ML13116A008

Engineering Evaluation of Postulated RWST Inventory Loss During the Reverse Osmosis Clean-up Skid Process in Accordance to 2-TAP-001-ROS Due to Seismic Event

ML13116A008
Person / Time
Site:	Indian Point
Issue date:	04/09/2013
From:	Entergy Nuclear Northeast
To:	Office of Nuclear Reactor Regulation
References
Download: ML13116A008 (33)

Text

ATTACHMENT 9.2 ENGINEERING CALCULATION COVER PAGE Sheet I of I El ANO-1 l ANO-2 El GGNS 0 IP-2

[] IP-3 El PLP El JAF El PNPS

[E RBS El VY El W3 El NP-GGNS-3 El NP-RBS-3 CALCULATION EC # 43679 Page 1 of 33 COVER PAGE Design Basis Calc. [-j YES

[0 NO

[*CALCULATION

[-l EC Markup Calculation No: IP-CALC-13-00005 Revision: 1

Title:

Engineering Evaluation of Postulated RWST Inventory Loss During Editorial the Reverse Osmosis Clean-up Skid Process in Accordance to 2-TAP-001-L-YES Z NO ROS due to a Seismic Event System(s): SI, CVCS and SFPC Review Org (Department):

Design Engineering - Mechanical Safety Class:

Component/Equipment/Structure Type/Number:

N Safety / Quality Related Unit 2 RWST Valve 845 L-Augmented Quality Program LNo-aeyRltdUnit 2 PAB Valve 350 r--] Non-Safety Related 21 Refueling Water Purification Pump Document Type: Calculation Keywords (Description/Topical Codes):

RWST Drain Down, Seismic, 2-TAP-001-ROS REVIEWS Name/Signature/Date Na ne/Signature/Date Nare/Sign a~ure/Dape-cL a4ridis

.i, 1

Alfieri, 1

1

ý

-~ V. Myers W

Responsible Engineer

[

Design erifier Supervisor/Approval I-1 Reviewer E-"L Comments Attached Q-Comments Attached

Calculation No. IP-CALC-13-00005 Rev. 1 Page 2 of 33 ATTACHMENT 9.3 CALCULATION REFERENCE SHEET Sheet I of I CALCULATION CALCULATION NO: IP-CALC-13-00005 REFERENCE SHEET REVISION: 1 I. EC Markups Incorporated (N/A to NP calculations)

1. EC 42176 2.

3.

4.

5.

II. Relationships:

Sht Rev Input Output Impact Tracking Doc Doc Y/N No.

1. Entergy Calculation FIX-00096, 1

0 0

"RWST - Level Instrumentation Channel Accuracies, Calibration, and Setpoints".

2. Entergy Report IP-RPT-09-00014, 1

EI "Critical Submergence Evaluations Related to Surface Vortices in Nuclear Safety and Augmented Quality Tanks/Pumps at IPEC".

3.

[3

[3

4.

0 0

5.

0 0_

III.

CROSS

REFERENCES:

1. See Section 11.0 of this calculation.

2.

3.

4.

5.

IV.

SOFTWARE USED:

Title:

None Version/Release:

Disk/CD No.

V.

DISK/CDS INCLUDED:

Title:

None Version/Release Disk/CD No.

VI.

OTHER CHANGES:

Calculation No. IP-CALC-13-00005 Rev. 1 Page 3 of 33 ATSACHMENT 9.4 RECORD OF REVISION Sheet 1 of 1 Revis:io

-rd of; Re..ision Initial issue of calculation IP-CALC-13-00005.

0 Issue of calculation IP-CALC-13-00005 Rev. 1. Revision includes the replacement of 2 postulated scenarios with 2 others as well as a number of 1

editorial comments for clarification purposes. It also included the correction of a typographical error in section 9.0 Eq. 9.13, and in Section 10, the Tables were changed to show decreasing RWST level.

4 i

Calculation No. IP-CALC-13-00005 Rev. 1 Page 4 of 33 4.0 Table of Contents 1.0 Calculation Cover Sheet 1

2.0 Calculation Reference Sheet 2

3.0 Record of Revision 3

4.0 Table of Contents 4

5.0 Purpose 5

6.0 Conclusion 6

7.0 Inputs and Design Criteria 6

8.0 Assumptions 8

9.0 Method of Analysis 8

10.0 Calculations 12 11.0 References 32 12.0 Attachments 33 12.1 Attachment 1 - Line Segment/Leg Information (1 Page).

Calculation No. IP-CALC-13-00005 Rev. 1 Page 5 of 33 5.0 Purpose

Background

During steps outlined in procedure 2-TAP-001-ROS, "Installation/Removal of the Reverse Osmosis Silica Clean-up Skid", temporary hoses/connections are installed in order to run the Unit 2 Osmosis Silica Clean-up Skid. The installation of the Reverse Osmosis Skid to Valve 725 (line #135) and to the flange downstream of valve 350 (line #253/252) creates an interface between seismic and non-seismic lines. These connections create new established pressure boundaries to the system as a whole during the operation of the Reverse Osmosis Skid.

Objective The objective of this calculation is to determine maximum flow through a break at the seismic/non-seismic boundaries at valve 725 (line # 135) and at the flange downstream of valve 350 (line #253/252), and the time available prior to reaching the minimum Refueling Water Storage Tank Technical Specifications water level limit of 36.83' (Reference 5 and 22 per SR 3.5.4.2), based on the minimum and maximum water level that could be stored in the RWST (Overflow level is 37.65', Reference 5). Revision 1 includes cases E and F which require that the Low Level Alarm in the CCR be manipulated for the duration of operation for this purification skid. Also after conversations with Licensing and Operations, and based on Operations experience, it was decided that the objective of this calculation should be considered for each of the following 6 scenarios:

A. The Low Level Alarm in the CCR is set at 37.01. The rupture occurs during circumstances that do not call for an SI signal, in which case the purification pump is in operation and the assumed operator time to respond and isolate Segment 1 is 3 minutes.

B. The Low Level Alarm in the CCR is set at 37.01. The rupture occurs during circumstances that do not call for an SI signal, in which case the purification pump is in operation and the assumed operator time to respond and isolate Segment 1 is 5 minutes.

C. The Low Level Alarm in the CCR is set at 37.01. The rupture occurs during circumstances that call for an SI signal, in which case the purification pump will be stripped out of operation, all three SI pumps are assumed to be operating and the assumed operator time to respond and isolate Segment 1 is 3 minutes.

D. The Low Level Alarm in the CCR is set at 37.01. The rupture occurs during circumstances that call for an SI signal, in which case the purification pump will be stripped out of operation, all three SI pumps are assumed to be operating and the assumed operator time to respond and isolate Segment 1 is 5 minutes.

E. The Low Level Alarm in the CCR is changed to 37.33 for the duration of the Purification Skid. The rupture occurs during circumstances that do not call for an SI signal, in which case the purification pump is in operation and the assumed operator time to respond and isolate Segment 1 is 10 minutes.

F. The Low Level Alarm in the CCR is changed to 37.33 for the duration of the Purification Skid. The rupture occurs during circumstances that call for an SI signal, in which case the purification pump will be stripped out of operation, all three SI pumps are assumed to be operating and the assumed operator time to respond and isolate Segment 1 is 10 minutes.

Note: Isolating Segment 1 involves the closure of valves 845 and 727A as well as tripping the Purification Pump if necessary (During circumstances that do not callfor an SI signal). Isolation of Segment 2 involves closing valve 350.

