ML17104A041

IP-CALC-13-00005, Rev. 1, Engineering Evaluation of Postulated RWST Inventory Loss During the Reverse Osmosis Clean-up Skid Process in Accordance to 2-TAP-001-ROS Due to a Seismic Event

ML17104A041
Person / Time
Site:	Indian Point
Issue date:	04/19/2013
From:	Mavridis L Entergy Nuclear Northeast
To:	Office of Nuclear Reactor Regulation
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ML17104A039	List: ML17104A041 ML17104A042
References
NL-17-035, TAC MF1440 IP-CALC-13-00005, Rev. 1
Download: ML17104A041 (33)

Text

ATTACHMENT 9.2 ENGINEERING CALCULATION COVER PAGE.

Sheet 1of1 DAN0-1 DAN0-2 0GGNS IZI IP-2 DIP-3 0PLP 0JAF OPNPS ORBS 0VY 0W3 DNP-GGNS-3 DNP-RBS-3 CALCULATION EC# 43679 Page 1 of 33 COVER PAGE Design Basis Cale. DYES [8JNO [8J CALCULATION 0ECMarkup Calculation No: IP-CALC-13-00005 Revision: 1

Title:

Engineering Evaluation of Postulated RWST Inventory Loss During Editorial the Reverse Osmosis Clean-up Skid Process in Accordance to 2-TAP-001- DYES [8J NO ROS due to a Seismic Event System(s): SI, CVCS and SFPC Review Org (Department):

Desi1!11 Emrlneerin2 - Mechanical Safety Class: Component/Equipment/Structure Type/Number:

[8J Safety I Quality Related I

• Unit2RWST Valve845 D Augmented Quality Program Unit2PAB Valve 350 D Non-Safety Related 21 Refueling Water Purification Pump Document Type: Calculation Keywords (Description/Topical Codes):

RWST Drain Down, Seismic, 2-T AP-001-ROS REVIEWS A L.lie£MTM-1~-"" ~

Name/Signature/Date ~e/Signature/Date Nz/signa ure!Dat'e 1JJJ.0lfieri 1-f/qfi~

~

~

V.Myers 1t/1/1)

Responsible Engineer [8J Design '1erifier ' r Supervisor/Approval D Reviewer D Comments Attached D Comments Attached

Calculation No. IP-CALC-13-00005 Rev.1 Page 2 of33 ATIACHMENT 9.3 CALCULATION REFERENCE SHEET Sheet I of l CALCULATION CALCULATION NO: IP-CALC-13-00005 REFERENCE SHEET REVISION: 1 I. EC Markups Incorporated (NIA to NP calculations)

1. EC 42176 ,

2.

3.

4.

5.

II. Relationships:

• Sht Rev Input Output Impact Tracking Doc Doc YIN No.

1. Entergy Calculation FIX-00096, 1 [8] 0 "RWST - Level Instnunentation Channel Accuracies,*Calibration, and Setpoints".

2. Entergy Report IP-RPT-09-00014, 1 [8] 0 "Critical Submergence Evaluations Related to Surface Vortices in Nuclear Safety and Augmented Quality Tanks/Pumps at IPEC".

3. 0 0

4. 0 0

5. 0 0 Ill. CROSS

REFERENCES:

1. See Section 11.0 of this calculation.

2.

3.

4.

5.

IV. SOFTWARE USED:

Title:

None Version/Release: Disk/CD No.

v. DISK/CDS INCLUDED:

Title:

None Version/Release Disk/CD No.

VI. OTHER CHANGES:

(

Calculation No. IP-CALC-13-00005 Rev.1 Page3 of33 AlTACHMENT 9.4 RECORD OF REVISION Sheet 1of1 Initial issue of calculation IP-CALC-13-00005.

0 Issue of calculation IP-CALC-13-00005 Rev. 1. Revision includes the replacement of 2 postulated scenarios with 2 others as well as a number of 1 editorial comments for clarification purposes. It also included the correction of a typographical error in section 9.0 Eq. 9.13, and in Section 10, the Tables were changed to show decreasing RWST level.

Calculation No. IP-CALC-13-00005 Rev. 1 Page 4 of33 4.0 Table of Contents 1.0 Calculation Cover Sheet 1 2.0 Calculation Reference Sheet 2 3.0 Record of Revision 3 4.0 Table of Contents 4 5.0 Purpose 5 6.0 Conclusion 6 7 .0 Inputs and Design Criteria 6 8.0 Assumptions 8 9.0 Method of Analysis 8 10.0 Calculations 12 11.0 References 32_

12.0 Attachments 33 12.1Attachment1 -Line Segment/LegJnformation (1 Page).

Calculation No. IP-CALC-13-00005 Rev. 1 Page S of33 5.0 Purpose

Background

During steps outlined in procedure 2-TAP-001-ROS, "Installation/Removal of the Reverse Osmosis Silica Clean-up Skid", temporary hoses/connections are installed in order to nm the Unit 2 Osmosis Silica Clean-up Skid. The installation of the Reverse Osmosis Skid to Valve 725 (line #135) and to the flange downstream of valve 350 (line #2531252) creates an interface between seismic and non-seismic lines. These connections create new established pressure boundaries to the system as a whole during the operation of the Reverse Osmosis Skid.

Objective The objective of this calculation is to determine maximum flow through a break at the seismic/non-seismic boundaries at valve 725 (line# 135) and at the flange downstream of valve 350 (line #253/252), and the time available prior to reaching the minimum Refueling Water Storage Tank Technical Specifications water level limit of 36.83' (Reference 5 and 22 per SR 3.5.4.2), based on the minimum and maximum water level that could be stored in the RWST (Overflow level is 37.65', Reference 5). Revision 1 includes cases E and F which require that the Low Level Alarm in the CCR be manipulated for the duration of operation for this purification skid. Also after conversations with Licensing and Operations, and based on Operations experience, it was decided that the objective of this calculation should be considered for each of the following 6 scenarios:

A. The Low Level Alarm in the CCR is set at 37.01. The rupture occurs during circumstances that do not call for an SI signal, in which case the purification pump is in operation.and the assumed operator time to respond and isolate Segment 1 is 3 minutes.

B. The Low Level Alarm in the CCR is set at 37.01. The rupture occurs during circumstances that do not call for an SI signal, fn which case the purification pump is in operation and the assumed operator time to respond and isolate Segment 1 is 5 minutes.

C. The Low Level Alarm in the CCR is set at 37.01. The rupture occurs during circumstances that call for an SI signal, in which case the purification pump will be stripped out of operation, all three SI pumps are assumed to be operating and the assumed operator time to respond and isolate Segli1ent 1 is 3 minutes.

D. The Low Level Alarm in the CCR is set at 37.01. The rupture occurs during circumstances that call for an SI signal, in which case the purification pump will be stripped out of operation, all three SI pumps are assumed to be operating and the assumed operator time to respond and isolate Segment 1 is 5 minutes.

E. The Low Level Alarm in the CCR is changed to 37.33 for the duration of the Purification Skid. The rupture occurs during circumstances that do not call for an SI signal, in which case the purification pump is in operation and the assumed operator time to respond and isolate Segment l is 10 minutes.

F. The Low Level Alarm in the CCR is changed to 37.33 for the duration of the Purification Skid. The rupture occurs during circumstances that call for an SI signal, in which case the purification pump will be stripped out of operation, all three SI pumps are assumed to be operating and the assumed operator time to respond and isolate Segment I is IO minutes.

Note: Isolating Segment 1 involves the closure of valves 845 and 727A as well as tripping the Purification Pump if necessary (During circumstances that do not call for an SI signal). Isolation of Segment 2 involves closing valve 350.

