ML20126A482

Consolidated Rev to SAR for Chem-Nuclear Sys,Inc,Model CNS 14-195H,Certificate of Compliance 9094,Type a Radwaste Shipping Container

ML20126A482
Person / Time
Site:	07109094
Issue date:	04/30/1985
From:	CHEM-NUCLEAR SYSTEMS, INC.
To:
Shared Package
ML20126A444	List: ML20126A440 ML20126A482 ML20126A504
References
25203, NUDOCS 8506130359
Download: ML20126A482 (100)

Text

{{#Wiki_filter:r 3. 7/-- 96W 1 v-G / ct e ss M ar SAFETY ANALYSIS REPORT FOR CHEM-NUCLEAR SYSTEMS, INC. MODEL NO. CNS 14-195H CERTIFICATE OF COMPLIANCE NO. 9094 TYPE A RADWASTE SHIPPING CONTAINER CONSOLIDATED REVISION APRIL 1985 CHEM-NUCLEAR SYSTEMS, INC. CORPORATE HEADQUARTERS I 220 STONERIDGE DRIVE COLUMBIA, SOUTH CAROLINA 29210 8506130359 850501 DR ADOCK 07109094 D PDR

TABLE OF CONTENTS 14-195H SHIPPING CASK 1.0 GENERAL INFORNATION 1.1 Introduction 1.2 Package Description 1.2.1 Packaging 1.2.2 Operational Features 1.2.3 Contents of Packaging 1.3 Appendix 2.0 STRUCTURAL EVALUATION 2.1 Introduction 2.2 Weights and Centers of Gravity 2.3 Mechanical Properties of Materials 2.4 General Standards for All Packages 2.4.1 Chemical and Galvanic Reactions 2.4.2 Positive Closure 2.4.3 Lifting Devices 2.4.4 Tiedown Devices 2.5 Standards for Type 8 Packaging 2.6 Normal Conditions of Transportation 2.6.1 Heat 2.6.2 Cold 2.6.3 Pressure 2.6.4 Vibration 2.6.5 Water Spray 2.6.6 Free Drop 2.6.7 Penetration 2.6.8 Compression 2.7 Hypothetical Accident Conditions 2.8 Special Form 2.9 Fuel Rods 2.10 Appendix 3.0 Thernal Evaluation 4.0 Containment 5.0 Shielding Evaluation 6.0 Criticality Evaluation 7.0 Operating Procedures 8.0 Acceptance Tests and Maintenance Program 9.0 Quality Assurance ( f l t 4 w

l-1.0 SENERAL INFORMATION i {

1.1 INTRODUCTION

The CNSI 14-19f shipping cask is a top-loading, shielded container i i designed for the transport of Type A and low specific activity (LSA) radioactive wastes. The cask will acconnodate fourteen (14) 55 i gallon drums or one 195 (nominal) cubic foot steel liner or other approved sealed containers. 1.2 PACKAGE DESCRIPTION j 1.2.1 Packanine I The cask is the primary containment vessel for the transport of radioactive wastes. It consists of a cask body and main cask lid which incorporates a second smaller diameter lid. The secondary lid is typically used for access when a i disposable liner is inserted in the cask. The cask is a right circular cylinder 83-1/8-inch diameter by 89-7/8 inch high, with an 77 inch diameter by 80-1/8 inch high cavity. l 3 4 i The cask body is a steel-lead-steel annulus in the form of a vertically oriented, right circular cylinder closed on the bottom. The side walls consist of a 1/8 inch inner stainless i steel shell, a 2-3/16 inch thick concentric lead cylinder r l bonded to the inner and outer shells, and a 3/4-inch thick i outer steel shell. The steel shells are welded to a concentric top flange designed to receive a silicone rubber + gasket. The cask primary lid is identical to the cask walls except that the inner shell plate is 1/4-inch steel. Incorporated into the main cask lid is a secondary lid installed concentric to the main lid. The secondary lid covers a j 26-inch diameter opening and 1s fabricated identical to the cask side walls. The secondary lid is fitted with a neoprene gasket and is bolted to the main lid with eighteen 3/4-inch diameter bolts. The main cask lid is bolted to the cask body I with twelve 1-1/4-inch diameter by 6-1/2-inch long bolts. r l The cask bottom consists of a 1/8 inch steel inner wall, 2-3/16 inch thick lead and is welded to a 3/4 inch thick, 96-inch square base plate. The cask has two lifting j trunnions which are welded to the top flange and the outer steel shell, three lid lift rings and one secondary lid lifting ring which is covered during transport. i

• THE 14-195 IS USED SYNONYMOUSLY WITH THE 14-195H THROUGHOUT THIS REPORT.

1-1

The lead shielding consists of sheets of lead bonded by an adhesive to the steel walls. CNSI manufacturing procedures 2MP-002 and 2MP-003 control the bonding and curing techniques for fabricating each of the steel-lead-steel composite cask components. This fabrication method has been demonstrated to result in lap shear strengths in excess of 5000 psi. (

Reference:

'How to join lead with Adhesives". ADHES1VE1 4K, September 1968 and 3-M Product Specification Data Sheets for 2024-T3 aluminum adherend and AF-126 (008) structural adhesive). This bonding strength is accounted for in certain portions of the structural analysis. The gross cask weight is 56,500 pounds including a maximum payload of 17,700 pounds. 1.2.2 OPERATIONAL FEATURES There are no complex operational requirements associated with this package. 1.2.3 CONTENTS OF PACKAGING (1) Type and Form of Material (1) Processed solids, either dewatered, solid or solidified in secondary containers, meeting the requirements for L5A radioactive material, or (ii) Solid reactor components in secondary containers as required that meet the requirements for L5A radioactive material. (iii) When liquid or resin waste is shipped using the auxiliary shield it shall be solidified with one of the following solidification media: l (a) Dow media; (D) Coment; (c) Asphalt; (d) Delaware custom media; or (e) Solidification media and process reviewed and approved by the U.S. Nuclear Regulatory Cossaission, Office of Nuclear Reactor Regulation. Solidified radiation waste shall have no detectable free standing liquids. For purposes of this condition, the terminology 'no detectible f ree standing liquids' means one-half percent - (0.55) by waste volume of non-corrosive liquids per container. I 1-2

o (2) Maximum quantity of material per package Greater than Type A quantities of radioactive material with the weight of the contents, secondary containers and shoring not exceeding 17,700 pounds. t 6 t i 1-3 l-

1.3 APPENDIX 1.3.1 Figure Oi.e -Cask Outline 1.3.2 CNSI Drawing 1-189-101 Rev. AF ( l l l e 1-4 )

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.s 2.0 STRUCTURAL EVALUATION Analyses are presented herein that demonstrate the acceptability of the packaging design features with respect to regulatory criteria in effect at the time that this container was initially approved for use.

