) = 1.7 ft H,4- = sum ofabove = 11.73 ft ENSM970919AF pg8 o<~t AF 9/19/97
For the 18" OD pipe it consists ofthe following:
tee branch, 14x18 increaser, 21.5 ft, 90'R elbow, 9.91 ft, 2.16 ft, tee branch, 2.25 ft, butterfly valve, 90'R elbow, 4.33 ft, tee branch, 2.66 ft Based on the above the totals are determined:
42.81 ft straight pipe length, 1 90'R elbow, 1 90'R elbow,1 14/18 increaser, 3 T-
- branches, 1 butterfly valve At 8000 gpm the velocity equals 11.5 ft/sec and the loss is 1.94 ftper 100 ft (pg. 3-27) 90'R elbow k =.36
'T-branch k=.72 k for diffuser = (1-(d1/d2)')'/(dl/d2)'rane 25th printing 1991 pg A-26 formula 4, 90'R elbow k =.19, butterfly valve k =.3, k from pg. 3-112 &3-113 Hpi Lx(hV100) = 42.8 1 x (1.94/1 00) =.83 ft Hh90.s= k (V )/2g =.36 x (11.5 /64.4) =.74 ft Hpo.=k (V'/2g =.19 x (11.5'/64.4)
=,.39 ft Hh~ttgggy k (V )/2g 3 x ( 1 1 5 /64 4) 62 ft Hkr-~ch k (V'/2g = 3 x.72 x (1 1.5'/64.4) = 4.44 ft diffuser = (1-(dl/d2)') ) /(d1/d2)
= (1-(14/18) ) / (14/18) =.426 H~~= k (V')/2g =..426 x (11.5 /64.4) =.875 ft H>> = sum ofabove = 7.9 ft
,Hrs =Hi4" + Hls" =
1963 ft Unit 2 WCCW P Friction Loss at 8000 m
The piping to the suction ofthe pump consists ofa 14" and 18" diameter pipes based on 2-CCW-38 1 of2, 2 of 2 starting from marked point A to B.
For the 14" OD pipe it consists ofthe following:
tee branch, 7.5 ft, tee run, 90'R elbow, 22.5<<ft, 90'R elbow, 8.5 ft, 90'R elbow, 36.83 ft, 45'lbow, 2.7 ft, 45'lbow, 12.75 ft ENSM970919AF 1g 0 Ot'I AF 9/19/97
I
Based on the above the totals are determined:
90.76 ft straight pipe length, 3 90'lbows, 2 45'lbows, 1 t-run, 1 t branch At 5000 gpm the velocity equals 11.86 ft/sec and the loss is 2.79 ft per 100 ft (pg. 3-26) 90'R elbows k =.21 45'lbows k=.21 T-run k =.26 T-branch k =.78 k from pg. 3-112 &3-113 Hp)
Lp x (hV100) 90 76 x (2 79/1 00) 2 53 ft 4
Hp,,= k (V'/2g = 3 x.21 x (11.86'/64.4) = 1.38 ft H4,. = k (V')/2g = 2 x.21 x (11.86'/64.4) =.92 ft H~.
= k (V')/2g =.26 x (11.86'/64.4) =.56 ft HT.b ~ = k (V')/2g =.78 x (11.86'/64.4) = 1.7 ft H,4. =sum ofabove=7.09 ft For the 18" OD pipe it consists ofthe following:
tee branch,14x18 increaser, 7.83 ft, 90'R elbow, 42.25 ft, 45'lbow, 3.18 ft, 90'R elbow, 33.08 ft, 90'R elbow, 5.66 ft, t branch, 3.33, 90'R elbow, butterfly valve, 90'R elbow, 4.33 A, tee branch. 2.67 ft Based on the above the totals are determined:
102.33 ft straight pipe length, 5 90'R elbow, 1 45'lbow, 1 14/18 increaser, 3 T-branch, 1 butterfly valve, At 8000 gpm the velocity equals 11.5 ft/sec and the loss is 1.94 ft per 100 ft (pg. 3-27) 90'R elbow k=.19 T-branch k =.72 k for diffuser = (1-(dl/d2)')'/(d1/d2)4 Crane 25th printing 1991 pg A-26 formula 4, butterfly valve k =.3, 45'lbow k =.19 k from pg. 3-112 &3-113 H> = L, x (hl/100) = 102.33 x (1.94/100) = 1.99 ft H~.~ = k (V')/2g = 5 x.19 x (11.5'/64.4) = 1.95 ft Hl,4s m = k (V )/2g =.19 x (11.5'/64.4) =.39 ft H~~tt~y k (V )/2g 3 x ( 1 1 5 /64 4) 62 ft HkY.l,=k (V'/2g = 3 x.72 x (11.5'/64.4) = 4.44 ft ENSM970919AF pg io of 2.1 AF 9/19/97
ayp a i(,
diffuser = (1-(dl/d2) ) ) /(dl/d2)'
(1-(14/18) ) / (14/18)'=.426 Hdi,~,= k (V')/2g =.426 x (11.5'/64.4) =.875 ft H- =sum ofabove= 10.27 ft Hf Hi4 + H- =
17 36 ft Determine NPSH available Based on the preceeding friction loss determinations, the Ul ECCW Pp's suction piping has the highest resistance.