Calculation No. IP-CALC-13-00005 Rev. 1 Page 6 of 33 6.0 Conclusion The maximum time available prior to reaching the minimum RWST TS water level limits during a postulated break at the seismic/non-seismic boundaries at valve 725 (line # 135) and at the flange downstream of valve 350 (line #253/252) has been calculated for 6 different scenarios. Scenarios during circumstances that do not call for an SI signal result in less time available for operator action. The maximum time available for scenarios A through F as outlined in section 5.0 are tabulated below:

Table 6.1 Time to Reach TS Limits (Min) Based on Postulated Scenarios Purification SafetyInjection Assumed Time Remaining Postulated Pump Pumps to Isolate Time to Isolate Scenario Operating Operating Segment I Segment 2 A

Yes No 3.0 9.6 B

Yes No 5.0 3.6 C

No Yes 3.0 10.3 D

No Yes 5.0 5.8 E

Yes No 10.0 21.7 F

No Yes 10.0 24.8 Note: For the calculated flow rate in each scenario refer to Tables 10.1 through 10.6. The values in Table 6.1 are based on a minimum water level in the RWST defined in each scenario description in section 5.

While the Table above demonstrates timing for specific RWST initial levels, the Tables in Section 10 demonstrate a wider range of RWST initial levels and isolation times for Segment 1 and Segment 2.

7.0 Inputs and Design Criteria Design Basis

1. Throughout this calculation, the paths from the RWST to each postulated break point are identified as follow:

a. Segment 1 begins at the 16" suction line from the RWST (line #155), through the 2" line leading to the Refueling Water Purification Pump (line #183), past the Refueling Water Purification Pump #21 through the 2" line and break point downstream of valve 725 (line #135) (Reference 1, 2, and 3).

b. Segment 2 begins at the 3" discharge line into the RWST (line #161), through the 2" line leading to the Boric Acid Blender in the CVCS (line #253), past valve 350 to the flange at the 2" line and break point downstream of valve 350 (line #252) (Reference 1 and 4).

2. The lengths of the Safety Injection and Auxiliary Coolant lines #155 (16"), #183 (2") and #135 (2") as well as the Safety Injection and Chemical Volume Control System lines #161 (3") and #253 and #252 (2") (Reference 1, 2, 3 and 4), are documented in the summary tables in Attachment 1.

3. The number of fittings and components in the flow path of the Safety Injection and Auxiliary Coolant lines #155 (16"), #183 (2") and #135 (2") as well as the Safety Injection and Chemical and Volume Control System lines #161 (3") and #253 and #252 (2") (Reference 1, 2, 3 and 4), are documented in the summary tables in Attachment 1.

Calculation No. IP-CALC-13-00005 Rev. 1 Page 7 of 33

4. The minimum water level in the RWST is 36.83', which was calculated based on the minimum water volume stated in the Surveillance Requirements of section 3.5.4 of the Unit 2 Technical Specifications (Reference 5 and 22).

5. The current RWST Low Level Alarm in the CCR is 37.01' and the RWST overflow level is 37.65' (Reference 15).

6. The elevations of the tanks outlet nozzle into line #155 is 82.5' and the elevation of the inlet nozzle into the tank from line #161 is 93.25' (Reference 1).

7. The elevations of the assumed breaks in the 2" lines (#135 and #253) at the seismic/non-seismic connections just downstream of valve 725 is 71.0' and the blind flange upstream of valve 350 is 99.5' (Reference 3 and 4 respectively).

8. The available minimum water inventory of 9368.1 gallons per 1 foot of height in the RWST (Reference 20).

9. All piping is Class 151R per Reference 6, 7, and 8. Per Specification in Reference 9, the 2" pipe can be schedule 10S or 40S (Stainless Steel) and the 3" pipe is schedule 40S (Stainless Steel). Per Reference 9 and 14, piping wall thickness and diameter for 16" pipe is 0.25" and 15.5" respectively, schedule 40S piping wall thickness and diameter for 3" pipe is 0.216" and 3.068" respectively, and schedule 10S (chosen for conservatism over 40S since this would lower the effective resistance through the pipe) piping wall thickness and diameter for 2" pipe is 0.109" and 2.157" respectively.

10. Rupture of the piping downstream of the purification pump #21 should be considered in this calculation as follows:

a. If the rupture occurs during circumstances that do not call for an SI signal, in which case the pump is in operation, then the maximum calculated flow through the rupture is governed by the pump runout flow of 180 GPM (Reference 10).

b. If the rupture occurs during circumstances that call for an SI signal, in which case the pump will be stripped out of operation, then the maximum calculated flow through the rupture via gravity drain will be used to determine available time to reach the RWST TS minimum required limit.

11. Rupture of the piping downstream of valve 350 (line #253/252) should be considered in this calculation as follows:

a. If the rupture occurs during circumstances that call for an SI signal, then the maximum calculated flow through the rupture is governed by the maximum recirculation flow from all three SI Pumps (for conservatism) of 99 GPM (Reference 11, 12 and 13).

b. If the rupture occurs during circumstances that do not call for an SI signal, then the maximum calculated flow through the rupture via gravity drain will be used to determine available time to reach the RWST TS minimum required limit.

12. Line break is conservatively assumed to be a fully "guillotine break" in the seismic/non-seismic connections immediately downstream of valve 725 and the flange upstream of valve 350. This is conservative, since this is a low pressure line and a smaller break or leak is more probable.

13. Pressure loss through the purification pump #21 (when the pump is not in operation) is not accounted for in this calculation. This is conservative, since the additional pressure loss would increase the available time.

Calculation No. IP-CALC-13-00005 Rev. 1 Page 8 of 33

14. Per Pipe Friction Data, A-26 in Reference 14, initial pipe friction factors for the affected piping sections are listed below:

a. 2" Pipe,fT= 0.019 (Segment 1 and 2)

b. 3" Pipe,fT= 0.018 (Segment 2)

c. 12-16"Pipe,fT=0.013 (Segment 1)

15. Pipe friction factors for the affected piping sections which are determined using the calculated Reynolds number and Friction Factor graphic A-25 in Reference 14 are the adjusted friction factors. The adjusted friction factors for the affected piping sections are listed below:

a. 2" Pipe,fT = 0.026 (Segment 1),fT = 0.027 (Segment 2)

b. 3" Pipe, fT = 0.028 (Segment 2)

c. 12-16" Pipe,fT=0.018 (Segment 1)

16. Water density and viscosity for this system is assumed to be at about 120'F with values of 61.71 pounds per cubic foot and 0.56 centipoise respectively (Reference 14).

17. Flow coefficients for each valve in the system (Reference 17 and 18; the Unit 3 drawing for reference 17 is also applicable for the same type of valves in Unit 2):

a. Valve 845, Cv = 60

b. Valve 727A, Cv = 60

c. Valve 726A, Cv =60

d. Valve 1860, Cv = 190

e. Valve 350, Cv = 70

18. In some cases, calculating the flow resistance through a fitting can be achieved from multiple equations depending on certain parameters. In such cases, the most conservative parameters are assumed in order to lead to the equation that is the most conservative overall (Reference 14).

Refer to section 11.0 for a complete list of references used in this calculation.

8.0 Assumptions None.

9.0 Method of Analysis The following approach has been used in performing this calculation:

a. Determine potential flow through identified lines leading to postulated break points at the seismic/non-seismic boundaries at valve 725 (line # 135) and at the flange downstream of valve 350 (line #252).

