ML20058B495
| ML20058B495 | |
| Person / Time | |
|---|---|
| Site: | 07109151 |
| Issue date: | 06/17/1982 |
| From: | HITTMAN NUCLEAR & DEVELOPMENT CORP. (SUBS. OF HITTMAN |
| To: | |
| Shared Package | |
| ML20058B483 | List: |
| References | |
| STD-R-02-001, STD-R-02-001-R04-ERR, STD-R-2-1, STD-R-2-1-R4-ERR, NUDOCS 8207260033 | |
| Download: ML20058B495 (10) | |
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PROPRIETARY DATA SAFETY ANALYSIS REPORT FOR THE HN-100 SERIES 3 RADWASTE SillPPING CASK referencino 10 CFR 71 Type "A" Packaaino Requlations STD-R-02-001, Rev. 4 Replacenent Pages l
l l
Hittman Nuclear F. Development Corooration Columbia, Marvland 21045 l
8207260033 B20617 i
PROPRIETARY DATA NOTICE This Safety Analysis Report and the associated drawings are the property of liittman Nucicar &
I)evelopment Corporat lon, Columbia, Ma ry land.
This material is being made availabic for the purpose of obtaining required certifications by the U.S. Nuclear Regulatory Commission, enabling utilities and other firms producing radioactive waste to be registered users of equipment and services supplied by liittman Nucicar & Development Co rporat lon, and enah-ling equipment to be manufactured on behalf of and under contracts with liittman Nuclear &
Development Corporation.
Part ies who may come into possession of this material are cautioned that the informatlon is PROPRIF.TARY to the interests of Ilittman Nuclear & Development Corporation, is not to be reproduced from this report and the associated drawings, or facsimiles made of these drawings without the express wrlLLen-consent of the liittman Nuclear & Development Corporatlon.
t h
PROPRIETARY DATl; Vertical Lift Assume weld to be 85% efficient.
Minimum throat of weld - (Sin 450)3/4" = 0.53" Weld strength per inch = 0.85(0.53' x 1")(21,000 psi) =
9460lbs/in. of weld Weld required = 39,754 lbs/9460 lbs/in. of weld = 4.2 in.
of weld 4.2 in. << (2" + 2" + 12" + 7.75" + 6")
F.S. = 7.0 3.1.4.4 Tiedown Lugs for Lifting Cask (inadvertant use)
If it is assumed the entire load is carried by the tiedown lug, Section Modulus = (bh?)/6: where b = 15.5 in., lenoth of tiedown luq: and h =
2", thickness of tiedown lup, (See Diagram page 20).
Tiedown lug section modulus = lb.5 (2)(2/6) = 10.33 in' Stress =(39,754 lbs)(3"/10.33 in ) = 11.5 KSI where 3" is 3
i the distance from the cask surface to the centerline of the hole.
11.5 KSI < 46 KSI F.S. = 4.0 1
Weld required to lift lug 4.2 in.
4.2 < 12" F.S. = 2.8 Weld to tiedown lug Shear = 39,754 lbs/(2 x 15.5) = 1282 lbs per inch of weld compression or tension due to moment couple 39,754 lbs (3"/15.5 in) of tiedown lug = 7694 lbs in/
inch of lug and moment couple with 2" thick lug 2"(3847 lbs)= 7694 lb/in Moment of Rotation (39,754)(4.34)/15.5 in =11,1311b-in/in. lug For 2" lug, then 5565 lb/in i
Stress on weld to tiedown lug =
a = /(1282)2 + (3847) + (5565)2
= 6885 6885 lbs per inch of weld : maximum of 9460 lb per inch of weld F.S. = 1.37 i
1 _ _ _.-- - _ _
PROPRIETARY DATA 3.1.5.3 Tie-down Lugs The tie-down lugs are constructed of A516 Gr.nle s t. eel h.ivinq.i minimum yield stress of 46,000 psi and a maximum ultimate stress of 78,000 psi.
The following values are used in the design of the tie-down lugs.
Tensile Yield = 46,000 psi Allowable Bearing Stress 0.9 tensile yield strength
=
Maximum Ultimate Tensile 78,000 psi
=
Shear Yield 0.577 x 46,000
=
26,542 psi
=
Shear Ultimate 0.577 x 78,000
=
= 45,006 psi Allowable Shear Stress on Welds 21,000 psi
=
Bearing Stress on Lug & Pin Maximun Load 274,330 lbs
=
Diameter of Hole 2.5 inches
=
Dianeter of Pin 2.25 inches
=
Thickness of Lug 3.0 inches
=
z Projected Area of Pin 3 x 2.25 = 6.75 in
=
Bearing Stress = 274,330 = 40,641 psi 6.75 S.F.