The resistance for this piping was detremined as 20.65 ft at 8000 gpm. Therefore, the bounding available NPSH is available Ha Hvpa Hat Hh
= 34-11.19+46.09
-21.11= 47.79 ftabs The available NPSH was determined at a fluid temperature of 160'F.
The NPSH available for the ECCW Pp willadditionally be detremined at 9000 gpm and 9194 gpm.
NPSH Available at 9000 m
For the 14" OD pipe it consists ofthe following:
tee run, 90'R elbow, 3.5 ft, 90'R elbow, tee run, 6.23 ft, 45'lbow, 29.67 ft, t run 45'lbow, 8.34 ft, 90'R elbow, 2.33 ft, 90'R elbow, 5.5 ft, 90'R elbow, 13.5 ft, 90'R elbow, 16.17 ft, 45'lbow, 6.48 ft, 45'lbow, 58.08 ft, 90'R elbow, 8.0 ft, 90'R elbow, 6.91 ft, 2 90'R elbow, 12.08 ft Based on the above the totals are determined:
176.79 ft straight pipe length, 6 90'lbows, 3 90'R elbow, 5 45'lbows, 3 t-run At 5000 gpm the velocity equals 11.86 fb'sec and the loss is 2.79 ftper 100 ft (pg. 3-26) 90'lbows k =.21 45'lbows k=.21 T-run k =.26 90'R elbow k=.39 k from pg. 3-112 8c 3-113 Hpi Lp x (hV1 00) =
176.79 x (2.79/ 1 00) = 4.93 ft H~<< = k (V')/2g = 6 x.21 x (11.86'/64.4) = 2.75 ft H~.,= k (V')/2g = 3 x.39 x (11.86'/64.4) = 2.56 ft ENSM970919AF Pg 11 of >I AF 9/19/97
)t4 0
H<<>.
='
(V'/2g = 5 x.21 x (11.86'/64.4) = 2.29 ft Hkr.=k (V'/2g = 3 x.26 x (11.86'/64.4) = 1.7 ft H,4- =sumofabove=14.23 ft For the 18" OD pipe it consists ofthe following:
tee branch, 14x18 increaser, 3.46 ft, 90'R elbow, 4.33 ft, tee branch, 2.67 ft, butterfly valve, tee branch Based on the above the totals are determined:
10.46 ft straight pipe length, 1 90'R elbow, 1 14/18 increaser, 3 T-branches, 1
butterfly valve At9000 gpm the velocity equals 12.9 ft/sec and the loss is 2.43 ft per 100 ft (pg. 3-27) 90'R elbow k =.36 T-branch k =.72 k for diffuser = (1-(dl/d2)')'/(dl/d2)'rane 25th printing 1991 pg A-26 formula 4, butterfly valve k =.3, k from pg. 3-112 &3-113 Hpi Lp x (hl/100) =
1 0.46 x (2.43/1 00) =.25 ft H~.,~ = k (V')/2g =.36 x (12.9'/64.4) =.93 ft (V )/2g 3 x ( 1 2 9 /64 4) 78 HT.,~~ = k (V'/2g = 3 x.72 x (12.9'/64.4) = 5.58 ft diffuser = (I-(d1/d2)s)s) /(dl/d2)'
(1-(14/18) ) / (14/18)'=.426 H~=k (V'/2g =.426 x (12.9'/64.4) = 1.1 ft H>>- = sum ofabove = 8.64 ft H=H,4- + H>>" = 22.87 ft Hamldle a
~ +
a fa
= 34-11.19+46.09
-22.87 = 46.03 ftabs
/
NPSH Available at 9194 m
low Instrument Uncertain For the 14" OD pipe it consists ofthe following:
ENSM970919AF Pg1g Of 2 /
AF 9/19/97
P 1
tee run, 90'R elbow, 3.5 ft, 90'R elbow, tee run, 6.23 ft, 45'lbow, 29.67 ft, t run 45'lbow, 8.34 ft, 90'R elbow, 2.33 ft, 90'R elbow, 5.5 ft, 90'R elbow, 13.5 ft, 90'R elbow, 16.17 A, 45'lbow, 6.48 A, 45'lbow, 58.08 ft, 90'R elbow, 8.0 ft, 90'R elbow, 6.91 ft, 2 90'R elbow, 12.08 ft Based on the above the totals are determined:
176.79 ft straight pipe length, 6 90'lbows, 3 90'R elbow, 5 45'lbows, 3 t-run At 5000 gpm the velocity equals 11.86 A/sec and the loss is 2.79 it per 100 ft (pg. 3-26) 90'lbows k =.21 45'lbows k=.21 T-run k =.26 90'R elbow k =.39 k from pg. 3-112 & 3-113 Hp>
Lp x (hl/I00) =
1 76.79 x (2.79/1 00) = 4.93 ft Hkc~ ) ~ = k (V )/2g = 6 x 21 x (1 1.86 /64 4) = 2.75 ft H~.,= k (V'/2g = 3 x.39 x (11.86'/64.4) = 2.56 ft H4,. = k (V')/2g = 5 x.21 x (11.86'/64.4) = 2.29 ft H~.