Calculation No. IP-CALC-13-00005 Rev. 1 Page 6 of33 6.0 Conclusion The maximum time available prior to reaching the minimum RWST TS water level limits during a postulated break at the seismic/non-seismic boundaries at valve 725 (line# 135) and at the flange downstream of valve 350 (line #253/252) has been calculated for 6 different scenarios. Scenarios during circumstances that do not call for aii SI signal result in less time available for operator action. The maximum time available for scenarios A through Fas outlined in section 5.0 are tabulated below:

Table 6.1 Time to Reach TS Limits (Min) Based on Postulated Scenarios Purification Safety Injection Assumed Time Remaining Postulated Pump Pumps to Isolate Ti me to lsol ate Scenario QperatinQ QperatinQ Seament 1 Seament 2 A Yes No 3.0 9.6 B Yes No 5.0 3.6 c No Yes 3.0 10.3 D No Yes 5.0 5.8 E Yes No 10.0 21.7 F No Yes 10.0 24.8 Note: For the calculated flow rate in each scenario refer to Tables 10.1through10.6. The values in Table 6.1 are based on a minimum water level in the RWST defined in each scenario description in section 5.

While the Table above demonstrates timing for specific RWST initial levels, the Tables in Section 10 demonstrate a wider rang~ of RWST initial levels and isolation times for Segment 1 and Segment 2.

7 .0 . Inputs and Design Criteria Design Basis

1. Throughout this calculation, the paths from the RWST to each postulated break point are identified as follow:

a. Segment 1 begins at the 16" suction line from the RWST (line #155), through the 2" line leading to the Refueling Water Purification Pump (line #183), past the Refueling Water Purification Pump #21 through the 2" line and break point downstream of valve 725 (line #135) (Reference 1, 2, and 3).

b. Segment 2 begins at the 3" discharge line into the R WST (line # 16 l ), through the 2" line leading to the Boric Acid Blender in the CVCS (line #253), past valve 350 to the flange at the 2" line and break point downstream of valve 350 (line #252) (Reference l and 4).

2. The lengths of the Safety Injection and Auxiliary Coolant lines #155 (16"), #183 (2") and #135 (2") as well as the Safety Injection and Chemical Volume Control System lines #161 (3") and #253 and #252 (2") (Reference 1, 2, 3 and 4), are documented in the sununary tables in Attachment 1.

3. The number of fittings and components in the flow path of the Safety Injection and Auxiliary Coolant lines #155 (16"), #183 (2") and #135 (2") as well as the Safety Injection and Chemical and Volume Control System lines #161 (3") and #253 and #252 (2") (Reference 1, 2, 3 and 4), are documented in the summary tables in Attachment 1.

Calculation No. IP-CALC-13-00005 Rev.1 Page 7of33

4. The minimum water level in the RWST is 36.83', which was calculated based on the minimum water volume stated in the Surveillance Requirements of section 3.5.4 of the Unit 2 Technical Specifications (Reference 5 and 22).

5. The current RWST Low Level Alarm in the CCR is 37.01' and the RWST overflow level is 37.65' (Reference 15).

6. The elevations of the tanks outlet nozzle into line #155 is 82.5' and the elevation of the inlet nozzle into the tank from line #161 is 93.25' (Reference 1).

7. The elevations of the assumed breaks in the 2" lines (#135 and #253) at the seismidnon-seismic connections just downstream of valve 725 is 71.0' and the blind flange upstream of valve 350 is 99.5' (Reference 3 and 4 respectively).

8. The available minimum water inventory of 9368.1 gallons per 1 foot of height in the RWST (Reference 20).

9. All piping is Class 151R per Reference 6, 7, and 8. Per Specification in Reference 9, the 2" pipe can be schedule lOS or 40S (Stainless Steel) and the 3" pipe is schedule 40S (Stainless Steel). Per Reference 9 and 14, piping wall thickness and diameter for 16" pipe is 0.25" and 15.5" respectively, schedule 40S piping wall thickness and diameter for 3" pipe is 0.216" and 3.0~8" respectively, and schedule lOS (chosen for conservatism over 40S since this would lower the effective resistance through the pipe) piping wall thickness and diameter for 2" pipe is 0.109" and 2.157" respectively.

10. Rupture of the piping downstream of the purification pump #21 should be considered in this calculation as follows:

a. If the rupture occurs during circumstances that do not call for an SI signal, in which case the pump is in operation, then the maximum calculated flow through the mpture is governed by the pump runout flow of 180 GPM (Reference 10).

b. If the rupture occurs during circumstances that call for an SI signal, in which case the pump will be stripped out of operation, then the maximum calculated flow through the mpture via gravity drain will be used to determine available time to reach the RWST TS minimum required limit.

11. Rupture of the piping downstream of valve 350 (line #253/252) should be considered in this calculation as follows:

a. If the rupture occurs during circumstances that call for an SI signal, then the-maximum calculated flow through the rupture is governed by the maximum recirculation flow from all three SI Pumps (for conservatism) of 99 GPM (Reference 11, 12and13).

b. If the rupture occurs during circumstances that do not call for an SI signal, then the maximum calculated flow through the mpture via gravity drain will be used to determine available time to reach the RWST TS minimum required limit.

12. Line break is conservatively assumed to be a fully '"guillotine break" in the seismic/non-seismic connections immediately downstream of valve 725 and the flange upstream of valve 350. This is conservative, since this is a low pressure line and a smaller break or leak is more probable.

13. Pressure loss through the purification pump #21 (when the pump is not in operation) is not accounted for in this calculation. This is conservative, since the additional pressure loss would increase the available time.

Calculation No. IP-CALC-13-00005 Rev. 1 Page 8of33

14. Per Pipe Friction Data, A-26 in Reference 14, initial pipe friction factors for the affected piping sections are listed below:

a, 2" Pipe,JT= 0.019 (Segment 1and2)

b. 3" Pipe.fr= 0.018 (Segment 2)

c. 12-16" Pipe,Jr = 0.013 (Segment 1)

15. Pipe friction factors for the affected piping sections which are determined using the calculated Reynolds . *:'

number and Friction Factor graphic A-25 in Reference 14 are the adjusted friction factors. The adjusted friction factors for the affected piping sections are listed below:

a. 2" Pipe, fT = 0.026 (Segment 1), fr= 0.027 (Segment 2)

b. 3" Pipe.fr= 0.028 (Segment2)

c. 12-16" Pipe,Jr=0.018(Segment1)

16. Water density and viscosity for this system is assumed to be at about 120°F with values of 61.71 pounds per cubic foot and 0.56 centipoise respectively (Reference 14).

17. Flow coefficients for each valve in the system (Reference 17 and 18; the Unit 3 drawing for reference 17 is also applicable for the same type of valves in Unit 2):

a. Valve 845, Cv = 60

b. Valve 727A, Cv = 60

c. Valve 726A, Cv = 60

d. Valve 1860, Cv = 190

e. Valv~ 350, Cv = 70

18. In some cases, calculating the flow resistance through a fitting can be achieved from multiple equations depending on certain parameters. In such cases, the most conservative parameters are assumed in order to lead to the equation that is the most conservative overall (Reference 14). ,

Refer to section 11.0 for a complete list of references used in this calculation.

8.0 Assumptions None.

9.0 Method of Analysis The following approach has been used in performing this calculation:

a. Determine* potential flow through identified lines leading to postulated break points at the seismic/non-seismic boundaries at valve 725 (line# 135) and at the flange downstream of valve 350 (line #252).