41,400 + 40,641 1.02
=
=
Tear Out The shear plane associated with the projected area of the pin is shown as follows:
2 2
yi = /1.25 - 1.125 y
0.545 1.25
=
yi y2 1.25 - 0.S45 = 0.705"
=
l 1.25 PROPRIETARY DATA 1.75" d
274,330 lb
/
-- 2. 25" Dia. Pin
=
% 2.5" Dia. Ilole s
3.0 thick 274.330 Shear Stress = 2 1, g = 26,127 psi 26,542 26,127 = 1.02 S.F.
=
Tension Reinforcing Plate f"
Stress - 274,330/2"(11.25"-2.5")
i
= 23,854 psi 8.25" S.F. = 46,000 23,854 = 1.93 Reinforcing Plate Weld 7,,
d 274,330 lb
- 2.25" Dia. Pin 7
2.5" Dia. IIole 6"
/
l
\\ /
Thickness main lug 2 inches Thickness reinforcing nlates 2 01/2 inch Total thickness 3 inches Load on reinforcinq plate = 1/6 x 274,330 = 45,722 psi l
Length of weld = 6 & 7 + 7 = 20" Area of shear = 20 x 1/2 x Sin 450 x 0.85 = 6.01 in' Stress = 45,722 1 6.01 = 7608 psi 2.76 S. F. = 21,000 1 7608
=
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PROPRIETARY DATA 3.1.5.4 Tie-down Lug Welds a) Pure shear 2(15.5)(Sin 45 )(1)(0.85)
Area of shear
=
>2"
+ (6+6+2)(Sin 450)(0.75)(0.85) = 25 I
l' tress = 274,330/25 = 11,000 psi i
b Moment forces on weld Maximum Moment = 274,330 x 2.75 = 754,407 in-lbs 15.5" 6" 0 3//."
6" e V/."
gg innn,,isiinunninin,,,Y n nsin n,,in, g
S l
W Reference
"'""" ""j"3 5" "'"/" " HI " " " " " " " ('"."""6 1"
15 5 Line
]
10.95 m
2 x 1 x 3/ 4 + 2 x 15. 5 x 8. 75 + 6 x0. 75 x8. 33 +6 x0. 75 x 10. 95 + 16. 5 x2x 3/ 4 "
x-0.75x2+15.5x2 + 6 x 0.75 + 6 x 0.75 + 2 x 0. 75
= 384.4 = 8.94 in.
j t
43 A
p suninninnn innnnnini$
2.0Wsa,innins n n '
v/unuuu usuuruiu<unuusunu aru n u s u uan 7.94
>(
6.56
=
M = compressive moment + tension moment coq)ressive moment = tension moment M = 2(tension moment)
M = 2f[(2.01)(6)(0.75)(0.707)(0.85) + (6.56)(2)(1/2)(6.56)(2/3)
(0.707)(0.85) + 2(6.56)(0.707)(0.85)(0.75)]
754,407 M=
57.2
=
f = 13,191 psi Combined stress 2
2 2
f=
M410 + 7843 =
y11,000 + 13,191
= 17,176 psi 1.22 17,176 F.S.
=
=
PROPRIETARY DATA At the highest stress location on the outer shell, the stress is 42.4 KSI; for ASTM 516 Grade 70 yield.
Per 3.1.4, the steel used in the outer shell will be specified to have a minimum yield strength of 49 KSI and will be certified by testing.
i 3.1.5.6 Failure Under Excessive, Load.
The tie-down lugs are designed to fail first under excessive load and preclude damage to the package.
Based on ultimate stningth of the shell material, the force required to cause extensive defonnation to the shell would be:
F = 274,330 x -h- - = 490,430 lbs (where 75,800 psi is the ultimate strength of the shell material)
The tie-down lugs are designed to fail by tear out when excessive forces are applied. The force required to cause tear out is as follows:
472,563 lbs F = 45,006 x 2 x 3 x 1.75
=
1 l
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PROPRIETARY DML Lid Ratchet Bi' der Assenbly n
Based on the 76,105 lb developed in the far ratchet binder during a top corner drop,the ratchet binder, the ratchet binder pin, and lug assemblies are analyzed as follows.