= k (V )/2g = 3 x.26 x (11.86 /64.4) = 1.7 ft H,4>> = sum ofabove = 14.23 ft For the 18" OD pipe it consists ofthe following:
Interpolation results for velocity and loss, values from Cameron pg 3-26 9000 12.9 9194 V
10000 14.3 2.43 L
2.99 V = 13.17 ft/sec L = 2.54 tee branch, 14x18 increaser, 3.46 fl,90'R elbow, 4.33 ft, tee branch, 2.67 ft, butterfly valve, tee branch Based on the above the totals are determined:
10.46 ft straight pipe length, 1 90'R elbow, 1 14/1 8 increaser, 3 T-branches, 1
butterfly valve At 9194 gpm the velocity equals 13.17 ft/sec and the loss is 2.54 ftper 100 ft (pg. 3-27) 90'R elbow k =.36 T-branch k =.72 k for diffuser = (1-(d1/d2)')'/(d1/d2)'rane 25th printing 1991 pg A-26 formula 4, butterfly valve k =.3, k from pg. 3-112 &3-113 ENSM970919AF ps iz of al AF 9/19/97
siq
Hp]
Lp x (hl/ 1 00) =
1 0.46 x (2.54/1 00) =,27 ft H~.,~ =- k (V')/2g =.36 x (13.17'/64 4) =.97 ft Hb=k (V')/2g =.3 x (13.17/64.4) =.81 ft Hr.b ~ = k (V'/2g = 3 x.72 x (13.17 /64.4) = 5.82 ft diffuser = (1-(d 1/d2) ) ) /(d 1/d2)
(1-(14/18) ) / (14/18) =.426 H~= k (V')/2g =.426 x (13.17'/64.4) = 1.15 ft H- =,sum ofabove=9.02 ft H, =H,4- + H-
23.25 ft NPSH,, =H, -H
+ H-H,
= 34 11.19+46.09
-23.25 = 45.65 ftabs NPSH Available at 11000 m Runout Flow For the 14" OD pipe it consists ofthe following:
tee run, 90'R elbow, 3.5 ft, 90'R elbow, tee run, 6.23 A, 45'lbow, 29.67 ft, t run 45'lbow, 8.34 ft, 90'R elbow, 2.33 ft,90'R elbow, 5.5 ft, 90'R elbow, 13.5 ft, 90'R elbow, 16.17 ft, 45'lbow, 6.48 ft, 45'lbow, 58.08 ft, 90'R elbow, 8.0 ft, 90'R elbow, 6.91 ft, 2 90'R elbow, 12.08 ft Based on the above the totals are determined:
176.79 ft straight pipe length, 6 90'lbows, 3 90'R elbow, 4 45'lbows, 3 t-run At5000 gpm the velocity equals 11.86 ft/sec and the loss is 2.79 ft per 100 ft (pg. 3-26) 90'lbows k=.21 45'lbows k=.21 T-run k=.26 90'R elbow k=.39 k from pg. 3-112 &3-113 Lp x /11/100) 176 79 x (2 79/100) 4 93 ft H~,U, = k (V')/2g = 6 x.21 x (11.86'/64.4) = 2.75 ft Hkpp;= k (V'/2g = 3 x.39 x (11.86'/64.4) = 2.56 ft H4,. = k (V')/2g = 5 x.21 x (11.86'/64.4) = 2.29 ft ENSM970919AF PS lg of AF 9/19/97
H>>.~ = k (V'/2g = 3 x.26 x (11.86'/64.4) = 1.7 ft H,4- = sum ofabove = 14.23 ft For the l 8" OD pipe it consists ofthe following:
Interpolation results for velocity and loss, values from Cameron pg 3-26 10000 14.3 11000 V
12000 17.2 2.99 L
4.27 V= 15.75 ft/sec L = 3.63 tee branch, 14x18 increaser, 3 46 ft, 90'R elbow, 4.33 A, tee branch, 2.67 ft, butterfly valve, tee branch Based on the above the totals are determined:
10.46 ft straight pipe length, 1 90'R elbow, 1 14/18 increaser, 3 T-branches, 1
