Text

Calculation G.13.18.2.7-116, Rev. 0, Load Drop Calculation for Spent Fuel Pool Gates (FNS-GATE1 and FNS-GATE2)& Licensee Commitment
	ML14272A181
Person / Time
Site:	River Bend
Issue date:	09/23/2014
From:	; Entergy Operations
To:	; Office of Nuclear Reactor Regulation
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ML14272A185	List: ML14272A181; RBG-47505, Response to Request for Additional Information on License Amendment Request 2013-13;
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Attachment 2 RBG-47505 Calculation G.13.18.2.7-116, Rev. 0 Load Drop Calculation for Spent Fuel Pool Gates (FNS-GATE1 and FNS-GATE2)

(208 pages)

ftOl ANO-1 El ANO-2 [-] GGNS El IP-2 [] IP-3 El PLP M JAF [IPNPS 0 RBS El VY El W3 EL NP-GGNS-3 EL NP-RBS-3 CALCULATION EC # 52637 Pagel1 of 208 COVER PAGE Design Basis Calc. r-] YES I*NO I*CALCULATION -1EC Markup Calculation No: G13.18.2.7-116 Revision: 0

Title:

Load Drop Calculation for Spent Fuel Pool Gates (FNS- Editorial:

GATEI and FNS-GATE2) EI YES N NO System(s): 055/ Refueling Review Org (Department): BE3 Platform Equipment Safety Class: Component/Equipment/Structure Type/Number:

N Safety / Quality Related MHF-CRNI FNS-GATE1 L Augmented Quality Program MHF-CRN2 FNS-GATE2 LI Non-Safety Related Document Type: F43.02 Keywords (Description/Topical Codes):

Spent Fuel Pool, Pool Gates Heavy Loads, Load Drop

+

Crane REVIEWS Name/Signature/Date Name/Signature/Date Name/Signature/Date See AS See AS See AS Responsible Engineer: Z Design Verifier: Supervisor/Approval:

Jordan Carter Eugene Desir Isaac Wells Melissa Litherland Nasser Pazooki I] Reviewer

[-L Comments Attached EI Comments Attached

CALCULATION CALCULATION NO: G13.18.2.7-116 REFERENCE SHEET REVISION: 0 I. EC Markups Incorporated (N/A to NP calculations)

None II. Relationships: Sht Rev Input Output Impact Tracking No.

Doc Doc Y/N

1. FB-1592 N/A 002 21 0 N

2. ER-RB-1996-0082-000 N/A 000 0 0 N

3. G13.18.2.7*031 N/A 000 0 0 N

4. 4200.060-003-001A N/A A R1 0 N

5. G13.18.9.5*059 N/A 001 IA 0 N

6. 8.2.102 N/A 000 IA 0 N

7. 4223.321-258-007A N/A 300 IA 0 N

8. 0223.321-258-004 N/A 300 0 0 N

9. G13.18.2.7*091 N/A 000 IZ 01 N

10. 223.321 N/A 001 EA 0 N

11. EV-003A N/A 011 EA 0l N

12. 0219.721-213-045 N/A 300 IA 0 N

13. EC-062H N/A 006 0 0 N

14. PN-311 N/A 002 El 0 N

15. C62.500 N/A 003 El 0 N

.16. PID-34-02A N/A 021 EA 0 N

17. LDT-SFC N/A 000 E1 0 N

18. PCD-SFC-001-CD-A N/A 007 El 0 N

19. PCD-SFC-014-CD-A N/A 007 El 0 N

20. PCD-SFC-006-CD-A N/A 006 IA 0 N

21. PCD-SFC-007-CD-A N/A 010 IA 0 N

22. PCD-SFC-006-CD-C N/A 005 IA 0 N

23. 228.000 N/A 004 0l 0 N

+

I - I - I - a- I - I Ill. CROSS

REFERENCES:

1. EC 42063 "Seismic Qualification of Fuel Building Bridge Crane MHF-CRN1 for Load of 2500 lbs and Revision of Fuel Pool Gate Rigging Plan for Resubmission of License Amendment Request LAR-2010-04"

2. EC 14186 "24 Month Cycles USAR Chapter 15 Safety Analysis"

3. NUREG/CR-6604, "RADTRAD: A Simplified Model for RADionuclide Transport and Removal And Dose Estimation", Published April December 1998 1997,and Supplement 1 Dated 6/8/99, and Supplement 2 Dated 10/2002.

4. Regulatory Guide 1.183, "Alternative Radiological Source Terms for Evaluating Design Basis Accidents at Nuclear Power Reactors", July 2000

5. Code of Federal Regulations, Title 10, Section 50.67, "Accident Source Term"

6. NUREG-0800, Standard Review Plan (July 1981), Section 6.4 (Rev. 2), "Control Room Habitability Systems"

7. American Institute of Steel Construction (AISC) Manual of Steel Construction, 1 3 th Edition

8. General Electric Company, GESSAR II Nuclear Island Design, (22A7007)

9. Crane Technical Paper No. 410 "Flow of Fluids"

10. River Bend Technical Specifications Section 3.7.6, Fuel Pool Water Level

11. Web page http:/Avww. enqineeringtoolbox.com/water-dynamic-kinematic-viscosity-d 596.html (Copy provided as Attachment C)

12. Perry's Chemical Engineer's Handbook, Sixth Edition, 1984

13. ASME III 1974, Section NA IV. SOFTWARE USED:

Title:

RADTRAD Version/Release: 3.02 Disk/CD No. N/A SDDF: 6244.400-912-001B Rev 300 V. DISK/CDS INCLUDED:

Title:

N/A Version/Release Disk/CD No._

VI. OTHER CHANGES:

None

G13.18.2.7-116 Rev. 0 Page 4 Revision*:' Record of Rev.ision ,.

0 Initial issue.

I1 U

TABLE OF CONTENTS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 5 Section Description Page 1.0 CALCULATION COVER PAGE 1 2.0 CALCULATION REFERENCE SHEET 2 3.0 RECORD OF REVISION 4 4.0 TABLE OF CONTENTS 5 5.0 PURPOSE 6

6.0 CONCLUSION

6 7.0 INPUT AND DESIGN CRITERIA 7 8.0 ASSUMPTIONS 19 9.0 METHOD OF ANALYSIS 23 10.0 CALCULATIONS 26 ATTACHMENTS ATTACHMENT A - RADTRAD Nuclide Input File 131 RBSfhaRevla266.nif ATTACHMENT B - RADTRAD Results File 144 ATTACHMENT C - Water Dynamic and Kinematic Viscosity 182 ATTACHMENT D - Excel Spread Sheet Formula Views, 183 Sections 10.2 through 10.4

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 6 5.0 PURPOSE The purpose of this calculation is to perform a load drop analysis for the Spent Fuel Pool gates (FNS-GATE1 and FNS-GATE2) during the rigging and gate movement operations to perform gate seal replacement. This load drop analysis will conform to the recommended guidelines within NUREG-0612.

6.0 CONCLUSION

The drop of a Spent Fuel Pool Gate (FNS-GATE1 or FNS-GATE2) and the associated rigging from a maximum height of 6.00 feet above the top of spent fuel bundles will result in a maximum of 209 damaged fuel rods. To provide additional margin for changes in rigging or fuel design, a failure of 266 rods is postulated and analyzed for dose consequences.

The dose analysis for a load drop resulting in a failure of 266 fuel rods with a decay time of 14 days (336 hours0.00389 days 0.0933 hours 5.555556e-4 weeks 1.27848e-4 months ) gives the following Total Effective Dose Equivalent (TEDE) at the Exclusion Area Boundary (EAB), Low Population Zone (LPZ) and Control Room (CR). As shown in the results table, the dose resulting from a drop of a Spent Fuel Pool Gate and the associated rigging is less than the RG 1.183 dose limits and is bounded by the dose analyzed for the design basis Fuel Handling Accident in the Fuel Building.

Calculation Results TEDE (REM)

Dose Receptor Acceptance FHA in Fuel Building Gate Drop in Fuel Building Criteria EAB* 6.3 2.5725 1.2155 LPZ 6.3 0.33912 0.16017 CR 5 1.6790 0.87328

Worst 2-hour period Analysis of the penetration of the steel spent fuel pool liner as a result of the drop of the gate and associated rigging components has determined that the minimum required liner thickness required to prevent perforation resulting from object impact is less than the thickness of the stainless steel liner. Given the liner will not be penetrated due to impact of objects being moved for Spent Fuel Pool gate seal replacement, there will be no water leakage from the pool. Thus, no minimum water makeup capability to accommodate leakage from the load drop is required.

Analysis of a load drop on the spent fuel storage racks has determined that the impact force for each potential dropped object is bounded by the existing fuel storage rack load drop analysis. Thus, the required keff for stored spent fuel is maintained in the event that a load drop occurs during Spent Fuel Pool gate movement.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 7 The assessment of the impact load drop on the Spent Fuel Pool Cooling piping located in the pool has determined that the Fuel Pool Cooling piping has adequate ductility to accommodate the impact of a fuel pool gate transitioning from an initial drop onto the spent fuel or racks and will not be perforated as a result of the impact. Based upon adequate ductility of the piping and the level of impact of the gate with the piping being below the minimum water level in the pool, it can be concluded that any damage to the piping will not affect the ability of the pool water to be transferred to or from the Spent Fuel Pool Cooling system. As a result, a load drop of the gates will not adversely affect the safe shutdown function to maintain spent fuel pool cooling.

The total weight of the objects utilized in this analysis is 2375 lbs. This is rounded to approximately 2500 lbs for inclusion in USAR Section 9.1.2.3.3. The use of "approximately 2500 Ibs" in the USAR is appropriate given the conservatisms included in this calculation and the 20% margin included in the dose analysis to account for any minor changes in rigging or fuel design.

7.0 INPUT AND DESIGN CRITERIA Definitions AST Alternate Source Term (same as RST)

CR Control Room EAB Exclusion Area Boundary FB Fuel Building FHA Fuel Handling Accident LPZ Low Population Zone RADTRAD Radionuclide Transport and Removal and Dose Estimate RG Regulatory Guide RPF Radial Peaking Factor RST Revised Source Term (same as AST)

TEDE Total Effective Dose Equivalent Per References 111.4 and 111.5, the calculated Total Effective Dose Equivalent (TEDE) limits are as follows:

EAB: 6.3 REM TEDE* (2 hour2.314815e-5 days 5.555556e-4 hours 3.306878e-6 weeks 7.61e-7 months duration)

LPZ: 6.3 REM TEDE (30 day duration)

Control Room: 5 REM TEDE (30 day duration)

Worst 2-hour period

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 8 Equations Edif = 1 - [M1 / (M1 + M2)] (Ref. 111.8, pg. 15.7-21; Ref. 11.3, pg. 6-7)

Where:

Edif = Fraction of kinetic energy absorbed during impact M= Mass of Gate M2= Mass of Impacted Fuel Bundles

= (# of fuel bundles)(Buoyant bundle wt, lbs/bundle)

Eabs = (PE)( Edi) (Ref. 111.8, pg. 15.7-24; Ref. 11.3, pg. 6-7)

Where:

Eabs = Energy absorbed during impact PE = Potential Energy Edif = Fraction of kinetic energy absorbed during impact Fcomp = [(Eabs)(19/(19+5))] / 200 ft-lb (Ref. 111.8, pg. 15.7-24; Ref. 11.5, pg. 15)

Where:

Fcomp = number of fuel rod failures caused by compression Eabs = Energy absorbed during impact Ai = AC

FD

FRP *FG *(I/DF) (Ref. 11.5_EC 14186 markup pg. 24)

Where:

Ai = total activity of isotope i released to the environment (Ci/MWt)

AC = total activity in the reactor core (Ci/MWt)

FD = fraction of core damaged (unitless)

= Number of rods damaged / (Rods per bundle

Bundles in core)

FRP = maximum radial peaking factor (unitless)

FG = fraction of isotope activity in damaged rods escaping as gap release (unitless).

DF = decontamination factor within pool water for isotope i (unitless)

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 9 L = Ei / (U)(Ai) (Ref. 11.7, pg. 4.2-240)

Where:

L = Length of Damage (in)

E= Total Impact Energy of Falling Object ýin*lb)

U = Strain Energy for Unit Volume (in*lb/in°)

A= Area of Impact Contact (in2)

Ai = (N)(I)(t) (Ref. 11.7, pg. 4.2-240)

Where:

Aj = Area of Impact Contact (in2)

N = Number of Plates in Impact Zone I = Contact Length per Plate (in) t = Plate Thickness (in)

E=U+K (Ref. 11.9, pg. 4)

Where:

E = Total Energy U = Potential Energy K = Kinetic Energy U = (M)(G)(H) (Ref. 11.9, pg. 4)

Where:

U = Potential Energy M = Mass G = Acceleration of Gravity H = Height of Drop

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 10 K=- (M)(V2) (Ref. 11.9, pg. 4)

Where:

K = Kinetic Energy M = Mass V = Velocity T312 = 0.5 M VS2 /(17,400K 2 D3 2/ ) (Ref. 11.4, pg. C-8)

Where:

T = steel thickness to just be perforated, in M = mass of the missile, lb-s 2/ft Vs= striking velocity of the missile normal to target surface, ft/s K = constant depending on the grade of the steel, K is usually = I D = diameter or equivalent diameter of the missile, in Thickness required to prevent steel perforation = T

1.25 (Ref. 11.4 pg. 2)

Where:

T = steel thickness to just be perforated, in Vo =(2gh) Y (Ref. 11.4, pg. E-4, 5-3)

Where:

Vo = velocity of the missile at contact with2 the water surface, ft/s g = gravitational acceleration = 32.17 ft/s h = distance between the missile and the water surface, ft Vs = [Z(H)]1/2 (Ref. 11.4, pg. 5-2)

Where:

Vs = velocity of the missile striking the steel surface, ft/s Z(H) = function for determination of striking velocity (see formulas below)

H = feet of fluid between fluid surface and surface of steel target

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 11 The following equations are from Ref. 11.4, pg. 5-2:

Zl(x) = (g/a) + (bAo)[(1-2ax)/2a 2 )] + e2ax[(Vo2 - (g/a) - (bAo / 2a 2)]

Z 2(x) = V2 2 + e-2ax {(bAo /2a 2)[ e 2aL(1 -2aL) - 1)] + Vo2 + [(g/a)[(e 2aL( 7/ym) - 1)]}

Where:

ZI(x) = function for determining the striking velocity at depth H = x when O<x<L Z 2 (x) = function for determining the striking velocity at depth H = x when x>L a = ( y

A0

CD)/ (2

W) (Ref. 11.4, pg. 5-3) b= (y*g)/W (Ref. 11.4, pg. 5-3) g = gravitational acceleration = 32.17 ft/s 2 (Ref. 11.4, pg. 5-3)

W = weight of missile, lb (Ref. 11.4, pg. 5-3) y = weight density of liquid, lb/ft3 (Ref. 11.4, pg. 5-3) ym = weight density of missile, lb/ft3 (Ref. 11.4, pg. 5-3) x = depth of missile center of gravity below the water surface, ft (Ref. 11.4, pg. 5-3, 5-5) 2 A0 = horizontal cross-sectional area of the missile (constant over length L), ft (Ref. 11.4, pg. 5-3)

CD = drag coefficient given in table 5-1 of the reference or other references on fluid mechanics which is a function of Lid, R and shape of the missile (Ref. 11.4, pg. 5-3, 5-4)

L = vertical length of the missile, ft (Ref. 11.4, pg. 5-3) d = characteristic dimension of the missile, for a rectangular surface d = width, ft (Ref. 11.4, pg. 5-3, 5-4)

R = Reynolds Number = (Vo

d ) / v (Ref. 11.4, pg. 5-3) v = kinematic viscosity of the liquid, ft2/s (Ref. 11.4, pg. 5-3)

Vo = initial velocity of the missile at x = 0, ft/s (Ref. 11.4, pg. 5-3, 5-5)

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 12 Vs = striking velocity of the missile at x = H, ft/s (Ref. 11.4, pg. 5-2)

V2 = terminal velocity, ft/s = [(g/a) * (1 - y/ym )]1/2 (Ref. 11.4, pg. 5-3)

H = depth of the fluid, ft (Ref. 11.4, pg. 5-3) a2 + b2 = C2 (Ref. 111.12, pg. 2-27)

Where:

a = triangle side length b = triangle side length c = triangle hypotenuse length Me = (Dx + 2d)

Mx Ref. 11.4 pg. 3-6 Where:

Me = Average effective mass of target during impact, lb Mx = Mass per unit length of steel beam, lb/in Dx = Maximum missile contact dimension in the x direction (longitudinal axis for beams),

inches d = depth of steel beam, inches E, = (Mm 2

VM2) / [ 2* (Mm + Me)] Ref. 11.4 pg. 3-5 Where:

Es = strain energy, in-lb Mm Mass of the missile, lb Me Effective mass of target during impact, lb Vs= Missile striking velocity, in/s

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 13 Rm = (8*I*fdy) / (L'd) Ref. 11.4 pg. E-3 Where:

Rm = plastic resisting force, 4

lb I = moment of inertia, in fdy = allowable dynamic strength value = (DIF)

fstat DIF = dynamic increase factor = 1 Fstat = static strength (yield strength), psi L = Length of beam, inches d = depth of steel beam, inches Xe RmL 3 / 48EI Ref. 11.4 pg. 4-5 Where:

Xe = yield displacement, in Rm = plastic resisting force, lb L = Length of beam, inches 2 E = modulus of elasticity,4 lb/in 1 = moment of inertia, in lgr = [(Es / (Xe

Rm)] + 0.5 Ref. 11.4 pg. 3-8 Where:

pr = required ductility ratio Es = strain energy, in-lb Rm = plastic resisting force, lb Xe = yield displacement, in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 14 Data L = Length of Spent Fuel Pool Gate = 24'-4 5/8" = 24.39 ft (Ref. 11.1, pg. All)

W = Width of Spent Fuel Pool Gate = 4'-9 %"= 4.771 ft (Ref. 11.1, pg. Al1)

T = Thickness of Spent Fuel Pool Gate = 4 /" = 0.3958 ft (Ref. 11.1, pg. 17)

MG = Weight of Spent Fuel Pool Gate = 1600 lbs (Ref. 11.1, pg. 28)

M= Estimated Total Weight of Spent Fuel Pool Gate and Rigging = 2000 lbs (Ref. 111.1, pg. 4);

M2= Buoyant Weight of Fuel Bundle = 562 lbs (Ref. 11.5, pg. 15)

Clad Yield Strength = 200 ft-lb (Ref. 11.5, pg. 15)

Spacing between Fuel Bundles = 6.25" = 0.5208 ft (Ref. 11.3, pg. 4)

L = Length of Intermediate Lifting Beam = 4'-9"= 4.75 ft (Ref. 11.2, pg. 6)

W = Width of Intermediate Lifting Beam = 5" = 0.4167 ft (Ref. 11.2, pg. 6)

D = Depth of Intermediate Lifting Beam = 5" = 0.4167 ft (Ref. 11.2, pg. 6)

Nominal Weight of HSS6x5x1/2 = 31.71 lbs/ft (Ref. 111.7, pg. 1-82)

W = Width of Alternate Lifting Beam = 4" = 0.333 ft (Ref. 111.7, pg. 1-26)

D = Depth of Alternate Lifting Beam = 6" = 0.5 ft (Ref. 111.7, pg. 1-26)

Nominal Weight of W6xl2 Steel Beam = 12 lbs/ft (Ref. 111.7, pg. 1-27)

U = Strairi Energy for Unit Volume (in*lb/in 3) = 19740 in-lb/in 3 (Ref. 11.7, pg. 4.2-240) t = thickness of cell assembly = 0.075 inches (Ref. 11.7, pg. 3.2-1)

Depth of poison material below top of rack = 16.22 inches (Ref. 11.7, pg. 4.2-235)

Elevation of Top of Fuel Racks = 177" + 70'1-5/16" = 84.86' (Ref. 11.8)

Elevation of bottom of Gate = 90' (Ref. 11.2, pg. 8)

Elevation of bottom of Intermediate Lifting Beam = 115' (Ref. 11.2, pg. 8)

Elevation of bottom of Alternate Lifting Beam = 123' (Ref. 11.2, pg. 12)

Acceleration of Gravity = 32.174 ft/sec 2 (Ref. 111.9, pg. B-10)

Impact Energy rating for Fuel Racks = 3800 ft-lb (Ref. 11.10, pg. 1-18)

Spent Fuel and Cask Pool floor elevation = 70' 0" or 70.0' (Ref. 11.11)

Spent Fuel Pool and Cask Pool floor steel liner thickness = 3/16" or 0.188" (Ref. 11.12)

Elevation of Fuel and Cask Pool Curb = 113' 4" (Ref. 11.13)

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 15 Approximate lift height above laydown floor elevation obstructions = 6" (Ref. 111.1, pg. 16)

Minimum water level above the top of irradiated fuel = > 23' (Ref. 111.10, pg. 3.7-15)

Stored fuel bundle upper tie plate elevation = 84.6645' (Ref. 11.3, pg. 4)

Maximum Spent Fuel Pool Water Temperature 155.6 deg. F (Ref. 11.14, pg. 5)

Density of water @ 160 deg. F 60.994 lb/ft 3 (Ref. 111.9, pg. A-6)

Kinematic viscosity of water @ 160 deg. F = 0.439 E-5 ft2/s (Ref. I11.11)

Allowable ductility ratio li for steel elements, members proportioned to preclude lateral and local buckling; Flexure, compression and shear * < 20 (Ref. 11.4 pg. 4-7)

Fuel Pool Cooling Lines Penetrating Spent Fuel Pool (Ref. 11.16)

SFC-012-001-3 SFC-012-014-3 SFC-012-006-3 SFC-012-007-3 Pipe Class (Spec. 228.000) of Spent Fuel Pool Cooling Piping

= Class 153 (Ref. 11.17)

Fuel Pool Cooling Piping Diameter and Schedule SFC-012-001-3 12" diameter Schedule STD (Ref. 11.23 pg. 16, 11.17)

SFC-012-014-3 12" diameter Schedule STD (Ref. 11.23 pg. 16, 11.17)

SFC-012-006-3 12" diameter Schedule STD (Ref. 11.23 pg. 16, 11.17)

SFC-012-007-3 12" diameter Schedule STD (Ref. 11.23 pg. 16, 11.17)

Fuel Pool Cooling Piping Material SFC-012-001-3 = SA312 Type 304 Stainless Steel (Ref. 11.23 pg. 167, 11.18)

SFC-012-014-3 = SA312 Type 304 Stainless Steel (Ref. 11.23 pg. 167, 11.19)

SFC-012-006-3 = SA312 Type 304 Stainless Steel (Ref. 11.23 pg. 167, 11.20)

SFC-012-007-3 = SA312 Type 304 Stainless Steel (Ref. 11.23 pg. 167,11.21)

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 16 Piping Parameters, 12" Schedule Standard (Ref. 111.9, pg. B-17)

Outer diameter = 12.75" Wall thickness = 0.375" Pipe weight per unit length = 49.56 4

lb / ft of length Moment of inertia (I) = 279.3 in Modulus of Elasticity, E, at 200 deg F for TP 304 SS = 27.7E6 Ibf / in2 (Ref. 111.12, pg. 6-92)

Material Properties, SA312 Type 304 Seamless Pipe (Ref. 111.13, pg. 76, 77)

Minimum Yield Strength = 30 ksi Minimum Ultimate Tensile Strength = 75 ksi Distance Fuel Pool Cooling Piping Extends into Pool SFC-012-001-3 = 1.302' (Ref. 11.18)

SFC-012-014-3 = 1.302' (Ref. 11.19)

SFC-012-006-3 = 1.5' (Ref. 11.20)

SFC-012-007-3 = 1.33' (Ref. 11.21)

Elevation of Fuel Pool Cooling Piping Connection to Liner Embed SFC-012-001-3 = 110' 0" (Ref. 11.18)

SFC-012-014-3 = 110' 0" (Ref. 11.19)

SFC-012-006-3 = 110'0" (Ref. 11.20, 11.22)

SFC-012-007-3 = 110'0" (Ref. 11.21)

Elevation of First Support below Liner Embed Connection SFC-012-001-3 = 86' 0" (Ref. 11.18)

SFC-012-014-3 = 86' 0" (Ref. 11.19)

SFC-012-006-3 = 92' 0" (Ref. 11.20,11.22)

SFC-012-007-3 = 92'0" (Ref. 11.21)

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 17 Meteorology Data (FB/RB X/Q Values) 3 EAB: (0 - 2 hours2.314815e-5 days 5.555556e-4 hours 3.306878e-6 weeks 7.61e-7 months ): 8.58E-04 sec/m (Ref. 11.6) 3 LPZ: (0 - 8 hours9.259259e-5 days 0.00222 hours 1.322751e-5 weeks 3.044e-6 months ): 1.1 3E-04 sec/m3 (Ref. 11.6)

(8 - 24 hours2.777778e-4 days 0.00667 hours 3.968254e-5 weeks 9.132e-6 months ): 7.89E-05 sec/mr3 (Ref. 11.6)

(1 - 4 days): 3.65E-05 sec/m3 (Ref. 11.6)

(4 - 30 days): 1.21 E-05 sec/m (Ref. 11.6) 3 CR: (0 -20 min): 1.62E-03 sec/m (Ref. 11.5_EC 14186 markup pg. 9) 3 (20 min - 8 hr): 4.05E-04 sec/m (Ref. 11.5_EC 14186 markup pg. 9) 3 (8 - 24 hours2.777778e-4 days 0.00667 hours 3.968254e-5 weeks 9.132e-6 months ): 3.OOE-04 sec/m (Ref. 11.5_EC 14186 markup pg. 9) 3 (1 - 4 days): 1.01 E-04 sec/m (Ref. 11.5_EC 14186 markup pg. 9) 3 (4 - 30 days): 1.62E-05 sec/m (Ref. 11.5_EC 14186 markup pg. 9)

Power Level: 31 00 MWt (Ref. 11.5_EC 14186 markup pg. 9)

Source Term: (Ref. 11.5_EC 14186 markup pg. 9) 24 Month Fuel Cycle Isotope Core Inventory (Ci/MW) at Time 0 1-131 2.70E+04 1-132 3.92E+04 1-133 5.52E+04 1-134 6.06E+04 1-135 5.17E+04 Kr-85 3.66E+02 Kr-85m 7.02E+03 Kr-87 1.35E+04 Kr-88 1.89E+04 Xe-133 5.26E+04 Xe-1 35 1.99E+04

3 Fuel Building Volume: 7.42E5 ft (Ref. 11.5_EC 14186 markup pg. 10)

CR Free Air Volume: 1.88E5 ft 3 (Ref. 11.5_EC 14186 markup pg. 10)

CR Filtration Credited Iodine Efficiency: 0% (Ref. 11.5_EC 14186 markup pg. 10)

CR Filtered Air Modeled Intake Flow: 1700 cfm (Ref. 11.5_EC 14186 markup pg. 11)

CR Unfiltered Air Modeled Inleakage Flow: 300 cfm (Ref. 11.5_EC 14186 markup pg. 11)

CR Total Modeled Intake Flow: 2000 cfm (Ref. 11.5_EC 14186 markup pg. 11)

CR Total Modeled Discharge Flow: 2000 cfm (Ref. 11.5_EC 14186 markup pg. 11)

Number of Bundles in Core: 624 (Ref. 11.5_EC 14186 markup pg. 17)

Core Radial Peaking Factor: 2.00 (Ref. 11.5_EC 14186 markup pg. 17)

Peak Assembly Burnup: - 62,000 MWd/t (Ref. 11.5_EC 14186 markup pg. 17)

Maximum Fuel Rod Pressurization: < 1200 psig (Ref. 11.5_EC 14186 markup pg. 17)

Minimum Spent Fuel Pool Water Depth: > 23 feet (Ref. 11.5_EC 14186 markup pg. 17, Ref. 111.10, pg. 3.7-15)

Number of Rods per Bundle for GE 9x9 Fuel: 74 (Ref. 11.5_EC 14186 markup pg. 17)

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 19 8.0 ASSUMPTIONS

1. The kinetic energy acquired by a falling fuel assembly may be dissipated in one or more impacts. This assumption is consistent with GE methodology used in GESSAR II 22A7007 (Ref. 111.8, Section 15.7.4.3.1).

2. The kinetic energy of a dropped assembly is assumed to be absorbed by only the cladding, non-fuel components of the assembly, and other pool structures (i.e., no energy is absorbed by the fuel). This assumption is consistent with GE methodology used in GESSAR II 22A7007 (Ref. 111.8, Section 15.7.4.3.1).

3. The fraction of the energy absorbed by the non-fuel parts of the assembly is assumed to be the same as the fraction of the structural material. As a result, the cladding absorbs 19/(19+5) of the energy absorbed during impact. This assumption is consistent with GE methodology used in GESSAR II 22A7007 (Ref. 111.8, Section 15.7.4.3.1).

4. For conservatism, dissipation of some of the mechanical energy of the falling Spent Fuel Pool Gate due to fluid drag is neglected. This assumption is consistent with GE methodology used in GESSAR II22A7007 (Ref. 111.8, Section 15.7.4.3.2).

5. For conservatism, the Spent Fuel Pool Storage racks are assumed to be 50% filled in Cases 2 and 4 (minimum impact fuel bundle cases) of the pool gate analysis. This condition would maximize the force of the gate on a fewer number of fuel bundles, failing a higher number of fuel rods.

6. In the design basis analysis, it is assumed that 50% of the energy is absorbed by the dropped fuel bundle and 50% by the struck assemblies. For conservatism, this analysis assumes that 100% of the energy is absorbed by the struck assemblies.

7. The decay time used in the radiological analysis is 14 days (336 hours0.00389 days 0.0933 hours 5.555556e-4 weeks 1.27848e-4 months ). This decay time is based upon the gate seal replacement being done with the plant on-line or in non-refueling outage conditions. The minimum realistic refueling outage duration is 14 days, thus the minimum decay time for newly discharged fuel bundles in the spent fuel pool is 14 days.

This is conservative based on the following:

Gate seal replacement is typically scheduled late in the operating cycle. As a result, the actual fuel decay time will be greater than the assumed 14 days.

The area of the gate and rigging members is significantly greater than the previously analyzed fuel bundle load drop, with a substantially larger number of fuel bundles impacted in the postulated gate and rigging drop scenario. A portion of these bundles will have been discharged prior to the most recent refueling outage with a minimum decay time exceeding 18 months. As a result, assuming all damaged bundles have a decay time of 14 days is conservative.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 20

8. Regulatory Guide 1.183-based Assumptions The following assumptions are documented in Ref. 11.5 EC 14186 markup Section 5.1 pages 18 and 19 with detailed summary of specific compliance to RG 1.183 located in Attachment C of the markup. The Attachment C discussion is applicable to the information reproduced below with the exception of the time after shutdown of 24 hours2.777778e-4 days 0.00667 hours 3.968254e-5 weeks 9.132e-6 months in Attachment C paragraph 3.3.a. For this analysis, the conformance statement is as follows:

3.3 The applicablerequirementsof Subsection 3.3 of Regulatory Position3 state:

a) Fornon-LOCA DBAs in which fuel damage is projected,the release from the fuel gap and the fuel pellet should be assumed to occur instantaneouslywith the onset of the projected damage. Conformance: In this analysis, all of the activity which is available for release from the fuel to the pool or reactor cavity is assumed to have been instantaneously released from the fuel gap to the water at the onset of the gate load drop analysis, 336 hours0.00389 days 0.0933 hours 5.555556e-4 weeks 1.27848e-4 months after shutdown. This assumption from RG 1.183 is met in its entirety.

8.1 The gap activity fractions of Table 3 in Regulatory Position 3 of RG 1.183 (Ref. 11.1.1) are utilized, as follows:

1-131 0.08 All other halogens 0.05 Kr-85 0.10 All other noble gases 0.05 8.2 All gap activity in the damaged fuel rods is assumed to be instantaneously released.

8.3 Radionuclides considered include the xenons, kryptons, halogens, cesiums, and rubidiums. However, all particulate radionuclides species (some halogens, cesiums, and rubidiums) are assumed to be retained in the fuel pool (infinite decontamination factor) consistent with RG 1.183 Appendix B Section 3 (Ref. 111.1). Also consistent with RG 1.183 Appendix B Section 3, all noble gases (xenons & kryptons) escape to the environment.

8.4 Of the radioiodine released from the damaged fuel rods, 99.85% of the released iodine is effectively assumed to be in the form of elemental iodine and 0.15% of the released iodine is assumed to be in the organic species (Ref. 111.1, Appendix B, Section 2.0).

8.5 Consistent with RG 1.183 Appendix B Section 4.1 and 5.3 (Ref. 111.1), all radionuclide releases from the pool to the environment are assumed to occur over a 2-hour period. This is accomplished via a 2-hour linear release from the pool to the building atmosphere with a simulated instantaneous release to the environment.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 21 8.6 Consistent with RG 1.183 Appendix B Section 2 (Ref. 111.1), the decontamination factor for organic iodine is assumed to be 1. The pool decontamination factor for elemental iodine is assumed such that the overall pool decontamination factor is 200 for all iodine species with a 23-foot water level above the postulated damaged fuel assembly.

8.7 The control room breathing rate is assumed to be 3.5E-04 m 3/sec. for the duration (Ref.

111.1, Section 4.2.6).

8.8 The offsite breathing rates are as follows (Ref. 111.1, Section 4.1.3):

0-8 hours: 3.5E-04 m3/sec 8-24 hours: 1.8E-04 m3/sec 1-30 days: 2.3E-04 m3/sec 8.9 Control Room Operator Occupancy Factors are as follows (Ref. 111.1, Section 4.2.6):

0-24 hours: 1.0 1-4 days: 0.6 4-10 days: 0.4 Note: The Occupancy Factorsare already included in the X/Q's. They will not be defined in the Control Room input, since in doing so they will be taken into account twice. Instead the occupancy factors in the RADTRAD model will be set to 1.0.

