ML20116J539

From kanterella
Jump to navigation Jump to search
Pressure Locking Evaluation for Required Pullout Force
ML20116J539
Person / Time
Site: Sequoyah  Tennessee Valley Authority icon.png
Issue date: 08/06/1996
From:
TENNESSEE VALLEY AUTHORITY
To:
Shared Package
ML20116J490 List:
References
EPM-RJP-031191, EPM-RJP-31191, NUDOCS 9608130257
Download: ML20116J539 (3)
v • d • e


Text

- - - -- - - _ - _. . __ _

e MOV Calc No. EPM-RJP-031191 Page ( oF 3 R

ERfSS(JRE LOCKING EVALUATION FOR REQUIRED PULLOUT FORCE MOV F1-FCV-68 333 ; Valve type = (Flex Wedge ~

- , ^ \ } .= INFUTS -

VALVE DWG g f 88405-2 5 EPRI MOV PPP INTERNAL DEslGN INFO, Ref.

VALVE DESIGN DATA MARK No. U y80008 D1 E1 M1 C2.937[32.Y8[ ' [0.812 y: 10.4 theta = iS deg a= ((D1 + E1)/ 2)/ 2 = 1.281 a= 1.2810 inches ro= 0.406 inches b= M1/ 2 = 0.406 = ro v= 0.3 v= Poisson's Ratio = , "7 0'.3' b= 0.406 inches u: fnction coefficient based on Calc method. & EPRI results i'RESSURE and TEMPERATURE DATA theta = 1/2 total valve w 22250 psi disk angle Pbon =

Phlgh = wwedO psi riow = mWst0 ps!

DP= 0 psid Nomial Temp = t;e es0 F Max Temp = .ewO F Delta Temp = ,

O F Pbonriet = Pbon + (Delta Temp *33 psi /F) 2250 psi l

ROARK FORMULAS 0.167176 C2= (1/4)(1-(b/a)2[1+2in(a/b} 0.028914 C3= (b/4a)([(b/a)2+1]In(a/b)+(b/a)2-1) 0.685158 C8= (1/2)[1+v+(1-v)(b/a)2] 0.286608 C9= (b/a)([(1+v)/2]In(a/b)+[(1-v)/4][1-(b/a)2}} 0.005962 L11= (1/64)(1+4(ro/a)2-5(rola)4-4(ro/a)2[2+(rola)2]In(a/ro}} 0.144066 L17= (1/4){1-((1-v)/4)[1-(ro/a)4]-(ro/a)2[1+(1+v)ln(a/ro)]) Load Constant = (C2L17-C8L11p(C2C9-C3C8) l0.7116331 , 4 SEAT REACTION LOAD (BONNET psi) 2051.1 lb/in  ; Reaction at Hub Perimeter = QH(Bonnet) = Pbonnet(a)(Load Constant) 

                                                                                                                           -646.3 lb/in                   l Reaction at Seat: QS(Bonnet) = QH(Bonnet)(b/a)-(Pbonnet/2a)(a2 b2)                                                                                 l SEAT REACTION LOAD (Di:rd Area DP) 0 lb/in Reaction at Hub perimeter = QH(DiskDP) = (DP)(a)(Load Constant) 0 lb/in        i Reaction at Seat = QS(DiskDP) = QH(DiskDP)(b/a)-((DP)/2a(a2-b2))

SEM FP. ACTION LOAD (Hub Area DP) 0 lb/in Force on Hub due to DP = Whub = OH(DPdisk)+(DP)PI(o^2))/2PI(t - _ 0 lb/in Reactica at Seat = QS(HebDP) = (-Whub)(b/a) 

                                                                                                                         -1292.57 lb/in Sum of Seat Peaction Loads = 2*QS(Bonnet)-QS(DiskDP)+QS(HubDP)

VF = mui(cosA + musinA) 0.387St 

                                                                                                                         -4035.97 lbs Thrust Load = VF'(Sum Seat Reaction)*(Seat Circumference)
                                                                                                                             -3666 lbs Unwedging Load (Static test)

TOTAL THRUST = Thrust Load + Unwedging Load = l -7702libs NOTE: THE NEGATIVE SIGN INDICATES THAT THE STEM IS IN TENSION 7608130257 960806 PDR ADDCK 05000327 P PDR Rev. Prepared: k .t Checked: rv