butterfly valve At 11000 gpm the velocity equals 15.75 A/sec and the loss is 3.63 ft per 100 ft(pg. 3-27) 90'R elbow k =.36 T-branch k =.72 k for diffuser = (1-(dl/d2)')'/(dl/d2)'rane 25th printing 1991 pg A-26 formula 4, butterfly valve k =.3, k from pg. 3-112. &3-113 Hpi Lp x (hl/1 00) =
1 0.46 x (3.63/1 00) =.3 8 ft H~,= k (V'/2g =.36 x (15.75'/64.4) = 1.39ft Hb,~=k (V'/2g =.3 x (15.75'/64.4) = 1.16 ft H>>~~,= k (V'/2g =- 3 x.72 x (15.75'/64.4) = 8.32 ft diffuser = (1-(dl/d2)')') /(dl/d2)4 = (1-(14/18)')'/ (14/18)4 =.426 H,=k(V )/2g =.426 x(15.75'/64.4) = 1.64 ft 4
Hip>> = sum ofabove = 12.89 ft Hrg H)4>> + Hip>
- 27. 12 ft NPSH, b=H, -H~ + H-H
= 34-11.19+46.09
-27.12 = 41.78 ftabs ENSM970919AF Pg 1~ of 4 I AF 9/19/97
~ l
Results:
Design Flow Maximum Flow 8000 gpm 9000 gpm Uncertainty Runout 9194 gpm 11000 gpm NPSH,,
47.79 ft abs 46.03 ft abs 45.65 ft abs 41.78 ft abs NPSHmquiM 16 ft abs 18.5 ft abs Margin 31.79 ft abs 27.53 ft abs 19 ft abs 25 ft abs 26.65 ft abs 16.78 ft abs
==
Conclusions:==
The above tabulation indicates that the available NPSH exceeds the required NPSH under the high temperature CCW conditions. Including the surge tank level and flow instrument uncertainty at the maximum normal procedural CCW flowof9194 gpm indicates that approximately 26 ft abs ofmargin exist.
However, the maximum flowis not a requirement ofthe cooldown analysis.
The cooldown analysis stipulates a maximum CCW flowof 8000 gpm. Allowingfor instrument uncertainty at 8000 gpm of 2.38% results in a flowof 8190 gpm. This is acceptable since the tabulation indicates that margin exist at the higher flows tabulated.
It is noted that the 9000 gpm maximum flowis stated in plant procedure 1,2 OHP 4021.016.003 (normal CCW operation).
During normal plant operating conditions the CCW temperature is at the design basis number of95'F. Atthis temperature, the CCW fluidtemperature supplied to the pump is 114'F from the CCW heat exchanger data sheet. The vapor pressure is determined to be 1.25 psia or 2.91 ft. The NPSH requirements at 114'F and maximum flowof9194 gpm during normal operation is as follows:
NPSH.
i*bi.=H. -H~. + H
- Hr = 34-291+4609
-23.25 = 53.93 ftabs From the above tabulation the NPSH required at 9194 gpm is 19 ft abs which yields a margin of34.93 ft abs.
ENSM970919AF Pg lg of Al AF 9/19/97
e t 1
W~nghouse Calculation Cover Sheet P
rieta Claws 2C
Title:
Cooldown Runs to Support Startup Page l of l5 project; AEp/AMp Author/Date: Gary J. Corpora Calculation //: SAPJFSE4-AEP/AMP@102 S.O.: ANLF-280 Purpose Perform single and 2-tnin own runs with RHRCOOL usuig parameters agreed upon with AEP.
Results: Both single and 2-train cooldown meet the~ldown times.
