ML20116J544

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Pressure Locking Evaluation for Required Pullout Force
ML20116J544
Person / Time
Site: Sequoyah  Tennessee Valley Authority icon.png
Issue date: 08/06/1996
From:
TENNESSEE VALLEY AUTHORITY
To:
Shared Package
ML20116J490 List:
References
2-FCV-68-333, GL-89-10, NUDOCS 9608130259
Download: ML20116J544 (3)
v • d • e


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2-FCV-68-333 (GL 89-10) Page f or 3

- MOV Calc No.

prs =.cct1RE LOCKING EVALUAT10N FOR REQUIRED PULLOUT FORCE Valve type = Flek Wedge"

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p 'lN@UTS MOV '2-FCV-68-333 ;

I -- EPRI MOV PPP INTERNAL DEslGN INFO. Ref.

VALVE DESIGN DATA VALVE MARK No.DWG h(;188405-2i

80006[ R _

D1, .. , E1 M1 _.

.s 2 2.9371 1 2 1BR__ a.0.8.12 p: < -: 0.4 theta = -5 deg a= ((D1 + E1)/ 2)/ 2 = 1.281 1.2810 inches ro= 0.406 inches b= M1/ 2 = 0.406 = ro a=

b= 0.406 inches v= 0.3 v= Poisson's Ratio = PMO.3' u fnction coefficient based on Calc method. & EPRI results b PRESSURE and TEMPERATURE DATA theta = 1/2 total valve e L2250 psi disk angle Pbon =

j' Phigh =

sprz0 psi Plow = Mamo psi 0 psid DP=

Normal Temp = mano F v ,r0 F Max Temp =

Delta Temp = ,

O F

' Pbonne! = Pbon + (Delta Temp *33 psi /F) 2250 psi ROARK FORMULAS 0.167176 C2= (1/4)(1-(b/a)2[1+2in(a/b)]}

0.028914 C3= (bl4a)([(b/a)2+1]In(a/b)+(b/a)2-1}

0.685158 C8= (1/2)[1+v+(1-v)(b/a)2]

0.286608

, C9= (b/a)([(1+v)/2]In(a/b)+[(1-v)/4][1-(b/a)2]}

0.005962 i L11= (1/64){1+4(ro/a)2 5(ro/a)4-4(rola)2(2+(rola)2]In(a/ro)}

0.144066 L17= (1/4)(1-((1-v)/4)(1-(rola)4}-(rola)2[1+(1+v)ln(a/ro} Load Constant = (C2L17-C8L11)/(C2C9-C3C8) l0.711633l SEAT REACTION LOAD (BONNET psi) 2051.1 lbMn Reaction at Hub Perimeter = QH(Bonnet) = Pbonnet(a)(Load Constant) 

                                                                                                                           -646.3 lbMn Reaction at Seat: QS(Bonnet) = OH(Bonnat)(b/a)-(Pbonnet/2a)(a2-b2)

SEAT REACTION LOAD (Disk Area DP) 0 lbMn Reaction at Hub perimeter = QH(DiskDP) = (DP)(a)(Load Constant) 0 lb/in Reaction at Seat = QS(DiskDP) = OH(DiskDP)(b/a)-((DP)/2a(a2-b2)) SEAT REACTION LOAD (Hub Area DP) 0 lb/in Force on Hub due to DP = Whub = QH(DPdisk)+(DP)PI(b^2))/2Pl(b) 0 lb/in Reaction at Seat = QS(HubDP) = (-Whub)(b/a) 

                                                                                                                         -1292.57 lb/in Sum of Seat Reaction Loads = 2*QS(Bonnet)-QS(DiskDP)+QS(HubOP)                                                0.387951 VF = mu/(cosA + musinA)                                                                                        -4035.97 lbs Thrust Load = VF*(Sum Seat Reaction)*(Seat Circumference)                                                          -5228 lbs Unwedging Load (Static test)

TOTAL THRUST = Thrust Load + Unwedging Load = l -9264llbs MOTE: THE NEGATIVE SIGN INDICATES THAT THE STEM IS IN TENSION 9608130259 960806 PDR ADOCK 05000327 P PDR 

                                                     <S
                                                    ' -j Prepared: IN            <     Checked; f            e Rev.

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1 MOV Calc No. 2-FCV-68-333 (GL 89-10) Page 2 of 3 i ' . . , .. PR***"*)RE LOCKING EVALUATION FOR REQUIRED PULLOUT FORCE I j '1iN@UTS MOV l2-FCV-68 333 Valve type = ' Flex Wedge ' I

VALVE DWG ?83405-2' EPRI MOV PPP INTERNAL DEslGN INFO, Ref.