2.1 INTRODUCTION

t This section identifies and describes the principal structrual engineering design features of the model 14-195 cask, which are important to safety in compliance with the performance requirements of 10 CFR 71 as applicable for a Type A package. 2.2 WEIGHTS AND CENTERS OF GRAVITY The center of gravity for the assembled package is located at the approximate geometric center. The cask shell weighs approximately 32,500 pounds and the total lid weight is 6,300 pounds giving a total empty container weight of 38,800 pounds. The maximum payload is 17,700 pounds resulting in a total maximum gross weight of 56,500 pounds. i l l l 2-1

o i l 2.3. MECHANICAL PROPERTIES OF MATERIALS The mechanical properties of materials of metallic components used l l for analysis of the CNSI 14-195 Cask are as follows: l Component Material Allowable External Shells 'A-36 Steel Fty = 36 ksi Internal Shells A-304 Fty = 30 ksi Trunnions SAE 1018 Fty = 40 ksi 8olts (1-1/4"D.) SAE J 429,Gr.8 Fty = 130 ksi (Primary lid) Ftu = 150 ksi 8olts (3/4" D.) SAE J 429, Sr.2 Fty = 57 ksi (Secondary lid) Ftu = 74 ksi l With Revision AF to Dwg. No. 1-189-101. A-36 Steel is replaced with ASTM A-516, Sr.70 Steel. This provides additional safety nergins above those shown elsewhere within this report, as follows: A-36 A-516. Gr.70 % Increase i Tension Yield, Fty 36 ksi 38 ksi 5.6% Tension Ultimate, Ftu 58 ksi 70 ksi 20.7% The 516 material is incorporated in packagings fabricated after March 31, 1980. Analysis performed for this SAR are based upon the A-36 properties for conservatism. 2.4 GENERAL STANDARDS FOR ALL PACKAGES 2.4.1 Chemical and Galvanic Reactions All solidified radioactive wastes will be contained within 55 gallon drums or approved liners. There is no potential for galvanic or chemical reactions between the package components and the package contents. 2.4.2 Positive Closure The cask lid is positively closed as noted in Section 1.2.1. l In addition, each cask is equipped with a seal feature which provides positive indication that the cask may have been tampered with. The main cask lid is sealed with a silicone rubber gasket and the secondary lid with a neoprene seal. Both lids are bolted to assure that they are water and pressure tight. 2-2 1

_ l 2.4.3 Liftina Devices 10CFR 71.45 (a) requires that any lift point be designed with a minimum safety factor of three against yielding wt'en used to lift the package in the intended manner. The CNS 14-195 package is equipped with two lifting trunnions as shown on CNS drawing.. -189-101 Rev AF. The following anaylsis 1 therefore evaluates one trunnion subjected to 3 times one-half of gross package weight, or a total load of 84,750 pounds. This analysis shows that the lifting. devices can withstand 3 times the gross package weight without failure. 9 f 2-3 r.--

Lifting Device Analysis D x 4"THK x 3"I.D. \\- GEOMETRY g Item 28 M* THK x 3" x 18k" Item 20 l. STL 3"0.D. 1018 STL Item 7 h*THK STL -Item 1 ~ h" THK STL Weld

REFERENCE:

DRAWING NUMBER 1-189-101 (Rev. A-F) DETAIL F AND DETAIL LIFTING LUG LOADS l l The regulatory criterion of three times pross package weight will be shared by two lifting trunnions. 1 2-4 i -,-.,_r._,..--..

MAXIMUM GROSS PACKAGE WEIGHT, W=56,500 3j{,3(56500)=84.75K LOAD TO EACH TRUNNION = r ANALYSIS ALLOWABLE STRESSES: Tensile Yield Strength, Y = 40 ksi Y Item 20 (1018 STEEL) Shear Strength, S 23.1 ksi = s = 3 3 i BRG SHEAR' END '4 EAR 3 [ 84.75 g. 3 = 28.25 k/in i r i I (_. N g iT(3) 7.07 in.2 Area = 4 = i BRG SHEAR = 5/8(28.25) (3) = 53.0 k 53 .C 23.1 ok ~ F SHEAR = A = 7.5 ksi 3 l L i l ( f 2-5

r WL2 28.25(3)2 a = 31.81n-kips Bend.M = T = 3 tR3 'li(1.5) 3 So= 4 = 4 = 2.65 in M 31.8 F Bend = T = T.'55 = 12 ksi 4 40 .. ok Bearing Eye Hook on 3" DIA BAR 3" DIA. BAR - i-4 RADIUS EYE HOOK \\ ROARK & YOUNG - 5th ED. Table 33 Case 26 DID2 6(3) 18 ~7 = 6 = 6-3 l Kb= Dl-D2 = 3' 0.59) 28.25(29)(10 ) 218 ksi 6 = Stress = Even though this calculated stress is higher than the corresponding allowable, this is not judged to be significant because this calculation is based on a conservative model. The actual effect in this situation would be a slight deformation of the hook /bar which would greatly reduce the stress value. i i o 2-6

SEARINGONCASKPLATESANDWELDSTRENGTH ITEMS 7 818 (5/8)WL.= 51'.6 kips 601 TO ITm 7 = 0.60 Oi5+0.5 40% TO ITEM 18 (ITEM 7 ITEM 18 (f8RG)7 50 j = 13.76 ksi Same as above = (f8RG 18 [0.) I BRG ALLOW A-36 = 0.9 Ys = 32.4 ksi > 13.76 ksi t. OK WELD STRENGTHS: i ITEM 7 7* 0.928(6)(fr)(8) = E Obviously OK ITEM 18 s 1 1r 2-7

~ Item 1 3 SHEARS I WL to Item 28 only WELD 0.928(8)(7)(3)=70k obviously ok Item 28 1 3 3 3* i WL = i (84.75) = 31.8 k Complete fixity at ends: PL 31.8(15) g, l 8 =59.61n-kips M y-59.6 (6)_ 53ksi_ ,Too Large ! F BEND = D 75(3)' = RECK. Using clear span: PL 31.8(12) 7= 8 =. 47.71n-kips 47.7(6). ~ F BEND = 0.75(3)' = 42.4'ksi still>Ys. j l e e 2-8

EQUIVALENT DIST. LOAD i i 5 I ~ W = 31.8 = 4.54k/in. 7 I 7." y, I I ~ i 12" CLEAR l SAY ITEM 1 I i l i o SHEAR O 15.5k, 25.68"k o MOMENT 38.2 < l SYM. 12) 38.2 in.-kips SAYM=h=31 = BENDING =-fi 2 '= 33.9 ksi 4 Ys ~ 36 ksi.. OK = 2-9

r-l WELDS AT ENDS 38.2 12.7 Kips 3 0.928(8)(3) = 22.3k CAPACITY > 12.4 Kips.', O K 3" ITEM 28 3" 1/2 IN. WELD (9 LINEAR INCHES) m 3 E k MOMENT 12.4 10P/ BOT SHEAR 15.5 4 22.3k,., OK k e O 2-10

c CASK BENDING ROARK & YOUNG - 5th ED. 4 . 3(1- /) g_m TABLE 30 .A= 22 = gg I (41.5)2(2.1)2 CASE 3 .h i Ak = 0.14(90) = 12.4 k COMPOSITE EQUIV. THK 2 2M A, = 2(M.)(0.14)2(41.5) = 0.77 M, = 't 2.1 f l i UPPER POD .. OK M,= 31.0(0.77) = 24 ksi \\ e I 1 .f 2-11 -e-2 -. A

f l-o' l ~2.4.4 Tiedown Devices The package tiedown system must be able to withstand a static force applied at the center of gravity of the package with a . vertical component equal to two times the weight of package ~ 'and contents, a horizontal component along the direction _of travel equal to ten times total loaded weight, and a . horizontal component transverse to the travel direction equal to five times the total weight. The resulting stresses in the package material shall be less than appropriate yield strengths. The tie-down system that evolved satisfying the above is a thickened base plate bolted to the trailer floor. The base plate consists of two plates welded together to provide a total thickness of 1-1/2 inches. The base plate is secured to the trailer floor with 16-1 1/4 inch bolts. The following analysis demonstrates the acceptability of this design. h 2-12

TIE-DOWN ANALYSIS _ 1-189-101 REY. AF 5 REFERENCE DRAWING NUMBER GEOMETRY t 83-1/8" 0.D. ~ ~. s 89-7/8 EFF. HGT. 1 e 14-195 CASK BODY C.G. X-SIDE ELEV. l<, 5 ... so..Ast,m;E L BASE PLATE 96" l O TIE DOWN BOLTS 4 BOLTS 1-1/4 INCH K DIAMETER IN EACH CORNER y (- ,e ~ P 2-13 ' ' ~ - - e