The first step in this process is to identify and calculate the available head that will determine the flow through the postulated breaks, which is a result of the differential pressure produced by the level in the RWST and the break locations. The equation used to calculate available head (Reference 14) is as follows:

HL-hR

- hBreak (9.1)

Calculation No. IP-CALC-13-00005 Rev. 1 Page 9 of 33 Where:

HL = Available Head (ft) hRWST = Elevation of level in the RWST (ft) hBreak = Elevation of break in the system (ft)

Once the available head has been determined, calculate the resistance losses through the straight length of pipe, fittings and components. The resistance loss through the straight length of piping in the system was determined using equation 9.2 (Reference 14):

KP =f x L (9.2)

D Where:

KP = Flow resistance of the piping system f = Friction factor of the piping system based on the pipe diameter L = Length of the piping system (ft)

D = Diameter of the pipe (ft)

The resistance losses through the 90' elbows in the piping system were determined using equation 9.3 (Reference 14):

K90 = 30 x f x N90 (9.3)

Where:

K90 = Flow resistance of the 90' elbow in the piping system f = Friction factor of the piping system based on the pipe diameter N90 = Number of 90' elbow in the piping system The resistance losses through the 450 elbows in the piping system were determined using equation 9.4 (Reference 14):

K45 = 16xf xN45 (9.4)

Where:

K45 = Flow resistance of the 45' elbow in the piping system f = Friction factor of the piping system based on the pipe diameter N45 = Number of 45° elbow in the piping system The resistance losses through a tee in the piping system were determined using equation 9.5 (Reference 14):

KT =60xf (9.5)

Where:

KT= Flow resistance of a tee in the piping system f = Friction factor of the piping system based on the pipe diameter The resistance losses through contractions and expansions in the piping system were determined using equation 9.6 and 9.7 respectively (Reference 14):

Calculation No. IP-CALC-13-00005 Rev. 1 Page 10 of 33 0.50x (1- /f2)X xsin

)(9.6)

KC =

fl4 2(96 KE- (1-,82)2 Where:

Kc = Flow resistance of the contraction in the piping system KE = Flow resistance of the expansion in the piping system

,8 = D1/D2 (Dl = smaller D, D2 = larger D)

(sin-) 2 = Assigned the value of 1 for conservatism.

2 The resistance loss through a fully open gate valve in the piping system was determined using equation 9.8 (Reference 14):

KGateVve = 8 x f x NGateVWlve (9.8)

Where:

KGa*eValve = Flow resistance through a fully open gate valve in the piping system f = Friction factor of the piping system based on the pipe diameter NGateValve = Number of fully open gate valves in the piping system The resistance loss through other fully open valves in the piping system was determined using equation 9.9 (Reference 14):

891xD4 Kvave =

(9.9)

CV Where:

KVatve = Flow resistance through a fully open valve in the piping system D = Diameter of the piping system (ft)

Cv= Flow Coefficient for each valve The resistance loss through a pipe entrance/inlet ( Kp, ) and a pipe exit ( KpE) in the piping system is 0.5 and 1 respectively (Reference 14).

When a piping system contains more than one size of pipe, valves and fittings, all resistances should be expressed in terms of one size. The resistance loss for sudden enlargements and contractions expressed in terms of the large pipe was determined using equation 9.10 (Reference 14):

K2 p4 (9.10)

Where:

K2 = Flow resistance in terms of the larger pipe diameter K1 = Flow resistance calculated based on actual pipe diameter

Calculation No. IP-CALC-13-00005 Rev. 1 Page 11 of 33

[= D1I/D2 (D1 = smaller D, D2 = larger D)

b. Once the total resistance is calculated, KT, it is used to determine the maximum flow rate through the piping system. The maximum flow rate through a piping system was determined using equation 9.11 (Reference 14):

Q = 19.65xD 2 xKT (9.11)

Where:

Q = Maximum flow rate through the piping system (GPM)

KT = Total flow resistance calculated through the piping system HL = Available Head (ft)

D = Diameter of the piping system (inches)

c. Calculate Reynolds number based on determined flow rates.

Using the maximum flow rate calculated, the Reynolds number can be determined using equation 9.12 (Reference 14):

Re = 50.6xQxp (9.12)

Dxp Where:

Re = Reynolds number based on calculated flow rate Q = Maximum flow rate through the piping system (GPM) p = Density in pounds per cubic feet @ 120'F

1. = Viscosity in centipoise @ 120'F D = Diameter of the piping system (inches)

d. Adjust the flow rate as necessary based on the calculated Reynolds number. The Reynolds number calculated above allows us to determine a more accurate Friction factor for this system. Using graphic A-25 in Reference 14, a more accurate friction factor for each piping segment (depending on the pipe diameter) is determined. Using those adjusted friction factors; equations 9.2 through 9.11 will be adjusted as necessary to re-calculate a more accurate maximum flow rate.

e. Using the calculated maximum flow rate (Equation 9.11), determine the available time prior to reaching Technical Specifications limit of 36.83' from assumed RWST alarm levels of 37.01' or 37.33' (based on available inventory of 9368.1 gallons of water per foot of height in the RWST, Reference 15) for each of the 6 scenarios outlined in section 5. In order to determine the available time prior to reaching the Technical Specifications Minimum Water Level of 36.83', a water level in the RWST of 37.65' (at Overflow Level) will be assumed to provide a higher HL when calculating Q, and Q2. Using a higher water level in the tank, Q, and Q2 are adjusted to account for the difference in available head (HL), leading to higher flowrates.

This will provide some additional head, leading to higher outflow rates of 123.9 gpm (instead of 122.8 gpm) for Q, at 37.01' level in the RWST and 91.0 gpm (instead of 89.5 gpm) for Q2 at 37.01' level in the RWST, which is overall conservative. The available time prior to reaching Technical Specifications limit of 36.83' can be calculated using equation 9.13:

Calculation No. IP-CALC-13-00005 Rev. 1 Page 12 of 33 TM. =-

(9.13)

Q1 + Q2 Where:

TMo* = Time available prior to reaching TS limit based on calculated flow rates (Min)

Q, = Maximum flow rate through segment 1 (GPM)

Q2= Maximum flow rate through segment 2 (GPM)

VRwsr = Volume in the RWST based on water level (Gallons)

Note: After isolating segment 1, Q, goes to zero.

f. Determine additional available time, if the initial level in the RWST is higher than 37.01' or 37.33' (Reference 15). In order to determine the available time prior to reaching the Technical Specifications Minimum Water Level of 36.83', a water level in the RWST of 37.65' (at Overflow Level) will be assumed to provide a higher HL when calculating Q, and Q2. Using a higher water level in the tank, Q, and Q2 are adjusted to account for the difference in available head (HL), leading to higher flowrates. This will provide some additional head, leading to higher outflow rates of 123.9 gpm (instead of 122.8 gpm) for Q1 at 37.01' level in the RWST and 91.0 gpm (instead of 89.5 gpm) for Q2 at 37.01' level in the RWST, which is overall conservative.

10.0 Calculations o Determine the maximum flow rate through the break downstream of valve 725 (line #135):

Available head that determines the flow through the break in the 2" line downstream of valve 725 (line

1. 135), is the result of the differential pressure produced by the level in the RWST and the break location.

1. Available head to drive flow through Segment 1 at the 2" line break from the RWST is as follows:

a. The RWST Minimum Limit Technical Specification level is 36.83' tank level (this includes an allowance for instrument uncertainty of 2.65'). The minimum log reading is 37.01' currently used for the RWST Low Level Alarm in the CCR according to procedure 2-ARP-SBF-1.

b. This equates to an elevation of 118.06' with the tank bottom being at elevation of 81.05'.

c. The break point downstream of valve 725 is at elevation 71' (Segment 1).

d. Therefore, using equation 9.1, at Minimum Limit Technical Specification level, available head through each break is:

HLI = Min. RWST Level Elevation (ft) - Break Point Elevation (ft)

HLI = 118.06' - 71' HLI = 47.06'

2. Determine the flow resistance for the various components within the 16" and 2" lines from the piping isometrics (Reference 1, 3 and 4) and formulas from Crane (Reference 14).

