ML20028D355
| ML20028D355 | |
| Person / Time | |
|---|---|
| Site: | 07106679 |
| Issue date: | 12/23/1982 |
| From: | Waller W U.S. ECOLOGY, INC. (FORMERLY NUCLEAR ENGINEERING |
| To: | Macdonald C NRC OFFICE OF NUCLEAR MATERIAL SAFETY & SAFEGUARDS (NMSS) |
| Shared Package | |
| ML20028D356 | List: |
| References | |
| 21732, NUDOCS 8301190023 | |
| Download: ML20028D355 (9) | |
Text
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US Ecology. Inc.
I 9200 Shelbyvdio Road Suite 520 g
b P.O. Bon 724G Louisville. Kentucky 40207 502 4?6-716n r/7
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UsEcology
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December 23, 1982 1]
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COMVOIN tc.M g) yd SecW1 4
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Charles E. MacDonald, Chief Transportation Certification Branch l/SNge Division of Fuel Cycle and Material Safety, NMSS 2
gab U.S.
Nuclear Regulatory Commission g
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S Docket No. 71-6679 g
HALF SUPERTIGER PACKAGE D
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Dear Mr. MacDonald:
This is in response to your letter of October 19, 1982, to Mr. Jerr Scoville regarding US Ecology's Model 6679 shipping package.
In response to those questions outlined in p ur letter of June 24, 1982, Question Nos. 1,2,3,7 and 8, the following information is submitted for your approval of our package for Mcde A utilization.
1.
Please find enclosed copies of those letters referenced on Page 2 of the SAR, specifically the thermal calculations defining the decay heat limit for the " Mode A" configuration.
Also, we have revised page 25 of the SAR to reference the correct Mode.
2.
The " Table of Plates" on pace iv of the SAR has been changed to include all of the drawings listed in our November 17, 1980 letter of application.
3.
The requirements of Subpart D.
of 10CFR71 have been previously aldressed as US Ecology's Quality Assurance Manua.1 was approved by the U.S. Nuclear Regulatory Commission on June 26, 1981
( A copy of the approval is enclosed). Operational inspection procedures, tonguing procedures, drawings, etc... are available to authorized customers prior to its utilization.
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PDR ADOCK 07106 i y,,
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JAN 6 1983
P Mr. MacDonald December 23, 1982 Page 2 7.
See attached tie-down and lifting device explanation.
8.
For Mode A 'onfiguration US Ecology feels the SAR previously submitted and approved by the Nuclear Regulatory Commission adequately addresses the 30 foot drop test.
However, the gross weight of the Half SuperTiger package used without the shield cask (Mode A) is 24,000 lbs. whereas, the grass weight of the SuperTiger package is 45,000 lbs.
The foam thickness for both units are equal except for the cap and end of the Half SuperTiger wnere it is reduced. The ratio of cap /end foam thicknesses for the two containers is greater than the gross weight ratio previourly indicated. Therefore, the crush daring a 30 foot drop will be a lesser percentage, thereby ir tne case of the Half SuperTiger the margin of safety is enh anced.
The materials and methods of construction for the Half SuperTiger are similar in regards to closure bolts, lid, flanges, etc.
Testing of the SuperTiger for the 30 foot drop showed that the materials of construction and methods of construction were adequate to prevent failure of the above mentioned items.
Copies of this evaluation are on file and available.
If you should have any questions or comments on these items, please do not hesitate in contacting US Ecology.
Sincerely, W.
Kenneth Waller Chief Radiological Control and Safety Officer WKW:jc l
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Appendix Tie-Downs and Lifting Devices
'Ane ISO corner castings provided as tie-downs and lifting devices will adequately withstand three times the package's gross weight.
If any of these fittings were loaded beyond their capability, failure would not in any way jeopardize the integrity of the overpack.
The purpose of the following analysis is to demonstrate the structural integrity of the Half Super Tiger overpack to semi-trailer interface. Per 10 CFR 71, the container tie-downs must be able to react 10 g's longitudinally, 5 g's laterally, and 2 g's vertically.
The half Super Tiger overpack will be secured to the semi-trailer by four (4) cable tie-dewus as shown (vertical position). The Half Super Tiger overpack can also be shipped horizontal using four (4) cable tie-downs. For conservatism, the number of attachment bolts have been increased to 12 on the Half Super Tiger overpack resulting in a margin of safety of +32%.
The ISO corner castings as shown in the attached drawing are used to secure the Half Super Tiger to the semi-trailer. Depending upon which orientation is utilized, the cable load. are reacted by the shear areas denoted "A",
"B" and "C".
These areas are:
"A" = 2.3 in 2 "B" = 2.53 in, "C" = 1.76 in' Fs = 36,000 psi Allowable load in double shear / fitting.
Fa = (36,000) (2. 3) (2) = 165,600 lbs.
Pb = (36,000) (2.53) (2) = 182,200 lbs.
Pc = (36,000) (1. 76) (2) = 126,720 lbs.
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Cable Tie Downs Figure 2 The applied load is reacted by cables attached to the upper ISO cotner castings. Area "A" is good for 165,000 lbs; i
area "B",
182,200 lbs., and area "C",
126,700.
These values t
will be used as allowable loads in this analysis.
3.
Case 1.
10 g's Longitudinal o
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Ten g's Longitudinal
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Figure 3
' 7' In the event of a 10 g longitudinal force, a free-body diagram of the restrained container would be as follows:
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150,000 /bs F[Cy n
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Free-body Diagram at 10 g's Longitudinal Figure 4 r4A = o, Cx = 120,789 lbs.
4.
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Force Cx is the sum of the lo'ngitudinal components of the two cables attached to the upper ISO fittings.
Because the esbles run from the top of the container to the opposite sides of the trailer, the cable load is obtained by dividing the horizontal component by the cosines of both the hori-zontal and vertical angles.
l[2 (120789)
_ 1/2 (120789)
C = TCos 4 5" ) (Cos 36-)
.707 (.81)
= 105461 This force will be-taken by shear area "A",
"B" or "C".
Then M.S.
= 165,600/126,700/182,200
- 1 =.57/.20/.73 105 5 g's Lateral,461 Case 2.
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diagram of the restrained container would be as follows:
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Free-body Diagram. at 5 g's Lateral.
Figure 6
11A = o,-C = 96130 lbs.
This force is the sum of the lateral components of load in two cables.
Individual cable loads can be obtained by dividing one-half of this value by the cosines of the appro-priate horizontal and vertical angles, as for Case 1.
4 CE_
(1/2) 96130
_ (1/2) 96130 (Cos 45') (Cos 54")
.707 (.588) i
= 115619 lbs.
Again, this force will be taken by shear area "A",
"B",
or "C".
Then:
M.S.
= 165,600/126,720/182,200
- 1 =. 4 3/.10/. 5 8 115,619 6.
Case 3.
2 g's Vertical.
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Two g's Vertical i
Figure 7 In the event of a 2 g upward force, all four (4) cables restrain the package.
The load' per cable would be:
C
-~1/4 I(2) (45000) 47000]
1/4 (45000)
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(Cos 45") (Cos 54*)
(.707) (.588)
= 27061 lbs.
This force will be taken by shear area "A","B",
or "C".
'Then:
M.S.
= 165,600/126,720/182,200
= + large 27,061
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