Assignment ofVerifier:
Name: Kenneth 'A. Gamer The individual named below is hereby assigned the responsibility of independent reviewer to verify the calculation identified above.
gcA<
g u'P Minimum Extent ofVerification (identified by responsible Manager):
The minimum extent ofverification is idcntified as follows: (l) Verifycalculation to the standards of the Westinghouse ESBU Quality Policy and Procedure Manual. specifically, Procedure WPP. l7.
llfanager's Signature:
Results ofVeri6cation (briefstatement by verifier);
The following brieay states how this calculation was verified:
~ Pi)tele l lese i es~ l4 css\\I
...~al.l Verifier's Signature:
Computer Code(s) Used in the Calcuhtion:
Date:
WarL r'4s/sc, a a 2 Date:
cy rs-/'y-y Program Name: RHRCOOL Issue/Rev. No.: 2.0 Release Letter No.: SAE/FSE-MW202, 8/26/97 Coinputer Used:
PC Date(s) Used:
8/l2,l5/97 Properly Used: (IfNO, list restrictions/exclusions and justifications) yes Program Name:
Release I~No.:
Issue/Rev. No.:
Date(s) Used:
Computer UsecL'roperly Used: (IfNO, list restrictions/exclusions and justifications)
This docsnnent is the property ofand contains proprietary information owned by Westinghouse Electric Corporation ssnd/or its
'"'~ "ont>dence and trust, and you agree to treat this document in strict st under whichit was provided to you.
Lue t Fax Note 7671 sctric CoipoPsstioa, AllRights ReMsved W~> c Cn. Mps Far>>
Frssin+
FAX X g ~r g~ qyo t IC~
Jp cer-
~
I
~
e
~
e e
4
TIIlE Cooldov(n Runs to Support Startup PACE 90f 15 PROJECT AEPIAMP
$.0.
ANU -280 AUTHOR 0, J. CaponI CALC NO SAFJFSE4 AEPIAMP4I02 CHK'0. BY FILE NO.
VERIFIEDBY DATE K. N, Oa(acr GROUP 117-2 1.81 110.4
~ Sl 106
~ 6 159.6 142
~ 3 112 ~ 3 155
~ 7 114-4 2-05 104
~ 8 1-27 105.8 157
~ 6 140.7 111
~ 4 159
~ 7 91.8 2.13 100.3 1.48 100.0 141.6 128.2 104.6 144 9
75.0 2.13 96-6 1.48 95.7 124.7:18.9 99.5 132.4 65.7 2-13 93-S 1.48 93.3 123 I 113.7 96.6 125.4 60.3 2.13 90.8 1.48 91.9 119.3 110.6 95.0 121.4 54.0 2.13 88-5 1.48 90.3 114.8 '07.1 93.0 116.7 48.9
- 2. 13 86.4 1.48 89.0 111.2 104.2 91,5 112.9 45.9 2.13 84.6 1
~ 48 88.2 109.0 102.5 90.5 110.6 44.6 2.13 83.6 1.48 87.9 108.1 101.8 90.1 109.7 1ttt*ttt*ttttttttt+t1ttt0t t*ttt @***a tel ttttItttttttt*
REACTOR COOLED TO 139.82 DEGREES IN 13.6 HOURS'HRHX MAX Q >>
120.76 AT 4.0 HRS.
RCS FLOW Wl THROTTLED TO NEET 50.0 F/HR CRITERION STARTED THROTTLING AT 4.0
- HRS, AND 350.0 DEGR.
STOPPED THROTTLING AT 6.2
- HRS, AND 240.0 DEGR.
300-0
~ 250.0 206.9 t 183.0 169.8 162.l 153o2 146-0 141.6 139.8 tfo*ht01 5.0 6.0 7.0 8.0 9.0 10.0 11-0 12.0 13.0
- 13. 6
>>>>>>>>>>SW>>>>>>>>>>>>l>>>>>>a>>>>
s>>>>>>>>>>>>
7t>>>> 'x>>>>>> '4>>>>>>s>>>>42>>>>>>
WESTINGHOUSE CONFIGURATION CONTROL Westinghouse Proprietary Informatian Code!
RHRCOOL
,Version: 2.0 conf igurations August 1,
1997 Executions September 15, 1997 control Number:
299184S696673 09:10>18.84 Program has not yet been verifiod A record of configured versions exists in the Westinghouse Engineering Technology Configuration Control Department.
>>$ >>%>>>>>>>>>>>>O>>>>>>>>>>>>E>>C+>>>>
>>>>>>>>>>>>>>>>S>>>>>>C>>'h>>%>>>>
1ttttt*t0tt*ttttttRHRCOOL PC REV 2 QQ* 0 t *t ttt 1ttttt*0t 1 ttttttt +tl 0 + ~ ~
~
SPECIAL COMMENTS cook Single Train cooldawn to Support Startup-OUTPUT CONTROL('UTPUT AT N2 HR INTERVALS( N2ll+0 BOP-FR"8(
ENTER 1
(ANS 5 ~ 1 1979(
ENTER 2 Xl>>lo Q
REACTOR POWER, MW>> 3411.0 Ul DESIGN UA CCW HX MBTU/HR/F 4 ~ 000 U2 DESIGN UA RHR HX
~
MBTUII'HR/P 2-126 Wle RCS FLOW THROUGH ONE RHR HX(
HLB/HR>>
1.,480 W6>> RHR PUMP MINZFLOW, MLB/HR>>
000 W2 CCW FLOW THROUGH ONE RHR HX(
HLB/HR>>
2'80 W3>>
MLB/HR>>
3-930 W4>>
CCW FLOW THROUGH ONE CCW HX, MLB/HR>>
4.000 Al,A2 AUX HEAT LOAD AT 4.00 HRS AND 20.00 HRS 5.86 C5>>
RCS HEAT CAPACITY, MBTU/F>>
2.13 P=
RCP POWER(
HBTU/HR>>
17.40 Ti(T2>> SW TEMP AT 4 ~ OOHRS AND 20 00 HRS >>
76 00 76'0 5.86 AUTHOR DATE CHK'0. BY DATE VERIFIEDBY DATE
psc5 I is((3r(VrJoc g.rx( v d
~ i wra ice,po TITU'ooldove Runs to Support Srartup PAGF 8 of 15 PROJECT AEPIAMP S.Q.