For the 16" section:

Calculation No. IP-CALC-13-00005 Rev. 1 Page 13 of 33 Length of piping is approximately 136.4'.

Number of 900 elbows is 3 (including one 14" elbow and two 16" elbows).

Number of 450 elbows is 1.

16" to 14" contraction.

14" to 16" expansion.

Valve 846 - 14" Anchor Darling Gate Valve.

Flow resistance for the 16" piping section using equation 9.2:

L K16p = f x-D Where:

K6p

= Flow resistance of the 16" piping system f = Friction factor of the 16" piping system (0.013)

L = Length of the 16" piping system (136.4')

D = Diameter of the 16" pipe in feet (15.5"/12" = 1.292')

Kl6, = 0.013x 13 6. 4 1.292 K,6p= 0.013x105.593 K 16p = 1.373 Flow resistance for 90' elbows in the 16" piping section using equation 9.3:

K90(16-) =30 x f x N90 Where:

K90(16-) = Flow resistance of 90' elbows in the 16" piping system f = Friction factor of the 12"-16" piping system (0.013)

N90 = Number of 90' elbows in the 16" piping system (2)

K90(,6.) = 30x f x N90 K90(,6.) =30x0.013x2 K90(16.) = 0.78 K90(,4-) =30 x f x N90 Where:

K90(,4-) = Flow resistance of 90° elbows in the 14" portion of the piping system f = Friction factor of the 12"-16" piping system (0.013)

N90 = Number of 90' elbows in the 16" piping system (1)

Calculation No. IP-CALC-13-00005 Rev. 1 Page 14 of 33 K90(1 4.) =30xf xN90 K90(1 4.) = 30x0.013x1 K90(14.) = 0.39 Calculate K90( 4.-) in terms of 16" piping using equation 9.10:

K90(e 1

6") = K90(1 4.)

J#4 Where:

K90(el6") = Flow resistance of 14" 900 elbow in terms of 16" piping K90(14.) = Flow resistance of 90' elbows in the 14" portion of the piping system (0.390) f8 = D1/D2 (D1 = 13.5" (smaller D), D2 = 15.5" (larger D)) (0.87097)

K90(14-)

K90(e06") =

4 0.39 K90(eI.) = (0.87097)4 K90(el 6.) =0.678 Flow resistance for 450 elbows in the 16" piping section using equation 9.4:

K45(,6-) =16xfxN45 Where:

K45(1.) = Flow resistance of 450 elbows in the 16" piping system f = Friction factor of the 12"-16" piping system (0.013)

N45 = Number of 45' elbows in the 16" piping system (1)

K45(,6.) =16x f x N45 K45(,6.) = 16x0.013xl K45(16.) = 0.208 Flow resistance for 16"-14" contraction in 16" piping section using equation 9.6:

0.50 x (1Q-

_P2) x (sin

)112 Kc =

f184 2.

Where:

Kc = Flow resistance of 16"-14" contraction in 16" piping system

,8 = D1/D2 (DI = 13.5" (smaller D), D2 = 15.5" (larger D)) (0.87097)

Calculation No. IP-CALC-13-00005 Rev. 1 Page 15 of 33

/9 (sin-))"2 = Assigned the value of 1 for conservatism 2

0.50 x (1- _2

) x (sin 0) 112 K -

21 0.50x (1- 0.87097 2 )xl C

0.870974 Kc = 0.210 Flow resistance for 14"-16" expansion in 16" piping section using equation 9.77:

S(1-fl 2 )2 KE

)6 4 Where:

KE = Flow resistance of 14"-16" expansion in 16" piping system

,8 = D1/D2 (D1 = 13.5" (smaller D), D2 = 15.5" (larger D)) (0.87097)

KE = (1-fl2 ) 2 (1-0.870972)2 KE =

0.870974 KE = 0.101 Flow resistance for valve 846 in the 16" piping section using equation 9.8:

K 846 =8xfxi Where:

K846 = Flow resistance of valve 846 in the 16" piping system f = Friction factor of the 12"-16" piping system (0.013)

K 846 =8xf K 846 =8x0.013 K846 = 0.104 Total resistance through 16" piping section KT16" =KI6p+ K90(16.) + K90(el 6") + K45( 6.) + Kc + KE + K846 KT16. = 1.373+0.678+0.78+0.208+0.210+0.101+0.104 KT16. = 3.453

Calculation No. IP-CALC-13-00005 Rev. 1 Page 16 of 33 For the 2" section:

Length of piping is approximately 24.0'.

Number of 900 elbows is 7.

Number of 450 elbows is 1.

Valve 845 - 2" Rockwell Edwards, Y-Globe Valve.

Valve 727A - 2" Rockwell Edwards, Y-Globe Valve.

Valve 726A - 2" Check Valve Valve 725 - 2" Grinnell Saunders, Diaphragm Valve.

Flow resistance for the 2" piping section using equation 9.2:

K2~

L K2p =fx-L D

Where:

K2p = Flow resistance of the 2" piping system f = Friction factor of the 2" piping system (0.019)

L = Length of the 2" piping system (23.990')

D = Diameter of the 2" pipe (0.180')

K 2p =0.019x 2 3 9 9 0 0.180 K 2p = 0.019x133.424 K2p =2.535 Flow resistance for 900 elbows in the 2" piping section using equation 9.3:

K90(2..) =30xf xN90 Where:

K90(.4) = Flow resistance of 90' elbows in the 2" piping system f = Friction factor of the 2" piping system (0.019)

N90 = Number of 90' elbows in the 2" piping system (7)

K90(2.) =30xf xN90 K90(2.) =30x0.019x7 K90(2.) = 3.990 Flow resistance for 45' elbows in the 2" piping section using equation 9.4:

K45(2.) =16xfxN45 Where:

K45(16.) = Flow resistance of 450 elbows in the 2" piping system

Calculation No. IP-CALC-13-00005 Rev. 1 Page 17 of 33 f = Friction factor of the 2" piping system (0.019)

N45 = Number of 45' elbows in the 2" piping system (1)

K45(2.) =16xfxN45 K45(2') =16x0.019xl K45(2.) = 0.304 Flow resistance for valve 845 in the 2" piping section using equation 9.9:

891xD 4

K845 --

C2 Where:

K845 = Flow resistance of valve 845 in the 2" piping system Cv Coefficient = 60 (Reference 18)

D = Diameter (2.157")

891xD 4 K 845 =

2 891x2.157 4 K845 =

602 K 845 = 5.358 Flow resistance for valve 727A in the 2" piping section using equation 9.9:

891xD 4

K 727A "V2 Where:

K 727a = Flow resistance of valve 727A in the 2" piping system Cv Coefficient = 60 (Reference 18)

D = Diameter (2.157")

891 xD 4 K 7 27A =

c2 891x2.157 4

K 7 27A =

602 K 7 27A =5.358 Flow resistance for valve 726A in the 2" piping section using equation 9.9:

Calculation No. IP-CALC-13-00005 Rev. 1 Page 18 of 33 891 xD 4 K 7 26A 89 2

Where:

K 727A -- Flow resistance of valve 726A in the 2" piping system Cv Coefficient = 60 (Reference 17; the Unit 3 drawing for reference 17 is also applicable for the same type of valves in Unit 2)

D = Diameter (2.157")

891xD 4

K726A --

c2 891x2.157 4

K726A =

602 K726A = 5.358 Flow resistance for valve 725 in the 2" piping section using equation 9.3:

K 725 =30xf xN90 Where:

K725 = Flow resistance of valve 725 in the 2" piping system f = Friction factor of the 2" piping system (0.019)

K725 =30xfxN90 K725 =30x0.019x1 K725 = 0.570 Note: During this process, the internals of valve 725 are removed and a hose is connected, and considering the shape of valves internals, the valve is assumed to behave like a 900 elbow in the system.