8.10 Iodine Species Breakdown (Ref. 111.1, Appendix B, Section 2):

Aerosol 0%

Elemental 57%

Organic 43%

9. The Intermediate Lifting Beam is TS5x5x1/2 per ER-RB-1996-082-000. This intermediate lifting beam is conservatively assumed to be HSS6x5x1/2 for the determination of the lifting beam mass only. The weight per foot of HSS6x5x1/2 bound the weight per foot of TS5x5x1/2.

Therefore, the mass calculation of this beam using HSS6x5x1/2 weight per foot is conservative.

10. In the fuel impact damage cases, the length of the Intermediate Lifting Beam is assumed to be 5 ft. This length is conservative because the actual length of this beam is 4'-9" per ER-RB-1996-082-000 pg. 6 and assuming a greater length maximizes the potential energy change.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 22

11. For the impact analysis on the pool liner and fuel storage racks, the density and viscosity water at 160 deg. F is used. This temperature exceeds the maximum pool temperature of the spent fuel pool water of 155.6 deg. F per Ref. 11.14, pg. 5. Use of density and viscosity values for a slightly higher water temperature than the maximum pool water temperature is conservative as it results in a higher impact velocity.

12. For the impact analysis on the pool liner cases, the nominal top of active fuel is treated as the stored fuel bundle upper tie plate at elevation 84.6645' per Ref. 11.3, pg. 4.

13. The purpose of this alternate lifting beam was to allow the option to have a rigging configuration that doesn't pull the crane hooks out of vertical. Per Ref. 11.2, pg. 8, the Bridge Crane hook and Cask Crane hook are 9'-2" apart. For conservatism, the alternate lifting beam is assumed to be 12' in length.

14. For the impact analysis on the pool liner cases, the gate weight is assumed to be the weight of the gate and rigging to maximize the velocity and density of the object, thereby maximizing the penetration thickness of the pool liner.

15. For the impact analysis on the Fuel Pool Cooling piping, a strike area of 2 square inches is assumed. This is reasonable based upon the curvature of the nominal 12" piping and as all of the force is assumed to be delivered to the piping, when some force will be absorbed by the gates.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 23 9.0 METHOD OF ANALYSIS As in the design basis Fuel Handling Accident analysis, the potential energy associated with a free air drop will be calculated first. The drop height will be based on the distance from the approximate elevation of the bottom of the gate to the elevation of the Fuel Bundles. Two sets of fall geometries will be analyzed. The first fall geometry will have an air-drop impact with only one laydown impact. The second fall geometry will have an air-drop impact with two laydown impacts. Based on the irregularities in the Spent Fuel Pool Gate's geometry, there is the potential for the gate to fall on its edge (rather than on its face) before resting with this largest surface area against the spent fuel. These laydown impacts are calculated with 100%

of the potential energy being transmitted into the impacted fuel rods.

These impact energies (multiplied by'a cladding to other structural material fraction) are then divided by the cladding yield strength to determine the number of fuel rod failures caused by compression. The fuel rod failures are totaled for each impact.

Three dropped objects are analyzed: the Spent Fuel Pool gate, an intermediate lifting beam, and an alternate lifting beam. The dimensions of W6x12 that is 12 ft in length are used for analysis of the Alternate Lifting Beam. The dimensions of TS5x5x1/2 are used for analysis of the Intermediate Lifting Beam. The bounding cases of all these dropped objects are totaled to determine the potential maximum number of failed fuel rods in compression.

The radiological analysis is performed utilizing the methodology described in calculation G13.18.9.5"059, Evaluation of Exclusion Area Boundary, Low Population Zone, and Control Room TEDE due to a Design Basis Fuel Handling Accident with Regulatory Guide 1.183 AST-based Assumptions (Ref. 11.5). Doses are evaluated at the Exclusion Area Boundary (EAB),

Low Population Zone (LPZ), and the Control Room (CR) using the NRC-developed computer Code RADTRAD (Ref. 111.3). These cases use the same methodology as the design basis Fuel Handling Accident (FHA) in the Fuel Building (FB) as described in USAR Section 15.7.4 with the following changes:

The number of rods damaged in the load drop event represent the calculated number of rods damaged for a drop of the gate and rigging plus a nominal 20% margin to account for future fuel design or rigging configuration changes.

" An assumed decay time of 14 days (336 hours0.00389 days 0.0933 hours 5.555556e-4 weeks 1.27848e-4 months ) rather than the 24 hour2.777778e-4 days 0.00667 hours 3.968254e-5 weeks 9.132e-6 months decay time assumed in the design basis FHA analysis.

A 2-hour linear release from the fuel pool to the building atmosphere is assumed with no credit taken for Fuel Building (FB) or Control Room (CR) filtration.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 24 The design basis decay time of 24 hours2.777778e-4 days 0.00667 hours 3.968254e-5 weeks 9.132e-6 months for Fuel Handling Accident analysis represents the earliest time that a fuel bundle discharged from the reactor could be handled during the refueling evolution. The gate seal replacement will be performed on-line or during non-refueling shutdown conditions. As a result, the assumed decay time will be 14 days. This time period is based upon the minimum realistic refueling outage duration.

The second portion of the load drop analysis is to assess the effect of the dropped load on the spent fuel pool, cask pool, and gate opening area liner. The River Bend Fuel Building pools are equipped with a 3/16" thick stainless steel liner. The liner is designed to provide a leak-proof barrier for the pools. If it is determined that the dropped load will not completely penetrate the stainless steel liner, no water leakage will result from the dropped load and consequently no water makeup to the pools as a result of the load drop event will be required.

The cask pool has been previously analyzed for a drop of a 250 ton fuel storage cask in Reference 11.15 with no adverse impact to the structural integrity of the concrete pool structure.

The cask drop analysis bounds the drop of all of the objects in the cask pool, gate area and spent fuel pool being analyzed in this calculation with respect to the concrete pool floor structure. As a result, this calculation will not analyze the concrete pool floor structure.

This portion of the calculation will also determine the impact velocities of the dropped objects on the fuel storage racks to be used in the effect on the fuel storage racks due to impact of the dropped objects.

The methodology used to determine the strike velocity on the submerged structures and the penetration in steel is from Reference 11.4, BC-TOP-9A Revision 2, September 1984, "Topical Report, Design of Structures for Missile Impact" for a missile impacting steel when dropping through air and/or water. This methodology does consider buoyancy and drag forces during the object travel through the water and is the same general methodology used in Reference 11.15 associated with the analysis of the concrete structure for the cask drop.

The third portion of the load drop analysis is to assess the effect on the spent fuel storage racks as a result of a drop of the gate, intermediate beam or alternate beam on the spent fuel storage racks to ensure that the required keff is maintained. This analysis compares the forces resulting from the subject dropped objects to the required force the racks must withstand per the rack design specification and analysis (References 11.7 and 11.10).

The final portion of the load drop analysis is to assess the effect on the Spent Fuel Pool Cooling piping that penetrates into the Spent Fuel Pool and has the potential to be struck by the gate in a secondary impact (i.e. transition to Position II or Position III as described in Section 10.1.1). Note that only a falling gate has adequate mass to result in any potential damage to the Spent Fuel Pool Cooling piping. The distance between the nearest potential drop point and the piping is determined for each of the lines. Then the elevation where the top of the gate impacts the line is then determined to assess if any potential damage is below the minimum pool water level. If any potential damage is below the minimum water level, no loss of cooling function will occur as water will still flow into/out of the damaged piping. The velocity of the impact of the gate on the piping is determined using the Reference 11.4, BC-TOP-9A

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 25 Revision 2, September 1984, "Topical Report, Design of Structures for Missile Impact" for a missile impacting steel when dropping through air and/or water. Note that this methodology is primarily for a missile impacting perpendicular to the target. In this case, the impact will not be directly perpendicular and thus, the velocity value will be conservative. The structural effect on the piping will be assessed using the methodology from Reference 11.4, treating the piping as a simply supported steel beam.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 26 10.0 Calculations 10.1 Damage to Fuel Bundles The damage to the spent fuel bundles will be analyzed first. Three dropped objects are analyzed: the Spent Fuel Pool gate, an intermediate lifting beam, and an alternate lifting beam.

10.1.1 Spent Fuel Pool Gate Fall Geometries The following geometric orientations of Spent Fuel Pool Gate (FNS-GATE1 or FNS-GATE2) will be analyzed for a potential maximum and minimum number of fuel bundle impacts. All analyzed cases will begin with an impact in Position 1 and a final impact in Position 3. Two analyzed cases will incorporate a possible impact in Position 2 after Position 1 and before Position 3. There will be a total of 4 load drop cases analyzed.

Position 1 Position 2 Position 3

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 27 In the table below, the specifics of each load case are detailed.

Position Position 2 Position 3 Max or Min Impacted Fuel I Impact Impact Impact Bundles Case I x x Max Case 2 x x Min Case 3 x x x Max Case 4 x x x Min Maximum Impacted Fuel Bundles Position 1:

In order to estimate the maximum number of impacted fuel bundles for this geometry, the width and thickness must be divided by spacing between bundles.

(Width of Gate) / (Spacing between bundles)

(4.771 ft) / (0.5208 ft) = 9.161 or 10 bundles (Thickness of Gate) / (Spacing between bundles)

(0.3958 ft) / (0.5208 ft) = 0.7599 or 1 bundle Because the thickness of the gate is over half the spacing of fuel bundles, it has the maximum potential to hit two rows of fuel bundles.

Total Bundles = (10 bundles)(2 bundles) = 20 impacted fuel bundles lI I I l!!IllI I I!II

-........ I I I - - I-.-

1 1 1 1 1 111111

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 28 Position 2:

In order to estimate the maximum number of impacted fuel bundles for this geometry, the length and thickness must be divided by spacing between bundles.

(Length of Gate) / (Spacing between bundles)

(24.39 ft) / (0.5208 ft) = 46.83 or 47 bundles Because the fractional unit of length of the gate is over half the spacing of fuel bundles, it has the maximum potential to hit 48 rows of fuel bundles.

(Thickness of Gate) / (Spacing between bundles)

(0.3958 ft) / (0.5208 ft) = 0.7599 or 1 bundle Because the thickness of the gate is over half the spacing of fuel bundles, it has the maximum potential to hit two rows of fuel bundles.

Total Bundles = (48 bundles)(2 bundles) = 96 impacted fuel bundles Position 3:

In order to estimate the maximum number of impacted fuel bundles for this geometry, the length and width must be divided by spacing between bundles.

(Length of Gate) / (Spacing between bundles)

(24.39 ft) / (0.5208 ft) = 46.83 or 47 bundles

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 29 For the maximized case this object has the potential to hit 48 rows of fuel bundles (impact across the full width of 46 bundles and partial width of one bundle on each end)

(Width of Gate) / (Spacing between bundles)

(4.771 ft) / (0.5208 ft) = 9.161 or 10 bundles Total Bundles = (48 bundles)(10 bundles) = 480 impacted fuel bundles Sý F7 at"-4 A!ý'i on AM No Agginamak.ý'l I A- eqv-ý NR M WK, VA V 92im Mmi 14, a a M M Mogen 2,A4ýMMMMEN omit MmVvit:- V '2: A.-a INa INMI'M M a M M 0 MY'A a W.a x-y M a MFo ps "AV M M91 ie- u a a 'ýia I MMEMEMInnffin Mn!E3=Mr3K=M:!1 M1C"3=K'M2 NZZ711

=82=a111Z Emmons Mommmmm Ann mono nommosommummms Minimum Impacted Fuel Bundles The minimum number of impacted fuel bundles for each position is obtained by conservatively assuming that 50% of the Spent Fuel Pool racks are filled Position 1:

In order to estimate the minimum number of impacted fuel bundles for this geometry, the width and thickness must be divided by spacing between bundles.

(Width of Gate) / (Spacing between bundles)

(4.771 ft) / (0.5208 ft) = 9.161 or 10 bundles (Thickness of Gate) / (Spacing between bundles)

(0.3958 ft) / (0.5208 ft) = 0.7599 or I bundle Total Bundles = (0.50)(10 bundles)(1 bundle) = 5 impacted fuel bundles

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 30 Position 2:

In order to estimate the minimum number of impacted fuel bundles for this geometry, the length and thickness must be divided by spacing between bundles.

(Length of Gate) / (Spacing between bundles)

(24.39 ft) / (0.5208 ft) = 46.83 or 47 bundles (Thickness of Gate) / (Spacing between bundles)

(0.3958 ft) / (0.5208 ft) = 0.7599 or I bundle Total Bundles = (0.50)(47 bundles)(1 bundle)= 23 impacted fuel bundles

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CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 31 Position 3:

In order to estimate the minimum number of impacted fuel bundles for this geometry, the length and width must be divided by spacing between bundles.

(Length of Gate) / (Spacing between bundles)

(24.39 ft) / (0.5208 ft) = 46.83 or 47 bundles (Width of Gate) I (Spacing between bundles)

(4.771 ft) / (0.5208 ft) = 9.161 or 10 bundles Total Bundles = (0.50)(47 bundles)(10 bundles) = 235 impacted fuel bundles Max Impacted Fuel Min Impacted Fuel Bundles Bundles Position I Impact 20 5 Position 2 Impact 96 23 Position 3 Impact 480 235

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 32 Initial Potential Energv PE = M1

Hd M, = Mass of Gate and Rigging Equipment = 2000 lbs Hd = (Elev. bottom of Pool Gate - Elev. top of Fuel Racks) = (90' - 84.27') = 5.73 ft use 6 ft PE = (2000 Ib)(6.00 ft)

PE = 12000 ft-lb Energy Difference The energy absorbed during the impact is determined based upon the relationship as given in the design basis Fuel Handling Accident analysis. For conservatism, M1 (weight of the Spend Fuel Pool Gate and associate rigging equipment) has been maximized and M2 (buoyant weight of the fuel bundles) has minimized.

Edif= 1 - [M 1 / (M 1 + M2 )

M= Mass of Gate and Rigging Equipment = 2000 lbs M2= Mass of Impacted Fuel Bundles = (# of fuel bundles)(562 lbs/bundle)

Case 1 This case analyzes the free air drop resulting in a position 1 impact, and one laydown impact in position 3 with maximized fuel bundle impacts.

For the first impact:

Edif = 1 - [2000 lb / (2000 lb + (20 bundles)(562 Ib)]

Edif= 1 - [0.1511]

Edif = 0.8489 For the second impact:

Edif = 1 - [2000 lb / (2000 lb + (480 bundles)(562 Ib)]

Edif = 1- [0.0074]

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 33 Edif = 0.9926 Essentially all of the second impact energy would be absorbed. As a result, third or subsequent impacts need not be considered.

Enerqy Absorbed The first impact absorbs 84.89% of the initial energy or, Eabs = (PE)(0.8489)

Eabs = (12000 ft-lb)(0.8489)

Eabs = 10187 ft-lb Fcomp = [(Eabs)(19/(19+5))] / 200 ft-lb Fcomp = [(10187 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 40.32 or 41 rods The second impact involves a rebound consisting of 15.11% of the initial drop energy and the laydown drop energy. The laydown drop provides additional energy due to the potential energy change resulting from the change of the Spent Fuel Pool Gate center of gravity of approximately 1/2 of the Spent Fuel Pool Gate length.

Potential Eneray Change CG 1 = Center of Gravity (Position One) = (L / 2) = (24.39 ft) /2 = 12.20 ft CG 3 = Center of Gravity (Position Three) = (T / 2) = (0.3958 ft) / 2 = 0.1979 ft CGA = Change in Center of Gravity = CGI - CG 3 = 12.20 ft - 0.1979 ft = 12.00 ft Change in Potential Energy = (CGA)(M,) = 24000 ft-lb The second impact:

E2nd = (0.1511)(PE) + 24000 ft-lb E2nd = (0.1511)(12000 ft-lb) + 24000 ft-lb E2nd = 25813 ft-lb Fcomp = [(E2nd)(19/(19+5))] / 200 ft-lb

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 34 Fcomp = [(25813 ft-lb)(19/(19+5))] /200 ft-lb Fcomp = 102.2 or 103 rods The total fuel rod failures during this scenario are:

Total Fuel Rod Failures = (1st Impact) + (2 nd Impact) =

Total Fuel Rod Failures = (41) + (103) = 144 rods Case 2 This case analyzes the free air drop resulting in a position 1 impact, and one laydown impact in position 3 with minimized fuel bundle impacts.

For the first impact:

Edif = 1 - [2000 lb /(2000 lb + (5 bundles)(562 Ib)]

Edif = 1 - [0.4158]

Edif = 0.5842 For the second impact:

Edif = 1 - [2000 lb / (2000 lb + (235 bundles)(562 Ib)]

Edif = 1 - [0.0149]

Edif = 0.9851 Essentially all of the second impact energy would be absorbed. As a result, third or subsequent impacts need not be considered.

Enerqgy Absorbed The first impact absorbs 58.42% of the initial energy or, Eabs = (PE)(0.5842)

Eabs = (12000 ft-lb)(0.5842)

Eabs = 7010 ft-lb

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 35 Fcomp = [(Eabs)(l 9/(19+5))] / 200 ft-lb Fcomp = [(7010 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 27.75 or 28 rods The second impact involves a rebound consisting of 41.58% of the initial drop energy and the laydown drop energy. The laydown drop provides additional energy due to the potential energy change resulting from the change of the Spent Fuel Pool Gate center of gravity of approximately 1/2 of the Spent Fuel Pool Gate length.

Potential Energy Change CG, = Center of Gravity (Position One) = (L /2) = (24.39 ft) / 2 = 12.20 ft CG 3 = Center of Gravity (Position Three) = (T / 2) = (0.3958 ft) / 2 = 0.1979 ft CGA = Change in Center of Gravity = CG 1 - CG 3 = 12.20 ft - 0.1979 ft = 12.00 ft Change in Potential Energy = (CGA)(Ml) = 24000 ft-lb The second impact:

E2nd = (0.4158)(PE) + 24000 ft-lb E2nd = (0.4158)(12000 ft-lb) + 24000 ft-lb E2nd = 28990 ft-lb Fcomp = [(E2nd)(19/(19+5))] / 200 ft-lb Fcomp = [(28990 ft-lb)(19/(19+5))] /200 ft-lb Fcomp = 114.8 or 115 rods The total fuel rod failures during this scenario are:

Total Fuel Rod Failures = ( 1 st Impact) + (2 nd Impact) =

Total Fuel Rod Failures = (28) + (115) = 143 rods

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 36 Case 3 This case analyzes the free air drop resulting in a position 1 impact, and two laydown impacts in position 2 and 3 with maximized fuel bundle impacts.

For the first impact:

Edif = 1 - [2000 lb / (2000 lb + (20 bundles)(562 Ib)]

Edif = 1 - [0.1511]

Edif = 0.8489 For the second impact:

Edif = 1 - [2000 lb / (2000 lb + (96 bundles)(562 Ib)]

Edif = 1 - [0.0357]

Edif = 0.9643 For the third impact:

Edif = 1 - [2000 lb / (2000 lb + (480 bundles)(562 Ib)]

Edif = 1- [0.0074]

Edif = 0.9926 Essentially all of the third impact energy would be absorbed. As a result, fourth or subsequent impacts need not be considered.

Eneray Absorbed The first impact absorbs 84.89% of the initial energy or, Eabs = (PE)(0.8489)

Eabs = (12000 ft-lb)(0.8489)

Eabs = 10187 ft-lb Fcomp = [(Eabs)(19/(19+5))] / 200 ft-lb

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 37 Fcomp = [(10187 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 40.32 or 41 rods The second impact involves a rebound consisting of 15.11% of the initial drop energy and the laydown drop energy. The laydown drop provides additional energy due to the potential energy change resulting from the change of the Spent Fuel Pool Gate center of gravity of approximately 1/2 of the Spent Fuel Pool Gate length.

Potential Energy Change CG 1 = Center of Gravity (Position One) = (L 2) = (24.39 ft) / 2 = 12.20 ft CG 2 = Center of Gravity (Position Two) = (W / 2) = (4.771 ft) / 2 = 2.386 ft CGa = Change in Center of Gravity = CG 1 - CG 2 = 12.20 ft - 2.386 ft = 9.814 ft Change in Potential Energy = (CGA)(Ml) = 19628 ft-lb The second impact:

E2nd = (0.1511)(PE) + 19628 ft-lb E2nd = (0.1511)(12000 ft-lb) + 19628 ft-lb E2nd = 21441 ft-lb Fcomp = [(E2nd)(19/(19+5))] /200 ft-lb Fcomp = [(21441 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 84.87 or 85 rods The third impact involves a rebound consisting of 3.57% of the initial drop energy and the laydown drop energy. The laydown drop provides additional energy due to the potential energy change resulting from the change of the Spent Fuel Pool Gate center of gravity of approximately 1/2 of the Spent Fuel Pool Gate length.

Potential Energy Change

.CG 2 = Center of Gravity (Position Two) = (W / 2) = (4.771 ft) / 2 = 2.386 ft CG 3 = Center of Gravity (Position Three) = (T / 2) = (0.3958 ft) / 2 = 0.1979 ft CGA = Change in Center of Gravity = CG 2 - CG 3 = 2.386 ft - 0.1979 ft = 2.188 ft

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 38 Change in Potential Energy = (CGA)(M1) = 4376 ft-lb The third impact:

E3rd = (0.0357)(PE) + 4376 ft-lb E3rd = (0.0357)(12000 ft-lb) + 4376 ft-lb E3rd = 4804 ft-lb Fcomp = [(E3rd)(19/(19+5))] /200 ft-lb Fcomp = [(4804 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 19.02 or 20 rods The total fuel rod failures during this scenario are:

Total Fuel Rod Failures = (1st Impact) + (2 nd Impact) + (3 rd Impact) =

Total Fuel Rod Failures = (41) + (85) + (20) = 146 rods Case 4 This case analyzes the free air drop resulting in a position 1 impact, and two laydown impacts in position 2 and 3 with maximized fuel bundle impacts.

For the first impact:

Edif = 1 - [2000 lb / (2000 lb + (5 bundles)(562 Ib)]

Edif = 1 - [0.4160]

Edif = 0.5840 For the second impact:

Edif = 1 - [2000 lb / (2000 lb + (23 bundles)(562 Ib)]

Edif = 1 - [0.1340]

Edif = 0.8660

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 39 For the third impact:

Edif = 1 - [2000 lb / (2000 lb + (235 bundles)(562 Ib)]

Edif = 1 - [0.0149]

Edif = 0.9851 Essentially all of the third impact energy would be absorbed. As a result, fourth or subsequent impacts need not be considered.

Energy Absorbed The first impact absorbs 58.40% of the initial energy or, Eabs = (PE)(0.5840)

Eabs = (12000 ft-lb)(0.5840)

Eabs = 7008 ft-lb Fcomp = [(Eabs)(1 9/(19+5))] / 200 ft-lb Fcomp = [(7008 ft-lb)(1 9/(19+5))] / 200 ft-lb Fcomp = 27.74 or 28 rods The second impact involves a rebound consisting of 41.60% of the initial drop energy and the laydown drop energy. The laydown drop provides additional energy due to the potential energy change resulting from the change of the Spent Fuel Pool Gate center of gravity of approximately 1/2 of the Spent Fuel Pool Gate length.

Potential Energy Change CG 1 = Center of Gravity (Position One) = (L / 2) = (24.39 ft) / 2 = 12.20 ft CG 2 = Center of Gravity (Position Two) = (W / 2) = (4.771 ft) / 2 = 2.386 ft CGA = Change in Center of Gravity = CG 1 - CG 2 = 12.20 ft - 2.386 ft = 9.814 ft Change in Potential Energy = (CGA)(M,) = 19628 ft-lb The second impact:

E2nd = (0.4160)(PE) + 19628 ft-lb

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 40 E2nd = (0.4160)(12000 ft-lb) + 19628 ft-lb E2nd = 24620 ft-lb Fcomp = [(E2nd)(1 9/(19+5))] / 200 ft-lb Fcomp = [(24620 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 97.45 or 98 rods The third impact involves a rebound consisting of 8.66% of the initial drop energy and the laydown drop energy. The laydown drop provides additional energy due to the potential energy change resulting from the change of the Spent Fuel Pool Gate center of gravity of approximately 1/2 of the Spent Fuel Pool Gate length.

Potential Enerqy Change CG 2 = Center of Gravity (Position Two) = (W / 2) = (4.771 ft) / 2 = 2.386 ft CG 3 = Center of Gravity (Position Three) = (T / 2) = (0.3958 ft) / 2 = 0.1979 ft CGa = Change in Center of Gravity = CG 2 - CG 3 = 2.386 ft - 0.1979 ft = 2.188 ft Change in Potential Energy = (CGA)(Ml) = 4376 ft-lb The third impact:

E3rd = (0.0866)(PE) + 4376 ft-lb E3rd = (0.0866)(12000 ft-lb) + 4376 ft-lb E3rd = 5415 ft-lb Fcomp = [(E3rd)(19/(19+5))] /200 ft-lb Fcomp = [(5415 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 21.43 or 22 rods The total fuel rod failures during this scenario are:

Total Fuel Rod Failures = (1st Impact) + (2 nd Impact) + (3 rd Impact) =

Total Fuel Rod Failures = (28) + (98) + (22) = 149 rods

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 41 Damaged Fuel Rods Case 1 144 Case 2 143 Case 3 146 Case 4 148

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 42 10.1.2 Alternate Lifting Beam Fall Geometries Lifting beams are long, slender members. For this reason, only two positions will be analyzed.

Since the width and depth of both beams has the same potential for impacting rods, there is no need to analyze a position 3.

Position 1 Position 2 Position 1: Impact of beam on its end (width

depth).

Position 2: Impact of beam on its side (length

width).

Position Position 2 Max or Min Impacted Fuel 1 Impact Impact Bundles Case I x x Max Case 2 x Max Case 3 x x Min Case 4 x Min Initial Potential Energy PE = M,

Hd A W6x1 2 beam (12 ft long) is used for calculation of the Alternate Lifting Beam.

M, = Mass of Beam and Rigging Equipment = (12 ft)(12 Ibs/ft) = 144 lbs use 200 lbs

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 43 Hd = (Elev. bottom of Beam - Elev. top of Fuel Racks) = (123' - 84.27') = 38.73 ft use 39 ft PE = (200 lbs)(39 ft)

PE = 7800 ft-lb Energy Difference The energy absorbed during the impact is determined using the same relationship as given in the design basis Fuel Handing Accident analysis. For conservatism, M1 (weight of the Spend Fuel Pool Gate and associate rigging equipment) has been maximized and M2 (buoyant weight of the fuel bundles) has minimized.

Edif= 1 - [M 1 / (M1 + M2 )]

M= Mass of Gate and Rigging Equipment = 200 lbs M2= Mass of Impacted Fuel Bundles = (# of fuel bundles)(562 lbs/bundle)

Geometry Position 1:

In order to estimate the maximum/minimum number of impacted fuel bundles for this geometry, the width and thickness must be divided by spacing between bundles.

(Width of Beam) / (Spacing between bundles)

(0.333 ft) / (0.5208 ft) = 0.6394 or 1 bundle Because the width of the beam is over half the spacing of fuel bundles, it has the maximum potential to hit two rows of fuel bundles.

(Depth of Beam)./ (Spacing between bundles)

(0.5 ft) / (0.5208 ft) = 0.9601 or 1 bundle Because the depth of the beam is over half the spacing of fuel bundles, it has the maximum potential to hit two rows of fuel bundles.

Maxiumum Impacted Bundles = (2 bundles)(2 bundles) = 4 impacted fuel bundles Minimum Impacted Bundles = (1 bundle)(1 bundle) = 1 bundle

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 44 Position 2:

In order to estimate the maximum/minimum number of impacted fuel bundles for this geometry, the length and width/depth must be divided by spacing between bundles. Because the width and depth of the beam have the same potential to impact fuel bundles, no position 3 will be analyzed.

(Width of Beam) / (Spacing between bundles)

(0.333 ft) / (0.5208 ft) = 0.6394 or I bundle Because the width of the beam is over half the spacing of fuel bundles, it has the maximum potential to hit two rows of fuel bundles.

(Length of Beam) / (Spacing between bundles)

(12 ft) / (0.5208 ft) = 23.04 or 24 bundles Maxiumum Impacted Bundles = (2 bundles)(24 bundles) = 48 impacted fuel bundles Minimum Impacted Bundles = (1 bundle)(24 bundle) = 24 bundle Case 1 This case analyzes the free air drop impact and one laydown impact with maximized fuel bundle impacts.

For the first impact:

Edif = I - [200 lb / (200 lb + (4 bundles)(562 Ib)]

Edif = 1 - [0.0817]

Edif = 0.9183 For the second impact:

Edif = 1 - [200 lb / (200 lb + (48 bundles)(562 Ib)]

Edif = 1 - [0.0074]

Edif = 0.9926 Essentially all of the second impact energy would be absorbed. As a result, third or subsequent impacts need not be considered.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 45 Energy Absorbed The first impact absorbs 91.83% of the initial energy or, Eabs = (PE)(0.9183)

Eabs = (7800 ft-lb)(0.9183)

Eabs = 7163 ft-lb Fcomp = [(Eabs)(19/(19+5))] / 200 ft-lb Fcomp = [(7163 ft-lb)(19/(19+5))] /200 ft-lb Fcomp = 28.35 or 29 rods The second impact involves a rebound consisting of 8.17% of the initial drop energy and the laydown drop energy. The laydown drop provides additional energy due to the potential energy change resulting from the change of the Spent Fuel Pool Gate center of gravity of approximately 2of the Spent Fuel Pool Gate length.

Potential Energy Change CG 1 = Center of Gravity (Position One) = (L / 2) = (12 ft) / 2 = 6 ft CG 3 = Center of Gravity (Position Three) = (T / 2) = (0.3333 ft) / 2 = 0.1667 ft CGA = Change in Center of Gravity = CG 1 - CG 3 = 6 ft - 0.1667 ft = 5.833 ft Change in Potential Energy = (CGA)(M 1 ) = 1167 ft-lb The second impact:

E2nd = (0.0817)(PE) + 1167 ft-lb E2nd = (0.0817)(7800 ft-lb) + 1167 ft-lb E2nd = 1804 ft-lb Fcomp = [(E2nd)(19/(19+5))] / 200 ft-lb Fcomp = [(1804 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 7.14 or 8 rods The total fuel rod failures during this scenario are:

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 46 Total Fuel Rod Failures = (Ist Impact) + (2 nd Impact) =

Total Fuel Rod Failures = (29) + (8) = 37 rods Case 2 This case analyzes the free air drop impact with the maximum potential for impacted fuel rods.

For the first impact:

Edif = 1 - [200 lb / (200 lb + (48 bundles)(562 Ib)]

Edif = 1 - [0.0074]

Edif = 0.9926 Essentially all of the first impact energy would be absorbed. As a result, second or subsequent impacts need not be considered.

Energy Absorbed The first impact absorbs 99.26% of the initial energy or, Eabs = (PE)(0.9926)

Eabs = (7800 ft-lb)(0.9926)

Eabs = 7742 ft-lb Fcomp = [(Eabs)(19/(19+5))] / 200 ft-lb Fcomp = [(7742 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 30.65 or 31 rods Case 3 This case analyzes the free air drop impact and one laydown impact with minimized fuel bundle impacts.

For the first impact:

Edif = 1 - [200 lb / (200 lb + (1 bundles)(562 Ib)]

Edif = 1 - [0.2625]

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 47 Edif = 0.7375 For the second impact:

Edif = 1 - [200 lb / (200 lb + (24 bundles)(562 Ib)]

Edif = 1 - [0.0146]

Edif = 0.9854 Essentially all of the second impact energy would be absorbed. As a result, third or subsequent impacts need not be considered.

Energy Absorbed The first impact absorbs 73.75% of the initial energy or, Eabs = (PE)(0.7375)

Eabs = (7800 ft-lb)(0.7375)

Eabs = 5753 ft-lb Fcomp = [(Eabs)(1 9/(19+5))] / 200 ft-lb Fcomp = [(5753 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 22.77 or 23 rods The second impact involves a rebound consisting of 26.25% of the initial drop energy and the laydown drop energy. The laydown drop provides additional energy due to the potential energy change resulting from the change of the Spent Fuel Pool Gate center of gravity of approximately /2 of the Spent Fuel Pool Gate length.

Potential Energy Change CG 1 = Center of Gravity (Position One) = (L / 2) = (12 ft) / 2 = 6 ft CG 3 = Center of Gravity (Position Three) = (T / 2) = (0.3333 ft) / 2 = 0.1667 ft CGA = Change in Center of Gravity = CG 1 - CG 3 = 6 ft - 0.1667 ft = 5.833 ft Change in Potential Energy = (CGA)(M 1 ) = 1167 ft-lb

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 48 The second impact:

E2nd = (0.2625)(PE) + 1167 ft-lb E2nd = (0.2625)(7800 ft-lb) + 1167 ft-lb E2nd = 3215 ft-lb Fcomp = [(E2nd)(1 9/(19+5))] / 200 ft-lb Fcomp = [(3215 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 12.73 or 13 rods The total fuel rod failures during this scenario are:

Total Fuel Rod Failures = (1st Impact) + ( 2fnd Impact) =

Total Fuel Rod Failures = (23) + (13) = 36 rods Case 4 This case analyzes the free air drop impact with the minimum potential for impacted fuel rods.

For the first impact:

Edif = 1 - [200 lb / (200 lb + (24 bundles)(562 Ib)]

Edif = I - [0.0.146]

Edif = 0.9854 Essentially all of the first impact energy would be absorbed. As a result, second or subsequent impacts need not be considered.