1 LOADS. CRITICAL LOADING BASED ON IDG IN DIRECTION OF TRAVEL. EVALUATE CAPABILITY OF TIE DOWN SYSTEM TO RESIST T ~ 56.5 kips at 1G WT. =

10G,

\\/ s ,p ~45" l I-l l f 2H F 2H T h 'IV 2 83-1/8" 2V -ob IMforward = 45(10)(56.5) -2V(83-1/8) = 0 45(10)(56.5) - = 152.'9 kips 2(83-1/8) V each corner bolt detail [F fomard = 10(56.5) -4H = 0 ( =565/4 = 141.2 kips H each corner bolt detail 2-14

I ANALYSIS ~ BOLTS LOADS: USE (4) 1/4" DIA. A325 x BOLTS EACH LOC AXIAL TENSION = 152.9/4 = 38.2 KIPS _PER BOLT SHEAR = 141.2/4 = 35.3 KIPS PER BOLT ALLOWABLE STRESSES FOR A-325 TENSILE ULTIMATE = 105 ksi TENSILE YIELD = 81 ksi SHEAR STRENGTH = 47 ksi l l l l l I RESULTS 3/4" REINF. PLATE WELDED TO 96 IN. SQ. BASE PLAT REFER TO DETAIL J OF DWG. 1-189-101 FOR WELDS i / \\ r CAPACITY = 7.4 KIPSflNWELD l K/IN RUNNING INCH AT ALL BOUNDARIES. I EFF. 7.42/2 = 3.71 2-15 O e

RESULTS BOLTS AXIAL TENSION = 152.9 K/n BASE SHEAR = 141.2/n Where n equals no. of bolts at each of 4 locations. Try 4 - Ik" DIA. A325 x Bolts ea. loc. (4 places). l TENSION CAP = 1.227(81)=99.4 KIPS SHEAR CAP 6 1.227(47) = 57.7 KIPS l 1 TENSION / BOLT = 152.9/4 = 38.2 k i SHEAR / BOLT = 141.2/4 = 35.3 k CK COMBINED LOAD: AISC SPEC. 1.6.3 F = 50 - 1.6fy 4 40.0 t [-

• 47 ksi allow.

USING Ys VALUES F = 100 - 1.6f,4 81 t I f \\ l l 2-16

AXIAL STRESS = 38.2/1.227 = 31.1 ksi f, = 35.3/1.227 = 28.8 ksi SUBSTITUTING F = 100 - 1.6(28.8) = 53.9 ksi > 31.1 ksi ., OK t - BRG ON A36 PLATE 35.3k = 37.65 ksi 4 48.6 ksi ., OK 0.75(1.25 PRYING ACTION l. i 14-195 BDY WALL 3/4" X X g. 3..

3. A g.

i BASE PLATE CONSIDER 12 IN EFFECTIVE GUSSET 12.7 K/IN LD/IN = 152.9/12 = TRY BASE PLATE 4 INCREASED TO 1.5 IN THK. 247 w -.n,.

LDING DIAGRAM P = 11.9 K/IN J L 3 - 3/8 - 1/16 = 2 9/16 IN I I / 14" ~ b h i 1 F=6P/2=35.7 k -N s SAY 36 k q FtQ Q 2-g Q=F 70aldb)' + ZlWltf,l'c 4 100b(db)2 - 18W(t/ 100(2.56)fl.25',2 - 18(6)(1.5)2 = 35.7,70a(1.25j' + 21(6)(1.5)' a= 3 IN, EFFECTIVE Q= 35.7 400 -243 - 9.2 KIPS 328 +283.5 0.26 l M2 = 9.2(3) = 27.6 IN-KIPS M = 45.2(2.56) - 9.2(5.36) = 64.6 IN-KIPS (GOVERNS) 1 .. OK bend = 64.6(6) / 6(1.5)2 = 28.7 ksi < 36 ksi f i 2-18 i l

i 2.5 Standards for Tvoe B Packaaina N/A for CNSI Model 14-195 ( 2.6 Normal Conditions of Transport 1 2.6.1 Hgat An evaluation was performed to consider the affects of increased ambient temperature on cask integrity. For this evaluation, an ambient temperature of 130' is assumed and an additional 100* F is considered for conservatism and to account for solar insolation. /ssuming that the cask is in an equilibrium, stress free condition at 70* F, this results in a net temperature change of 160* F to induce stesses in the cask wall as a result of differential thermal expansion -between the steel and lead. The following analysis shows that this condition will cause the lead to load the outer shell in tension by 7854 psi which is well below the 36,000 psi yield strength of A-36 steel. l l 2-19

k ANALYSIS FOR INCREASED AMBIENT TEMPERATURE a v AT=Tf-To = (130 + 100) - 70 = 160*F {Steadystate ! GEOMETRY l STL(A36) LEAD g STL (304) / 381" s f s

d..,,..

38 fg. ALL RADII TO 40'I# GEOMETRIC CENTER m e 2-20

SNALYSIS! W Values: 6 STL A36 11.7(10-6)j C E=29(10 )psj a 6 LEAD 29(10-6))'C E=2(10) psi 6 SIL 304 10.4(10-6)f:C E=28(10)p39 Conversion:

• C=5/9 (' F-32)
• F=9/5 *C + 32

~ Divide values by 9/5 = 1.8 To obtain rF values. 11.7(10-6) 6.5(10-6)j,p v.STL A36 = 1.8 = 29ll10-0) 16.1(10-6)j p e ~3. 8 = E LEAD = 10.4(10-6) 5.78(10-6)j,F o< STL 304 = 1.8 = e f a 2-21 ^

1 AR = < AT R. Int-face 1 2 3 4 5 6 ~- 0.0357 0.0356 304 l Lead O 105.1 0.0995 A36 0.0432 0.0424 l I I Above values unrestrained. - Underlined values significant W.R.T. stresses (Int.) Lead wants to load STL body wall radially; STL wants to confine lead expansion. EQUILIBRIUM INT. PRESSURE FORM'JLAE: LEAD (LEADACTINGONSTL) ( \\ (j) fg=ab![a2+r) 2 r'sa - b-) l STL Eocy l = -qb!(a! r <, 2 f a= outer radius f 33t r'(a'-b'j beinner radius l i 9 2-22 , -, = -

EXT. PRESSURE FORMULAE: (STL RESTRAINING LEAD) 2 2 f. = -ca (b2+r) r'(a' - b') 2 2 2 f agan= -ce (r _ b ) r'(a' - b') - COMPATIBILITY A LEAD = ASTL EXT (3) INT (2) DEFORMATION RELATIONS = b I[ ak + ' b!+ } b - - b~ + 0.0424 a (t.b) STL 1[a 2+h2 + 0.1051 a' - b' (Aa) = LEAD ( Solution by equating and solving for 4 (Bearing measure between STL and lead). e 2-23

(41.5625)2 + (40.8125) b[a2+b 40.8, + = 29(10") a' - b' + 0. 3, T ga' - b' 40.8125 " 3393 29(10*) TDI + 0.3 = 0.00008 = \\ 2+b2 40.8125 (40.8125) t (38.625)2 q 2(10') a - b' -0.45J Y s a a T P - b- = ~ 40.8125_' 3157 0.45 = 0.00036 2(10") = EQ's. 0.00008 q + 0.0424 = -0.00036 q + 0.1051 q = 143 psi (BRGpressurebet.STLandlead) CK. (ab) = 0.00008(143) = 0.0112 in (Load only) STL (aa) = -0.00036(143) = -0.0515 in (Load only) LEAD Combine withAT effect: 0.1051 0.0424 -0.0515 I-0.0112 0.0536 LEAD .~.ok 0.0536 STL t l 2-24