Total resistance through 2" piping section:

KT 2. - K 2p + K90(2.) + K45(2.) + K845 + K 727A + K 726A + K 725 KT2. = 2.535 + 3.990 + 0.304 + 5.358 + 5.358 + 5.358 + 0.570 KT 2. = 23.473 Calculate K. 2. in terms of 16" piping using equation 9.10:

Ke6-KT2" KTeI6"~ = KP 4 Where:

Calculation No. IP-CALC-13-00005 Rev. 1 Page 19 of 33 Kge 6,. -: Flow resistance of 2" total in terms of 16" piping system fi = D1/D2 (D1 = 2.157" (smaller D), D2 = 15.5" (larger D)) (0.139161)

KTe16' KT2"

'g 4 K11I6 "

23.473 (0.13916 KTe16" = 62586.538 Total resistance through entire piping section:

KT=KT=e 6.. + KT6

+

+ Kinket+

Ke1,

KT2. = 62586.538 + 3.453 + 0.5 + 1 K2., = 62591.492

3. Calculate maximum flow through the combined 16" and 2" piping section using equation 9.11:

Q,= 19.65x D1 6,, x/

2 Where:

Q, = Flow in GPM Dl6. = Diameter in terms of 16" pipe (15.5")

HL = Available Head due to elevation only (47.06')

K = Total resistance (62591.492)

Q, =19.65xDi-6.X KL-Q, = 19.65x 15.52 X 625 112 QI = 129.45 o Based on the above flow rate, calculate the Reynolds Number using equation 9.12:

Re = 50.6xQxp Dx/u Where:

Q = Flowin GPM D= Diameter (15.5" and 2.157")

p = Density in pound per cubic feet @ 120'F (61.71) 4= Absolute viscosity in centepoise @ 120'F (0.56)

Calculation No. IP-CALC-13-00005 Rev. 1 Page 20 of 33 For the 16" section:

50.6xQ1 xp Re6.

16 xU 50.6 x 129.45 x 61.71 15.5x0.56 Re 6. = 4.66E + 04 At the above Reynolds No., friction factor is approximately equal to 0.018 for the 16" piping section as per figure A-25 of Reference 14. This number is greater than the assumed value of 0.013. Therefore, flow resistance of the piping system needs to be adjusted and re-computed using a friction factor of 0.018 for the 16" piping section instead of 0.013.

For the 2" section:

50.6xQ1 xp Re2.-

D= x~

D2' X'"/

50.6 x 129.45 x 61.71 Re2.. =

2.157x0.56 Re 2. = 3.350E + 05 At the above Reynolds No., friction factor is approximately equal to 0.026 for the 2" piping section as per figure A-25 of Reference 14. This number is greater than the assumed value of 0.019. Therefore, flow resistance of the piping system needs to be adjusted and re-computed using a friction factor of 0.026 for the 2" piping section instead of 0.019.

o Adjust the calculated flow rate by going through the calculation steps using equations 9.2 through 9.11 adjusting the flow resistance through the system, where applicable, with the new friction factors based on the above determined Reynolds number:

For the 16" Pipe:

K16p = 1.901 K90(1 6.) = 1.08 K90(6*"6 ) = 0.938 K45(1 6.) = 0.288 Kc = 0.210 KE = 0.101 K84 = 0.144 KT 6.. = 4.662 For the 2" Pipe:

K2p = 3.469 K90(2.) = 5.46 K45( 2.) = 0.416

Calculation No. IP-CALC-13-00005 Rev. 1 Page 21 of 33 K 845 = 5.358 K727A= 5.358 K 726A = 5.358 K725 = 0.780 K2,.= 26.198 KTel6,, = 69539.01 Kinete =0.5 K

=,i= 1.000 KT = 69545.172 The adjusted flow rate using the adjusted KT is:

Q1 = 122.81 GPM o Determine the maximum flow rate through the break downstream of valve 350 (line #252):

Available head that determines the flow through the break in the 2" line downstream of valve 350 (line

1. 252), is the result of the differential pressure produced by the level in the RWST and the break location.

1. Available head to drive flow through Segment 2 at the 2" line break from the RWST is as follows:

a. The RWST Minimum Limit Technical Specification level is 36.83' tank level (this includes an allowance for instrument uncertainty of 2.65'). The minimum log reading is 37.01' currently used for the RWST Low Level Alarm in the CCR according to procedure 2-ARP-SBF-1.

b. This equates to an elevation of 118.06' with the tank bottom being at elevation of 81.05'.

c. The break point downstream of valve 350 is at elevation 91.5' (Segment 1).

d. Therefore at Minimum Limit Technical Specification level, available head through each break is:

1412 = Min. RWST Level Elevation (ft) - Break Point Elevation (ft)

Hr2 = 118.06' - 91.5' HL = 26.56'

2. Determine the flow resistance for the various components within the 3" and 2" lines from the piping isometrics (Reference 1, 3 and 4) and formulas from Crane (Reference 14).

For the 3" section:

Length of piping is approximately 152.49'.

Number of 900 elbows is 4.

Number of 450 elbows is 1.

3" tee connecting line #161 and #253.

3" to 2" contraction.

Calculation No. IP-CALC-13-00005 Rev. 1 Page 22 of 33 Valve 1860- 3" Grinnell Saunders Diaphragm Valve.

Flow resistance for the 3" piping section using equation 9.2:

K 3p =fx L

D Where:

K 3p = Flow resistance of the 3" piping system f = Friction factor of the 3" piping system (0.018)

L = Length of the 16" piping system (152.49')

D = Diameter of the 3" pipe (0.256')

K3 = 0.018x 1 5 2.4 9 0.256 K3p= 0.018x596.361 K3p= 10.735 Flow resistance for 900 elbows in the 3" piping section using equation 9.3:

K90(3.) =30xf xN90 Where:

K90(3.) = Flow resistance of 900 elbows in the 3" piping system f = Friction factor of the 3" piping system (0.018)

N90 = Number of 90' elbows in the 3" piping system (4)

K90(3 ") =30xf xN90 K90(3.) =30x0.018x4 K90(3.) = 2.16 Flow resistance for 450 elbows in the 3" piping section using equation 9.4:

K45(3.) =16xf xN45 Where:

K45(3.) = Flow resistance of 45' elbows in the 3" piping system f = Friction factor of the 3" piping system (0.018)

N45 = Number of 45' elbows in the 3" piping system (1)

K45(3.) =16xf xN45 K45(3.) =16x0.018xl K45(3") =0.288

Calculation No. IP-CALC-13-00005 Rev. 1 Page 23 of 33 Flow resistance for valve 1860 in the 3" piping section using equation 9.9:

891xD 4 K 1860 -= 8 2

Where:

K 72 7A = Flow resistance of valve 1860 in the 3" piping system Cv Coefficient = 190 (Reference 16)

D = Diameter (3.068")

891xD 4

891 x 3.068 4 K 1860 -

1902 K18 0 = 2.187 Flow resistance for 3 "-2" contraction in 3" piping section using equation 9.6:

0.50 x (1-,f 2) x (sin 0 )1/2 Kc 2

p Where:

Kc = Flow resistance of 3"-2" contraction in 3" piping system f6 = Dl/D2 (D1 = 2.157" (smaller D), D2 = 3.068" (larger D)) (0.703)

(sin

= Assigned the value of 1 for conservatism 2

0.50 x (1-/#2 ) X(SM _)~

Kc =

4 2

0.50 x (1 - 0.7032) xl Kc 0.7034 Kc = 1.035 Flow resistance for tee in the 3" piping section using equation 9.5:

K(Tee3") = 60 x f x1 Where:

K(T3.-= Flow resistance of tee in the 3" piping system f = Friction factor of the 3" piping system (0.018)

Calculation No. IP-CALC-13-00005 Rev. 1 Page 24 of 33 K(Tee3") = 60 x f K(Tee3") =60x0.018 K(Tee3") =1.08 Total resistance through 3" piping section:

KT3 K3p + K90(3.") + K45(3")+ Kc + Kre + K1860 K3.= 10.735 + 2.16 + 0.288 + 2.187 +1.08 +1.035 KT 3. = 17.485 For the 2" section:

Length of piping is approximately 70.318'.

