ML17331A927: Difference between revisions

From kanterella
Jump to navigation Jump to search
Created page by program invented by StriderTol
StriderTol Bot change
 
Line 16: Line 16:


=Text=
=Text=
{{#Wiki_filter:ACCELERANT             0 DOCUMENT DlSTR                   BU'r.'j.ox SX~"j.'j.'Xi REGULA         INFORMATION DISTRIBUTIO         YSTEM (RIDS)
{{#Wiki_filter:ACCELERANT 0 DOCUMENT DlSTR BU'r.'j.ox SX~"j.'j.'Xi REGULA INFORMATION DISTRIBUTIO YSTEM (RIDS)
ACCESSION NBR:9308110256             DOC.DATE:   93/08/06   NOTARIZED: NO           DOCKET ¹ FACIL:50-315 Donald C. Cook Nuclear Power Plant, Unit 1, Indiana                   M 05000315 50-316 Donald C. Cook Nuclear Power Plant, Unit 2, Indiana                 M 05000316 AUTH. NAME           AUTHOR AFFILIATION FITZPATRICK,E.       Indiana Michigan Power Co. (formerly Indiana             6 Michigan Ele RECIP.NAME           RECIPIENT AFFILIATION MURLEY                 Document Control Branch (Document           Control Desk)
ACCESSION NBR:9308110256 DOC.DATE: 93/08/06 NOTARIZED: NO DOCKET ¹ FACIL:50-315 Donald C.
Cook Nuclear Power Plant, Unit 1, Indiana M
05000315 50-316 Donald C.
Cook Nuclear Power Plant, Unit 2, Indiana M
05000316 AUTH.NAME AUTHOR AFFILIATION FITZPATRICK,E.
Indiana Michigan Power Co. (formerly Indiana 6 Michigan Ele RECIP.NAME RECIPIENT AFFILIATION MURLEY Document Control Branch (Document Control Desk)
I
I


==SUBJECT:==
==SUBJECT:==
Provides update to 930611 initial response to NRC Bulletin 93-002.Analysis confirming that subj roughing filters will remain confined within kidney fans in event of LOCA inside containment encl.
Provides update to 930611 initial response to NRC Bulletin 93-002.Analysis confirming that subj roughing filters will remain confined within kidney fans in event of LOCA inside containment encl.
DISTRIBUTION CODE: IE11D           COPIES RECEIVED:LTR         ENCL       SIZE:
DISTRIBUTION CODE:
TITLE: Bulletin   Response     (50 DKT)
IE11D COPIES RECEIVED:LTR ENCL SIZE:
TITLE: Bulletin Response (50 DKT)
NOTES:
NOTES:
RECIPIENT             COPIES              RECIPIENT          COPIES ID CODE/NAME             LTTR ENCL        ID CODE/NAME        LTTR ENCL PD3-1 PD                     1      1      DEAN,W                1    1 INTERNAL: AEOD/DOA                     1      1      NRR/DE/EMEB            1    1 NRR/DRPW/OGCB               1      1      NRR/DRSS/PEPB          1    1 N
RECIPIENT ID CODE/NAME PD3-1 PD INTERNAL: AEOD/DOA NRR/DRPW/OGCB NRR/DSSA N ~ II-2 REG FI 02 G
REG G
FILE 01 EXTERNAL: NRC PDR COPIES LTTR ENCL 1
              ~ II-2 NRR/DSSA FI FILE 02 01 1
1 1
1 1
1 1
1 1
1 1
1 1
1 NRR/DSSA/SRXB NRR/SCSB RES/DSIR/EIB 1
1 1
1 1
1 1
1 1
1 EXTERNAL: NRC PDR                      1     1     NSIC                   1     1 D
1 1
A, D i D
1 1
NOTE TO ALL "RIDS" RECIPIENTS:
1 RECIPIENT ID CODE/NAME DEAN,W NRR/DE/EMEB NRR/DRSS/PEPB NRR/DSSA/SRXB NRR/SCSB RES/DSIR/EIB NSIC COPIES LTTR ENCL 1
1 1
1 1
1 1
1 1
1 1
1 1
1 D
A, D
i NOTE TO ALL"RIDS" RECIPIENTS:
PLEASE HELP US TO REDUCE WASTE! CONTACT THE DOCUMENT CONTROL DESK, ROOM Pl-37 (EXT. 504-2065) TO ELIMINATEYOUR NAME FROM DISTRIBUTION LISTS FOR DOCUMENTS YOU DON'T NEED!
PLEASE HELP US TO REDUCE WASTE! CONTACT THE DOCUMENT CONTROL DESK, ROOM Pl-37 (EXT. 504-2065) TO ELIMINATEYOUR NAME FROM DISTRIBUTION LISTS FOR DOCUMENTS YOU DON'T NEED!
TOTAL NUMBER OF COPIES REQUIRED: LTTR               15   ENCL   15
D TOTAL NUMBER OF COPIES REQUIRED:
LTTR 15 ENCL 15


Inmana Michigan Power Company P.O. Box 16631 Coiumbus, OH 43216 Z'NDIANA NICHI64N IaOMfER Donald C. Cook Nuclear Plant Units       1 and 2           AEP:NRC:1188A Docket Nos. 50-315 and 50-316 License Nos. DPR-58 and DPR-74 BULLETIN NO.       93-02'EBRIS   PLUGGING OF EMERGENCY                 '.
Inmana Michigan Power Company P.O. Box 16631 Coiumbus, OH 43216 Z'NDIANA NICHI64N IaOMfER Donald C.
CORE COOLING SUCTION STRAINERS S. Nuclear Regulatory Commission Attention:       Document Control Desk Washington, DC'0555 August 6, 1993
Cook Nuclear Plant Units 1 and 2
Docket Nos.
50-315 and 50-316 License Nos.
DPR-58 and DPR-74 BULLETIN NO. 93-02'EBRIS PLUGGING OF EMERGENCY CORE COOLING SUCTION STRAINERS AEP:NRC:1188A S. Nuclear Regulatory Commission Attention:
Document Control Desk Washington, DC'0555 August 6, 1993


==Dear Dr. Murley:==
==Dear Dr. Murley:==
The purpose of this letter is to provide an update to our initial response to NRC Bulletin 93-02 dated June 11, 1993.
The initial response noted that additional time was required to investigate the capability of ventilation units in the containments of Cook Nuclear Plant to contain fibrous filters following a
Loss of Coolant Accident (LOCA).
Specifically, the Containment Auxiliary Cleanup Ventilation Units (kidney fans) located in the basement of the lower compartment of Cook Nuclear Plant containments needed to be analyzed.
As stated in the original letter, these were the only sources of the fibrous material addressed in the bulletin that posed a concern for blocking the containment recirculation sump.
An analysis has been completed that confirms that the subj ect roughing filters will remain confined within the kidney fans in the event of a LOCA inside containment.
As requested by your staff, a
copy of the analysis is included as an attachment to this letter.
This analysis utilized the leak before break philosophy, developed by Westinghouse as part of the resolution of unresolved safety issue USI-A2.
Leak before break is applicable to Cook Nuclear Plant via amendment no.
76 to Unit 2 and an NRC SER dated November 22, 1985.
loooaI As indicated in our original response letter referenced
: above, the filters discussed
'have been found to be unnecessary for the functionality of the ventilation units.
Current plans are to ensure the roughing filters are removed from Unit 1
during the next refueling outage scheduled to begin February 1994.
If Unit 1 is forced into an unplanned outage of sufficient duration prior to this
: date, every effort will be made to ensure the removal of the roughing filters sooner.
We verified by inspection that there were no roughing filters in Unit 2 during the forced outage which began August 2, 1993.
9308ii0256 930806 PDR ADQCK 050003i5 8
PDR


The purpose        of this letter is to provide an update to our initial response to NRC Bulletin 93-02 dated June 11, 1993.          The initial response noted that additional time was required to investigate the capability of ventilation units in the containments of Cook Nuclear Plant to contain fibrous filters following a Loss of Coolant Accident (LOCA). Specifically, the Containment Auxiliary Cleanup Ventilation Units (kidney fans) located in the basement of the lower compartment of Cook Nuclear Plant containments needed to be analyzed.        As stated in the original letter, these were the only sources of the fibrous material addressed in the bulletin that posed a concern for blocking the containment recirculation sump.
Dr. T. E. Murley AEP:NRC:1188A This letter is submitted pursuant to 10 CFR 50. 54(f)
An    analysis has been completed that confirms that the subj ect roughing filters will remain confined within the kidney fans in the event of a LOCA inside containment. As requested by your staff, a copy of the analysis is included as an attachment to this letter.
: and, as
This analysis utilized the leak before break philosophy, developed by Westinghouse as part of the resolution of unresolved safety issue USI-A2. Leak before break is applicable to Cook Nuclear Plant via amendment no. 76 to Unit 2 and an NRC SER dated November 22, 1985.
: such, an oath statement is attached.
As    indicated in our original response letter referenced above, the filters        discussed 'have been found to be unnecessary for the functionality of the ventilation units. Current plans are to ensure the roughing filters are removed from Unit 1 during the next refueling outage scheduled to begin February 1994. If Unit 1 is forced into an unplanned outage of sufficient duration prior to this date, every effort will be made to ensure the removal of the roughing filters sooner. We verified by inspection that there were no roughing filters in Unit 2 during the forced outage which began August 2, 1993.
loooaI 9308ii0256 930806 PDR  ADQCK 050003i5 8                  PDR
 
Dr. T. E. Murley                               AEP:NRC:1188A This letter is   submitted pursuant to 10 CFR 50. 54(f) and, as such, an oath statement   is attached.
Sincerely, r'~gpss)
Sincerely, r'~gpss)
E. E. Fitzpatrick Vice President eh Attachment CC:   A. A. Blind - Bridgman J. R. Padgett G. Charnoff NFEM Section Chief J. B. Martin - Region   III NRC Resident Inspector - Bridgman
E.
E. Fitzpatrick Vice President eh Attachment CC:
A. A. Blind - Bridgman J.
R. Padgett G. Charnoff NFEM Section Chief J.
B. Martin - Region III NRC Resident Inspector
- Bridgman


COUNTY OF FRANKLIN E. E. Fitzpatrick, being duly sworn, deposes and says that he is the Vice President of licensee Indiana Michigan Power Company, that he has read the forgoing response to Bulletin 93-02: Debris Plugging of Emergency Core Cooling Suction Strainers and knows the contents thereof; and that said contents are true to the best of his knowledge and belief.
COUNTY OF FRANKLIN E.
Subscribed and sworn to before   me this ~4 day of                                   199~8 OTARY       UBLIC plIh 0 )il'iL NOTS aiY F'UCUC. STQE OF OHIO
E. Fitzpatrick, being duly sworn, deposes and says that he is the Vice President of licensee Indiana Michigan Power Company, that he has read the forgoing response to Bulletin 93-02:
Debris Plugging of Emergency Core Cooling Suction Strainers and knows the contents thereof; and that said contents are true to the best of his knowledge and belief.
Subscribed and sworn to before me this ~4 day of 199~8 OTARY UBLIC plIh 0 )il'iL NOTS aiY F'UCUC. STQE OF OHIO


ATTACHMENT TO AEP:NRC:1188A ANALYSIS OF A LOCA ON THE VENTILATION UNITS
ATTACHMENT TO AEP:NRC:1188A ANALYSIS OF A LOCA ON THE VENTILATIONUNITS


ATTACHMENT TO AEP:NR     88A                                                               Page 1 ANERlCAN ELECTRIC PWKR Dato   July 29, 1993 sub)oct Ef feet of Loss of Coolant Accident.                             on Ventilation Units Housing Fibrous Materials prom   T. J. Crawford xo     S. A. Hover~
ATTACHMENT TO AEP:NR 88A Page 1
Responding   to your memo of June 11, 1993,                           we have       analyzed the effects of   a LOCA on the ventilation units.
ANERlCAN ELECTRIC PWKR Dato July 29, 1993 sub)oct Effeet of Loss of Coolant Accident. on Ventilation Units Housing Fibrous Materials prom T. J. Crawford xo S.
The maximum differential pressure across                               the ventilation units was calculated to be less than 0.1                               psi.
A. Hover~
The break   of the accumulator line feeding the cold leg was used as the LOCA. Because     of the the double-ended cold-leg break or cross-under
Responding to your memo of June 11,
                                              'Leak-before-break'riteria leg break were not considered as the LOCA scenario. Direct impingement or dynamic effects were not included since the accumulator line enters the cold leg near elevation 615 and the number 2 steam generator and its four support columns are between the break location and the ventilation unit.
: 1993, we have analyzed the effects of a LOCA on the ventilation units.
The maximum differential pressure across the ventilation units was calculated to be less than 0.1 psi.
The break of the accumulator line feeding the cold leg was used as the LOCA. Because of the
'Leak-before-break'riteria the double-ended cold-leg break or cross-under leg break were not considered as the LOCA scenario.
Direct impingement or dynamic effects were not included since the accumulator line enters the cold leg near elevation 615 and the number 2 steam generator and its four support columns are between the break location and the ventilation unit.
Attached for your information and record retention is a copy of the calculation. If you need additional information please do not hesitate to contact me at 1284.
Attached for your information and record retention is a copy of the calculation. If you need additional information please do not hesitate to contact me at 1284.
cc: S.J. Brewer   / J.B. Kingseed   /           S.A. Hover                 w      attachment E.ED Fitzpatrick                                                         w/o          II G.R. Burris Jr.                                                         w/o          It M.K. Guha / C.D. Olsen / File             N930601                     w/o           If Intra-Syatom
cc: S.J.
E.ED G.R.
M.K.
Brewer / J.B. Kingseed / S.A. Hover Fitzpatrick Burris Jr.
Guha / C.D. Olsen / File N930601 w
attachment w/o II w/o It w/o If Intra-Syatom


ATTACHMENT TO AEP:N     188A                                         Page 2 May 1980 Jan 1984, Rev 1 Dec 1988, Rev 2 Calculation Cover Sheet Technical Assessment Section Job No.: N930601
ATTACHMENT TO AEP:N 188A Page 2
May 1980 Jan
: 1984, Rev 1
Dec 1988, Rev 2
Calculation Cover Sheet Technical Assessment Section Job No.: N930601


==Title:==
==Title:==
Effect of   Loss of Coolant Accident on Ventilation Units Housin Fibrous Materials or Filters System:Emer enc     Core Coolin Plant:   D.C. Cook                             File No.:     Unit: 1 6 2 Design   Basis:~NA By:   T. J. Crawford                                             Date:~726  93 Review: C. P. Lin                           ethod: 4 ~ ~ C.< > 4 8.4 Date: 7 >   3 Approval:M. K. Guha                                                  Date:~7~       VJ Table of Contents Pacae
Effect of Loss of Coolant Accident on Ventilation Units Housin Fibrous Materials or Filters System:Emer enc Core Coolin Plant:
: 1. Problem
D.C.
: 2. Conclusion 3   Procedure
Cook File No.:
: 4. Assumption(s)
Unit:
: 5. Content(s)
1 6
: a. Compartment Energy
2 Design Basis:~NA By:
: b. Initial Compartment   Masses
T. J. Crawford Review: C.
: c. Flow Rates Between Compartments
P. Lin Approval:M. K. Guha Date:~726 93 ethod: 4 ~
: d. New Compartment Masses
~
: e. New Thermodynamic State of Superheated Compartments                     10
C.< > 4 8.4 Date: 7 >
: f. New Thermodynamic State of Saturated Compartments                         10
3 Date:~7~
: g. Heat Transfer to Containment Walls
VJ Table of Contents Pacae 1.
: h. Heat Transfer Within Containment Walls                                   12
Problem 2.
: 6. Reference(s)                                                                   13
Conclusion 3
: 7. Attachment(s).                                                                 15
Procedure 4.
Assumption(s) 5.
Content(s) a.
Compartment Energy b.
Initial Compartment Masses c.
Flow Rates Between Compartments d.
New Compartment Masses e.
New Thermodynamic State of Superheated Compartments f.
New Thermodynamic State of Saturated Compartments g.
Heat Transfer to Containment Walls h.
Heat Transfer Within Containment Walls 10 10 12 6.
Reference(s) 7.
Attachment(s).
13 15


ATTACHMENT TO AEP:N     188A                                     Page 3 TECHNICAL ASSESSMENT CALCULATION VERIFICATION CHECKLIST Page   0 of 'SQ Reviewer:   Q~                                     Date:
ATTACHMENT TO AEP:N 188A Page 3
Section lleneger:   J~tt-~+
TECHNICAL ASSESSMENT CALCULATION VERIFICATION CHECKLIST Page 0 of 'SQ Reviewer:
Q~
Section lleneger:
J~tt-~+
Date:
Review of the calculation shall include evaluation against the following questions:
Review of the calculation shall include evaluation against the following questions:
YES   NO           Basis for Determination
YES NO Basis for Determination 1.
: 1. Was an appropriate method used?
Was an appropriate method used?
: 2. Are the results reason-                             ~rM f able compared to the input?                                           CJ l< l-~SOS.
2.
: 3. Are the results numerically correct?
Are the results reason-able compared to the input?
: 4. Are the equations used correct and the reference documented?
~rM f CJ l< l-~SOS.
: 5. Were the correct inputs                       c used and their sources documented?                                       prP~ 5
3.
: 6. Are the assumptions reasonable and properly documented (including appro-priate references and adequate justi-fication)?
Are the results numerically correct?
: 7. Is the calculation acceptable?
4.
P<sM     >< ~ ~oVg-
Are the equations used correct and the reference documented?
5.
Were the correct inputs used and their sources documented?
c prP~ 5 6.
Are the assumptions reasonable and properly documented (including appro-priate references and adequate justi-fication)?
7.
Is the calculation acceptable?
P<sM
>< ~ ~oVg-


I ~V ATTACHMENT TO AEP:N   1188A                               Page 4 EFFECT OF   L.O.C.A. ON VENTILATION UNITS
ATTACHMENT TO AEP:N 1188A I ~V Page 4
: 1. PROBLEM In a memo of June   ll,   1993(Ref; 1), Mr. S. A. Hover of Nuclear Operations requested Technical Assessment to analyze the effects of the accumulator leg break LOCA blowdown forces on the Containment, Auxiliary Cleanup (Ventilation)
EFFECT OF L.O.C.A.
ON VENTILATIONUNITS 1.
PROBLEM In a memo of June ll, 1993(Ref; 1), Mr. S.
A. Hover of Nuclear Operations requested Technical Assessment to analyze the effects of the accumulator leg break LOCA blowdown forces on the Containment, Auxiliary Cleanup (Ventilation)
Unit located in the basement of lower containment at the D.C. Cook Plant.
Unit located in the basement of lower containment at the D.C. Cook Plant.
The purpose of the analysis is to determine the differential pressure that may be exerted on the ventilation unit during a LOCA, and would be used by Structural Engineering to determine the ability of units to contain fibrous filter materials.                       I The analysis would be in response to NRC bulletin 93-02 and would be used to support continued operation until the next refueling outage.
The purpose of the analysis is to determine the differential pressure that may be exerted on the ventilation unit during a LOCA, and would be used by Structural Engineering to determine the ability of units to contain fibrous filter materials.
I The analysis would be in response to NRC bulletin 93-02 and would be used to support continued operation until the next refueling outage.


                                                              ~
ATTACHMENT TO AEP:
                                                                <</ 5Q ATTACHMENT TO AEP:      188A
188A
: 2. CONCLUSION The maximum   differential pressure across the cleanup or ventilation units was calculated to be less than 0.1 psi.
~
<</ 5Q 2.
CONCLUSION The maximum differential pressure across the cleanup or ventilation units was calculated to be less than 0.1 psi.
The break of the accumulator line feeding the cold leg was used as the LOCA.
The break of the accumulator line feeding the cold leg was used as the LOCA.
Because of the 'Leak-before-break'riteria the double-ended cold-leg break or cross-under leg-break were not considered as the LOCA scenario. Direct, impingement or dynamic effects were not included since the accumulator line enters the cold leg near elevation 615 and the number 2 steam generator and its four support columns are between the break location and the ventilation unit(Refs; 8 & 20).
Because of the 'Leak-before-break'riteria the double-ended cold-leg break or cross-under leg-break were not considered as the LOCA scenario.
: Direct, impingement or dynamic effects were not included since the accumulator line enters the cold leg near elevation 615 and the number 2 steam generator and its four support columns are between the break location and the ventilation unit(Refs; 8
& 20).
The unit sits on elevation 598 and is about 10 feet high, bringing the top of the unit to elevation 608.
The unit sits on elevation 598 and is about 10 feet high, bringing the top of the unit to elevation 608.
The pressure and temperature were calculated for the various containment compartments. The initial'ressure, temperature, and relative humidity were 14.7 psia, 90.0 F, and 100% respectively. The initial temperature of the ice condenser was 27.0 F.
The pressure and temperature were calculated for the various containment compartments.
The computer program       written for this analysis(LOCA01) was checked for reasonableness     by using   it to analyze the double-ended cold leg break with the appropriate initial pressure and temperatures, and comparing it with the Westinghouse TMD results and the MPR Associates results displayed on p IV-19 of Ref. 5. The results are tabulated below.
The initial'ressure, temperature, and relative humidity were 14.7 psia, 90.0 F, and 100% respectively.
Peak Sub-Compartment       Pressure(psia)     Peak Deck   Differential Pressure(psi)
The initial temperature of the ice condenser was 27.0 F.
LOCA01      MPR        TMD                      LOCAOl   MPR     TMD 29.0     26.0       23.9                         8.4     8.3     8.6 The LOCA01 program     calculates a slightly more conservative pressure and differential pressure. The relatively close agreement of LOCAOl         with TMD and MPR provides additional confidence in the results of the present analysis of the ventilation unit.
The computer program written for this analysis(LOCA01) was checked for reasonableness by using it to analyze the double-ended cold leg break with the appropriate initial pressure and temperatures, and comparing it with the Westinghouse TMD results and the MPR Associates results displayed on p IV-19 of Ref. 5.
The results are tabulated below.
Peak Sub-Compartment Pressure(psia)
LOCA01 MPR TMD Peak Deck Differential Pressure(psi)
LOCAOl MPR TMD 29.0 26.0 23.9 8.4 8.3 8.6 The LOCA01 program calculates a slightly more conservative pressure and differential pressure.
The relatively close agreement of LOCAOl with TMD and MPR provides additional confidence in the results of the present analysis of the ventilation unit.