RESULTS ca! 4 b2 143(3393) 62 = 7854 psi t Yield.*.ok (f Hoom ) = a- - b' = STL -a2a _ -143(2l(40.8125:,2 2 2741 psi (40.8325)~ - (38.625)' = = a' -b4 (f Noop ) LEAD =

REFERENCE:

ROARK & YOUNG - 5th ED. Table 32 Cases la & Ic e e 2-25

i 2.6.2 Egli An evaluation was performed to consider the effects of reduced ambient temperature on cask integrity. An environmental temperature of -30' F was considered which results in a temperature difference of 100' F below the 70* F stress-free condition. The 100* F temperature change causes a differential thermal contraction between the lead and. inner steel wall. This results in a compressive loading on the inner wall of 16,830 psi which is below the yield strength of 30,00 psi for A-304 steel. i i 2-26

t ANALYSIS FOR REDUCED AMBIENT TEMPERATURE u i SEOMETRY i L I l 5 LEAD -3/16" R = 38.6" (AVG) STL = 39.7" (AVG) = RLEAD STL 1/8" '- ,j R [ ST LEAD ~ 4 r ' LOADS 1 o 4 T = -100'F ASSUMED DUE TO TEMP. CHANGE fR =%TR = 16.1(10-6)(-100)(39.7) = -0.064 IN. ARLEAD = 5.78(10-6){,'100)(38.6) = -0.022 IN. ARSTL + Thus lead will ext compress STL inner liner. Use thin shell theory. [ -s e i 's 2-27 ,...e / Ir

ANALYS!$ i + EQUILIBRibM EXT q DN STL 1/8" THK..!NNER SHELL

• ' INT q ON LEAD

+ IF INT. LOADING (LEAD) f = qR/t - IF EXT. LOADING (STL) l M00P - 308.8 (38.6) qBPA f ,,%RG STL 0.125 39.7) . 18.14

• h (188 9BRG ILEAD

2. _

DEFORMATION ( NO DIRECT END LOADING EX. TEMP.) 2 AR = qR /Et 8RG(10'0) ( } "" ~4l9

• ~98RG ARSTL 6

29(10 )(0.125) (10 % q,gg = ARLEAD * %RG 6 2(10 )(2.188) l l I 6 i' l%' l 2-28

~ COMPATIBILITY AT R= 38-1/2 IN. ARSTL = ARg SUBSTITUTING -0.064 -411(10-6) %RG ~ 0.022

• 360(10-6)qBRG

~ g gg 10.0a - 0.022H10h 54.s osi 360 + 411 RESULTS I 4 YIELD OK 37t.-308.8(54.5)16,830 psi f LEAD

• 39.7(54.5) = 1360 psi f

e eemum m ( 2-29

2.6.3 Pressure An evaluation is presented below which considers the effects of a reduced ambient pressure of 0.5 atmosphere on cask integrity. This is equivalent to an internal over pressure of 7.3 psi. The following. analysis verifies that stresses in the cask bottom, walls, and lid bolts are acceptable. The analysis also shows that the specified bolt torque at assembly is sufficient to maintain a leak tight seal under this reduced pressure condition, l i i i 2-30 i

5 +. - 1 REDUCED AMBIENT PRESSURE ANALYSIS I GEOM.ETRY l t j l 4 i l r 7.3 psi 1 HGT. = 86" l l i l i \\ l t l 'y s .DIA.= 83" R 41.5 i I = G = 15 > 10 1 ANALYSIS l CYL. L 7.3(35) R c,"(axial) = 2t 4(0.75) = 202 psi. 2 2 1R / 9 7.3(41,5'l 1-0.15 .6R = It ( 1-Y ~29(10")i,0.75) = = 0.0005 in. larger i I 2-31

BOTTOM Assume unsupported on bottom. lP l( Wall l4)jis -l. a=41" I Sample support at body. ROARK & YOUNG - 5th ED Table 24 Case 10g(5+Y) -Qa Yc= 64D(1+V) b Neglect lead for now. 29(10 )(0.75)3 6 3 2 = 1.12(10 ) LB-IN /IN Et 12(1- 0.09) D= 12(1-v ) = -7.3(41)#(5.3) = 1.17 IN. f Too large! Yc = 64D(1.3) Q Must consider composite action of STL and LEAD. STL,' Y i 2 /t," 3 LEAO t =2.10 in 3,1* eq. STL ? stiffness i i I.. d ( 2-32

l- .= 29(10 ?(2.1)3 6 2

24.6(10 ) LB-IN /IN D

12(3-0.09) 1 -7.3(41) (5.3) Yc = ^64D(1.3) = 0.053 IN Valid small diff. theory ca (3+v). 7.3(41)2(S.3) 2 16 = 2531 IN-LBS/IN Small! Mck 16 = 3 7.3f41)3 ca 8D;1.3) = 0.002 Radians G,,= f,D(H () = . = O.113' LID BOLTS 18 bolts:[b1A. 74ksi Ult. 33" l s 3 3 i i tn I 83" l _ (- 12 BOLTS: 1" DIA. 150 ksi Ult. LOAD /18 bolts = 7.3'T(33)2 = 6244 LBS 4 = 1039 psi /.Not critical AXIAL STRESS / BOLT = 6244 18(0.334) I I L ( i 2-33 . ~

LOAD / per12 Bolts = 7.3 % (83)2 39,500 lbs = 4 5432 psi AXIAL STRESS /_1"p Bolt 06) = BOLTS OBVIOUSLY OK Primaryandsecondarysealsconsiskofsiliconerubberandflat They are compressed by imposed neoprene gaskets respective,1y. displacements determined by torqued, or preloaded, lid bolts and Proper gasket mechanical stops reacting the bolt preload. performance is assured provided the bolt and mechanical stop Primary. preload is maintained during the reduced pressure event. lid bolts are torqued to 200 ft-lbs. and secondary lid bolts are torqued to 50 ft-lbs. The adequacy of these preloads is demonstrated by the following analysis: Primary Lid Bolts (12 each,1L." - 7UNC) T = KDF

T = torque, in-lb.

K = torque coefficient. 0.18 D = Nominal bolt diameter, in F = Bolt Preload T = 200 ft-lbs (12) = 2400 in-lbs F= = 2400/(.18) (1.25) = 10667 lbs/ bolt 0 Since the bolts are installed at 45, the effective preload per bolt is: Fa = F cos 45' = 7542 lbs/ bolt. l The internal pressure of 4 atmosphere produces a bolt load of: 2 Pa = pA A=nD N 4 D = 77+5/8 = 77.625 p = 14.7/2 psi = 7.35 psi N = 12 bolts f 97 \\ (7.35)LT/(77.625)2 2899 lbs/ bolt ~ = p,, 12 2-34 + ,.,,-,-,,,n- --,-----,---,,-,e

c.* Therefore, since the pressure load, Pa is significantly below The the bolt preload, the integrity of the seal is maintained. sealing margin of safety is: M.S. = Fa/Pa - 1 = 7542/2899 - 1 = + 1.60 Secondary Lid Bolts (18 each, 3/4"- 10UNC) The torque is: T = 50 ft-lbs (12) = 600 in-1bs The bolt preload is: f = 600/(-18)(3/4) = 4444 lbs/ bolt Fa = The pressure load per bolt is: Pa = r D2

D = 27.5 in N

er. = (7.35) 4 (27.5)2 = 243 lbs/ bolt 18 Once again, the integrity of the seal is maintained because the bolt preload force exceeds the pressure force by a wide margin. The sealing margin of safety is: M.S. = Fa/Pa - 1 = 4444/243 - 1 = + 17.3 i 2.6.4 Vibration Shock and vibration normally incident to transport are considered to have negligible effects on the 14-195 packaging. 2.6.5 Water Sorav . The package is fabricated of material (steel and lead) that are not ef fected in any fashion by water spray. 2-35 I f