ANLP-280 AUTHOR G. J. Corpora CALO NO, SAEIFSEC-AEPIAMP4102 CHK'D. BY Fll E NO.
DATF.
VERIFIED BY DATE K N,Gamer GROUP FSG ttttt~**tttttt**ttRHRCOOLPC RE) 2 QQtttttttttt*tttkttt*tttttt*tttt*tttt SPECIAL COMMENTS Cook Normal Cooldown to SuPPort Startup - 3411 MWt OUTPUT CONTROI )
OUTPUT AT N2 HR INTERVALS) N2>>1 ~ 0 BOP-FR 8)
ENTER 1 )ANS-5 ~ 1-1979, ENTER 2 -Xl>>1) g<<
REACTOR
- POWER,
~>> 341).0 Uli DESIGN UA CCW HX)
MBTU/HR/F>>
4 000 U2= DESIGN UA RHR HX, MBTU/HR/F>>
2.126 Wl>> RCS FLOW THROUGH ONE RHR HX, MLB/HR>>
1.480 W6>>
RHR PUMP MINIFLOW) MLB/HR>>
.000 W2>>
CCW 'FLOW THROUGH ONE RHR HX, MLB/HR>>
2.480 W3>>
MLB/HR>>
3.930 W4>>
CCW FLOW THROUGH ONE CCW HX, MI8/HR~
4)000 Al A2 AUX HEAT LOAD AT 4.00 HRS AND 20.00 HRS 5.86 CS>>
RCS HEAT CAPACITY)
MQTU/Ft '.13 '
2.
N4)t NUMBER OF RHR HX<<
2.
T7>>
RCP STOP
- TEMP, F<<
160)00 T9>>
RCS FINAL TEMP)
F>>
140.00 T8>> ccW MAX TEMP BEFORE F 00 HRs)
F>>
120s00 T10>>
F>>
120.00 X>> MAX RCS TEMP CRADIENT)
F/HR>>
50 ~ 00 B4>> TIME COOLDOWN INITIATED)
HR>>
4i0 83>>
RCS START TEMP>> 350.0 Ll CCW HX TYPE TWO TUBE PASS <<1, COUNTERFLOW = 0 Ll L2>> g RHR HX SHELL PASSES>>
1 tttt*ttttt*tttt*ltt*tttttttttltt 0ttttttt**t1ttttttttttt*ttt 0 k
RHR HX INITIAL UA CORRECTION RHRHX DESICN U) BTU/HR/FTttZ/F>> 350.0 DESIGN UA>>
2.126 RCS DESIGN FLOW >>
1'80 CCW DESIGN FLOW >>
2.480 CORRECTED UA >>
2 '26 RCS ACTUAL FLOW <<
1.480 CCW ACTUAL FLOW >>
2.480 ttt*ttt*tttt***ttttttt*t**tttt
~tttttttttt'tttttttt*tttttttttt tttttttttttttttttt*tttttttttttttttttttttfttttttttttt**tttttt*
tttttt*t'Attytttttttttt*ttlttttt*tttttttttt*t0t*ttttt*I*t*Itt CCW HX ZNZTZAL UA CORRECTION CCWHX DESIGN U) BTU/HR/FT* 2/P
>> 328)0 DESIGN Uh >>
4.000 SW DESIGN FLOW>>
4.750 1
CCW DESIGN FLOW >>
4.000 CORRECTED UA 3 '35 SW ACTUAL PLOW 3 '30 t
CCW ACTUAL FLOW>>
4 ~ 000 ttttt*tttttt**lt*ttt'tttt 1ttt ~t*t*t4 1ttt*tttttttttttttttt 't'tt*
tt**ttttttt*tt 1ttttttltttt*tlttttttttl*tttttttttt*ttttttt*tt*
CCW-TEMPERATURES t
RHRHX RHRHX DECAY RCS SWOUT RHRHX CCWHX CCWHX RCOUT t RCS HEAT Uh HEAT. FLOW TEMP TOUT TIN TOUT TEMP
- .TEMP BT/H BT/H/F BT/H P/H DEC F DEG F DEG F DEC F DEG F t DEG F t 350.0 3.06 ttgtt H4.0 DAlE AUTHOR DATE CHK'D. BY DATE VERIFIED BY DATE J
(JO
/:&w57yp!%4(<
p)
(S etc 4f L.f h ~- ~f(<I<7
1 Cooi...:-n ibm to Support Startup PAGE I
IO af 15~
ANLF-23v AUTHOR 0, J, Corpas CALC NO.