Energy Absorbed The first impact absorbs 98.54% of the initial energy or, Eabs = (PE)(0.9854)

Eabs = (7800 ft-lb)(0.9854)

Eabs = 7686 ft-lb Fcomp = [(Eabs)(191(19+5))] /200 ft-lb

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 49 Fcomp = [(7686 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 30.42 or 31 rods Damaaed Fuel Rods Case 1 37 Case2 131 Case 3 36 Case 4 31

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 50 10.1.3 Intermediate Lifting Beam Fall Geometries Lifting beams are long, slender members. For this reason, only two positions will be analyzed.

Since the width and depth of both beams has the same potential for impacting rods, there is no need to analyze a position 3.

Position 1: Impact of beam on its end (width

depth).

Position 2: Impact of beam on its side (length

width).

Position Position 2 Max or Min Impacted Fuel I Impact Impact Bundles Case I x x Max Case 2 x Max Case 3 x x Min Case 4 x Min Initial Potential Energy PE = M,

Hd A HSS6x5x1/2 beam (5 ft long) is used for calculation of the Intermediate Lifting Beam.

M, = Mass of Beam and Rigging Equipment = (5 ft)(31.71 lbs/ft) = 158.55 lbs use 175 lbs Hd = (Elev. bottom of Beam - Elev. top of Fuel Racks) = (115' - 84.27') = 30.73 ft use 31 ft PE = (175 lb)(31 ft)

PE = 5425 ft-lb

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 51 Energy Difference The energy absorbed during the impact is assumed to be the same relationship as given in the original calculation. For conservatism, M1 (weight of the Spend Fuel Pool Gate and associate rigging equipment) has been maximized and M2 (buoyant weight of the fuel bundles) has minimized.

Edif= 1 - [M1 / (M1 + M2 )]

M= Mass of Beam and Rigging Equipment = (5 ft)(31.71 Ibs/ft) = 158 lbs (175 lbs is conservatively used for all further calculation)

M2 = Mass of Impacted Fuel Bundles = (# of fuel bundles)(562 lbs/bundle)

Geometry Position 1:

In order to estimate the maximum/minimum number of impacted fuel bundles for this geometry, the width and thickness must be divided by spacing between bundles.

(Width of Beam) / (Spacing between bundles)

(0.4167ft) / (0.5208 ft) = 0.8001 or 1 bundle For the maximized case this object has the potential to hit two rows of fuel bundles (impact across the partial width of two bundles)

(Depth of Beam) / (Spacing between bundles)

(0.4167 ft) / (0.5208 ft) = 0.8001 or 1 bundle For the maximized case this object has the potential to hit two rows of fuel bundles (impact across the partial width of two bundles)

Maxiumum Impacted Bundles = (2 bundles)(2 bundles) = 4 impacted fuel bundles Minimum Impacted Bundles = (1 bundle)(1 bundle) = 1 bundle

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 52 Position 2:

In order to estimate the maximum/minimum number of impacted fuel bundles for this geometry, the length and width/depth must be divided by spacing between bundles. Because the width and depth of the beam have the same potential to impact fuel bundles, no position 3 will be analyzed.

(Width of Beam) / (Spacing between bundles)

(0.4167ft) / (0.5208 ft) = 0.8001 or I bundle For the maximized case this object has the potential to hit two rows of fuel bundles (impact across the partial width of two bundles)

(Length of Beam) / (Spacing between bundles)

(5 ft) / (0.5208 ft) = 9.601 or 10 bundles For the maximized case this object has the potential to hit eleven rows of fuel bundles (Impact across the full width of 9 bundles and partial width of one bundle on each end.)

Maxiumum Impacted Bundles = (2 bundles)(1 1 bundles) = 22 impacted fuel bundles Minimum Impacted Bundles = (1 bundle)(10 bundle) = 10 bundles Case 1 This case analyzes the free air drop impact and one laydown impact with maximized fuel bundle impacts.

For the first impact:

Edif = I - [175 lb / (175 lb + (4 bundles)(562 Ib)]

Edif = 1 - [0.0722]

Edif = 0.9278 For the second impact:

Edif = 1 - [175 lb / (175 lb + (22 bundles)(562 Ib)]

Edif = 1 - [0.0140]

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 53 Edif = 0.986 Essentially all of the second impact energy would be absorbed. As a result, third or subsequent impacts need not be considered.

Energy Absorbed The first impact absorbs 92.78% of the initial energy or, Eabs = (PE)(0.9278)

Eabs = (5425 ft-lb)(0.9278)

Eabs = 5033 ft-lb Fcomp = [(Eabs)(19/(19+5))] / 200 ft-lb Fcomp = [(5033 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 19.92 or 20 rods The second impact involves a rebound consisting of 7.22% of the initial drop energy and the laydown drop energy. The laydown drop provides additional energy due to the potential energy change resulting from the change of the Spent Fuel Pool Gate center of gravity of approximately 1/2 of the Spent Fuel Pool Gate length.

Potential Energy Change CG 1 = Center of Gravity (Position One) = (L / 2) = (5 ft) / 2 = 2.5 ft CG 3 = Center of Gravity (Position Three) = (T / 2) = (0.4167 ft) / 2 = 0.2084 ft CGA = Change in Center of Gravity = CG 1 - CG 3 = 2.5 ft - 0.2084 ft = 2.292 ft Change in Potential Energy = (CGA)(M 1) = 401 ft-lb The second impact:

E2nd = (0.0722)(PE) + 401 ft-lb E2nd = (0.0722)(5425 ft-lb) + 401 ft-lb E2nd = 792.7 ft-lb Fcomp = [(E2nd)(19/(19+5))] / 200 ft-lb

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 54 Fcomp = [(792.7 ft-lb)(19/(19+5))] /200 ft-lb Fcomp = 3.14 or 4 rods The total fuel rod failures during this scenario are:

Total Fuel Rod Failures = (1st Impact) + (2 nd Impact) =

Total Fuel Rod Failures = (20) + (4) = 24 rods Case 2 This case analyzes the free air drop impact with the maximum potential to impact fuel bundles.

For the first impact:

Edif = 1- [175 lb / (175 lb + (22 bundles)(562 Ib)]

Edif = 1 - [0.0140]

Edif = 0.986 Essentially all of the first impact energy would be absorbed. As a result, second or subsequent impacts need not be considered.

Energy Absorbed The first impact absorbs 98.60% of the initial energy or, Eabs = (PE)(0.9860)

Eabs = (5425 ft-lb)(0.9860)

Eabs = 5349 ft-lb Fcomp = [(Eabs)(1 9/(19+5))] / 200 ft-lb Fcomp = [(5349 ft-lb)(1 9/(19+5))] / 200 ft-lb Fcomp = 21.17 or 22 rods

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 55 Case 3 This case analyzes the free air drop impact and one laydown impact with minimized fuel bundle impacts.

For the first impact:

Edif = 1 - [175 lb / (175 lb + (1 bundles)(562 Ib)]

Edif = 1 - [0.2374]

Edif = 0.7626 For the second impact:

Edif = 1 -[175 lb /(175 lb + (10 bundles)(562 Ib)]

Edif = 1 - [0.0302]

Edif = 0.9698 Essentially all of the second impact energy would be absorbed. As a result, third or subsequent impacts need not be considered.

Energy Absorbed The first impact absorbs 76.26% of the initial energy or, Eabs = (PE)(0.7626)

Eabs = (5425 ft-lb)(0.7626)

Eabs = 4137 ft-lb Fcomp = [(Eabs)(1 9/(19+5))] / 200 ft-lb Fcomp = [(4137 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 16.38 or 17 rods The second impact involves a rebound consisting of 23.74% of the initial drop energy and the laydown drop energy. The laydown drop provides additional energy due to the potential energy change resulting from the change of the Spent Fuel Pool Gate center of gravity of approximately 1/2 of the Spent Fuel Pool Gate length.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 56 Potential Energy Change CG 1 = Center of Gravity (Position One) = (L / 2) = (5 ft) / 2 = 2.5 ft CG 3 = Center of Gravity (Position Three) = (T /2) = (0.4167 ft) / 2 = 0.2084 ft CGA = Change in Center of Gravity = CG 1 - CG 3 = 2.5 ft - 0.2084 ft = 2.292 ft Change in Potential Energy = (CGA)(M ) = 401 ft-lb The second impact:

E2nd = (0.2374)(PE) + 401 ft-lb E2nd = (0.2374)(5425 ft-lb) + 401 ft-lb E2nd = 1689 ft-lb Fcomp = [(E2nd)(1 91(19+5))] / 200 ft-lb Fcomp = [(1689 ft-lb)(19/(19+5))] / 200 ft-lb Fcomp = 6.69 or 7 rods The total fuel rod failures during this scenario are:

Total Fuel Rod Failures = (1st Impact) + (2 nd Impact) =

Total Fuel Rod Failures = (17) + (7) = 24 rods Case 4 This case analyzes the free air drop impact with the minimum potential to impact fuel bundles.

For the first impact:

Edif = 1 - [175 lb / (175 lb + (10 bundles)(562 Ib)]

Edif = 1 - [0.0302]

Edif = 0.9698 Essentially all of the first impact energy would be absorbed. As a result, second or subsequent impacts need not be considered.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 57 Ener-gy Absorbed The first impact absorbs 96.98% of the initial energy or, Eabs = (PE)(0.9698)

Eabs = (5425 ft-lb)(0.9698)

Eabs = 5261 ft-lb Fcomp = [(Eabs)(19/(19+5))] / 200 ft-lb Fcomp = [(5261 ft-lb)(i 9/(19+5))] / 200 ft-lb Fcomp = 20.82 or 21 rods Damaued Fuel Rods Case 1 24 Case 2 22 Case 3 24 Case 4 21 By totaling the bounding cases of each dropped object (pool gate, intermediate lifting beam, and alternate lifting beam), a maximum total number of 209 fuel rods will fail in compression.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 58 Dose Analysis Based upon the load drop analysis, the maximum number of damaged rods is 209. This number of rods is increased 20% to account for potential future fuel design changes or changes in rigging. This provides the following number of damaged rods to use in the dose analysis:

209 damaged rods

1.20 = 265.2 use 266 damaged rods The activity of each isotope released to the environment is determined using the following relationship:

Ai = AC

FD

FRP *FG *(1/DF) where:

Ai = total activity of isotope i released to the environment (Ci/MWt)

AC = total activity in the reactor core (Ci/MWt)

FD = fraction of core damaged (unitless)

= Number of rods damaged / (Rods per bundle

Bundles in core)

FRP = maximum radial peaking factor (unitless)

FG = fraction of isotope activity in damaged rods escaping as gap release (unitless).

DF = decontamination factor within pool water for isotope i (unitless)

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 59 AC for each isotope is shown in the following table:

Source Term: (Ref. 11.5_EC 14186 markup pg. 9) 24 Month Fuel Cycle Isotope Core Inventory (Ci/MW) at Time 0 1-131 2.70E+04 1-132 3.92E+04 1-133 5.52E+04 1-134 6.06E+04 1-135 5.17E+04 Kr-85 3.66E+02 Kr-85m 7.02E+03 Kr-87 1.35E+04 Kr-88 1.89E+04 Xe-1 33 5.26E+04 Xe-135 1.99E+04 FD = fraction of core damaged (unitless)

= Number of rods damaged / (Rods per bundle

Bundles in core)

Number of rods damaged = 266 Number of Rods per Bundle for GE 9x9 Fuel: 74 (Ref. 11.5_EC 14186 markup pg. 17)

Number of Bundles in Core: 624 (Ref. 11.5_EC 14186 markup pg. 17)

FD = 266 rods damaged / ( 74 rods per bundle

624 Bundles in core)

FD = 0.005761 or 5.761 E-3 FRP = maximum radial peaking factor (unitless)

Core Radial Peaking Factor: 2.00 (Ref. 11.5_EC 14186 markup pg. 17)

FRP = 2.0

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 60 FG = fraction of isotope activity in damaged rods escaping as gap release (unitless).

From Assumption 8.8.1, the gap activity fractions of Table 3 in Regulatory Position 3 of RG 1.183 (Ref. 111,1) are utilized, as follows:

1-131 0.08 All other halogens 0.05 Kr-85 0.10 All other noble gases 0.05 FG 1-131 ="0.08 FG Other halogens = 0.05 FG Kr-85 = 0.10 FG Other noble gases = 0,05 DF = decontamination factor within pool water for isotope i (unitless)

DF Noble Gases = 1 Per Assumption 8.8.6:

DF lodines = 200 Ai for each isotope is calculated using an Excel spread sheet shown on the following page. A copy of the formula view of the spread sheet is also included on the subsequent page.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 61 Gate Drop Case 266 failed rods

___ AC FD FRP FG DF Ai Ai

3100 MWt Isotope 24 Mo Core FHA Damaged FHA Damaged AST FHA Gap Effective Pool DF Activity Released Activity Inventory (Ci/MW) Fuel - Fraction of Fuel - Radial Fraction (Ci/MWt) Released (Ci) at time = 0 Core Peaking Factor Released 1-131 2.70E+04 5.761E-03 2.00 0.08 200 1.244E-01 3.857E+02 1-132 3.92E+04 5.761E-03 2.00 0.05 200 1.129E-01 3.500E+02 1-133 5.52E+04 5.761E-03 2.00 0.05 200 1.590E-01 4.929E+02 1-134 6.06E+04 5.761E-03 2.00 0.05 200 1.745E-01 5.411E+02 1-135 5.17E+04 5.761E-03 2.00 0.05 200 1.489E-01 4.616E+02 1-136 N/A N/A N/A N/A N/A N/A

..... .. ... . =: i. : . .. :.i . .. .. . .

KR-83m N/A N/A N/A N/A N/A N/A Kr-85 3.66E+02 5.761E-03 2.00 0.1 1 4.217E-01 1.307E+03 KR-85m 7.02E+03 5.761E-03 2.00 0.05 1 4.044E+00 1.254E+04 Kr-87 1.35E+04 5.761E-03 2.00 0.05 1 7.777E+00 2.411E+04 KR-88 1.89E+04 5.761E-03 2.00 0.05 1 1.089E+01 3.375E+04 KR-89 N/A N/A N/A N/A N/A N/A Xe-131m N/A N/A N/A N/A N/A N/A Xe-133m N/A N/A N/A N/A N/A N/A Xe-133 5.26E+04 5.761E-03 2.00 0.05 1 3.030E+01 9.393E+04 Xe-135m N/A N/A N/A N/A N/A N/A Xe-135 1.99E+04 5.761E-03 2.00 0.05 1 1.146E+01 3.554E+04 Xe-137 N/A N/A N/A N/A N/A N/A Xe-138 N/A N/A N/A N/A N/A N/A

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 62 Formula view of Excel Spread Sheet A B C D E F G H 189 Isotope 24 Mo Core FHA Damaged Fuel - FHA AST FHA Effective Activity Released (CI/MWt) Activity Released Inventory Fraction of Core Damaged Gap Pool DF (al)

(Cl/MW) at Fuel - Fraction time = 0 Radial Released Peaking Factor 190 191 1-131 27000 =266/(74*624) 2 0.08 200 =(B191-C191*D191E191)/F191 --G191*3100 192 1-132 39200 =266/(74*624) 2 0.05 200 =(8192*C192*D192*E192)/F192 =G192*3100 193 1-133 55200 =266/(74*624) 2 0.05 200 =(B193*C193*D193*E193)/F193 =G193"3100 194 1-134 60600 =266/(74*624) 2 0.05 200 =(B194*C194*D194*E194)/F194 =G194*3100 195 1-135 51700 =266/(74*624) 2 0.05 200 =(B195*C195*D195*E195)/F195 =G195*3100 196 1-136 N/A N/A N/A N/A N/A N/A 197 198 KR-83m N/A N/A N/A N/A N/A N/A 199 Kr-85 366 =266/(74"624) 2 0.1 1 =(B199*C199*D199*E199)/F199 =G199*3100 200 KR-85m 7020 =266/(74*624) 2 0.05 1 =(B200*C200*D200*E200)/F200 =G200*3100 201 Kr-87 13500 =266/(74*624) 2 0.05 1 =(B201*C201-D201*E201)/F201 =G201*3100 202 KR-88 18900 =266/(74*624) 2 0.05 1 =(B202*C202*D202*E202)/F202 --G202*3100 203 KR-89 N/A N/A N/A N/A N/A N/A 204 205 Xe-131m N/A N/A N/A N/A N/A N/A 206 Xe-133m N/A N/A N/A N/A N/A N/A 207 Xe-133 52600 =266/(74*624) 2 0.05 1 =(B207*C207*D207"E207)/F207 =G207*3100 208 Xe-135m N/A N/A N/A N/A N/A N/A 209 Xe-135 19900 =266/(74-624) 2 0.05 1 =(B209*C209-D209*E209)/F209 =G209*3100 210 Xe-137 N/A N/A N/A N/A N/A N/A 211 Xe-138 N/A N/A N/A N/A N/A N/A

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 63 RADTRAD Model - Load Drop over Spent Fuel Pool- 336 Hours Decay with no Credit Taken for FB, ContainmentIntegrity or CR Filtration*

A RADTRAD CR model based on ventilation system parameters as described in Sections 7, 8 and 9 is developed as discussed below. Note that this model is identical to the model developed for Case 1 in calculation G13.18.9.5*059 (Ref. 11.5) with the exception of the source term and the assumed decay time. RADTRAD model information from G13.18.9.5*059 is provided in this section. References for the various inputs are provided in the inputs section of this calculation, thus the references are not duplicated in this section.

The activity released to the environment previously calculated is modeled to be released at ground level from the Fuel Building in a time period not to exceed 2 hours2.314815e-5 days 5.555556e-4 hours 3.306878e-6 weeks 7.61e-7 months . This is accomplished by purging the actual FB free volume at a very high rate while releasing the available activity in the Fuel Pool over a 2 hour2.314815e-5 days 5.555556e-4 hours 3.306878e-6 weeks 7.61e-7 months period. All leakage is immediately released to the environment from the FB without holdup, plateout, or dilution.

RADTRAD Volume 1 represents the FB 3

RBS FB volume is modeled as 7.42E+05 ft

100% of the AST FHA source term exiting the pool is released to the Environment

No additional inputs RADTRAD Volume 2 represents the Environment

- No inputs RADTRAD Volume 3 represents the Control Room 3 "Control Room habitability volume equals 188,000 ft

" No additional inputs RADTRAD Pathway 1 represents the FB leakage term (total release in 24 hours2.777778e-4 days 0.00667 hours 3.968254e-5 weeks 9.132e-6 months )

FB air exhaust rate modeled as 7.42E+09 cfm (to allow for a 2 hour2.314815e-5 days 5.555556e-4 hours 3.306878e-6 weeks 7.61e-7 months release)

0% efficient filters for elemental & organic species

No additional inputs.

RADTRAD Source Term:

User Inventory file RBS_FHARev1 a266.nif. This file is developed by using the calculated release for the individual isotopes (Ai) previously determined based upon a failure of 266 fuel rods.

Modeled RBS AEP power level as 3100 MWth Model isotopic decay and daughter in-growth

Use the user defined RADTRAD release fraction file, rbs fharevl.rft. This file defines a .001 -

hour release duration with a 100% release fraction in that period after allowing a 336-hour decay period.

" The specified iodine species fractions are 0.57 elemental and 0.43 organic

" Use the default RADTRAD FGR 11 & 12 dose conversion factors for the MACCS 60 isotope inventory, FGR1 1&12.inp

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 64 o No additional inputs RADTRAD Analysis Results Calculation Results TEDE (REM)

Dose Receptor Acceptance Criteria Gate Drop in Fuel Building EAB* 6.3 1.2155 LPZ 6.3 0.16017 CR 5 0.87328

Worst 2-hour period

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 65 10.2 Damage to Pool Liner In assessing the damage to the pool liner the following cases are analyzed based upon the load path.

Drop from Maximum Lift Height The maximum lift height occurs when transferring the gate from the cask pool to the laydown area on the Fuel Building 113' elevation. Objects analyzed for this drop are the gate, intermediate lifting beam and alternate lifting beam. Potential points of impact for this drop are:

1) Cask pool floor at 70' elevation;

2) Cask pool shelf at 93' elevation;

3) Gate opening at 88' elevation.

Load Drop with Gate in Pool This scenario is during the movement of the gate from its installed location in the spent fuel pool to the gate opening between the spent fuel pool and cask pool, through the gate opening, then into the cask pool. Objects analyzed for this drop are the gate, intermediate lifting beam and alternate lifting beam. Potential points of impact for this drop are:

1) Spent fuel pool or cask pool floor at 70' elevation;

2) Gate opening floor at 88' elevation.

Load Drop onto Fuel Storage Racks This scenario postulates a load drop during movement of the load in the spent fuel pool area that impacts the fuel storage racks. Objects analyzed for this drop are the gate, intermediate lifting beam and alternate lifting beam. This scenario only determines the impact velocity of the objects as an input to the evaluation in Section 10.3.

10.2.1 Drop from Maximum Lift Height The maximum lift height occurs when transferring the gate from the cask pool to the laydown area on the Fuel Building 113' elevation. Objects analyzed for this drop are the gate, intermediate lifting beam and alternate lifting beam. Potential points of impact for this drop are:

1) Cask pool floor at 70' elevation;

2) Cask pool shelf at 93' elevation;

3) Gate opening at 88' elevation.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 66 Determine Pool Minimum Water Level Elevation TS Minimum water level above the top of irradiated fuel = > 23' (Ref. 111.10, pg. 3.7-15)

Stored fuel bundle upper tie plate elevation = 84.6645' (Ref. 11.3, pg. 4 and Assumption 8.12)

Pool Min Level Elevation = Top of Irradiated Fuel Elevation + Min TS Water Coverage Pool Min Level Elevation = 84.6645' + 23' = 107.6645' use 107.7' Determine Maximum Object Lift Elevation For the initial movement the objects being evaluated had the following elevations:

Elevation of bottom of Gate = 90' (Ref. 11.2, pg. 8)

Elevation of bottom of Intermediate Lifting Beam = 115' (Ref. 11.2, pg. 8)

Elevation of bottom of Alternate Lifting Beam = 123' (Ref. 11.2, pg. 12)

Maximum Lift Elevation of the Gate Bottom Elevation of Fuel and Cask Pool Curb = 113' 4" (Ref. 11.13)

Approximate lift height above laydown floor elevation obstructions = 6" (Ref. 111.1, pg. 16)

Max Gate Bottom Lift Elevation = Curb elevation + lift height above obstructions Max Gate Bottom Lift Elevation = 113' 4" + 6" = 113' 10' use 115' 0" or 115.0' Using the elevations of the bottom of the gate, intermediate lifting beam and alternate lifting beam from the initial movement, determine the Maximum Lift Elevation for the Intermediate Beam and Alternate Beam.

Max Lift Elevation of Intermediate Beam

= Max Gate Bottom Lift El. + (Initial Lift Int. Beam Bottom El. - Initial Lift Gate Bottom El.)

Max Lift Elevation of Intermediate Beam = 115.0' + (115'-90') = 140'

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 67 Max Lift Elevation of Alternate Beam

= Max Gate Bottom Lift El. + (Initial Lift Alt. Beam Bottom El. - Initial Lift Gate Bottom El.)

Max Lift Elevation of Alternate Beam = 115' + (123'-90') = 148' Determine Object Air Drop Distance Air Drop Distance = Max Lift Elevation - Pool Min Level Elevation Gate Air Drop Distance = Max Lift Elevation - Pool Min Level Elevation Gate Air Drop Distance = 115' - 107.7' = 7.3' Intermediate Beam Air Drop Distance = Max Lift Elevation - Pool Min Level Elevation Intermediate Beam Air Drop Distance = 140'- 107.7' = 32.3' Alternate Beam Air Drop Distance = Max Lift Elevation - Pool Min Level Elevation Alternate Beam Air Drop Distance = 148' - 107.7' = 40.3' Determine Water Drop Distance Water Drop Distance = Pool Min Level Elevation - Elevation of Impact Point Cask Pool Floor Water Drop Distance = 107.7- 70' = 37.7' Cask Pool Shelf Water Drop Distance = 107.7' - 93' = 14.7' Gate Opening Water Drop Distance = 107.7'- 88' = 19.7' The equation to determine strike velocity is selected based upon the relationship of object length (L) to water depth (H) as follows:

Z1(x) = function for determining the striking velocity at depth H = x when 0<x<L Z2(x) = function for determining the striking velocity at depth H = x when x>L The following table provides a summary of the air drop distance, water drop distance H, the length of the dropped object, and the selected strike velocity function based upon the criteria above for each Maximum Lift Load Drop case.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 68 Case Description Air Drop Water Drop L ft Strike Distance, Distance, Velocity h ft H ft Function Gate Drop to Cask Pool Floor 7.3' 37.7' 24.39' Z2(x)

Gate Drop to Cask Pool Shelf 7.3' 14.7' 24.39' ZI(x)

Gate Drop to Gate Opening 7.3' 19.7' 24.39' Z x)

Intermediate Beam Drop to Cask Pool Floor 32.3' 37.7' 4.75' Z2(x)

Intermediate Beam Drop to Cask Pool Shelf 32.3' 14.7' 4.75' Z2(x)

Intermediate Beam Drop to Gate Opening 32.3' 19.7' 4.75' Z2(x)

Alternate Beam Drop to Cask Pool Floor 40.3' 37.7' 12' Z2(x)

Alternate Beam Drop to Cask Pool Shelf 40.3' 14.7' 12' Z2(x)

Alternate Beam Drop to Gate Opening 40.3' 19.7' 12' Z2(x)

For the Object Drop cases to assess liner damage, the following equations will be used:

Vo =(2gh) Y2 (Ref. 11.4, pg. E-4, 5-3)

Where:

Vo = velocity of the missile at contact with2 the water surface, ft/s g = gravitational acceleration = 32.17 ft/s h = distance between the missile and the water surface, ft Vs = [Z(H)1"2 (Ref. 11.4, pg. 5-2)

Where:

Vs = velocity of the missile striking the steel surface, ft/s Z(H) = function for determination of striking velocity (see formulas below)

H = feet of fluid between fluid surface and surface of steel target

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 69 The following equations are from Ref. 11.4, pg. 5-2:

Zi(x) = (g/a) + (bAo)[(1 -2ax)/2a 2)] + e2ax[(Vo2 - (g/a) - (bAo / 2a 2)]

Z2 (x) = V2 2 + e-2ax {(bAo /2a 2 )[ e 2aL(1 -2aL) - 1)] + V02 + [(g/a)[(e 2aL( Y/ym ) - 1)]}

Where:

Zl(x) = function for determining the striking velocity at depth H = x when O<x<L Z2 (x) = function for determining the striking velocity at depth H = x when x>L a = (y

A0

CD) / (2* W) (Ref. 11.4, pg. 5-3) b=(y*g)/W (Ref. 11.4, pg. 5-3) g = gravitational acceleration = 32.17 ft/s 2 (Ref. 11.4, pg. 5-3)

W = weight of missile, lb (Ref. 11.4, pg. 5-3) y = weight density of liquid, lb/ft 3 (Ref. 11.4, pg. 5-3) ym = weight density of missile, lb/ft3 (Ref. 11.4, pg. 5-3) x = H = depth of missile center of gravity below the water surface, ft (Ref. 11.4, pg. 5-3, 5-5) 2 A0 = horizontal cross-sectional area of the missile (constant over length L), ft (Ref. 11.4, pg. 5-3)

CD = drag coefficient given in table 5-1 of the reference or other references on fluid mechanics which is a function of Lid, R and shape of the missile (Ref. 11.4, pg. 5-3, 5-4)

L = vertical length of the missile, ft (Ref. 11.4, pg. 5-3) d = characteristic dimension of the missile, for a rectangular surface d = width, ft (Ref. 11.4, pg. 5-3, 5-4)

R = Reynolds Number = (Vo

d ) / v (Ref. 11.4, pg. 5-3) v = kinematic viscosity of the liquid, ft2/s (Ref. 11.4, pg. 5-3)

Vo = initial velocity of the missile at x = 0, ft/s (Ref. 11.4, pg. 5-3, 5-5)

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 70 Vs = striking velocity of the missile at x = H, ft/s (Ref. 11.4, pg. 5-3)

V2 = terminal velocity, ft/s = [(g/a) * (1 - y/ym )]1/2 (Ref. 11.4, pg. 5-3)

H = depth of the fluid, ft (Ref. 11.4, pg. 5-1)

T312 = 0.5 M Vs 2 / (17,400 K2 D 3/2) (Ref. 11.4, pg. C-8)

Where:

T = steel thickness to just be perforated, in M = mass of the missile, lb-s 2/ft Vs = striking velocity of the missile normal to target surface, ft/s K = constant depending on the grade of the steel, K is usually = 1 D = diameter or equivalent diameter of the missile, in The inputs for the maximum lift load drop cases are as follows:

All cases:

2 g = Acceleration of Gravity = 32.174 ft/sec (Ref. 111.9, pg. B-10) 3 y= Density of water @ 160 deg. F = 60.994 lb/ft (Ref. 111.9, pg. A-6) v = Kinematic viscosity of water @ 160 deg. F = 0.439 E-5 ft2/s (Ref. 111.11)

K = constant related to grade of steel = 1 The inputs for the maximum lift gate load drop cases are as follows:

L = Length of Spent Fuel Pool Gate = 24.39 ft (Ref. 11.1, pg. All) d = Width of Spent Fuel Pool Gate = 4.771 ft (Ref. 11.1, pg. Al1) t = Thickness of Spent Fuel Pool Gate = 0.3958 ft (Ref. 11.1, pg. 17)

W = Weight of Spent Fuel Pool Gate and Rigging = 2000 lbs (Ref. 111.1, pg. 4);

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 71 Case Description Air Drop Water Drop L ft Strike Distance, Distance, Velocity h ft H ft Function Gate Drop to Cask Pool Floor 7.3' 37.7' 24.39' Z2 (x)

Gate Drop to Cask Pool Shelf 7.3' 14.7' 24.39' Z1(x)

Gate Drop to Gate Opening 7.3' 19.7' 24.39' Z1(x) ym = weight density of missile, Ib/ft3 = weight, lb / (L, ft

d, ft

t, ft) lb/ft3 ym = weight density of gate, lb/ft = 2000 lb / (24.39 ft

4.771 ft

0.3958 ft) = 43.424 3

For Gate Drop to Cask Pool Floor Determine V0 Vo = (2gh) 1/2 Where:

Vo = velocity of the missile at contact with2 the water surface, ft/s g = gravitational acceleration = 32.17 ft/s h = distance between the missile and the water surface, ft V0 .= (2

32.17 ft/s 2* 7.3 ft) Y'= 21.672 ft/s Determine R Note that d in the Reynolds number represents the width of the gate.

R = (Vo

d )v = (21.672 ft/s

4.771 ft) / 0.439 E-5 ft 2/s = 2.355E7 Determine CD In determining CD for rectangular bodies L = length of the body, d = width Gate length (height) = 24.39' Gate width = 4.771' L/d = 24.39'/4.771' = 5.112 Using Ref. 11.4, pg. 5-4 Table 5-1 CD = 1.20

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 72 Determine Ao 2

Ao = horizontal cross-sectional area of the missile (constant over length L), ft (Ref. 11.4, pg. 5-3) 2 Ao = gate width

gate thickness = 4.771

0.3958 = 1.888 ft Determine Coefficient a a = (y

A0

CD ) /(2

W) = (60.994 lb/ft3

1.888 ft2

1.20) / (2*2000 Ib) = 0.035 Determine Coefficient b b = (y

g ) / W = (60.994 lb/ft3

32.17 ft/s 2) I 2000 lb = 0.981 Determine Terminal Velocity V9 2

V2 = [(g/a) * (1 - y/ym )]112 =[ (32.17 ft/s / 0.035) * (1 - (60.994 lb/ft3 / 43.424 lb/ft3 ))] 1/2 V2 = [919.143 * (1-1.405) ] 1/2 V2 =[-372.253 ] 1 2 As the square root of a negative number is indeterminate, this indicates that the gate will float as the density of the gate is less than the density of water. Although the value determined for the overall gate density is correct, it is unlikely that the gate will float. Therefore the thickness of the gate will be adjusted to achieve a gate density greater than water. The smaller gate thickness will be used throughout this case. This will ultimately reduce the impact area experienced by the liner which increases the penetration thickness and is thus conservative.

Note that this dimension adjustment is only used for this case.

The adjusted gate thickness is 0.275' or 3.3" The adjusted density of the gate is as follows:

3 7m = 2000 lb / (24.39 ft

4.771 ft

0.275 ft) = 62.499 lb/ft

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 73 Determine Revised 0 A0 = horizontal cross-sectional area of the missile (constant over length L), ft2 (Ref. 11.4, pg. 5-3) 2 Ao = gate width

gate thickness = 4.771* 0.275 = 1.312 ft Determine Revised Coefficient a a = (y

Ao

CD ) / (2

W) = (60.994 lb/ft 3

1.312 ft2

1.20) / (2*2000 Ib) = 0.024 Determine Revised Terminal Velocity V2 3 3 V2 = [(g/a) * (1 - 7/'Ym )]112 =[ (32.17 ft/S / 0.024) * (1 - (60.994 lb/ft / 62.499 lb/ft ) 112 2

V2 = [1340.417 * (1-0.976) 11/2 = 5.681 ft/s Determine Z2 (x)

Note thatx=H such that the result of Z 2(x) can be directly used to determine strike velocity.

Z 2(x) = V22 + e-2ax {(bAo /2a 2)[ e2aL(1 -2aL) - 1)] + V0 2 + [(g/a)[(e 2aL( "Y/Ym ) - 1 )]}

For simplicity the various intermediate relations in the formula are determined individually.

Only results values are listed without units.