The first step in this process is to identify and calculate the available head that will detennine the flow through the postulated breaks, which is a result of the differential pressure produced by the level in the RWST and the break locations. The equation used to calculate available head (Reference 14) is as follows:

HL = hRWST -hBreuk (9.1)

Calculation No. IP-CALC-13-00005 Rev.1 Page9of33 Where:

=

H L Available Head (ft) hRwsr = Elevation of level in the RWST (ft) h8 ,.ak = Elevation of break in the system (ft)

Once the available head has been determined, calculate the resistance losses through the straight length of pipe, fittings and components. The resistance loss through the straight length of piping in the system was determined using equation 9.2 (Reference 14):

L Kr =fx- (9.2)

D Where:

KP = Flow resistance of the piping system f = Friction factor of the piping system based on the pipe diameter L = Length of the piping system (ft)

D = Diameter of the pipe (ft)

The resistance losses through the 90° elbows in the piping system were determined using equation 9.3 (Reference 14):

K90 = 30 x f x N90 .(9.3)

Where:

K90 = Flow resistance of the 90° elbow in the piping system f = Friction factor of the piping system based on the pipe diameter N90 = Number of 90° elbow in the piping system The resistance losses through the 45° elbows in the piping system were detennined using equation 9.4 (Reference 14):

K45=16xfxN45 (9.4)

Where:

K 45 = Flow resistance of the 45°* elbow in the piping system f = Friction factor of the piping system based on the pipe diameter N45 =Number of 45° elbow in the piping system The resistance losses through a tee in the piping system were determined using equation 9.5 (Reference 14):

Kr =60xf (9.5)

Where:

Kr = Flow resistance of a tee in the piping system f = Friction factor of the piping system based on the pipe diameter The resistance losses through contractions and expansions in the piping system were determined using equation 9.6 and 9.7 respectively (Reference 14):

Calculation No. IP-CALC-13-00005 Rev. 1 Page 10of33 (9.6)

(9.7)

Where:

Kc = Flow resistance of the contraction in the piping system KE = Flow resistance of the expansion in the piping system p= Dl/D2 (Dl =smaller D, D2 =larger D)

(sine ) 112 = Assigned the value of l for ~onservatism.

2 The resistance loss through a fully open gate valve in the piping system was determined using equation 9.8 (Reference 14):

• K Ga1eVafre =8 X J X N GateVafre (9.8)

Where:

KcareValve = Flow resistance through a fully open gate valve in the piping system f = Friction factor of the piping system based on the pipe diameter N caieVafre = Number of fully open gate valves in the piping system

• The resistance loss through other fully open valves in the piping system was determined using equation 9.9 (Reference 14):

(9.9)

Where:

Kvafre = Flow resistance through a fully open valve in the piping system D = Diameter of the piping system (ft)

Cv =Flow Coefficient for each valve The resistance loss through a pipe entrance/inlet ( K PI) and a pipe exit ( K PE) in the piping system is 0.5 and l respectively (Reference 14).

\\<'hen a piping system contains more than one size of pipe, valves and fittings, all resistances should be expressed in terms of one size. The resistance loss for sudden enlargements and contractions expressed in terms of the large pipe was detennined using equation 9.10 (Reference 14):

K =Ki 2 p4 (9.10)

Where:

K 2 = Flow resistance in tem1s of the larger pipe diameter K1 = Flow resistance calculated based on actual pipe diameter

, Calculation No. IP-CALC-13-00005 Rev. 1 Page 11 of33 fJ = Dl/D2 (Dl =smaller D, D2 =larger D)

b. Once the total resistance is calculated, KT, it is used to determine the maximum flow rate through the piping system. The maximum flow rate through a piping system was detem1ined using equation 9 .11 (Reference 14):

l/2 2

Q=l9.65xD x HL (9.11)

(

KT )

Where:

Q = Maximum flow rate through the piping system (GPM)

KT = Total flow resistance calculated through the piping system H L = Available Head (ft)

D = Diameter of the piping system (inches)

c. Calculate Reynolds number based on determined flow rates.

Using the maximum flow rate calculated, the Reynolds number can be determined using equation 9.12 (Reference 14):

Re= 50.6xQxp (9.12).

Dxµ Where:

Re = Reynolds number based on calculated flow rate Q = Maximum flow rate through the piping system (GPM) p = Density in pounds per cubic feet @ 120°F

. µ = Viscosity in centipoise @ 120°F D = Diameter of the piping system (inches)

d. Adjust the flow rate as necessary based on the calculated Reynolds number. The Reynolds number calculated above allows us to determine a more accurate Friction factor for this system. Using graphic A-25 in Reference 14, a more accurate friction factor for each piping segment (depending on the pipe diameter) is determined. Using those adjusted friction factors; equations 9.2 through 9.11 will be adjusted as necessary to re-calculate a more accurate maximum flow rate.

e. Using the calculated maximum flow rate (Equation 9.1 l), determine the available time prior to reaching Technical Specifications limit of 36.83' from assumed RWST alarm levels of 37.01' or 37.33' (based on available inventory of 9368.1 gallons of water per foot of height in the RWST; Reference 15) for each of the 6 scenarios outlined in section 5. In order to determine the available time prior to reaching the Technical Specifications Minimum Water Level of 36.83', a water level in the RWST of 37.65' (at Overflow Level) will be assumed to provide a higher HL when calculating Q 1 and Q2* Using a higher water level in the tank, Q1 and Q2 are adjusted to account for the difference in available head (HL), leading to higher flowrates.

This will provide some additional head, leading to higher outflow rates of 123.9 gpm (instead of 122.8 gpm) for Q1 at37.01' level in the RWST and 91.0 gpm (instead of 89.5 gpm) for Q2 at 37.01' level in the RWST, which is overall conservative. The available time prior to reaching Technical Specifications limit of 36.83' can be calculated using equation 9.13:

Calculation No. IP-CALC-13-00005 Rev. 1 Page 12of33 (9.13)

Where:

TMux = Time available prior to reaching TS limit based on calculated flow rates (Min)

Q1 = Maximum flow rate through segment 1 (GPM)

Q2 = Maximum flow rate through segment 2 (GPM)

VRwsT = Volume in the RWST based on water level (Gallons)

Note: After isolating segment 1, Q1 goes to zero.

f. Determine additional available time, if the initial level in the RWST is higher than 37.01' or 37.33' (Reference 15). In order to determine the available time prior to reaching the Technical Specifications Minimum Water Level of 36.83' ,'a water level in the RWST of 37.65' (at Overflow Level) will be assumed to provide a higher HL when calculating Q 1 and Q2

• Using a higher water level in the tank, Q 1 and Q2 are adjusted to account for the difference in available head (HL), leading to.higher flowrates. This will provide some additional head, leading to higher outflow rates of 123.9 gpm (instead of 122.8 gpm) for Ql at 37.01' level in the RWST and 91.0 gpm (instead of 89.5 gpm) for Q2 at 37.01' level in the RWST, which is overall conservative.

10.0 Calculations o Determine the maximum flow rate through the break downstream of valve 725 (line #135):

Available head that determines the flow through the break in the 2" line downstream of valve 725 (line

1. 135), is the result of the differential pressure produced by the level in the RWST and the break location.

1. Available head to drive flow through Segment 1 at the 2" line break from the RWST is as follows:

a. The RWST Minimum Limit TechniCal Specification level is 36.83' tank level (this includes an allowance for instrument uncertainty of 2.65'). The minimum log reading is 37.01' currently used for the RWST Low Level Alarm in the CCR according to procedure 2-ARP-SBF-l.

b. This equates to an elevation of 118.06' with the tank bottom being at elevation of 81.05'.

c. The break point downstream of valve 725 is at elevation 71' (Segment l).

d. Therefore, using equation 9.1, at Minimum Limit Technical Specification level, available head through each break is:

Hu= Min. RWST Level Elevation (ft) - Break Point Elevation (ft)

Hu = 118.06' - 71' Hu= 47.06'

2. Determine the flow resistance for the various components within the 16" and 2" lines from the piping isometrics (Reference 1, 3 and 4) and formulas from Crane (Reference 14).

For the 16" section:

Calculation No. IP-CALC-13-00005 Rev.-1 Page 13of33

- Length of piping is approximately 136.4'.

- Number of 90° elbows is 3 (including one 14" elbow and two 16" elbows).

- Number of 45° elbows is 1.

- 16" to 14" contraction.

- 14" to 16" expansion.

- Valve 846-14" Anchor Darling Gate Valve.