Number of 900 elbows is 6.

Number of 450 elbows is 4.

Valve 350 - 2" Rockwell Edwards, Y-Globe Valve.

Flow resistance for the 2" piping section using equation 9.2:

K 2p -f L

Where:

K2p = Flow resistance of the 2" piping system f = Friction factor of the 2" piping system (0.019)

L = Length of the 2" piping system (70.318')

D = Diameter of the 2" pipe (0.18')

K 2p =0.019x 70.3 1 8 0.18 K2p =0.019x391.088 K2p = 7.433 Flow resistance for 900 elbows in the 2" piping section using equation 9.3:

K90(2') =30xf xN90 Where:

K90(2.) = Flow resistance of 90* elbows in the 2" piping system f = Friction factor of the 2" piping system (0.019)

N90 = Number of 90' elbows in the 2" piping system (6)

Calculation No. IP-CALC-13-00005 Rev. 1 Page 25 of 33 K90(2.) =30x f x N90 K.90(2.) =30x0.019x6 K90(2.) = 3.420 Flow resistance for 450 elbows in the 2" piping section using equation 9.4:

K45(2.) = 16 x f x N45 Where:

K45(16.) = Flow resistance of 450 elbows in the 2" piping system f = Friction factor of the 2" piping system (0.019)

N45 = Number of 45° elbows in the 2" piping system (4)

K45(2.) =16xf xN45 K45(2.) =16x0.019x4 K45(2.) = 1.216 Flow resistance for valve 350 in the 2" piping section using equation 9.9:

891xD 4

K350 --

2 Where:

K350 = Flow resistance of valve 350 in the 2" piping system Cv Coefficient = 70 (Reference 16)

D = Diameter (2.157")

891xD 4

K 350

=

c2 891x2.157 4

K 350 =

702 K 350 =3.936 Total resistance through 2" piping section:

Kr2. = K2P + K90(2.) + K45(2.) + K350 KT2,, = 7.431+ 3.42 +1.216 + 3.936 KT 2 - = 16.003

Calculation No. IP-CALC-13-00005 Rev. 1 Page 26 of 33 Calculate total flow resistance through 2" piping in terms of 3" piping using equation 9.10:

KTe3. -

K 2 ".

Where:

Kre16, -: Flow resistance of 2" total in terms of 3" piping system fi = D1/D2 (DI = 2.157" (smaller D), D2 = 3.068" (larger D)) (0.703)

KT2,,

gTe3" =

fl4 16.003 Kre3. = 0.7034 KTe3

" = 65.505 Total resistance through entire piping section:

KT = KTe3 + KT 3 + Kine, + K*,,

KT = 65.505+17.485+0.5+1 KT = 84.49

3. Calculate maximum flow through the combined 3" and 2" piping section using equation 9.11:

Q2= 19.65x D3. X (HL1 2

Where:

Q2= Flow in GPM D3,, = Diameter in terms of 3" pipe (3.068")

HL = Available Head due to elevation only (26.56')

K = Total resistance (84.49)

Q2= 19.65 x D. x(HL 2

Q 2 = 19.65 x 3.068 2 X26.56 )"2 Q2 = 103.701 o Based on the above flow rate, calculate the Reynolds Number using equation 9.12:

Re= 50.6xQxp Dxp

Calculation No. IP-CALC-13-00005 Rev. 1 Page 27 of 33 Where:

Q = Flow in GPM D= Diameter (3.068" and 2.157")

p = Density in pound per cubic feet @ 120'F (61.71) a= Absolute viscosity in centepoise @ 120'F (0.56)

For the 3" section:

ReY = 50.6xQ, xp DR Xe/I 50.6 x 103.701 x 61.71 Re3

=

3.068 x 0.56 Re3. = 1.88E + 05 At the above Reynolds No., friction factor is approximately equal to 0.028 for the 3" piping section as per figure A-25 of Reference (14). This number is greater than the assumed value of 0.018. Therefore, flow resistance of the piping system needs to be adjusted and re-computed using a friction factor of 0.028 for the 3" piping section instead of 0.018.

For the 2" section:

50.6xQ, xp Re 2.- =

D 2"xU 50.6 x 103.701 x 61.71 2.157 x0.56 Re 2. = 2.68E + 05 At the above Reynolds No., friction factor is approximately equal to 0.027 for the 2" piping section as per figure A-25 of Reference (14). This number is greater than the assumed value of 0.019. Therefore, flow resistance of the piping system needs to be adjusted and re-computed using a friction factor of 0.027 for the 2" piping section instead of 0.019.

o Adjust the calculated flow rate by going through the calculation steps using equations 9.2 through 9.11 adjusting the flow resistance through the system, where applicable, with the new friction factors based on the above determined Reynolds number:

For the 3" Pipe:

K3p= 16.700 K90(3) =3.36 K45(3-) =0.448 K1860 = 2.187 Kc -1.035 KTe = 1.68 KT3. = 25.41

Calculation No. IP-CALC-13-00005 Rev. 1 Page 28 of 33 For the 2" Pipe:

Kzp = 10.562 K90(2.) = 4.860 K45(2.)

1.728 K350 = 3.936 KT2,= 21.087 KTe3,, = 86.303 Kinlet =0.5 Kei, = 1.000 KT = 113.213 The adjusted flow rate using the adjusted KT is:

Q2 = 89.586 GPM o Minimum Technical Specifications indicated level is 36.83' (Reference 5 and 22 per SR 3.5.4.2).

o Current Low Level Alarm in the CCR set at 37.01' (Reference 15). At this level indication, with 936.81 gallons per 0.1 foot, there are about 1686.3 gallons of water over the minimum Technical Specifications available.

Available time can be calculated using equation 9.13, which is equal to the available inventory (1686.3 gallons), based on the Low Level Alarm in the CCR, divided by the total loss rate through the postulated breaks for each scenario outlined in section 5.0. Total loss rate varies by the postulated time scenarios to isolate Segment 1 (For scenario details refer to section 5.0).

Note: Isolating Segment 1 involves the closure of valves 845 and 727A as well as tripping the Purification Pump if necessary (During circumstances that do not callfor an SI signal). Isolation of Segment 2 involves closing valve 350.

o Using equation 9.13, determine additional available time for levels above 37.01' for each of the postulated scenarios outlined in section 5.0. In order to determine the available time prior to reaching the Technical Specifications Minimum Water Level of 36.83', a water level in the RWST of 37.65' (at Overflow Level) will be assumed to provide a higher HL when calculating Q, and Q2. Using a higher water level in the tank, Q, and Q2 are adjusted to account for the difference in available head (HL), leading to higher flowrates.

This will provide some additional head, leading to higher outflow rates of 123.9 gpm (instead of 122.8 gpm) for Q1 at 37.01' level in the RWST and 91.0 gpm (instead of 89.5 gpm) for Q2 at 37.01' level in the RWST, which is overall conservative.