                                                                /'g o ATTACHMENT TO AEP:N 1188A                               page 6
ATTACHMENT TO AEP:N 1188A
: 3. PROCEDURE A. Obtain the dimensions of the air filtering unit(Ref. 2), the distances between the unit and the crane wall, the unit and the biological shield, the unit and the ceiling, and the two elevations. Calculate flow area for steam/water mixture around the   air unit.
/'g o page 6
B. Obtain the   diameter of the accumulator line and the maximum blowdown flow rate from it(Fig. 2-3, Ref. 3) . Use a realistic value of temperature for cold leg water to calculate the density and quality of the steam-water mixture that would be released.
3.
C. Obtain necessary. input data. Much of this was taken from Refs. 4, 5, 6, 7,
PROCEDURE A. Obtain the dimensions of the air filtering unit(Ref. 2), the distances between the unit and the crane wall, the unit and the biological shield, the unit and the ceiling, and the two elevations.
: 8. This included the dimensions of the containment building, sub-compartment volumes, flow areas between compartments, wall surface areas and thicknesses, and mass and area of metal in the compartments.
Calculate flow area for steam/water mixture around the air unit.
B. Obtain the diameter of the accumulator line and the maximum blowdown flow rate from it(Fig. 2-3, Ref.
: 3).
Use a realistic value of temperature for cold leg water to calculate the density and quality of the steam-water mixture that would be released.
C. Obtain necessary. input data.
Much of this was taken from Refs.
4, 5, 6, 7, 8.
This included the dimensions of the containment building, sub-compartment
: volumes, flow areas between compartments, wall surface areas and thicknesses, and mass and area of metal in the compartments.
D. Divide the containment building into twelve sub-compartments or regions.
D. Divide the containment building into twelve sub-compartments or regions.
The lower compartment was divided into six regions. The two fan-accumulator rooms, the reactor cavity, and the instrument room were four more regions. The ice condenser and the upper compartment were two more   regions.
The lower compartment was divided into six regions.
The two fan-accumulator rooms, the reactor cavity, and the instrument room were four more regions.
The ice condenser and the upper compartment were two more regions.
E. Divide the containment walls into slabs or nodes of increasing thickness from the surface to the interior.
E. Divide the containment walls into slabs or nodes of increasing thickness from the surface to the interior.
F. Write a computer program to calculate the thermodynamic states and properties in each compartment, and the flow of air and steam among compartments. This was done by incorporating some of the techniques used in t: he MARCH program(Ref. 9).
F. Write a computer program to calculate the thermodynamic states and properties in each compartment, and the flow of air and steam among compartments.
G. Make the necessary calculations and tabulate the results.
This was done by incorporating some of the techniques used in t:he MARCH program(Ref.
9).
G.
Make the necessary calculations and tabulate the results.


                                                                      ~ (
ATTACHMENT TO AEP:N 188A 4.
                                                                            ~     J~
ASSUMPTIONS
ATTACHMENT TO AEP:N    188A                                Page~ 7 7 /7.qf> >
~
: 4. ASSUMPTIONS A. The containment building may be accurately represented as a lower compartment divided into six regions separated by a steam generator or the filtering unit,     the dead ended regions and reactor cavity, the ice condenser and the upper compartment,     for a total of twelve regions.
(
~
J~
Page~
7 7/7.qf> >
A. The containment building may be accurately represented as a lower compartment divided into six regions separated by a steam generator or the filtering unit, the dead ended regions and reactor cavity, the ice condenser and the upper compartment, for a total of twelve regions.
B. The pressure and temperature were uniform throughout each compartment.
B. The pressure and temperature were uniform throughout each compartment.
The air and steam or water vapor formed a homogeneous mixture.
The air and steam or water vapor formed a homogeneous mixture.
C~ The   flow rate of   air and steam among compartments could be adequately modelled using     a form of compressible flow equation(p 3-5, Ref. 10) with an appropriate flow coefficient, flow area opening, specific volumes, and the pressure difference between the compartments. This equation includes an acceleration pressure loss as well as form losses.
C ~ The flow rate of air and steam among compartments could be adequately modelled using a form of compressible flow equation(p 3-5, Ref.
      'The flow coefficients were obtained from Refs. 4 8 5. The flow         .
10) with an appropriate flow coefficient, flow area opening, specific
coefficient for the passage formed by the filtering unit was calculated using Ref. 12, p335-335.
: volumes, and the pressure difference between the compartments.
As was done in Ref. 6, the flow calculated for each time step was limited somewhat by a restriction factor to eliminate the excessive changes in compartment mass in each time step, and the resulting large pressure oscillations that would be observed without it.
This equation includes an acceleration pressure loss as well as form losses.
Ref. 6 calculated the number of moles of air and vapor that must be transferred to bring the pressure of two adjacent compartments to an equilibrium pressure. The number of moles to transfer was calculated for the largest flow passage area for a compartment; flow through smaller areas was then based on flow through this largest area.
'The flow coefficients were obtained from Refs.
The present calculation used a very small time step(0.0001 sec) to utilize a simple restriction factor (/1.4), and avoid calculating moles transferred and flows based on large and small volumes and flow areas.
4 8 5. The flow coefficient for the passage formed by the filtering unit was calculated using Ref.
D. Flow of liquid or water between adjacent compartment floors was also calculated using a weir flow type equation with the difference in water depth. This method was also used in Ref. 16.
12, p335-335.
E. The air was treated as an ideal gas. The value of constant pressure specific heat was assumed constant at 0.240 Btu/ibm/F. The value of constant volume specific heat was also assumed constant and was calculated using Cv = Cp R/778.16 . The internal energy of air was a function of temperature only.
As was done in Ref.
6, the flow calculated for each time step was limited somewhat by a restriction factor to eliminate the excessive changes in compartment mass in each time step, and the resulting large pressure oscillations that would be observed without it.
Ref.
6 calculated the number of moles of air and vapor that must be transferred to bring the pressure of two adjacent compartments to an equilibrium pressure.
The number of moles to transfer was calculated for the largest flow passage area for a compartment; flow through smaller areas was then based on flow through this largest area.
The present calculation used a very small time step(0.0001 sec) to utilize a simple restriction factor (/1.4),
and avoid calculating moles transferred and flows based on large and small volumes and flow areas.
D. Flow of liquid or water between adjacent compartment floors was also calculated using a weir flow type equation with the difference in water depth.
This method was also used in Ref.
16.
E.
The air was treated as an ideal gas.
The value of constant pressure specific heat was assumed constant at 0.240 Btu/ibm/F. The value of constant volume specific heat was also assumed constant and was calculated using Cv = Cp R/778.16 The internal energy of air was a function of temperature only.
F. The steam/water vapor was also treated as an ideal gas when calculating the number of moles in a compartment or its average molecular weight.
F. The steam/water vapor was also treated as an ideal gas when calculating the number of moles in a compartment or its average molecular weight.
Steam properties were taken from Ref. 11.
Steam properties were taken from Ref.
G. The containment walls were semi-infinite slabs, and heat transfer only occurred perpendicular to the thickness. The walls were insulated on the outside surface. They could absorb heat from the air/vapor mixture, but could not loose heat to the outside.
11.
G. The containment walls were semi-infinite slabs, and heat transfer only occurred perpendicular to the thickness.
The walls were insulated on the outside surface.
They could absorb heat from the air/vapor mixture, but could not loose heat to the outside.


ATTACHMENT TO AEP:N   188A
ATTACHMENT TO AEP:N 188A
                                                                      /
/
Page 8
Page 8
                                                                          ~)'~/e a H. The   floor between the upper and lower compartments was treated as a wall insulated at the center line." Each room could access half the wall thickness. The walls separating the lower compartment from the dead-ended region was treated the same. The walls between the upper compartment and the ice condenser were neglected.
~)'~/e a H. The floor between the upper and lower compartments was treated as a
J. The metal equipment in the lower and upper compartments was also modelled as a slab, and heat flow and temperature were calculated similarly to the concrete walls.
wall insulated at the center line." Each room could access half the wall thickness.
The walls separating the lower compartment from the dead-ended region was treated the same.
The walls between the upper compartment and the ice condenser were neglected.
J.
The metal equipment in the lower and upper compartments was also modelled as a slab, and heat flow and temperature were calculated similarly to the concrete walls.
K. The temperature of containment air was initially 90 F, the pressure was 14.7 psia, and the relative humidity was 100%.
K. The temperature of containment air was initially 90 F, the pressure was 14.7 psia, and the relative humidity was 100%.
L. The temperature of the containment walls was initially 90 F.
L. The temperature of the containment walls was initially 90 F.
M. All ice condenser lower plenum inlet doors and outlet intermediate deck doors were assumed to be open.
M. All ice condenser lower plenum inlet doors and outlet intermediate deck doors were assumed to be open.
N. The ice condenser baskets and ice were treated as a wall with heat transfer being calculated as in. item F. The heat transferred from the steam/air mixture to the ice was calculated at each time step.
N. The ice condenser baskets and ice were treated as a wall with heat transfer being calculated as in. item F.
The heat transferred from the steam/air mixture to the ice was calculated at each time step.
The corresponding amount of ice melt was then calculated.
The corresponding amount of ice melt was then calculated.
O. Emissivity of the gas mixture to the walls was 0.3 P. No credit   was allowed for the containment spray system.
O. Emissivity of the gas mixture to the walls was 0.3 P.
OTHER   INPUTS/DATA The compartment volumes,     wall surface areas, thicknesses, physical properties, etc. were taken from Refs 6 and 7. The wall surface areas were re-apportioned for the new volumes based on the amount of perimeter or arc covered by the volume(Ref. 8). These are listed in the computer output. The containment walls are described in the Attachments.
No credit was allowed for the containment spray system.
OTHER INPUTS/DATA The compartment volumes, wall surface
: areas, thicknesses, physical properties, etc.
were taken from Refs 6 and 7.
The wall surface areas were re-apportioned for the new volumes based on the amount of perimeter or arc covered by the volume(Ref. 8).
These are listed in the computer output.
The containment walls are described in the Attachments.
Only a portion of the floor surface area between the upper compartment and the lower compartment was considered.
Only a portion of the floor surface area between the upper compartment and the lower compartment was considered.
The inside diameter of the accumulator line was 8.75 inches(Ref. 19) and the maximum blowdown   flow rate from   it was taken as 24400 lb/sec/ft**2 (Fig. 2-3, Ref. 3). This value corresponds to the mass flux at 2250 psia and 540 F, the conditions of cold-leg saturated liquid. It was kept constant for the entire transient to assure a very conservative flow rate. For comparing the LOCA01 program against the Westinghouse TMD results(Ref. 4) and the MPR Associates results(Ref. 5), the cold leg diameter used was 31 inches, the blowdown flow rate used was 9882.777, and the temperature was 534.6 F. These values gave the 103,600 lb/hr and 530 btu/ibm inputs respectively of p IV-2, Ref. 5.
The inside diameter of the accumulator line was 8.75 inches(Ref.
19) and the maximum blowdown flow rate from it was taken as 24400 lb/sec/ft**2 (Fig. 2-3, Ref. 3).
This value corresponds to the mass flux at 2250 psia and 540 F, the conditions of cold-leg saturated liquid. It was kept constant for the entire transient to assure a very conservative flow rate.
For comparing the LOCA01 program against the Westinghouse TMD results(Ref.
: 4) and the MPR Associates results(Ref.
5), the cold leg diameter used was 31 inches, the blowdown flow rate used was 9882.777, and the temperature was 534.6 F.
These values gave the 103,600 lb/hr and 530 btu/ibm inputs respectively of p IV-2, Ref. 5.


ATTACHMENT TO AEP:N 188A                             P4g
ATTACHMENT TO AEP:N 188A P4g
                                                                        /<9 /g~
/<9 /g~
The number   of ice baskets was 1944; 'their length was 48 feet,; their diameter and pitch were 12 and 14 inches respectively (Ref. 18).
The number of ice baskets was 1944; 'their length was 48 feet,; their diameter and pitch were 12 and 14 inches respectively (Ref. 18).
The surface of the walls and other structures within the ice condenser compartment were neglected.
The surface of the walls and other structures within the ice condenser compartment were neglected.
Natural convection and condensation heat transfer coefficients between the walls and the steam/air mixture were calculated using the equations of pp 6-13 to 6-16(Ref. 9) Radiation heat transfer was also included.
Natural convection and condensation heat transfer coefficients between the walls and the steam/air mixture were calculated using the equations of pp 6-13 to 6-16(Ref.
Where steam/air velocities were high enough forced convection heat transfer was included using Ref. 13, p148 for the walls and pl76 for the ice baskets.
9)
Heat transfer through the slab walls was modelled by dividing each wall into adjacent layers of varying thickness, using pp 6-15 and 6-16 (Ref. 9). '
Radiation heat transfer was also included.
The ice condenser was initially at 27 F, and   it contains 2,370,000 lbs of ice also at 27 F. Ice properties were from Ref. 14.
Where steam/air velocities were high enough forced convection heat transfer was included using Ref.
13, p148 for the walls and pl76 for the ice baskets.
Heat transfer through the slab walls was modelled by dividing each wall into adjacent layers of varying thickness, using pp 6-15 and 6-16 (Ref. 9).
The ice condenser was initially at 27 F, and it contains 2,370,000 lbs of ice also at 27 F. Ice properties were from Ref.
14.
 
ATTACHMENT TO AEP:N 1188A
'/>u Page 10 5.
CONTENTS A.
COMPARTMENT ENERGY..
The total internal energy of each compartment was calculated using the First Law of Thermodynamics for an open system.
The change in energy equals the mass flow of enthalpy in minus the mass flow of enthalpy out minus the heat transferred to the walls.
The new internal energy was calculated in subroutine ENERGY using U2=
mi *hi


                                                                                '/>u ATTACHMENT TO AEP:N        1188A                                      Page 10
me*he
: 5. CONTENTS A. COMPARTMENT ENERGY..
The  total internal    energy of each compartment was calculated using the First Law  of Thermodynamics for an open system. The change in energy equals the mass  flow of enthalpy in minus the mass flow of enthalpy out minus the heat transferred to the walls. The new internal energy was calculated in subroutine ENERGY using U2=        mi  *hi              me*he         Q  +  Ul Each  flow rate in and out          was averaged        over two time steps using mi =    (  mi(2)    +  mi(1)    )  / 20 B. INITIAL COMPARTMENT MASSES The    initial volume    of the ice was calculated using Ref. 14 with, the            initial ice  mass. The volume of air and vapor in the ice condenser was provided in Refs. 6    or 7. The total volume of the ice condenser was calculated by adding the volumes of ice and            air.
VTOT(1,7) = W(1,5)
* VICE where W(1,7) = Ice mass VICE    =  specific      volume of      ice VTOT ( 3 I 7 )  VTOT ( 2 g 7 ) + VTOT ( 1 I 7 )
where VTOT(3,7)      total ice condenser volume VTOT(2,7)      air and vapor volume VTOT(1,7)      ice volume 7      the ice condenser compartment identification no.
The  initial water      vapor mass in each compartment, including the ice condenser,      was calculated using the steam tables with initial pressure, temperature, relative humidity, and open or void compartment volume.
W(2,NC) = VTOT(2,NC)          /  VGT( T(NC)      )
                                                          * ( RH(NC) / IOO.  )
where VTOT(2,NC) = open volume VGT(T(NC)') = specific volume              of vapor at temperature  T(NC)
RH(NC)        =    relative humidity


(P%
Q
ATTACHMENT TO AEP:N       188A                               Page ll 7/~~/g s The initial air     mass   in   each compartment was calculated using the     ideal gas law with   partial pressure of air, temperature,       and open volume.
+
W(4,NC) = P(2,NC)
Ul Each flow rate in and out was averaged over two time steps using mi =
( mi(2)
+ mi(1)
) / 20 B. INITIALCOMPARTMENT MASSES The initial volume of the ice was calculated using Ref.
14 with,the initial ice mass.
The volume of air and vapor in the ice condenser was provided in Refs.
6 or 7.
The total volume of the ice condenser was calculated by adding the volumes of ice and air.
VTOT(1,7)
= W(1,5)
* VICE where W(1,7)
= Ice mass VICE
= specific volume of ice VTOT( 3 I 7 )
VTOT( 2 g 7 )
+ VTOT( 1 I 7 )
where VTOT(3,7)
VTOT(2,7)
VTOT(1,7) 7 total ice condenser volume air and vapor volume ice volume the ice condenser compartment identification no.
The initial water vapor mass in each compartment, including the ice condenser, was calculated using the steam tables with initial pressure, temperature, relative humidity, and open or void compartment volume.
W(2,NC)
= VTOT(2,NC) / VGT( T(NC)
) *
( RH(NC) / IOO.
)
where VTOT(2,NC)
= open volume VGT(T(NC)') = specific volume of vapor at temperature T(NC)
RH(NC)
= relative humidity
 
ATTACHMENT TO AEP:N 188A (P%
Page ll 7/~~/g s The initial air mass in each compartment was calculated using the ideal gas law with partial pressure of air, temperature, and open volume.
W(4,NC)
= P(2,NC)
* 144.
* 144.
* VTOT(2,NC) / R /         ( T(NC) + 460.   )
* VTOT(2,NC) / R /
where P(2,NC) =     partial pressure of air
( T(NC)
                    =   total pressure partial pressure of water vapor R         =   ideal gas constant for air C. FLOW RATES BETWEEN COMPARTMENTS The flow rate of gas or vapor between adjacent compartments         was   calculated using p 3-5, Ref. 10 F() =     ( ( 2.0
+ 460.
)
where P(2,NC)
= partial pressure of air
= total pressure partial pressure of water vapor R
= ideal gas constant for air C.
FLOW RATES BETWEEN COMPARTMENTS The flow rate of gas or vapor between adjacent compartments was calculated using p 3-5, Ref.
10 F()
=
(
( 2.0
* gc
* gc
* 144.
* 144.
Line 193: Line 381:
* AREA()**2 ) /
* AREA()**2 ) /
( 2.0
( 2.0
* dv() + KLS()
* dv()
* v() ) )**1/2 where DP()       pressure difference between compartments AREA()      flow area KLS()        flow loss coefficient v()        average specific volume of mixture dv()        difference between v() between compartments The amount   of air and vapor mass transferred in each time step           was calculated using DF() =     F()
+ KLS()
* TS   / DPDFS where TS       = time step DPDFS   = a flow     limiting factor(1.4) for multiple flow   paths through each compartment to help avoid pressure oscillations and which helped benchmark the program against the TMD and MPR results.
* v()
The flow of'iquid water between adjacent compartments was calculated using                 a version of the weir flow equation of p 479, Ref. 15.
) )**1/2 where DP()
F(l,NP,) = Cflw
AREA()
KLS()
v()
dv()
pressure difference between compartments flow area flow loss coefficient average specific volume of mixture difference between v() between compartments The amount of air and vapor mass transferred in each time step was calculated using DF()
=
F()
* TS
/ DPDFS where TS
= time step DPDFS
= a flow limiting factor(1.4) for multiple flow paths through each compartment to help avoid pressure oscillations and which helped benchmark the program against the TMD and MPR results.
The flow of'iquid water between adjacent compartments was calculated using a
version of the weir flow equation of p 479, Ref.
15.
F(l,NP,)
= Cflw
* rho
* rho
* Width * ( Z(NF(NP)) Z(NT(NP)) ) / 12.
* Width *
where Cflw        weir flow coeff; taken large to accommodate inertia.
( Z(NF(NP))
rho       density of water.
Z(NT(NP))
Width       a characteristic width between adjacent compartments.
) / 12.
Z(NF,)      depth of water in 'from'ompartment, larger than Z(NT,)
whereCflw rho Width Z(NF,)
Z(NT,)
Z(NT,)
weir flow coeff; taken large to accommodate inertia.
density of water.
a characteristic width between adjacent compartments.
depth of water in 'from'ompartment, larger than Z(NT,)


                                                                          '/'3q               ~ d ATTACHMENT TO AEP:N    1188A                                    P~s~                 >> 7/z(z~
ATTACHMENT TO AEP:N 1188A
The flow of enthalpy per time step from       a compartment was   calculated using DH(j,NP) = DF(j,NP)
'/'3q
* H(j,NC) where H(j,NC)   = the enthalpy of fluid type j in compartment       NC DF(j,NP)   = mass   flow per time step along flow path NP j   = liquid, vapor, and air D. NEW COMPARTMENT   MASSES..
~ d P~s~ >>
The new masses of liquid,         vapor, and air were calculated using the amounts of mass transferred averaged         over the last two time steps using, W(j,NC) = W(j,NC)     +   ( DF(j,in, 1) +   DF(j,in, 2) ) / 2.0 )
7/z(z~
( DF(jioutg1) +   DF(jgoutg2) ) / 2 ' )
The flow of enthalpy per time step from a compartment was calculated using DH(j,NP)
where DF()   mass flow per time step
= DF(j,NP)
          ?
* H(j,NC) where H(j,NC) = the enthalpy of fluid type j in compartment NC DF(j,NP)
liquid, vapor,     and air in      flow path into the compartment out    flow path from the compartment 1,2    previous, present time step For gas flow the 'flow from'ompartment was always at a pressure greater than the 'flow into'ompartment. Pressure in each compartment was checked each time step to identify from and to numbers. For 1'iquid flow the 'flow from'ompartment had a greater depth of liquid than the 'flow into'ompartment.
= mass flow per time step along flow path NP j
= liquid, vapor, and air D.
NEW COMPARTMENT MASSES..
The new masses of liquid, vapor, and air were calculated using the amounts of mass transferred averaged over the last two time steps
: using, W(j,NC) = W(j,NC)
+
( DF(j,in, 1)
+ DF(j,in, 2)
) / 2.0
)
( DF(jioutg1)
+ DF(jgoutg2)
) / 2 '
)
where DF()
?in out 1,2 mass flow per time step liquid, vapor, and air flow path into the compartment flow path from the compartment
: previous, present time step For gas flow the 'flow from'ompartment was always at a pressure greater than the 'flow into'ompartment.
Pressure in each compartment was checked each time step to identify from and to numbers.
For 1'iquid flow the 'flow from'ompartment had a greater depth of liquid than the 'flow into'ompartment.