Flow resistance for the 16" piping section using equation 9.2:

L Kt6p =fx-D Where:

K 16 P =Flow resistance of the 16" piping system f =Friction factor of the 16" piping system (0.013)

L =Length of the 16" piping system (136.4')

D =Diameter of the 16" pipe in feet (15.5"/12" = 1.292')

136 K 16 = 0.013x .4 p 1.292 K 16 P = 0.013x105.593 K 16 P = 1.373 Flow resistance for 90° elbows in the 16" piping section using equation 9.3:

K90 06 ..) = 30 x f x N90 Where:

K90 06 .. > =Flow resistance of 90° elbows in the 16" piping system f =Friction factor of the 12"-16" piping system (0.013)

N90 =Number of 90° elbows in the 16" piping system (2)

K90 06 .. ) = 30x f x N90 K90n 6"l = 30x0.013x 2 K90< 16 .. ) = 0.78 K90 <14.. 1 = 30 x f x N90 Where:

K90< 14 .. l =Flow resistance of 90° elbows in the 14" portion of the piping system f =Friction factor of the 12"-16" piping system (0.013)

N90 =Number of 90° elbows in the 16" piping system ( 1)

Calculation No. IP-CALC-13-00005 Rev.1 Page 14of33 K90 04 .> =30 x f x N90 K90( 14.> = 30x0.013xl K90< 14-i = 0.39 Calculate K90 04.> in terms of 16" piping using equation 9.10:

K90< 14..>

K90<cl6") = /34 Where:

K90<e1 6*i =Flow resistance of 14" 90° elbow in terms of 16" piping K90< 14.> =Flow resistance of 90° elbows in the 14" portion of the piping system (0.390) p = 01/02 (Dl = 13.5" (smaller 0), 02 = 15.5" (larger D)) (0.87097)

K90 04..>

. K90<e16"> = /34 K90 - 0;39 6

(el ") - (0.87097) 4 K90<* 16 ..> = 0.678 Flow resistance for 45° elbows in the 16" piping section using equation 9.4:

K45 06.> =16xfxN45 Where:

K45 06..> =Flow resistance of 45° elbows in the 16" piping system f =Friction factor of the 12"-16" piping system (0.013)

N45 =Number of 45° elbows in the 16" piping system (1)

K45 06 ..> =16xfxN45 K45< 16.> = 16x0.013xl K45 06 .. , = 0.208 Flow resistance for 16 "-14" contraction in 16" piping section using equation 9. 6:

{} .

0.50x(l-/3 2 )x(sin-) 112 K C* -- 2

/34 Where:

Kc =Flow resistance of 16"-14" contraction in 16" piping system p =Dl/D2(D1 = 13.5" (smaller D), 02 = 15.5" (larger 0)) (0.87097)

Calculation No. IP-CALC-13-00005 Rev. 1 Page 15 of33 (sin() ) 112 =Assigned the value of 1 for conservatism 2

8 0.50x(l- p 2 )x(sin )112 K - 2 c- p4 K _ 0.50x(l-0.87097 2 )xl c- 0.87097 4 Kc =0.210 Flow resistance for 14"-16 expansion in 16" piping section using equation 9.7:

Where:

KE =Flow resistance of 14"-16" expansion in 16" piping system fJ = Dl/D2 (Dl = 13.5" (smaller D), D2 = 15.5" (larger D)) (0.87097)

(1- p2)2 KE= p4 2 2 K = (1-0.87097 )

E 0.87097 4 KE =0.101 Flow resistance for valve 846 in the 16" piping section using equation 9.8:

K 846 =8Xf Xl Where:

K 846 =Flow resistance of valve 846 in the 16" piping system f =Friction factor of the 12"-16" piping system (0.013)

Ks46 =8Xf K846 = Sx0.013 K 846 =0.104 Total resistance through 16" piping section Krt 6.. = K 16 P + K90( 16.l + K90\el6"l + K45(Iti") +Kc+ KE+ K846 Km .. == 1.373+ 0.678+0.78+0.208+0.210+0.101+0.104 Km . = 3.453

Calculation No. IP-CALC-13-00005 Rev. 1 Page 16of33 For the 2" section:

- Length of piping is approximately 24.0'.

- Number of 90° elbows is 7.

Number of 45° elbows is 1.

- Valve 845-2" Rockwell Edwards, Y-Globe Valve.

- Valve 727 A - 2" Rockwell Edwards, Y-Globe Valve.

- Valve 726A- 2" Check Valve

- Valve 725 - 2" Grinnell Saunders, Diaphragm Valve.

Flow resistance for the 2" piping section using equation 9.2:

Where:

K 2 P =Flow resistance of the 2" piping system f =Friction factor of the 2" piping system (0.019)

L =Length of the 2" piping system (23.990')

D =Diameter of the 2" pipe (0.180')

23 990 K 2 =0.019x

• P 0.180 K2 P = 0.019xl33.424 K 1 p =2.535 Flow resistance for 90° elbows in the 2" piping section using equation 9. 3:

K90< 2"l =30xfxN90 Where:

K90< 2") =Flow resistance of 90° elbows in the 2" piping system f =Friction factor of the 2" piping system (0.019)

N90 =Number of 90° elbows in the 2" piping system (7)

K90< 2"J =30x .f x N90 K90< 2") = 30x0.019x7 K90< 2 "J =_3.990 Flow resistance for 45° elbows in the 2" piping section using equation 9.4:

K 45 <1") = 16 x f x N 45 Where:

K 45 06 .. } =Flow resistance of 45° elbows in the 2" piping system

Calculation No. IP-CALC-13-00005 Rev. 1 Page 17of33 f =Friction factor of the 2" piping system (0.019)

N45 =Number of 45° elbows in the 2" piping system (1)

K45<Z") =16xf xN45 K45cz*> = 16x0.019xl K45<n =0.304 Flow resistance for valve 845 in the 2" piping section using equation 9. 9:

K _ 891xD 4 845 - czv Where:

. K845 =Flow resistance of valve 845 in the 2" piping system Cv Coefficient = 60 (Reference 18)

D =Diameter (2.157")

. 891xD 4 Ks4s = ci v

. _ 891x2.157 4 K 845 - 602 K 845 = 5.358 Flow resistance for valve 72 7A in the 2 *: piping section using equation 9. 9:

4 K _ 891xD 727A - C2 v

Where:

K727 .1 =Flow resistance of valve 727 A in the 2" piping system Cv Coefficient= 60 (Reference 18)

D =Diameter (2.157")

89lxD 4 K121A = c2 v

K = 891x2.157 4 727A 602 K 727 A =5.358 Flow resistance for valve 726A in the 2" piping section using equation 9.9:

I Calculation No. IP-CALC-13-00005 Rev. 1 Page 18of33 4

K _ 89lxD 726A - C2 v

Where:

K 727 A =Flow resistance of valve 726A in the 2" piping system Cv Coefficient= 60 (Reference 17; the Unit 3 drawing for reference 17 is also applicable for the same type of valves in Unit 2)

D =Diameter (2.157")

K _ 891XD 4 n6,\ - c2 v

4 K = 891x2.157 726.4. 602 K726A =5.358 Flow resistance for valve 725 in the 2" piping section usi1tg equation 9.3:

K 725 =30xf xN90 Where:

K 125 =Flow resistance of valve 725 in the 2" piping system f =Friction factor of the 2" piping system (0.019)

K 725 =30xf xN90 K125 = 30x0.019Xl K 725 =0.570 Note: During this process, the internals of valve 725 are removed and a hose is connected, and considering the shape of valves internals, the valve is assumed to behave like a 90° elbow in the system.

Total resistance through 2" piping section:

Kn" = K + K90( "> + K45( 2"l + K + K + K + K 2 ,, 2 845 721 A 726 A 725 Kn- =2.535 +3.990 + 0.304 + 5.358 + 5.358 + 5.358 + 0.570 KT2" = 23.473 Calculate Kr 2" in terms of 16" piping using equation 9.10:

. KT? .

