ML20031F211
| ML20031F211 | |
| Person / Time | |
|---|---|
| Issue date: | 05/18/1979 |
| From: | Abramson L NRC OFFICE OF MANAGEMENT AND PROGRAM ANALYSIS (MPA) |
| To: | Liaw B Office of Nuclear Reactor Regulation |
| Shared Package | |
| ML13319A640 | List:
|
| References | |
| FOIA-81-313 NUDOCS 8110190360 | |
| Download: ML20031F211 (2) | |
Text
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UNITED STATES
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NUCLEAR REGULATORY COMMISSION g
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May 18, 1979 MEMlRANDUM FOR:
B. D. Liaw, Engineering Branch, Division of Operating Reactors NRR THRU:
Roger H. Moore, Chief, Applied Statistics Branch, MPA FROM:
Lee R. Abramson, Applied Statistics Branch, MA
SUBJECT:
WESTINGHOUSE REPORT ON " STEAM GENERATOR RETUBING AND REFURBISHMENT", W-9398, JANUARY 1979 Per J. Strosnider's request, I have reviewed Section 7.2.7, "Fie:d Inspection Procedure",of the subject report and have the following coments.
Page 7-8 1.
There is no discussion of the assumptions on which Figure 7-4 is based.
Presumably, it was assumed that hole size.in the regt'n to be sampled has a Gaussian distribution with the same 4nean and v:ri=nce for all holes. How valid are these assumptions and what woulu be the effect of reasonable departures from them?
2.
There is no discussion of the tradeoffs among sample size, tolerance coverage, confidence level, and the cost of making the wrong decision.
How are the sample size, tolerance coverage and confidence levels to be chosen?
Page 7-9 The discussion on cracked ligaments is too cryptic.
I don't understand what is being assumed or what statistical procedure is being proposed.
Much more ditail is needed.
Page 7-15
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According to the text (page 7-8), Figure 7-4 presents one-sided tolerance limits. However, the contours do not correspond to one-sided 90% coverage tolerance limits. They are much closer to one-sided 95% coverage or two-sided 90% coverage tolerance limits.
For example, at 90% confidence, the one-sided k-factor for 90% coverage for n = 6 is 2.49, the one-sided k-factor far 95% coverage is 2.09 and the two-sided k-factor for 90%' coverage is 3.13.
The corresponding tolerance limits for an average enlarged hole size of 890 c.ils are g og y a10e27 ifwp a:,-313 PDR
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- 8. D. Liaw May 18, 1979
.s23rf. c 2.-.
- -- ~ 1 L(.90)=890+(2.49)(4)=900.0',
j L (.95) = 890 + (3.09)(4) = 902.4,
j L(.90)a 890+(3.13)(4)=902.5.
2 ThevaluesofL(.95)andL(.90)correspondmuchmorecloselytoFigure7-15 3
2 than does L (.90).
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1 will be glad to further discuss the report with you.
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Lee R. Abramson Applied Statistics Branch Division of Technical Support Office of Management and Program Analysis cc:
J. Strosnider EB V. Noonan, EB Norman M. Haller, MPA b
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