P  IV/ Pg ATTACHMENT TO AEP:N   1188A                                   Page 13
ATTACHMENT TO AEP:N 1188A P IV/ Pg Page 13~)~~/>>
                                                                              ~)~~/>>
E.
E. NEW THERMODYNAMIC STATE OF SUPERHEATED COMPARTMENTS The new   pressure, temperature, etc., of each superheated compartment following the additions or removals of mass and energy was calculated by balancing the total volume with component(vapor and air) volumes, and balancing total energy with component, energy. This gave two equations( volume and energy ) and two unknowns( total pressure and temperature ). The system was solved by iteration with a Newton-Raphson technique for non-linear equations,
NEW THERMODYNAMIC STATE OF SUPERHEATED COMPARTMENTS The new pressure, temperature, etc., of each superheated compartment following the additions or removals of mass and energy was calculated by balancing the total volume with component(vapor and air) volumes, and balancing total energy with component, energy.
( pp 37-39, Ref. 17)     The two equations were expressed as the following two functions, Gl(P2,T2)   = VTOT(3,NC) (
This gave two equations(
                    = U(4,NC)
volume and energy
Mg*Vg(P9,T2) + Ma*Va(Pa,T2) ) / 2.0 G2(P2,T2)                     ( Mg*Ug(Pg,T2) + Ma*Ua(T2) )
) and two unknowns( total pressure and temperature
where VTOT(3,NC)     compartment    total volume U(4,NC)         compartment     total energy P2,T2          new total pressure and temperature Pg,Pa          partial pressure of vapor, air Mg,Vg,Ug      mass,   specific volume, and specific energy of vapor Ma,Va,Ua      mass,   specific volume, and specific energy of air Additional properties such as specific enthalpy, xelative humidity, etc.           were then calculated using the       new P2 and T2.
). The system was solved by iteration with a Newton-Raphson technique for non-linear equations,
F. NEW THERMODYNAMIC STATE OF SATURATED COMPARTMENTS The new   pressure, temperature, etc., of each saturated compartment following the additions or removals of mass and energy was calculated by balancing the total energy with component energy. This gave one equation( energy ) and one unknown( temperature ). The system was solved by iteration with the bisection technique.( p 18, Ref. 17)
( pp 37-39, Ref.
The energy balance equation was expressed as the following function, Gl(T2)   = U(4,NC)   ( Mf(T2)*Uf(T2) + Mg(T2)*U9(T2)     + Ma*Ua(T2) )
17)
where U(4,NC)     = compartment
The two equations were expressed as the following two functions, Gl(P2,T2)
                      = new temperature total energy T2 Mf,Mg,Ma     = mass of    liquid, vapor, and air Uf,Ug,Ua     = internal energy      of liquid, vapor, air Additional properties such as pressure, specific enthalpy, relative humidity, etc. were then 'calculated using the new T2 and the saturated properties.
= VTOT(3,NC)
( Mg*Vg(P9,T2) + Ma*Va(Pa,T2)
) / 2.0 G2(P2,T2)
= U(4,NC)
( Mg*Ug(Pg,T2)
+ Ma*Ua(T2)
)
where VTOT(3,NC)
U(4,NC)
P2,T2 Pg,Pa Mg,Vg,Ug Ma,Va,Ua compartment total volume compartment total energy new total pressure and temperature partial pressure of vapor, air
: mass, specific volume, and specific energy of vapor
: mass, specific volume, and specific energy of air Additional properties such as specific enthalpy, xelative humidity, etc.
were then calculated using the new P2 and T2.
F.
NEW THERMODYNAMIC STATE OF SATURATED COMPARTMENTS The new pressure, temperature, etc., of each saturated compartment following the additions or removals of mass and energy was calculated by balancing the total energy with component energy.
This gave one equation(
energy
) and one unknown( temperature
). The system was solved by iteration with the bisection technique.(
p 18, Ref.
17)
The energy balance equation was expressed as the following function,
= compartment total energy
= new temperature
= mass of liquid, vapor, and air
= internal energy of liquid, vapor, air Gl(T2) = U(4,NC)
( Mf(T2)*Uf(T2) + Mg(T2)*U9(T2) + Ma*Ua(T2)
)
where U(4,NC)
T2 Mf,Mg,Ma Uf,Ug,Ua Additional properties such as pressure, specific enthalpy, relative humidity, etc.
were then 'calculated using the new T2 and the saturated properties.


ATTACHMENT TO AEP:N   188A G- HEAT TRANSFER TO CONTAINMENT WALLS(SLAB)
ATTACHMENT TO AEP:N 188A G-HEAT TRANSFER TO CONTAINMENT WALLS(SLAB)
Heat   transfer to the slab walls by natural convection and condensation was calculated based on the methods of Ref. 9, pp 6-13, 6-15. A radiation heat transfer coefficient and a forced convection coefficient were also included for this calculation. A total heat transfer coefficient was calculated by summing the individual heat flows.
Heat transfer to the slab walls by natural convection and condensation was calculated based on the methods of Ref.
qt = qc + qn + qr'               qf ht*(Tb Tw) = hc*(Tsat Tw) + hn*(Tb Tw) + hr*(Tb Tw) +
9, pp 6-13, 6-15.
hf*( Tb     Tw)
A radiation heat transfer coefficient and a forced convection coefficient were also included for this calculation.
Solving for ht gives, ht = hc*(Tsat         Tw)/(Tb   Tw)   +   hn   + hr   + hf where qt              total heat flux(Btu/hr/ft**2) qc,qn,qr,qf      heat flux due to condensation, natural convection, radiation, and forced convection.
A total heat transfer coefficient was calculated by summing the individual heat flows.
ht              total heat transfer coefficient(Btu/hr/ft**2/F) hc,hn,hr,hf      heat transfer coefficients due to condensation, natural convection, radiation, and forced convection.
qt
Tb,Tsat,Tw      bulk and saturation temperatures of gas mixture and wall surface temperature.
=
Condensation was assumed to occur only the  dew  point temperature.
qc
if the wall temperature was less than
+
qn
+
qr' qf ht*(Tb Tw)
= hc*(Tsat Tw)
+ hn*(Tb Tw)
+ hr*(Tb Tw) +
hf*( Tb Tw)
Solving for ht gives, ht
=
hc*(Tsat Tw)/(Tb Tw)
+
hn
+
hr
+
hf whereqtqc,qn,qr,qf hthc,hn,hr,hf Tb,Tsat,Tw total heat flux(Btu/hr/ft**2) heat flux due to condensation, natural convection, radiation, and forced convection.
total heat transfer coefficient(Btu/hr/ft**2/F) heat transfer coefficients due to condensation, natural convection, radiation, and forced convection.
bulk and saturation temperatures of gas mixture and wall surface temperature.
Condensation was assumed to occur only if the wall temperature was less than the dew point temperature.


g / t./        v)+!
ATTACHMENT TO AEP:N 1188A H.
ATTACHMENT TO AEP:N     1188A zg ~~
HEAT TRANSFER WITHIN CONTAINMENT WALLS(SLABS) g
H. HEAT TRANSFER WITHIN CONTAINMENT WALLS(SLABS)
/ t./
The walls were     divided into adjacent slabs or nodes of increasing thickness as per Ref. 9.     The heat transfer coefficient for conduction heat transfer between adjacent slabs was calculated using ht(n) = k / ( x(n) x(n-1) )
v)+!
where ht(n) = total   heat transfer coefficient(Btu/hr/ft**2/F) node n x(n) = location or coordinate of node n k:     = thermal conductivity of concrete(Btu/hr/ft/F)
zg ~~
The conduction heat transfer entering node n from node (n-1) on the left) was calculated using, qw(n') = ht(n) * ( Tw(n-1) Tw(n) )
The walls were divided into adjacent slabs or nodes of increasing thickness as per Ref. 9.
And the conduction heat transfer leaving node n to node (n+1).on the right) was calculated using, qw(n+1) = ht(n+1) *       ( Tw(n)   Tw(n+1) )
The heat transfer coefficient for conduction heat transfer between adjacent slabs was calculated using ht(n)
The temperature     change   of the   first node was calculated using       a heat balance:
= k /
qw(2) )*TS /
( x(n) x(n-1)
DTw(l) =    ( QWavg                      ( rho
)
where ht(n)
= total heat transfer coefficient(Btu/hr/ft**2/F) node n
x(n)
= location or coordinate of node n
k:
= thermal conductivity of concrete(Btu/hr/ft/F)
The conduction heat transfer entering node n from node (n-1) on the left) was calculated using, qw(n')
= ht(n)
( Tw(n-1)
Tw(n)
)
And the conduction heat transfer leaving node n to node (n+1).on the right) was calculated using, qw(n+1)
= ht(n+1) *
( Tw(n)
Tw(n+1)
)
The temperature change of the first node was calculated using a heat balance:
DTw(l) =
(
QWavg qw(2)
)*TS /
( rho
* dx(l)
* dx(l)
* Cp )
* Cp
where QWavg         ( qt(TS=1) + qt(TS=2) ) / 2.0 time averaged heat flux entering surface of node conduction heat flux leaving node 1 to node 2 l.
)
qw(2)
where QWavg qw(2)
TS            time step size rho,Cp        density and heat capacity of concrete or steel.
TS rho,Cp dx(1)
dx(1)        thickness of control volume, node 1 The temperature     changes   of the other   nodes was   calculated in   a   similar manner using:
( qt(TS=1)
DTw(n) =   ( qw(n)     qw(n+1) )*TS     / ( rho
+ qt(TS=2)
) / 2.0 time averaged heat flux entering surface of node l.
conduction heat flux leaving node 1 to node 2
time step size density and heat capacity of concrete or steel.
thickness of control volume, node 1
The temperature changes of the other nodes was calculated in a similar manner using:
DTw(n)
=
( qw(n) qw(n+1)
)*TS /
( rho
* dx(n)
* dx(n)
* Cp )
* Cp
where qw(n)     = heat   flux leaving II node n-1 and II        II entering II node   n qw(n+1)                                   n                         n+1 dx(n)     = thickness of control volume, node       n
)
where qw(n)
= heat flux leaving node n-1 and entering node n
qw(n+1)
II II n
II II n+1 dx(n)
= thickness of control volume, node n


ATTACHMENT TO AEP:N     188A 76~))q
ATTACHMENT TO AEP:N 188A 6.
: 6. REFERENCES 1 ~ Memo of May 27, 1993, from S.A. Hover to T.J. Crawford, of Fibrous Material on Recirculation Pump Screen'.
REFERENCES 76~))q 1 ~
titled 'Effect 2   ~ Drawing No. 107C-890301-H,       from American Air Filter Co., Inc.,
Memo of May 27,
Louisville, Ky.,     1972.
: 1993, from S.A. Hover to T.J. Crawford, titled 'Effect of Fibrous Material on Recirculation Pump Screen'.
: 3. Larson,     J.R., System Analysis Handbook, NUREG/CR-4041, EGG-2354, Revision 1, November, 1985.
2 ~
: 4. Updated F.S.A.R. for D.C. Cook Plant, Tables 14.3.4-15, 14.3.4-16, and Figure 14.3.4-18
3.
: 5. MPR   Associates,   Inc., Ice   Condenser Containment Independent Analysis Program Final Report,     MPR-340, April, 1972.
Drawing No.
: 6. Technical Assessment Section calculation N-921001, Containment Building Pressure and Temperature in Event of DHR Failure While in Mid-Loop Operation, January, 1993.
107C-890301-H, from American Air Filter Co., Inc.,
7 ~ Containment Data Collection Notebook, D.C. Cook Nuclear Plant         I.P.E.,
Louisville, Ky., 1972.
Larson, J.R.,
System Analysis Handbook, NUREG/CR-4041, EGG-2354, Revision 1,
: November, 1985.
4.
5.
6.
Updated F.S.A.R. for D.C. Cook Plant, Tables 14.3.4-15, 14.3.4-16, and Figure 14.3.4-18 MPR Associates, Inc., Ice Condenser Containment Independent Analysis Program Final Report, MPR-340, April, 1972.
Technical Assessment Section calculation N-921001, Containment Building Pressure and Temperature in Event of DHR Failure While in Mid-Loop Operation,
: January, 1993.
7
~
8.
9.
Containment Data Collection Notebook, D.C.
Cook Nuclear Plant I.P.E.,
prepared by Fauske 6 Associates, Inc., January, 1992.
prepared by Fauske 6 Associates, Inc., January, 1992.
: 8. A.E.P. drawings 12-3181-14,           1-5688-10, and 1-5699-10.
A.E.P. drawings 12-3181-14, 1-5688-10, and 1-5699-10.
: 9. NUREG/CR-3988, BMI-2115,           MARCH 2 Code Description and Users Manual.
NUREG/CR-3988, BMI-2115, MARCH 2 Code Description and Users Manual.
: 10. Steam,     Its Generation and Use., 40th ed., Babcock 6 Wilcox Company, Barberton, Ohio, 1992.
10.
A.S.M.E. Steam Tables, Thermodynamic and Transport Properties of Steam, 2nd ed., 1967.
Steam, Its Generation and Use.,
: 12. Idelchik, I.E., and Fried, E., Flow Resistance: A Design Guide for Engineers., Hemisphere Publishing Co., New York, 1989.
40th ed.,
: 13. Holman, J.P., Heat Transfer, 3rd. ed. McGraw-Hill Book Co.,
Babcock 6 Wilcox Company, Barberton,
: Ohio, 1992.
A.S.M.E. Steam Tables, Thermodynamic and Transport Properties of Steam, 2nd ed.,
1967.
12.
13.
Idelchik, I.E., and Fried, E., Flow Resistance:
A Design Guide for Engineers.,
Hemisphere Publishing Co.,
New York, 1989.
Holman, J.P.,
Heat Transfer, 3rd. ed. McGraw-Hill Book Co.,
New York, 1972.
New York, 1972.
: 14. Perry, R.H., and         Chilton, C.H., Chemical Engineer's Handbook, 5th ed.,
: 14. Perry, R.H.,
and Chilton, C.H., Chemical Engineer's
: Handbook, 5th ed.,
Table 3-275.
Table 3-275.
: 15. Streeter, V.L., Fluid Mechanics, 5th ed., McGraw-Hill         Book Co.,
: 15. Streeter, V.L., Fluid Mechanics, 5th ed., McGraw-Hill Book Co.,
New York, 1971.
New York, 1971.
: 16. Technical Assessment           Section calculation N-920101, Fire Protection Water Storage Tanks     for Unit   1 6 Unit 2 at D.C. Cook Plant, January, 1992.
: 16. Technical Assessment Section calculation N-920101, Fire Protection Water Storage Tanks for Unit 1
6 Unit 2 at D.C. Cook Plant,
: January, 1992.


ATTACHMENT TO AEP:N 188A
ATTACHMENT TO AEP:N 188A
: 17. Grove, W.E.,   Brief Numerical Methods., Prentice-Hall, Inc , 1966.
: 17. Grove, W.E., Brief Numerical Methods., Prentice-Hall, Inc 1966.
: 18. Various written communications between Nuclear Safety Section and Technical Assessment(Attached).
: 18. Various written communications between Nuclear Safety Section and Technical Assessment(Attached).
: 19. Verbal communications between S.A. Hover   of Nuclear Operations and T.J. Crawford of Technical Assessment.
: 19. Verbal communications between S.A. Hover of Nuclear Operations and T.J. Crawford of Technical Assessment.
: 20. Tubeco Inc., drawing 1-51-31, isometric pipe drawing.
20.
Tubeco Inc., drawing 1-51-31, isometric pipe drawing.


ATTACHMENT TO AEP:N 188A                             Page 18 J>pf~
ATTACHMENT TO AEP:N 188A Page 18 J>pf~
: 7. ATTACHMENTS A. Sketch of Containment with Compartments and Flow Paths B. Descriptions of Compartment Volumes and Containment Walls or Slabs C. Flow Diagram of Computer Program LOCA01.
7.
D. Selected References.
ATTACHMENTS A.
E. Program Listing of LOCA01.
Sketch of Containment with Compartments and Flow Paths B.
F. Program outputs for; accumulator leg break(d=8.75), run time = 0.1112 sec cold leg break(d=31.), run time = 0.2752 sec
Descriptions of Compartment Volumes and Containment Walls or Slabs C.
Flow Diagram of Computer Program LOCA01.
D.
Selected References.
E.
Program Listing of LOCA01.
F.
Program outputs for; accumulator leg break(d=8.75),
run time = 0.1112 sec cold leg break(d=31.),
run time = 0.2752 sec


                                                                                                                "'"(w~
ATTACHMENT TO AEP:N 188A
ATTACHMENT TO AEP:N                188A                                                                  Page 19 l   jg         o AREA REACTOR COOLANT                                                 DOOR SYSTEM COMPARTMENT                             ,NO.         3                                 ICE CONDENSER
"'"(w~
                                                                                                  ~ )
Page 19 l jg o
: <c                       STEAM GENERATOR
REACTOR COOLANT SYSTEM COMPARTMENT AREA
                                                                                                                ) ~
,NO.
r')                                       l3 2'og                        ~   ~
3 DOOR ICE CONDENSER
C
~ )
                          ~ t
: <c
                            /                             ~ ~
)
h          ~
~
                                                                                                                              ~ a 3
STEAM GENERATOR 2'og r')
A
~
                        ~ ~    v')V1                    'V e$
~
AREA                          ,i   C ARE.
C l3 AREA 2 DOOR
2 DOOR C'
~t
l                                     NO. 4 D
/
                                      )                                                                                        ~ (
~ ~
                      ~ ~
A v
                        ~ ~
V1
                        ~ H     0+ ~
') e$
,i C
h
~
~ ~
'V C'
l 3
~ a ARE.
NO. 4 D
~ ~~ ~
~ H
)
0+ ~
'v~r-
~ ~ )
~ (
r
r
                                'v~r-                                                                                        % ~
% ~
                                                                                                                      ~~ )
~l-l
      ~l-l ui                    ~  k       ~ s ~
\\
ui
:C ~
i~
r OR r ~
~
~,
~ (y )
AREA NO. I DO REACTOR COOLANT SYSTEM RUPTURE
~
k
~ s ~
l,5
l,5
:C ~ i ~
~..a..~.
~
~I r C
~
FLOV/'UCT UNDERNEATH REFUELLING CANAL ~
AREA jl NO.
5 DOOR
>(). ~7zs'e J
+(z. 2Y'vr la i3 -.'/0 <>~
V<q=2y u~ v V yP
>5. X"Q~
PLANT DESIGN - PLAN VIE%V SECTION OF REACTOR CCO3 ANT SYSTEM.i COhiPARTi.fENT
~O
.7
) Qv ryg
 
ATTACHMENT TO AEP:N 188A 0
fg
)
00 l IP/g~
f'age 20
~Jz.~gg~
ee 0,
F1N COMPARTMENT /
'(. 6 I
r
r
  \
'v 1CC UPPER COKP ARTIST g5 61TK 33 (0
AREA                                                                                                              AREA jl NO. I DO OR                                                                                                    NO. 5 DOOR r ~  ~ ~
1CC Qr I
(y~, )    ~ I r
IS,Q I
                                                                                  ~ ..a ..~.
I C
C    ~
.G.i Qr 1CC Jg~ o
                                                                                                ~
/p
REA CTOR COOLANT                                                  FLOV/'UCT SYSTEM RUPTURE                                                UNDERNEATH REFUELLING CANAL ~
< 8 FiN CDllPMWKNT
PLANT DESIGN - PLAN VIE%V SECTION OF REACTOR CCO3 ANT SYSTEM.i COhiPARTi.fENT J
~/
  >().    ~7zs'e
O 0
  +(z. 2Y'vr                                                                                            ~O .7    )    Qv ryg la i3 -.'/0  <>~
: g. -
V<q=2y      u~ v V yP    >5. X"Q~
~
 
ATTACHMENT TO AEP:N      188A l IP/g~
f'age  20 fg  )      0                          ~Jz.~gg~
0                              0 r
F1N COMPARTMENT /        'v UPPER COKP ARTIST ee                                        1CC                g5
                        '(. 6 I
0, 61TK 33 (0
Qr                                Qr I
IS,Q         .G.i                                 Jg~ o I
1CC                                        1CC
                                                                    /p I                                            <
C                                                      8 FiN CDllPMWKNT               ~
                                                          /
O         0
: g. - ~


ATTACHMENT TO   AEP'NRC'1188A                                                       Page 21
ATTACHMENT TO AEP'NRC'1188A Page 21
            = 9~~$
= 9~~$
i ~ M SG                                              lq
SG
                                                                    ~
) Rgb~
..-vg 27<$ 0 i=7) ltu'0
~
i
~ M
~
7 lq 0 = )~"
7
7
                                ) Rgb~
~ /v h= ) ~'t IC3 0
                    ..-vg 0 =  )~"  ~
MS A=)o 9o o'4
                                                                                        /v 27<$ 0            i=7)           ltu'0                                 7 h= ) ~'t                    IC 3 9o o'4 0                                      /i ""             QiC.                       )ro>g =
/i""
                                                                                        ) Z4 1~>~
SG 3 QiC.
MS                                                                      P  ~Zgo3
)VSY9b P ~Zgo3
                                                      )VSY9b A=)o SG 3
)ro>g =
) Z4 1~>~
7 R
7 R
D4                 IC 4
D4 IC4
          >7'r$ 3 ~'                                          Ir A-)) 3 w
>7'r$3 ~
n )(      Jj ti: i-r SG R
w n )(
DUCT                                                  5               I C5 0~ )5c.
Jj A-)) 3 Ir ti: i-r SG DUCT R
4=72.             2,Z 4'o,i REACTOR CONTAINMENT SUBVOLUMES AND F'LOW PATHS
5 I C5 4=72.
2,Z 4'o,i 0~ )5c.
REACTOR CONTAINMENTSUBVOLUMES AND F'LOW PATHS


                                                              /pp ATTACHMENT TO AEP:   1188A                         Page 22
ATTACHMENT TO AEP:
                                                                  ~ ~/~~
1188A COMPARTMENT NUMBERS AND VOLUMES(Refs.
COMPARTMENT NUMBERS AND VOLUMES(Refs. 4 a 5 )
4 a
No.               Description                 Volume (ft**3)
5
Break region in Lower Compartment       27 250.
)
between Refueling Canal and Steam Generator No. 2 (S/G 2)
< /pp Page 22
Volume between S/G   2 and             19 000.
~ ~/~~
Ventilation  Unit.
No.
Volume between   Ventilation Unit and 19  000.
Description Break region in Lower Compartment between Refueling Canal and Steam Generator No.
S/G 3 Volume between S/G   3 and S/G 4       90 000.
2 (S/G 2)
Volume between S/G   4 and S/G 1       38 000.
Volume between S/G 2 and Ventilation Unit.
Volume between S/G   1 and Refueling   22 500.
Volume (ft**3) 27 250.
Canal Ice Condenser(void volume)             126 940.
19 000.
Upper Compartment                      745 896.
Volume between Ventilation Unit and S/G 3
Dead Ended Region Housing                27 450.
Volume between S/G 3 and S/G 4
Accumulators 2 and 3 10     Dead Ended Region   Instrument Room     17 111.
Volume between S/G 4 and S/G 1
Dead Ended Region Housing                27 450.
Volume between S/G 1 and Refueling Canal 19 000.
Accumulators 1 and 4 12     Reactor Cavity                           19 731.
90 000.
38 000.
22 500.
Ice Condenser(void volume)
Upper Compartment Dead Ended Region Housing Accumulators 2 and 3
126 940.
745 896.
27 450.
10 Dead Ended Region Instrument Room Dead Ended Region Housing Accumulators 1 and 4
17 111.
27 450.
12 Reactor Cavity 19 731.