SAE/FSE4.AEP/AMP@)02 I
~~:K'0 GY
'LBNQ VERIFIEO BY OATE K.N G~
GROUP FSE MRHX RHRMX DECAY RCS'WOUT RHRHX CCWHX RCOUT HEAT UA HEAT FLOW TEMP TOUT TIN TOUT TEMP BT/H BT/H/P BT/H P/H DEQ F DEQ F DEQ F DEG F DRQ F 139. 6 139. 6 139.6 139.6 139.6 139.7 139.6 130.5 122.6 11&.5 111m&
107.8 104 7
102-1 99.9 58-1 96.4 94.9 93.6 92.3
- 1. 80 1.83 F 86 1.91 1.96 2.03 2'2 2-13
- 2. 13 2 13 2.13 2'3 2 13 2-13 2a13
- 2. 13 2.13 2'3 2'3 2-13 110,4 104.8 l00.3 96 6
93.5 90.8 88.5 86.4 84.6 82.9 81 4
80.1 18.8 77.7 7&.6 75.5 74.3 73 '
72 2
71.3
~ 80
.83
.89
~ 97 1.07 1 23 1.45 1.48
- 1. 48 1 ~ 48 1.48 1 ~ 48 1.48 1.48 1.48 1
~ 48 1.48 1'8
- 1. 48
- 1. 48 113
~ 0 113.0 113.0 113.0 l13.0 113. 0 113.0 110.7 108.7 107.1 105.9 104.9 104. 1 103. 5 102.9 102.4 102.0 101.6 101.3
~ Pi g
~ I
~
~ L, 176.3 176. 3 176.3 176. 3 176 ~ 3 176. 3 176.3 l69.8 164.3 159.9 156.5 153-8 151.6 149.8 148. 3 147aQ l45.8 144 '
f4) ~ 8
'42.9 156.4 356 ~ 4 156 '
156.4 156-4 156s4 151 ~ 3 147.Q 143.6 140-9 138 8
137. 1 135.6 134.4 133.4 132. 5 31 ~ 7 130.9 130.2 120 i0 120.0 120.0 120.0 120.0 120.0 120.0 117.2 t14.8 1 a3.0 111 '
110 4
109.4 108. 6 108.0 107.4 106.9 106.5 106 3.
105.7 171.5 172.2 173.2 174.6 176. 3
,178. 4 181.0 1/4.5 168 ~ 7 164. 1 160.5 157 ~ 7 155.4 153.5 151.9 150.5 149. 3 148.2 147.2 146.2 RCS i TEMP
~
DEG F
3~iC. Q 346
- 3)>>., 4 330.3 319
~ 2 306.4 t 292,4 2 7.1 262 6
i 251.5 442
~ 8 s
236
~ Q t 23' i 226.1
- 222.4 219. 4 216. 6 214-4 212 ~ 3 210 '
208.6 El 5.0 6 ~ 0 7.0 B. Q.
IG.Q 11.0 12.0 13.0 l4.0 15.v 16.0 17.0 lA. ~
- .9. 0 20.0 21-0 22 '
23 '
24.0 R
nATE CHX'D.BY OATE V~R~r'=-0 BY N3>>
NUMBER OF CCW HX>>
1.