J s *

  • M'OV Calc No. EPM-RJP-031191 Page _2 or 3 PRESSURE LOCKING EVALUATION FOR REQUIRED PULLOUT FORCE i wC" T -

MOV !1-FCV-68-333 i Valve type = ' Flex' Wedge ' l ( " ~R =INFUTS VALVE DWG T88406-2! EPRI MOV PPP INTERNAL DESIGN INFO. Ref. 4 VALVE DESIGN DATA MARK No. , ;80006 D1 E1 M1 T2.937[72.1lB7,[2 ' [0.8l12 i u- w + 0.4 theta- +5 deg a= ((D1 + E1) / 2) / 2 = 1.281 j a= 1.2810 inches ro= 0.406 inches b= M1/ 2 = 0.406 = ro i b= 0.406 inches v= 0.3 v= Poisson's Ratio = T 0.3 1 u: fnction coefficient PRESSURE and TEMPERATURE DATA based on Calc method. & EPRI results ,3 theta = 1/2 total valve ! Pbon = m 2W psi disk angle Phigh = w m 300 psi l . Plow = etm#WO psl i DP = 300 psid i Normal Temp = em>mo F Max Temp = s=wr 0 F j Delta Temp = 0 F a Pbonnet = Pbon + (Delta Temp *33 psi /F) 2235 psi ROARK FORMULAS i i C2= (1/4)(1-(b/a)2[1+2in(a/b)l} 0.167176 C3= (b/4a)([(b/a)2+1]In(a/b)+(b/a)2-1) 0.028914 C8= (1/2)[1+v+(1-v)(b/a)?] 0.685158 j l d C9= (b/a)([(1+v)/2]In(a/b)+[(1-v)/4][1-(b/a)2]) 0.286608 l 

,              L11= (1/64)(1+4(rola)2-5(rola)4-4(ro/a)2[2+(ro/a)2]In(a/ro))                  0.005962 L17= (1/4)(1-((1-v)/4)(1-(ro/a)4]-(ro/a)2[1+(1+v)ln(a/ro)])                    0.144066 Lord Constant = (C2L17-C8L11)/(C2C9-C3C8)                                             l 0.7116331

$ SEAT REACTION LOAD (BONNET psi) Reaction at Hub Perimeter = QH(Bonnet) = Pbonnet(a)(Load Constant) 2037.4 lb/in i l j Reaction at Seat: QS(Bonnet) = QH; Bonnet)(b/a)-(Pbonnet/2a)(a2-b2) -642.0 lb/in l 3 SEAT REACTION LO AD idisk Area DP) f Reaction at Hub perimeter = QH(DiskDP) = (DP)(a)(Load Consunt) 273.4806 lblin 

                                                                                                                            -86.1714 lblin       ;

Reactinn at Seat = QS(DiskDP) = QH(DiskDP)(b/a)-((DP)/2a(a2-b2)) SEAT REACTION LOAD (Hub Area DP) 334.3806 lb/in Force on Hub due to CP = Whub = QH(DPdisk)+(DP)PI(b^2))/2Pl(b) 

                                                                                                                            -105.979 lb/in Reaction at Seat o QS(HubDP) = (-Whub)(b/a)
                                                                                                                             -1303.76 lb/in Sum of Seat Reaction Loads = 2*QS(Bonnet)-QS(DiskDP)+QS(HubOP) 0.387951 VF = mu/(cosA + musinA)
                                                                                                                             -4070 91 lbs Thrust Load = VF'(Sum Seat Reaction)*(Seat Circumference)
                                                                                                                                 -3666 lbs Unw2dging Load (Static test)

TOTAL THRUST = Thrust Load + Unwedging Load = l -7737llbs NOTE: THE NEGATIVE SIGN INDICATES THAT THE STEM IS IN TENSION 3 Rev. Preparei t i Checked:

l 

           *MdV Calc No.                                     EPM-RJP-031191                                Page 3#

n . PRESSURE LOCKING REQUIREMENT = 7737lbs 

  'l :,
        ..l ACTUATORNALVE CAPABILITY EVALUATION                     CALCULATION:        iEPM' RJP-031191 Actuator Model                                                      [SjjByl Motor Start Torque (MT)                                               ??72(filbs Overall Gear Ratio (OGR)                                            g/^^~ $9, Pullout Efficien y (PE)                                             [;3b]MO,%

, Application Factor (AF) 0.9 er 1.0 kpf$f0.9] Valve Factor (VF) 1.0 or (VF/460)"2 k M.0000) 424.4VAC 

 ,,                  Stem Factor (SF)                                                    h:O$f0Ml56]

Max Temperaturc (Temp) 327 F Loss Percentage (elevated temp) M K4232 % Note 1 Torque Loss Factor = 1-Loss %*(Temp-104)/(356-77) 0.8146 Actuator Torque Capability = (MT

  • OGR
  • PE
  • AF
  • TLF
  • VF) 359.22 filbs SF =
                    , Actuator Thrust Capability = Torque / Stem Factor                        23027lbs                                0.0156 Actuator Thrust / Torque Rating                                     [gs~;196'0]0 Ibs EN250 d,ft!bs Valve Weak Link Thrust / Torque Rating                              Ei35sD]!bs             SF =

228.54 filbs 0.0156 Seismic Thrust / Torque Rating @[5@lbs, SF= 335.40 ft!bs 0.0156 Nota 1:

Reference:

Limitorque Technical Update 93-03 RESULTS: PRESSURE LOCKING REQUIREMENT = 7737 lbs ACTUATOR / VALVE LIMITING CAPABIL!TY = 14650 lbs COMMENTS: Rev. Prepared: Checked: W/! - _ _ _ - _ _ _ _ - _ _ _ _}}

Retrieved from "https://kanterella.com/w/index.php?title=ML20116J539&oldid=2807487"