ATTACHMENT TO AEP:N     188A                           Page 23 z/z ~g>
ATTACHMENT TO AEP:N 188A Page 23 z/z ~g>
DESCRIPTION OF CONTAINMENT WALLS OR HEAT SINK SLABS(Refs. 4   5: 5)
DESCRIPTION OF CONTAINMENT WALLS OR HEAT SINK SLABS(Refs.
No.       Description               Surface Area Thickness Removes Heat (ft**2)     (ft)   From Cmpt 1 Between Cmpts     1 a'nd   9     1  392. 3.0/2 Between Cmpts     2 and     9       915. 3.0/2 3 Between Cmpts
4 5: 5)
      \
No.
3 and    9    1  006. 3.0/2 4 Between Cmpts     4 and     9     1  336. 3.0/2 5 Between Cmpts     4 and 10       3  165. 3.0/2 6 Between Cmpts     4 and I
Description Surface Area (ft**2)
ll    1  301. 3.0/2 7 Between Cmpts     7 and     7   293 148.      N/A 8 Between Cmpts     5 and   ll     1  878. 3.0/2 9 Between Cmpts     6 and   ll     1 288.      3.0/2 10   Between Cmpts     9 and     1    1 392.      3.0/2 J
Thickness (ft)
11   Between Cmpts     9 and     2      915.      3.0/2 12 Between Cmpts       9 and     3     1 006.      3.0/2 13 Between Cmpts       9 and     4     1 336.      3.0/2 14 Between Cmpts 10 and         5     3 165.      3.0/2        10 15 Between Cmpts 11 and         4     1 301.      3.0/2 16 Between Cmpts     ll and     5     1 878.      3.0/2 17 Between Cmpts 11 and         6     1 288.      3.0/2 18   Interior of   Cmpt 1               508.      2.25 19   Interior of   Cmpt 2               244.      2.25 20   Interior of   Cmpt 3               269.      2.25 21   Interior of   Cmpt 4             1 549.      2.25 22   Interior of   Cmpt 5               501.      2.25 23 Interior   of Cmpt   6               447.      2.25 24 Floor of   Cmpt   1                   539.      5.00 25 Floor of   Cmpt 2                     259.     5.00
Removes Heat From Cmpt 1
Between Cmpts 1 a'nd 9
2 Between Cmpts 2 and 9
3 Between Cmpts 3 and 9
\\
4 Between Cmpts 4 and 9
5 Between Cmpts 4 and 10 6
Between Cmpts 4
7 Between Cmpts 7
and ll I
and 7
8 Between Cmpts 5 and ll 9
Between Cmpts 6 and ll 10 Between Cmpts 9 and 1
11 Between Cmpts 9 and 2
12 Between Cmpts 9 and 3
13 Between Cmpts 9 and 4
14 Between Cmpts 10 and 5
15 Between Cmpts 11 and 4
16 Between Cmpts ll and 5
17 Between Cmpts 11 and 6
18 Interior of Cmpt 1
19 Interior of Cmpt 2
20 Interior of Cmpt 3
21 Interior of Cmpt 4
22 Interior of Cmpt 5
23 Interior of Cmpt 6
24 Floor of Cmpt 1
25 Floor of Cmpt 2
1 392.
915.
1 006.
1 336.
3 165.
1 301.
293 148.
1 878.
1 288.
1 392.
915.
1 006.
1 336.
3 165.
1 301.
1 878.
1 288.
508.
244.
269.
1 549.
501.
447.
539.
259.
3.0/2 3.0/2 3.0/2 3.0/2 3.0/2 3.0/2 N/A 3.0/2 3.0/2 3.0/2 J
3.0/2 3.0/2 3.0/2 3.0/2 3.0/2 3.0/2 3.0/2 2.25 2.25 2.25 2.25 2.25 2.25 5.00 5.00 10


ATTACHMENT TO AEP:N     188A                         Page 24 26, Floor   of Cmpt 3                         285. 5.00 27 Floor   of Cmpt   4                   1    641. 5.00 28 Floor   of Cmpt 5                         531. 5.00 29 Floor   of Cmpt   6                       474. F 00 30 Between Cmpts       1 and   8       2    511. 2.875/2 31 Between Cmpts       2 and   8       1   301. 2.875/2 32 Between Cmpts       3 and  8        1    327. 2.875/2 33 Between Cmpts I
ATTACHMENT TO AEP:N 188A Page 24 26, Floor of Cmpt 3
and   8       7   654. 2.875/2 34 Between Cmpts       5 and   8       2   477. 2.875/2 35 Between Cmpts       6 and   8       2   208. 2.875/2 36 Between Cmpts       8 and   1       2   511. 2.875/2 37 Between Cmpts       8 and   2       1   301. 2.875/2
27 Floor of Cmpt 4
                                            't 38   Between Cmpts       8 and   3       1   327. 2.875/2 39   Between Cmpts       8 and   4   ,  7     654. 2.875/2 40   Between Cmpts       8 and   5       2     477. 2.875/2 41   Between Cmpts       8 and   6       2     208. 2.875/2 42   Between Cmpt       8 and Outside 24 567.       3.5 43   Between Cmpt       9 and Outside 4     829. 3.5 44   Between Cmpt     10 and     Outside 3     288. 3 '  10 45   Between Cmpt     ll and     Outside 4     640. 3.5 46   Metal in Cmpt   1                   9    479 ~  0.134 47   Metal in Cmpt   2                   4    556. 0.134 48   Metal in Cmpt   3                   5    009. 0.134 49   Metal in Cmpt   4                 28 889.        0.134 50   Metal in Cmpt 5                   9    349. 0.134 51   Metal in   Cmpt 6                   8    334. 0.134 52   Metal in   Cmpt 8                 38 435.       0.012
28 Floor of Cmpt 5
29 Floor of Cmpt 6
30 Between Cmpts 1 and 8
31 Between Cmpts 2 and 8
285.
1 641.
531.
474.
2 511.
1 301.
32 Between Cmpts 3
33 Between Cmpts 4
I and 8
and 8
1 327.
7 654.
34 Between Cmpts 5 and 8
2 477.
35 Between Cmpts 6 and 8
2 208.
36 Between Cmpts 8 and 1
2 511.
37 Between Cmpts 8 and 2
1 301.
't 38 Between Cmpts 8 and 3
1 327.
39 Between Cmpts 8 and 4
7 654.
40 Between Cmpts 8 and 5
2 477.
41 Between Cmpts 8 and 6
2 208.
42 Between Cmpt 8 and Outside 24 567.
43 Between Cmpt 9 and Outside 4 829.
44 Between Cmpt 10 and Outside 3 288.
45 Between Cmpt ll and Outside 4 640.
5.00 5.00 5.00 F 00 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 3.5 3.5 3 '
3.5 10 46 Metal in Cmpt 1
47 Metal in Cmpt 2
48 Metal in Cmpt 3
49 Metal in Cmpt 4
50 Metal in Cmpt 5
51 Metal in Cmpt 6
52 Metal in Cmpt 8
9 479
~
4 556.
5 009.
28 889.
9 349.
8 334.
38 435.
0.134 0.134 0.134 0.134 0.134 0.134 0.012


c/p ATTACHMENT TO AEP:N 188A                             Page 25 7/re/~ ~
ATTACHMENT TO AEP:N 188A c/p Page 25 7/re/~ ~
DESCRIPTION OF FLOW PATHS/AREAS BETWEEN COMPARTMENTS(REFS. 4 & 5)
DESCRIPTION OF FLOW PATHS/AREAS BETWEEN COMPARTMENTS(REFS.
No.       Description           Flow Area   Loss Coeff (ft**2) 1 From Cmpt     1 to 2           635.0      0.300 2   From Cmpt 2 to 3             1  079.0      0.170 3   From Cmpt 3 to 9                 77.0      4.200 4  From Cmpt 3 to 4               585.0      0.340 5   From'Cmpt 4 to 5               585.0      0.340 6  From Cmpt 6 to 5                 635.0      0.300 7 From Cmpt, 1 to 6                 72.0      1.450 8 From Cmpt 2 to 9                 77.0      4.200 9 From Cmpt 9 to 10                 10.0      3.000 10   From Cmpt   ll to 10           10.0      3.000 ll   From Cmpt 5 to     ll           154.0      4.200 12   From Cmpt 4 to 12               144.0      1.500 13   From Cmpt 1 to 7                 122.0      0.890 14   From Cmpt 2 to 7                 72.0      0.890 15   From Cmpt 3 to 7               '2.0        0.890 16   From Cmpt 4 to 7               487.0        0.890 17   From Cmpt 5 to 7                 155.0      0.890 18   From Cmpt 6 to 7               155.0        0.890 19   From Cmpt 7 to 8,           2 003.0       1.430 20  From Break Line to 1               0.4        N/A
4
& 5)
No.
Description Flow Area (ft**2)
Loss Coeff 1
From Cmpt 1 to 2
2 From Cmpt 2 to 3
3 From Cmpt 3 to 9
4 From Cmpt 3 to 4
5 From'Cmpt 6
From Cmpt 4 to 5
6 to 5
7 From Cmpt, 1 to 6
8 From Cmpt 2 to 9
9 From Cmpt 9 to 10 10 From Cmpt ll to 10 ll From Cmpt 5 to ll 12 From Cmpt 4 to 12 13 From Cmpt 1 to 7
14 From Cmpt 2 to 7
15 From Cmpt 3 to 7
16 From Cmpt 4 to 7
17 From Cmpt 5 to 7
18 From Cmpt 6 to 7
19 From Cmpt 7 to 8,
20 From Break Line to 1
635.0 1 079.0 77.0 585.0 585.0 635.0 72.0 77.0 10.0 10.0 154.0 144.0 122.0 72.0
'2.0 487.0 155.0 155.0 2 003.0 0.4 0.300 0.170 4.200 0.340 0.340 0.300 1.450 4.200 3.000 3.000 4.200 1.500 0.890 0.890 0.890 0.890 0.890 0.890 1.430 N/A


                                                                                      '>(3" ATTACHMENT TO AEP:N           1188A                                           Page 26 Walls and Related Compartments; file=LOCA01 Areas are from HALFLP02 & N.O.D. note book Walls 1:       8     between L.C. and D.E.
ATTACHMENT TO AEP:N 1188A Walls and Related Compartments; file=LOCA01 Areas are from HALFLP02
& N.O.D. note book
'>(3" Page 26 Walls 1:
8 between L.C. and D.E.
ALC:= 12280.
ALC:= 12280.
iRC~ ~             ~       ~       g         q       6(   g     $
iRC~
Arco:= 32.1 +21.1 +23.2 +30.8 '+73.0 +30.0 +43.3 +29.7
~
                            /       ci         I     /Q   /1     1I Arco     =   283.2 A:=
~
32.1 'LC Arco A:=
~
21.1 'LC Arco A:=
g q
23 '
6(
Arco
g Arco:= 32.1 +21.1 +23.2 +30.8 '+73.0 +30.0 +43.3 +29.7
                                                                                    'LC A:=
/
4     'rco 30.8 ALC        A:=
ci I
73.0 'LC Arco             A:=
/Q
30.0 'LC A:=
/1 1I Arco = 283.2 32.1 A:=  
Arco A:=        43.3                            29.7 ALC                          ALC Arco                            Arco Wall     7   is Ice     Baskets       in   Program LOCAOI A9   '.=   293148.         g(( ~   -
'LC Arco 21.1 A:=  
g Walls 10:         17   between D.E. and L.C.
'LC Arco 23 '
M=        I  9        )1 I j2:=       10 .. 17 J>lt       Q       Q ~Q       ) )g (j2 - 9)
A:=  
Walls 18: 23 are Xnterior of L.C.
'LC Arco 30.8 A:=
>I(.~ = I                   z.
ALC 4 'rco 43.3 A:=
A18:= 3517.
ALC Arco 73.0 A:=
Arci:= 43.9 +21.1 +23.2 +133.8 +43.3 +38.6 18 'rci A:=         43.9 '18          A:=
'LC Arco 29.7 A:=
21.1 Arci
ALC Arco 30.0 A:=  
                                                    ~
'LC Arco Wall 7 is Ice Baskets in Program LOCAOI A9
A18        A:=
'.=
23 '
293148.
Arci
g(( ~
                                                                                  'A18 A21    '
- g Walls 10:
133.8 'AIS Arci               A:='rci 22 43.3 A18      A:=     .
17 between D.E.
38.6 '18 Arci
and L.C.
j2:=
10.. 17 (j2 - 9)
J>lt M=
Q I 9 Q
~Q
)1 I )
)g Walls 18:
23 are Xnterior of L.C.
>I(.~
=
I z.
Arci:= 43.9 +21.1 +23.2 +133.8 +43.3 +38.6 A18:=
3517.
43.9 A:=  
'18 18 'rci 21.1 A:=  
~ A18 Arci 23 '
A:=
'A18 Arci 133.8 A21
'AIS Arci 43.3 A:=
A18 22 'rci 38.6 A:=.'18 Arci


y~c.y~ ~>ri <
ATTACHMEMT TO AEP:N 188A Walls 24:
ATTACHMEMT TO AEP:N       188A Walls 24: 29 are Floor of L.C.                               A24:= 3728.
29 are Floor of L.C.
l)Cm =
A24:=
3728.
y~c.y~
~>ri <
- l)Cm =
43.9 A:=.A24 24 Arci 21.1 A:=.
A24 Arci 3
A:=
A:=
24 43.9 Arci     A24    A:=       .
A24 23-2 26 'rci 133.8 Arci A:=  
21.1 Arci     A24 26 'rci A:=
. A24 43.3 28 Arci 38.6 A:=
3 23-2 A24 133.8 Arci A:=
A24 Arci l'I ('.)m
28 43.3 Arci
=
                                                    . A24        A:=   38.6 Arci   A24 Walls 30:     35   are between L.C. and U.C.               A30:= 16246. + 1139.
/
l'I ('.)m A:=
43.9 A:=  
            =
.A30 Arci z
43.9 Arci
: 21. 1 A:=
                      /
A30 Arci Walls 30:
                          .A30        A:=         z 21.
35 are between L.C. and U.C.
Arci 1
A30:=
A30       A:=    3 23 ~ 2 Arci   A30 133.8 Arci A:=
16246.
34 43.3 '30 Arci A:=   .
+ 1139.
38.6 '30 Arci Walls 36:       41   are between U.C. and L.C.
3 23
j3:=     36 .. 41 l>c~= 4<8 (j3- 6)
~ 2 A:=
Wall   42   is   between U.C. and Outside A42 '=   24567.                     )'l c.m = 8 Walls 43:       45   are between D.E. and Outside                 A43:= 12757.
A30 Arci 133.8 Arci 43.3 A:=.'30 34 Arci 38.6 A:=.'30 Arci Walls 36:
A:=
41 are between U.C.
                                                                  /~
and L.C.
(234. 126. 8)                           73.0 '43 Ared                       44      Arco 1(
j3:=
(30.0 +43.3 +29.7) 45                                 A43 Arco n:= 43..45               Sum:=   7   A n              Sum = 12757
36.. 41 (j3-6) l>c~= 4<8 Wall 42 is between U.C. and Outside A42
'=
24567.
)'l c.m
=
8 Walls 43:
45 are between D.E.
and Outside A43:=
12757.
(234.
126. 8)
Ared 1(
(30.0 +43.3 +29.7) 45 Arco A43
/~
73.0 A:=
'43 44 Arco n:= 43..45 Sum:= 7 An Sum
= 12757


                                                                                              /So ATTACHMENT TO AEP:N     188A                                                 Page 28 Walls 46: 51 are Metal in L.C.                                     A4   :=     65616.           ~/"h~
ATTACHMENT TO AEP:N 188A Walls 46:
p/ c.~                                     Z-                      3 A:=
51 are Metal in L.C.
46 43.9 'A46 Arci A:=       .
/So Page 28 A4
21.1 Arci  A46          A:=
:=
48 23 2 Arci
65616.
                                                                            'A46 49 133.8 Arci A:=       .
~/"h~
43.3 Arci  A46          A:= .. 38.
p/ c.~
Arci 6
43.9 A:=.'A46 46 Arci Z-21.1 A:=.A46 Arci 3
A46 S                              I n:= 46..51 Sum:=        An Sum =   65616 Wall     52   is Metal in U.C.
23 2
A52   '.=   38435.
A:=.'A46 48 Arci 133.8 49 Arci n:= 46..51 43.3 A:=.A46 Arci S
Summary       of Wall Areas nl:= 1..         9     n2:=   10 .. 17     n3:=   18 .. 23     n4:=     24   .. 29 nl                     n2                    A 1391.907 )                                                              n4 914.929               1391.907   )O 508.05 ) &              538.53 z.Y 914.929               244.188                  258.838 1005.989 3            1005.989 1335.537                                       268.491 KQ              284.599 xl 1335.537    )3          1548.452 5)             1641.35 E7 3165.395 J            3165.395    Ig 1300.847                                        501.106                531.169 1300.847    )5          446 '13 z3              473.514 z 'P 1877.556 1287.839 'I 1877.556    )I 1287.839    ))
Sum:=
293148 7 n5:=     30 .. 35 n6:= 36   .. 41     n7:=   42 .. 45     n8:=     46   .. 52 n5                   n6                    n7                    n8 2511.357      30     2511.357 3L                                  9478.586          b 1207.053       3)                              24567    lf+
An A:=..
1207.053  77 4828.921 v/7          4555.767 Y7 1327.187      7L      1327.187 75 7654.205                                     3288.351              5009.185 y        V~
A46
33      7654.205  35                                28889.177 2477.034      3 bg                          4639.728 2208.164      3g 2477.034  9'0                                9349.038 5e 2208.164  L/ /                                8334.247 X) 38435
: 38. 6 Arci I
Sum
= 65616 Wall 52 is Metal in U.C.
A52
'.=
38435.
Summary of Wall Areas nl:= 1..
9 n2:=
10.. 17 n3:=
18.. 23 n4:=
24.. 29 nl 1391.907 914.929 1005.989 1335.537 3165.395 1300.847 1877.556 1287.839 293148
)
3 J
'I 7
n2 1391.907
)O
)3 Ig
)5)I
))
914.929 1005.989 1335.537 1300.847 1877.556 1287.839 3165.395 A
508.05 244.188 268.491 1548.452 501.106 446 '13
) &
KQ 5) z3 n4 538.53 258.838 284.599 1641.35 531.169 473.514 z.Y xl E7 z 'P n5:=
30.. 35 n6:=
36.. 41 n7:=
42.. 45 n8:=
46.. 52 n5 30 3) 7L 33 3 bg 3g 2511.357 1207.053 1327.187 7654.205 2477.034 2208.164 n6 2511.357 1207.053 1327.187 7654.205 2477.034 2208.164 3L 77 75 35 9'0 L/ /
n7 24567 4828.921 3288.351 4639.728 lf+
v/7 n8 9478.586 4555.767 5009.185 28889.177 9349.038 8334.247 38435 b
Y7 y V~
5e X)


                                                                              /9p ATTACHMENT TO AEP:N   1188A                                   Page 29
ATTACHMENT TO AEP:N 1188A COMPUTER PROGRAM LOCA01
                                                                                +/2 r/~
/9p Page 29
COMPUTER    PROGRAM      LOCA01 MAIN                             INITL                           SOLID()
+/2 r/~
MAIN F, L, LT, N
READ TEND, LEDT Calc WR,
.LW CALL INITL UHVALS I'NITLS METAL DO 135 NC = 1, NCMPT CALL CLOSE1(NC) 135 CALL CLOSE2 CALL CLOSE3 1234 CALL ENERGY SATEST DO 137 NC = 1, NCMPT IF LSPRHT THEN CALL TEMPl(NC)
ELSE IF NC=7 THEN CALL TEMP7(NC)
ELSE CALL TEMP2(NC) 137 CALL SLAB CALL FLOWS IF()
GO TO 1234 CALL WRIT1 IF() CALL WRIT2 IF()
PLOT1(M)
IF()
PLOT2(M)
DATA SL, F, LT, NS, N
I I
I I
I INITL F, LT, N
Calc break flow area CALL SOLID()
CALL FCONVC1(HF())
Calc W(l:4,1:12),
P(1:3,1:12) and MOLES(),
MWC()
for all CMPTS 1:12 Estimate TRCS UHVALS F,
N Calc v(), h(), u()
for NCMPTS INITLS F,
SL, NS Calc DX(), HT()
SET TW(NS)=T(NC)
DTW(NS)=0.0 for all slabs.
ENERGY F, LT, N
Calc U(4,NC=l:12) mi*hi me*he Q(NC)
+ U(4,NC) for all Cmpts Set Q(l:12)=0.0, will calc in SLAB I
J SOLID()
(Ti, vs, hs)
(Ti, vs, hs)
F, L, LT,    N                      F, LT,    N Calc vs, hs of ice Calc break flow area        I READ TEND, LEDT CALL SOLID()                J Calc  WR, .LW                      CALL FCONVC1(HF())                  TEMP1(NC)
Calc vs, hs of ice TEMP1(NC)
CALL  INITL                        Calc W(l:4,1:12),                F, SL, L, LT,     N UHVALS                              P(1:3,1:12) and I'NITLS                        I MOLES(), MWC()          Calc new T, P, v, h for NCMPT if it I
F, SL, L, LT, N
METAL I
Calc new T, P, v, h for NCMPT if it is superheated.
for all    CMPTS  1:12 I  Estimate    TRCS                is superheated.
CALL CLOSE1(NC)
DO  135 NC = 1, NCMPT            I CALL CLOSE1(NC)                                                 CALL CLOSE1(NC) 135 UHVALS CALL CLOSE2 CALL CLOSE3                              F,  N                        TEMP2(NC) 1234                                Calc  v(), h(), u()              B, F,   L, LT,   N CALL ENERGY                        for NCMPTS SATEST                                                    Calc new T, P, v, h for NCMPT if it DO  137 NC = 1, NCMPT                                              is saturated.
TEMP2(NC)
IF LSPRHT THEN                        INITLS CALL TEMPl(NC)                                            -CLOSE1 ELSE IF NC=7 THEN                  F, SL, NS                      for CLOSE EDITS CALL TEMP7(NC)
B, F, L, LT, N
ELSE                            Calc DX(), HT()
Calc new T, P, v, h for NCMPT if it is saturated.
CALL TEMP2(NC)            SET TW(NS)=T(NC) 137                                    DTW(NS)=0.0      for            TEMP7(NC) all  slabs.
-CLOSE1 for CLOSE EDITS TEMP7(NC)
CALL SLAB                                                          B, F, LT,   N CALL FLOWS Calc new T, P, v, IF()  GO TO  1234                      ENERGY                      and WMELT(2)
B, F, LT, N
Calc new T, P, v, and WMELT(2)
Calc W(l:3,7), u()
Calc W(l:3,7), u()
CALL WRIT1                            F, LT,    N                  VTOT(), h, etc.,
VTOT(), h, etc.,
IF() CALL WRIT2                                                      FT7=F(1:,NP,) for IF() ."" PLOT1(M)                  Calc U(4,NC=l:12)                condensed vapor.
FT7=F(1:,NP,) for condensed vapor.
IF()        PLOT2(M)                mi*hi    me*he    Q(NC)
CALL CLOSE1(NC)
                                    + U(4,NC)                    CALL CLOSE1(NC) for all  Cmpts DATA                        Set Q(l:12)=0.0, will calc in      SLAB SL, F, LT, NS, N


ATTACHMENT TO AEP:N     188A LOCA01   ..continued...
ATTACHMENT TO AEP:N 188A LOCA01..continued...
FLOWS                                         SLAB B~   PLI 1 ~ FI SLg LTI LI N                    AI BI    Fg SLI LTI NS~  N Set NF(N)=NCFT(N,1), DFRX()=1.0, Set F(...,1)= F(...,2), DF(...,1)=DF(             ,2)      Set QW(NS,1)=QW(,2)
FLOWS B~ PLI 1 ~ FI SLg LTI LI N Set NF(N)=NCFT(N,1),
DH(...,l)=DH(...,2)                                         QW(NS,2)=0.0 F(...,.2)=0.0, DF(...,2)=0.0, DH( ,2)=0.
DFRX()=1.0, Set F(...,1)= F(...,2),
Calc ASFR,TDEW,T Calc Z(NC), F(l,NP,.) for liquid                           CALL FCONVC(HF)
DF(...,1)=DF(
Calc F(4,NBK,.), then F(l:2, ), DF(l:2, ),
,2)
DH(1:2, ) for the break flow path.                   Calc HN, HC, HT,      QW Calc  DP(), DV,, VBAR, F(4,NP,.) all flow paths               TW, Q(NC)    for Calc PLPS(), NSNL(), DN(), DFRX(), all paths.               slabs NS=1,52 Calc DF(1,NP,.) & DH(1,NP,.)
DH(...,l)=DH(...,2)
Calc DF(4,NP,.) based on DF(4,1,.), various NP               CLOSE2 for  CLOSE EDITS Calc F(2:3,NP,), DF(2:3,NP,.),         & DH(2:3,NP,.)
F(...,.2)=0.0, DF(...,2)=0.0, DH(
Calc W(3:4,NC), MOLES(),       MWC()   for all compartments       NC=1,12                                     METAL CLOSE3                                                      FI SLg LTg NS for  CLOSE EDITS Calc   WMTL, DXM for metal equip slabs NS=46,52 as TVOL(NC)          DATA in INITLS F, LT Calc empt T* using            SATEST WRITl                           VTOT(3,NC) and W(2:3,NC); used  in    F, L, LT, N AI BI NSI LT                         SBRS SLAB & SATEST  Calc U(NC) above saturated; Write T, P,     U, H, W,                                   Is  NC  saturated?
,2)=0.
F, DF,   DH,   QWg   Qg               PLOT1(M)
Calc Z(NC), F(l,NP,.) for liquid Calc F(4,NBK,.), then F(l:2,
TW(ND=l,NS=1:52)                         PL for all    CMPTS                                              FCONVI Plots P(3,1:12) &
), DF(l:2,
T(1:12) vs Time FI .SLI LTI NI   NS Calc 'cross area of WRIT2                              PLOT2(M)        each empt   for RE no PL A, LT                                              -ENTRY FCONVC ( HF )
),
Plots P(3,1:12) on    Calc HF(1:52)     for Write TW(ND=l:S,NS=1:52)                  finer scale          each   slab.
DH(1:2,
) for the break flow path.
Calc DP(),
DV,, VBAR, F(4,NP,.) all flow paths Calc PLPS(),
NSNL(), DN(), DFRX(), all paths.
Calc DF(1,NP,.)
& DH(1,NP,.)
Calc DF(4,NP,.)
based on DF(4,1,.), various NP Calc F(2:3,NP,), DF(2:3,NP,.),
& DH(2:3,NP,.)
Calc W(3:4,NC), MOLES(), MWC() for all compartments NC=1,12 CLOSE3 for CLOSE EDITS TVOL(NC)
F, LT SLAB AI BI Fg SLI LTI NS~
N Set QW(NS,1)=QW(,2)
QW(NS,2)=0.0 Calc ASFR,TDEW,T CALL FCONVC(HF)
Calc HN, HC, HT, QW TW, Q(NC) for slabs NS=1,52 CLOSE2 for CLOSE EDITS METAL FI SLg LTg NS Calc WMTL, DXM for metal equip slabs NS=46,52 as DATA in INITLS WRITl AI BI NSI LT Write T, P, U, H, W,
F, DF, DH, QWg Qg TW(ND=l,NS=1:52) for all CMPTS WRIT2 A, LT Write TW(ND=l:S,NS=1:52)
Calc empt T* using VTOT(3,NC) and W(2:3,NC); used in SBRS SLAB & SATEST PLOT1(M)
PL Plots P(3,1:12)
T(1:12) vs Time PLOT2(M)
PL Plots P(3,1:12) on finer scale SATEST F, L, LT, N
Calc U(NC) above saturated; Is NC saturated?
FCONVI FI.SLI LTI NI NS Calc 'cross area of each empt for RE no
-ENTRY FCONVC ( HF )
Calc HF(1:52) for each slab.