Available time is equal to available inventory (936.81 gallons per 0.1 foot) divided by the total loss rate in each postulated scenario. Tabulated results are as follows:

Calculation No. IP-CALC-13-00005 Rev. 1 Page 29 of 33 Case A: Purification Pump in Operation Flowrate from Segment I In GPM (at Overflow Water Level):

Flowrate from Segment 2 In GPM (at Overflow Water Level):

Minimum Technical Specificaton level (ft):

Assumed Time to Isolate Segment 1 (minutes):

Available inventory (gallons) per 0.1:

180.0 91.0 36.83 3

936.81 Table 10.1 Tabulated Results of Scenario A 01 - Flowrate 0

- Flowrate Excess Water Calculated Total Initial Indicated Through Segment Through Segment Above Tech. Specs Time to TS Min.

RWST Level (FT) 1 (GPM) 2 (GPM)

Limit (Gal)

Level (Min) 37.65 180.0 91.0 7681.8 78.5 37.63 180.0 91.0 7494.5 76.5 37.53 180.0 91.0 6557.7 66.2 37.43 180.0 91.0 5620.9 55.9 37.33 180.0 91.0 4684.1 45.6 37.23 180.0 91.0 3747.2 35.3 37.13 180.0 91.0 2810.4 25.0 37.03 180.0 91.0 1873.6 14.7 37.01 180.0 91.0 1686.3 12.6 36.93 180.0 91.0 936.8 4.4 36.83 180.0 91.0 0.0 0.0 Case B: Purification Pump in Operation Flowrate from Segment I In GPM (at Overflow Water Level):

180.0 Flowrate from Segment 2 In GPM (at Overflow Water Level):

91.0 Minimum Technical Specificaton level (ft):

36.83 Assumed Time to Isolate Segment 1 (minutes):

5 Available Inventory (gallons) per 0.1:

936.81 Table 10.2 Tabulated Results of Scenario B 01-Flowrate 02-Flowrate Excess Water Calculated Total Initial Indicated Through Segment Through Segment Above Tech. Specs Time to TS Min.

RWST Level (FT) 1 (GPM) 2 (GPM)

Limit (Gal)

Level (Min) 37.65 180.0 91.0 7681.8 74.6 37.63 180.0 91.0 7494.5 72.5 37.53 180.0 91.0 6557.7 62.2 37.43 180.0 91.0 5620.9 51.9 37.33 180.0 91.0 4684.1 41.6 37.23 180.0 91.0 3747.2 31.3 37.13 180.0 91.0 2810.A 21.0 37.03 180.0 91.0 1873.6 10.7 37.01 180.0 91.0 1686.3 8.6 36.93 180.0 91.0 936.8 3.5 36.83 180.0 91.0 0.0 0.0

• At the given RWST Level, the calculated total time to Technical Specifications minimum level is less than the assumed 5 minutes allowed to isolate segment 1.

Calculation No. IP-CALC-13-00005 Rev. 1 Page 30 of 33 Case C: All Three SI Pumps In Operation Flowrate from Segment 1 In GPM (at Overflow Water Level):

Flowrate from Segment 2 in GPM (at Overflow Water Level):

Minimum Technical Specificaton level (ft):

Assumed Time to Isolate Segment 1 (minutes):

Available inventory (gallons) per 0.1':

Table 10.4 Tabulated Results of Scenario C 123.9 99.0 36.83 3

936.81 01-Flowrate U2 - Flowrate Excess Water Calculated Total Initial Indicated Through Segment Through Segment Above Tech. Specs Time to TS Min.

RWST Level (FT) 1 (GPM) 2 (GPM)

Limit (Gal)

Level (Min) 37.65 123.9 99.0 7681.8 73.8 37.63 123.9 99.0 7494.5 71.9 37.53 123.9 99.0 6557.7 62.5 37.43 123.9 99.0 5620.9 53.0 37.33 123.9 99.0 4684.1 43.6 37.23 123.9 99.0 3747.2 34.1 37.13 123.9 99.0 2810.4 24.6 37.03 123.9 99.0 1873.6 15.2 37.01 123.9 99.0 1686.3 13.3 36.93 123.9 99.0 936.8 5.7 36.83 123.9 99.0 0.0 0.0 Case D: All Three Sl Pumps In Operation Flowrate from Segment 1 In GPM (at Overflow Water Level):

123.9 Flowrate from Segment 2 in GPM (at Overflow Water Level):

99.0 Minimum Technical Specificaton level (ft):

36.83 Assumed Time to Isolate Segment 1 (minutes):

5 Available inventory (gallons) per 0.1:

936.81 Table 10.5 Tabulated Results of Scenario D 01-Flowrate 02-Flowrate Excess Water Calculated Total Initial Indicated Through Segment Through Segment Above Tech. Specs Time to TS Min.

RWST Level (FT) 1 (GPM) 2 (GPM)

Limit (Gal)

Level (Min) 37.65 123.9 99.0 7681.8 71.3 37.63 123.9 99.0 7494.5 69.4 37.53 123.9 99.0 6557.7 60.0 37.43 123.9 99.0 5620.9 50.5 37.33 123.9 99.0 4684.1 41.1 37.23 123.9 99.0 3747.2 31.6 37.13 123.9 99.0 2810.4 22.1 37.03 123.9 99.0 1873.6 12.7 37.01 123.9 99.0 1686.3 10.8 36.93 123.9 99.0 936.8 4.2 36.83 123.9 99.0 0.0 0.0

• At the given RWST Level, the calculated total time to Technical Specifications minimum level is less than the assumed 5 minutes allowed to isolate segment 1.

Calculation No. IP-CALC-13-00005 Rev. 1 Page 31 of 33 Case E: Purification Pump in Operation Flowrate from Segment 1 in GPM (at Overflow Water Level):

Flowrate from Segment 2 in GPM (at Overflow Water Level):

Minimum Technical Specificaton level (ft):

Assumed Time to Isolate Segment 1 (minutes):

Available inventory (gallons) per 0.1':

Table 10.7 Tabulated Results of Scenario E 180.0 91.0 36.8 10 936.8 Q1-Flowrate 02-Flowrate Excess Water Calculated Total Initial Indicated Through Segment Through Segment Above Tech. Specs Time to TS Min.

RWST Level (FT) 1 (GPM) 2 (GPM)

Limit (Gal)

Level (Min) 37.33 180.0 91.0 4684.1 31.7 Case F: All Three SI Pumps in Operation Flowrate from Segment 1 In GPM (at Overflow Water Level):

123.9 Flowrate from Segment 2 In GPM (at Overflow Water Level):

99.0 Minimum Technical Specificaton level (ft):

36.8 Assumed Time to Isolate Segment 1 (minutes):

10 Available inventory (gallons) per 0.1':

936.8 Table 10.8 Tabulated Results of Scenario F 0 1 - Flowrate U2 - Fowrate Excess Water Calculated Total Initial Indicated Through Segment Through Segment Above Tech. Specs Time to TS Min.

RWST Level (FT) 1 (GPM) 2 (GPM)

Limit (Gal)

Level (Min) 37.33 123.9 99.0 4684.1 34.8 The maximum time available for each of the 6 scenarios outlined in section 5.0 based on the current 37.01' (cases A through D) and 37.33' (cases E and F) log used for the Low Level Alarm in the CCR (Reference

15) are tabulated below:

Table 10.7 Time to Reach TS Limits (Min) Based on Postulated Scenarios Purification Safety Injection Assumed Time Remaining Postulated Pump Pumps to Isolate Time to Isolate Scenario Operating Operating Segment 1 Segment 2 A

Yes No 3.0 9.6 B

Yes No 5.0 3.6 C

No Yes 3.0 10.3 D

No Yes 5.0 5.8 E

Yes No 10.0 21.7 F

No Yes 10.0 24.8 Note: For the calculated flow rate in each scenario refer to Tables 10.1 through 10.6. The values in Table

10. 7 are based on a minimum water level in the RWST defined in each scenario description in section 5.