^. i i~ 2.6.6 Free Drop Analysis for the one foot free fall indicates that two possible drop orientations, top end and top corner, would -result in the most significant loads on the lid attachments.- I- -The top end drop was shown to be more severe than the top corner dropuprovided the outer shell extension would not collapse from a top drop. A one-foot top end free fall test onto an essentially Post unyielding surface was performed, with a 14-1g5 cask. test examination of the cask showed that the outer shell L extension did not collapse as a result of the top end drop. It was-This orientation was shown to be the most damaging. ntvesselandnodfstoEfto he"cloN$e."No e o contai significant damage was observed in the target surface. The full scale flat drop test was conducted with a payload For weight of 11,350 lbs., corresponding to 14 loaded drums. a fully loaded 195 cubic foot liner weighing 17,700 lbs., appropriate adjustment to the demonstrated performance of the closure bolts is necessary. The rationale for this adjustment follows. During the test the closure bolts were required to react the j impact loads of the payload (11,350 pounds) and the lid Combined (6,300 pounds), for a total of 17,650 pounds. i weight for the liner payload and lid will be 17,700 pounds + 6,300 pounds = 24,000 pounds. K1 = 24,000 lbs./17,650 lbs. K1 = 1.36 This' represents an increase of 36% in the load carried by the If we conservatively assumed the bolts were stressed up to bolts. their yield point during the test we can conclude that their capacity must be increased by at least 36% to react the higher loads associated with the heavier payload. By increasing the bolt diameter from the tested (and analyzed) 1 inch diameter to a 1-1/4 inch diameter the basic area of the minor diameter will increase by the following ratio. ~ K2

• A /A2 1

2-36

Where: Aj = 1.024 in2 (1-1/2" diametst) A2 =.6464 in2 (1" diameter) .K2 = 1.024/.6464 = 1.58 or an increase of 58% in capacity. Margin of Safety M.S. = K /K1-I 2 = 1.58/1.36 - 1 = +.16 Therefore it can be concluded that the increased bolt size will more than compensate for the increased payload weight (11,350 lbs. to 17,700 lbs.) An additional factor of safety is achieved by modifying the lid to react impact loads in direct compression. Through the use of spacers or stand-off blocks, impact loads are reacted through the blocks directly to the lid and payload. This will nearly eliminate all tension loads in the bolts. The spacer or stand-off blocks are shown as Part 15 on the drawing. It can be seen that these retainer brackets are flush with the top rim of the package. They will react impact loads directly as well as provide protection for the nut. It should be noted that accelerations experienced during a flat end drop are significantly greater than those of the corner drop. Therefore, if the bolts are able to react to the end drop condition a conservative Margin of Safety exists for the corner drop condition. As a result the 14-195H can safely withstand the Normal Conditions of Transport up to a maximum payload weight of 17,700 pounds. In addition to the drop test performed, the following analyses are presented to demonstrate the structural capability of this package. 2.6.6.1 End Drop - Bottom Down 2.6.6.2 End Drop - Top Down 2.6.6.3 Side Drop 2.6.6.4 Corner Drop - Bottom 2.6.6.5 Corner Drop Top 2.6.6.6 Evaluation of Drop Test 2-37 [

i 2.6.6.1 ANALYSIS FOR END DROP - BOTTOM DOWN Gcomcinv 80-1/8" CLR 89-7/8" HGT I 77" ID - b r 83-1/8"0D 96" SQ BASE PL LlD CONST. W A t.t. A r.0 BASE CON ST. 3/ ggg g j C 84 W 'i Y ,\\ r '/g a \\\\\\ \\ t, s o c s gcc c Y LEAD d i \\ '., g gg 3 otAD g \\ g /gg { ' '/v'srccc C AV'T f l Y _j , 3/4 STcC L Si D.C L 2-38

i LOADS a GROSSW[. CASK 38,800 LBS 17,700 LBS PAYLOAD (MAX) l. TOTAL'- 56,500 LBS LID (TOTAL) 6,300 SHELL(CYL) 32,500 SECONDARY LID 850 'f I ASSUP.PTIONS: 1. Fully plastic 2. Total energy abs. by body walls. ENERGY = 56,500(12) = 678,000 IN-LBS ?L1 Ft. req'd since wt.> 30.000 LBS 678,000 3 VOL. STL. = 36,000 = 18.83 IN Dyn. flow stress STL. = Yield strength via CASK DESIGNERS GUIDE, page 56 ~ e 2-39

I . AREA STL = TT(83.125-0.75)(0.75) = 194 IN 18.83 5 = 194.1 = 0.10 IN plastic h .12 - G "- T = 3'.T0 = 120 impact ' ANALYSIS - LID Gsm. J ina ( 7 m l l l / / i -/ 33n .a

7...-

e ~ l P 38Y' IR I + 710 (2.19) 490 (0.75+0.25) TTIE WT. SECONDARY LIO = TTI6 = 0.28 + 0.90 = 1.18 psi q = , DL ROARK & YOUNG - 5th ED. Table 24 Case 10a/10b I 5 2-40 ' ^ " "'4- -~

Consider half-fixity at inner bolt circle: -0.0637 - 0.01563 2 = 0.040 K' = ye 0.20625 + 0.08125 = 2 = 0.144 K EC 4 y=K., o a 2 D M=K,qa = 3 Mc= o.144(1.18)(120)(33.25)2 = 5626 IN-LBS/IN 2 3 Et D= 12(1 i') E Secondary lid stiffness (eq. STL) ST = 15 E transfomed section properties LEAD <t 2Aytop = 1(0.75)(0.375) + 1/15(2.1875)(1.844) + 1(0.125)( 3 = 0.281 + 0.269 + 0.375 = 0.925 IN = o.75 + 1/15(2.1875) +0.125 = 1.021 IN A/IN 0.925 (Ytop) =M = 0.906 IN Sec. Lid l 2-41 l

i (0.75) + 0.75(0.906 -0.375) + 1 (2.1875)' + 2.1875 (0.935)E COMPOSITE = SECTION 12 15 12 15 0.125 (3-0.906)2 gggl3,jg, +

• EFF h12(0.981)'

2.275 IN. = ET 29(10') (2.275) 31.27(10') LB-IN /IN 2 D = = = 12(1-v') 12(1-0.09) 0.04(1.18)(120) (33.25)" 0.002 IN << Half Thickness Y, = = D 2 5626(3.06-0.906) 12.353 osi Mc = = = bend 1 0.981 < Yield STL 5626(5.06-0.906-0.125) MY i- = = Lead 15 1 15 (0.981) 776 nsi < Yield Lead = 1.18(120)(33.25) Q 1177 LS/IN nR = = = Max 2 4 0.40 IN3 0.75(0.906-0.375) Q = = 1 2-42

1177(0.40) =4V 0.981 = 480 psi

4. 1000-2000 RANGE ACCEPT.

= q SHEAR SUtdARY ~ Secondary Lid: STL STRESS = 12,350 psi 4 Yield 780 psi ( Yield = LEAD 480 psi < Allowable = BOND Main Annular Lid: Loaded by line load at inner body and unifomly dur to own wt. ROARK & YOUNG - 5th ED Table 24 Cases le and 2e 850(120)_ W= E(26) = 1249 LBS/IN AT 120 G 0.34 = = ( 3 y= K wa /D y3 = -0.03 K y M= a l ( = 0.25 I 1 l t l l 2-43 l

7 i 142 nsi at 120G 1.18(120) = q = - 0.01 Y = Ky 0 K = 3 0.08 M = Km ga2 ~ 1 K = m FA, = 0.75(0.375) + 2.1875 (1.844) + 0.23(3.063) 15 = 1.32 IN3 2 A = 1.15 IN i,= 1.15 IN i 0.75(1.15-0.375)* (2.1875)3 = + 2.1875 (0.694) (0.75) + 7 = CONPOSITE 12 15(12) 15 + 0.25(3.063-1.15)2 0.035 + 0.45 + 0.058 = 4 + 0.070 + 0.915 = 1.54 IN /IN 3 t 2.64 IN N12(1.53) EFF STL = = 29(10')(2.64) 48.72(10)' L8/IN /IN 0= Et = = l 12(1-v ) 122(1.09) 2 l i i 2-44 . ~.