0     Q             r           r r r r r r                        e      r    e P
P 0
ATTACHMENT TO AEP:N     1188A                             Page 3>    y. gs)
Q r
                                                                                              ~J).+/fp 7 Yipes       z~>   6'P~~~     9! 1 lv'4>"~                   - p~z I
r r
gVv f+
r ATTACHMENT TO AEP:N 1188A r
              ~     v
r r
( ~   h                                                   v QQ'0   7lg>"
Page 7 Yipes z~> 6'P~~~
g gS g( ~
lv'4>"~
                                              ~Pry T 59~ -PPg~"                 /
I 9!
1 e
r e
3>
: y. gs)
~J).+/fp
- p~z gVv f+
~
v
(
~
h QQ'0 7lg>"
v g
gS g(~
~Pry T 59~ -PPg~"
/
27-<
27-<
      @0~-(5       5 m   (S'" ) t C>o'~9         lv) - )Zebra AT )v-     ('tv$ 0   -7 /, )   (gyes   9>)     )J j- ( 33.1 ].     )q l >7p     v     j)
@0~-(5 5
m (S'"
) t C>o'~9 lv) - )Zebra AT
)v-('tv$ 0 -7 /, )
(gyes 9>) ) J j- (
33.1 ].
)q l >7p v j)


                                                                                                                        /
ATTACHMENT TO AEP:N 188A
ATTACHMENT TO AEP:N                                   188A                                                           Page 32     7gtyf ~: l Bodies of different shapes in a tube; three-dimensional           low;                                     Diagram Sm/F, < 0.3 [29,38)                                                                                       10-9
/
    ~os SmlFo               2r "o 1.15cx                       1 po/                 (1     rSmlFo)             Do Re'   wodm Name   of a body and scheme                           Drag coefflcient c>>
Page 32 7gtyf~: l Bodies ofdifferent shapes in a tube; three-dimensional low; Sm/F, < 0.3 [29,38)
Convex hemispherewup (without Re'=4 X 10', c>>=0.36; end phne) Sm  m srdm~
Diagram 10-9
Re'=SX 10', c>>=0.34; 4
~os SmlFo 2r "o 1.15cx ',
r ~0.5 for r, see Diagram     10-1 Hemispher~one Sm Wo Fo           ZO'e'= m  =7fdm 4
1 po/
1.35 X   10'; cx = 0.088; r ~0.5 Concave hemispherewup (without end plane) Sm m =  Tom 4
(1 rSmlFo)
Re'=4X 10; c>>=1.44; Re' 5 X 10', cx = 1.42; r ~1.5
Do wodm Re' Name of a body and scheme Convex hemispherewup (without srdm~
                              =
end phne) Sm m
ZO'e'=1.35 Smm  4mdm'onekemisphere 4
4 Drag coefflcient c>>
X 10', c>>=0.16; Wo,Fo                      p                                                        r ~0.5 r/dm   08   1       2       3       4       5       6     7 cx     1.0 0.91     0.85     0.85   0.87   0.90     0.95   0.99 Circular smooth cylinder in a flow                                                  r ~1.0
Re'=4 X 10', c>>=0.36; Re'=SX 10', c>>=0.34; r ~0.5 forr, see Diagram 10-1 7fdm Hemispher~one Sm =
                      ~
m 4
parallel to the axis Sm    m
Wo Fo ZO'e'=
                                ~dm 4                                                          Q(o)
1.35 X 10'; cx = 0.088; r ~0.5 Concave hemispherewup (without Tom end plane) Sm =
Ws 0       ZO       4.0       6'0 t/der 333
m 4
Re'=4X 10; c>>=1.44; Re' 5 X 10', cx = 1.42; r ~1.5 4mdm'onekemisphere Sm=
m 4
Wo,Fo pZO'e'=1.35 X 10', c>>=0.16; r ~0.5 Circular smooth cylinder in a flow
~
~dm parallel to the axis Sm m
4 r/dm 08 1
2 3
4 5
6 7
cx 1.0 0.91 0.85 0.85 0.87 0.90 0.95 0.99 r ~1.0 Q(o)
Ws 0
ZO 4.0 6'0 t/der 333


0     ~ ~
g
g              ~                ~
~
I ~ ~                                                     ~       ~
0
            ~     ~ ~   t         ~               I ~
~
                                                              ~
~
                                                                ~     9 ~ ~     I s            I t           I           t       I         I     I       t     I
~
                                                                                                                          '    I I           I       I         I     I '
I
r           le           I       It         I' t       I     '        I Pi                                                                                 ~5
~
                ~ t   ~       ~     I
~
                                                  ~         I         I   I     I       I         I         I      I
~
                                                                                              'I
~
-lm                                                         I         I ~         I       I         I           I   '      I
~
              ~     ~     .
~ ~ t
                  ~r~ mam la&#xc3; 855
~
~ ~     ~         ~           ~
I
                              ~       I   I
~
          ~   Fs~                                                 I I     I   I   I I     I       lie   I       I I   I
~
s I
~
9
~
~
I t
I t
I I
I t
I I
I I
I I
I r
le I
It I' t
I I
Pi
~5
~ t
~
~
I
~
I I
I I
I I
I I
-lm I
I
~
I I 'I I
I I
~
~
~r~
mam la&#xc3; 855
~
~
~
~
~
~
I I
~Fs~
I I I
I I
I I
lie I
I I I


ATTACHMENT TO AEP:NI   188A                                 Page 34 DISPLAY COMPONENT DATA                 PAGE 1  OF 21 COMPONENT NO.: 1-PP-45-2 COMPONENT TYPE: PUMP CENTRIFUGAL SIZE AND UNITS:         88500         GALLONS/MINUTE PLANT SYSTEM:         REACTOR COOLANT CABLE SYSTEM:
ATTACHMENT TO AEP:NI 188A Page 34 DISPLAY COMPONENT DATA COMPONENT NO.: 1-PP-45-2 COMPONENT TYPE:
FUNCTIONAL NAME: REACTOR COOLANT PUMP g2 UNIT:   1 BUILDING: CONTAINMENT         FLOOR ELEVATION: 598   CONTAINMENT AZIMUTH: 130 ROOM: LOWER CONTAINMENT, QUADRANT NO. 2 FEG                                             FEG BOUNDARY:
PUMP CENTRIFUGAL SIZE AND UNITS:
1 0 2 02     jg 1 2 RCP ( REACTOR COOLANT PU CONTROL PANEL: 1-RCP OTHER LOCATION           ON SOUTHEAST SIDE OF STEAM GENERATOR   g2-OME-3-2 INFORMATION:
88500 GALLONS/MINUTE PLANT SYSTEM:
ENTER NEXT COMPONENT NO.:                               PRINTER ID:         PAGE NO.:
REACTOR COOLANT CABLE SYSTEM:
PF3/15=DISPLAY NEXT COMPONENT          PF4/16=PRINT ALL DATA WITH M & E NOS.: N PF5/17=DISPLAY ASSEMBLY DATA          PF6/18=DISPLAY M & E DATA PF8/20=PAGE FORWARD PF9/21=SYSTEM MENU                    PF12/24=EXIT LU g4
FUNCTIONAL NAME: REACTOR COOLANT PUMP g2 UNIT:
1 BUILDING: CONTAINMENT FLOOR ELEVATION: 598 ROOM:
LOWER CONTAINMENT, QUADRANT NO.
2 FEG FEG BOUNDARY:
1 0 2 02 jg1 2 RCP (REACTOR COOLANT PU PAGE 1
OF 21 CONTAINMENT AZIMUTH: 130 CONTROL PANEL: 1-RCP OTHER LOCATION ON SOUTHEAST SIDE OF STEAM GENERATOR g2-OME-3-2 INFORMATION:
ENTER NEXT COMPONENT NO.:
PF3/15=DISPLAY NEXT COMPONENT PF5/17=DISPLAY ASSEMBLY DATA PF9/21=SYSTEM MENU PRINTER ID:
PAGE NO.:
PF4/16=PRINT ALL DATA WITH M
& E NOS.:
N PF6/18=DISPLAY M
& E DATA PF8/20=PAGE FORWARD PF12/24=EXIT LU g4


ATTACHMENT TO AEP:N 1188A                                 Page 35 FDBM043                         DISPLAY COMPONENT DATA                 PAGE 1 OF 9 COMPONENT NO.: 1-SI-170-L2 COMPONENT TYPE: VALVE CHECK SIZE AND UNITS:       10           INCH PLANT SYSTEM:     RESIDUAL HEAT REMOVAL CABLE SYSTEM:
ATTACHMENT TO AEP:N 1188A Page 35 FDBM043 DISPLAY COMPONENT DATA PAGE 1
FUNCTIONAL NAME: ACCUMULATOR TANK OME-6-2 OUTLET & ECCS TO REACTOR COOLANT LOOP g2 COLD LEG CHECK VALVE UNIT: 1 BUILDING- CONTAINMENT         FLOOR ELEVATION: 617   CONTAINMENT AZIMUTH- 140 ROOM: LOWER CONTAINMENT, QUADRANT NO. 2 FEG:                                         FEG BOUNDARY:
OF 9
102.00       RCS (REACTOR COOLANT SYSTEM CONTROL PANEL:
COMPONENT NO.: 1-SI-170-L2 COMPONENT TYPE:
OTHER LOCATION         BETWEEN REACTOR COOLANT PUMP g1-PP-45-2 AND THE SHIELD WALL, INFORMATION:          2 FEET BELOW THE 617 ELEVATION PLATFORM ENTER NEXT COMPONENT NO.:                             PRINTER ID:       PAGE NO.:
VALVE CHECK SIZE AND UNITS:
PF3/15=DISPLAY NEXT COMPONENT      PF4/16=PRINT ALL DATA WITH M & E NOS.: N PF5/17=DISPLAY ASSEMBLY DATA        PF6/18=DISPLAY M & E DATA PF8/20=PAGE FORWARD PF9/21=SYSTEM MENU                  PF12/24=EXIT LU P4
10 INCH PLANT SYSTEM:
RESIDUAL HEAT REMOVAL CABLE SYSTEM:
FUNCTIONAL NAME: ACCUMULATOR TANK OME-6-2 OUTLET
& ECCS TO REACTOR COOLANT LOOP g2 COLD LEG CHECK VALVE UNIT: 1 BUILDING-CONTAINMENT FLOOR ELEVATION: 617 CONTAINMENT AZIMUTH-140 ROOM:
LOWER CONTAINMENT, QUADRANT NO.
2 FEG:
FEG BOUNDARY:
102.00 RCS (REACTOR COOLANT SYSTEM CONTROL PANEL:
OTHER LOCATION INFORMATION:
BETWEEN REACTOR COOLANT PUMP g1-PP-45-2 AND THE SHIELD WALL, 2 FEET BELOW THE 617 ELEVATION PLATFORM ENTER NEXT COMPONENT NO.:
PF3/15=DISPLAY NEXT COMPONENT PF5/17=DISPLAY ASSEMBLY DATA PF9/21=SYSTEM MENU PRINTER ID:
PAGE NO.:
PF4/16=PRINT ALL DATA WITH M
& E NOS.:
N PF6/18=DISPLAY M
& E DATA PF8/20=PAGE FORWARD PF12/24=EXIT LU P4


f14, Jll'VJla4441 j JV lli a ~ Jilt@ ~ s kVV4'1                                             j O$ C 4V ACUiCJLAT1.MCD           7/28/93 p.l
f14, Jll'VJla4441 j JV lli a
* CALCULATION CHECK                                 *
~ Jilt@ ~ s kVV4'1 ACUiCJLAT1.MCD 7/28/93 j O$C 4V p.l CALCULATION CHECK
* Maximum Differential Pressure across the Ventilation Unit *
* Maximum Differential Pressure across the Ventilation Unit
* by C. P. Lin
* by C. P. Lin A. Input Information ORIGIN :=
* A. Input Information                 :        ORIGIN :=     1     i :=   1 ..2   j := 1   ..3 1; Region           1     region between refueling canal and steam generator                           No 2, in which the accumulator line breaks.
1 i := 1..2 j :=
Volume,               V:= 27250 (ft 3) 1 Flow path(11)             to the region between             steam generator No 2 and ventilation unit, Area,             A           :=   635 (ft 2)
1..3 1; Region 1 region between refueling canal and steam generator No 2, in which the accumulator line breaks.
Flow path(12) l,l through refueling             canal, Area,             A           := 72   (ft 2) 1,2 Flow path(13)             to ice condenser through inlet doors, Area,             A           := 95   (ft 2) 1,3
: Volume, V:= 27250 (ft 3) 1 Flow path(11) to the region between steam generator No 2 and ventilation unit,
: 2. Region           2   region betweem steam generator                     No 2 and   ventilation unit, Volume,                 V 2
: Area, A
:= 19000         (ft 3)
:= 635 (ft 2) l,l Flow path(12) through refueling canal,
Flow path(21)             to the region           between   ventilation unit     and steam generator       No     3, Area,               A           := 1079       (ft 2) 2,1 Flow path(22) to ice condenser through                           inlet   doors, Area,               A           := 64     (ft   2) 2I2 Flow path(23) to dead end region housing accumulators 2 and 3, Area,               A 2/3
: Area, A
:= 77       (ft   2)
:= 72 (ft 2) 1,2 Flow path(13) to ice condenser through inlet doors,
: 3. Lower Containment Conditions Plc := 14.7 (psia)                         Tlc := 90 (F) RHlc := 100.0 Water vapor partial pressure,                             Pw := 0.698 Air partial pressure,                                     Pa := Plc  Pw          Pa = 14. 002 Water vapor mass contained in Region 1 and 2, Pw. 144 V     ~
: Area, A
1                        58-0181 Mw i
:= 95 (ft 2) 1,3
1545 18
: 2. Region 2
                                    ~
region betweem steam generator No 2 and ventilation unit,
(Tlc       + 460)
: Volume, V
Mw =  t40.4533      (lb)
:= 19000 (ft 3) 2 Flow path(21) to the region between ventilation unit and steam generator No 3,
Air mass contained in                     Region   1 and 2, Pa- 144 V     ~
: Area, A
Ma i
:= 1079 (ft 2) 2,1 Flow path(22) to ice condenser through inlet doors,
1545 28.97 (Tlc       + 460)
: Area, A
Ma =
:= 64 (ft 2) 2I2 Flow path(23) to dead end region housing accumulators 2 and 3,
I1873.167I L1306.061]       (lb)
: Area, A
:= 77 (ft 2) 2/3
: 3. Lower Containment Conditions Plc := 14.7 (psia)
Tlc := 90 (F)
Water vapor partial pressure, Pw Air partial pressure, Pa Water vapor mass contained in Region Pw. 144 ~ V 1
Mw Mw =
i 1545
~ (Tlc + 460) 18 Air mass contained in Region 1 and 2, Pa-144
~ V RHlc := 100.0
:= 0.698
:= Plc Pw 1 and 2, Pa = 14. 002 t
58-0181 40.4533 (lb)
Mai 1545 (Tlc + 460) 28.97 I1873.167I Ma =
L1306.061]
(lb)


ATTACHMENT TO AEP:N           188A                                               Page 37 p 2 B. Flow Path Resistance
ATTACHMENT TO AEP:N 188A B. Flow Path Resistance 36 y := 12.8 2:= 1.0 Using Cx := 0.702 Sm
: 1. Flow Path through Steam Generator                   :
: 1. Flow Path through Steam Generator from Idel'Chik P.335, FO:= 1203 dm:= 11.5 l
from   Idel'Chik P.335, FO:=     1203
DO := 23.2 DO Page 37 p 2 Sm:= dm. 1 Sm = 414 y= 1.2
:= 23.2 dm:= 11.5               l     36      Sm:=   dm. 1   Sm = 414 DO y := 12.8          DO y=   1.2 2
.3333 RES:= 1.15-Cx-FO Sm 1-r FO 2
Using      Cx := 0.702                := 1.0 Sm
2 1
                                                                .3333 RES:= 1.15-     Cx-FO 3
3 DO RES = 0.95 FO - Sm K:= RES.
1 2 DO RES =   0.95 1-r      Sm FO 2
1,1 FO K
K:=
= 0.408 l,l
1,1 RES.
: 2. Flow Path through Ventilation Unit from Idel'Chik P.335, FO := 1203 dm := 9.9 1 := 13.8 Sm := dm 1 DO := 51.84 DO dm y
FO FO Sm K
~
l,l
y = 20.97 2
                                                                = 0.408
2 Using Cx := 1.11 z := 1.5 Sm
: 2. Flow Path through Ventilation Unit from Idel'Chik P.335, FO := 1203       dm := 9.9             1 := 13.8     Sm   := dm 1     Sm =  136.62 DO := 51.84                   DO     dm y   ~
.3333 Sm = 136.62 RES:= 1.15. Cx.
y = 20.97 2       2 Using       Cx := 1.11             z := 1.5 Sm
FO Sm 1
                                                                .3333 RES:= 1.15. Cx.
FO 3
1 2
DO RES =  0.146 Sm 1
FO 2
FO 2
K:=
2 1
2,1 RES-FO Sm FO K
3 DO RES = 0.146 FO Sm K:= RES-2,1 FO K
2,1
= 0.115 2,1
                                                              = 0.115
: 3. Flow Path through Refueling Canal Entrance loss and velocity head, K
: 3. Flow Path through Refueling Canal Entrance loss and velocity head, K       := 1 + 0.5 1,2
:=
: 4. Flow Path through Ice Condenser Inlet Doors Lower inlet door opening, 84"x91.5" Hydraulic diameter,                           4 (84 91.5)     1 Dh                                   Dh =  7.299 2 (84 +   91.5)   12 Crane    wall thickness,              1:=     3 From    Idel'Chik, P.144, 1
1 + 0.5 1,2 Dh = 7.299 Crane wall thickness, From Idel'Chik, P.144, 1
Dh 0.411              K 1,3
0.411 Dh K:= K 2,2 1,3 K
:= 2.59            K:=
:= 2.59 1,3
2,2 K
: 4. Flow Path through Ice Condenser Inlet Doors Lower inlet door opening, 84"x91.5" Hydraulic diameter, 4 (84 91.5) 1 Dh 2 (84 + 91.5) 12 1:= 3
1,3


ATTACHMENT TO AEP:N         1188A                                             Page 38 p 3
ATTACHMENT TO AEP:N 1188A Page 38 p 3
: 5. Flow Path to Dead Ended Housing Accumulators                     2 a 3 K:=
: 5. Flow Path to Dead Ended Housing Accumulators 2
From FSAR Table 14.3.4-16, 2/3 4.2 C. Assumptions
a 3
From FSAR Table 14.3.4-16, K:= 4.2 2/3 C. Assumptions
: 1. Pressures in the areas outside of region 1 a 2 are the same.
: 1. Pressures in the areas outside of region 1 a 2 are the same.
: 2. From Tom s calculation results for region 1, air in the region 1 and                       2 is depleted in 0.3 sec.
2.
From Tom s calculation results for region 1, air in the region 1 and 2
is depleted in 0.3 sec.
: 4. All the steam generated in the region 1 is carried out through flow paths.
: 4. All the steam generated in the region 1 is carried out through flow paths.
D. Flow Calculations
D. Flow Calculations
: 1. Region     1 Critical flow rate           from accumulator       line break,-     D := 8.75   (in)
: 1. Region 1
RCS   cold leg conditions, Pres := 2250         (psia)         Tres := 541       (F) hrcs := 536.07 (Btu/lb)
Critical flow rate from accumulator line break,-
From "System Analysis Handbook",                   mf := 24400   (lb/sec/ft 2) 2 n   D                             4 MFR:= mf.                     MFR =   1.019.10        (lb/sec) 4   12 Steam     generation, hrcs   58.018                             3 Gs   := MFR                                 Gs =  4.671.10      (lb/sec) 1100.8       58.018 Air depletion rate, Ma 1                                   3 Sa                             Sa     6.244 10 F
D := 8.75 (in)
(lb/sec) 1      0.3                     1 Steam/air mixture density, Gs + Sa 1
RCS cold leg conditions, Pres
MW                                  MW    = 22.977 Sa                 1 Gs         1 18     28.97 Plc   144 (lb/ft 3) p 1
:= 2250 (psia)
a 1545 MH
Tres
                            ~
:= 541 (F) hrcs
(Tlc   + 460) p 1
:= 536.07 (Btu/lb)
                                                          = 0.057 1
From "System Analysis Handbook",
        ****Assume region             1 & 2   pressure ****
mf := 24400 (lb/sec/ft 2) 2 n
Pl := 0.211         (psi   above outside pressure)
D MFR:= mf.
P2 := 0.033         (psi   above outside pressure)
MFR =
4 12 Steam generation, hrcs 58.018 Gs := MFR 1100.8 58.018 Air depletion rate, Ma 1
Sa Sa 1
0.3 1
Steam/air mixture density, Gs + Sa 1
4 1.019.10 (lb/sec) 3 6.244 F 10 (lb/sec) 3 Gs = 4.671.10 (lb/sec)
MW Sa Gs 1
18 28.97 Plc 144 MW
= 22.977 1
p
= 0.057 (lb/ft 3) 1 p
a 1
1545
~ (Tlc + 460)
MH 1
****Assume region 1
& 2 pressure ****
Pl := 0.211 (psi above outside pressure)
P2 := 0.033 (psi above outside pressure)