V2 2 = (5.681 ft/s ) 2 = 32.274 e-2ax = e (-2

0.024 37.7) = 0.164 (bAo /2a 2) = (0.981

1.312) / (2 * (0.024) 2) = 1117.250 2aL = 2*0.024*24.39 = 1.171 e 2 aL = e (1.171) = 3.225

[ e 2aL(1-2aL) - 1)] = [ ((3.225 (1 - 1.171)) - 1] = -1.551 V02 = (21.672 ft/s) 2 = 469.676 g/a = 32.17 / 0.024 = 1340.417 y/m= 60.994 lb/ft3 / 62.499 lb/ft 3 = 0.976

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 74 Z 2 (x) = V2 2 + e-2ax {(bA0 /2a 2)[ e 2aL(1 -2aL) - 1)] + V0 2 + [(g/a)[(e 2aL( Y/hm ) - 1)]}

Z2 (x) = 32.274 + 0.164 {(1117.250)[-1.551] + 469.676 + [(1340.417)[(3.225( 0.976) - 1)]}

Z2 (x) = 32.274 + 0.164{ -1732.855 + 469.676 + 2878.679} = 297.216 Determine Vs Vs= [Z(H)]" 2 (Ref. 11.4, pg. 5-2)

Where:

Vs = velocity of the missile striking the steel surface, ft/s Z(H) = function for determination of striking velocity H = feet of fluid between fluid surface and surface of steel target Vs= [297.216112 = 17.239 ft/s Convert the impact area to equivalent diameter D The impact area is equal to A0 calculated previously.

2 Ao = 1.312 ft 2

1.312 ft2

144 in2 /ft 188.928 in2 188.928 in2 = r r2 r = 7.755 in D = 2*r = 2

7.755 in = 15.509 in Determine M M=W/g M = 2000 lb / 32.17 ft/s 2 = 62.170 Ib-s 2 /ft

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 75 Determine Steel Penetration Thickness T3/2 = 0.5 M Vs2 / (17,400 K2 D 3/2) (Ref. 11.4, pg. C-8)

Where:

T = steel thickness to just be perforated, in M = mass of the missile, lb-s 2/ft Vs = striking velocity of the missile normal to target surface, ft/s K = constant depending on the grade of the steel, K is usually = 1 D = diameter or equivalent diameter of the missile, in T3/2 = 0.5

62.170 * (17.239)2 / (17,400 *(1)2 (15.509 3/2)) = 0.008693 T = 0.042 in The analysis methodology to calculate Z2 (x) and T has been input into an Excel spread sheet.

The results of the spread sheet for the previously calculated case is on the following page.

Note that there are differences in some values due to variations the significant figures stored in Excel verses those displayed in the manual calculation. Due to the Excel limitations with respect to formatting, some of the variables are indicated by description rather than symbol.

The spread sheet method will be used in all of the subsequent cases.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 76 Gate Drop from Max Lift Height to Pool Floor 70' Value Units Gate Length L 24.390 ft Gate Width, d 4.771 ft Gate thickness (reduced to obtain density greater than water) 0.275 ft Gate weight, W 2000.000 lb Gate density 62.499 lb/cu ft water density @ 160F 60.994 Ib/ cu ft water kinematic viscosity @ 16OF 4.390E-06 sq ft/s water density/gate density 0.976 drop distance in air 7.300 ft drop distance in water 37.700 ft Vo where h is drop distance in air, V = (2gh)A2 21.672 ft/s Reynolds no =( Vo

d)/viscosity 2.355E+07 Check L/d using gate length and width 5.112 Check L/D using gate width and thickness 17.349 Drag Coefficient CD 1.200 Ao = width

thickness 1.312 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.024 b = (water density

g)/W 0.981 Terminal Velocity, V2 = SQRT((g*(1-density water/density gate)/a) 5.681 ft/s exp(-2*a*x) where x = drop distance in water 0.164 bAo 1.287 exp(2aL) 3.226 2aL 1.171 V2A2 32.276 VoA2 469.682 bAo*[exp(2aL)*(1-2aL)-l]/2aA2 -1732.907 g*(exp(2aL)

wtr dens/gate dens -1)/a 2878.065 Z2x 296.504 Vs = (Zx)AO.5 17.219 ft/s Convert impact area to equivalent diameter 15.509 in mass weight/g 62.170 lb-s2/ft thickness T 0.042 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 77 For Gate Drop to Cask Pool Shelf Zl(x) = (g/a) + (bAo)[(1-2ax)/2a 2 )] + e-2ax[(Vo 2 - (g/a) - (bAo/ 2a 2)]

Determine Vo Vo = (2gh) 1/2 Where:

Vo = velocity of the missile at contact with2 the water surface, ft/s g = gravitational acceleration = 32.17 ft/s h = distance between the missile and the water surface, ft Vo = (2

32.17 ft/s 2* 7.3 ft) Y= 21.672 ft/s Determine R Note that d in the Reynolds number represents the width of the gate.

R =(Vo

d )/v = (21.672 ft/s

4.771 ft) / 0.439 E-5 ft2/s =2.355E7 Determine Cr In determining CD for rectangular bodies L = length of the body, d = width Gate length (height) = 24.39' Gate width = 4.771' L/d = 24.39'/4.771' = 5.112 Using Ref. 11.4, pg. 5-4 Table 5-1 CD = 1.20 Determine Ao 2

A0 = horizontal cross-sectional area of the missile (constant over length L), ft (Ref. 11.4, pg. 5-3) 2 Ao = gate width

gate thickness = 4.771

0.3958 = 1.888 ft Determine Coefficient a a = (y

Ao

CD ) / (2

W) = (60.994 lb/ft3

1.888 ft2

1.20) / (2*2000 Ib) = 0.0345

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 78 Determine Coefficient b b = (*y* g ) / W = (60.994 lb/ft 3

32.17 ft/s 2 ) /2000 lb = 0.981 Determine Zl(x)

Note that x=H such that the resultof Z2 (x) can be directly used to determine strike velocity.

Zl(x) = (g/a) + (bAo)[(1-2ax)/2a 2 )] + e-2ax[(Vo2 - (g/a) - (bAo / 2a 2)]

For simplicity the various intermediate relations in the formula are determined individually.

Only results values are listed without units.

e-2ax = e (-2

0.0345

14.7) = 0.3627 bA0 = (0.981

1.888) = 1.852 2ax = 2

0.0345

14.700 = 1.014 V 0 2 = (21.672 ft/s ) 2 = 469.676 g/a = 32.17 / 0.0345 = 932.464 (bAo)[(1 -2ax)/2a 2 )] = (1.852)[(1 -1.014)/2*(0.0345)2] = -10.892 e-2ax[(Vo2 - (g/a) - (bAo / 2a 2)] = (0.3627)[(469.676)-(932.464)-(1.852/2*0.03452)] = -450.029 Zl(x) = (g/a) + (bAo)[(1-2ax)/2a] + e-2ax[(Vo 2 - (g/a) - (bAo/ 2a 2 )]

Zl(x) = 932.464 + (-10.892) + (-450.029) = 471.543 Determine Vt Vs = [Z(H)]" 2 (Ref. 11.4, pg. 5-2)

Where:

Vs = velocity of the missile striking the steel surface, ft/s Z(H) = function for determination of striking velocity H = feet of fluid between fluid surface and surface of steel target Vs = [471.543]112 = 21.712 ft/s

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION:, 0 PAGE: 79 Convert the impact area to equivalent diameter D The impact area is equal to A0 calculated previously.

Ao = 1.888 ft2 2 2 2 1.888 W

144 in /ft = 271.872 in 271.872 in2 = [ r2 r = 9.302 in D = 2*r = 2

9.302 in = 18.605 in Determine M M=W/g M = 2000 lb / 32.17 ft/s 2 = 62.170 Ib-s2/ft Determine Steel Penetration Thickness T 3/2 = 0.5 M Vs2 / (17,400 K2 D 3/2) (Ref. 11.4, pg. C-8)

Where:

T = steel thickness to just be perforated, in M = mass of the missile, Ib-s2/ft Vs = striking velocity of the missile normal to target surface, ft/s K = constant depending on the grade of the steel, K is usually = 1 D = diameter or equivalent diameter of the missile, in T32= 0.5

62.170 * (21.712)2 / (17,400 *(1)2 (18.605 3/2) = 0.010494 T = 0.048 in The analysis methodology to calculate Zl(x) and T has been input into an Excel spread sheet.

The results of the spread sheet for the previously calculated case is shown on the following page. Note that there are differences in some values due to variations the significant figures stored in Excel verses those displayed in the manual calculation. Due to the Excel limitations with respect to formatting, some of the variables are indicated by description rather than symbol. The spread sheet method will be used in all of the subsequent cases.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 80 Gate Drop from Max Lift Height to Cask Shelf Value Units Gate Length L 24.390 ft Gate Width, d 4.771 ft Gate thickness 0.396 ft Gate weight, W 2000.000 lb Gate density 43.424 Ib/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/s water density/gate density 1.405 drop distance in air 7.300 ft drop distance in water 14.700 ft Vo where h is drop distance in air, V = (2gh)A2 21.672 ft/s Reynolds no =( Vo

d)/viscosity 2.355E+07 Check L/d using gate length and width 5.112 Check L/D using gate width and thickness 12.054 Drag Coefficient CD 1.200 Ao = width

thickness 1.888 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.035 b = (water density

g)/W 0.981 exp(-2*a*x) where x = drop distance in water 0.362 bAo 1.853 2ax 1.016 VoA2 469.682 g/a 931.017 bAo*[(1-2ax)]/2aA2 -12.318 exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] -447.965 ZIx 470.734 Vs = (Zx)AO.5 21.696 ft/s Convert impact area to equivalent diameter 18.606 in mass = weight/g 62.170 lb-s2/ft thickness 0.048 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 81 For Gate Drop to Gate Opening Gate Drop from Max Lift Height to Gate Opening Value Units Gate Length L 24.390 ft Gate Width, d 4.771 ft Gate thickness 0.396 ft Gate weight, W 2000.000 lb Gate density 43.424 lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/s water density/gate density 1.405 drop distance in air 7.300 ft drop distance in water 19.700 ft Vo where h is drop distance in air, V = (2gh)A2 21.672 ft/s Reynolds no =( Vo

d)/viscosity 2.355E+07 Check L/d using gate length and width 5.112 Check L/D using gate width and thickness 12.054 Drag Coefficient CD 1.200 Ao = width

thickness 1.888 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.035 b = (water density

g)/W 0.981 exp(-2*a*x) where x = drop distance in water 0.256 bAo 1.853 2ax 1.361 VoA2 469.682 g/a 931.017 bAo* [(1-2ax)]/2aA2 -280.401 exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] -317.088 ZIx 333.528 Vs = (Zx)AO.5 18.263 ft/s Convert impact area to equivalent diameter 18.606 in mass = weight/g 62.170 Ib-s2/ft thickness 0.038 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 82 Intermediate Beam Cases The inputs for the maximum lift intermediate beam load drop cases are as follows:

L = Length of Intermediate Lifting Beam = 4.75 ft (Ref. 11.2, pg. 6) d = Width of Intermediate Lifting Beam = 0.4167 ft (Ref. 11.2, pg. 6) t = Thickness of Intermediate Lifting Beam = 0.4167 ft (Ref. 11.2, pg. 6)

W = Weight of Beam and Rigging = 175 lbs (Section 10.1.3)

Case Description Air Drop Water Drop L ft Strike Distance, Distance, Velocity h ft H ft Function Intermediate Beam Drop to Cask Pool Floor 32.3' 37.7' 4.75' Z2(x)

Intermediate Beam Drop to Cask Pool Shelf 32.3' 14.7' 4.75' Z2(x)

Intermediate Beam Drop to Gate Opening 32.3' 19.7' 4.75' Z2(x)

Ym = weight density of missile, Ib/ft3 = weight, lb / (L, ft

d, ft

t, ft) 3 7m = weight density of beam, Ib/ft3 = 175 lb / (4.75 ft

0.4167 ft

0.4167 ft) = 212.177 lb/ft

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 83 For Intermediate Beam Drop to Cask Pool Floor Intermediate Beam Drop from Max Lift Height to Pool Floor 70' Beam Length L 4.750 ft Beam Width, d 0.417 ft Beam thickness 0.417 ft Beam weight, W 175.000 lb Beam density 212.177 lb/cu ft water density @ 160F 60.994 Ib/cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 0.287 drop distance in air 32.300 ft drop distance in water 37.700 ft Vo where h is drop distance in air, V = (2gh)A2 45.587 ft/s Reynolds no =( Vo

d)/viscosity 4.327E+06 Check L/d using beam length and width 11.399 Check L/D using beam width and thickness 1.000 Drag Coefficient CD 1.160 Ao = width

thickness 0.174 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.035 b = (water density

g)/W 11.212 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) 25.554 ft/s exp(-2*a*x) where x = drop distance in water 0.071 bAo 1.947 exp(2aL) 1.396 2aL 0.333 V2A2 653.027 VoA2 2078.182 bAo*[exp(2aL)*(1-2aL)-l]/2aA2 -55.030 g*(exp(2aL)

wtr dens/beam dens -1)/a -548.751 Z2x 757.546 Vs = (Zx)A0.5 27.524 ft/s Convert impact area to equivalent diameter 5.642 in mass = weight/g 5.440 lb-s2/ft thickness 0.043 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 84 For Intermediate Beam Drop to Cask Pool Shelf Intermediate Beam Drop from Max Lift Height to Cask Shelf 93' El Beam Length L 4.750 ft Beam Width, d 0.417 ft Beam thickness 0.417 ft Beam weight, W 175.000 lb Beam density 212.177 lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/s water density/gate density 0.287 drop distance in air 32.300 ft drop distance in water 14.700 ft Vo where h is drop distance in air, V = (2gh)A2 45.587 ft/s Reynolds no =( Vo

d)/viscosity 4.327E+06 Check L/d using beam length and width 11.399 Check L/D using beam width and thickness 1.000 Drag Coefficient CD 1.160 Ao = width

thickness 0.174 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.035 b = (water density

g)/W 11.212 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) 25.554 ft/s exp(-2*a*x) where x = drop distance in water 0.356 bAo 1.947 exp(2aL) 1.396 2aL 0.333 V2A2 653.027 VoA2 2078.182 bAo* [exp(2aL)*(1-2aL)-1]/2aA2 -55.030 g*(exp(2aL)

wtr dens/beam dens -1)/a -548.751 Z2x 1178.357 Vs = (Zx)AO.5 34.327 ft/s Convert impact area to equivalent diameter 5.642 in mass = weight/g 5.440 lb-s2/ft thickness 0.057 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 85 For Intermediate Beam Drop to Gate Opening Intermediate Beam Drop from Max Lift Height to Gate Opening 88' Beam Length L 4.750 ft Beam Width, d 0.417 ft Beam thickness 0.417 ft Beam weight, W 175.000 lb Beam density 212.177 lb/cu ft water density @ 160F 60.994 Ib/ cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/s water density/gate density 0.287 drop distance in air 32.300 ft drop distance in water 19.700 ft Vo where h is drop distance in air, V= (2gh)A2 45.587 ft/s Reynolds no =( Vo

d)/viscosity 4.327E+06 Check L/d using beam length and width 11.399 Check L/D using beam width and thickness 1.000 Drag Coefficient CD 1.160 Ao = width

thickness 0.174 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.035 b = (water density

g)/W 11.212 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) 25.554 ft/s exp(-2*a*x) where x = drop distance in water 0.251 bAo 1.947 exp(2aL) 1.396 2aL 0.333 V2A2 653.027 VoA2 2078.182 bAo*[exp(2aL)*(1-2aL)-l]/2aA2 -55.030 g*(exp(2aL)

wtr dens/beam dens -1)/a -548.751 Z2x 1022.846 Vs.= (Zx)^O.5 31.982 ft/s Convert impact area to equivalent diameter 5.642 in mass = weight/g 5.440 lb-s2/ft thickness 0.052 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 86 The inputs for the maximum lift alternate beam load drop cases are as follows:

L = Length of Alternate Lifting Beam = 12' (Assumption 8.13) d = Width of Alternate Lifting Beam = 0.5 ft (Ref. 111.7, pg. 1-26) t = Thickness of Alternate Lifting Beam = 0.333 ft (Ref. 111.7, pg. 1-26)

W = Weight of Beam and Rigging = 200 lbs (Section 10.1.2)

Case Description Air Drop Water Drop L ft Strike Distance, Distance, Velocity h ft H ft Function Alternate Beam Drop to Cask Pool Floor 40.3' 37.7' 12' Z2(x)

Alternate Beam Drop to Cask Pool Shelf 40.3' 14.7' 12' Z2(x)

Alternate Beam Drop to Gate Opening 40.3' 19.7' 12' Z2(x) ym = weight density of missile, Ib/ft 3 = weight, lb / (L, ft

d, ft

t, ft) 3 ym = weight density of beam, Ib/ft = 200 lb / (12 ft

0.333 ft

0.5 ft) = 100.100 Ib/ft 3

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 87 For Alternate Beam Drop to Cask Pool Floor Alternate Beam Drop from Max Lift Height to Pool Floor 70' Beam Length L 12.000 ft Beam Width, d 0.500 ft Beam thickness 0.333 ft Beam weight, W 200.000 lb Beam density 100.100 lb/cu ft water density @ 160F 60.994 Ib/ cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 0.609 drop distance in air 40.300 ft drop distance in water 37.700 ft Vo where h is drop distance in air, V = (2gh)A2 50.921 ft/s Reynolds no =( Vo

d)/viscosity 5.800E+06 Check L/d using beam length and width 24.000 Check L/D using beam width and thickness 1.502 Drag Coefficient CD 1.160 Ao = width

thickness 0.167 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.029 b = (water density

g)/W 9.811 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) 20.658 ft/s exp(-2*a*x) where x = drop distance in water 0.109 bAo 1.634 exp(2aL) 2.028 2aL 0.707 V2A2 426.738 VoA2 2592.902 bAo*[exp(2aL)*(1-2aL)-l]/2aA2 -381.910 g*(exp(2aL)

wtr dens/beam dens -1)/a 257.178 Z2x 694.643 Vs = (Zx)A0.5 26.356 ft/s Convert impact area to equivalent diameter 5.525 in mass = weight/g 6.217 lb-s2/ft thickness 0.045 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 88 For Alternate Beam Drop to Cask Pool Shelf Alternate Beam Drop from Max Lift Height to Cask Shelf 93' El Beam Length L 12.000 ft Beam Width, d 0.500 ft Beam thickness 0.333 ft Beam weight, W 200.000 lb Beam density 100.100 lb/cu ft water density @ 160F 60.994 Ib/cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 0.609 drop distance in air 40.300 ft drop distance in water 14.700 ft Vo where h is drop distance in air, V = (2gh)A2 50.921 ft/s Reynolds no =( Vo

d)/viscosity 5.800E+06 Check L/d using beam length and width 24.000 Check L/D using beam width and thickness 1.502 Drag Coefficient CD 1.160 Ao = width

thickness 0.167 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.029 b = (water density

g)/W 9.811 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) 20.658 ft/s exp(-2*a*x) where x = drop distance in water 0.421 bAo 1.634 exp(2aL) 2.028 2aL 0.707 V2A2 426.738 VoA2 2592.902 bAo*[exp(2aL)* (1-2aL)-l]/2aA2 -381.910 g*(exp(2aL)

wtr dens/beam dens -1)/a 257.178 Z2x 1465.074 Vs = (Zx)AO.5 38.276 ft/s Convert impact area to equivalent diameter 5.525 in mass = weight/g 6.217 lb-s2/ft thickness 0.074 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 89 For Alternate Beam Drop to Gate Opening Alternate Beam Drop from Max Lift Height to to Gate Opening 88' Beam Length L 12.000 ft Beam Width, d 0.500 ft Beam thickness 0.333 ft Beam weight, W 200.000 lb Beam density 100.100 lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 0.609 drop distance in air 40.300 ft drop distance in water 19.700 ft Vo where h is drop distance in air, V = (2gh)A2 50.921 ft/s Reynolds no =( Vo

d)/viscosity 5.800E+06 Check L/d using beam length and width 24.000 Check L/D using beam width and thickness 1.502 Drag Coefficient CD 1.160 Ao = width

thickness 0.167 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.029 b = (water density

g)/W 9.811 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) 20.658 ft/s exp(-2*a*x) where x = drop distance in water 0.313 bAo 1.634 exp(2aL) 2.028 2aL 0.707 V2A2 426.738 VoA2 2592.902 bAo*[exp(2aL)*(1-2aL)-l]/2aA2 -381.910 g*(exp(2aL)

wtr dens/beam dens -1)/a 257.178 Z2x 1200.191 Vs = (Zx)AO.5 34.644 ft/s Convert impact area to equivalent diameter 5.525 in mass = weight/g 6.217 lb-s2/ft thickness 0.065 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 90 10.2.2 Load Drop with Gate in Pool This scenario is during the movement of the gate from its installed location in the spent fuel pool to the gate opening between the spent fuel pool and cask pool, through the gate opening, then into the cask pool. Objects analyzed for this drop are the gate, intermediate lifting beam and alternate lifting beam. Potential points of impact for this drop are:

1) Spent fuel pool or cask pool floor at 70' elevation;

2) Gate opening floor at 88' elevation.

Object Lift Elevation For the initial movement the objects being evaluated had the following elevations:

Elevation of bottom of Gate = 90' (Ref. 11.2, pg. 8)

Elevation of bottom of Intermediate Lifting Beam = 115' (Ref. 11.2, pg. 8)

Elevation of bottom of Alternate Lifting Beam = 123' (Ref. 11.2, pg. 12)

Pool Min Level Elevation = 84.6645' + 23' = 107.6645' use 107.7' Determine Object Air Drop Distance Air Drop Distance = Lift Elevation - Pool Min Level Elevation Gate Air Drop Distance = Lift Elevation - Pool Min Level Elevation Gate Air Drop Distance = 90' - 107.7' = -17.7' As the gate is mostly submerged, the air drop distance for the gate is 0'. Correspondingly, the value for V0 and R will also be zero. As the Reynolds number is less than 1E3, the drag coefficient, CD will be assumed to be 1.00.

Intermediate Beam Air Drop Distance = Lift Elevation - Pool Min Level Elevation Intermediate Beam Air Drop Distance = 115' - 107.7' = 7.3' Alternate Beam Air Drop Distance = Lift Elevation - Pool Min Level Elevation Alternate Beam Air Drop Distance = 123' - 107.7' = 15.3'

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 91 Determine Water Drop Distance Because the gate is partially submerged, the water drop distance formula is as follows:

Gate Water Drop Distance = Elevation of Gate Bottom - Elevation of Impact Point For the Pool Floors Gate Water Drop Distance = 90' - 70' = 20' For the Gate Opening Gate Water Drop Distance = 90' - 88' = 2' As the beams have an initial elevation above the pool level, the beam water drop distance utilizes the same relationship as that utilized in Section 10.2.1.

Water Drop Distance = Pool Min Level Elevation - Elevation of Impact Point Pool Floor Water Drop Distance = 107.7 - 70' = 37.7' Gate Opening Water Drop Distance = 107.7'- 88' = 19.7' The following table provides a summary of the air drop distance, water drop distance H, the length of the dropped object, and the selected strike velocity function based upon the criteria above for each Load Drop case.

Case Description Air Drop Water Drop L ft Strike Distance, Distance, Velocity h ft H ft Function Gate Drop to Pool Floor 0' 20' 24.39' Zl(x)

Gate Drop to Gate Opening 0' 2' 24.39' Z1(x)

Intermediate Beam Drop to Pool Floor 7.3' 37.7' 4.75' Z2(x)

Intermediate Beam Drop to Gate Opening 7.3' 19.7' 4.75' Z2(x)

Alternate Beam Drop to Pool Floor 15.3' 37.7' 12' Z2(x)

Alternate Beam Drop to Gate Opening 15.3' 19.7' 12' Z2(x)

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 92 The inputs for the load drop cases are as follows:

All cases:

g = Acceleration of Gravity = 32.174 ft/sec 2 (Ref. 111.9, pg. B-10) 3 y = Density of water @ 160 deg. F = 60.994 lb/ft (Ref. 111.9, pg. A-6) v = Kinematic viscosity of water @ 160 deg. F = 0.439 E-5 ft2/s (Ref. 111.11)

K = constant related to grade of steel = 1 The inputs for the gate load drop cases are as follows:

L = Length of Spent Fuel Pool Gate = 24.39 ft (Ref. 11.1, pg. All) d = Width of Spent Fuel Pool Gate = 4.771 ft (Ref. 11.1, pg. All) t = Thickness of Spent Fuel Pool Gate = 0.3958 ft (Ref. 11.1, pg. 17)

W = Weight of Spent Fuel Pool Gate and Rigging = 2000 lbs (Ref. 111.1, pg. 4);

3

'yi = weight density of gate, lb/ft3 = 2000 lb / (24.39 ft

4.771 ft

0.3958 ft) = 43.424 lb/ft The inputs for the intermediate beam load drop cases are as follows:

L = Length of Intermediate Lifting Beam = 4.75 ft (Ref. 11.2, pg. 6) d = Width of Intermediate Lifting Beam = 0.4167 ft (Ref. 11.2, pg. 6) t = Thickness of Intermediate Lifting Beam = 0.4167 ft (Ref. 11.2, pg. 6)

W = Weight of Beam and Rigging = 175 lbs (Section 10.1.3) 3 7m = weight density of beam, lb/ft3 = 175 lb / (4.75 ft

0.4167 ft

0.4167 ft) = 212.177 lb/ft The inputs for the alternate beam load drop cases are as follows:

L = Length of Alternate Lifting Beam = 12' (Assumption 8.13) d = Width of Alternate Lifting Beam = 0.5 ft (Ref. 111.7, pg. 1-26) t = Thickness of Alternate Lifting Beam = 0.333 ft (Ref. 111.7, pg. 1-26)

W = Weight of Beam and Rigging = 200 lbs (Section 10.1.2) 3 ym = weight density of beam, lb/ft 3 = 200 lb / (12 ft

0.333 ft

0.5 ft) = 100.100 lb/ft

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 93 The inputs were entered into the Excel spread sheet with the results for each case shown in the following tables.

Gate Drop to Pool Floor Gate Length L 24.390 ft Gate Width, d 4.771 ft Gate thickness 0.396 ft Gate weight, W 2000.000 lb Gate density 43.424 lb/cu ft water density @ 160F 60.994 Ib/ cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 1.405 drop distance in air 0.000 ft drop distance in water 20.000 ft Vo where h is drop distance in air, V = (2gh)A2 0.000 ft/s Reynolds no =( Vo

d)/viscosity 0.000E+00 Check L/d using gate length and width 5.112 Check L/D using gate width and thickness 12.054 Drag Coefficient CD 1.000 Ao = width

thickness 1.888 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.029 b = (water density

g)/W 0.981 exp(-2*a*x) where x = drop distance in water 0.316 bAo 1.853 2ax 1.152 VoA2 0.000 g/a 1117.220 bAo*[(1-2ax)]/2aA2 -169.580 exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] -706.242 ZIx 241.398 Vs = (ZX)AO.5 15.537 ft/s Convert impact area to equivalent diameter 18.606 in mass = weight/g 62.170 tb-s2/ft thickness 0.031 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 94 Gate Drop in Gate Opening Gate Length L 24.390 ft Gate Width, d 4.771 ft Gate thickness 0.396 ft Gate weight, W 2000.000 lb Gate density 43.424 lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 1.405 drop distance in air 0.000 ft drop distance in water 2.000 ft Vo where h is drop distance in air, V = (2gh)^2 0.000 ft/s Reynolds no =( Vo

d)/viscosity 0.000 Check L/d using gate length and width 5.112 Check L/D using gate width and thickness 12.054 Drag Coefficient CD 1.000 Ao = width

thickness 1.888 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.029 b = (water density

g)/W 0.981 exp(-2*a*x) where x = drop distance in water 0.891 bAo 1.853 2ax 0.115 VoA2 0.000 g/a 1117.220 bAo*[(1-2ax)]/2aA2 988.540 exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] -1991.348 Zlx 114.412 Vs = (7x)AO.5 10.696 ft/s Convert impact area to equivalent diameter 18.606 in mass = weight/g 62.170 lb-s2/ft thickness 0.019 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 95 Intermediate Beam Drop to Pool Floor Beam Length L 4.750 ft Beam Width, d 0.417 ft Beam thickness 0.417 ft Beam weight, W 175.000 lb Beam density 212.177 lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 0.287 drop distance in air 7.300 ft drop distance in water 37.700 ft Vo where h is drop distance in air, V = (2gh)A2 21.672 ft/s Reynolds no =( Vo

d)/viscosity 2.057E+06 Check L/d using beam length and width 11.399 Check L/D using beam width and thickness 1.000 Drag Coefficient CD 1.160 Ao = width

thickness 0.174 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.035 b = (water density

g)/W 11.212 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) 25.554 exp(-2*a*x) where x = drop distance in water 0.071 bAo 1.947 exp(2aL) 1.396 2aL 0.333 V2A2 653.027 VoA2 469.682 bAo* [exp(2aL)* (1-2aL)-1]/2aA2 -55.030 g*(exp(2aL)

wtr dens/beam dens -1)/a -548.751 Z2x 643.521 Vs = (Zx)A0.5 25.368 ft/s Convert impact area to equivalent diameter 5.642 in mass = weight/g 5.440 Ib-s2/ft thickness 0.038 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 96 Intermediate Beam Drop to Gate Opening Beam Length L 4.750 ft Beam Width, d 0.417 ft Beam thickness 0.417 ft Beam weight, W 175.000 lb Beam density 212.177 lb/cu ft water density @ 160F 60.994 Ib/cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 0.287 drop distance in air 7.300 ft drop distance in water 19.700 ft Vo where h is drop distance in air, V = (2gh)^2 21.672 ft/s Reynolds no =( Vo

d)/viscosity 2.057E+06 Check L/d using beam length and width 11.399 Check L/D using beam width and thickness 1.000 Drag Coefficient CD 1.160 Ao = width

thickness 0.174 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.035 b = (water density

g)/W 11.212 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) .25.554 ft/s exp(-2*a*x) where x = drop distance in water 0.251 bAo 1.947 exp(2aL) 1.396 2aL 0.333 V2A2 653.027 VoA2 469.682 bAo* [exp(2aL)*(1-2aL)-l]/2aA2 -55.030 g*(exp(2aL)

wtr dens/beam dens -1)/a -548.751 Z2x 619.392 Vs = (Zx)AO.5 24.888 ft/s Convert impact area to equivalent diameter 5.642 in mass = weight/g 5.440 lb-s2/ft thickness 0.037 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 97 Alternate Beam Drop to Pool Floor Beam Length L 12.000 ft Beam Width, d 0.500 ft Beam thickness 0.333 ft Beam weight, W 200.000 lb Beam density 100.100 lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 0.609 drop distance in air 15.300 ft drop distance in water 37.700 ft Vo where h is drop distance in air, V = (2gh)A2 31.375 ft/s Reynolds no =( Vo

d)/viscosity 3.573E+06 Check L/d using beam length and width 24.000 Check L/D using beam width and thickness 1.502 Drag Coefficient CD 1.160 Ao = width

thickness 0.167 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.029 b = (water density

g)/W 9.811 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) 20.658 ft/s exp(-2*a*x) where x = drop distance in water 0.109 bAo 1.634 exp(2aL) 2.028 2aL 0.707 V2A2 426.738 VOA2 984.402 bAo* [exp(2aL)*(1-2aL)-l]/2aA2 -381.910 g*(exp(2aL)

wtr dens/beam dens -1)/a 257.178 Z2x 520.050 Vs = (Zx)A0.5 22.805 ft/s Convert impact area to equivalent diameter 5.525 in mass = weight/g 6.217 lb-s2/ft thickness 0.037 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 98 Alternate Beam Drop to Gate Opening Beam Length L 12.000 ft Beam Width, d 0.500 ft Beam thickness 0.333 ft Beam weight, W 200.000 lb Beam density 100.100 lb/cu ft water density @ 160F 60.994 Ib/ cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 0.609 drop distance in air 15.300 ft drop distance in water 19.700 ft Vo where h is drop distance in air, V = (2gh)A2 31.375 ft/s Reynolds no =( Vo

d)/viscosity 3.573E+06 Check L/d using beam length and width 24.000 Check L/D using beam width and thickness 1.502 Drag Coefficient CD 1.160 Ao = width

thickness 0.167 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.029 b = (water density

g)/W 9.811 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) 20.658 ft/s exp(-2*a*x) where x = drop distance in water 0.313 bAo 1.634 exp(2aL) 2.028 2aL 0.707 V2A2 426.738 VoA2 984.402 bAo* [exp(2aL)*(1-2aL)-l]/2aA2 -381.910 g*(exp(2aL)

wtr dens/beam dens -1)/a 257.178 Z2x 696.134 Vs = (Zx)A0.5 26.384 ft/s Convert impact area to equivalent diameter 5.525 in mass = weight/g 6.217 Ib-s2/ft thickness 0.045 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 99 Using the calculated steel thickness to just experience perforation calculated in Sections 10.2.1 and 10.2.2, determine the minimum required liner thickness to prevent perforation based upon the following equation:

Thickness required to prevent steel perforation = T

1.25 (Ref. 11.4 pg. 2)

Where:

T = steel thickness to just be perforated, in For the Max Gate Drop to Cask Pool Floor case T = 0.042 in Thickness required to prevent steel perforation = T

1.25 Thickness required to prevent steel perforation = 0.042 in

1.25 = 0.053 in This formula was placed in an Excel spread sheet to determine the thickness required to prevent steel perforation for the balance of the liner impact drop cases. The results are shown in the table below.

