ML20116J544

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Pressure Locking Evaluation for Required Pullout Force
ML20116J544
Person / Time
Site: Sequoyah  Tennessee Valley Authority icon.png
Issue date: 08/06/1996
From:
TENNESSEE VALLEY AUTHORITY
To:
Shared Package
ML20116J490 List:
References
2-FCV-68-333, GL-89-10, NUDOCS 9608130259
Download: ML20116J544 (3)


Text

-_

~

A e

MOV Calc No.

2-FCV-68-333 (GL 89-10)

Page f or 3

~,

prs =.cct1RE LOCKING EVALUAT10N FOR REQUIRED PULLOUT FORCE

-r:p 'lN@UTS MOV

'2-FCV-68-333 ;

Valve type =

Flek Wedge" I

VALVE DWG h(;188405-2i EPRI MOV PPP INTERNAL DEslGN INFO. Ref.

VALVE DESIGN DATA MARK No.

80006[ R D1,..,

E1 M1 _.

2 __

2.9371 1 1BR a.0.8.12

.s 2 p:

< -: 0.4 theta =

-5 deg a=

((D1 + E1)/ 2)/ 2 =

1.281 a=

1.2810 inches ro=

0.406 inches b=

M1/ 2 =

0.406 = ro b=

0.406 inches v=

0.3 v= Poisson's Ratio = PMO.3' u

fnction coefficient based on Calc method. & EPRI results b

PRESSURE and TEMPERATURE DATA theta =

1/2 total valve e L2250 psi disk angle Pbon =

sprz0 psi j'

Phigh =

Mamo psi Plow =

0 psid DP=

Normal Temp =

mano F v

,r0 F Max Temp =

O F Delta Temp =

' Pbonne! = Pbon + (Delta Temp *33 psi /F) 2250 psi ROARK FORMULAS 0.167176 C2= (1/4)(1-(b/a)2[1+2in(a/b)]}

0.028914 C3= (bl4a)([(b/a)2+1]In(a/b)+(b/a)2-1}

0.685158 C8= (1/2)[1+v+(1-v)(b/a)2]

0.286608 C9= (b/a)([(1+v)/2]In(a/b)+[(1-v)/4][1-(b/a)2]}

0.005962 i

L11= (1/64){1+4(ro/a)2 5(ro/a)4-4(rola)2(2+(rola)2]In(a/ro)}

0.144066 L17= (1/4)(1-((1-v)/4)(1-(rola)4}-(rola)2[1+(1+v)ln(a/ro} Load Constant = (C2L17-C8L11)/(C2C9-C3C8) l0.711633l SEAT REACTION LOAD (BONNET psi) 2051.1 lbMn Reaction at Hub Perimeter = QH(Bonnet) = Pbonnet(a)(Load Constant) -646.3 lbMn Reaction at Seat: QS(Bonnet) = OH(Bonnat)(b/a)-(Pbonnet/2a)(a2-b2) SEAT REACTION LOAD (Disk Area DP) 0 lbMn Reaction at Hub perimeter = QH(DiskDP) = (DP)(a)(Load Constant) 0 lb/in Reaction at Seat = QS(DiskDP) = OH(DiskDP)(b/a)-((DP)/2a(a2-b2)) SEAT REACTION LOAD (Hub Area DP) 0 lb/in Force on Hub due to DP = Whub = QH(DPdisk)+(DP)PI(b^2))/2Pl(b) 0 lb/in Reaction at Seat = QS(HubDP) = (-Whub)(b/a) -1292.57 lb/in Sum of Seat Reaction Loads = 2*QS(Bonnet)-QS(DiskDP)+QS(HubOP) 0.387951 VF = mu/(cosA + musinA) -4035.97 lbs Thrust Load = VF*(Sum Seat Reaction)*(Seat Circumference) -5228 lbs Unwedging Load (Static test) l -9264llbs TOTAL THRUST = Thrust Load + Unwedging Load = MOTE: THE NEGATIVE SIGN INDICATES THAT THE STEM IS IN TENSION 9608130259 960806 PDR ADOCK 05000327 P PDR <S ' -j Rev. Prepared: IN Checked; f e

i e 1 MOV Calc No. 2-FCV-68-333 (GL 89-10) Page 2 of 3 i PR***"*)RE LOCKING EVALUATION FOR REQUIRED PULLOUT FORCE MOV l2-FCV-68 333 Valve type = ' Flex Wedge ' I j '1iN@UTS VALVE DWG ?83405-2' EPRI MOV PPP INTERNAL DEslGN INFO, Ref. VALVE DESIGN DATA MARK No..;_l80008L 2 D1 E1 M1 em g g 5 deg a= ((D1 + E1)/ 2)/ 2 = 1.281 l u- ~ 0.4 lheta-i a= 1.2810 inches ro= 0.406 inches b= M1/ 2 = 0.406 = ro b= 0.406 inches v= 0.3 v= Poisson's Ratio = "" 7.3' 0 u friction coefficient l PRESSURE and TEMPERATURE DATA based on Calc method. & EPRI results theta = 1/2 total valve Pbon = m *2235 psi disk angle Phigh =