Kre16" = --t-

/J Where:

Calculation No. IP-CALC-13-00005 Rev.1 Page 19of33 K7e1 6* =Flow resistance of 2" total in terms of 16" piping system f3 = Dl/D2 (Dl = 2.157" (smaller D), 02 = 15.5" (larger D)) (0.139161)

Kn*

Krew=y K _ 23.473 6

Tel " - (0.139161)4 KTel6" = 62586.538 Total resistance through entire piping section:

KT = KTe\6" + KT16" + Kinter + Kexit KT2" = 62586.538 + 3.453+0.5+1 K.1'2" = 62591.492

3. Calculate maximum flow through the combined 16" and 2" piping.section using equation 9.11:

H )11 2 Q1 =19.65xDL6"x ( ;

Where:

Q1 =Flow in GPM D16. =Diameter in terms of 16" pipe (15.5")

H L =Available Head due to elevation only (47.06')

K = Total resistance ( 62591.492)

H )112 Q1 =19.65XD(6.. X (  ;

Q = 19.65x15.5 2 l

x( 47 06 62591.492 )

If"

~

Q1 =129.45 o Based on the above flow rate, calculate the Reynolds Number using equation 9.12:

Re= 50.6xQxp Dxµ Where:

Q =Flow in GPM D = Diameter ( l 5.5" and 2.1. 57")

p =Density in pound per cubic feet@ 120°F (61.71)

J,i =Absolute viscosity in centepoise @ 120°F (0.56)

Calculation No. IP-CALC-13-00005 Rev. 1 Page 20of33 For the 16" section:

_ 50.6xQ1 xp Re16* -

D16.xµ R _ 50.6x129.45x61.71 eiii* - 15.5x0.56 Rel6" = 4.66E +04 At the above Reynolds No., friction factor is approximately equal to 0.018 for the 16" piping section as per figure A-25 of Reference 14. This number is greater thtln the assumed value of 0.013. Therefore, flow resistance of the piping system needs to be adjusted and re-computed using a friction factor of 0.018 for the 16" piping section instead of 0.013.

For the 2" section:

', Re .. = 50.6xQ1 xp 2

Drxµ R 50.6x129.45x61.71 e2" = 2.1S7x0.56 Re 2.. = 3.350£ + 05 --

At the above Reynolds No., friction factor

\ .

is approximately equal to 0.026 for the 2" piping section as per figure A-25 of Reference 14. This number is greater than the assumed value of 0.019. Therefore, flow resistance of the piping system needs to be adjusted and re-computed using a friction factor of 0.026 for the 2" piping section instead of 0.019.

o Adjust the calculated flow rate by going through the calculation steps using equations 9.2 through 9.11 adjusting the flow resistance through the system, where applicable, with the new friction factors based on the above determined Reynolds number:

For the 16" Pipe:

K 16 r = 1.901 K90 06 .. > = 1.08 K90c 016 .. ) = 0.938 K45< 16..i = 0.288 Kc= 0.210 KE= 0.101 K 846 = 0.144 - (

Kn 6.. = 4.662 For the 2" Pipe:

K 2P = 3.469 K90< 2..1 = 5.46 K45t 2 "> = 0.416

Calculation No. IP-CALC-13-00005 Rev. 1 Page 21of33 K 845 = 5.358 K727A = 5.358 K726A = 5.358 K 125 = 0.780 Kn . = 26.198 KTel 6" = 69539.01 Kin/et= 0.5 Kexit = 1.000 KT= 69545.172 The adjusted flow rate using the adjusted Kr is:

Q1 = 122.81 GPM o Determine the maximum flow rate through the break downstream of valve 350 (line #252):

Available head that determines the flow through the break in the 2" line downstream of valve 350 (line

1. 252), is the result of the differential pressure produced by the level in the RWST and the break location.

1. Available head to drive flow through Segment 2 at the 2" line break from the RWST is as follows:

a. The RWST Minimum Limit Technical Specification level is 36.83' tank level (this includes an allowance for instrument uncertainty of 2.65'). The minimum log reading is 37.01' currently used for the RWST Low Level Alarm in the CCR according to procedure 2-ARP-SBF-1.

b. This equates to an elevation of 118.06' with the tank bottom being at elevation of 81.05'.

c. T_he break point downstream of valve 350 is at elevation 91.5' (Segment 1).

d. Therefore at Minimum Limit Technical Specification level, available head through each break is:

HL2 ==Min. RWST Level Elevation (ft) - Break Point Elevation (ft)

Hu== 118.06' - 91.5' Hu== 26.56'

2. Determine the flow resistance for the various components within the 3" and 2" lines from the piping isometrics (Reference 1, 3 and4) and formulas from Crane (Reference 14).

For the 3" section:

- Length of piping is approximately 152.49'.

- Number of 90° elbows is 4.

- Number of 45° elbows is L 3" tee connecting line # 161 and #253.

- 3" to 2" contraction.

Calculation No. IP-CALC-13-00005 Rev.1 Page 22of33

- Valve 1860- 3" Grinnell Saunders Diaphragm Valve.

Flow resistance for the 3" piping section using equation 9.2:

L K3p =fx-D Where:

K 3 P =Flow resistance of the 3" piping system f =Friction factor of the 3" piping system (0.018)

L =Length of the 16" piping system (152.49')

D =Diameter of the 3" pipe (0.256')

152 9 K = 0.018x .4 Jp 0.256 K 3P = 0.018x596.361 K 3 P = 10.735 Flow resistance for 90° elbows in the 3" piping section using equation 9.3:

K90< 3.l = 30xf xN90 Where:

K90< 3") =Flow resistance of 90° elbows in the 3" piping system f =Friction factor of the 3" piping system (0.018)

N90 =Number of 90° elbows in the 3" piping system (4)

K90<J"> = 30xf xN90 K90( 3.> = 30x0.018x4 K90 13 ..l =2.16 Flow resistance for 45° elbows in the 3" piping section using equation 9.4:

K45 0 .l = 16xf x N45 Where:

K45cn =Flow resistance of 45° elbows in the 3" piping system f =Friction factor of the 3" piping system (0.018)

N45 =Number of 45° elbows in the 3" piping system (1)

K45crJ =16xfxN45 K45w) = 16x0.018xl K 45< 3") =0.288

Calculation No. IP-CALC-13-00005 Rev.1 Page 23of33 Flow resistance for valve 1860 in the 3" piping section using equation 9. 9:

4 K _ 891XD 1s60 - c2v Where:

K 727 A =Flow resistance of valve 1860 in the 3" piping system Cv Coefficient = 190 (Reference 16)

D = Dian1eter (3.068")

4 K _ 891xD 1s60 - c2v 4

K _ 891x3.068 1860 - 1902 Ki 860 = 2.187 Flow resistance for 3 "-2" contraction in 3" piping section using equation 9. 6:

8 0.50x(l-/J2)x(sin ) 112 Kc 2 .

- /34 Where:

Kc= Flow resistance of 3"-2" contraction in 3" piping system fJ = Dl/D2 (Dl = 2.157" (smaller D), D2 =3.068" (larger D)) (0.703) 8 (sin )112 = Assigned the value of 1 for conservatism 2

8 0.50 x (1- /3 2 ) x (sin )111 K c -- /34 2

2 K .. = 0.50x(l-0.703 )xl c 0.703 4 Kc =1.035 Flow resistance for tee in the 3" piping section using equation 9.5:

Km:eJ") =60XfX1 Where:

K(n"> =Flow resistance of tee in the 3" piping system 1

f =Friction factor of the 3" piping system (0.018)

Calculation No. IP-CALC-13-00005 Rev. 1

• Page 24 of 33 K(Tee3") = 60x f K(Tee 3") = 60X0.018 K(Tee3") = 1.08 Total resistance through 3" piping section:

Kn .. = K 3 P + K90( 3 .> + K45(J"l +Kc+ K 1e* + K1860 Kn* =10.735 + 2.16 + 0.288+2.187+1.08+1.035 Kn . =17.485 For the 2" section:

- Length of piping is approximately 70 .318'.