Case Description Calculated Thickness Actual Perforation Required to Liner Thickness, Prevent Thickness, T, in Perforation, in in Max Gate Drop to Cask Pool Floor 0.042 0.053 0.188 Max Gate Drop to Cask Pool Shelf 0.048 0.060 0.188 Max Gate Drop to Gate Opening 0.038 0.048 0.188 Max Intermediate Beam Drop to Cask Pool Floor 0.043 0.054 0.188 Max Intermediate Beam Drop to Cask Pool Shelf 0.057 0.071 0.188 Max Intermediate Beam Drop to Gate Opening 0.052 0.065 0.188 Max Alternate Beam Drop to Cask Pool Floor 0.045 0.056 0.188 Max Alternate Beam Drop to Cask Pool Shelf 0.074 0.093 0.188 Max Alternate Beam Drop to Gate Opening 0.065 0.081 0.188 Gate in Water Gate Drop to Pool Floor 0.031 0.039 0.188 Gate in Water Gate Drop to Gate Opening 0.019 0.024 0.188 Gate in Water Intermediate Beam Drop to Pool Floor 0.038 0.048 0.188 Gate in Water Intermediate Beam Drop to Gate Opening 0.037 0.046 0.188 Gate In Water Alternate Beam Drop to Pool Floor 0.037 0.046 0.188 Gate in Water Alternate Beam Drop to Gate Opening 0.045 0.056 0.188 In all analyzed cases, the actual pool liner thickness exceeds the thickness required to prevent steel perforation resulting from impact of the dropped load. As the steel liner will not be perforated as a result of the analyzed load drops, no liner leakage will occur as a result of the impact. Given that no leakage will occur due to impact of the dropped load, no water makeup to accommodate leakage is required.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 100 10.2.3 Load Drop Spent Fuel Storage Rack Strike Velocity This section is to determine the strike velocity of the objects during the movement of the gate from its installed location in the spent fuel pool to the gate opening when the potential exists for these objects to impact the fuel storage racks. Objects analyzed for this drop are the gate, intermediate lifting beam and alternate lifting beam. The point of impact for this scenario is the top of the racks.

Elevation of Top of Fuel Racks = 177" + 70'1-5/16" = 84.86' (Ref. 11.8)

Object Lift Elevation For the initial movement the objects being evaluated had the following elevations:

Elevation of bottom of Gate = 90' (Ref. 11.2, pg. 8)

Elevation of bottom of Intermediate Lifting Beam = 115' (Ref. 11.2, pg. 8)

Elevation of bottom of Alternate Lifting Beam = 123' (Ref. 11.2, pg. 12)

Pool Min Level Elevation = 84.6645' + 23' = 107.6645' use 107.7' Determine Object Air Drop Distance As the initial drop elevations are identical to that in Section 10.2.2, the air drop distance is unchanged from that determined in Section 10.2.2.

Determine Water Drop Distance to Top of Racks Because the gate is partially submerged, the water drop distance formula is as follows:

Gate Water Drop Distance = Elevation of Gate Bottom - Elevation of Impact Point Gate Water Drop Distance = 90' - 84.86' = 5.14' As the beams have an initial elevation above the pool level, the beam water drop distance utilizes the same relationship as that utilized in Section 10.2.1.

Water Drop Distance = Pool Min Level Elevation - Elevation of Impact Point Rack Water Drop Distance = 107.7 - 84.86" = 22.84'

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 101 The following table provides a summary of the air drop distance, water drop distance H, the length of the dropped object, and the selected strike velocity function based upon the criteria above for each Load Drop case.

Case Description Air Drop Water Drop L ft Strike Distance, Distance, Velocity h ft H ft Function Gate Drop to Racks 0' 5.14' 24.39' Zi(x)

Intermediate Beam Drop to Racks 7.3' 22.84' 4.75' Z2(x)

Alternate Beam Drop to Racks 15.3' 1 22.84' 12' Z2(x)

The other inputs for the load drop cases are the same as Section 10.2.2.

The inputs were entered into the Excel spread sheet with the results for each case shown in the following tables.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 102 Gate Drop to Racks Gate Length L 24.390 ft Gate Width, d 4.771 ft Gate thickness 0.396 ft Gate weight, W 2000.000 lb Gate density 43.424 lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 1.405 drop distance in air 0.000 ft drop distance in water 5.140 ft Vo where h is drop distance in air, V = (2gh)A2 0.000 ft/s Reynolds no =( Vo

d)/viscosity 0.000 Check L/d using gate length and width 5.112 Check L/D using gate width and thickness 12.054 Drag Coefficient CD 1.000 Ao = width *.thickness 1.888 ft2 a z (water density

Drag Coeff

Ao )/(2*W) 0.029 b = (water density

g)/W 0.981 exp(-2*a*x) where x = drop distance in water 0.744 bAo 1.853 2ax 0.296 VoA2 0.000 g/a 1117.220 bAo*[(1-2ax)]/2aA2 786.512 exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] -1661.933 ZIx 241.800 Vs = (Zx)AO.5 15.550 ft/s

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 103 Intermediate Beam Drop to Racks Beam Length L 4.750 ft Beam Width, d 0.417 ft Beam thickness 0.417 ft Beam weight, W 175.000 lb Beam density 212.177 lb/cu ft water density @ 160F 60.994 Ib/ cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/beam density 0.287 drop distance in air 7.300 ft drop distance in water 22.841 ft Vo where h is drop distance in air, V = (2gh)A2 21.672 ft/s Reynolds no =( Vo

d)/viscosity 2.057E+06 Check L/d using beam length and width 11.399 Check L/D using beam width and thickness 1.000 Drag Coefficient CD 1.160 Ao = width

thickness 0.174 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.035 b = (water density

g)/W 11.212 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) 25.554 ft/s exp(-2*a*x) where x = drop distance in water 0.201 bAo 1.947 exp(2aL) 1.396 2aL 0.333 V2A2 653.027 VoA2 469.682 bAo* [exp(2aL)*(1-2aL)-l]/2aA2 -55.030 g*(exp(2aL)

wtr dens/beam dens -1)/a -548.751 Z2x 626.048 Vs = (Zx)AO.5 25.021 ft/s

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 104 Alternate Beam Drop to Racks Beam Length L 12.000 ft Beam Width, d 0.500 ft Beam thickness 0.333 ft Beam weight, W 200.000 lb Beam density 100.100 lb/cu ft water density @ 160F 60.994 Ib/cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/beam density 0.609 drop distance in air 15.300 ft drop distance in water 22.840 ft Vo where h is drop distance in air, V = (2gh)A2 31.375 ft/s Reynolds no =( Vo

d)/viscosity 3.573E+06 Check L/d using beam length and width 24.000 Check L/D using beam width and thickness 1.502 Drag Coefficient CD 1.160 Ao = width

thickness 0.167 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.029 b = (water density

g)/W 9.811 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) 20.658 ft/s exp(-2*a*x) where x = drop distance in water 0.260 bAo 1.634 exp(2aL) 2.028 2aL 0.707 V2A2 426.738 VoA2 984.402 bAo*[exp(2aL)* (1-2aL)-1]/2aA2 -381.910 g*(exp(2aL)

wtr dens/beam dens -1)/a 257.178 Z2x 650.645 Vs = (Zx)A0.5 25.508 ft/s

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 105 Results summary The strike velocity of each object on the spent fuel pool storage racks is as follows:

Gate 15.550 ft/s Intermediate Beam 25.021 ft/s Alternate Beam 25.508 ft/s

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 106 10.3 Damage to Fuel Rack Assembly Damage to the Spent Fuel Pool Rack will be analyzed within two impact cases. Case 1 will analyze the damage to the fuel rack by objects (gate, intermediate lifting beam, alternate lifting beam) that impact the centerline of empty fuel cells. This bounding case would analyze the minimum amount of structural material resisting the energy of each object dropped, which would maximize the length of damage.

The fuel racks are rated for an impact energy of 3800 ft-lb. Case 2 will analyze the impact velocities of the dropped objects to determine if these impact energies are bounded. Each impact case will evaluate all previously analyzed objects (gate, intermediate lifting beam, alternate lifting beam).

Case 1 The poison material within the fuel pool racks is 16.22 inches below the top of the rack. It is necessary to demonstrate that the accidental drop of an object will not violate the criticality requirements. The following equation can be used to determine the length of damage.

L = Ei /(U)(Ai)

L = Length of Damage (in)

E= Total Impact Energy of Falling Object (in-lb)

U = Strain Energy for Unit Volume (in-lb/in 3)

Ai = Area of Impact Contact (in2)

In order to solve for length of damage, the area of impact contact must first be calculated. The following equation can be used to determine the area of impact contact.

Ai = (N)(I)(t)

Ai = Area of Impact Contact (in2 )

N = Number of Plates in Impact Zone I = Contact Length per Plate (in) t = Plate Thickness (in)

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 107 Part A (Spent Fuel Pool Gate)

The number of plates within the impact zone is determined by dividing the width of the gate by the bundle spacing.

(4.771 ft) / (0.5208 ft) = 9.16 bundles are impacted Therefore, the gate has the potential to impact a minimum of 9 plates. Using the minimum number of plates for calculation is conservative because this minimizes the area of support that resists the energy of the drop.

Ai = (N)(l)(t)

Ai = (9)(4.75 in.)(0.075 in.)

2 Al = 3.206 in It is conservatively assumed that the entire potential energy of the drop is transferred into the rack in one impact.

L = Ei(U)(Ai)

E= PE = 12000 ft-lb = 144000 in-lb (Section 10.1.1, pg. 27)

L = (144000 in-lb) / (19740 in-lb/in 3)(3.206 in2 )

L = 2.275 in < 16.22 in to poison material Part B (Alternate Lifting Beam)

The number of plates within the impact zone is determined by dividing the width and depth of the beam by the bundle spacing.

(0.333 ft) / (0.5208 ft) = 0.6394 bundles are impacted (0.5 ft) / (0.5208 ft) = 0.9601 bundles are impacted Therefore, the beam has the potential to impact a minimum of 1 plate. Using the minimum number of plates for calculation is conservative because this minimizes the area of support that resists the energy of the drop.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 108 Note: A W6x12 beam will be used for the Alternate Lifting Beam. 4"'6"'x" plates will be welded to each end of the beam. These plates will increase the surface area of the ends of the beam, reducing the damage to the fuel rack, if dropped. Four inches is used for the length of impact because this will be the smallest dimension of the plate that is attachedto the beam.

Ai = (N)(I)(t)

Ai = (1)(4 in.)(0.075 in.)

2 Ai = 0.3 in It is conservatively assumed that the entire potential energy of the drop is transferred into the rack in one impact.

L = EI/(U)(Ai)

Ei = PE = 7800 ft-lb = 93600 in-lb (Section 10.1.2, pg. 37)

L = (93600 in-lb) 1(19740 in-lb/in 3 )(0.3 in2 )

L = 15.81 in < 16.22 in to poison material Part C (Intermediate Lifting Beam)

The number of plates within the impact zone is determined by dividing the width and depth of the beam by the bundle spacing.

(0.4167 ft) / (0.5208 ft) = 0.8001 bundles are impacted (0.4167 ft) / (0.5208 ft) = 0.8001 bundles are impacted Therefore, the beam has the potential to impact a minimum of 1 plate. Using the minimum number of plates for calculation is conservative because this minimizes the area of support that resists the energy of the drop.

Note: A TS5x5xY beam will be used for the Intermediate Lifting Beam. Plates will be welded to each end of the beam, per Ref 11-2, pg. 6. These plates will increase the surface area of the ends of the beam, reducing the damage to the fuel rack, if dropped. Five inches is used for the length of impact because this will be the smallest dimension of the plate that is attached to the beam.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 109 Ai = (N)(l)(t)

Ai = (1)(5 in.)(0.075 in.)

2 Ai = 0.375 in It is conservatively assumed that the entire potential energy of the drop is transferred into the rack in one impact.

L = E / (U)(Ai)

EI = PE = 5425 ft-lb = 65100 in-lb (Section 10.1.3, pg. 45)

L = (65100 in-lb) / (19740 in-lb/in 3 )(0.375 in2)

L = 8.794 in < 16.22 in to poison material Case 2 The fuel racks are rated for an impact energy of 3800 ft-lb. Case 2 will analyze the impact velocities of the dropped objects to determine if these impact energies are bounded per (Ref.

11-10).

The rack strike velocity for each object determined in Section 10.2.3 are as follows:

Gate 15.550 ft/s Intermediate Beam 25.021 ft/s Alternate Beam 25.508 ft/s

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 110 Part A (SDent Fuel Pool Gate)

K= 2(M)(\2) (Ref. 11-9, pg. 4)

Where:

K = Kinetic Energy M = Mass V = Velocity K= / (2000 Ibs)(15.550 ft/s) 2 (1 / 32.174 ft/s 2 )

Note: The (1 / 32.174 ft/s 2 ) term in the equation above is needed to convert to the correct units.

K = 7515.463 ft-lb Since the Spent Fuel Pool Gate has the minimum potential to impact 5 fuel bundles (conservatively assuming that the fuel rack is 50% full), we must divide this impact energy by 5.

K = (7515.463) / (5) = 1503.093 ft-lb 3800 ft-lb Therefore, OK.

Part B (Alternate Lifting Beam)

K y2(M)(V2) (Ref. 11-9, pg. 4)

Where:

K = Kinetic Energy M = Mass V = Velocity K = / (200 lbs)(25.508 ft/s) 2 (1 / 32.174 ft/s 2 )

Note: The (1 / 32.174 ft/s 2) term in the equation above is needed to convert to the correct units.

K = 2022.31 ft-lb < 3800 ft-lb Therefore, OK.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 I REVISION: 0 PAGE: 111 Part C (Intermediate Lifting Beam)

K = 1/2(M)(V2) (Ref. 11-9, pg. 4)

Where:

K = Kinetic Energy M = Mass V = Velocity K = 1/2 (175 lbs)(25.021 ft/s) 2 (1 /32.174 ft/s 2)

Note: The (1 /32.174 ft/s 2) term in the equation above is needed to convert to the correct units.

K = 1702.599 ft-lb < 3800 ft-lb Therefore, OK.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 112 10.4 Impact of Gate Drop on Fuel Pool Cooling Piping The only safe shutdown equipment with the potential to be affected by a Spent Fuel Pool Gate Movement load drop are the suction and return lines for the Spent Fuel Pool Cooling portion of the Fuel Pool Cooling and Cleanup System (SFC).

The Spent Fuel Cooling suction piping consists of two (2) 12" diameter lines located on the south wall of the Spent Fuel Pool. Each line penetrates horizontally into the pool at elevation 110' for approximately 16 inches then turns 90 degrees downward extending to nominal elevation 83' 6" where the lines transition into a nominal 6" diameter horizontal suction header located at elevation 83'. (Ref. 11.16, 18, 19, 20, 21,22)

The Spent Fuel Cooling discharge piping consists of two (2) 12" diameter lines located on the north wall of the Spent Fuel Pool. Each line penetrates horizontally into the pool at elevation 110' for approximately 16 inches then turns 90 degrees downward extending to nominal elevation 72'0" where the lines transition into a nominal 6" diameter horizontal distribution sparger located at elevation 71'6". (Ref. 11.16, 18, 19, 20, 21,22)

A general diagram of the piping layout is shown below. (Ref. 11.11, 13, 16, 18, 19, 20, 21,22)

T 4.943' (typ) 9.693 (typ)

I C, El.110' (typ)

Plan Elevation 113' Spent Fuel Pool Area

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 113 The pool gates have adequate length that they could potentially strike the cooling piping following an initial impact on the spent fuel storage racks, i.e. in the transition to Position 2 or 3 as described in Section 10.1.1. The piping could be struck as the top of the gate moves downward toward the storage racks. The highest potential location for the impact of each line is determined by:

1. Calculating the horizontal distance between the following locations using the formula a 2 +

b2 = c 2 . Refer to the previous general diagram for the locations of Points A and B.

" Point A and line SFC-012-001-3.

" Point A and line SFC-012-014-3.

" Point B and line SFC-012-006-3.

2. Using the a 2 + b 2 = c 2 formula with the previously calculated horizontal distance and the 24.39' gate length, the vertical distance where the subject pipe will be struck by the top of the gate is determined. The vertical distance is added to the top elevation of the spent fuel storage racks of 84.86' to determine the elevation where the gate strikes the applicable line.

3. The elevation of the gate strike is compared to the minimum water level elevation. As long as any damage, such as distortion (denting), a crack or other opening, is below the elevation of the minimum water level, the cooling function can continue to be maintained as the flowpath via the line will still be intact.

Horizontal Distance The triangles shown on the diagram below represent determination of the distance between Point A and line SFC-01 2-001-3 and the determination of the distance between Point B and line SFC-012-006-3. Determination of the distance for the remaining two lines is similar.

GateOpening 4.943' 17" 99 9.693 . 012-006-3 012-oz-l110'(typ- .

U cooling Return Cooling Suction

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 114 Distance Fuel Pool Cooling Piping Extends into Pool SFC-012-001-3 = 1.302' (Ref. 11.18)

SFC-012-014-3 = 1.302' (Ref. 11.19)

SFC-012-006-3 = 1.5' (Ref. 11.20)

SFC-012-007-3 = 1.33' (Ref. 11.21)

Point A and line SFC-012-001-3. SFC-012-001-3 extends 1.302' into the pool. (Ref. 11.18)

Distance from southeast pool corner to SFC-012-001-3 = 4.943' North-South distance from Point A to line SFC-01 2-001-3 = 10.99'- 1.302' Distance from Point A to SFC-012-001-3 = [(4.943 )2 + (10.99'-1.302 )2]0.5 = 10.88' Point A and line SFC-012-014-3. SFC-012-014-3 extends 1.302' into the pool. (Ref. 11.19)

Distance from southeast pool corner to SFC-012-014-3 = 9.693' North-South distance from Point A to line SFC-012-001-3 = 10.99'- 1.302' Distance from Point A to SFC-012-014-3 = [(9.693 )2 + (10.99'-1.302 )2]°05 = 13.70' Point B and line SFC-012-006-3. SFC-012-006-3 extends 1.5' into the pool. (Ref. 11.20)

Distance from northeast pool corner to SFC-012-006-3 = 4.943' North-South distance from Point B to line SFC-012-006-3 = 17.99'- 1.5' Distance from Point B to SFC-012-006-3 = [(4.943 )2 + (17.99'-1.5')2]0.5 = 17.21' Point B and line SFC-012-007-3. SFC-012-007-3 extends 1.33' into the pool. (Ref. 11.21)

Distance from northeast pool corner to SFC-01 2-007-3 = 9.693' North-South distance from Point B to line SFC-012-007-3 = 17.99'- 1.33' Distance from Point B to SFC-012-007-3 = [(9.693')2 + (17.99'-1.33')2]0.5 = 19.27'

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 115 Vertical Distance and Gate Strike Elevation The diagram below represents the determination of the vertical height above the gate bottom elevation where the top of the gate will impact the subject pipe.

Height of impact Gate length = 24.39' with pipe above bottom elevation of gate.

Horizontal distance between point A or Band subject pipe.

SFC-012-001-3 Horizontal distance = 10.88' Gate length = 24.39' Vertical distance = [ (24.39 )2 - (10.88')2 ]0.5 = 21.83' Gate strike elevation = Top of rack elevation + vertical distance Gate strike elevation = 84.86 + 21.83 = 106.69' elevation SFC-012-014-3 Horizontal distance = 13.70' Gate length = 24.39' Vertical distance = [ (24.39')2 - (13.70')2 ]0.5 = 20.18' Gate strike elevation = Top of rack elevation + vertical distance Gate strike elevation = 84.86 + 20.18 = 105.04' elevation

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 116 SFC-012-006-3 Horizontal distance = 17.21' Gate length = 24.39' Vertical distance = [(24.39')2 - (17.21')2 ]0.5 = 17.28' Gate strike elevation = Top of rack elevation + vertical distance Gate strike elevation = 84.86 + 17.28 = 102.14' elevation SFC-012-007-3 Horizontal distance = 19.27' Gate length = 24.39' Vertical distance = [ (24.39')2 - (19.27')2 ]0.5 = 14.95' Gate strike elevation = Top of rack elevation + vertical distance Gate strike elevation = 84.86 + 14.95 = 99.81' elevation Minimum spent fuel pool water level elevation = 107.7' (previously determined in Section 10.2.1)

Results Summary Line Number Gate Strike Elevation Minimum Pool Level Elevation SFC-012-001-3 106.69' 107.7' SFC-012-014-3 105.04' 107.7' SFC-012-006-3 102.14' 107.7' SFC-012-007-3 99.81' 107.7' To assess the structural response of the piping due to the impact of the gate, the strike velocity is estimated using the methodology in Section 10.2.3. Because the gate has already struck the racks/fuel after dropping vertically, and is moving to Position 2 or 3 as indicated in Section 10.1.1, the dimensions representing length, width, and thickness with respect to the velocity equation have changed, as the area moving approximately perpendicular to the piping is the dimension of 24.390' and either the dimension of 4.771' (transition to Position 2) or the dimension of 0.396' (transition to Position 3). For the purposes of the velocity determination the gate width will be established as the 24.390' dimension and the gate dimension of 0.396' as the thickness.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 117 The Top of Gate drop distance is determined as follows:

Top of Gate drop distance = (Gate length + top of rack elevation) - Gate strike elevation As the center of gravity of the gate is located at the halfway point of the gate length, the water drop distance of the center of gravity is determined as follows:

Water drop distance = Top of gate drop distance / 2 The piping is treated as a simply supported steel beam as indicated in Ref. 11.4 page 4-5 description 2. This is based upon the upper end of the pipe being fixed in position via the attachment to the liner embedment above the strike elevation and supported by a pipe support below the strike elevation as shown on Ref. 11.18, 19, 20, 21, 22.

Determine Top of Gate Drop Distance:

Top of gate drop distance = (Gate length + top of rack elevation) - Gate strike elevation Gate length = 24.39' Top of rack elevation = 84.86' SFC-012-001-3 Gate Strike Elevation = 106.69' SFC-012-001-3 Top of gate drop distance = (24.39' + 84.86') - 106.69' = 2.56' Determine Water Drop Distance As the center of gravity of the gate is located at the halfway point of the gate length, the water drop distance of the center of gravity is determined as follows:

Water drop distance = Top of gate drop distance / 2 SFC-01 2-001-3 Water drop distance = 2.56'/ 2 = 1.28' The water drop distance for the balance of the lines is shown in the table below.

Line Number Gate Strike Elevation Water Drop Distance SFC-012-001-3 106.69' 1.28' SFC-012-014-3 105.04' 2.105' SFC-012-006-3 102.14' 3.555' SFC-012-007-3 99.81' 4.72'

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 118 The strike velocity is calculated using the methodology from Section 10.2.3. The Excel spread sheet for each line is shown on the following pages.

Gate Tip Onto Piping SFC-012-001-3 Gate Length L 4.771 ft Gate Width, d 24.390 ft Gate thickness 0.396 ft Gate weight, W 2000.000 lb Gate density 43.402 lb/cu ft water density @ 160F 60.994 Ib cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 1.405 drop distance in air 0.000 ft drop distance in water 1.280 ft Vo where h is drop distance in air, V = (2gh)A2 0.000 ft/s Reynolds no =( Vo

d)/viscosity 0.000 Check L/d using gate length and width 0.196 Check L/D using gate width and thickness 61.591 Drag Coefficient CD 1.000 Ao = width

thickness 9.658 ft2 a = (water density

Drag Coeff

Ao )/(2*W) 0.147 b = (water density

g)/W 0.981 exp(-2*a*x) where x = drop distance in water 0.686 bAo 9.476 2ax 0.377 VoA2 0.000 g/a 218.432 bAo*[(1-2ax)]/2aA2 136.077 exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] -299.644 ZIx 54.865 Vs = (Zx)AO.5 7.407 ft/s Convert impact area to equivalent diameter 1.596 in mass = weight/g 62.170 lb-s2/ft thickness 0.133 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 119 Gate Tip Onto Piping SFC-012-014-3 Gate Length L 4.771 ft Gate Width, d 24.390 ft Gate thickness 0.396 ft Gate weight, W 2000.000 lb Gate density 43.402 lb/cu ft water density @ 160F 60.994 Ib/ cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 1.405 drop distance in air 0.000 ft drop distance in water 2.105 ft Vo where h is drop distance in air, V = (2gh)A2 0.000 ft/s Reynolds no =( Vo

d)/viscosity 0.000 Check L/d using gate length and width 0.196 Check L/D using gate width and thickness 61.591 Drag Coefficient CD 1.000 Ao = width

thickness 9.658 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.147 b = (water density

g)/W 0.981 exp(-2*a*x) where x = drop distance in water 0.538 bAo 9.476 2ax 0.620 VoA2 0.000 g/a 218.432 bAo* [(1-2ax)]/2aA2 82.997 exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] -235.001 Zix 66.428 Vs = (Zx)AO.5 8.150 ft/s Convert impact area to equivalent diameter 1.596 in mass = weight/g 62.170 lb-s2/ft thickness 0.151 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 120 Gate Tip Onto Piping SFC-012-006-3 Gate Length L 4.771 ft Gate Width, d 24.390 ft Gate thickness 0.396 ft Gate weight, W 2000.000 lb Gate density 43.402 lb/cu ft water density @ 160F 60.994 Ib/ cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 1.405 drop distance in air 0.000 ft drop distance in water 3.555 ft Vo where h is drop distance in air, V = (2gh)A2 0.000 ft/s Reynolds no =( Vo

d)/viscosity 0.000 Check L/d using gate length and width 0.196 Check L/D using gate width and thickness 61.591 Drag Coefficient CD 1.000 Ao = width

thickness 9.658 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.147 b = (water density

g)/W 0.981 exp(-2*a*x) where x = drop distance in water 0.351 bAo 9.476 2ax 1.047 VoA2 0.000 g/a 218.432 bAo* [(1-2ax)]/2aA2 -10.296 exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] -153.314 ZIx 54.822 Vs = (Zx)A0.5 7.404 ft/s Convert impact area to equivalent diameter 1.596 in mass = weight/g 62.170 lb-s2/ft thickness 0.133 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 121 Gate Tip Onto Piping SFC-012-007-3 Gate Length L 4.771 ft Gate Width, d 24.390 ft Gate thickness 0.396 ft Gate weight, W 2000.000 lb Gate density 43.402 lb/cu ft water density @ 160F 60.994 Ib/ cu ft water kinematic viscosity @ 160F 4.390E-06 sq ft/sec water density/gate density 1.405 drop distance in air 0.000 ft drop distance in water 4.720 ft Vo where h is drop distance in air, V = (2gh)A2 0.000 ft/s Reynolds no =( Vo

d)/viscosity 0.000 Check L/d using gate length and width 0.196 Check L/D using gate width and thickness 61.591 Drag Coefficient CD 1.000 Ao = width

thickness 9.658 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) 0.147 b = (water density

g)/W 0.981 exp(-2*a*x) where x = drop distance in water 0.249 bAo 9.476 2ax 1.390 VoA2 0.000 g/a 218.432 bAo*[(1-2ax)]/2aA2 -85.252 exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] -108.780 Zlx 24.399 Vs = (Zx)AO.5 4.940 ft/s Convert impact area to equivalent diameter 1.596 in mass = weight/g 62.170 lb-s2/ft thickness 0.078 in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 122 For the structural evaluation of the piping, the piping is treated as a simply supported steel beam as indicated in Ref. 11.4 page 4-5 description 2. This is based upon the upper end of the pipe being fixed in position via the attachment to the liner embedment above the strike elevation and supported by a pipe support below the strike elevation as shown on References 11.16, 18, 19, 20, 21, and 22 Because the pipe has a round surface subject to impact rather than a flat surface subject to impact as in the case of the beam configuration, the contact length between the pipe and the gate is assumed to be 2" (Refer to Assumption 8.15).

Elevation of Fuel Pool Cooling Piping Connection to Liner Embed SFC-012-001-3 = 110' 0" (Ref. 11.18)

SFC-012-014-3 = 110' 0" (Ref. 11.19)

SFC-012-006-3 = 110' 0" (Ref. 11.20,11.22)

SFC-01 2-007-3 = 110' 0" (Ref. 11.21)

Elevation of First Support below Liner Embed Connection SFC-012-001-3 = 86' 0" (Ref. 11.18)

SFC-012-014-3 = 86' 0" (Ref. 11.19)

SFC-012-006-3 = 92' 0" (Ref. 11.20,11.22)

SFC-012-007-3 = 92' 0" (Ref. 11.21)

Distance between supports:

SFC-012-001-3 110' 0"- 86' 0"= 24' (Ref. 11.18 SFC-012-014-3 110' 0"-86' 0" 24' (Ref. 11.19)

SFC-012-006-3 110' 0"- 92' 0"= 18' (Ref. 11.20,11.22)

SFC-012-007-3 110' 0"- 92' 0"= 18' (Ref. 11.21)

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 123 Note: The following sections are performed for line SFC-012-001-3. These formulas have been included in an Excel spread sheet and the cases for the balance of the lines will be shown in the spread sheet format.

Determine Target Effective Mass Me = (Dx + 2d)

Mx Ref. 11.4 pg. 3-6 Where:

Me = Average effective mass of target during impact, lb Mx = Mass per unit length of steel beam Dx = Maximum missile contact dimension in the x direction, inches d = depth of steel beam, inches Pipe weight per unit length = 49.56 lb / ft of length Ref. 111.9 pg. B-17 d = Pipe Outer Diameter = 12.75" Ref. 111.9 pg. B-17 Dx= 2" Assumption 8.15 Me = (Dx + 2d)

Mx Me = (2"/12 in/ft + (2

12.75)/12 in/ft)

49.56 lb/ft / 32.174 = 3.53 lb Determine the Strain Energy resulting from the impact Es = (Mm2

VM2) / [ 2* (Mm + Me)] Ref. 11.4 pg. 3-5 Where:

Es = strain energy, in-lb Mm = Mass of the missile, lb Me = Effective mass of target during impact, lb V, = Missile striking velocity, in/s Mm = Mass of the gate = 2000 lb/32.174 = 62.162 lb Me = 3.53 lb V = 7.407 ft/s

12 in/ft = 88.884 in/s

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 124 Es = (Mm 2

Vs2) I [ 2* (Mm + Me)]

Es = (62.1622

88.8842)/ [ 2* (62.162 + 3.530)] = 232,356.411 in-lb Determine the Plastic Resistinqj Force Rm = (8*l*fdy) / (L'd) Ref. 11.4 pg. E-3 Where:

Rm = plastic resisting force, 4 lb I = moment of inertia, in fdy = allowable dynamic strength value = (DIF)

fstat DIF = dynamic increase factor = 1 Fstat = static strength (yield strength), psi L = Length of beam, inches d = depth of steel beam, inches 4

I = moment of inertia, in4 = 279.3 in (Ref. 111.9, pg. B-17)

Fstat = 30 ksi (Ref. 111.13, pg. 76, 77)

L = 24' (convert to inches) d = 12.75" (Ref. 111.9, pg. B-17)

Rm = (8*l*fdy) (L*d)

Rm = (8* 279.3 in4

30,000 psi ) / ( 24 ft

12 in/ft

12.75 in ) = 18,254.902 lb Determine the Yield Displacement X, RmL 3 / 48EI Ref. 11.4 pg. 4-5 Where:

Xe = yield displacement, in Rm = plastic resisting force, lb L = Length of beam, inches 2 E = modulus of elasticity, lb/in 4

I = moment of inertia, in Modulus of Elasticity, E, at 200 deg F for TP 304 SS = 27.7E6 lb / in2 (Ref. 111.12, pg. 6-92)

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 125 X= RmL 3 / 48EI Xe = (18,254.902 * (24'

12 in/ft) 3 ) / (48

27.7 E6 lb/in 2

279.3 in4) = 1.174 in Determine the Ductility Ratio g~r = [(Es / (Xe

Rm)] + 0.5 Ref. 11.4 pg. 3-8 Where:

r= required ductility ratio Es= strain energy, in-lb Rm = plastic resisting force, lb Xe = yield displacement, in Es= 232,356.411 in-lb Rm = 18,254.902 lb Xe = 1.174 in lir = [(Es / (Xe

Rm)] + 0.5 gr = [(232,356.411 in-lb / (1.174 in

18,254.902 Ib)] + 0.5 = 11.342 An Excel spread sheet has been developed reflecting these formulas and is shown below. As previously discussed, minor differences between the spread sheet values and those shown in the above hand calculation may occur. The spread sheet method is utilized for the balance of the lines.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 126 Line SFC-012-001 g 32.174 ft/s2 mass per length 49.560 lb/ft length Dx = 2 in 0.167 ft d = 12.75 in 1.063 ft (Dx+2d) 2.292 ft Me = (Dx+2d)*Mx 3.530 lb Mm = 2000/g 62.162 lb Impact velocity 7.407 ft/s Vs 88.884 in/s Es = Mm2*Vs2/2(Mm+Me) 232356.302 I 279.300 in4 E 2.770E+07 Ib/in2 fdy 30000.000 Ib/in2 length, ft 24.000 ft L 288.000 in Rm = 8*l*fdy/(L*d) 18254.902 lb xe = RmLA3/48EI 1.174 in mu 11.340 4

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 127 Line SFC-012-014 g 32.174 ft/s2 mass per length 49.560 lb/ft length Dx = 2 in 0.167 ft d = 12.75 in 1.063 ft (Dx+2d) 2.292 ft Me = (Dx+2d)*Mx 3.530 lb Mm = 2000/g 62.162 lb Impact velocity 8.150 ft/s Vs 97.800 in/s Es = Mm2*Vs2/2(Mm+Me) 281309.879 279.300 in4 E 2.770E+07 Ib/in2 fdy 30000.000 Ib/in2 length, ft 24.000 ft L 288.000 in Rm = 8*l*fdy/(L*d) 18254.902 xe = RmLA3/48EI 1.174 mu 13.623

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 128 Line SFC-012-006 g 32.174 ft/s2 mass per length 49.560 lb/ft length Dx= 2 in 0.167 ft d = 12.75 in 1.063 ft (Dx+2d) 2.292 ft Me = (Dx+2d)*Mx 3.530 lb Mm = 2000/g 62.162 lb Impact velocity 7.404 ft/s Vs 88.848 in/s Es = Mm2*Vs2/2(Mm+Me) 232168.121 279.300 in4 E 2.770E+07 Ib/in2 fdy 30000.000 Ib/in2 length, ft 18.000 ft L 216.000 in Rm = 8*l*fdy/(L*d) 24339.869 xe = RmLA3/48EI 0.661 mu 14.941

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 129 Line SFC-012-007 g 32.174 ft/s2 mass per length 49.560 lb/ft length Dx = 2 in 0.167 ft d = 12.75 in 1.063 ft (Dx+2d) 2.292 ft Me = (Dx+2d)*Mx 3.530 lb Mm = 2000/g 62.162 lb Impact velocity 4.940 ft/s Vs 59.280 in/s Es = Mm2*Vs2/2(Mm+Me) 103353.137 279.300 in4 E 2.770E+07 lb/in2 fdy 30000.000 Ib/in2 length, ft 18.000 ft L 216.000 in Rm = 8*l*fdy/(L*d) 24339.869 xe = RmLA3/48EI 0.661 mu 6.929 Results Summary Line Number Yield Displacement Ductility Ratio SFC-012-001-3 1.174" 11.340 SFC-012-014-3 1.174" 13.623 SFC-012-006-3 0.661" 14.941 SFC-012-007-3 0.661" 6.929 The calculated ductility ratio is less than the maximum recommended ductility ratio of 20.