Ratchet Binders -
The ratchet binder will have a shank diameter of 1-3/4 inches and rated generically for an ultimate failure load of 135,000 pounds. The binders will generally fail in the threaded portion of the shank. The shank is fabricated from Grade C1040 or equivalent cold worked steel having a generic yield strength of 70,000 psi and an ultimate strength of 85,000 psi.
The minimum root diameter of the thread portion of the shank is 123 inches.
The strength of the shank is calculated as follows:
2 Yield Strength 70,000 x 1.5 x n 4 = 123,700 pounds
=
2 Ultimate Strength = 85,000 x 1.5 xn+
4 = 150,207 pounds Based on yield strength the factor of safety will be:
123,/00
/6,105 =
1.62 Ratchet Binder Pin -
Pin is 1-1/8 inch diameter bolt made of FAF Grade 5 or eq6f valent, having a yield strength of 74,000 psi. Based on double shearing of the bolt during loading, A
76,105 lb 76,105 2
2 1-1/8" esultant Force = 76,105 lh j
o = (76,105/2)/(1.125)2(n/4) = 38,281 nsi s
Safety Factor = (74,000)(0.577)/(38,281)
= 1.12 PROPRIEIANY DATA 4.0 THERMAL EVAlllATION
.The Hil-100 Series 3 casks will be used to transport waste primarily from nuclear electric genera ting plants. The principal radionuclides to be transported will be Cobalt 60 and Cesium 137.
The shielding on the cask will limit the amount of these materials that can i,9 trans-ported as follows.
Gamma Specific Total ( I Isotope Energy Activity Activity Mev pCi/ml Ci Cobalt 60 1.33 5.0 23.2 Cesium 137 0.66 140.0 650 (1) Based on cement solidified waste and 10 mR at six feet from cask.
(2) Based on 164 cubic feet of solidified material.
With the maximum amount of these materials that can be transported in the HN-100 Series 3 cask, the heat generated by the waste will fue as follows.
t L
Hea t Total Genera tion Activit Total Heat Bla tts/ Curie)
(~Curi es) y~
(Wa tts)
(RTil/ilR)
Cobal t 0.0154 23.2 0.35 1.19 Cesium 0.0048 650 3.14 10.7 The weight of waste,per container will be about 17,500, pounds. Based on a specific heat of 0.156 BTH per degree F., 2730 RTll's or over 10 days with cesium would be required to heat the waste one deqree Fa hrenheit. Accordingly, the amount of heat generated by the waste is insignificant.
f,
,,.,,_,,..,,,,,,,n
PROPRIETARY DATA The qasket dimensions are 22.75 in. OD, 20.25 in. ID, and 3/8 in, thick.
The pasket is equivalent to a Durometer 50.
Area = n(Ro _ gjz) = v(11.3757 - 10.125') = 84.43 in?
2 Force downward on lid is the sum of the weight of the lid plus the force of the studs (P).
P=h=(80ft/lb)(12in/ft)/(0.15)(0.75in)
P = (8533 lb/ stud)(8 studs) = 68,266 lb W = 400 lb Total force = 68,266 + 400 = 68,666 lb Pressure on gasket = f = 68,666 lb/84.43 in? = 813.3 psi As shown on Appendix D-2, the compression of the shield plug gasket is 25% of initial thickness or 1/8 inch.
5.3 Seal with Internal Pressurization The innertsteel shell is designed to act as a pressure vessel when the
' cask lid is in place and tightened. As shown in Section 3.2, the cask will withstand an internal pressure of 7.5 psig as required by 10 CFR 71, Appendix A.
As described in Section 1.0, the nature of the waste being transported is such that phase change or ga.s generation which may over-pressurize the cask, will not occur.
The stepped flange surface at the end of the cask body has been designed to minimize effects of columnated radiation streaming and problems associated with gasket damage during impact.
If the cask is pressurized to 7.5 psiq, the resultant force on each ratchet binder (as calculated in Section 3.2) is 4,113 pounds.
The resultant strain on the steel ratchet binder (1-3/4" diameter) is:
6 P/AE = (4.113)/(1.77)(30 X 10 ) = 0.000093 in./in.
P = 4,113 1b A = Area of 1-1/2" minor diameter = 1.'/7 in' E = Youngs Modulus = 30 X 10' and for a 24 inch long binder, total strain is:
(24 in. )(0.000077 in./in. ) = 0.0019 in This is less than 2% of the initial compression of the gasket. '
_ _ ___