- Number of 90° elbows is 6.

- Number of 45° elbows is 4.

- Valve 350-2" Rockwell Edwards, Y-Globe Valve.

Flow resistance for the 2" piping section using equation 9.2:

L K2p=fX-

. D Where:

K 2 P =Flow resistance of the 2" piping system f =Friction factor of the 2" piping system (0.019)

L =Length of the 2" piping system (70.318')

D =Diameter of the 2" pipe (0.18')

70318 K 2 =0.019x P 0.18 K2 P = 0.019x391.088 K 2P = 7.433 Flow resistance for 90° elbows in the 2" piping section using equation 9.3:

K90(n =30xfxN90 Where:

K90l 2"l =Flow resistance of 90° elbows in the 2" piping system f =Friction factor of the 2" piping system (0.019)

N90 =Number of 90° elbows in the 2" piping system (6)

Calculation No. IP-CALC-13-00005 Rev. 1 Page 25 of33 K90< 2") = 30x f x N90 K90cr) = 30x0.019x6 K90cr> = 3.420 Flow resistance for 45° elbows in-the 2" piping section using equation 9.4:

K45< 2"l = 16x f x N45 Where:

K45 06 .> =Flow resistance of 45° elbows in the 2" piping system f =Friction factor of the 2" piping system (0.019) ..,

N45 =Number of 45° elbows in the 2" piping system (4)

K45m =16xfxN45 K45< 2"> = 16x0.019x4 K45< 2..l = 1.216 Flow resistance for valve 350 in the 2" piping section using equation 9.9:

4 K _ 89lxD 3so - c2 v

Where:

I K 350 =Flow resistance of valve 350 in the 2" piping system

. Cv Coefficient = 70 (Reference 16)

D =Diameter (2.157")

4 K = 891XD 350 c2 v

4 K = 89lx2.l57 350 702 K 350 =3.936 Total resistance through 2" piping section:

Kn . = K 2P + K90< 2-> + K45cz"> + K 350 Kn*= 7.431+3.42+1.216+ 3.936 Kn . = 16.003

Calculation No. IP-CALC-13-00005 Rev. 1 Page 26of33 Calculate total flow resistance through 2" piping in terms of 3" piping using equation 9.10:

Where:

Kre 16* =Flow resistance of 2" total in terms of 3" piping system P= Dl/D2 (Dl = 2.157" (smaller D), D2 = 3.068" (larger D)) (0.703)

Kr2*

KTe3" =y K _ 16.003 Te3" - 0.7034 KTeJ" = 65 .505 Total resistance through entire piping section:

KT= KTe3" + KT3" + Ki11/e1 + Kexit KT = 65.505+17.485+0.5+1 KT =84.49

3. Calculate maximum flow through the combined 3" and 2" piping section using equation 9 .11:

2 H )11 Q 2 =19.65xv;. x ( KL Where:

Q2 = Flow in GPM D3.. = Diameter in terms of 3" pipe (3.068")

HL =Available Head due to elevation only (26.56')

K = Total resistance (84.49)

H )112 Q 2 =19.65xv;. x ( ;

x(

112 2 26 56 Q 2 =19.65x3.068 * )

84.49 Q2=103.701 o Based on the above flow rate, calculate the Reynolds Number using equation 9.12:

Re= 50.6xQxp i Dxµ

Calculation No. IP-CALC-13-00005 Rev.1 Page 27of33 Where:

Q =Flow in GPM D= Diameter (3.068" and 2.157")

p =Density in pound per cubic feet@ 120°F (61.71)

µ =Absolute viscosity in centepoise@ 120°F (0.56)

For the 3" section:

_ 50.6xQ 1 xp Re3" -

D 3.xµ R 50.6x103.701x61.71 e 3* = 3.068 x 0.56 Re 3.. =l.88E+05 At the above Reynolds No., friction factor is approximately equal to 0.028 for the 3" piping section as per figure A-25 of Reference (14). This number is greater than the assumed value of 0.018. Therefore, flow resistance of the piping system needs to be adjusted and re-computed using a friction factor of 0.028 for the 3" piping section instead of 0.018.

For the 2" section:

Re,, . = 50.6xQ 1 xp

• - Drxµ Re,, . = 50.6x103.701x61.71

- 2.157 x0.56 .

Rer = 2.68E + 05 At the above Reynolds No., friction factor is approximately equal to 0.027 for the 2" piping section as per figure A-25 of Reference (14). This number is greater than the assumed value of0.019. Therefore, flow resistance of the piping system needs to be adjusted and re-computed using a friction factor of 0.027 for the 2" piping section instead of 0.019.

o Adjust the calculated flow rate by going through the calculation steps using equations 9.2 through 9.11 adjusting the flow resistance through the system, where applicable, with the new friction factors based on the above determined Reynolds number:

For the 3" Pipe:

K3 r = 16.700 K90< 3.. ) = 3.36 K 45 0 .. l = 0.448 K 1860 = 2.187 Kc= 1.035 Kree = 1.68 Kn*= 25.41

Calculation No. IP-CALC-13-00005 Rev. 1 Page 28of33 For the 2" Pipe:

K 2 P = 10.562 K90<Z"> = 4.860 K 45 <Z"> = 1.728 K 350 = 3.936 Kn .. = 21.087 KTeJ" = 86.303 Kirrlet = 0.5 Kexir = 1.000 Kr= 113.213 The adjusted flow rate using the adjusted Kr is:

Q2 = 89.586 GPM o Minimum Technical Specifications indicated level is 36.83' (Reference 5 and 22 per SR 3.5.4.2).

o Current Low Level Alarm in the CCR set at 37.01' (Reference 15). At this level indication, with 936.81 gallons per 0.1 foot, there are about 1686.3 gallons of water over the minimum Technical Specifications available.

• Available time can be calculated using equation 9.13, which is equal to the available inventory (1686.3 gallons), based on the Low Level Alarm in the CCR, divided by the total loss rate through the postulated breaks for each scenario outlined in section 5.0. Total loss rate varies by the postulated time scenarios to isolate Segment 1 (For scenario detai.ls refer to section 5.0).