-0.03(1249)(38.5) - 0.01(142)(38.5) Y' = O D 0.11 IN <* Nalf Thickness = -0.04 - 0.06 = 0.08(142)(38.5) 2 M = 0.25(1249)(38.5) + 28.860 IN-L8/IN = 6300(120) 3125 L8/IN Q = = 'fr (77) 2121 0 12 4 = = 1 1 Lill IN'/IN (Static) 0.75(1.15.375) Q = = _1187 nsi < 1200 psi 3125(0.581) q = = 1.53 (- l i 2-45

r 2.6.6.2 ANALYSIS FOR END DROP - TOP DOWN t , C E D A Q C 1' 7,-, s r' il 2> t SElb * ** r i l ~ l i I l l } j CRITICAL, LOADING UPSIDE DOWN " FLAT" IMPACT IS 14-55' GAL. DRUM PAYLOAD. s 2,46

LOADS PAYLOAD 7.35 FT3 55 GAL. DRUM = 75 PCF SOLIDIFIED WASTE DENSITY = \\ WEIGHT PER DRUM = 550 LBS, USE 600 L85 9000 L91 TOTAL = 14(600) = 8400 LBS + PALLETS = TOTAL WEIGHT = 38,800 + 9000 = 47.800 LBS 573.600 IN-L85 = 47,800(12) = 15.93 IN 573.600 VOLUME STL = = 36,000 i i l 8 0.08 IN (Plastic) ]1.J1 = = 194.1 150 a's (impact) 12 h G = = = 6 0.08 y { I l l 2-47

.= ANALYSIS BASE Subjected to.150 x its dead wt. only. WT. BOTTOMi 710(2.1875)_ 490(0.875) ^ 1728 = 0.25 + 0.90 = 1.15 psi at IG 1728 . + ROARK & YOUNG - 5th E,0 * ~ Table 24 Case 10b 4 y=K,qa /0 K,c = -0.01563 2 M=K qa Kg = -0.125 y D=31.27(10)LB-IN/IN (Seepage 2-54) 6 2 Y = -0.01563(1.15)(150)(38.5)4 = 0.19 IN <C HALF THK e D = -0.125(1.15)(150)(38.5)2 = 31.961 IN-LBS/IN. M3 = 1.15(150)n(77)2 = 1.15(150)(77)_ = 3320 LBS/IN Q 4 force it(11) 4 VALIDATED BY TEST! l i I 2-48 I

kl.R qOtL. d i SECONDARY ' g,g 4 4 f j 4 g i l l* i 33,4 2072L85 at 1G 115 W (29.5) + 2(9000) = TOTAL WT. = 4 14 358 osi at 150G 2072(150)(4) = q = D*' w (33.25)2 4 Roark & Young - 5th Ed. Table 24 Case 10a - 0.0637 y=KyM K = yc D l I .1.20625 M=K qa K = n g, m -0.0637(353}(16.63)" 0.0561N = Y' = 31.27 (106) 0.20623(358)(16.63)2 20.420 LB/IN/IN MAX. Mc = = i VALIDATED BY TEST RESULTS i l 2-49 L_

MAIN ANNULUS 26" (D+L) 1 l \\l I i i i IL 4 .K .i s _.n n C 1 _) -_-_ 4 _\\ 33 W".~ ~ c .77,."ED i i' TOTAL LOAD AT 150G = (6300-850)150 + 12f 9000)(150) 14 j = (5450 + 1714)150 = 1975 Kios 0.48 480 nsi 1975k = q D (17* - 26*) = qr 4 -0.0029 - 0.0008 = 0.002 K ,y ROARK & YOUNG - 5th Ed. = 3 2 TABLE 24 CASE 2c = 0.02s -0.0463 - 0.0101 2L21 - 9.J.E K ,3 = h = m 2 e 77 _0.043 -0.0552 + 0.03 = K m,- 2 0.462 0.6015 + 0.3230 = K = Rb 2 O 2-50

=. 1 g o.002(4s0)(3s5) 0.043 1N. Small! T = Ky o 4s.72(10*) = 1 0.02s(4s0)(3s.5)2 19.921 LS-IN/IN Ega2 = = = K482. 0.0 43(4s0)(3s.5)2 30.600 LB-IN/IN = .Mr 314,2 L8/IN 0.462(480)(36.5) i Q = Egga = = STRESS

SUMMARY

I \\ Mc 30.600(2.04) si bend I= 1 1.53 l = [ if \\ fadial jg. STL. BRX 0 = 40.750 nsi 24dlEAD N 30.600fl.19) 23s7 esi i 1.53(15) bend) = = i 1**d Y

3/4' sn.

T i y,0 8540f 0.75)(1.13-0.373) 3244 nsi i C shear 1.53 I = = I As0VE STRESSES MUST BE COMPARED WITH TEST RESULTS FOR FINAL RESOLUTION. i Y 2-51 \\

800Y BOLTS 4.48 k/IN 8.54('tf )(33.25) 1975 Load = = ctr (77) 90 kips VERT. COMP. 4.48 Y (77) Load / Bolt = = 12 127 kios 90 Tension / Bolt = = 0.707 Bolts are SAE.1429 Grade 8 Min. Yield Strength = 130 ksi 0.79 IN2 T /4 Area = = i 162 ksi (tensile) 127 f = = 0.79 NOTE: CAPACITY OF BOLT TO CARRY ACTUAL LOAD MUST BE RESOLVED BY COMPARISON WITH DROP TEST RESULTS. k 2-52

2.6.6.3 SIDE DROP ANALYSIS GD4ETRY I m. 96" r-D0 VIEW OF BASEPLATE 8' 8' s i EERGY ABSORBED = (VOLtNE) (CRUSH STRENGTH) 2-53

l . LOADS Wh=B4t f,a (TOTAL) ENERGY = 0.131 IN SAY 50-50 split between 56.500 (12) = g tl BASEPLATE AND TOP RING = 2(96)(0.73)(36,000) s BAR 2-1/2 x 4 2592 kios AT BASE END 36,000'(96)(0.73) LOAD = =

91. 8 - - - - - - - - - - - - SAY 9 2 2592 LOAD FACTOR

= = 56.5/2 ANAL,YSIS CAPACITY OF BASEPLATE WELDNENT 5/8 IN. FILLET BETWEEN SIDE WALL AND BASE 2423 kips <1f (83.125)(.928)(10) = l 2-54

~ RESULTS CONTENTS BOTTOM.. + LID SHELL 56,500 LBS TOTAL WT. = LID WT. 6.300 50,200 BASE WT.,6.500 43.70 M 1/2 AT EACH END / 43.700 (92).. IMERTIAL LOAD ACROSS BASE WELD = 2 = 2010 kios < 2423 kips ,, OK ' ?. j:

*.~

J V 2-55

2.6.6.4 ANALYSIS FOR CORNER DROP (BOTTOM) GE0 METRY' . Drop Angle k = Tan ^ 43.86* from vertical 77 = 8U 125 c.G Q l Basep ate. v wo.nl Energy = 56,500 (12") = 678,000 in-lbs. xx x s wv EMPRLT FORC5 W .. j l $lis SI$ Leal stl / / in Ar