Based on the above yield displacements and ductility ratio values, it is expected that the pipe will experience deformation, most likely in the form of a dent at the point of impact. A steel thickness determination was performed in conjunction with the determination of the strike velocity using an impact area of 2 square inches. The maximum calculated perforation thickness was 0.151". The thickness required to prevent perforation would then be 0.151"

1.25 = 0.189". The pipe wall thickness is 0.375". On the basis of the above assessment, the Fuel Pool Cooling piping has adequate ductility to accommodate the impact of a fuel pool gate

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 130 transitioning from an initial drop onto the spent fuel or racks and will not be perforated as a result of the impact.

This information, in conjunction with the level of impact being below the minimum water level in the pool such that any damage to the piping will not affect the ability of the pool water to be transferred to or from the Spent Fuel Pool Cooling system. As a result, a load drop of the gates will not affect the safe shutdown function to maintain spent fuel pool cooling.

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 131 ATTACHMENT A RADTRAD Nuclide Input File RBSfhaRevla266.nif Nuclide Inventory Name: RBSFHARevI.NIF River Bend Fuel Handling Accident with AST Power Level:

0.1000E+01 Nuclides:

60 Nuclide 001:

Co-58 7

0.6117120000E+07 0.5800E+02 0.OOOOE+00 none 0.0000E+00 none 0.OOOOE+00 none 0.0000E+00 Nuclide 002:

Co-60 7

0.1663401096E+09 0.6000E+02 0.0000E+00 none 0.OOOOE+00 none 0.0000E+00 none 0.0000E+00 Nuclide 003:

Kr-85 1

0.3382974720E+09 0.8500E+02 0.4217E+00 none 0.OOOOE+00 none 0.0000E+00 none 0.0000E+00 Nuclide 004:

Kr-85m 1

0.16i2800000E+05 0.8500E+02 0.4044E+01 Kr-85 0.2100E+00 none 0.OOOOE+00 none 0.0000E+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 132 Nuclide 005:

Kr-87 1

0.4578000000E+04 0.8700E+02 0.7777E+01 Rb-87 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 006:

Kr-88 1

0.1022400000E+05 0.8800E+02 0.1089E+02 Rb-88 0.1000E+01 none 0.0000E+00 none 0.OOOOE+00 Nuclide 007:

Rb-86 3

0.1612224000E+07 0.8600E+02 0.OOOOE+00 none 0.0000E+00 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 008:

Sr-89 5

0.4363200000E+07 0.8900E+02 0.OOOOE+00 none 0.0000E+00 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 009:

Sr-90 5

0.9189573120E+09 0.9000E+02 0.OOOOE+00 Y-90 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 133 Nuclide 010:

Sr-91 5

0.3420000000E+05 0.9100E+02 0.OOOOE+00 Y-91m 0.5800E+00 Y-91 0.4200E+00 none 0.OOOOE+00 Nuclide 011:

Sr-92 5

0.9756000000E+04 0.9200E+02 0.OOOOE+00 Y-92 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 012:

Y-90 9

0.2304000000E+06 0.9000E+02 0.OOOOE+00 none 0.OOOOE+00 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 013:

Y-91 9

0.5055264000E+07 0.9100E+02 0.OOOOE+00 none 0.OOOOE+00 none 0.OOOOE+00 none 0.0000E+00 Nuclide 014:

Y-92 9

0.1274400000E+05 0.9200E+02 0.0000E+00 none 0.OOOOE+00 none 0.OOOOE+00 none 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 134 Nuclide 015:

Y-93 9

0.3636000000E+05 0.9300FE+02 0.0000E+00 Zr-93 0.1000E+01 none 0.0000E+00 none 0.0000E+00 Nuclide 016:

Zr-95 9

0.5527872000E+07

0. 9500F+02 0..O0000E+00 Nb-95m 0.7000E-02 Nb-95 0.9900E+00 none 0.OOOOE+00 Nuclide 017:

Zr-97 9

0.6084000000E+05 0.9700E+02 0.0000E+00 Nb-97m 0.9500E+00 Nb-97 0.5300E-01 none 0.0000E+00 Nuclide 018:

Nb-95 9

0.3036960000E+07 0.9500E+02 0.0000E+00 none 0.OOOOE+00 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 019:

Mo-99 7

0.23760000000E+06 0.9900E+02 0.OOOOE+00 Tc-99m 0.8800E+00 Tc-99 0.1200E+00 none 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 135 Nuclide 020:

Tc-99m 7

0.2167200000E+05 0.9900E+02 0.OOOOE+00 Tc-99 0.1000E+01 none 0.0000E+00 none 0.OOOOE+00 Nuclide 021:

Ru-103 7

0.3393792000E+07 0.1030E+03 0.0000E+00 Rh-103m 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 022:

Ru-105 7

0.1598400000E+05 0.1050E+03 0.0000E+00 Rh-105 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 023:

Ru-106 7

0.3181248000E+08 0.1060E+03 0.OOOOE+00 Rh-106 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 024:

Rh-105 7

0.1272960000E+06 0.1050E+03 0.0000E+00 none 0.OOOOE+00 none 0.OOOOE+00 none 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 136 Nuclide 025:

Sb-127 4

0.3326400000E+06 0.1270E+03 0.0000E+00 Te-127m 0.1800E+00 Te-127 0.8200E+00 none 0.000'OE+00 Nuclide 026:

Sb-129 4

0.1555200000E+05 0.1290E+03 0.OOOOE+00 Te-129m 0.2200E+00 Te-129 0.7700E+00 none 0.0000E+00 Nuclide 027:

Te-127 4

0.3366000000E+05 0.12,70E+03 0.0000E+00 none 0.0000E+00 none 0.0000E+00 none 0.OOOOE+00 Nuclide 028:

Te-127m 4

0.9417600000E+07 0.1270E+03 0.0000E+00 Te-127 0.9800E+00 none 0.0000E+00 none 0.0000E+00 Nuclide 029:

Te-129 4

0.4176000000E+04 0.1290E+03 0.OOOOE+00 1-129 0.1000E+01 none 0.0000E+00 none 0.0000E+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 137 Nuclide 030:

Te-129m 4

0.2903040000E+07 0.1290E+03 0.OOOOE+00 Te-129 0.6500E+00 1-129 0.3500E+00 none 0.OOOOE+00 Nuclide 031:

Te-131m 4

0.1080000000E+06 0.1310E+03 0.OOOOE+00 Te-131 0.2200E+00 1-131 0.7800E+00 none 0.0000E+00 Nuclide 032:

Te-132 4

0.2815200000E+06 0.1320E+03 0.OOOOE+00 1-132 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 033:

1-131 2

0.6946560000E+06 0.1310E+03 0.1244E-00 Xe-131m 0.1100E-01 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 034:

1-132 2

0.8280000000E+04 0.1320E+03 0.1129E-00 none 0.OOOOE+00 none 0.OOOOE+00 none 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 138 Nuclide 035:

1-133 2

0.7488000000E+05 0.1330E+03 0.1590E-00 Xe-133m 0.2900E-01 Xe-133 0.9700E+00 none 0.OOOOE+00 Nuclide 036:

1-134 2

0.3156000000E+04 0.1340E+03 0.1745E-00 none 0.0000E+00 none 0.0000E+00 none 0.0000E+00 Nuclide 037:

1-135 2

0.2379600000E+05 0.1350E+03 0.1489E-00 Xe-135m 0.1500E+00 Xe-135 0.8500E+00 none 0.OOOOE+00 Nuclide 038:

Xe-133 1

0.4531680000E+06 0.1330E+03 0.3030E+02 none 0.OOOOE+00 none 0.0000E+00 none 0.OOOOE+00 Nuclide 039:

Xe-135 1

0.3272400000E+05 0.1350E+03 0.1146E+02 Cs-135 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 139 Nuclide 040:

Cs-134 3

0.6507177120E+08 0.1340E+03 0.OOOOE+00 none 0.0000E+00 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 041:

Cs-136 3

0.1131840000E+07 0.1360E+03 0.OOOOE+00 none 0.0000E+00 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 042:

Cs-137 3

0.9467280000E+09 0.1370E+03 0.OOOOE+00 Ba-137m 0.9500E+00 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 043:

Ba-139 6

0.4962000000E+04 0.1390E+03 0.OOOOE+00 none 0.OOOOE+00 none 0.0000E+00 none 0.OOOOE+00 Nuclide 044:

Ba-140 6

0.1100736000E+07 0.1400E+03 0.OOOOE+00 La-140 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 140 Nuclide 045:

La-140 9

0.1449792000E+06 0.1400E+03 0.0000E+00 none 0.OOOOE+00 none 0.0000E+00 none 0.OOOOE+00 Nuclide 046:

La-141 9

0.1414800000E+05 0.1410E+03 0.OOOOE+00 Ce-141 0.1000E+01 none 0.0000E+00 none 0.0000E+00 Nuclide 047:

La-142 9

0.5550000000E+04 0.1420E+03 0.0000E+00 none 0.0000E+00 none 0.0000E+00 none 0.0000E+00 Nuclide 048:

Ce-141 8

0.2808086400E+07 0.1410E+03 0.OOOOE+00 none 0.OOOOE+00 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 049:

Ce-143 8

0.1188000000E+06 0.143.OE+03 0.OOOOE+00 Pr-143 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 141 Nuclide 050:

Ce-144 8

0.2456352000E+08 0.1440E+03 0.0000E+00 Pr-144m 0.1800E-01 Pr-144 0.9800E+00 none 0.OOOOE+00 Nuclide 051:

Pr-143 9

0.1171584000E+07 0.1430E+03 0.0000E+00 none 0.OOOOE+00 none 0.OOOOE+00 none 0.0000E+00 Nuclide 052:

Nd-147 9

0.9486720000E+06 0.1470E+03 0.OOOOE+00 Pm-147 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 053:

Np-239 8

0.2034720000E+06 0.2390E+03 0.00O0E+00 Pu-239 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 054:

Pu-238 8

0.2768863824E+10 0.2380E+03 0.OOOOE+00 U-234 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 142 Nuclide 055:

Pu-239 8

0.7594336440E+12 0.2390E+03 0.0000E+00 U-235 0.1000E+01 none 0.0000E+00 none 0.0000E+00 Nuclide 056:

Pu-240 8

0.2062920312E+12 0.2400E+03 0.OOOOE+00 U-236 0.1000E+01 none 0.0000E+00 none 0.0000E+00 Nuclide 057:

Pu-241 8

0.4544294400E+09 0.2410E+03 0.OOOOE+00 U-237 0.2400E-04 Am-241 0.1000E+01 none 0.OOOOE+00 Nuclide 058:

Am-241 9

0.1363919472E+11 0.2410E+03 0.OOOOE+00 Np-237 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00 Nuclide 059:

Cm-242 9

0.1406592000E+08 0.2420E+03 0.OOOOE+00 Pu-238 0.1000E+01 none 0.OOOOE+00 none 0.0000E+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 143 Nuclide 060:

Cm-244 9

0.5715081360E+09 0.2440E+03 0.0000E+00 Pu-240 0.1000E+01 none 0.OOOOE+00 none 0.OOOOE+00 End of Nuclear Inventory File

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAG E: 144 ATTACHMENT B - RADTRAD Results File RADTRAD Version 3.02 run on 8/11/2014 at 15:33:00

1. 1. 1. 1. 4#########4###4#####44##############################

4####4#44444###444##########44#4######4##4###4444####################

File information

1. 1. 1. 1. 4 #####################44 #######################

Plant file name = C:\FHAMelissa266wd.psf Inventory file name = C:\radtrad files\Radtrad files\FHA\RbsfhaRevla266.nif Scenario file name = C:\FHAMelissa266wd.psf Release file name = c:\radtrad files\radtrad files\fha\rbs fharevl.rft Dose conversion file name = c:\program files\u s nuclear regulatory commission\radtrad\defaults\fgrll&12.inp 4 #4 ft 444 #4 4v 4 4

44 44# #44 4 4 4 4 #4# #4 444# 4 4 4 Fis 4 4im 4Thr444otug4h 4444 4 #4 44#4##4* 4 Radtrad 3.02 1/5/2000 First Time Through Nuclide Inventory File:

C: \radtrad files\Radtrad files\FHA\Rbs fhaRevla266.nif Plant Power Level:

3.1000E+03 Compartments:

3 Compartment 1:

RBS Fuel Building 3

7.4200E+05 0

0 0

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 145 Compartment 2:

RBS Environment 2

0.OOOOE+00 0

0 0

Compartment 3:

RBS Control Room 1

1.8800E+05 0

0 1

0 0

Pathways:

5 Pathway 1:

RBS Fuel Building to RBS Environment 1

2 2

Pathway 2:

RBS Environment t o RBS Control Room 2

3 2

Pathway 3:

RBS Environment to RBS Control Room 2

3 2

Pathway 4:

RBS Environment to RBS Control Room 2

3 2

Pathway 5:

RBS Control Room to RBS Environment 3

2 2

End of Plant Model File

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 146 Scenario Description Name:

Plant Model Filename:

Source Term:

1 1 1.OOOOE+00 c:\program files\u s nuclear regulatory commission\radtrad\defaults\fgrll&12.inp c:\radtrad files\radtrad files\fha\rbs fharevl.rft 3.3600E+02 1

O.OOOOE+00 5.7000E-01 4.3000E-01 1.OOOOE+00 Overlying Pool:

0 o.OOOOE+00 0

0 0

0 Compartments:

3 Compartment 1:

1 1

0 0

0 Compartment 2:

1 1

0 0

0 Compartment 3:

1 1

0 0

1 2.OOOOE+03 3

3.3600E+02 1.OOOOE+02 0.OOOOE+00 0.OOOOE+00 3.3602E+02 1.OOOOE+02 0.OOOOE+00 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 147 1.0560E+03 O.OOOOE+00 0.OOOOE+00 O.OOOOE+00 0

0 Pathways:

5 Pathway 1:

0 0

0 1

2 3.3600E+02 7.4200E+09 1.OOOOE+02 0.000OE+00 o.OOOOE+00 1.0560E+03 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 0

0 0

0 Pathway 2:

0 0

0 1

3 3.3600E+02 1.7000E+03 1.OOOOE+02 0.OOOOE+00 0.0000E+00 3.3602E+02 0.000OE+00 1.OOOOE+02 1.OOOOE+02 1.OOOOE+02 1.0560E+03 0.000OE+00 0.0000E+00 o.OOOOE+00 0.OOOOE+00 0

0 0

0 Pathway 3:

0 0

0 1

3 3.3600E+02 o.OOOOE+00 1.OOOOE+02 1.OOOOE+02 1.OOOOE+02 3.3602E+02 1.7000E+03 1.OOOOE+02 0.OOOOE+00 0.OOOOE+00 1.0560E+03 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 0

0 0

0

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 148 0

0 Pathway 4:

0 0

0 1

2 3.3600E+02 3.000OE+02 1.OOOOE+02 O.OOOOE+00 0.00O0E+00 1.0560E+03 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 o.OOOOE+00 0

0 0

0 Pathway 5:

0 0

0 1

2 3.3600E+02 2.OOOOE+03 1.OOOOE+02 0.OOOOE+00 o.OOOOE+00 1.0560E+03 O.OOOOE+00 0.OOOOE+00 0.OOOOE+00 O.OOOOE+00 0

0 0

0 Dose Locations:

3 Location 1:

EAB 2

1 2

3.3600E+02 8.5800E-04 1.0560E+03 0.000OE+00 1

4 3.3600E+02 3.5000E-04 3.4400E+02 1.8000E-04 3.6000E+02 2.3000E-04 1.0560E+03 0.OOOOE+00 0

Location 2:

LPZ 2

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 149 1

5 3.3600E+02 1 . 1300E-04 3.4400E+02 7.8900E-05 3.6000E+02 3.6500E-05 4.3200E+02 1.21O0E-05 1.0560E+03 0.000OE+00 1

4 3.3600E+02 3.5000E-04 3.4400E+02 1.8000E-04 3.6000E+02 2.3000E-04 1.0560E+03 0.OOOOE+00 0

Location 3:

Control Room 3

0 1

2 3.3600E+02 3.5000E-04 1.0560E+03 O.OOOOE+00 1

4 3.3600E+02 1.OOOOE+00 3.6000E+02 1.OOOOE+00 4.3200E+02 1.OOOOE+00 1.0560E+03 0.OOOOE+00 Effective Volume Location:

1 6

3.3600E+02 1.6200E-03 3.3633E+02 4.0500E-04 3.4400E+02 3.OOOOE-04 3.6000E+02 1.0100E-04 4.3200E+02 6.2000E-05 1.0560E+03 0.OOOOE+00 Simulation Parameters:

1 3.3600E+02 0.OOOOE+00 Output Filename:

C:\FHAMelissa266wd.oO 1

1 1

End of Scenario File

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 150.

1. 1. 1. 1. 4################################################################

RADTRAD Version 3.02 run on 8/11/2014 at 15:33:00 Plant Description Number of Nuclides = 60 Inventory Power = 1.0000E+00 MWth Plant Power Level = 3.1000E+03 MWth Number of compartments =3 Compartment information Compartment number 1 (Source term fraction = 1.OOOOE+00 Name: RBS Fuel Building Compartment volume = 7.4200E+05 (Cubic feet)

Pathways into and out of compartment 1 Pathway to compartment number 2: RBS Fuel Building to RBS Environment Compartment number 2 Name: RBS Environment Pathways into and out of compartment 2 Pathway to compartment number 3: RBS Environment to RBS Control Room Pathway to compartment number 3: RBS Environment to RBS Control Room Pathway to compartment number 3: RBS Environment to RBS Control Room Pathway from compartment number 1: RBS Fuel Building to RBS Environment Pathway from compartment number 3: RBS Control Room to RBS Environment Compartment number 3 Name: RBS Control Room Compartment volume = 1.8800E+05 (Cubic feet)

Removal devices within compartment:

Filter(s)

Pathways into and out of compartment 3 Pathway to compartment number 2: RBS Control Room to RBS Environment Pathway from compartment number 2: RBS Environment to RBS Control Room Pathway from compartment number 2: RBS Environment to RBS Control Room Pathway from compartment number 2: RBS Environment to RBS Control Room Total number of pathways = 5

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 151 RADTRAD Version 3.02 run on 8/11/2014 at 15:33:00 Scenario Description Time between shutdown and first release = 3.3600E+02 (Hours)

Radioactive Decay is enabled Calculation of Daughters is enabled RELEASE NAME = BWR, NUREG-1465, Tables 3.11 & 3.13, Jun Release Fractions and Timings GAP EARLY IN-VESSEL 2.0000 hrs 1.5000 hrs NOBLES 1.0000E+00 0.OOOOE+00 IODINE 1.0000E+00 0.OOOOE+00 CESIUM 0.0000E+00 0.OOOOE+00 TELLURIUM 0.0000E+00 0 OOOOE+00 STRONTIUM 0.OOOOE+00 0.OOOOE+00 BARIUM 0.OOOOE+00 0 OOOOE+00 RUTHENIUM 0.0000E+00 0.OOOOE+00 CERIUM 0.OOOOE+00 0.OOOOE+00 LANTHANUM 0.OOOOE+00 0 OOOOE+00 Iodine fractions Aerosol = 0.OOOOE+00 Elemental - 5.7000E-01 Organic = 4.3000E-01 COMPARTMENT DATA Compartment number 1: RBS Fuel Building Compartment number 2: RBS Environment Compartment number 3: RBS Control Room Compartment Filter Data Time (hr) Flow Rate Filter Efficiencies (%)

(cfm) Aerosol Elemental Organic 3.3600E+02 2.OOOOE+03 1.0000E+02 0.OOOOE+00 0.OOOOE+00 3.3602E+02 2.OOOOE+03 1.OOOOE+02 0.OOOOE+00 0.OOOOE+00 1.0560E+03 2.OOOOE+03 O.OOOOE+00 O.OOOOE+00 O.OOOOE+00 PATHWAY DATA Pathway number 1: RBS Fuel Building to RBS Environment

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 152 Pathway Filter: Removal Data Time (hr) Flow Rate Filter Efficiencies (%)

(cfm) Aerosol Elemental Organic 3.3600E+02 7.4200E+09 1.OOOOE+02 O.OOOOE+00 O.OOOOE+00 1.0560E+03 O.OOOOE+00 O.OOOOE+00 O.OOOOE+00 O.OOOOE+00 Pathway number 2: RBS Environment to RBS Control Room Pathway Filter: Removal Data Time (hr) Flow Rate Filter Efficiencies (%)

(cfm) Aerosol Elemental Organic 3.3600E+02 1.7000E+03 1.OOOOE+02 O.OOOOE+00 O.OOOOE+00 3.3602E+02 o.OOOOE+00 1.OOOOE+02 1.OOOOE+02 1.OOOOE+02 1.0560E+03 o.OOOOE+00 O.OOOOE+00 O.OOOOE+00 O.OOOOE+00 Pathway number 3: RBS Environment to RBS Control Room Pathway Filter: Removal Data Time (hr) Flow Rate Filter Efficiencies (%)

(cfm) Aerosol Elemental Organic 3.3600E+02 O.OOOOE+00 1.OOOOE+02 1.OOOOE+02 1.OOOOE+02 3.3602E+02 1.7000E+03 1.0000E+02 O.OOOOE+00 O.OOOOE+00 1.0560E+03 o.OOOOE+00 O.OOOOE+00 O.OOOOE+00 O.OOOOE+00 Pathway number 4: RBS Environment to RBS Control Room Pathway Filter: Removal Data Time (hr) Flow Rate Filter Efficiencies (%)

(cfm) Aerosol Elemental Organic 3.3600E+02 3.OOOOE+02 1.OOOOE+02 O.OOOOE+00 0.OOOOE+00 1.0560E+03 0.OOOOE+00 0.OOOOE+00 O.OOOOE+00 0.OOOOE+00 Pathway number 5: RBS Control Room to RBS Environment Pathway Filter: Removal Data Time (hr) Flow Rate Filter Efficiencies (%)

(cfm) Aerosol Elemental Organic 3.3600E+02 2.OOOOE+03 1.OOOOE+02 O.OOOOE+00 0.OOOOE+00 1.0560E+03 O.OOOOE+00 0.OOOOE+00 O.OOOOE+00 0.OOOOE+00 LOCATION DATA Location EAB is in compartment 2 Location X/Q Data Time (hr) X/Q (s

m^-3) 3.3600E+02 8.5800E-04 1.0560E+03 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 153 Location Breathing Rate Data Time (hr) Breathing Rate (m^3

sec^-I) 3.3600E+02 3.5000E-04 3.4400E+02 1.8000E-04 3.6000E+02 2.3000E-04 1.0560E+03 0.0000E+00 Location LPZ is in compartment 2 Location X/Q Data Time (hr) X/Q (s

m^-3) 3.3600E+02 1.1300E-04 3.4400E+02 7.8900E-05 3.6000E+02 3.6500E-05 4.3200E+02 1.2100E-05 1.0560E+03 0.0000E+00 Location Breathing Rate Data Time (hr) Breathing Rate (m^3

sec^-I) 3.3600E+02 3.5000E-04 3.4400E+02 1.8000E-04 3.6000E+02 2.3000E-04 1.0560E+03 0.0000E+00 Location Control Room is in compartment 3 Location X/Q Data Time (hr) X/ (s

m^-3) 3.3600E+02 1.6200E-03 3.3633E+02 4.0500E-04 3.4400E+02 3.OOOOE-04 3.6000E+02 1. O100E-04 4.3200E+02 6.2000E-05 1.0560E+03 0.OOOOE+00 Location Breathing Rat :e Data Time (hr) BrEeathing Rate (m^3

sec^-1) 3.3600E+02 3.5000E-04 1.0560E+03 0.OOOOE+00 Location Occupancy Facctor Data Time (hr) Occcupancy Factor 3.3600E+02 1.OOOOE+00 3.6000E+02 1.0000E+00 4.3200E+02 1.OOOOE+00 1.0560E+03 0.OOOOE+00 USER SPECIFIED TIME STEP DATA - SUPPLEMENTAL TIME STEPS Time Time step 0.OOOOE+00 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 154 RADTRAD Version 3.02 run on 8/11/2014 at 15:33:00

1. 1. 1. tf ft ft ftt#### #####ft ft ft #####f ft # # # ft ft ft ft ft ft ft ft ft ft ft ft ft ft ft ft

ft ft ft ft ##### ft ft ft ft #tf# ft ft ft ft ft ft ft #t # ft ft ft ft ft ft

1. 1. 1. tf ####ft ft# ft Dose, Detailed model and Detailed Inventory Output Detailed model information at time (H) = 336.0200 EAB Doses:

Time (h) = 336.0200 Whole Body Thyroid TEDE Delta dose (rem) 8.0357E-04 3.7421E-01 1.2196E-02 Accumulated dose (rem) 8.0357E-04 3.7421E-01 1.2196E-02 LPZ Doses:

Time (h) = 336.0200 Whole Body Thyroid TEDE Delta dose (rem) 1.0583E-04 4.9284E-02 1.6063E-03 Accumulated dose (rem) 1.0583E-04 4.9284E-02 1.6063E-03 Control Room Doses:

Time (h) = 336.0200 Whole Body Thyroid TEDE Delta dose (rem) 4.9747E-07 4.4823E-03 1.3696E-04 Accumulated dose (rem) 4.9747E-07 4.4823E-03 1.3696E-04 RBS Fuel Building Compartment Nuclide Inventory:

Time (h) = 336.0200 Ci kg Atoms Bq Kr-85 1.0868E-03 2.7701E-09 1.9626E+16 4.0212E+07 1-131 9. 6114E-05 7. 7527E-13 3.5640E+12 3.5562E+06 1-133 5.6298E-09 4. 9698E-18 2.2503E+07 2.0830E+02 Xe-133 1.2317E-02 6.5802E-11 2. 9795E+14 4.5572E+08

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 155 RBS Fuel Building Transport Group Inventory:

Overlying Time (h) = 336.0200 Atmosphere Sump Pool Noble gases (atoms) 1.9924E+16 0.OOOOE+0o 0.OOOOE+00 Elemental I (atoms) 2.0316E+12 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 1.5326E+12 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 Deposition Recirculating Time (h) = 336.0200 Surfaces Filter Noble gases (atoms) 0.000OE+00 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 o.0oOOE+00 Organic I (atoms) 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 RBS Fuel Building to RBS Environment Transport Group Inventory:

Pathway Time (h) = 336.0200 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment Integral Nuclide Release:

Time (h) = 336.0200 Ci kg Atoms Bq Kr-85 1.3041E+01 3.3239E-05 2.3549E+20 4. 8250E+ll 1-131 1.153.3E+00 9.3026E-09 4.2765E+16 4.2672E+10 1-133 6.7555E-05 5. 9635E-14 2.7002E+ll 2.4996E+06 Xe-133 1.4779E+02 7.8957E-07 3.5751E+18 5.4683E+12 Xe-135 2.7249E-09 1.0670E-18 4.7598E+06 1.0082E+02 RBS Environment Transport Group Inventory:

Present Release Total Time (h) = 336.0200 Release Rate/s Release Noble gases (atoms) 2.3907E+20 3. 3204E+18 2.3244E+20 Elemental I (atoms) 2.4378E+16 3.3858E+14 2.3702E+16 Organic I (atoms) 1.8390E+16 2.5542E+14 1.7881E+16 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 RBS Fuel Building to RBS Environment Transport Group Inventory:

Pathway Time (h) = 336.0200 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 156 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 336.0200 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 336.0200 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.0000E+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room to RBS Environment Transport Group Inventory:

Pathway Time (h) = 336.0200 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room Compartment Nuclide Inventory:

Time (h) = 336.0200 Ci kg Atoms Bq Kr-85 1. 9814E-02 5.0502E-08 3.5780E+17 7. 3311E+08 1-131 1.7523E-03 1. 4134E-11 6.4976E+13 6.4835E+07 1-133 1.0264E-07 9.0606E-17 4 .1026E+08 3.7977E+03 Xe-133 2.2455E-01 1. 1997E-09 5.4319E+15 8.3085E+09 RBS Control Room Transport Group Inventory:

Overlying Time (h) = 336.0200 Atmosphere Sump Pool Noble gases (atoms) 3.6324E+17 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 3.7039E+13 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 2.7942E+13 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 157 Deposition Recirculating Time (h) = 336.0200 Surfaces Filter Noble gases (atoms) 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 336.0200 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.0000E+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 336.0200 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 336.0200 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room to RBS Environment Transport Group Inventory:

Pathway Time (h) = 336.0200 Filter Noble gases (atoms) 0.000OE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.000OE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 158 Detailed model information at time (H) = 338.0000 EAB Doses:

Time (h) = 338.0000 Whole Body Thyroid TEDE Delta dose (rem) 7.9181E-02 3. 6934E+01 1.2036E+00 Accumulated dose (rem) 7.9985E-02 3.7308E+01 1.2158E+00 LPZ Doses:

Time (h) = 338.0000 Whole Body Thyroid TEDE Delta dose (rem) 1.0428E-02 4.8643E+00 1 . 5852E-01 Accumulated dose (rem) 1.0534E-02 4. 9136E+00 1. 6013E-01 Control Room Doses:

Time (h) = 338.0000 Whole Body Thyroid TEDE Delta dose (rem) 1.6832E-03 1.5193E+01 4. 6425E-01 Accumulated dose (rem) 1.6837E-03 1.5198E+01 4. 6438E-01 RBS Fuel Building Compartment Nuclide Inventory:

Time (h) = 338.0000 Ci kg Atoms Bq Kr-85 1.0868E-03 2.7700E-09 1. 9625E+16 4.0211E+07 1-131 9.5433E-05 7. 6978E-13 3.5387E+12 3.5310E+06 1-133 5.2704E-09 4.6525E-18 2. 1066E+07 1.9500E+02 Xe-133 1.2183E-02 6.5088E-11 2. 9471E+14 4.5078E+08 RBS Fuel Building Transport Group Inventory:

Overlying Time (h) = 338.0000 Atmosphere Sump Pool Noble gases (atoms) 1.9920E+16 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 2.0177E+12 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 1.5221E+12 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 Deposition Recirculating Time (h) = 338.0000 Surfaces Filter Noble gases (atoms) 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 RBS Fuel Building to RBS Environment Transport Group Inventory:

Pathway Time (h) = 338.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 159 RBS Environment Integral Nuclide Release:

Time (h) = 338.0000 Ci kg Atoms Bq Kr-85 1.3046E+03 3.3252E-03 2.3558E+22 4.8269E+13 1-131 1.1495E+02 9.2720E-07 4.2624E+18 4 .2531E+12 1-133 6.5314E-03 5.7656E-12 2.6106E+13 2.4166E+08 Xe-133 1.4702E+04 7.8542E-05 3.5563E+20 5.4396E+14 Xe-135 2.5224E-07 9. 8775E-17 4.4062E+08 9.3330E+03 RBS Environment Transport Group Inventory:

Present Release Total Time (h) = 338.0000 Release Rate/s Release Noble gases (atoms) 2.3914E+22 3.3214E+18 2.3908E+22 Elemental I (atoms) 2.4304E+18 3.3756E+14 2. 4298E+18 Organic I (atoms) 1.8335E+18 2.5465E+14 1.8330E+18 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 RBS Fuel Building to RBS Environment Transport Group Inventory:

Pathway Time (h) = 338.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 338.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOE+00 Aerosols (kg) 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 160 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 338.0000 Filter Noble gases (atoms) 0.0000E+00 Elemental I (atoms) 0.0000E+00 Organic I (atoms) 0.0000E+00 Aerosols (kg) 0. 0000E+00 RBS Control Room to RBS Environment Transport Group Inventory:

Pathway Time (h) = 338.0000 Filter Noble gases (atoms) 0.0000E+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room Compartment Nuclide Inventory:

Time (h) = 338.0000 Ci kg Atoms Bq Kr-85 3.8219E-01 9.7413E-07 6.9016E+18 1.4141E+10 1-131 3.3561E-02 2.7071E-10 1.2444E+15 1.2417E+09 1-133 1.8534E-06 1.6361E-15 7.4082E+09 6.8576E+04 Xe-133 4.2845E+00 2.2889E-08 1. 0364E+17 1.5853E+lI Xe-135 6.8663E-11 2.6887E-20 1.1994E+05 2.5405E+00 RBS Control Room Transport Group Inventory:

Overlying Time (h) = 338.0000 Atmosphere Sump Pool Noble*gases (atoms) 7.0059E+18 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 7.1216E+14 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 5.3724E+14 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 Deposition Recirculating Time (h) = 338.0000 Surfaces Filter Noble gases (atoms) 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) O.OOOE+00 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 338.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) O.OOOOE+00 Aerosols (kg) O.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 161 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 338.0000 Filter Noble gases (atoms.) 0.0000E+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.0000E+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 338.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room to RBS Environment Transport Group Inventory:

Pathway Time (h) = 338.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 Detailed model information at time (H) = 339.5000 EAB Doses:

Time (h) = 339.5000 Whole Body Thyroid TEDE Delta dose (rem) 1.4381E-05 6.7268E-03 2.1918E-04 Accumulated dose (rem) 7.9999E-02 3.7315E+01 1.2161E+00 LPZ Doses:

Time (h) = 339.5000 Whole Body Thyroid TEDE Delta dose (rem) 1.8940E-06 8.8593E-04 2.8866E-05 Accumulated dose (rem) 1.0536E-02 4.9144E+00 1. 6016E-01 Control Room Doses:

Time (h) = 339.5000 Whole Body Thyroid TEDE Delta dose (rem) 9.1384E-04 8.2707E+00 2.5272E-01 Accumulated dose (rem) 2.5975E-03 2.3468E+01 7.1710E-01 RBS Fuel Building Compartment Nuclide Inventory:

Time (h) = 339.5000 Ci kg Atoms Bq

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 162 RBS Fuel Building Transport Group Inventory:

Overlying Time (h) = 339.5000 Atmosphere Sump Pool Noble gases (atoms) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 0.0000E+00 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 0.0000E+00 0.0000E+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.0000E+00 0.OOOOE+00 Deposition Recirculating Time (h) = 339.5000 Surfaces Filter Noble gases (atoms) 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 0.0000E+00 0.OOOOE+00 Aerosols (kg) 0.0000E+00 0.OOOOE+00 RBS Fuel Building to RBS Environment Transport Group Inventory:

Pathway Time (h) = 339.5000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment Integral Nuclide Release:

Time (h) = 339.5000 Ci kg Atoms Bq Kr-85 1.3048E+03 3.3258E-03 2.3563E+22 4.8278E+13 1-131 1.1497E+02 9.2737E-07 4.2632E+18 4 .2539E+12 1-133 6.5325E-03 5.7666E-12 2.6111E+13 2.4170E+08 Xe-133 1.4704E+04 7.8556E-05 3.5570E+20 5.4406E+14 Xe-135 2.5228E-07 9. 8790E-17 4.4069E+08 9.3345E+03 RBS Environment Transport Group Inventory:

Present Release Total Time (h) = 339.5000 Release Rate/s Release Noble gases (atoms) 2.3919E+22 1. 8983E+18 2.3912E+22 Elemental I (atoms) 2.4309E+18 1.9293E+14 2. 4302E+18 Organic I (atoms) 1.8338E+18 1. 4554E+14 1. 8333E+18 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 O.OOOOE+00 RBS Fuel Building to RBS Environment Transport Group Inventory:

Pathway Time (h) = 339.5000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 163 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 339.5000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.0000E+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 339.5000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.0000E+00 Aerosols (kg) 0.0000E+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 339.5000 Filter Noble gases (atoms) 0.0000E+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room to RBS Environment Transport Group Inventory:

Pathway Time (h) = 339.5000 Filter Noble gases (atoms) O.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.0000E+00 RBS Control Room Compartment Nuclide Inventory:

Time (h) = 339.5000 Ci kg Atoms Bq Kr-85 1.4676E-01 3.7407E-07 2. 6503E+18 5.4302E+09 1-131 1.2818E-02 1.0340E-10 4.7532E+14 4.7428E+08 1-133 6.7703E-07 5. 9766E-16 2.7061E+09 2.5050E+04 Xe-133 1. 6318E+00 8.7175E-09 3.9472E+16 6.0375E+10 RBS Control Room Transport Group Inventory:

Overlying Time (h) = 339.5000 Atmosphere Sump Pool Noble gases (atoms) 2.6904E+18 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 2.7348E+14 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 2.0631E+14 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 164 Deposition Recirculating Time (h) = 339.5000 Surfaces Filter Noble gases (atoms) 0.0000E+00 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 0.0000E+00 Organic I (atoms) 0.0000E+00 0.0000E+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 339.5000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 339.5000 Filter Noble gases (atoms) 0.000OE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room to RBS Environment Transport Group Inventory:

Pathway Time (h) = 339.5000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 165 Detailed model information at time (H) = 344.0000 EAB Doses:

Time (h) = 344.0000 Whole Body Thyroid TEDE Delta dose (rem) 8.3225E-06 3.9074E-03 1.2728E-04 Accumulated dose (rem) 8.0008E-02 3.7319E+01 1.2162E+00 LPZ Doses:

Time (h) = 344.0000 Whole Body Thyroid TEDE Delta dose (rem) 1.0961E-06 5.1461E-04 1.6763E-05 Accumulated dose (rem) 1.0537E-02 4.9150E+00 1. 6017E-01 Control Room Doses:

Time (h) = 344.0000 Whole Body Thyroid TEDE Delta dose (rem) 5.3130E-04 4.8264E+00 1.4747E-01 Accumulated dose (rem) 3.1288E-03 2.8295E+01 8. 6457E-01 RBS Fuel Building Compartment Nuclide Inventory:

Time (h) = 344.0000 Ci kg Atoms Bq RBS Fuel Building Transport Group Inventory:

Overlying Time (h) = 344.0000 Atmosphere Sump Pool Noble gases (atoms) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 Deposition Recirculating Time (h) = 344.0000 Surfaces Filter Noble gases (atoms) 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 RBS Fuel Building to RBS Environment Transport Group Inventory:

Pathway Time (h) = 344.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 166 RBS Environment Integral Nuclide Release:

Time (h) = 344.0000 Ci kg Atoms Bq Kr-85 1.3050E+03 3.3261E-03 2.3565E+22 4 .8283E+13 1-131 1.1498E+02 9.2747E-07 4.2636E+18 4 .2543E+12 1-133 6.5331E-03 5.7672E-12 2. 6113E+13 2.4173E+08 Xe-133 1.4706E+04 7.8564E-05 3.5573E+20 5.4412E+14 Xe-135 2.5230E-07 9.8798E-17 4.4072E+08 9.3352E+03 RBS Environment Transport Group Inventory:

Present Release Total Time (h) = 344.0000 Release Rate/s Release Noble gases (atoms) 2.3921E+22 8. 3059E+17 2.3914E+22 Elemental I (atoms) 2.4311E+18 8 .4415E+13 2.4305E+18 Organic I (atoms) 1.8340E+18 6.3681E+13 1.8335E+18 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 RBS Fuel Building to RBS Environment Transport Group Inventory:

Pathway Time (h) = 344.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 344.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 167 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 344.0000 Filter Noble gases (atoms) 0.0000E+00 Elemental I (atoms) 0.0000E+00 Organic I (atoms) 0.0000E+00 Aerosols (kg) 0.0000E+00 RBS Control Room to RBS Environment Transport Group Inventory:

Pathway Time (h) = 344.0000 Filter Noble gases (atoms) 0.0000E+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room Compartment Nuclide Inventory:

Time (h) = 344.0000 Ci kg Atoms Bq Kr-85 8. 3107E-03 2.1183E-08 1.5008E+17 3.0749E+08 1-131 7. 1425E-04 5.7613E-12 2.6485E+13 2.6427E+07 1-133 3.3000E-08 2.9131E-17 1.3190E+08 1.2210E+03 Xe-133 9. 0143E-02 4.8158E-10 2.1805E+15 3.3353E+09 RBS Control Room Transport Group Inventory:

Overlying Time (h) = 344.0000 Atmosphere Sump Pool Noble gases (atoms) 1.5235E+17 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 1.5487E+13 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 1.1683E+13 0.OOOOE+00 0.0000E+00 Aerosols (kg) 0.OOOOE+00 0.0000E+00 0.OOOOE+00 Deposition Recirculating Time (h) = 344.0000 Surfaces Filter Noble gases (atoms) 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 344.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 168 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 344.0000 Filter Noble gases (atoms) 0.0000E+00 Elemental I (atoms) 0.0000E+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 344.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room to RBS Environment Transport Group Inventory:

Pathway Time (h) = 344.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 Detailed model information at time (H) = 360.0000 EAB Doses:

Time (h) = 360.0000 Whole Body Thyroid TEDE Delta dose (rem) 4.8707E-07 1.1857E-04 4.0970E-06 Accumulated dose (rem) 8.0008E-02 3.7319E+01 1.2162E+00 LPZ Doses:

Time (h) = 360.0000 Whole Body Thyroid TEDE Delta dose (rem) 4.4790E-08 1.0903E-05 3.7675E-07 Accumulated dose (rem) 1.0537E-02 4.9150E+00 1. 6017E-01 Control Room Doses:

Time (h) = 360.0000 Whole Body Thyroid TEDE Delta dose (rem) 3.1138E-05 2.8518E-01 8.7135E-03 Accumulated dose (rem) 3.1599E-03 2.8580E+01 8.7328E-01 RBS Fuel Building Compartment Nuclide Inventory:

Time (h) = 360.0000 Ci kg Atoms Bq

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 169 RBS Fuel Building Transport Group Inventory:

Overlying Time (h) = 360.0000 Atmosphere Sump Pool Noble gases (atoms) 0.0000E+00 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 0.0000E+00 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 Deposition Recirculating Time (h) = 360.0000 Surfaces Filter Noble gases (atoms) 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 RBS Fuel Building to RBS Environment Transport Group Inventory:

Pathway Time (h) = 360.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment Integral Nuclide Release:

Time (h) = 360.0000 Ci kg Atoms Bq Kr-85 1.3050E+03 3.3261E-03 2.3565E+22 4 .8284E+13 1-131 L.1498E+02 9.2747E-07 4.2636E+18 4 .2544E+12 1-133 6.5331E-03 5.7672E-12 2.6113E+13 2.4173E+08 Xe-133 I..4706E+04 7.8565E-05 3.5574E+20 5. 4412E+14 Xe-135 2.5230E-07 9. 8799E-17 4.4072E+08 9.3353E+03 RBS Environment Transport Group Inventory:

Present Release Total Time (h) - 360.0000 Release Rate/s Release Noble gases (atoms) 2.3921E+22 2.7687E+17 2.3915E+22 Elemental I .(atoms) 2.4312E+18 2. 8138E+13 2. 4305E+18 Organic I (atoms) 1.8340E+18 2. 1227E+13 1. 8335E+18 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 O.OOOOE+00 RBS Fuel Building to RBS Environment Transport Group Inventory:

Pathway Time (h) = 360.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.0000E+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) O.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116

[REVISION:0 PAGE: 170 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 360.0000 Filter Noble gases (atoms) 0.0000E+00 Elemental I (atoms) 0.0000E+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.0000E+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 360.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 360.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room to RBS Environment Transport Group Inventory:

Pathway Time (h) = 360.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.000OE+00 RBS Control Room Compartment Nuclide Inventory:

Time (h) = 360.0000 Ci kg Atoms Bq Kr-85 3.0584E-07 7.7954E-13 5.5229E+12 1.1316E+04 1-131 2.4820E-08 2.0020E-16 9.2033E+08 9.1833E+02 Xe-133 3.0379E-06 1.6230E-14 7.3487E+10 1.1240E+05 RBS Control Room Transport Group Inventory:

Overlying Time (h) = 360.0000 Atmosphere Sump Pool Noble gases (atoms) 5.6073E+12 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 5.6999E+08 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 4.2999E+08 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 O.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 171 Deposition Recirculating Time (h) = 360.0000 Surfaces Filter Noble gases (atoms) 0.OOOOE+00 0.0000E+00 Elemental I (atoms) 0.0000E+00 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 0.0000E+00 Aerosols (kg) 0.0000E+00 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 360.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 360.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room to RBS Environment Transport Group Inventory:

Pathway Time (h) = 360.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 172 Detailed model information at time (H) = 432.0000 EAB Doses:

Time (h) = 432.0000 Whole Body Thyroid TEDE Delta dose (rem) 1.6498E-11 5.2711E-09 1.7698E-10 Accumulated dose (rem) 8.0008E-02 3.7319E+01 1.2162E+00 LPZ Doses:

Time (h) = 432.0000 Whole Body Thyroid TEDE Delta dose (rem) 7.0186E-13 2.2424E-10 7.5288E-12 Accumulated dose (rem) 1.0537E-02 4.9150E+00 1. 6017E-01 Control Room Doses:

Time (h) = 432.0000 Whole Body Thyroid TEDE Delta dose (rem) 1.0884E-09 1.0238E-05 3. 1280E-07 Accumulated dose (rem) 3.1599E-03 2. 8580E+01 8.7328E-01 RBS Fuel Building Compartment Nuclide Inventory:

Time (h) = 432.0000 Ci kg Atoms Bq RBS Fuel Building Transport Group Inventory:

Overlying Time (h) = 432.0000 Atmosphere Sump Pool Noble gases (atoms) 0.OOOOE+00 0.OOOOE+00 0.0000E+00 Elemental I (atoms) 0.OOOOE+00 0.OOOOE+00 0.0000E+00 Organic I (atoms) 0.0000E+00 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 0.0000E+00 Deposition Recirculating Time (h) = 432.0000 Surfaces Filter Noble gases (atoms) 0.OOOOE+00 0.0000E+00 Elemental I (atoms) 0.0000E+00 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 RBS Fuel Building to RBS Environment Transport Group Inventory:

Pathway Time (h) = 432.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.0000E+00 Organic I (atoms) 0.0000E+00 Aerosols (kg) 0.0000E+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 173 RBS Environment Integral Nuclide Release:

Time (h) = 432.0000 Ci kg Atoms Bq Kr-85 1.3050E+03 3.3261E-03 2.3565E+22 4.8284E+13 1-131 1.1498E+02 9.2747E-07 4.2636E+18 4 .2544E+12 1-133 6. 5331E-03 5.7672E-12 2. 6113E+13 2.4173E+08 Xe-133 1.4706E+04 7.8565E-05 3.5574E+20 5.4412E+14 Xe-135 2.5230E-07 9.8799E-17 4.4072E+08 9.3353E+03 RBS Environment Transport Group Inventory:

Present Release Total Time (h) = 432.0000 Release Rate/s Release Noble gases (atoms) 2.3921E+22 6. 9217E+16 2.3915E+22 Elemental I (atoms) 2.4312E+18 7.0346E+12 2. 4305E+18 Organic I (atoms) 1.8340E+18 5. 3068E+12 1.8335E+18 Aerosols (kg) 0.0000E+00 0.OOOOE+00 0.0000E+00 RBS Fuel Building to RBS Environment Transport Group Inventory:

Pathway Time (h) = 432.0000 Filter Noble gases (atoms) 0.0000E+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 432.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 432.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 174 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 432.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.0000E+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room to RBS Environment Transport Group Inventory:

Pathway Time (h) = 432.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room Compartment Nuclide Inventory:

Time (h) = 432.0000 Ci kg Atoms Bq RBS Control Room Transport Group Inventory:

Overlying Time (h) = 432.0000 Atmosphere Sump Pool Noble gases (atoms) 6.1886E-08 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 6.2907E-12 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 4.7456E-12 0.000.OE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 Deposition Recirculating Time (h) = 432.0000 Surfaces Filter Noble gases (atoms) 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 432.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 175 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 432.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) O.0000E+00 Aerosols (kg) 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) = 432.0000 Filter Noble gases (atoms) o.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room to RBS Environment Transport Group Inventory:

Pathway Time (h) = 432.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.O00OE+00 Detailed model information at time (H) = 1056.0000 EAB Doses:

Time (h) =1056.0000 Whole Body Thyroid TEDE Delta dose (rem) 1.2447E-31 4.4915E-29 1.4919E-30 Accumulated dose (rem) 8.0008E-02 3.7319E+01 1.2162E+00 LPZ Doses:

Time (h) =1056.0000 Whole Body Thyroid TEDE Delta dose (rem) 1.7553E-33 6. 3342E-31 2.1040E-32 Accumulated dose (rem) 1.0537E-02 4.9150E+00 1. 6017E-01 Control Room Doses:

Time (h) =1056.0000 Whole Body Thyroid TEDE Delta dose (rem) 8.2110E-30 8.7242E-26 2.6643E-27 Accumulated dose (rem) 3.1599E-03 2.8580E+01 8.7328E-01 RBS Fuel Building Compartment Nuclide Inventory:

Time (h) =1056.0000 Ci kg Atoms Bq

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 176 RBS Fuel Building Transport Group Inventory:

Overlying Time (h) =1056.0000 Atmosphere Sump Pool Noble gases (atoms) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 0. OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0. OOOOE+00 0.OOOOE+00 Deposition Recirculating Time (h) =1056.0000 Surfaces Filter Noble gases (atoms) 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 RBS Fuel Building to RBS Environment Transport Group Inventory:

Pathway Time (h) =1056.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.0000E+00 Aerosols (kg) 0.OOOOE+00 RBS Environment Integral Nuclide Release:

Time (h) =1056.0000 Ci kg Atoms Bq Kr-85 1.3050E+03 3.3261E-03 2.3565E+22 4.8284E+13 1-131 1. 1498E+02 9.2747E-07 4.2636E+18 4.2544E+12 1-133 6. 5331E-03 5.7672E-12 2.6113E+13 2 .4173E+08 Xe-133 1.4706E+04 7.8565E-05 3.5574E+20 5.4412E+14 Xe-135 2.5230E-07 9. 8799E-17 4.4072E+08 9.3353E+03 RBS Environment Transport Group Inventory:

Present Release Total Time (h) =1056.0000 Release Rate/s Release Noble gases (atoms) 2.3921E+22 9.2289E+15 2.3915E+22 Elemental I (atoms) 2.4312E+18 9.3795E+1I 2.4305E+18 Organic I (atoms) 1.8340E+18 7.0757E+II 1.8335E+18 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00 RBS Fuel Building to RBS Environment Transport Group Inventory:

Pathway Time (h) =1056.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental .I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00

CALCULATION DETAILS [CALCULATION NO: G13.18.2.7-116

[REVISION:0 PAGE: 177 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) =1056.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) =1056.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.0000E+00 Aerosols (kg) 0.0000E+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) =1056.0000 Filter Noble gases (atoms) 0.0000E+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room to RBS Environment Transport Group Inventory:

Pathway Time (h) =1056.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room Compartment Nuclide Inventory:

Time (h) =1056.0000 Ci kg Atoms Bq RBS Control Room Transport Group Inventory:

Overlying Time (h) =1056.0000 Atmosphere Sump Pool Noble gases (atoms) 6.6550-181 0.OOOOE+00 0.OOOOE+00 Elemental I (atoms) 6.7648-185 0.OOOOE+00 0.OOOOE+00 Organic I (atoms) 5.1033-185 0.OOOOE+00 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 0.OOOOE+00 0.OOOOE+00

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 178 Deposition Recirculating Time (h) =1056.0000 Surfaces Filter Noble gases (atoms) 0.OOOOE+00 0.0000E+00 Elemental I (atoms) 0.OOOOE+00 0.0000E+00 Organic I (atoms) 0.OOOOE+00 0.0000E+00 Aerosols (kg) 0.OOOOE+00 0.0000E+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) =1056.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) =1056.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) O.OO0OE+00 RBS Environment to RBS Control Room Transport Group Inventory:

Pathway Time (h) =1056.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 RBS Control Room to RBS Environment Transport Group Inventory:

Pathway Time (h) =1056.0000 Filter Noble gases (atoms) 0.OOOOE+00 Elemental I (atoms) 0.OOOOE+00 Organic I (atoms) 0.OOOOE+00 Aerosols (kg) 0.OOOOE+00 838

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0

.PAGE: 179 1-131 Summary RBS Fuel Building RBS Environment RBS Control Room Time (hr) 1-131 (Curies) 1-131 (Curies) 1-131 (Curies) 336.001 9.6121E-05 3.1944E-02 4.8838E-05 336.020 9.6114E-05 1.1533E+00 1.7523E-03 336. 420 9.5976E-05 2.4205E+01 3.2447E-02 336. 720 9.5873E-05 4.1474E+01 3.2769E-02 337.020 9.5770E-05 5.8725E+01 3.3029E-02 337.320 9.5667E-05 7.5958E+01 3.3237E-02 337. 620 9.5563E-05 9.3172E+01 3.3402E-02 337. 920 9.5461E-05 1.1037E+02 3.3531E-02 338.000 9.5433E-05 1.1495E+02 3.3561E-02 338 .300 0.OOOOE+00 1.1496E+02 2.7684E-02 338.600 0.OOOOE+00 1.1496E+02 2.2837E-02 338.900 0.OOOOE+00 1.1496E+02 1.8838E-02 339.200 0.OOOOE+00 1.1497E+02 1.5539E-02 339. 500 0.OOOOE+00 1.1497E+02 1.2818E-02 339. 800 0.000OE+00 1.1497E+02 1.0574E-02 340.100 0.OOOOE+00 1.1497E+02 8.7224E-03 340.400 0.OOOOE+00 1.1498E+02 7.1951E-03 340.700 0.OOOOE+00 1 .1498E+02 5.9353E-03 341.000 0.OOOOE+00 1 .1498E+02 4.8960E-03 341.300 0.OOOOE+00 1.1498E+02 4.0387E-03 341.600 0.OOOOE+00 1 .1498E+02 3.3315E-03 341.900 0.000OE+00 1 .1498E+02 2.7482E-03 342.200 0.OOOOE+00 1.1498E+02 2.2670E-03 342.500 0.OOOOE+00 1.1498E+02 1.8700E-03 342.800 0.OOOOE+00 1.1498E+02 1.5426E-03 343.100 0.OOOOE+00 1.1498E+02 1.2725E-03 343.400 0 OOOOE+00 1.1498E+02 1 .0497E-03 343.700 0 OOOOE+00 1.1498E+02 8.6586E-04 344.000 0.OOOOE+00 1.1498E+02 7.1425E-04 344.300 0.OOOOE+00 1.1498E+02 5 .8917E-04 344.600 0.OOOOE+00 1.1498E+02 4.8600E-04 344.900 0 OOOOE+00 1.1498E+02 4 .0089E-04 345.200 0 OOOOE+00 1.1498E+02 3.3069E-04 345.500 0 OOOOE+00 1.1498E+02 2.7278E-04 345.800 0.OOOOE+00 1.1498E+02 2.2501E-04 346.100 0.OOOOE+00 1.1498E+02 1.8561E-04 346.400 0.OOOOE+00 1.1498E+02 1.5311E-04 360.000 0.OOOOE+00 1.1498E+02 2.4820E-08 432.000 0.OOOOE+00 1.1498E+02 2.1150E-28 1056.000 0.OOOOE+00 1.1498E+02 2.4176-202

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 180

1. 1. 1. 1. C##############################################################

Cumulative Dose Summary EAB LPZ Control Room Time Thyroid TEDE Thyroid TEDE Thyroid TEDE (hr) (rem) (rem) (rem) (rem) (rem) (rem) 336.001 1.0364E-02 3.3780E-04 1.3650E-03 4 .4489E-05 3.4690E-06 1.0600E-07 336.020 3.7421E-01 1.2196E-02 4.9284E-02 1. 6063E-03 4.4823E-03 1.3696E-04 336.420 7.8558E+00 2. 5604E-01 1.0346E+00 3.3720E-02 1.8171E+00 5.5525E-02 336.720 1.34 61E+01 4.3871E-01 1.7728E+00 5.7779E-02 4.3195E+00 1.3199E-01 337.020 1. 9060E+01 6.2118E-01 2.5102E+00 8. 1811E-02 6.8441E+00 2.0913E-01 337.320 2. 4653E+01 8.0345E-01 3.2468E+00 1.0582E-01 9.3866E+00 2.8682E-01 337.620 3. 0240E+01 9.8552E-01 3.9827E+00 1.2979E-01 1.1943E+01 3.6494E-01 337.920 3.5821E+01 1.1674E+00 4 .7177E+00 1. 5375E-01 1.4511E+01 4.4341E-01 338.000 3.7308E+01 1.2158E+00 4 .9136E+00 1. 6013E-01 1.5198E+01 4.6438E-01 338.300 3.7310E+01 1.2159E+00 4. 9138E+00 1. 6014E-01 1.7541E+01 5.3598E-01 338.600 3.7312E+01 1.2160E+00 4. 9140E+00 1. 6014E-01 1.9474E+01 5.9504E-01 338.900 3.7313E+01 1.2160E+00 4.9142E+00 1. 6015E-01 2.1068E+01 6.4376E-01 339.200 3.7314E+01 1.2160E+00 4. 9143E+00 1. 6015E-01 2.2383E+01 6.8395E-01 339.500 3.7315E+01 1 .2161E+00 4. 9144E+00 1 .6016E-01 2.3468E+01 7.1710E-01 339.800 3.7316E+01 1.2161E+00 4. 9145E+00 1. 6016E-01 2.4363E+01 7.4445E-01 340.100 3.7316E+01 1 .2161E+00 4. 9146E+00 1.6016E-01 2.5102E+01 7.6700E-01 340.400 3.7317E+01 1 .2161E+00 4. 9147E+00 1 . 6017E-01 2.5711E+01 7.8561E-01 340.700 3.7317E+01 1.2161E+00 4. 9147E+00 1 . 6017E-01 2.6213E+01 8.0096E-01 341.000 3.7318E+01 1. 2161E+00 4. 9148E+00 1 . 6017E-01 2.6627E+01 8.1362E-01 341.300 3.7318E+01 1.2162E+00 4.9148E+00 1.6017E-01 2.6969E+01 8.2407E-01 341.600 3.7318E+01 1.2162E+00 4. 9148E+00 1. 6017E-01 2.7251E+01 8.3268E-01 341.900 3.7318E+01 1 .2162E+00 4. 9149E+00 1. 6017E-01 2.7484E+01 8.3979E-01 342.200 3.7318E+01 1 .2162E+00 4. 9149E+00 1. 6017E-01 2.7676E+01 8.4565E-01 342.500 3.7319E+01 1 .2162E+00 4. 9149E+00 1 . 6017E-01 2.7834E+01 8.5049E-01 342.800 3.7319E+01 1.2162E+00 4 9149E+00 1 . 6017E-01 2.7965E+01 8.5448E-01 343.100 3.7319E+01 1.2162E+00 4. 914 9E+00 1 .6017E-01 2.8072E+01 8.5777E-01 343.400 3.7319E+01 1 .2162E+00 4.9149E+00 1 . 6017E-01 2.8161E+01 8.6048E-01 343.700 3. 7319E+01 1.2162E+00 4. 9150E+00 1. 6017E-01 2.8234E+01 8.6272E-01 344.000 3. 7319E+01 1.2162E+00 4. 9150E+00 1. 6017E-01 2.8295E+01 8.6457E-01 344.300 3.7319E+01 1.2162E+00 4 .9150E+00 1. 6017E-01 2.8345E+01 8.6609E-01 344 .600 3.7319E+01 1.2162E+00 4. 9150E+00 1. 6017E-01 2.8386E+01 8.6735E-01 344.900 3..7319E+01 1.2162E+00 4. 9150E+00 1. 6017E-01 2.8420E+01 8.6839E-01 345. 200 3.7319E+01 1.2162E+00 4. 9150E+00 1. 6017E-01 2.8448E+01 8.6924E-01 345.500 3.7319E+01 1.2162E+00 4 .9150E+00 1 . 6017E-01 2.8471E+01 8.6995E-01 345. 800 3.7319E+01 1.2162E+00 4. 9150E+00 1 . 6017E-01 2.8490E+01 8.7053E-01 346. 100 3.7319E+01 1.2162E+00 4. 9150E+00 1. 6017E-01 2.8506E+01 8.7101E-01 346.400 3. 7319E+01 1.2162E+00 4. 9150E+00 1. 6017E-01 2.8519E+01 8.7141E-01 360. 000 3.7319E+01 1.2162E+00 4. 9150E+00 1 .6017E-01 2.8580E+01 8.7328E-01 432.000 3.7319E+01 1.2162E+00 4. 9150E+00 1. 6017E-01 2.8580E+01 8.7328E-01 1056.000 3.7319E+01 1.2162E+00 4. 9150E+00 1. 6017E-01 2.8580E+01 8.7328E-01

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 181 Worst Two-Hour Doses Note: All of the dose locations are shown below but the worst two-hour dose is only meaningful for the EAB dose location. Please disregard the two-hour worst doses for the other dose locations EAB.

Time Whole Body Thyroid TEDE (hr) (rem) (rem) (rem) 336.0 7.9963E-02 3.7298E+01 1.2155E+00 LPZ Time Whole Body Thyroid TEDE (hr) (rem) (rem) (rem) 336.0 1.0531E-02 4.9122E+00 1.6008E-01 Control Room Time Whole Body Thyroid TEDE (hr) (rem) (rem) (rem) 336.4 1.8224E-03 1. 6459E+01 5.0291E-01

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 182 ATTACHMENT C - Water Dynamic and Kinematic Viscosity Rewurue5. Tools and Base Intmaio~in for Engiornring wd Designm 4(Teclaical Applicaiim! - adapft jeomkyly, 0p"km.ý pn, Wa4d dishs~p WNater - Dvynainic and Kinematic Viscosity Viscosity of water at temperatures. between 0. 1OO"C (32 2120 F) - in Imperial and. SI1 Units Spornsord LMnks Dyniank IAtwfullj) andiK~ineai Vt~imity ot WAwi in ImMieis Ll~fts 0a Units):

Tcrnpcamume~rn~ .rtuw

(/,/o x 10.2 32 1.732 3.924 4() 3.228 1.664 50 2-130 I .WTT 60 23."4 1110 702.034. 1.01-1 8131.791 0.926 115 1423 0.738 120 :-164 0.6037 140 0.974 035!!

16U 0O832 0.439 180 0.721 0383 2150 4,634 o.339 212 0.349 0.31?

Dynamic (AbWluiO saWKincroaki Vscjiv otyaWawte it S1Unti.,

-I- *J . V

('0 fPQ J. N.vvi 1(,- twlj)'

O 1'/0.