Note: Isolating Segment 1 involves the closure of valves 845 and 727A as well as tripping the Purification Pump if necessary (During circumstances that do not call for an SI signal). Isolation of Segment 2 involves

~~~~~ '

o Using equation 9.13, determine additional available time for levels above 37.0 l' for each of the postulated scenarios outlined in section 5.0. In order to determine the available time prior to reaching the Technical Specifications Minimum Water Level of 36.83', a water level in the RWST of 37 .65' (at Overflow Level) will be assumed to provide a higher HL when calculating Q 1 and Q 2

• Using a higher water level in the tank, Q1 and Q2 are adjusted to account for the difference in available head (HL), leading lo higher flowrates.

This will provide some additional head, leading to higher outflow rates of 123.9 gpm (instead of 122.8 gpm) for Ql at 37.01' level in the RWST and 91.0 gpm (instead of 89.5 gpm) for Q2 at 37.01' level in the RWST, which is overall conservative.

Available time is equal to available inventory (936.81 gallons per 0.1 foot) divided by the total loss rate in each postulated scenario. Tabulated results are as follows:

Calculation No. IP-CALC-13-00005 Rev.1 Page 29of33 Case A: Purification Pump in Operation Flowrate from Segment 1 in GPM (at Overflow Water Level): 180.0 Flowrate from Segment 2 in GPM (at Overflow Water Level): 91.0 Minimum Technical Specificaton level (ft): 36.83 Assumed Time to Isolate Segment 1 (minutes): 3 Available inventory (gallons) per 0.1': 936.81 Table 10.1 Tabulated Results of Scenario A Q 1- Flowrate Q2 - Flowrate Excess Water Calculated Total Initial Indicated Through Segment Through Segment Above Tech. Specs Time to TS Min.

RWST Level (FT) 1 (GPM) 2 (GPM) Limit (Gal) Level (Min) 37.65 180.0 91.0 7681.8 78.5 37.63 180.0 91.0 7494.5 76.5 37.53 180.0 91.0 6557.7 66.2 37.43 180.0 91.0 5620.9 55~9 37.33 180.0 91.0 4684.1 45.6 37.23 180.0 91.0 3747.2 35.3 37.13 180.0 91.0 2810.4 25.0 37.03 180.0 91.0 1873.6 14.7 37.01 180.0 91.0 1686.3 12.6 36.93 180.0 91.0 936.8 4.4 36.83 180.0 91.0 0.0 0.0 Case B: Purification Pump in Operation Flowrate from Segment 1 in GPM (at Overflow Water Level): 180.0 Flowrate from Segment 2 in GPM (at Overflow Water Level): 91.0 Minimum Teehnical Specificaton level (ft): 36.83 Assumed Time to Isolate Segment 1 {minutes): 5 Available inventory (gallons) per 0.1': 936.81 Table 10.2 Tabulated Results of Scenario B Q 1 - Flowrate Q 2 - Flowrate Excess Water Calculated Total Initial Indicated Through Segment Through Segment Above Tech. Specs Time to TS Min.

RWST Level (FT) 1*(GPM) 2(GPM) Limit (Gal) Level (Min) 37.65 180.0 91.0 7681.8 . 74.6 37.63 180.0 91;0 7494.5 72.5 37.53 180.0 91.0 6557.7 62.2 37.43 180.0 91.0 5620.9 51.9 37.33 180.0 91.0 4684.1 41.6 37.23 180.0 91.0 3747.2 31.3 37.13 180.0 91.0 2810.4 21.0 37.03 180.0 91.0 1873.6 10.7 37.01 180.0 91.0 1686.3 8.6 36.93 180.0 91.0 936.8 3.5

• 36.83 180.0 91.0 0.0 0.0

• At the given RWS,T Level, the ~alculated total time to Technical Specifications minimum level is less than the assumed 5 minutes allowed to isolate segment I.

Calculation No. IP-CALC-13-00005 Rev. 1 Page 30of33 Case C: All Three SI Pumps in Operation Flowrate from Segment 1 in GPM (at Overflow Water Level): 123.9 Flowrate from Segment 2 In GPM (at Overflow Water Level): 99.0 Minimum Technical Speciflcaton level (ft): 36.83 Assumed Time to Isolate Segment 1 (minutes): 3 Available inventory (gallons) per 0.1': 936.81 I

Table 10.4 Tabulated Results of Scenario C U1 - t'IOWrate "'2

• t'IOWrate Excess Water calculated Total Initial Indicated Through Segment Through Segment Above Tech. Specs Time to TS Min.

RWST Level CFn 1 (GPM) 2(GPM) Limit {Gal) Level {Min)

'37.65 123.9 99.0 7681.8 73.8 37.63 123.9 99.0 - 7494.5 71.9 37.53 123.9 99.0 6557.7 62.5 37.43 123.9 99.0 5620.9 53.0 37.33 123.9 99.0 4684.1 43.6 37.23 123.9 99.0 3747.2 34.1 37.13 123.9 99.0' 2810.4 24.6 37.03 123.9 99.0 1873.6 15.2

/

37.01 123.9 99.0 1686.3 13.3 36.93 123.9 99.0 936.8 5.7 36.83 - 123.9 99.0 0.0 0.0 Case D: All Three SI Pumps in Operation Flowrate from Segment 1 in GPM {at Overflow Water Level): 123.9 Flowrate from Segment 2 in GPM {at Overflow Water Level): 99.0 Minimum Technical SpecHlcaton level {ft): 36.83 Assumed Time to Isolate Segment 1 (minutes): 5 Available inventory {gallons) per 0.1': 936.81 Table 10.5 Tabulated Results of Scenario D 01 - Flowrate 0 2 - Flow rate Excess Water Calculated Total Initial Indicated Through Segment Through Segment Above Tech. Specs Time to TS Min.

RWST Level CFTl 1 CGPMl 2 (GPM) - Limit (Gal) Level (Min}

37.65 123.9 99.0 7681.8 71.3 37.63 123.9 99.0 7494.5 69.4 37.53 123.9 99.0 6557.7 60.0 37.43 123.9 99.0 5620.9 50.5 37.33 123.9 99.0 4684.1 41.1 37.23 123.9 99.0 3747.2 31.6 37.13 123.9 99.0 2810.4 22.1

. 37.03 123.9 99.0 1873.6 12.7 I

37.01 123.9 99.0 1686.3 10.8 36.93 123.9 99.0 936.8 4.2

• 36.83 123.9 99.0 o.o 0.0

• At the given RWST Level, the calculated total time to Technical Specifications minimum level is less than the assumed 5 minutes allowed to isolate segment I.

Calculation No. IP-CALC-13-00005 Rev.1 Page 31 of33 Case E: Purification Pump in Operation Flowrate from Segment 1 in GPM (at Overflow Water Level): 180.0 Flowrate from Segment 2 in GPM {at Overflow Water Level): 91.0 Minimum Technical Specificaton level (ft): 36.8 Assumed Time to Isolate Segment 1 (minutes): 10 Available inventory (gallons) per 0.1': 936.8 Table 10.7 Tabulated Reslilts of Scenario E 1- lowrate - owrate Excess Water Calculated Total Initial Indicated Through Segment Through Segment Above Tech. Specs Time to TS Min.

RWST Level FT 1 GPM 2 GPM Limit Gal Level Min 37.33 180.0 91.0 4684.1 31.7 Case F: All Three SI Pumps in Operation Flowrate from Segment 1 In GPM (at Overflow Water Level): 123.9 Flowrate from Segment 2 in GPM (at Overflow Water Level): 99.0 Minimum Technical Specificaton level (ft): 36.8 Assumed Time to Isolate Segment 1 (minutes): 10 Available inventory {gallons) per 0. 1': 936.8 Table 10.8 Tabulated Results of Scenario F 1- owra e 2- owra e Excess Water Calculated Total Initial Indicated Through Segment Through Segment Above Tech. Specs Time to TS Min.