VALVE DESIGN DATA MARK No. .;_l80008L 2 em D1 E1 M1 g g u- ~ 0.4 lheta- - 5 deg a= ((D1 + E1)/ 2)/ 2 = 1.281 l a= 1.2810 inches ro= 0.406 inches b= M1/ 2 = 0.406 = ro i

b= 0.406 inches v= 0.3 v= Poisson's Ratio = "" 70.3' u friction coefficient l PRESSURE and TEMPERATURE DATA based on Calc method. & EPRI results theta = 1/2 total valve Pbon = m *2235 psi disk angle Phigh =
t m e300 psl Plow = rammo psi DP= 300 psid Normal Temp = m *
  • a0 F
Max Temp = ee +R 0 F
                                                                          -              0 F                                                  j

, , Delta Temp = ' Pbonnet = Pbon + (Detta Temp *33 psi /F) 2235 psi j ROARK FORMULAS 4 0.167176 C2= (1/4)(1-(b/a)2[1+2!n(a/b)]) 0.028914 C3= (b/4a)([(b/a)2+1]In(a/b)+(b/a)2-1) 0.685158 

;                  C8= (1/2)[1+v+(1-v)(b/a)2]

0.286608 C9= (b/a)([(1+v)/2]In(a/b)+[(1-v)/4][1-(b/a)2]) 0.005962 L11= (1/64)(1+4(ro/a)2-5(rola)4-4(rola)2[2+(ro/a)2]In(a/ro}} 0.144066 L17= (1/4)(1-((1 v)/4)(1-(ro/a)4]-(ro/a)2[1+(1+v)ln(a/ro)]} Load Constant = (C2L17-C8L11)/(C2C9-C3C8) l 0.711633l SEAT REACTION LOAD (BONNET psi) 2037.4 lb/in Reaction at Hub Perimeter = QH(Bonnet) = Pbonnet(a)(Load Constant) 

                                                                                                                           -642.0 lb/in Reaction at Seat: QS(Bonnet) = QH(Bonnet)(b/a)-(Pbonnet/2a)(a2-b2) j SEAT REACTION LOAD (Disk Area DP)

Reaction at Hub perimeter = QH(DiskDP) = (DP)(a)(Lead Constant) 273.4806 tb/in 

                                                                                                                        -86.1714 lb/in Reaction at Seat = QS(DiskDP) = OH(DiskDP)(b/a)-((DP)/2a(a2-b2))

SEAT REACTION LOAD (Hub Area DP) 334.3806 lb/in Force on Hub due to DP = Whub = OH(DPdisk)+(DP)PI(b^2))/2PI(b) 

                                                                                                                        -105.979 lb/in Reaction at Seat = QS(HubOP) = (-Whub)(b/a)
                                                                                                                         -1303.76 lb/in Sum of Seat Reaction Loads = 2*QS(Bonnet)-OS(DiskDP)+QS(HubDP) 0.387951 VF = mu/(ccsA + musinA)                                                                                     -4070.91 lbs Thrust Load = VF'(Sum Seat Reaction)*(Seat Circumference)                                                       5228 lbs Unwsdging Load (Static test)

TOTAL THRUST = Thrust Load + Unwedging Load = l -9299llbs "OTE: THE NEGATIVE SIGN INDICATES THAT THE STEM IS IN TENSION Prepared: Checked: 4 - l Rev. 1 4

p F 

       )MOV Calc No.                                 2-FCV-68-333 (GL 89-10)                                           Page 3of 3
                  . PisESSURE LOCKING REQUIREMENT =                       9264 lbs
. sn          .

9 A CTUA TORNA L VE CA PA BILITY EVAL UA TION CALCULATION: ' EPM RJP-031191 Actuator Model [SMB-00j 

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Motor Start Torque (MT) ' 525' filbs Overall Gear Ratio (OGR) s :49 Pullout Efficiency (PE) 340.% Application Factor (AF) 0.9 or 1.0 ..y0.9. 1.0 or (VF/460)"2 1,0000, 427.2VAC Valve Factor (VF) 

                                                                                            ,   x0,0156j

, Stem Factor (SF) Max Temperature (Temp) 327 F , Loss Percentage (elevated temp) [$M2]% riote 1 Torque Loss Factor = 1-Loss %*(Temp-104)/(356-77) 0.8146 Actuator Torque Capability = (MT

  • OGR
  • PE
  • AF
  • TLF
  • VF) 359.22 fttbs SF =

Actuator Thrust Capability = Torque / Stem Factor 23027lbs 0.0156 Actuator Thrust / Torque Rating ?I3is560}lbs 

                                                                                        , {di250.00,ftIbs Valve Weak Link Thrust / Torque Rating                                     Is%9850]Ibs                                          SF =

228.54 filbs 0.0156 Seismic Thrust / Torque Rating $J2}500[lbs SF = 335.40 filbs 0.0156 Nota 1:

Reference:

Limitorque Technical Update 93-03 RESULTS: PRESSURE LOCKING REQUIREMENT = 9264lbs ACTUATOR / VALVE LIMITING CAPABILITY = 14650 lbs COMMENTS: , l 1 

                                                                                                                                                               )

l Rev. Prepared: s Checked: pg __}}

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