ATTACHMENT TO AEP:           1188A                                                   Page 39 P.4 Pressure   differential         across flow paths, DP       := P1     P2 1,1 DP       := Pl               DP       := Pl 1,2                           1,3 Steam/air flow through             a flow path can be calculated by the following equation, DP.p .144. 2- 32.2 MFR:= A                                           0 l,j         l,j             K l,j Flow   ratio of     path (1,2) and (1,3) to             (l,l),
ATTACHMENT TO AEP:
DP A
1188A Page 39P.4 Pressure differential across flow paths, DP
l,j l,j Kl,j                             FR 1,
:= P1 P2 1,1 DP
FR l,j                 DP 0.064 0.065 A
:= Pl DP
l,l 1,1 K Steam/air l,l flow rate throu             path (1, 1),
:= Pl 1,2 1,3 Steam/air flow through a flow path can be calculated by the following
gh Gs + Sa 1                                       3 MFR                                          MFR        =  9.667.10          (lb/sec) l,l Pressure j
: equation, DP.p.144. 2-32.2 MFR:= A 0
differential         across flow paths, 2                       DP K            MFR      . FR l,j                                                      1,'P 0.211 l(j       A 2
l,j l,j Kl,j Flow ratio of path (1,2) and (1,3) to (l,l),
                            .p
Al,j DPl,j Kl,j FR 1,
: 2. 32.2           144                 0.211 l,j      1
FRl,j 0.064 0.065 DPl,l A
: 2. Region 2 Incoming steam flow from Region 1, Gs STi := MFR l,l    Gs + Sa STi = 4.137     '0 3    (lb/sec) 1 Incoming air flow from Region 1, AIRi := MFR             STi 1,1                                                   (lb/sec)
1,1 Kl,l flow rate throu h 3
Air depletion rate in Region 2, Ma Sa 2
MFR
:=   AIRi 0.3 2
= 9.667.10 l,l MFR Steam/air g
                        +                            Sa 2
path (1, 1),
                                                            =  9.883 10 3
Gs + Sa 1
(lb/sec)
Kl,j MFR
. FR j
Pressure differential across flow paths, 2
DP 1,'P l(j 2
A
.p l,j 1
: 2. 32.2 144 0.211 0.211 3
Sa
= 9.883 10 2
: 2. Region 2
Incoming steam flow from Region 1, Gs 3
STi := MFR STi = 4.137 '0 l,l Gs + Sa 1
Incoming air flow from Region 1, AIRi := MFR STi 1,1 Air depletion rate in Region 2, Ma 2
Sa
:= + AIRi 2
0.3 (lb/sec)
(lb/sec)
(lb/sec)
(lb/sec)


ATTACHMENT TO AEP:N           188A                                               Page 40 p.5 Steam/air mixture density, STi + Sa 2
ATTACHMENT TO AEP:N 188A Page 40 p.5 Steam/air mixture density, STi + Sa 2
MW                                     MW    = 24.554 2                Sa                2 STi            2 18      28.97 Plc      144 (lb/ft 3) p 2
MW
1545 MW
= 24.554 2
                    ~
MW Dp.p 144 2.32.2 MFR:= A a
(Tlc    + 460) p 2
2/j 2/j K
                                                      = 0.061 2
2 /
Steam/air flow through a flow path can be calculated by the following equation, Dp.p 144   2.32.2 MFR:= A                                         a 2/j         2/j             K 2/
Flow ratio of path (2,2)&(2,3) to (2,1),
Flow   ratio of path (2,2)&(2,3)               to (2,1),
2 Sa STi 2
A          K                        FR 2/         2,1                      2/
18 28.97 Plc 144 p
FR 2/j     A         K                         0. 012 2,1         2/ g                   0.012 St earn/air flow ra te          through path (2/1) /
p
STi + Sa 2                                    4 MFR                                           MFR      = 1.369 10         (lb/sec) 2,1                                           2,1 Pressure j
= 0.061 (lb/ft 3) 2 1545 2
differential         across flow paths, 2
 
K             MFR      FR                            DP 2/                                                     2/
~ (Tlc + 460)
DP 2/g       2                 2 32.2           144               0.033 A      ~
MW 2
p                                              0.033 2/g      2 I Differential   pressure across ventilation                 unit is less than 0.1 psi I
Steam/air flow through a flow path can be calculated by the following
: equation, A
2 /
FR2/j A
2,1 St K
2,1 K
2/ g te thr FR 2/
: 0. 012 0.012 (2/1) /
4 MFR
= 1.369 10 2,1 MFR 2,1 earn/air flow ra ough path STi + Sa 2
(lb/sec) j Pressure differential across flow paths, 2
K 2 /
DP 2/g 2
A
~ p 2/g 2
MFR FR 2 32.2 144 DP 2/
0.033 0.033 I Differential pressure across ventilation unit is less than 0.1 psi I


ATTACHMENT TO AEP:N               188A                                             Page 41 AMERlCAN KLECTRlC POWKR Data     July 30,       1993 subject Cook Nuclear Plant Containment Building, EL. 598'-9 3/8" HV-CFT Ventilation Units From     C. E. Shute/         . L. Ball To     J. B. Eingseed/S.     A. Hover NEDS has performed a GT-STRUDL               finite element analysis of the filter house portion of the HV-CFT ventilation units as requested by S.A.
ATTACHMENT TO AEP:N 188A Page 41 AMERlCAN KLECTRlC POWKR Data July 30, 1993 subject Cook Nuclear Plant Containment Building, EL. 598'-9 3/8" HV-CFT Ventilation Units From C. E. Shute/
. L. Ball To J.
B. Eingseed/S.
A. Hover NEDS has performed a GT-STRUDL finite element analysis of the filter house portion of the HV-CFT ventilation units as requested by S.A.
Hover in his June 16, 1993 memo.
Hover in his June 16, 1993 memo.
The analysis found that the filter house can withstand a jet impingement pressure of 0.25 psi based on the capacity of the floor anchorage and of 1.13 psi based on the capacity of the housing.
The analysis found that the filter house can withstand a jet impingement pressure of 0.25 psi based on the capacity of the floor anchorage and of 1.13 psi based on the capacity of the housing.
The Technical Assessment Section has established that the maximum pressure that the units can be expected to receive is less than 0.10 psi.
The Technical Assessment Section has established that the maximum pressure that the units can be expected to receive is less than 0.10 psi.
Therefore, the HEPA filters housed inside the box will not be dislodged in the event of a LOCA or steam line break.
Therefore, the HEPA filters housed inside the box will not be dislodged in the event of a LOCA or steam line break.
The original design criteria for the filter house required that it be able to withstand a jet impingement pressure of 2 psi. The above findings by NEDS show pressures much less and it should be noted that NEDS did not use a conservative approach in their analysis.                     During the next refueling outages, a walkdown will be performed by NEDS to gather additional structural data on these filter houses.             Recommendations will then be made for modifications necessary to bring these structures up to their original design requirements.
The original design criteria for the filter house required that it be able to withstand a jet impingement pressure of 2 psi.
Approved by                                   r   cJcc lA N   R ccIa - Man er' clear Design - Structural   Er, Analytical CES/ JAR: dm xc:       J. A. Kobyra/R. C. Armstrong Ref stru'thv+ftms Intra4ystam}}
The above findings by NEDS show pressures much less and it should be noted that NEDS did not use a conservative approach in their analysis.
During the next refueling outages, a walkdown will be performed by NEDS to gather additional structural data on these filter houses.
Recommendations will then be made for modifications necessary to bring these structures up to their original design requirements.
Approved by r
cJcc lA N
R ccIa - Man er' clear Design - Structural Er, Analytical CES/ JAR: dm xc:
J. A. Kobyra/R.
C. Armstrong Ref stru'thv+ftms Intra4ystam}}

Latest revision as of 14:20, 7 January 2025

Provides Update to 930611 Initial Response to NRC Bulletin 93-002.Analysis Confirming That Subj Roughing Filters Will Remain Confined within Kidney Fans in Event of LOCA Inside Containment Encl
ML17331A927
Person / Time
Site: Cook  
Issue date: 08/06/1993
From: Fitzpatrick E
INDIANA MICHIGAN POWER CO. (FORMERLY INDIANA & MICHIG
To: Murley
NRC OFFICE OF INFORMATION RESOURCES MANAGEMENT (IRM)
References
AEP:NRC:1188A, IEB-93-002, IEB-93-2, NUDOCS 9308110256
Download: ML17331A927 (46)


Text

ACCELERANT 0 DOCUMENT DlSTR BU'r.'j.ox SX~"j.'j.'Xi REGULA INFORMATION DISTRIBUTIO YSTEM (RIDS)

ACCESSION NBR:9308110256 DOC.DATE: 93/08/06 NOTARIZED: NO DOCKET ¹ FACIL:50-315 Donald C.

Cook Nuclear Power Plant, Unit 1, Indiana M

05000315 50-316 Donald C.

Cook Nuclear Power Plant, Unit 2, Indiana M

05000316 AUTH.NAME AUTHOR AFFILIATION FITZPATRICK,E.

Indiana Michigan Power Co. (formerly Indiana 6 Michigan Ele RECIP.NAME RECIPIENT AFFILIATION MURLEY Document Control Branch (Document Control Desk)

I

SUBJECT:

Provides update to 930611 initial response to NRC Bulletin 93-002.Analysis confirming that subj roughing filters will remain confined within kidney fans in event of LOCA inside containment encl.

DISTRIBUTION CODE:

IE11D COPIES RECEIVED:LTR ENCL SIZE:

TITLE: Bulletin Response (50 DKT)

NOTES:

RECIPIENT ID CODE/NAME PD3-1 PD INTERNAL: AEOD/DOA NRR/DRPW/OGCB NRR/DSSA N ~ II-2 REG FI 02 G

FILE 01 EXTERNAL: NRC PDR COPIES LTTR ENCL 1

1 1

1 1

1 1

1 1

1 1

1 1

1 1

1 RECIPIENT ID CODE/NAME DEAN,W NRR/DE/EMEB NRR/DRSS/PEPB NRR/DSSA/SRXB NRR/SCSB RES/DSIR/EIB NSIC COPIES LTTR ENCL 1

1 1

1 1

1 1

1 1

1 1

1 1

1 D

A, D

i NOTE TO ALL"RIDS" RECIPIENTS:

PLEASE HELP US TO REDUCE WASTE! CONTACT THE DOCUMENT CONTROL DESK, ROOM Pl-37 (EXT. 504-2065) TO ELIMINATEYOUR NAME FROM DISTRIBUTION LISTS FOR DOCUMENTS YOU DON'T NEED!

D TOTAL NUMBER OF COPIES REQUIRED:

LTTR 15 ENCL 15

Inmana Michigan Power Company P.O. Box 16631 Coiumbus, OH 43216 Z'NDIANA NICHI64N IaOMfER Donald C.

Cook Nuclear Plant Units 1 and 2

Docket Nos.

50-315 and 50-316 License Nos.

DPR-58 and DPR-74 BULLETIN NO. 93-02'EBRIS PLUGGING OF EMERGENCY CORE COOLING SUCTION STRAINERS AEP:NRC:1188A S. Nuclear Regulatory Commission Attention:

Document Control Desk Washington, DC'0555 August 6, 1993

Dear Dr. Murley:

The purpose of this letter is to provide an update to our initial response to NRC Bulletin 93-02 dated June 11, 1993.

The initial response noted that additional time was required to investigate the capability of ventilation units in the containments of Cook Nuclear Plant to contain fibrous filters following a

Loss of Coolant Accident (LOCA).

Specifically, the Containment Auxiliary Cleanup Ventilation Units (kidney fans) located in the basement of the lower compartment of Cook Nuclear Plant containments needed to be analyzed.

As stated in the original letter, these were the only sources of the fibrous material addressed in the bulletin that posed a concern for blocking the containment recirculation sump.

An analysis has been completed that confirms that the subj ect roughing filters will remain confined within the kidney fans in the event of a LOCA inside containment.

As requested by your staff, a

copy of the analysis is included as an attachment to this letter.

This analysis utilized the leak before break philosophy, developed by Westinghouse as part of the resolution of unresolved safety issue USI-A2.

Leak before break is applicable to Cook Nuclear Plant via amendment no.

76 to Unit 2 and an NRC SER dated November 22, 1985.

loooaI As indicated in our original response letter referenced

above, the filters discussed

'have been found to be unnecessary for the functionality of the ventilation units.

Current plans are to ensure the roughing filters are removed from Unit 1

during the next refueling outage scheduled to begin February 1994.

If Unit 1 is forced into an unplanned outage of sufficient duration prior to this

date, every effort will be made to ensure the removal of the roughing filters sooner.

We verified by inspection that there were no roughing filters in Unit 2 during the forced outage which began August 2, 1993.

9308ii0256 930806 PDR ADQCK 050003i5 8

PDR

Dr. T. E. Murley AEP:NRC:1188A This letter is submitted pursuant to 10 CFR 50. 54(f)

and, as
such, an oath statement is attached.

Sincerely, r'~gpss)

E.

E. Fitzpatrick Vice President eh Attachment CC:

A. A. Blind - Bridgman J.

R. Padgett G. Charnoff NFEM Section Chief J.

B. Martin - Region III NRC Resident Inspector

- Bridgman

COUNTY OF FRANKLIN E.

E. Fitzpatrick, being duly sworn, deposes and says that he is the Vice President of licensee Indiana Michigan Power Company, that he has read the forgoing response to Bulletin 93-02:

Debris Plugging of Emergency Core Cooling Suction Strainers and knows the contents thereof; and that said contents are true to the best of his knowledge and belief.

Subscribed and sworn to before me this ~4 day of 199~8 OTARY UBLIC plIh 0 )il'iL NOTS aiY F'UCUC. STQE OF OHIO

ATTACHMENT TO AEP:NRC:1188A ANALYSIS OF A LOCA ON THE VENTILATIONUNITS

ATTACHMENT TO AEP:NR 88A Page 1

ANERlCAN ELECTRIC PWKR Dato July 29, 1993 sub)oct Effeet of Loss of Coolant Accident. on Ventilation Units Housing Fibrous Materials prom T. J. Crawford xo S.

A. Hover~

Responding to your memo of June 11,

1993, we have analyzed the effects of a LOCA on the ventilation units.

The maximum differential pressure across the ventilation units was calculated to be less than 0.1 psi.

The break of the accumulator line feeding the cold leg was used as the LOCA. Because of the

'Leak-before-break'riteria the double-ended cold-leg break or cross-under leg break were not considered as the LOCA scenario.

Direct impingement or dynamic effects were not included since the accumulator line enters the cold leg near elevation 615 and the number 2 steam generator and its four support columns are between the break location and the ventilation unit.

Attached for your information and record retention is a copy of the calculation. If you need additional information please do not hesitate to contact me at 1284.

cc: S.J.

E.ED G.R.

M.K.

Brewer / J.B. Kingseed / S.A. Hover Fitzpatrick Burris Jr.

Guha / C.D. Olsen / File N930601 w

attachment w/o II w/o It w/o If Intra-Syatom

ATTACHMENT TO AEP:N 188A Page 2

May 1980 Jan

1984, Rev 1

Dec 1988, Rev 2

Calculation Cover Sheet Technical Assessment Section Job No.: N930601

Title:

Effect of Loss of Coolant Accident on Ventilation Units Housin Fibrous Materials or Filters System:Emer enc Core Coolin Plant:

D.C.

Cook File No.:

Unit:

1 6

2 Design Basis:~NA By:

T. J. Crawford Review: C.

P. Lin Approval:M. K. Guha Date:~726 93 ethod: 4 ~

~

C.< > 4 8.4 Date: 7 >

3 Date:~7~

VJ Table of Contents Pacae 1.

Problem 2.

Conclusion 3

Procedure 4.

Assumption(s) 5.

Content(s) a.

Compartment Energy b.

Initial Compartment Masses c.

Flow Rates Between Compartments d.

New Compartment Masses e.

New Thermodynamic State of Superheated Compartments f.

New Thermodynamic State of Saturated Compartments g.

Heat Transfer to Containment Walls h.

Heat Transfer Within Containment Walls 10 10 12 6.

Reference(s) 7.

Attachment(s).

13 15

ATTACHMENT TO AEP:N 188A Page 3

TECHNICAL ASSESSMENT CALCULATION VERIFICATION CHECKLIST Page 0 of 'SQ Reviewer:

Q~

Section lleneger:

J~tt-~+

Date:

Review of the calculation shall include evaluation against the following questions:

YES NO Basis for Determination 1.

Was an appropriate method used?

2.

Are the results reason-able compared to the input?

~rM f CJ l< l-~SOS.

3.

Are the results numerically correct?

4.

Are the equations used correct and the reference documented?

5.

Were the correct inputs used and their sources documented?

c prP~ 5 6.

Are the assumptions reasonable and properly documented (including appro-priate references and adequate justi-fication)?

7.

Is the calculation acceptable?

P<sM

>< ~ ~oVg-

ATTACHMENT TO AEP:N 1188A I ~V Page 4

EFFECT OF L.O.C.A.

ON VENTILATIONUNITS 1.

PROBLEM In a memo of June ll, 1993(Ref; 1), Mr. S.

A. Hover of Nuclear Operations requested Technical Assessment to analyze the effects of the accumulator leg break LOCA blowdown forces on the Containment, Auxiliary Cleanup (Ventilation)

Unit located in the basement of lower containment at the D.C. Cook Plant.

The purpose of the analysis is to determine the differential pressure that may be exerted on the ventilation unit during a LOCA, and would be used by Structural Engineering to determine the ability of units to contain fibrous filter materials.

I The analysis would be in response to NRC bulletin 93-02 and would be used to support continued operation until the next refueling outage.

ATTACHMENT TO AEP:

188A

~

<</ 5Q 2.

CONCLUSION The maximum differential pressure across the cleanup or ventilation units was calculated to be less than 0.1 psi.

The break of the accumulator line feeding the cold leg was used as the LOCA.

Because of the 'Leak-before-break'riteria the double-ended cold-leg break or cross-under leg-break were not considered as the LOCA scenario.

Direct, impingement or dynamic effects were not included since the accumulator line enters the cold leg near elevation 615 and the number 2 steam generator and its four support columns are between the break location and the ventilation unit(Refs; 8

& 20).

The unit sits on elevation 598 and is about 10 feet high, bringing the top of the unit to elevation 608.

The pressure and temperature were calculated for the various containment compartments.

The initial'ressure, temperature, and relative humidity were 14.7 psia, 90.0 F, and 100% respectively.

The initial temperature of the ice condenser was 27.0 F.

The computer program written for this analysis(LOCA01) was checked for reasonableness by using it to analyze the double-ended cold leg break with the appropriate initial pressure and temperatures, and comparing it with the Westinghouse TMD results and the MPR Associates results displayed on p IV-19 of Ref. 5.

The results are tabulated below.

Peak Sub-Compartment Pressure(psia)

LOCA01 MPR TMD Peak Deck Differential Pressure(psi)

LOCAOl MPR TMD 29.0 26.0 23.9 8.4 8.3 8.6 The LOCA01 program calculates a slightly more conservative pressure and differential pressure.

The relatively close agreement of LOCAOl with TMD and MPR provides additional confidence in the results of the present analysis of the ventilation unit.

ATTACHMENT TO AEP:N 1188A

/'g o page 6

3.

PROCEDURE A. Obtain the dimensions of the air filtering unit(Ref. 2), the distances between the unit and the crane wall, the unit and the biological shield, the unit and the ceiling, and the two elevations.

Calculate flow area for steam/water mixture around the air unit.

B. Obtain the diameter of the accumulator line and the maximum blowdown flow rate from it(Fig. 2-3, Ref.

3).

Use a realistic value of temperature for cold leg water to calculate the density and quality of the steam-water mixture that would be released.

C. Obtain necessary. input data.

Much of this was taken from Refs.

4, 5, 6, 7, 8.

This included the dimensions of the containment building, sub-compartment

volumes, flow areas between compartments, wall surface areas and thicknesses, and mass and area of metal in the compartments.

D. Divide the containment building into twelve sub-compartments or regions.

The lower compartment was divided into six regions.

The two fan-accumulator rooms, the reactor cavity, and the instrument room were four more regions.

The ice condenser and the upper compartment were two more regions.

E. Divide the containment walls into slabs or nodes of increasing thickness from the surface to the interior.

F. Write a computer program to calculate the thermodynamic states and properties in each compartment, and the flow of air and steam among compartments.

This was done by incorporating some of the techniques used in t:he MARCH program(Ref.

9).

G.

Make the necessary calculations and tabulate the results.

ATTACHMENT TO AEP:N 188A 4.

ASSUMPTIONS

~

(

~

J~

Page~

7 7/7.qf> >

A. The containment building may be accurately represented as a lower compartment divided into six regions separated by a steam generator or the filtering unit, the dead ended regions and reactor cavity, the ice condenser and the upper compartment, for a total of twelve regions.

B. The pressure and temperature were uniform throughout each compartment.

The air and steam or water vapor formed a homogeneous mixture.

C ~ The flow rate of air and steam among compartments could be adequately modelled using a form of compressible flow equation(p 3-5, Ref.

10) with an appropriate flow coefficient, flow area opening, specific

volumes, and the pressure difference between the compartments.

This equation includes an acceleration pressure loss as well as form losses.

'The flow coefficients were obtained from Refs.

4 8 5. The flow coefficient for the passage formed by the filtering unit was calculated using Ref.

12, p335-335.

As was done in Ref.

6, the flow calculated for each time step was limited somewhat by a restriction factor to eliminate the excessive changes in compartment mass in each time step, and the resulting large pressure oscillations that would be observed without it.

Ref.

6 calculated the number of moles of air and vapor that must be transferred to bring the pressure of two adjacent compartments to an equilibrium pressure.

The number of moles to transfer was calculated for the largest flow passage area for a compartment; flow through smaller areas was then based on flow through this largest area.

The present calculation used a very small time step(0.0001 sec) to utilize a simple restriction factor (/1.4),

and avoid calculating moles transferred and flows based on large and small volumes and flow areas.

D. Flow of liquid or water between adjacent compartment floors was also calculated using a weir flow type equation with the difference in water depth.

This method was also used in Ref.

16.

E.

The air was treated as an ideal gas.