Calculation No. IP-CALC-13-00005 Rev. 1 Page 32 of 33 11.0 References

1. Drawing 9321-F-2633, Rev. 38, "Nuclear Tank Farm Composite Piping".

2. Drawing 9321-F-2570, Rev. 73, "Primary Auxiliary Building Composite Piping Arrangement".

3. Drawing 9321-F-2580, Rev. 30, "Primary Auxiliary Building Composite Piping Arrangement Sections - Sheet No. 8".

4. Drawing ISO-253-A-2-1, Rev. 2, "Piping Isometrics - Line #252 + #253 Also Found Under Indian Point 2".

5. Entergy Calculation FIX-00096-01, "RWST - Level Instrumentation Channel Accuracies, Calibration, and Setpoints".

6. Drawing 9321-F-2735, Rev. 140, "Safety Injection System" UFSAR Figure No. 6.2-1 (Sht.1).

7. Drawing 9321-F-2736, Rev. 129, "Chemical & Volume Control System - UFSAR Figure No. 9.2-1 (SHT.1)".

8. Drawing A227781, Rev. 82, "Auxiliary Coolant System - UFSAR Figure No. 9.3-1 (SHT.1)".

9. Entergy Specification 9321-01-248-18, Rev. 19, "Fabrication of Piping Systems - Turbine Generator Plant".

10. Purchase Order No. 9-05664, Refueling Water Purification Pump #21.

11. Entergy Procedure 2-PT-Q029A, Rev. 24, "21 Safety Injection Pump".

12. Entergy Procedure 2-PT-Q029B, Rev. 20, "22 Safety Injection Pump".

13. Entergy Procedure 2-PT-Q029C, Rev. 21, "23 Safety Injection Pump".

14. Crane Technical Paper 410, 1982 Edition, "Flow of Fluid Through Valves, Fittings and Pipe".

15. Entergy Procedure 2-ARP-SBF-1, Rev. 41, "CCR Safeguards".

16. ITT Industries - Dia-Flo Industrial Diaphragm Valves Engineering Catalog.

17. Drawing IP3V-354-0006, Rev. 3 "Stainless Steel Univalve Check Valve".

18. Vendor Manual 1775, Rev. 3, "Service Manual for Rockwell Edwards Univalves".

19. Entergy Calculation IP3-CALC-SI-03333, Rev. 0, "Engineering Evaluation of postulated RWST Inventory Loss in Support of ACT 99-44077".

20. Entergy Report IP-RPT-09-00014, Rev. 1, "Critical Submergence Evaluations Related to Surface Vortices in Nuclear Safety and Augmented Quality Tanks/Pumps at IPEC".

21. ANSI/ASME Code B16.9, 1986 Edition, "Factory Made Wrought Steel Butt-welding Fittings".

22. Entergy Controlled Document - Technical Specifications, "Indian Point 2 Improved Technical Specifications"

Leg Line Diameter Le h

Elevatio Direction Class 907 E*6mws 45* E s Contractions E Tees Valves Pumps Drawing 1

155 16" 1T8 11/16' 1.724 826' NortWaEs 151 1(141) 0 1 (16"-14")

0 0

1(846) 0 9321-F-2633 2

155 16" 41'05W8 41.052 826' Nmhf't est 151 0

1 (16) 0 1(16'-141) 0 0

0 9321-F-2633 3

155 16' 210318V 2.865 82' 6 West 151 1(161 0

0 0

0 0

0 9321-F-2633 4

155 16' 26' 2500 82 '-760' 151 1 (16) 0 0

0 0

0 0

9321-F-2633 9321-F-2633 1

5 155 16" 88' 88.250 76 0" West 151 0

0 0

0 0

0 0

9321-F-2570 From__

_ _9321-F-2580 to r V Tve 6 183 2"

U'10 0.8 76 r8-77' 9 3 151 1(21 0

0 0

0 0

0 9321-F-25M0 725 7

183 2'

0'7' 0.583 77 93/8" SoutiEast 151 0

1 (Z) 0 0

0 0

0 9321-F-2580 (Z

8 183 2"

125W 1.219 77938 SoiJh 151 IM) 0 0

0 0

0 0

9321-F-2580 0'0 9 183 2"

2338 2.281 77'93/8"-75' 151 1(2) 0 0

0 0

0 0

9321-F-2580 D 10 183 2'

11'101t 11.875 76 SDih 151 1J(1 0

0 0

0 185 0

9321-F-2580 11 183 2z 3 10" 3.833 75-6.6' 151 1 (2) 0 0

0 0

1 (727A) 0 9321-F-2580 12 183 21 2' 3 2.250 69 6-71' West 151 2

0 0

0 0

1 9321-F-2580 13 135 2"

1.'

1.083 17' S1 h 151 0

0 0

0*

0 2(A& 725)1 0

9321 -F-2590 Total Le th of Straight pipe -16" 136'411/16" 1363 31 1

1 1

1 Total nU t of Straght Le-2 23 11 7/8" 2.990

_7 1

0 0

0 4__

'14" Elbo

'1-2Z Exlaer assuumto be part of puriition pump Resistano is neglected oci nservatles

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Leg Line Diaetert Legh Elevation Direction Class 91' Emws 45' Boows Ciontadons Tees saves Purr__s DOWN 1

161 3"

9 7 1V 9.625 83"-9533' 151 1(1 0

0 0

0 0

0 9321-F-2633 2

161 3"

36 71/2" 36.6Z 833' 3"

NotiyE 151 0

0 0

0 0

0 0

9321-F-2633 3

161 3"

21 11/16*

P-141 873' 3" Noti'Eed 151 1 (M 0

0 0

0 1(1860I) 0 9321-F2633 4

161 3'

42 6 1/8' 42.510 833' NothfWfst 151 0

()

0 0

0 0

0 9321-F-2633 7l 5

161 3'

527/8' 5.240 1

83' West 151 1 (3)

0.

0 0

0 0

0 9321-F-2634 6

161 3"

69 211/16' 6.M4 76'-83 3' 151 1 (3) 0 0

0 0

0 0

9321-F-2635 2

7 161 3'

5011/2' 50.125 766' West 151 0

0 1 (3"-2")

0 1

0 0

9321-F-2633 Fi*rm RAIS" 9_21-F-2570 to2' Bird 8

253 2z 075/8" 0.635 776t-77 North 151 0

1 (2) 0 0

0 0

0 ISO-253-A-2-1 to Range Past 9

253 2

32 51/4" 3.438 77 North 151 0

1 (2) 0 0

0 0

0 ISO-253-A-2-1 Vahe 350 10 253 2

2 19'16' 2.130 77 NodhWAAest 151 0

1 (2) 0 0

0 0

0 ISO-2534.2L1 1

11 253 2T 2 105/8 2.885 77 North 151 1(Z 1 (2")

0 0

0 0

0 IS253A2-1 12 253 2

(7 7" 0.583 77-94' 6-151 1 (Z) 0 0

0 0

0 0

ISO-253-A-2-1 13 253 2z 1'3" 1.250 94!' 6 North 151 1(2")

0 0

0 0

0 0

ISO-253A-2-1 14 253 2z 246' 24.500 946' East 151 1 (Z) 0 0

0 0

0 0

iSO.253A-2-1 15 253 2'

4! 6' 4.500 94! 6'-99' 6 151 1 (2) 0 0

0 0

0 0

lSO-253A-2-1 16 253252 2'

1' 4 3/4!

1.396 996' South 151 1(2) 0 0

0 0

1(350) 0 ISC-253-A-2-1 Total Length of Straight ppe-3" 152 51/8" 152.490 4

1 1

0 1

1 Total Lngh of Sght pipe-2" 70 31316' 70.318 6

4 0

0 0

1