N4>>
NUMBER OF RHR HX>>
1-T7>>
RCP STOP TEMPi F>>
160.00 T9>>
RCS FINAL TEMP, F>>
200.00 8
CCW MAX TEMP BEFORE 8.00
- MRS, F
120.00 T10>>
CCW MAX TEMP AFTER 8
QQ HRSi P>>
120 00 X>> MAX RCS TEMP QRADIENTi F/HR>>
50 00 84>> TIME COOLDOWN INITIATEDi HR>>
4 0 83>>
RCS START TEMP>> 350.0 L1>> CCW HX TYPE, TWO TUBE PASS
\\,
COUNTERFLOW 0 Ll L2>>
1 ktttt*t*ttttttitttt*ttttt**tt\\tt*titty ttitttjtt*tttiiiittet 1
RHR HX INITIAL UA CORRECTION RHRHX DESIGN U, BTU/HR/FTtt2/F 350.0 k
DESIGN UA>>
2 ~ 126
'CS DESZCN FLOW>>
1.480 CCW DESIGN FLOW>>
2,480 CORRECTED UA =
2 ~ 126 RCS ACTUAL FLOW >>
1<480 CCW ACTUAL FLOW >>
2.480 tt*t'IRttt**ttt*l*tttt*tttttt**itttt*l*ttttttttttte k*tata k k k ~
k ~tt*ttitittttttttttttttttti*tttit*i*tttititit*itttteieiiee
~ *
~ S *i k 1itt**ttttttttttt eitttII*i*itt>>iti*tttt 1 *tt >>*Ik r ktt ki 1 t t
CCW HX INITIAL UA, CORRECTION CCWHX DESIGN Ui BTU/MR/FTt*2/F>> 328.0 DESIGN UA>>
4-QQQ S'W DESIGN FLOW>>
4.7:,c.
CCW DESIGN FLOW>>
4.000 CORRECTED UA >>
3.835 SV ACTUAL FLOW >>
3.930 CCW ACTUAL FLOW >>
4.000 k i t t t it l*t 1 ~tt*tttktt+tttttttiitttitt*kt*tttit ititt k k tits k >> +
iit*itit itttitt tt*tt itt*titit tttt it it tt t tt tt tttiiit e i kt k ~ e
~ ( i CCW-TEMPE TURSS e
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'i'ABLE COMPONENT COOLING WATER SYSTEM MINIMUM FLOW REQUIREMENTS PER TRAIN (GPM)
Serv4ce Safe uardo Train'okHAI OPfikATIOII LOCA IHJRCTIOH LOCA kfiCIRCULATIOII COttlLQ RHR Heat fixchanger CCP PP Hx SI PP Hx RHR PP Hx CTS PP Hx Subtotal 31 31 20 4950 20 5009 4950 ep 5009 Hiocellaneoua Train BA Bvaporator SPP Hx'aste U<<a Compreoooro Sample Cuulero (Vl/U2)
Pout Accident S<<mpllng Syotem'etd<un Hx<
Seal Water Heat 6xchanger Ctmt.
Pen.
Cooling C6Q Pan Htro'CP Hotoro RCP Therm<<l Barrier Hxo Reactor Support Cire Subtotal lUI/U2) 1442 2980 42.5 139/169<
984 300 404 140 40 6670.5/6700.5 59/59 15 59/59 42.5 139/169<
984 199 300 404 140 40 2248.5/2278.5 Hoteo 33 II)
II)
I) 5068/5068 6701. 5/6'731
~ 5 59/59 Totals
{Ul/U2) 7257.5/7287.5 float the uae of one oaf eguard' train.
The second oef <<guard tr<<in may be placed in oervice provided the neceoaary eguipment Single train operation results in minimum oafeguard'o re<luiremento and a minimum cooldoun.
por LOCA Recirculation only one CBQ fan io reguired.
An analyoio uao performed uhich determined acceptable performance <<t e reduced flou of 15 gpm The 44 gpm flow io baoed on tho uoe of 3 model QC-S6) lip gpm ea.)
and 1 model QC-501 (14 gp<a) uample coolero.
SPP Hx is assumed to be on the non-accident unit.
S.
Theo<< flous represent the maximum flouol they may be oignificantly reduced ao necessary to control proceoo temp<<rat le Letdovn Hx lo assumed to be inaervice, The excess letdokn Hx io pl'c Hx's deuign flou rate io 2)0 gpm.
9 ri.ll
- July, l <J>7
227200-STG-5400-02 REV.
1 PAGE 13 OF 13 Ev<<.,'Oi5)
DONALD C.
COOK NUCLEAR PLANT Feectie7iafi"-Awee VERIFICATION CHECKLIST CALCULATIONS Calculation Number D+ )
/
s~
<<7 Signature of Verifier Date
1.0 Basis
Mere the inputsjdraTasi'ciiirces correctly selected, incorporated and documented into tfie calculation'?
Yes ~
N/A u'.0 Basis:
Are assumptions necessary to perform the calculation adequately described and reasonable?
Yes v
N/A
3.0 Basis
Are the applicable codes, standards and regulatory requirements identified and r'equirements for design met?
Yes ~N/A
4.0 Basis
Mas an appropriate design method used?
Yes ~
N/A
5.0 Basis
Is the output reasonable compared to input?
Yes ~
N/A
6.0 'asis
Are t5e results numerically corr'ect?
Yes v
N(A Attachment 5
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