RWST Level FT 1 GPM 2 GPM Limit Gal Level Min 37.33 123.9 99.0 4684.1 34.8 The maximum time available for each of the 6 scenarios outlined in section 5.0 based on the current 37 .01' (cases A through D) and 37.33' (cases E and F) log used for the Low Level Alarm in the CCR (Reference

15) are tabtilated below:

Table 10.7 Time to Reach TS Limits {Min} Based on Postulated Scenarios Safety Injection Assumed Time Remaining Postulated Pumps to Isolate Time to Isolate Scenario 0 s ment 1 s rnent 2 A 3.0 9.6 B No 5.0 3.6 c No Yes 3.0 10.3 D No Yes 5.0 5.8 E Yes No 10.0 21.7 F No Yes 10.0 24.8 Note: For the calculated flow rate in each scenario refer to Tables 10.1through10.6. The values in Table 10.7 are based on a minimum water level in the RWST defined in each scenario description in section 5.

Calculation No. IP-CALC-13-00005 Rev.1 Page 32 of33 11.0 References

1. Drawing 9321-F-2633, Rev. 38, "Nuclear Tank Farm Composite Piping".

2. Drawing 9321-F-2570, Rev. 73, "Primary Auxiliary Building Composite Piping Arrangement".

3. Drawing 9321-F-2580, Rev. 30, "Primary Auxiliary Building Composite Piping Arrangement Sections - Sheet No. 8".

4. Drawing IS0-253-A-2-1, Rev. 2, "Piping Isometrics - Line #252 + #253 Also Found Under Indian Point 2".

5. Entergy Calculation FIX-00096-:01, "RWST - Level Instrumentation Channel Accuracies, Calibration, and Setpoints".

6. Drawing 9321-F-2735, Rev.140, "Safety Injection System" UFSAR Figure No. 6.2-1 (Sht.1).

7. Drawing 9321-F-2736, Rev.129, "Chemical & Volume Control System- UFSAR },igure No. 9.2-1 (SHT.1)".

8. Drawing A227781, Rev. 82, "Auxiliary Coolant System - UFSAR Figure No. 9.3-1 (SHT.1)".

9. Entergy Specification 9321-01-248-18, Rev. 19, "FabriCation of Piping Systems~ Turbine Generator Plant".

10. Purchase Order No. 9-05664, Refueling Water Purification Pump #21.

11. Entergy Procedure 2-PT-Q029A, Rev. 24, "21 Safety Injection Pump".

12. Entergy Procedure 2-PT-Q029B, Rev. 20, "22 Safety Injection Pump".

13. Entergy Procedure 2-PT-Q029C, Rev. 21, "23 Safety Injection Pump".

14. Crane Technical Paper 410, 1982 Edition, "Flow of Fluid Through Valves, Fittings and Pipe".

15. Entergy Procedure 2-ARP-SBF-1, Rev. 41, "CCR Safeguards".

16. ITT Industries - Dia-Flo Industrial Diaphragm Valves Engineering Catalog*.

17. Drawing IP3V-354-0006, Rev. 3 "Stainless Steel Univalve Check Valve".

18. Vendor Manual 1775, Rev. 3, "Service Manual for Rockwell Edwards Univalves".

19. Entergy Calculation IP3-CALC-Sl-03333, Rev. 0, "Engineering Evaluation of postulated RWST Inventory Loss in Support of ACT 99-44077".

20. Entergy Report IP-RPT-09-00014, Rev. 1, "Critical Submergence Evaluations Related to Surface Vortices in Nuclear Safety and Augmented Quality Tanks/Pumps at IPEC".

21. ANSl/ASME Code B16.9, 1986 Edition, "Factory Made Wrought Steel Butt-welding Fittings".

22. Entergy Controlled Document - Technical Specifications, "Indian Point 2 Improved Technical Specifications"

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Sement Lea 1

Line 155 Diameter 16" 1' 811/16' length 1.724 Elevalioo 82'6" DirEdi on North'East Oass 00" Ellx:lws 45° 800\lls Contractions 151 1114"\ 0 1116"-14"l l->rnl'Y1Ar<:

0 Tees 0

Valves 118461 Purrp; 0

' urawina 9321-F-2633

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2 155 16" 41'05'8' 41.052 82'6" North/v\est 151 0 1 (16"\ 0 1116"-14"\ 0 0 0 9321-F-2633 ~

3 155 16" 2' 103'8" 2.665 82' 6" WfS. 151 1116'1 0 0 0 0 0 0 9321-F-2633 (1 4 155 16" 2'6 2.500 az 6'-76' er - 151 1116"\ 0 0 0 0 0 0 9321-F-2633 > ~

9321-F-2633 (1 5 155 16" 88'3' 88250 76'0' WfS. 151 0 0 0 0 0 0 0 9321-F-2570 I 1

9321-F-2580 '"I'""

(,H From RAISr to 2 Valve 6 183 2" a 1031a*

err 0.865 76' 8"-77 9 3'8" -*- 151 112'\ 0 0 0 0 0 0 9321-F-2580 9321-F-2580 > Q Q

725 7 183 2" 0.583 7793/ff' S'.JuthlEast 151 0 112"\ 0 0 0 0 0 ~ Q 8 183 2" 1' 2 518" 1.219 7793/ff' South 151 1(2'\ 0 0 0 0 0 0 9321-F-2580

~ Q s=-

9 183 2 2' 33'8' 2.281 7793/8"*75' - 151 112'\ 0 0 0 0 0 0 9321-F-2580 (Ii 10 183 2" 2"

11' 10112

2/ 10" 11.875 75' South 151 1121 0 0 0 0 11845\ 0 9321-F-2580 9321-F-2580 rtl ~

11 12 183 183' 2' 2'3' 3.833 2.250 75'-00 6" 69' 6"*71' WfS.

151 151 112"\

212'\

0 0

0 0

0 0

0 0

11727A\

0 0

1 9321-F-2580 =...... ~

13 135 2 1' 1" 1.083 71' South 151 0 0 a ,()*' 0 2trd:il\& r.!!>J 0 9321-F-2580  !':" '"'""

Total Lena n of Straiom nipe

• 16" 136' 411116" 23' 117/8" 136.391 3* 1 1 1 0 1

~

Total Lenath of Straight Dlce-2"

'14"EIOOW 23.990 7 1 0 0 0 4

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• • 1-2" Exi;ender ass lined to be part d purification purr-p. Resistanre is negla:ted for cooseivalisrn r:r.i rtl (JQ Segment Lea Line Diarreter Lergth Elevalioo DirEdioo Oass 00" Ellx:lws 45" Ellx:lws Contractions Elq::aiders Tees . Valves Punm lJraWing s

~

1 2

161 161 3"

3"

'J71iZ' 36' 71/2

9.625 36.625 83' 3"-93' 3' 83' 3*

North'East 151 151 1 (3"1 0

0 0

0 0

0 0

0 0

0 0

0 0

9321-J-*2633 9321*J--2trn =

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3 161 3" 2' 111/16" 2.141 83'3' North'East 151 1 (3") 0 0 0 0 1 (1800) 0 9321-F-2633 ('D 4 161 3" 4261/8" 42.510 83'3" North/V\est 151 0 1 (3") 0 0 0 0 0 9321-F-2633 (JQ 5 161 3" f3 271W 5.240 83'3" WeS. 151 1 (3") 0 0 0 0 0 0 9321-F-2634 ......

6 161 3' 6' 211/16" 6.224 76' 6"*83' 3" *-- 151 1 (3") 0 0 0 0 0 0 9321-F-2635 =

~

2 9321-F-2633 From RAISr 7 161 3" flJ 11/2 50.125 76' 6" WeS. 151 0 0 1 (3"*2') 0 1 0 0 9321-F-2570 ""

9

~

to2"~ind Flange Past Val\350 8

9 10 253 253 253 2'

2" 2'

(]7518" 32 51/4" 2' 1 ~16' 0.635 32.438 2.130 776"-77 77 77 North North f'b1hMest 151 151 151 0

0 0

1 (2')

1 (2')

1 (2")

0 0

0 0

0 0

0 0

0 0

0 0

0 0

0 IID253-A-2-1 IID253-A-2-1 IID253-A*2-1

-*=

c 11 253 2 2105'8" 2.665 77 North 151 1 (2) 1(2'~ 0 0 0 0 0 IS).253-A-2-1 12 253 2." Cf 7' 0.583 77-94'6" --- 151 1 (2) 0 0 0 0 0 0 IS0.253-A-2-1 13 253 2" 1'3' 1.250 94'6" North 151 1 (2") 0 0 0 0 0 0 IS0.253-A-2-1 14 253 *2' 24'6" 24.500 94'6' Ba 151 1 (2") 0 0 0 0 0 0 IS0.253-A-2-1 15 253 2" 4'6" 4.500 94' 6"*006" - 151 1 (2") 0 0 0 0 0 0 IS0.253-A-2-1 16 253252 2" 1' 43'4" 1.300 006" South 151 1 (2") 0 0 0 0 1 (350) 0 IID253-A-2-1 looC

~

Total Len01111 ofSraiantoioe-3" 152' 51/8" 152.490 4 1 1 0 1 1 Total Lenath of Sraiaht Dice- 2" 7fJ 31l'16" 70.318 6 4 0 0 ' 0 1 ~

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