2. I B7 6 3,o 3 mches

, cos 4 . wept J lema e:t t=nar l l 2-56 D - 0

( LOADS CK to see if sufficient energy is absorbed for deformation depth equal to21 = 3.03 - 0.8(2.183) MAX. LEAD /A = 3.03 - 0.8(2.183) = 1.28 IN LEAD 0.75 2.32 IN. TRY 2YT = 2k IN. TOTAL A= 1.28 + cosp = 3 3 ~VOL.LEADONLY=Rtanp(sine-Scos0-sin 0/3) cosp=g6 LEAD /YoLEAD=0.721 .', (Yo) LEAD =4 LEAD /0.721 0.75 /_ LEAD =2.25-cosg = 1.21 IN. This provides more than 80% original shielding. sinh =4 LEAD /SLEAD SLEAD=1.21/ sink =1.73IN. R-Rcose = S cose = 1.S/R = 1-(1.75/R) R= 83.125 - 1.5 = 40.15 IN. 2 .0= cos-I (1-1.75/40.81) = 16.84' 2-57

Tan h O.29 - 0.29 (0.96) -(0.29) vol. lead = R3 3 1 = 18.7 in.3 Energy absorbed by lead = 5000 (18.7) = 93,500 in-1bs Energy absorbed by steel walls: 2/3 (yo) stl stl tstl (f yield) stl (Yo) stl = Sstl Tan k =(1.75 + 0.375) Tan k = 2.04 inches SI= 1-2.13 1 -{ksg 0.95 cos e stl = = 40.81 + 0.375 = 18.50 ,, e, g body stl = 2(18.5) y (40.81 + 0.375) (2) = 26.6 in. 360 Energy steel wall = 2 (2.04) (26.6) (0.75) (36,000) 3 = 976,600 in-lbs > 678,000 in-lbs Note: At this point shielding is no problem since less than 20% of original thickness is deformed. 2-58

= 2.00 in. Iterate with 67 2.0-1.04 = 0.96 in, A lead = A - 0.75 = 7 cos g S ead = 0.96 1.39 in SINK =fa l = M lead S stl 1.39 + 0.375 = 1.77 in = Sstl tan k = 1.70 in Ystl = 1 'I \\ = 1-1.77 = 16.940 cos e stl = / TU31 body stl. = 2 (16.94) y (40.81) + 0.375) (2) = 24.35 in 360 vol. stl. wall = 2 (Yo{bg/stl 7 3 = 2 (1.70) (24.38) (0.75) = 20.70 in 7 energy a.b,erbcd body steel = 36,000 (20.70) = 745,000 in-1bs Note:. Since contact area not super sensitive ta4this value will be used to determine inertial load factor. A = 2.00 inches > actual required. 7 l \\ i l l l 2-59 l

l 6tte \\wO d b ~ ^r LEAD IMPACT AREA ( A*) lead = ab(Tr - stri'c) - cd T T a = major axis = R = 40.81 = 56.6 in 2 cosh M b = R = 40.81 in l x = Slead = 1.39 = 1.93 in cost -'T72 1 c = a - x,= 56.6 - 1.93 = 54.67 in. T Cli 1 (56.6)2 - (54.67)2' = ~ 10.57 in h2-c2 = 40.81 d = b,/ I ) l l i 2-60

(A) lead = 56.6 (40.81 ( 4f - 1.31) - 54.67 (10.57) = 27.1 in2 7 IMPACT FORCE = 10,000 (27.1) = 271,000 lbs. STL AREA = 24.35 (0.75) RECALCUALTE DEFORMATIONS FOR CLOSER ENERGY BALANCE. l TRY 6 = 1.75 in 7 fis. 2 k I"J J. / staa bottom \\ / - N,g 6 1.3 5 7 Hssi N N ENERGY ABS. BY STL WALL 1.04 in 0.75 cos N = St1 ,, Hstl = U THK = h Lead = 6, - Hstl = 1.75 - 1.04 = 0.71 in 1.024 in 0.71 Alead S lead = = = sin a G3 [ I l I l 2-61

e " ' S ead + 0.375 = 1.4 in Sstl l Ssti tan h = 1.345 in Ystl l 6)stl = 150 cos Ostl = (1-S) = 1-1.4 = 0.966 in-Ystl 4T M 2(15) er((41.19) (2) = 21.54 in Body steel wall = W vol stl wall = 2 (Yo)g,g BDY tstl = 14.5 in3 sti 7 (Energy)stl wall = 14.5 (36,000) = 522,000 in-lbs Bending of steel base plate plastic = 1.5 M yield =.1.5 (0.75)2 (36000) = 5062.5 in-lbs M 6 Energy =Mk =5062.5 (0.766) = 3875 in-1bs/in NOTE: THE BULK OF THE ENERGY IS ABS. BY THE STL WALL. COMPUTE INERITA LOADS USING IMPACT AREA BASED ON 6 T = 1 3/4 IN. 4 5 e 2-62

LEAD IMPACT AREA + (A)' LEAD = ab(G/2 - sin.~1(c/a) ) - cd a=Majoraxis/2=R/cosQ=40.81/0.72=56.6IN. b = Min'or axis /2 = 40.81 IN. Xo = S LEAD / cosh = 1.024/0.721 = 1.42 IN. c = a - Xo = 56.6 - 1.42 = 55.18 IN. b 40.81 56.6 (56.6)2 - (55.15)2 = 9.085 IN. 2 - c2 d=a a = g (a ) LEAD = 56.6(40.81) U/2 - sin-1 (55.18/56.6) - 55.18(9.085) ~ f = 16.5 IN ( (ImpactForce) LEAD STL WALL IMP;CT AREA ' ( ?.U /)ST., = 21.54 IN. f AREA = BDY(0.75)/cosd = 22.41 IN.2 l-(Impact Force)STL WALL + 22.41(36000) = 306,760 LBS l l.. I s i s 2-63

.g- - t,. STL BASE PLATE- = 5062.5 IN-LBS/IN. Mplastic = 1.5 Myfeld 2d = 2(9.085) =_18.17 IN. TOTALENERGYBENDINGBASEPLATE=91,986k FORCE =. E/t LEAD =91,986h/0.71 = 99,178 LBS. INERTIA FACTOR .STL WALL 14.3 LEAD 2.9 STL BASE 9. 1.76 18.96 USE 19 -l ' APPROX. ENERGY % STL WALL 77 LEAD 13 - STL BASE P_ 10 100 e 9 2-64

ANALYSIS 14-195H BOTTOM DOWN CORNER DROP N base. de. wall pi \\\\\\ / \\\\ \\ Impact plare; bending of overhangingj Base plate conservatively neglected 19g load (contents + bottom wt.) Acting on base plate Total acting nomal = (17.700 + 6500) cos 4 17,449 lbs = 3.47 psi (for 1G) (4) (q,, ) normal = 17.450 = 77 + 85.125 2 y for 19G, Q = 65.9, use 66 psi l l l 9 2-65 +--<-a-

(Ye)-=4 -0.04(66)(38.3)4 = 0.18 in< Half effective thickness, valid center 31.5 (1016 ' deflection Me = 66 (38.5)2 (2.3) = 14,063 in-lbs/ 16 /in [(bend)1gg = 14,063 (3,0623 - 0.906) 30,820 psi <yf eld = .j 0.984 1941' psi < yield 1456 (14063) - (f bend)- lea'd = = 1054V Shear stress at bondline: 511 psi Low' Q1gg = 387 (66) = T Weld _- Base plate-to Wall: 1/2 in fillet or better 7.42 K/in Length = 83.125 = 261 in 1,937,700 lbs Capacity normal = a , OK i Max at 19G = 17449 (19) = 331,531 lbs 1. 0229C ( l l l l l l 2-66 i.