The value of constant pressure specific heat was assumed constant at 0.240 Btu/ibm/F. The value of constant volume specific heat was also assumed constant and was calculated using Cv = Cp R/778.16 The internal energy of air was a function of temperature only.

F. The steam/water vapor was also treated as an ideal gas when calculating the number of moles in a compartment or its average molecular weight.

Steam properties were taken from Ref.

11.

G. The containment walls were semi-infinite slabs, and heat transfer only occurred perpendicular to the thickness.

The walls were insulated on the outside surface.

They could absorb heat from the air/vapor mixture, but could not loose heat to the outside.

ATTACHMENT TO AEP:N 188A

/

Page 8

~)'~/e a H. The floor between the upper and lower compartments was treated as a

wall insulated at the center line." Each room could access half the wall thickness.

The walls separating the lower compartment from the dead-ended region was treated the same.

The walls between the upper compartment and the ice condenser were neglected.

J.

The metal equipment in the lower and upper compartments was also modelled as a slab, and heat flow and temperature were calculated similarly to the concrete walls.

K. The temperature of containment air was initially 90 F, the pressure was 14.7 psia, and the relative humidity was 100%.

L. The temperature of the containment walls was initially 90 F.

M. All ice condenser lower plenum inlet doors and outlet intermediate deck doors were assumed to be open.

N. The ice condenser baskets and ice were treated as a wall with heat transfer being calculated as in. item F.

The heat transferred from the steam/air mixture to the ice was calculated at each time step.

The corresponding amount of ice melt was then calculated.

O. Emissivity of the gas mixture to the walls was 0.3 P.

No credit was allowed for the containment spray system.

OTHER INPUTS/DATA The compartment volumes, wall surface

areas, thicknesses, physical properties, etc.

were taken from Refs 6 and 7.

The wall surface areas were re-apportioned for the new volumes based on the amount of perimeter or arc covered by the volume(Ref. 8).

These are listed in the computer output.

The containment walls are described in the Attachments.

Only a portion of the floor surface area between the upper compartment and the lower compartment was considered.

The inside diameter of the accumulator line was 8.75 inches(Ref.

19) and the maximum blowdown flow rate from it was taken as 24400 lb/sec/ft**2 (Fig. 2-3, Ref. 3).

This value corresponds to the mass flux at 2250 psia and 540 F, the conditions of cold-leg saturated liquid. It was kept constant for the entire transient to assure a very conservative flow rate.

For comparing the LOCA01 program against the Westinghouse TMD results(Ref.

4) and the MPR Associates results(Ref.

5), the cold leg diameter used was 31 inches, the blowdown flow rate used was 9882.777, and the temperature was 534.6 F.

These values gave the 103,600 lb/hr and 530 btu/ibm inputs respectively of p IV-2, Ref. 5.

ATTACHMENT TO AEP:N 188A P4g

/<9 /g~

The number of ice baskets was 1944; 'their length was 48 feet,; their diameter and pitch were 12 and 14 inches respectively (Ref. 18).

The surface of the walls and other structures within the ice condenser compartment were neglected.

Natural convection and condensation heat transfer coefficients between the walls and the steam/air mixture were calculated using the equations of pp 6-13 to 6-16(Ref.

9)

Radiation heat transfer was also included.

Where steam/air velocities were high enough forced convection heat transfer was included using Ref.

13, p148 for the walls and pl76 for the ice baskets.

Heat transfer through the slab walls was modelled by dividing each wall into adjacent layers of varying thickness, using pp 6-15 and 6-16 (Ref. 9).

The ice condenser was initially at 27 F, and it contains 2,370,000 lbs of ice also at 27 F. Ice properties were from Ref.

14.

ATTACHMENT TO AEP:N 1188A

'/>u Page 10 5.

CONTENTS A.

COMPARTMENT ENERGY..

The total internal energy of each compartment was calculated using the First Law of Thermodynamics for an open system.

The change in energy equals the mass flow of enthalpy in minus the mass flow of enthalpy out minus the heat transferred to the walls.

The new internal energy was calculated in subroutine ENERGY using U2=

mi *hi

me*he

Q

+

Ul Each flow rate in and out was averaged over two time steps using mi =

( mi(2)

+ mi(1)

) / 20 B. INITIALCOMPARTMENT MASSES The initial volume of the ice was calculated using Ref.

14 with,the initial ice mass.

The volume of air and vapor in the ice condenser was provided in Refs.

6 or 7.

The total volume of the ice condenser was calculated by adding the volumes of ice and air.

VTOT(1,7)

= W(1,5)

  • VICE where W(1,7)

= Ice mass VICE

= specific volume of ice VTOT( 3 I 7 )

VTOT( 2 g 7 )

+ VTOT( 1 I 7 )

where VTOT(3,7)

VTOT(2,7)

VTOT(1,7) 7 total ice condenser volume air and vapor volume ice volume the ice condenser compartment identification no.

The initial water vapor mass in each compartment, including the ice condenser, was calculated using the steam tables with initial pressure, temperature, relative humidity, and open or void compartment volume.

W(2,NC)

= VTOT(2,NC) / VGT( T(NC)

) *

( RH(NC) / IOO.

)

where VTOT(2,NC)

= open volume VGT(T(NC)') = specific volume of vapor at temperature T(NC)

RH(NC)

= relative humidity

ATTACHMENT TO AEP:N 188A (P%

Page ll 7/~~/g s The initial air mass in each compartment was calculated using the ideal gas law with partial pressure of air, temperature, and open volume.

W(4,NC)

= P(2,NC)

  • 144.
  • VTOT(2,NC) / R /

( T(NC)

+ 460.

)

where P(2,NC)

= partial pressure of air

= total pressure partial pressure of water vapor R

= ideal gas constant for air C.

FLOW RATES BETWEEN COMPARTMENTS The flow rate of gas or vapor between adjacent compartments was calculated using p 3-5, Ref.

10 F()

=

(

( 2.0

  • gc
  • 144.
  • DP()
  • AREA()**2 ) /

( 2.0

  • dv()

+ KLS()

  • v()

) )**1/2 where DP()

AREA()

KLS()

v()

dv()

pressure difference between compartments flow area flow loss coefficient average specific volume of mixture difference between v() between compartments The amount of air and vapor mass transferred in each time step was calculated using DF()

=

F()

  • TS

/ DPDFS where TS

= time step DPDFS

= a flow limiting factor(1.4) for multiple flow paths through each compartment to help avoid pressure oscillations and which helped benchmark the program against the TMD and MPR results.

The flow of'iquid water between adjacent compartments was calculated using a

version of the weir flow equation of p 479, Ref.

15.

F(l,NP,)

= Cflw

  • rho
  • Width *

( Z(NF(NP))

Z(NT(NP))

) / 12.

whereCflw rho Width Z(NF,)

Z(NT,)

weir flow coeff; taken large to accommodate inertia.

density of water.

a characteristic width between adjacent compartments.

depth of water in 'from'ompartment, larger than Z(NT,)

ATTACHMENT TO AEP:N 1188A

'/'3q

~ d P~s~ >>

7/z(z~

The flow of enthalpy per time step from a compartment was calculated using DH(j,NP)

= DF(j,NP)

  • H(j,NC) where H(j,NC) = the enthalpy of fluid type j in compartment NC DF(j,NP)

= mass flow per time step along flow path NP j

= liquid, vapor, and air D.

NEW COMPARTMENT MASSES..

The new masses of liquid, vapor, and air were calculated using the amounts of mass transferred averaged over the last two time steps

using, W(j,NC) = W(j,NC)

+

( DF(j,in, 1)

+ DF(j,in, 2)

) / 2.0

)

( DF(jioutg1)

+ DF(jgoutg2)

) / 2 '

)

where DF()

?in out 1,2 mass flow per time step liquid, vapor, and air flow path into the compartment flow path from the compartment

previous, present time step For gas flow the 'flow from'ompartment was always at a pressure greater than the 'flow into'ompartment.

Pressure in each compartment was checked each time step to identify from and to numbers.

For 1'iquid flow the 'flow from'ompartment had a greater depth of liquid than the 'flow into'ompartment.

ATTACHMENT TO AEP:N 1188A P IV/ Pg Page 13~)~~/>>

E.

NEW THERMODYNAMIC STATE OF SUPERHEATED COMPARTMENTS The new pressure, temperature, etc., of each superheated compartment following the additions or removals of mass and energy was calculated by balancing the total volume with component(vapor and air) volumes, and balancing total energy with component, energy.

This gave two equations(

volume and energy

) and two unknowns( total pressure and temperature

). The system was solved by iteration with a Newton-Raphson technique for non-linear equations,

( pp 37-39, Ref.

17)

The two equations were expressed as the following two functions, Gl(P2,T2)

= VTOT(3,NC)

( Mg*Vg(P9,T2) + Ma*Va(Pa,T2)

) / 2.0 G2(P2,T2)

= U(4,NC)

( Mg*Ug(Pg,T2)

+ Ma*Ua(T2)

)

where VTOT(3,NC)

U(4,NC)

P2,T2 Pg,Pa Mg,Vg,Ug Ma,Va,Ua compartment total volume compartment total energy new total pressure and temperature partial pressure of vapor, air

mass, specific volume, and specific energy of vapor
mass, specific volume, and specific energy of air Additional properties such as specific enthalpy, xelative humidity, etc.

were then calculated using the new P2 and T2.

F.

NEW THERMODYNAMIC STATE OF SATURATED COMPARTMENTS The new pressure, temperature, etc., of each saturated compartment following the additions or removals of mass and energy was calculated by balancing the total energy with component energy.

This gave one equation(

energy

) and one unknown( temperature

). The system was solved by iteration with the bisection technique.(

p 18, Ref.

17)

The energy balance equation was expressed as the following function,

= compartment total energy

= new temperature

= mass of liquid, vapor, and air

= internal energy of liquid, vapor, air Gl(T2) = U(4,NC)

( Mf(T2)*Uf(T2) + Mg(T2)*U9(T2) + Ma*Ua(T2)

)

where U(4,NC)

T2 Mf,Mg,Ma Uf,Ug,Ua Additional properties such as pressure, specific enthalpy, relative humidity, etc.

were then 'calculated using the new T2 and the saturated properties.

ATTACHMENT TO AEP:N 188A G-HEAT TRANSFER TO CONTAINMENT WALLS(SLAB)

Heat transfer to the slab walls by natural convection and condensation was calculated based on the methods of Ref.

9, pp 6-13, 6-15.

A radiation heat transfer coefficient and a forced convection coefficient were also included for this calculation.

A total heat transfer coefficient was calculated by summing the individual heat flows.

qt

=

qc

+

qn

+

qr' qf ht*(Tb Tw)

= hc*(Tsat Tw)

+ hn*(Tb Tw)

+ hr*(Tb Tw) +

hf*( Tb Tw)

Solving for ht gives, ht

=

hc*(Tsat Tw)/(Tb Tw)

+

hn

+

hr

+

hf whereqtqc,qn,qr,qf hthc,hn,hr,hf Tb,Tsat,Tw total heat flux(Btu/hr/ft**2) heat flux due to condensation, natural convection, radiation, and forced convection.

total heat transfer coefficient(Btu/hr/ft**2/F) heat transfer coefficients due to condensation, natural convection, radiation, and forced convection.

bulk and saturation temperatures of gas mixture and wall surface temperature.

Condensation was assumed to occur only if the wall temperature was less than the dew point temperature.

ATTACHMENT TO AEP:N 1188A H.

HEAT TRANSFER WITHIN CONTAINMENT WALLS(SLABS) g

/ t./

v)+!

zg ~~

The walls were divided into adjacent slabs or nodes of increasing thickness as per Ref. 9.

The heat transfer coefficient for conduction heat transfer between adjacent slabs was calculated using ht(n)

= k /

( x(n) x(n-1)

)

where ht(n)

= total heat transfer coefficient(Btu/hr/ft**2/F) node n

x(n)

= location or coordinate of node n

k:

= thermal conductivity of concrete(Btu/hr/ft/F)

The conduction heat transfer entering node n from node (n-1) on the left) was calculated using, qw(n')

= ht(n)

( Tw(n-1)

Tw(n)

)

And the conduction heat transfer leaving node n to node (n+1).on the right) was calculated using, qw(n+1)

= ht(n+1) *

( Tw(n)

Tw(n+1)

)

The temperature change of the first node was calculated using a heat balance:

DTw(l) =

(

QWavg qw(2)

)*TS /

( rho

  • dx(l)
  • Cp

)

where QWavg qw(2)

TS rho,Cp dx(1)

( qt(TS=1)

+ qt(TS=2)

) / 2.0 time averaged heat flux entering surface of node l.

conduction heat flux leaving node 1 to node 2

time step size density and heat capacity of concrete or steel.

thickness of control volume, node 1

The temperature changes of the other nodes was calculated in a similar manner using:

DTw(n)

=

( qw(n) qw(n+1)

)*TS /

( rho

  • dx(n)
  • Cp

)

where qw(n)

= heat flux leaving node n-1 and entering node n

qw(n+1)

II II n

II II n+1 dx(n)

= thickness of control volume, node n

ATTACHMENT TO AEP:N 188A 6.

REFERENCES 76~))q 1 ~

Memo of May 27,

1993, from S.A. Hover to T.J. Crawford, titled 'Effect of Fibrous Material on Recirculation Pump Screen'.

2 ~

3.

Drawing No.

107C-890301-H, from American Air Filter Co., Inc.,

Louisville, Ky., 1972.

Larson, J.R.,

System Analysis Handbook, NUREG/CR-4041, EGG-2354, Revision 1,

November, 1985.

4.

5.

6.

Updated F.S.A.R. for D.C. Cook Plant, Tables 14.3.4-15, 14.3.4-16, and Figure 14.3.4-18 MPR Associates, Inc., Ice Condenser Containment Independent Analysis Program Final Report, MPR-340, April, 1972.

Technical Assessment Section calculation N-921001, Containment Building Pressure and Temperature in Event of DHR Failure While in Mid-Loop Operation,

January, 1993.

7

~

8.

9.

Containment Data Collection Notebook, D.C.

Cook Nuclear Plant I.P.E.,

prepared by Fauske 6 Associates, Inc., January, 1992.

A.E.P. drawings 12-3181-14, 1-5688-10, and 1-5699-10.

NUREG/CR-3988, BMI-2115, MARCH 2 Code Description and Users Manual.

10.

Steam, Its Generation and Use.,

40th ed.,

Babcock 6 Wilcox Company, Barberton,

Ohio, 1992.

A.S.M.E. Steam Tables, Thermodynamic and Transport Properties of Steam, 2nd ed.,

1967.

12.

13.

Idelchik, I.E., and Fried, E., Flow Resistance:

A Design Guide for Engineers.,

Hemisphere Publishing Co.,

New York, 1989.

Holman, J.P.,

Heat Transfer, 3rd. ed. McGraw-Hill Book Co.,

New York, 1972.

14. Perry, R.H.,

and Chilton, C.H., Chemical Engineer's

Handbook, 5th ed.,

Table 3-275.

15. Streeter, V.L., Fluid Mechanics, 5th ed., McGraw-Hill Book Co.,

New York, 1971.

16. Technical Assessment Section calculation N-920101, Fire Protection Water Storage Tanks for Unit 1

6 Unit 2 at D.C. Cook Plant,

January, 1992.

ATTACHMENT TO AEP:N 188A

17. Grove, W.E., Brief Numerical Methods., Prentice-Hall, Inc 1966.
18. Various written communications between Nuclear Safety Section and Technical Assessment(Attached).
19. Verbal communications between S.A. Hover of Nuclear Operations and T.J. Crawford of Technical Assessment.

20.

Tubeco Inc., drawing 1-51-31, isometric pipe drawing.

ATTACHMENT TO AEP:N 188A Page 18 J>pf~

7.

ATTACHMENTS A.

Sketch of Containment with Compartments and Flow Paths B.

Descriptions of Compartment Volumes and Containment Walls or Slabs C.

Flow Diagram of Computer Program LOCA01.

D.

Selected References.

E.

Program Listing of LOCA01.

F.

Program outputs for; accumulator leg break(d=8.75),

run time = 0.1112 sec cold leg break(d=31.),

run time = 0.2752 sec

ATTACHMENT TO AEP:N 188A

"'"(w~

Page 19 l jg o

REACTOR COOLANT SYSTEM COMPARTMENT AREA

,NO.

3 DOOR ICE CONDENSER

~ )

<c

)

~

STEAM GENERATOR 2'og r')

~

~

C l3 AREA 2 DOOR

~t

/

~ ~

A v

V1

') e$

,i C

h

~

~ ~

'V C'

l 3

~ a ARE.

NO. 4 D

~ ~~ ~

~ H

)

0+ ~

'v~r-

~ ~ )

~ (

r

% ~

~l-l

\\

ui

C ~

i~

r OR r ~

~

~,

~ (y )

AREA NO. I DO REACTOR COOLANT SYSTEM RUPTURE

~

k

~ s ~

l,5

~..a..~.

~

~I r C

~

FLOV/'UCT UNDERNEATH REFUELLING CANAL ~

AREA jl NO.

5 DOOR

>(). ~7zs'e J

+(z. 2Y'vr la i3 -.'/0 <>~

V<q=2y u~ v V yP

>5. X"Q~

PLANT DESIGN - PLAN VIE%V SECTION OF REACTOR CCO3 ANT SYSTEM.i COhiPARTi.fENT

~O

.7

) Qv ryg

ATTACHMENT TO AEP:N 188A 0

fg

)

00 l IP/g~

f'age 20

~Jz.~gg~

ee 0,

F1N COMPARTMENT /

'(. 6 I

r

'v 1CC UPPER COKP ARTIST g5 61TK 33 (0

1CC Qr I

IS,Q I

I C

.G.i Qr 1CC Jg~ o

/p

< 8 FiN CDllPMWKNT

~/

O 0

g. -

~

ATTACHMENT TO AEP'NRC'1188A Page 21

= 9~~$

SG

) Rgb~

..-vg 27<$ 0 i=7) ltu'0

~

i

~ M

~

7 lq 0 = )~"

7

~ /v h= ) ~'t IC3 0

MS A=)o 9o o'4

/i""

SG 3 QiC.

)VSY9b P ~Zgo3

)ro>g =

) Z4 1~>~

7 R

D4 IC4

>7'r$3 ~

w n )(

Jj A-)) 3 Ir ti: i-r SG DUCT R

5 I C5 4=72.

2,Z 4'o,i 0~ )5c.

REACTOR CONTAINMENTSUBVOLUMES AND F'LOW PATHS

ATTACHMENT TO AEP:

1188A COMPARTMENT NUMBERS AND VOLUMES(Refs.

4 a

5

)

< /pp Page 22

~ ~/~~

No.

Description Break region in Lower Compartment between Refueling Canal and Steam Generator No.

2 (S/G 2)

Volume between S/G 2 and Ventilation Unit.

Volume (ft**3) 27 250.

19 000.

Volume between Ventilation Unit and S/G 3

Volume between S/G 3 and S/G 4

Volume between S/G 4 and S/G 1

Volume between S/G 1 and Refueling Canal 19 000.

90 000.

38 000.

22 500.

Ice Condenser(void volume)

Upper Compartment Dead Ended Region Housing Accumulators 2 and 3

126 940.

745 896.

27 450.

10 Dead Ended Region Instrument Room Dead Ended Region Housing Accumulators 1 and 4

17 111.

27 450.

12 Reactor Cavity 19 731.

ATTACHMENT TO AEP:N 188A Page 23 z/z ~g>

DESCRIPTION OF CONTAINMENT WALLS OR HEAT SINK SLABS(Refs.

4 5: 5)

No.

Description Surface Area (ft**2)

Thickness (ft)

Removes Heat From Cmpt 1

Between Cmpts 1 a'nd 9

2 Between Cmpts 2 and 9

3 Between Cmpts 3 and 9

\\

4 Between Cmpts 4 and 9

5 Between Cmpts 4 and 10 6

Between Cmpts 4

7 Between Cmpts 7

and ll I

and 7

8 Between Cmpts 5 and ll 9

Between Cmpts 6 and ll 10 Between Cmpts 9 and 1

11 Between Cmpts 9 and 2

12 Between Cmpts 9 and 3

13 Between Cmpts 9 and 4

14 Between Cmpts 10 and 5

15 Between Cmpts 11 and 4

16 Between Cmpts ll and 5

17 Between Cmpts 11 and 6

18 Interior of Cmpt 1

19 Interior of Cmpt 2

20 Interior of Cmpt 3

21 Interior of Cmpt 4

22 Interior of Cmpt 5

23 Interior of Cmpt 6

24 Floor of Cmpt 1

25 Floor of Cmpt 2

1 392.

915.

1 006.

1 336.

3 165.

1 301.

293 148.

1 878.

1 288.

1 392.

915.

1 006.

1 336.

3 165.

1 301.

1 878.

1 288.

508.

244.

269.

1 549.

501.

447.

539.

259.

3.0/2 3.0/2 3.0/2 3.0/2 3.0/2 3.0/2 N/A 3.0/2 3.0/2 3.0/2 J

3.0/2 3.0/2 3.0/2 3.0/2 3.0/2 3.0/2 3.0/2 2.25 2.25 2.25 2.25 2.25 2.25 5.00 5.00 10

ATTACHMENT TO AEP:N 188A Page 24 26, Floor of Cmpt 3

27 Floor of Cmpt 4

28 Floor of Cmpt 5

29 Floor of Cmpt 6

30 Between Cmpts 1 and 8

31 Between Cmpts 2 and 8

285.

1 641.

531.

474.

2 511.

1 301.

32 Between Cmpts 3

33 Between Cmpts 4

I and 8

and 8

1 327.

7 654.

34 Between Cmpts 5 and 8

2 477.

35 Between Cmpts 6 and 8

2 208.

36 Between Cmpts 8 and 1

2 511.

37 Between Cmpts 8 and 2

1 301.

't 38 Between Cmpts 8 and 3

1 327.

39 Between Cmpts 8 and 4

7 654.

40 Between Cmpts 8 and 5

2 477.

41 Between Cmpts 8 and 6

2 208.

42 Between Cmpt 8 and Outside 24 567.

43 Between Cmpt 9 and Outside 4 829.

44 Between Cmpt 10 and Outside 3 288.

45 Between Cmpt ll and Outside 4 640.

5.00 5.00 5.00 F 00 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 2.875/2 3.5 3.5 3 '

3.5 10 46 Metal in Cmpt 1

47 Metal in Cmpt 2

48 Metal in Cmpt 3

49 Metal in Cmpt 4

50 Metal in Cmpt 5

51 Metal in Cmpt 6

52 Metal in Cmpt 8

9 479

~

4 556.

5 009.

28 889.

9 349.

8 334.

38 435.

0.134 0.134 0.134 0.134 0.134 0.134 0.012

ATTACHMENT TO AEP:N 188A c/p Page 25 7/re/~ ~

DESCRIPTION OF FLOW PATHS/AREAS BETWEEN COMPARTMENTS(REFS.

4

& 5)

No.