t m e300 psl Plow =

rammo psi DP= 300 psid Normal Temp = m *

  • a0 F ee +R 0 F Max Temp =

0 F j , Delta Temp = j Pbonnet = Pbon + (Detta Temp *33 psi /F) 2235 psi ROARK FORMULAS 4 C2= (1/4)(1-(b/a)2[1+2!n(a/b)]) 0.167176 C3= (b/4a)([(b/a)2+1]In(a/b)+(b/a)2-1) 0.028914 0.685158 C8= (1/2)[1+v+(1-v)(b/a)2] C9= (b/a)([(1+v)/2]In(a/b)+[(1-v)/4][1-(b/a)2]) 0.286608 L11= (1/64)(1+4(ro/a)2-5(rola)4-4(rola)2[2+(ro/a)2]In(a/ro}} 0.005962 L17= (1/4)(1-((1 v)/4)(1-(ro/a)4]-(ro/a)2[1+(1+v)ln(a/ro)]} 0.144066 Load Constant = (C2L17-C8L11)/(C2C9-C3C8) l 0.711633l SEAT REACTION LOAD (BONNET psi) Reaction at Hub Perimeter = QH(Bonnet) = Pbonnet(a)(Load Constant) 2037.4 lb/in Reaction at Seat: QS(Bonnet) = QH(Bonnet)(b/a)-(Pbonnet/2a)(a2-b2) -642.0 lb/in SEAT REACTION LOAD (Disk Area DP) j 273.4806 tb/in Reaction at Hub perimeter = QH(DiskDP) = (DP)(a)(Lead Constant) -86.1714 lb/in Reaction at Seat = QS(DiskDP) = OH(DiskDP)(b/a)-((DP)/2a(a2-b2)) SEAT REACTION LOAD (Hub Area DP) 334.3806 lb/in Force on Hub due to DP = Whub = OH(DPdisk)+(DP)PI(b^2))/2PI(b) -105.979 lb/in Reaction at Seat = QS(HubOP) = (-Whub)(b/a) -1303.76 lb/in Sum of Seat Reaction Loads = 2*QS(Bonnet)-OS(DiskDP)+QS(HubDP) 0.387951 VF = mu/(ccsA + musinA) -4070.91 lbs Thrust Load = VF'(Sum Seat Reaction)*(Seat Circumference) 5228 lbs Unwsdging Load (Static test) TOTAL THRUST = Thrust Load + Unwedging Load = l -9299llbs "OTE: THE NEGATIVE SIGN INDICATES THAT THE STEM IS IN TENSION Rev. Prepared: Checked: 4 4

F p )MOV Calc No. 2-FCV-68-333 (GL 89-10) Page 3of 3 . PisESSURE LOCKING REQUIREMENT = 9264 lbs . sn 9 A CTUA TORNA L VE CA PA BILITY EVAL UA TION CALCULATION: ' EPM RJP-031191 Actuator Model [SMB-00j Motor Start Torque (MT) ' 525' filbs ~ Overall Gear Ratio (OGR)

49 s

Pullout Efficiency (PE) 340.% Application Factor (AF) 0.9 or 1.0 ..y0.9. Valve Factor (VF) 1.0 or (VF/460)"2 1,0000, 427.2VAC Stem Factor (SF) x0,0156j 327 F Max Temperature (Temp) Loss Percentage (elevated temp) [$M2]% riote 1 Torque Loss Factor = 1-Loss %*(Temp-104)/(356-77) 0.8146 Actuator Torque Capability = (MT

  • OGR
  • PE
  • AF
  • TLF
  • VF) 359.22 fttbs SF =

Actuator Thrust Capability = Torque / Stem Factor 23027lbs 0.0156 ?I3is560}lbs , {di250.00,ftIbs Actuator Thrust / Torque Rating Valve Weak Link Thrust / Torque Rating Is%9850]Ibs SF = 228.54 filbs 0.0156 Seismic Thrust / Torque Rating $J2}500[lbs SF = 335.40 filbs 0.0156 Nota 1:

Reference:

Limitorque Technical Update 93-03 RESULTS: PRESSURE LOCKING REQUIREMENT = 9264lbs ACTUATOR / VALVE LIMITING CAPABILITY = 14650 lbs COMMENTS: 1 ) pg Checked: Rev. Prepared: s __}}