1,7137 1.787 5 1.5191.511) 10 1307 1_34)7 20 10.c12 I.qxj4

.10 0.798 0-8011

.4046530.5 0.5470.3 60 OA.67 .7 U,4054 13I Sri35 (1S .3m0 W0 0.313 (1.326 Y"5 0112 0.29 Related Mobile Appsi from The Engineering Tipoiflu

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 183 ATTACHMENT D - Excel Spread Sheet Formula Views, Sections 10.2 through 10.4 Load Drop Max Lift Gate Drop from Max Uft Height to Pool Floor 70' Gate Length L 24.39 ft Gate Width, d 4.771 ft Gate thickness (reduced to obtain density greater than water) 0.275 ft Gate weight, W 2000 lb Gate density =B5/(B2*B3*B4) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/s water density/gate density =B7/B6 drop distance in air 7.3 ft drop distance in water 37.7 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B1O) ft/s Reynolds no =( Vo

d)/viscosity =(Bl2*B3)/B8 Check L/d using gate length and width =132/133 Check L/D using gate width and thickness =B3/134 Drag Coefficient CD 1.2 Ao = width

thickness =B3*B4 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B7*B16*B17)/(2*B5) b = (water density

g)/W =(B7*32.17)/B5 Terminal Velocity, V2 = SQRT((g*(1-density water/density gate)/a) ft/s exp(-2*a*x) where x = drop distance in water =EXP(-2*Bl8*B11) bAo =B319*B317 exp(2aL) =EXP(2*B18*B2) 2aL =2*318*B32 V2A2 =B20A2 VoA2 =B12A2 bAo*[exp(2aL)*(1-2aL)-l]/2aA2 =B22*(B23*(1-B24)-1)/(2*(B18A2))

g*(exp(2aL)

wtr dens/gate dens -1)/a =32.17*(B23*B9.1)/B18 Z2x =B25+(B21*(B27+B26+B28))

Vs = (Zx)A^.5 =SQRT(B29) ft/s Convert impact area to equivalent diameter =2*(((B17*144)/3.142)AO .5) in mass = weight/g =BS/32.17 lb-s2/ft thickness =((B34*B3lA2/2)A(2/3))/(672*B33) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 184 Gate Drop from Max Lift Height to Cask Shelf 93' El Gate Length L 24.39 ft Gate Width, d 4.771 ft Gate thickness 0.3958 ft Gate weight, W 2000 lb Gate density =B42/(B39*B40*841) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/s water density/gate density =B44/B43 drop distance in air 7.3 ft drop distance in water 14.7 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B47) ft/s Reynolds no =( Vo

d)/viscosity =(B49*B40)/B45 Check L/d using gate length and width =B39/B40 Check I/D using gate width and thickness =B40/B41 Drag Coefficient CD 1.2 Ao = width

thickness =B40*B41 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B44*B53*B54)/(2*B42) b = (water density

g)/W =(B44*32.17)/B42 exp(-2*a*x) where x = drop distance in water =EXP(-2*B55*B48) bAo =B56*B54 2ax =2*BS5*B48 VoA2 =B49A2 g/a =32.17/B55 bAo* [(1-2ax)]/2aA2 =B58*((1-B59)/(2*(B55A2)))

exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] =B57*(B49A2-B61-(B58/(2*B55A2)))

Zlx =B61+B62+B63 Vs = (7x)A0.5 =SQRT(B64) ft/s Convert impact area to equivalent diameter =2*(((B54*144)/3.142)AO.5) in mass = weight/g =B42/32.17 lb-s2/ft thickness =((B69*B66A2/2)A(2/3))/(672*B68) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 185 Gate Drop from Max Uft Height to Gate Opening Gate Length L 24.39 ft Gate Width, d 4.771 ft Gate thickness 0.3958 ft Gate weight, W 2000 lb Gate density =B77/(B74*B75*B76) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/s water density/gate density =B79/178 drop distance in air 7.3 ft drop distancein water 19.7 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B82) ft/s Reynolds no =(Vo

d)/viscosity =(B84*B75)/B80 Check L/d using gate length and width =B74/B75 Check L/D using gate width and thickness =B75/B76 Drag Coefficient CD 1.2 Ao = width

thickness =B75*B76 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B79*B88*B89)/(2*B77) b = (water density

g)/W =(B79*32.17)/B77 exp(-2*a*x) where x = drop distance in water =EXP(-2*B90*B83) bAo =B91*B89 2ax =2*B90*B83 VoA2 =B84A2 P./a =32.17/B90 bAo* [(1-2ax)]/2aA2 =B93*(1-B94)/(2*(B90A2))

exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] =B92*(B84A2-B96-(B93/(2*B90A2)))

z1x =B96+B97+B98 Vs = (Zx)AO.5 =SQRT(B99) ft/s Convert impact area to equivalent diameter =2*(((B89*144)/3.142)AO.5) in mass = weight/g =B77/32.17 lb-s2/ft thickness =((BlO4*B1O^A2/2)A(2/3))/(672*Bt03) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 186 Intermediate Beam Drop from Max Lift Height to Pool Floor 70' Beam Length L 4.75 ft Beam Width, d 0.4167 ft Beam thickness 0.4167 ft Beam weight, W 175 lb Beam density =B112/(B109*B110*B111) Ib/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =B114/B1113 drop distance in air 32.3 ft drop distance in water 37.7 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B117) ft/s Reynolds no =( Vo

d)/viscosity =(B119*B110)/B115 Check L/d using beam length and width =B109/B110 Check L/D using beam width and thickness 1 Drag Coefficient CD 1.16 Ao = width

thickness =B110*B111 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B114*B123*B124)/(2*B112) b = (water density

g)/W =(8114*32.17)/B112 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) =((32.17/B125)*(1-B3116))^0 .5 ft/s exp(-2*a*x) where x = drop distance in water =EXP(-2*B125*B118) bAo =B126*B124 exp(2aL) =EXP(2*B125*B109) 2aL =2*B125*B109 V2A2 =B127A2 VoA2 =B119A2 bAo*[exp(2aL)*(1-2aL)-l]/2aA2 =B129*(B130*(1-B131)-

1)/(2*(B125A2))

g*(exp(2aL)

wtr dens/beam dens -1)/a =32.17*(B130*B116-1)/B125 Z2x =B132+(B128*(B134+B133+B135))

Vs = (Zx)AO.5 =SQRT(B136) ft/s Convert impact area to equivalent diameter =2*(((B124*144)/3.142)AO.5) in mass = weight/g =B112/32. 17 lb-s2/ft thickness =((B141*B138A2/2)A(2/3))/(672*BI40) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 187 Intermediate Beam Drop from Max Uft Height to to Cask Shelf 93' El Beam Length L 4.75 ft Beam Width, d 0.4167 ft Beam thickness 0.4167 ft Beam weight, W 175 lb Beam density =B149/(B146*B147*B148) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/s water density/gate density =B151/B150 drop distance in air 32.3 ft drop distance in water 14.7 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17* B154) ft/s Reynolds no =( Vo

d)/viscosity =(B156*B147)/B152 Check L/d using beam length and width =B146/B147 Check L/D using beam width and thickness 1 Drag Coefficient CD 1.16 Ao = width

thickness =B147*B148 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B151*B160*B161)/(2*B149) b = (water density

g)/W =(B151*32.17)/13149 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) =((32.17/B162)*(1-B153))A0.5 ft/s exp(-2*a*x) where x = drop distance in water =EXP(-2*B162*B155) bAo =B163*B161 exp(2aL) =EXP(2*B162*B146) 2aL =2*B162*B146 V2A2 =B164A2 VoA2 =B156A2 bAo* [exp(2aL)*(1-2aL)-l]/2aA2 =B166*(B167*(1-B168)-

1)/(2*(B162A2))

g*(exp(2aL)

wtr dens/beam dens -1)/a =32.17*(B167*13153-1)/13162 Z2x =B169N(B165*(B171+B170+B172))

Vs = (ZX)A0.5 =SQRT(B173) ft/s Convert impact area to equivalent diameter =2*(((B161*144)/3.142)AO.5) in mass = weight/g =B149/32.17 lb-s2/ft thickness =((B178*B175A2/2)A(2/3))/(672*Bl77) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 188 Intermediate Beam Drop from Max Lift Height to to Gate Opening 88' Beam Length L 4.75 ft Beam Width, d 0.4167 ft Beam thickness 0.4167 ft Beam weight, W 175 lb Beam density =B186/(B183*B184*Bl85) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/s water density/gate density =13188/13187 drop distance in air 32.3 ft drop distance in water 19.7 ft Vo where h is drop distance in air, V (2gh)A2 =SQRT(2*32.17*l3191) ft/s Reynolds no =( Vo

d)/viscosity =(B193*B184)/B189 Check L/d using beam length and width =13183/13184 Check L/D using beam width and thickness =13184/13185 Drag Coefficient CD 1.16 Ao = width

thickness =11184*B3185 ft2 a = (water density

Drag Coeff

Ao )/(2*W) =(B188*B197*B198)/(2*Bl86) b = (water density

g)/W =(B188*32.17)/B186 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) =((32.17/B199)*(1-B190))A0.5 ft/s exp(-2*a*x) where x = drop distance in water =EXP(-2*B199*B192) bAo =B200*B198 exp(2aL) =EXP(2*B199*B183) 2aL =2*13199*B183 V2A2 =13201A2 VoA2 =B193A2 bAo*[exp(2aL)*(1-2aL)-l]/2aA2 =B203*(B204*(1-B205)-

1)/(2*(B199A2))

g*(exp(2aL)

wtr dens/beam dens -1)/a =32.17*(B204*B190-1)/B199 Z2x =B206+(l3202*(B208+B207+B209))

Vs = (Zx)AO.5 =SQRT(B210) ft/s Convert impact area to equivalent diameter =2*(((B198*144)/3.142)AO.5) in mass = weight/g =13186/32. 17 lb-s2/ft thickness =((B215*B212A2/2VA(2/3))/(672*B214) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 189 Alternate Beam Drop from Max Lift Height to Pool Floor 70' Beam Length L 12 ft Beam Width, d 0.5 ft Beam thickness 0.333 ft Beam weight, W 200 lb Beam density =B223/(B220*B221*B222) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =B225/B224 drop distance in air 40.3 ft drop distance in water 37.7 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B228) ft/s Reynolds no =( Vo

d)/viscosity =(B230*B221)/B226 Check L/d using beam length and width =B220/B221 Check L/D using beam width and thickness =B221/B222 Drag Coefficient CD 1.16 Ao = width

thickness =B221*B222 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B225* B234*B235)/(2*B223) b = (water density

g)/W =(B225*32.17)/B223 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) =((32.17/B236)*(1-B227))A0.5 ft/s exp(-2*a*x) where x = drop distance in water =EXP(-2*B236*B229) bAo =B237* B235 exp(2aL) =EXP(2*B236*B220) 2aL =2*B236*B220 V2A2 =B238A2 VoA2 =B230A2 bAo*[exp(2aL)*(1-2aL)-1]/2aA2 =B240*(B241*(l-B242)-

1)/(2 *(B236A2))

g*(exp(2aL)

wtr dens/beam dens -1)/a =32.17*(B241*B227-1)/B236 Z2x =B243+(B239*(B245+B244+B246))

Vs = (Zx)AO.5 =SQRT(B247) ft/s Convert impact area to equivalent diameter =2*(((B235*144)/3.142)AO.5) in mass = weight/g =B223/32.17 Ib-s2/ft thickness =((B252*B249A2/Z)A(2/3))/(672*B251) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 190 Alternate Beam Drop from Max Lift Height to to Cask Shelf 93' El Beam Length L 12 ft Beam Width, d 0.5 ft Beam thickness 0.333 ft Beam weight, W 200 lb Beam density =B260/(B257*B258*B259) lb/cu ft water density @ 160F 60.994 Ib/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =B262/B261 drop distance in air 40.3 ft drop distance in water 14.7 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B265) ft/s Reynolds no :( Vo

d)/viscosity =(B267*B258)/B263 Check L/d using beam length and width =B257/B258 Check L/D using beam width and thickness =B258/B259 Drag Coefficient CD 1.16 Ao = width

thickness =B258*B259 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B262* B271*B272)/(2*B260) b = (water density

g)/W =(B262*32.17)/B260 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) =((32.17/B273)*(1-B264))A0.5 ft/s exp(-2*a*x) where x = drop distance in water =EXP(-2*B273*B266) bAo =B274*B272 exp(2aL) =EXP(2*B273*B257) 2aL =2*B273*B257.

V2A2 =B275A2 VoA2 =B267A2 bAo*[exp(2aL)*(1-2aL)-l]/2aA2 =B277*(B278*(1.B279)-

1)/(2*(B273A2))

g*(exp(2aL)

wtr dens/beam dens -1)/a =32.17*(B278*B264-1)/B273 Z2x =B280+(B276*(B282+B281+B283))

Vs = (Zx)AO.5 =SQRT(B284) ft/s Convert impact area to equivalent diameter =2*(((B272*144)/3.142)AO0.5) in mass = weight/g =B260/32.17 Ib-s2/ft

=((B289*B286A2/2)A(Z/3))/(672*B288) in thickness -

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 191 Alternate Beam Drop from Max Lift Height to to Gate Opening 88' Beam Length L 12 ft Beam Width, d 0.5 ft Beam thickness 0.333 ft Beam weight, W 200 lb Beam density =B297/(B294*B295*B296) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =B299/B298 drop distance in air 40.3 ft drop distance in water 19.7 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B302) ft/s Reynolds no =( Vo

d)/viscosity =(B304*B295)/B300 Check L/d using beam length and width =B294/B295 Check L/D using beam width and thickness =B295/B296 Drag Coefficient CD 1.16 Ao = width

thickness =B295*B296 ft2 a z (water density

Drag Coeff

Ao )/ (2*W) =(B299*B308*B309)/(2*B297) b = (water density

g)/W =(B299*32.17)/B297 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) =((32.17/B310)*(1.B301))AO .5 ft/s exp(-2*a*x) where x = drop distance in water =EXP(-2*B310*B303) bAo =B311*B309 exp(2aL) =EXP(2*B310*B294) 2aL =2*B310*B294 V^A2 =B312A2 VOA2 =B304A2 bAo*[exp(2aL)*(1-2aL)-1]/2aA2 =B314*(B315*(1-B316)-

1)/(2*(B310A2))

g*(exp(2aL)

wtr dens/beam dens -1)/a =32.17*(B315*B301-1)/B310 Z2x =B317+(B313*(B319+B318+B320))

Vs = (Zx)A0.5 =SQRT(B321) ft/s Convert impact area to equivalent diameter =2*(((B309*144)/3.142)AO.5) in mass = weight/g =B297/32.17 lb-s2/ft thickness =((B326*B323A2/2)A(2/3))/(672*B325) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 192 Load Drop in Pool Gate Drop to Pool Floor Gate Length L 24.39 ft.

Gate Width, d 4.771 ft Gate thickness 0.3958 ft Gate weight, W 2000 lb Gate density =BS/(B2*B3*B4) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =B7/B6 drop distance in air 0 ft drop distance in water 20 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B1O) ft/s Reynolds no =( Vo

d)/viscosity =(B12*B3)/B8 Check L/d using gate length and width =B2/B3 Check L/D using gate width and thickness =B3/B4 Drag Coefficient CD 1 Ao = width

thickness =83*84 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B7*B16*B17)/(2*B5) b = (water density

g)/W =(B7*32.17)/B5 exp(-2*a*x) where x = drop distance in water =EXP(-2*B18*Bll) bAo =B19*B17 2ax =2*B18*B11 VoA2 =B12A2 g/a =32.17/B18 bAo*[(1-2ax)]/2aA2 =B21*(1-B22)/(2*(B18A2))

exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] =B20*(B12A2-B24-(B21/(2*B18A2)))

Zlx =B24+B25+B26 Vs = (Zx)AO.5 =SQRT(B27) ft/s Convert impact area to equivalent diameter =2*(((B17* 144)/3.142)A0.5) in mass = weight/g =B5/32.17 lb-s2/ft thickness =((B32*B29A2/2)A(2/3))/(672*B31) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 193 Gate Drop in Gate Opening Gate Length L 24.39 ft Gate Width, d 4.771 ft Gate thickness 0.3958 ft Gate weight, W 2000 lb Gate density =B39/(B36*B37*B38) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =841/B40 drop distance in air 0 ft drop distance in water 2 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17* B44) ft/s Reynolds no =( Vo

d)/viscosity =(B46*B37)/B42 Check L/d using gate length and width =136/B37 Check L/D using gate width and thickness =B37/B38 Drag Coefficient CD 1 Ao = width

thickness =B37*B38 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B41*B50*B51)/(2*B39) b = (water density

g)/W =(B41*32.17)/B39 exp(-2*a*x) where x = drop distance in water =EXP(-2*B52*B45) bAo =B53*1B51 2ax =2*B52*B45 VoA2 =B46A2 g/a =32.17/B52 bAo* [(1-2ax)]/2aA2 =B55*(1-B56)/(2*(B52A2))

exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] =B54*(B46A2-B58-(B55/(2*B52A2)))

Zlx =B58+B59+B60 Vs = (Zx)AO.5 =SQRT(B61) ft/s Convert impact area to equivalent diameter =2*(((B51*144)/3.142)AO.5) in mass = weight/g =B39/32.17 Ib-s2/ft thickness =((B66*B63A2/2)A(2/3))/(672*B65) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 194 Intermediate Beam Drop to Pool Floor Beam Length L 4.75 ft Beam Width, d 0.4167 ft Beam thickness 0.4167 ft Beam weight, W 175 lb Beam density =B74/(B71*B72*B73) Ib/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =B76/B75 drop distance in air 7.3 ft drop distance in water 37.7 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B79) ft/s Reynolds no =( Vo

d)/viscosity =(B81*B72)/B77 Check L/d using beam length and width =B71/B72 Check L/D using beam width and thickness =B72/B73 Drag Coefficient CD 1.16 Ao = width

thickness =B72*B73 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B76*IB85*B86)/(2*B74) b = (water density

g)/W =(B76*32.17)/B74 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) =SQRT((32.17*((1-B78)/B87)))

exp(-2*a*x) where x = drop distance in water =EXP(-2*B87*B80) bAo =B88*B86 exp(2aL) =EXP(2*B87*B71) 2aL =2*B87*B71 V2A2 =B89A2 VoA2 =B81A2 bAo* [exp(2aL)*(1-2aL)-l]/2aA2 =B91*(892*(1-B93)-1)/(2*(B87^2))

g*(exp(2aL)

wtr dens/beam dens -1)/a =32.17*(B92*B78-1)/B87 Z2x =B94+(B90*(B96+B95+B98))

Vs = (Zx)AO.5 =SQRT(B99) ft/s Convert impact area to equivalent diameter =2*(((B86*144)/3.142)A0.5) in mass = weight/g =B74/32.17 lb-s2/ft thickness =((B104*B1O1A2/2)A(2/3))/(672*Bl03) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 195 Intermediate Beam Drop to Gate Opening Beam Length L 4.75 ft Beam Width, d 0.4167 ft Beam thickness 0.4167 ft Beam weight, W 175 lb Beam density =B112/(B109*B11O*B111) lb/cu ft water density @ 160F 60.99.4 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =B114/B113 drop distance in air 7.3 ft drop distance in water 19.7 ft Vo where h is drop distance in air, V = (2gh)^2 =SQRT(2*32.17*B117) ft/s Reynolds no =( Vo

d)/viscosity =(B119*B110)/B115 Check L/d using beam length and width =B109/B110 Check L/D using beam width and thickness =B110/13111 Drag Coefficient CD 1.16 Ao = width

thickness =B110*B111 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B114*B123*B124)/(2*B112) b = (water density

g)/W =(B114*32.17)/B112 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) =SQRT((32.17*((1-B116)/B125)))

ft/s exp(-2*a*x) where x = drop distance in water =EXP(-2*B125*B118) bAo =B126*B124 exp(2aL) =EXP(2*B125*B109) 2aL =2*B125*B109 V2A2 =B127A2 VoA2 =B119A2 bAo*[exp(2aL)*(1-2aL)-l]/2aA2 =B129*(B130*(1-B131)-

1)/(2*(B125A2))

g*(exp(2aL)

wtr dens/beam dens -1)/a =32.17*(B130*B116-1)/B125 Z2x =B132+(B128*(B134+B133+B135))

Vs = (Zx)AO.5 =SQRT(B136) ft/s Convert impact area to equivalent diameter =2*(((B124*144)/3.142)A0.5) in mass = weight/g =B112/32.17 lb-s2/ft thickness =((B141*B138A2/2)A(2/3))/(672*B140) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 196 Alternate Beam Drop to Pool Floor Beam Length L 12 ft Beam Width, d 0.5 ft Beam thickness 0.333 ft Beam weight, W 200 lb Beam density =B149/(B146*B147*B148) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =B151/B150 drop distance in air 15.3 ft drop distance in water 37.7 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B154) ft/s Reynolds no =( Vo

d)/viscosity =(B156*B147)/B152 Check L/d using beam length and width =B146/B147 Check L/D using beam width and thickness =B147/B148 Drag Coefficient CD 1.16 Ao = width

thickness =B147*B148 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B151*B160*B161)/(2*B149) b = (water density

g)/W =(B151*32.17)/B149 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) =SQRT((32.17*((1-B153)/B162))) ft/s exp(-2*a*x) where x = drop distance in water =EXP(-2*B162*B155) bAo =B163*B161 exp(2aL) =EXP(2*B162*B146) 2aL =2*B162*B146 V2A2 =B164A2 VoA2 =B156A2 bAo*[exp(2aL)*(1-2aL)-l]/2aA2 =B166*(B167*(1-8168)-

1)/(2*(B162A2))

g*(exp(2aL)

wtr dens/beam dens -1)/a =32.17*(B167*B153-1)/B162 Z2x =B169+(B165*(B171+B170+B172))

Vs = (Zx)A0.5 =SQRT(B173) ft/s Convert impact area to equivalent diameter =2*(((B161*144)/3.142)AO.5) in mass = weight/g =B149/32.17 lb-s2/ft thickness =((Bl78*Bl75A2/2)A(2/3))/(672*Bl77) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 197 Alternate Beam Drop to Gate Opening Beam Length L 12 ft Beam Width, d 0.5 ft Beam thickness 0.333 ft Beam weight, W 200 lb Beam density =B186/(B183*B184*B185) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =B188/B187 drop distance in air 15.3 ft drop distance in water 19.7 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B191) ft/s Reynolds no =( Vo

d)/viscosity =(B193*B184)/B189 Check L/d using beam length and width =B183/B184 Check L/D using beam width and thickness =B184/B185 Drag Coefficient CD 1.16 Ao = width

thickness =B184*B185 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B188* B197*B198)/(2*B186) b = (water density

g)/W =(B188*32.17)/B186 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) =SQRT((32.17*(1-B190)/B199)) ft/s exp(-2*a*x) where x = drop distance in water =EXP(-2*B199*B192) bAo =B200*B198 exp(2aL) =EXP(2*B199*B183) 2aL =2*B199*B183 V2A2 =B201A2 VoA2 =B193A2 bAo*[exp(2aL)*(1-2aL)-l]/2aA2 =B203*(B204*(1-B205)-

1)/(2*(B199A2))

g*(exp(2aL)

wtr dens/beam dens -1)/a =32.17*(B204*B190-1)/B199 Z2x =B206+(B202*(B208+B207+B209))

Vs = (Zx)AO.5 =SQRT(B210) ft/s Convert impact area to equivalent diameter =2*(((B198*144)/3.142)AO.5) in mass = weight/g =B186/32.17 lb-s2/ft thickness =((B215*B212A2/2)A(2/3))/(672*B214) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 198 Load Drop to Racks Gate Drop to Racks Gate Length L 24.39 ft Gate Width, d 4.771 ft Gate thickness 0.3958 ft Gate weight, W 2000 lb Gate density =B5/(B2*B3*B4) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =B7/B6 drop distance in air 0 ft drop distance in water 5.14 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B10) ft/s Reynolds no =( Vo

d)/viscosity =(B12*B3)/B8 Check L/d using gate length and width =B2/B3 Check L/D using gate width and thickness =B3/B4 Drag Coefficient CD 1 Ao = width

thickness =B3*B4 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B7*B16*B17)/(2*B5) b = (water density

g)/W =(B7*32.17)/B5 exp(-2*a*x) where x = drop distance in water =EXP(-2*B18*Bll) bAo =B19*B17 2ax =2*B18*B11 Vo^2 =B12A2 g/a =32.17/B18 bAo*[(1-2ax)]/2aA2 =B21*(1-B22)/(2*(B18A2))

exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] =B20*(B12A2-B24-(B21/(2*B18A2)))

Zix =B24+B25+B26 VS = (Zx)^0 .5 =SQRT(B27) ftls

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 199 Intermediate Beam Drop to Racks Beam Length L 4.75 ft Beam Width, d 0.4167 ft Beam thickness 0.4167 ft Beam weight, W 175 lb Beam density =B35/(B32*B33*B34) lb/cu ft water density @ 160F 60.994 Ib/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/beam density =B37/B36 drop distance in air 7.3 ft drop distance in water 22.841 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B40) ft/s Reynolds no =( Vo

d)/viscosity =(B42*B33)/B38 Check L/d using beam length and width =B32/B33 Check L/D using beam width and thickness =B33/B34 Drag Coefficient CD 1.16 Ao = width

thickness =B33*B34 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B37*B46* B47)/(2*B35) b = (water density

g)/W =(B37*32.17)/B35 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) =SQRT((32.17*(1-B39)/B48)) ft/s exp(-2*a*x) where x = drop distance in water =EXP(-2*B48*B41) bAo =B49*B47 exp(2aL) =EXP(2*B48*B32) 2aL =2*B48*B32 V2A2 =B50A2 VoA2 =B42A2 bAo*[exp(2aL)*(1-2aL)-l]/2aA2 =B52*(B53*(1-B54)-1)/(2*(B48A2))

g*(exp(2aL)

wtr dens/beam dens -1)/a =32.17*(B53*B39-1)/B48 Z2x =B55+(B51*(B57+B56+B58))

Vs = (7-x)^0.5 =SQRT(B59) ft/s

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 200 Alternate Beam Drop to Racks Beam Length L 12 ft Beam Width, d 0.5 ft Beam thickness 0.333 ft Beam weight, W 200 lb Beam density =B68/(B65*B66*B67) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/beam density =B70/B69 drop distance in air 15.3 ft drop distance in water 22.84 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B73) ft/s Reynolds no =( Vo

d)/viscosity =(B75*B66)/B71 Check L/d using beam length and width =B65/B66 Check L/D using beam width and thickness =B66/B67 Drag Coefficient CD 1.16 Ao = width

thickness =B66*B67 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B70*B79*B80)/(2*B68) b = (water density

g)/W =(B70*32.17)/B68 Terminal Velocity, V2 = SQRT((g*(1-density water/density beam)/a) =SQRT((32.17*(1-B72)/B81)) ft/s exp(-2*a*x) where x = drop distance in water =EXP(-2*B81*B74) bAo =B82*B80 exp(2aL) =EXP(2*B81*B65) 2aL =2*B81*B65 V2A2 =B83A2 VOA2 =B75A2 bAo*[exp(2aL)*(1-2aL)-l]/2aA2 =B85*(B86*(1-B87)-1)/(2*(B81A2))

g*(exp(2aL)

wtr dens/beam dens -1)/a =32.17*(B86*B72-1)/B81 Z2x =B88+(B84*(B90+B89+B91))

VS = (Zx)^0.5 =SQRT(B92) ft/s

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 201 Gate Tip On Piping Velocity Cases Gate Tip Onto Piping SFC-012-001-3 Gate Length L 4.771 ft Gate Width, d 24.39 ft Gate thickness 0.396 ft Gate weight, W 2000 lb Gate density =B5/(B2*B3*B4) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =B7/B6 drop distance in air 0 ft drop distance in water 1.28 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*BO) ft/s Reynolds no =( Vo

d)/viscosity =(B12*B3)/B8 Check L/d using gate length and width =B2/B3 Check L/D using gate width and thickness =B3/B4 Drag Coefficient CD 1 Ao = width

thickness =B3*B4 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B7*B16*B17)/(2*B5) b = (water density

g)/W =(B7*32.17)/BS, exp(-2*a*x) where x = drop distance in water =EXP(-2*B18*B11) bAo =B19*B17 2ax =2*B18*B11 VoA2 =612A2 g/a =32.17/B18 bAo* [(1-2ax)]/2aA2 =B21*(1-B22)/(2*(B18A2))

exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] =B20*(B12A2-B24-(B21/(2*B18A2)))

ZIx =B24+B25+B26 Vs = (Zx)A0.5 =SQRT(B27) ft/s Convert impact area to equivalent diameter 1.596 in mass = weight/g =B5/32.17 Ib-s2/ft thickness =((B32*B29A2/2)A(2/3))/(672*B31) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 202 Gate lip On Piping SFC-012-014-3 Gate Length L 4.771 ft Gate Width, d 24.39 ft Gate thickness 0.396 ft Gate weight, W 2000 lb Gate density =B39/(B36*B37*B38) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =B41/B40 drop distance in air 0 ft drop distance in water 2.105 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B44) ft/s Reynolds no =( Vo

d)/viscosity =(B46*B37)/B42 Check L/d using gate length and width =B36/B37 Check L/D using gate width and thickness =B37/B38 Drag Coefficient CD 1 Ao = width

thickness =B37*B38 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B41*B50*B51)/(2*B39) b = (water density

g)/W =(B41*32.17)/B39 exp(-2*a*x) where x = drop distance in water =EXP(-2*B52*B45) bAo =B53*B51 2ax =2*B52*B45 VoA2 =B46A2 g/a =32.17/B52 bAo* [(1-2ax)]/2aA2 =B55*(1-B56)/(2*(B52A2))

exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] =B54*(B46A2-B58-(B55/(2*B52A2)))

Zix =B58+B59+B60 Vs = (Zx)AO.5 =SQRT(B61) ft/s Convert impact area to equivalent diameter 1.596 in mass = weight/g =B39/32.17 lb-s2/ft thickness =((B66*B63A2/2)A(2/3))/(672*B65) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 203 Gate Tip On Piping SFC-012-006-3 Gate Length L 4.771 ft Gate Width, d 24.39 ft Gate thickness 0.396 ft Gate weight, W 2000 lb Gate density =B74/(B71*B72*B73) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =B76/B75 drop distance in air 0 ft drop distance in water 3.555 ft Vo where h is drop distance in air, V = (2gh)A2 =SQRT(2*32.17*B79) ft/s Reynolds no =( Vo

d)/viscosity =(B81*B72)/B77 Check L/d using gate length and width =B71/B72 Check L/D using gate width and thickness =B72/B73 Drag Coefficient CD 1 Ao = width

thickness =B72*B73 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B76*B85*B86)/(2*B74) b = (water density

g)/W =(B76*32.17)/B74 exp(-2*a*x) where x = drop distance in water =EXP(-2*B87*B80) bAo =B88*B86 2ax =2*B87*B80 VoA2 =B81A2 g/a =32.17/B87 bAo*[(1-2ax)]/2aA2 =B90*(1-B91)/(2*(B87A2))

exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] =B89*(B81A2-B93-(B90/(2*B87A2)))

Zlx =B93+B94+B95 Vs = (Zx)A0.5 =SQRT(B96) ft/s Convert impact area to equivalent diameter 1.596 in mass = weight/g =B74/32.17 lb-s2/ft thickness =((B101*B98A2/2)A(2/3))/(672*B100) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 204 Gate Tip On Piping SFC-012-007-3 Gate Length L 4.771 ft Gate Width, d 24.39 ft Gate thickness 0.396 ft Gate weight, W 2000 lb Gate density =B109/(B106*B107*1B108) lb/cu ft water density @ 160F 60.994 lb/cu ft water kinematic viscosity @ 160F 0.00000439 sq ft/sec water density/gate density =B111/B110 drop distance in air 0 ft drop distance in water 4.72 ft Vo where h is drop distance in air, V = (2gh)^2 =SQRT(2*32.17*B114) ft/s Reynolds no =( Vo

d)/viscosity =(B116*B107)/B112 Check L/d using gate length and width =B106/B107 Check L/D using gate width and thickness =1107/1108 Drag Coefficient CD 1 Ao = width

thickness =B107*B108 ft2 a = (water density

Drag Coeff

Ao )/ (2*W) =(B111*B120*B121)/(2*B109) b = (water density

g)/W =(B111*32.17)/B109 exp(-2*a*x) where x = drop distance in water =EXP(-2*B122*B115) bAo =B123*B121 2ax =2*"122*"115 VoA2 =B116A2 g/a =32.17/B122 bAo* [(1-2ax)]/2aA2 =B125*(1-B126)/(2*(B122A2))

exp(-2ax) *[(VoA2-(g/a)-(bAo/2*aA2)] =B124*(B116A2-B128-(B125/(2*B122A2)))

Zix =B128+B129+1B130 Vs = (Zx)AO.5 =SQRT(B131) ft/s Convert impact area to equivalent diameter 1.596 in mass = weight/g =13109/32.17 lb-s2/ft thickness =((B136*B133A2/2)A (2/3))/(672*B135) in

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 205 Piping Yield and Ductility Ratio Line SFC-012-001 g 32.174 ft/s2 mass per length 49.56 lb/ft length Dx = 2 in =2/12 ft d = 12.75 in =12.75/12 ft (Dx+2d) =B4+(2*B5) ft Me = (Dx+2d)*Mx =(B6*B3)/B2 lb Mm = 2000/g =2000/B2 lb Impact velocity 7.407 ft/s Vs =B10"12 in/s Es= =(B9A2*B11A2)/(2*(B9+B7))

Mm2*Vs2/2(Mm+Me)

I 279.3 in4 E 27700000 Ib/in2 fdy 30000 Ib/in2 length, ft 24 ft L =B17*12 in Rm = 8*I*fdy/(L*d) =(8*B14*B16)/(B18*12.75) lb xe = RmLA3/48EI =(B19*B18A3)/(48*B15*B14) in mu =B12/(B21*B19) + 0.5

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 206 Line SFC-012-014 g 32.174 ft/s2 mass per length 49.56 lb/ft length Dx= 2 in =2/12 ft d = 12.75 in =12.75/12 ft (Dx+2d) =B30+(2*B31) ft Me = (Dx+2d)*Mx =(B32*B29)/B28 lb Mm = 2000/g =2000/B28 lb Impact velocity 8.15 ft/s Vs =B36*12 in/s Es = =(B35A2*B37A2)/(2*(B35+B33 Mm2*Vs2/2(Mm+Me)

I 279.3 in4 E 27700000 Ib/in2 fdy 30000 Ib/in2 length, ft 24 ft L =843*12 in Rm = 8*l*fdy/(L*d) =(8" B40*B42)/(B44*12.75) xe = RmLA3/48EI =(B45*B44A3)/(48*B41*B40) mu =B38/(B47*B45)+0.5

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 207 Line SFC-012-006 g 32.174 ft/s2 mass per length 49.56 lb/ft length Dx= 2 in =2/12 ft d = 12.75 in =12.75/12 ft (Dx+2d) =B56+(2*B57) ft Me = (Dx+2d)*Mx =(B58*B55)/B54 lb Mm = 2000/g =2000/B54 lb Impact velocity 7.404 ft/s Vs =B62*12 in/s Es = =(B61A2*B63A2)/(2*(B61+B59 Mm2*Vs2/2(Mm+Me)

I 279.3 in4 E 27700000 Ib/in2 fdy 30000 Ib/in2 length, ft 18 ft L =B69*12 in Rm = 8*l*fdy/(L*d) =(8*B66*B68)/(B70*12.75) xe = RmLA3/48EI =(B71*B70A3)/(48*B67*B66) mu =B64/(B73*B71)+0.5 mu

CALCULATION DETAILS CALCULATION NO: G13.18.2.7-116 REVISION: 0 PAGE: 208 Line SFC-012-007 g 32.174 ft/s2 mass per length 49.56 lb/ft length Dx = 2 in =2/12 ft d = 12.75 in =12.75/12 ft (Dx+2d) =B82+(2*B83) ft Me = (Dx+2d)*Mx =(B84*B81)/B80 lb Mm = 2000/g =2000/B80 lb Impact velocity 4.94 ft/s Vs =B88*12 in/s Es = =(B87A2*B89A2)/(2*(B87+B85 Mm2*Vs2/2(Mm+Me)

I 279.3 in4 E 27700000 lb/in2 fdy 30000 lb/in2 length, ft 18 ft L =B95*12 in Rm = 8*l*fdy/(L*d) =(8*B92*B94)/(B96*12.75) xe = RmLA3/48EI =(B97*B96A3)/(48*B93*B92) mu =B90/(B99*B97)+0.5

Attachment 3 RBG-47505 Licensee Commitment (1 page)

This table identifies actions discussed in this letter for which Entergy commits to perform. Any other actions discussed in this submittal are described for the NRC's information and are not commitments.

TYPE Check one) SCHEDULED ONE- COMPLETION COMMITMENT TIME CONTINUN DATE ACTION (If Required)

During movement of pool gates, no fuel in x Upon the affected pools will have been part of a implementation of critical core within the preceding 14 days. this amendment 1

ML14272A181

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