Description Flow Area (ft**2)

Loss Coeff 1

From Cmpt 1 to 2

2 From Cmpt 2 to 3

3 From Cmpt 3 to 9

4 From Cmpt 3 to 4

5 From'Cmpt 6

From Cmpt 4 to 5

6 to 5

7 From Cmpt, 1 to 6

8 From Cmpt 2 to 9

9 From Cmpt 9 to 10 10 From Cmpt ll to 10 ll From Cmpt 5 to ll 12 From Cmpt 4 to 12 13 From Cmpt 1 to 7

14 From Cmpt 2 to 7

15 From Cmpt 3 to 7

16 From Cmpt 4 to 7

17 From Cmpt 5 to 7

18 From Cmpt 6 to 7

19 From Cmpt 7 to 8,

20 From Break Line to 1

635.0 1 079.0 77.0 585.0 585.0 635.0 72.0 77.0 10.0 10.0 154.0 144.0 122.0 72.0

'2.0 487.0 155.0 155.0 2 003.0 0.4 0.300 0.170 4.200 0.340 0.340 0.300 1.450 4.200 3.000 3.000 4.200 1.500 0.890 0.890 0.890 0.890 0.890 0.890 1.430 N/A

ATTACHMENT TO AEP:N 1188A Walls and Related Compartments; file=LOCA01 Areas are from HALFLP02

& N.O.D. note book

'>(3" Page 26 Walls 1:

8 between L.C. and D.E.

ALC:= 12280.

iRC~

~

~

~

g q

6(

g Arco:= 32.1 +21.1 +23.2 +30.8 '+73.0 +30.0 +43.3 +29.7

/

ci I

/Q

/1 1I Arco = 283.2 32.1 A:=

'LC Arco 21.1 A:=

'LC Arco 23 '

A:=

'LC Arco 30.8 A:=

ALC 4 'rco 43.3 A:=

ALC Arco 73.0 A:=

'LC Arco 29.7 A:=

ALC Arco 30.0 A:=

'LC Arco Wall 7 is Ice Baskets in Program LOCAOI A9

'.=

293148.

g(( ~

- g Walls 10:

17 between D.E.

and L.C.

j2:=

10.. 17 (j2 - 9)

J>lt M=

Q I 9 Q

~Q

)1 I )

)g Walls 18:

23 are Xnterior of L.C.

>I(.~

=

I z.

Arci:= 43.9 +21.1 +23.2 +133.8 +43.3 +38.6 A18:=

3517.

43.9 A:=

'18 18 'rci 21.1 A:=

~ A18 Arci 23 '

A:=

'A18 Arci 133.8 A21

'AIS Arci 43.3 A:=

A18 22 'rci 38.6 A:=.'18 Arci

ATTACHMEMT TO AEP:N 188A Walls 24:

29 are Floor of L.C.

A24:=

3728.

y~c.y~

~>ri <

- l)Cm =

43.9 A:=.A24 24 Arci 21.1 A:=.

A24 Arci 3

A:=

A24 23-2 26 'rci 133.8 Arci A:=

. A24 43.3 28 Arci 38.6 A:=

A24 Arci l'I ('.)m

=

/

43.9 A:=

.A30 Arci z

21. 1 A:=

A30 Arci Walls 30:

35 are between L.C. and U.C.

A30:=

16246.

+ 1139.

3 23

~ 2 A:=

A30 Arci 133.8 Arci 43.3 A:=.'30 34 Arci 38.6 A:=.'30 Arci Walls 36:

41 are between U.C.

and L.C.

j3:=

36.. 41 (j3-6) l>c~= 4<8 Wall 42 is between U.C. and Outside A42

'=

24567.

)'l c.m

=

8 Walls 43:

45 are between D.E.

and Outside A43:=

12757.

(234.

126. 8)

Ared 1(

(30.0 +43.3 +29.7) 45 Arco A43

/~

73.0 A:=

'43 44 Arco n:= 43..45 Sum:= 7 An Sum

= 12757

ATTACHMENT TO AEP:N 188A Walls 46:

51 are Metal in L.C.

/So Page 28 A4

=

65616.

~/"h~

p/ c.~

43.9 A:=.'A46 46 Arci Z-21.1 A:=.A46 Arci 3

23 2

A:=.'A46 48 Arci 133.8 49 Arci n:= 46..51 43.3 A:=.A46 Arci S

Sum:=

An A:=..

A46

38. 6 Arci I

Sum

= 65616 Wall 52 is Metal in U.C.

A52

'.=

38435.

Summary of Wall Areas nl:= 1..

9 n2:=

10.. 17 n3:=

18.. 23 n4:=

24.. 29 nl 1391.907 914.929 1005.989 1335.537 3165.395 1300.847 1877.556 1287.839 293148

)

3 J

'I 7

n2 1391.907

)O

)3 Ig

)5)I

))

914.929 1005.989 1335.537 1300.847 1877.556 1287.839 3165.395 A

508.05 244.188 268.491 1548.452 501.106 446 '13

) &

KQ 5) z3 n4 538.53 258.838 284.599 1641.35 531.169 473.514 z.Y xl E7 z 'P n5:=

30.. 35 n6:=

36.. 41 n7:=

42.. 45 n8:=

46.. 52 n5 30 3) 7L 33 3 bg 3g 2511.357 1207.053 1327.187 7654.205 2477.034 2208.164 n6 2511.357 1207.053 1327.187 7654.205 2477.034 2208.164 3L 77 75 35 9'0 L/ /

n7 24567 4828.921 3288.351 4639.728 lf+

v/7 n8 9478.586 4555.767 5009.185 28889.177 9349.038 8334.247 38435 b

Y7 y V~

5e X)

ATTACHMENT TO AEP:N 1188A COMPUTER PROGRAM LOCA01

/9p Page 29

+/2 r/~

MAIN F, L, LT, N

READ TEND, LEDT Calc WR,

.LW CALL INITL UHVALS I'NITLS METAL DO 135 NC = 1, NCMPT CALL CLOSE1(NC) 135 CALL CLOSE2 CALL CLOSE3 1234 CALL ENERGY SATEST DO 137 NC = 1, NCMPT IF LSPRHT THEN CALL TEMPl(NC)

ELSE IF NC=7 THEN CALL TEMP7(NC)

ELSE CALL TEMP2(NC) 137 CALL SLAB CALL FLOWS IF()

GO TO 1234 CALL WRIT1 IF() CALL WRIT2 IF()

PLOT1(M)

IF()

PLOT2(M)

DATA SL, F, LT, NS, N

I I

I I

I INITL F, LT, N

Calc break flow area CALL SOLID()

CALL FCONVC1(HF())

Calc W(l:4,1:12),

P(1:3,1:12) and MOLES(),

MWC()

for all CMPTS 1:12 Estimate TRCS UHVALS F,

N Calc v(), h(), u()

for NCMPTS INITLS F,

SL, NS Calc DX(), HT()

SET TW(NS)=T(NC)

DTW(NS)=0.0 for all slabs.

ENERGY F, LT, N

Calc U(4,NC=l:12) mi*hi me*he Q(NC)

+ U(4,NC) for all Cmpts Set Q(l:12)=0.0, will calc in SLAB I

J SOLID()

(Ti, vs, hs)

Calc vs, hs of ice TEMP1(NC)

F, SL, L, LT, N

Calc new T, P, v, h for NCMPT if it is superheated.

CALL CLOSE1(NC)

TEMP2(NC)

B, F, L, LT, N

Calc new T, P, v, h for NCMPT if it is saturated.

-CLOSE1 for CLOSE EDITS TEMP7(NC)

B, F, LT, N

Calc new T, P, v, and WMELT(2)

Calc W(l:3,7), u()

VTOT(), h, etc.,

FT7=F(1:,NP,) for condensed vapor.

CALL CLOSE1(NC)

ATTACHMENT TO AEP:N 188A LOCA01..continued...

FLOWS B~ PLI 1 ~ FI SLg LTI LI N Set NF(N)=NCFT(N,1),

DFRX()=1.0, Set F(...,1)= F(...,2),

DF(...,1)=DF(

,2)

DH(...,l)=DH(...,2)

F(...,.2)=0.0, DF(...,2)=0.0, DH(

,2)=0.

Calc Z(NC), F(l,NP,.) for liquid Calc F(4,NBK,.), then F(l:2,

), DF(l:2,

),

DH(1:2,

) for the break flow path.

Calc DP(),

DV,, VBAR, F(4,NP,.) all flow paths Calc PLPS(),

NSNL(), DN(), DFRX(), all paths.

Calc DF(1,NP,.)

& DH(1,NP,.)

Calc DF(4,NP,.)

based on DF(4,1,.), various NP Calc F(2:3,NP,), DF(2:3,NP,.),

& DH(2:3,NP,.)

Calc W(3:4,NC), MOLES(), MWC() for all compartments NC=1,12 CLOSE3 for CLOSE EDITS TVOL(NC)

F, LT SLAB AI BI Fg SLI LTI NS~

N Set QW(NS,1)=QW(,2)

QW(NS,2)=0.0 Calc ASFR,TDEW,T CALL FCONVC(HF)

Calc HN, HC, HT, QW TW, Q(NC) for slabs NS=1,52 CLOSE2 for CLOSE EDITS METAL FI SLg LTg NS Calc WMTL, DXM for metal equip slabs NS=46,52 as DATA in INITLS WRITl AI BI NSI LT Write T, P, U, H, W,

F, DF, DH, QWg Qg TW(ND=l,NS=1:52) for all CMPTS WRIT2 A, LT Write TW(ND=l:S,NS=1:52)

Calc empt T* using VTOT(3,NC) and W(2:3,NC); used in SBRS SLAB & SATEST PLOT1(M)

PL Plots P(3,1:12)

T(1:12) vs Time PLOT2(M)

PL Plots P(3,1:12) on finer scale SATEST F, L, LT, N

Calc U(NC) above saturated; Is NC saturated?

FCONVI FI.SLI LTI NI NS Calc 'cross area of each empt for RE no

-ENTRY FCONVC ( HF )

Calc HF(1:52) for each slab.

P 0

Q r

r r

r ATTACHMENT TO AEP:N 1188A r

r r

Page 7 Yipes z~> 6'P~~~

lv'4>"~

I 9!

1 e

r e

3>

y. gs)

~J).+/fp

- p~z gVv f+

~

v

(

~

h QQ'0 7lg>"

v g

gS g(~

~Pry T 59~ -PPg~"

/

27-<

@0~-(5 5

m (S'"

) t C>o'~9 lv) - )Zebra AT

)v-('tv$ 0 -7 /, )

(gyes 9>) ) J j- (

33.1 ].

)q l >7p v j)

ATTACHMENT TO AEP:N 188A

/

Page 32 7gtyf~: l Bodies ofdifferent shapes in a tube; three-dimensional low; Sm/F, < 0.3 [29,38)

Diagram 10-9

~os SmlFo 2r "o 1.15cx ',

1 po/

(1 rSmlFo)

Do wodm Re' Name of a body and scheme Convex hemispherewup (without srdm~

end phne) Sm m

4 Drag coefflcient c>>

Re'=4 X 10', c>>=0.36; Re'=SX 10', c>>=0.34; r ~0.5 forr, see Diagram 10-1 7fdm Hemispher~one Sm =

m 4

Wo Fo ZO'e'=

1.35 X 10'; cx = 0.088; r ~0.5 Concave hemispherewup (without Tom end plane) Sm =

m 4

Re'=4X 10; c>>=1.44; Re' 5 X 10', cx = 1.42; r ~1.5 4mdm'onekemisphere Sm=

m 4

Wo,Fo pZO'e'=1.35 X 10', c>>=0.16; r ~0.5 Circular smooth cylinder in a flow

~

~dm parallel to the axis Sm m

4 r/dm 08 1

2 3

4 5

6 7

cx 1.0 0.91 0.85 0.85 0.87 0.90 0.95 0.99 r ~1.0 Q(o)

Ws 0

ZO 4.0 6'0 t/der 333

g

~

0

~

~

~

I

~

~

~

~

~

~ ~ t

~

I

~

~

s I

~

9

~

~

I t

I t

I I

I t

I I

I I

I I

I r

le I

It I' t

I I

Pi

~5

~ t

~

~

I

~

I I

I I

I I

I I

-lm I

I

~

I I 'I I

I I

~

~

~r~

mam laà 855

~

~

~

~

~

~

I I

~Fs~

I I I

I I

I I

lie I

I I I

ATTACHMENT TO AEP:NI 188A Page 34 DISPLAY COMPONENT DATA COMPONENT NO.: 1-PP-45-2 COMPONENT TYPE:

PUMP CENTRIFUGAL SIZE AND UNITS:

88500 GALLONS/MINUTE PLANT SYSTEM:

REACTOR COOLANT CABLE SYSTEM:

FUNCTIONAL NAME: REACTOR COOLANT PUMP g2 UNIT:

1 BUILDING: CONTAINMENT FLOOR ELEVATION: 598 ROOM:

LOWER CONTAINMENT, QUADRANT NO.

2 FEG FEG BOUNDARY:

1 0 2 02 jg1 2 RCP (REACTOR COOLANT PU PAGE 1

OF 21 CONTAINMENT AZIMUTH: 130 CONTROL PANEL: 1-RCP OTHER LOCATION ON SOUTHEAST SIDE OF STEAM GENERATOR g2-OME-3-2 INFORMATION:

ENTER NEXT COMPONENT NO.:

PF3/15=DISPLAY NEXT COMPONENT PF5/17=DISPLAY ASSEMBLY DATA PF9/21=SYSTEM MENU PRINTER ID:

PAGE NO.:

PF4/16=PRINT ALL DATA WITH M

& E NOS.:

N PF6/18=DISPLAY M

& E DATA PF8/20=PAGE FORWARD PF12/24=EXIT LU g4

ATTACHMENT TO AEP:N 1188A Page 35 FDBM043 DISPLAY COMPONENT DATA PAGE 1

OF 9

COMPONENT NO.: 1-SI-170-L2 COMPONENT TYPE:

VALVE CHECK SIZE AND UNITS:

10 INCH PLANT SYSTEM:

RESIDUAL HEAT REMOVAL CABLE SYSTEM:

FUNCTIONAL NAME: ACCUMULATOR TANK OME-6-2 OUTLET

& ECCS TO REACTOR COOLANT LOOP g2 COLD LEG CHECK VALVE UNIT: 1 BUILDING-CONTAINMENT FLOOR ELEVATION: 617 CONTAINMENT AZIMUTH-140 ROOM:

LOWER CONTAINMENT, QUADRANT NO.

2 FEG:

FEG BOUNDARY:

102.00 RCS (REACTOR COOLANT SYSTEM CONTROL PANEL:

OTHER LOCATION INFORMATION:

BETWEEN REACTOR COOLANT PUMP g1-PP-45-2 AND THE SHIELD WALL, 2 FEET BELOW THE 617 ELEVATION PLATFORM ENTER NEXT COMPONENT NO.:

PF3/15=DISPLAY NEXT COMPONENT PF5/17=DISPLAY ASSEMBLY DATA PF9/21=SYSTEM MENU PRINTER ID:

PAGE NO.:

PF4/16=PRINT ALL DATA WITH M

& E NOS.:

N PF6/18=DISPLAY M

& E DATA PF8/20=PAGE FORWARD PF12/24=EXIT LU P4

f14, Jll'VJla4441 j JV lli a

~ Jilt@ ~ s kVV4'1 ACUiCJLAT1.MCD 7/28/93 j O$C 4V p.l CALCULATION CHECK

  • Maximum Differential Pressure across the Ventilation Unit
  • by C. P. Lin A. Input Information ORIGIN :=

1 i := 1..2 j :=

1..3 1; Region 1 region between refueling canal and steam generator No 2, in which the accumulator line breaks.

Volume, V:= 27250 (ft 3) 1 Flow path(11) to the region between steam generator No 2 and ventilation unit,
Area, A
= 635 (ft 2) l,l Flow path(12) through refueling canal,
Area, A
= 72 (ft 2) 1,2 Flow path(13) to ice condenser through inlet doors,
Area, A
= 95 (ft 2) 1,3
2. Region 2

region betweem steam generator No 2 and ventilation unit,

Volume, V
= 19000 (ft 3) 2 Flow path(21) to the region between ventilation unit and steam generator No 3,
Area, A
= 1079 (ft 2) 2,1 Flow path(22) to ice condenser through inlet doors,
Area, A
= 64 (ft 2) 2I2 Flow path(23) to dead end region housing accumulators 2 and 3,
Area, A
= 77 (ft 2) 2/3
3. Lower Containment Conditions Plc := 14.7 (psia)

Tlc := 90 (F)

Water vapor partial pressure, Pw Air partial pressure, Pa Water vapor mass contained in Region Pw. 144 ~ V 1

Mw Mw =

i 1545

~ (Tlc + 460) 18 Air mass contained in Region 1 and 2, Pa-144

~ V RHlc := 100.0

= 0.698
= Plc Pw 1 and 2, Pa = 14. 002 t

58-0181 40.4533 (lb)

Mai 1545 (Tlc + 460) 28.97 I1873.167I Ma =

L1306.061]

(lb)

ATTACHMENT TO AEP:N 188A B. Flow Path Resistance 36 y := 12.8 2:= 1.0 Using Cx := 0.702 Sm

1. Flow Path through Steam Generator from Idel'Chik P.335, FO:= 1203 dm:= 11.5 l

DO := 23.2 DO Page 37 p 2 Sm:= dm. 1 Sm = 414 y= 1.2

.3333 RES:= 1.15-Cx-FO Sm 1-r FO 2

2 1

3 DO RES = 0.95 FO - Sm K:= RES.

1,1 FO K

= 0.408 l,l

2. Flow Path through Ventilation Unit from Idel'Chik P.335, FO := 1203 dm := 9.9 1 := 13.8 Sm := dm 1 DO := 51.84 DO dm y

~

y = 20.97 2

2 Using Cx := 1.11 z := 1.5 Sm

.3333 Sm = 136.62 RES:= 1.15. Cx.

FO Sm 1

FO 2

2 1

3 DO RES = 0.146 FO Sm K:= RES-2,1 FO K

= 0.115 2,1

3. Flow Path through Refueling Canal Entrance loss and velocity head, K
=

1 + 0.5 1,2 Dh = 7.299 Crane wall thickness, From Idel'Chik, P.144, 1

0.411 Dh K:= K 2,2 1,3 K

= 2.59 1,3
4. Flow Path through Ice Condenser Inlet Doors Lower inlet door opening, 84"x91.5" Hydraulic diameter, 4 (84 91.5) 1 Dh 2 (84 + 91.5) 12 1:= 3

ATTACHMENT TO AEP:N 1188A Page 38 p 3

5. Flow Path to Dead Ended Housing Accumulators 2

a 3

From FSAR Table 14.3.4-16, K:= 4.2 2/3 C. Assumptions

1. Pressures in the areas outside of region 1 a 2 are the same.

2.

From Tom s calculation results for region 1, air in the region 1 and 2

is depleted in 0.3 sec.

4. All the steam generated in the region 1 is carried out through flow paths.

D. Flow Calculations

1. Region 1

Critical flow rate from accumulator line break,-

D := 8.75 (in)

RCS cold leg conditions, Pres

= 2250 (psia)

Tres

= 541 (F) hrcs
= 536.07 (Btu/lb)

From "System Analysis Handbook",

mf := 24400 (lb/sec/ft 2) 2 n

D MFR:= mf.

MFR =

4 12 Steam generation, hrcs 58.018 Gs := MFR 1100.8 58.018 Air depletion rate, Ma 1

Sa Sa 1

0.3 1

Steam/air mixture density, Gs + Sa 1

4 1.019.10 (lb/sec) 3 6.244 F 10 (lb/sec) 3 Gs = 4.671.10 (lb/sec)

MW Sa Gs 1

18 28.97 Plc 144 MW

= 22.977 1

p

= 0.057 (lb/ft 3) 1 p

a 1

1545

~ (Tlc + 460)

MH 1

        • Assume region 1

& 2 pressure ****

Pl := 0.211 (psi above outside pressure)

P2 := 0.033 (psi above outside pressure)

ATTACHMENT TO AEP:

1188A Page 39P.4 Pressure differential across flow paths, DP

= P1 P2 1,1 DP
= Pl DP
= Pl 1,2 1,3 Steam/air flow through a flow path can be calculated by the following
equation, DP.p.144. 2-32.2 MFR:= A 0

l,j l,j Kl,j Flow ratio of path (1,2) and (1,3) to (l,l),

Al,j DPl,j Kl,j FR 1,

FRl,j 0.064 0.065 DPl,l A

1,1 Kl,l flow rate throu h 3

MFR

= 9.667.10 l,l MFR Steam/air g

path (1, 1),

Gs + Sa 1

(lb/sec)

Kl,j MFR

. FR j

Pressure differential across flow paths, 2

DP 1,'P l(j 2

A

.p l,j 1

2. 32.2 144 0.211 0.211 3

Sa

= 9.883 10 2

2. Region 2

Incoming steam flow from Region 1, Gs 3

STi := MFR STi = 4.137 '0 l,l Gs + Sa 1

Incoming air flow from Region 1, AIRi := MFR STi 1,1 Air depletion rate in Region 2, Ma 2

Sa

= + AIRi 2

0.3 (lb/sec)

(lb/sec)

(lb/sec)

ATTACHMENT TO AEP:N 188A Page 40 p.5 Steam/air mixture density, STi + Sa 2

MW

= 24.554 2

MW Dp.p 144 2.32.2 MFR:= A a

2/j 2/j K

2 /

Flow ratio of path (2,2)&(2,3) to (2,1),

2 Sa STi 2

18 28.97 Plc 144 p

p

= 0.061 (lb/ft 3) 2 1545 2

~ (Tlc + 460)

MW 2

Steam/air flow through a flow path can be calculated by the following

equation, A

2 /

FR2/j A

2,1 St K

2,1 K

2/ g te thr FR 2/

0. 012 0.012 (2/1) /

4 MFR

= 1.369 10 2,1 MFR 2,1 earn/air flow ra ough path STi + Sa 2

(lb/sec) j Pressure differential across flow paths, 2

K 2 /

DP 2/g 2

A

~ p 2/g 2

MFR FR 2 32.2 144 DP 2/

0.033 0.033 I Differential pressure across ventilation unit is less than 0.1 psi I

ATTACHMENT TO AEP:N 188A Page 41 AMERlCAN KLECTRlC POWKR Data July 30, 1993 subject Cook Nuclear Plant Containment Building, EL. 598'-9 3/8" HV-CFT Ventilation Units From C. E. Shute/

. L. Ball To J.

B. Eingseed/S.

A. Hover NEDS has performed a GT-STRUDL finite element analysis of the filter house portion of the HV-CFT ventilation units as requested by S.A.

Hover in his June 16, 1993 memo.

The analysis found that the filter house can withstand a jet impingement pressure of 0.25 psi based on the capacity of the floor anchorage and of 1.13 psi based on the capacity of the housing.

The Technical Assessment Section has established that the maximum pressure that the units can be expected to receive is less than 0.10 psi.

Therefore, the HEPA filters housed inside the box will not be dislodged in the event of a LOCA or steam line break.

The original design criteria for the filter house required that it be able to withstand a jet impingement pressure of 2 psi.

The above findings by NEDS show pressures much less and it should be noted that NEDS did not use a conservative approach in their analysis.

During the next refueling outages, a walkdown will be performed by NEDS to gather additional structural data on these filter houses.

Recommendations will then be made for modifications necessary to bring these structures up to their original design requirements.

Approved by r

cJcc lA N

R ccIa - Man er' clear Design - Structural Er, Analytical CES/ JAR: dm xc:

J. A. Kobyra/R.

C. Armstrong Ref stru'thv+ftms Intra4ystam