.g ..w RESULTS ?~ l BOTTOM CORNER DROP Acceleration - 19G for I ft, drop height. Bottom plate - 30,820 psi MAX STL ~1,941 psi MAX LEAD , Bondline shear - 511 psi MAX SHEAR STRESS Weldment - Not Critical NOTE: MATERIAL STRESSES ARE ELASTIC. i TEST RESULTS WOULD INDICATE AB0VE STRESSES ARE AT LEAST DOUBLE ACTUAL VALUES EXPERIENCED BY CASK. l 4 6 6 t 2-67

2.6.6.5 ANALYSIS FOR CORNER DROP (TOP) } l I ) 6 6 4 s sooy 's j 26' j

Gdpg, BC# $

I I \\ I I /2.u i I 33'/dh a .y Determine. edge fixity at body (Elastic only). 4 (yield = (0.75)2 36000 = 3375 in-1bs/in (Myield) g su = S 3f FULL FIXITY MOMENT: Roark and Young - 5th Ed. Table 24/ case le b = 13 = 0.34 3 = 16.6 = 0.43 a W.5 a 38 5 Evaluation based on half fixity: case 2e case 2 a K1 = -0.1135 K2 = 0.0778 K2 = 0.3272 where, M = Kqa2 ; Thus, use the following: K1 = -0.1135 = -0.057 2 uniform load on annular portion K2 = 0.0778 + 0.3272 = 0.203 2 Case le Case la 0.2503 K1 = 0.621 line load K1 = near inner body. t -0.1687 K2 = where M = K WB m (M yield)'/w sti 0.057 qa2 = 0.057 (66)(38.5)2 = 5576 in-% 2-68

g- .+ Now try 1/4 fixity. K1 = -0.1132 = -0.028 (uniform load coeff.) 4 K2 = -0.1687 = -0.042 (line load coeff. ) 4 M = 0.028 (66)(38.5)2 -0.042 (W)(38.5) W = 66 qr (13)2 = 335 lb/in 4r (33.25) M = 3320 in-lbs/in -c 3375 .. valid at body K = 0.3272 - (0.3272-0.0778) = 0.265 - -- - - - uniform load factor 4 K = 0.621 - (0.621 - 0.2503) = 0.528 - - - - - line load factor 4 Total load body bolts = 17,450 (19) = 331,550 lbs load / bolt = 27,630 lbs (req'd. vert. component) Angle at 450 yields actual tension = 39.08 kips = 12 bolts SAE J429 tension allowable = 42.41 kips -

• . oA tension stress =

39 = 49.4 ksi < yield = 130 ksi U 7?I M = 0.265 ga2 + 0.523 wa = 0.265 (66)(38.5)2 + 0.523 (338) (38.5) = 32,739 in-lbs in f end = 32734 (3.183 - 1.13) = 43,603 psi (inner steel) b 1.53 f end = 32734 (1.79) = 2553 psi (lead) b 15(1.53) Sheer stress of bondline: I q = 66 (38.5) (0.56) = 482 psi low valve 2 (1.53) It is concluded that the above conservatively calculated stresses demonstrate adequate containment. 0228C 2-69

t. 2.6.6.6 EVALUATION OF DROP TEST END DROP TEST - TOP DOWN. (prawing 1-189-101 Rev AF) ~ ~ 89-7/8" l j. 83-1/8" OD CASK LOADED WITH 14 - 55 6ALLON DRUMS EACH WEIGHING 750 LBS. 'WT. SURVEY: 10,500 LBS 14 - 55 GALLON DRUMS AT 750 LBS EA. = 500 LBS 2 - PALLETS AT 250 LBS EA. = 350 LBS 1 - BRACING ERID = TOTAL PAYLOAD 11.350 LBS t 2-70

e LOADS GROSS WT = 51.310 LBS (ACTUALTEST) '~ 667.030 IN-L85 ENERGY = 51,310(13) = 18.53 IN3 VOL. STL REQUIRED = 667.030 = 36,000 194.1 IN2 80DY AREA IMPACT = rw-(83.125 - 0.73)(0.75) = 0.10 IN. DEFORMATION,A = 18 53 = 194.1 130 o's (plastic) 13 h 6 = = = Ji 0.10 7000 kios FI 194.1 (36,000) = = 136 a's (load) 7000 6 = = 51.3 2-71

r-t~ ANALYSIS CK B'OTTOM Circuiarplate77"DIA. 1.15 psi Wt. BOTTOM = 490(0.75+0.125) + 710[2.19)_ = 1728 2728 ~ TOTALID =ff(77) (1.15) = 5345 LBS CK 4 ROARK & YOUNG - 5th ED Table 24 Case IOb 2 M, = -0.125qa l Nm=-0.125 M.s=-0.125(1.15)(136)(38.5)2=-30,000 IN-LBS/IN 4 Yc = Kycqa /D SHERE Kyc = -0.02 APPROX. 3 D= Et 12(1 91 4 2-72

3/4" STL 0.906" = e 2-3/16" LEAD ESTL = 15 ELEAD TRANSFORMED SECTION 0.067 IN 1 tLEAD = = 15 in = (0.7 5)* + 0.067(2.19)(1.84) + 0.125(3) Apy,doy 2 0.926 IN3 = 1.02 IN2 0.75 + 0.125 + 0.067 (2.19) A = = y Q 0.906 IN 0.926 = = 1.02 Composite (0.75)' = + 0.75(0.531) + 0.125(2.094) 12 0.067(0.156)3 0.067(2.032)' + + 3 3 0.035 + 0.211 + 0.548 + - + 0.187 = l 4 0.981 IN /IN = 3 2.275 IN (steel effective thickness) tay = 3/12(0.981) = ST L y 1 l l 2-73 m

3 31.26 (10') LB-IN /IN 29(10')(2.2751 2 O = =

2 ( o.91)

-0.02(1.15)(136)(38.5)" 0.22 IN < 1 IN..*. Y = = 0 TEST VALID J RESULTS BASE MOMENT CAPACITY DEMONSTRATED BY TEST W/0 YIELDING: M l' O.125(1.15)(136)(38.5)2 29.000 IN-LBS = y SHEAR VALUE VALIDATED BY TEST, W/0 BOND FAILURE: Q LOAD 2 1.15(136)(38.5) 3010 LBS/IN = 2 LID MOMENT CAPACITY DEMONSTRATED BY TEST W/0 YIELDING ~ ~ \\(30,600) M 2 5450 6(11300) I 136 32,000 LB/IN = y (1975000f 7 CAPAEITY OF ALL COMPONENTS OF LID IS AT LEAST 5% GREATER THAN THE LDAD. a 6 O 2-74 ,,n-,,-r w n,..--

g. 2.6.7 Penetration The following analysis evaluates the effect of a 1.25 inch diamete,13 pound cylinder impacting the cask af ter a free fall through 40 inches. This analysis conservatively estimates a maximum penetration of 0.06 inches which is much less than the 3/4 inch thick outer wall. Hence the integrity of the package or shielding is not compromised. l l L 2-75 l -^--9

PENETRATION ANALYSIS 3 WT. = 13 LBS GEOMETRY J ~ ~ s HEMI-SPHERICAL 40" END Ik" DIA. ^ j IMPACT ZONE DIAMETER =' 83-1/8" s ,. 3 s ( LENGTH = 89-7/8" l LOADS EhERGY = Wh = 13(40)=520IN-LBS I VOL. STL = 520/36.000 = 0.0144 IN (r=RADIUSOF13LBCYLINDER v I 14-195 BDY I 2-76

\\ a t 4 SINCE R/r VERY LARGE CONSIDER VOLUME AS PORT BY PLANE SURFACE. 2 ' VOL. SPHERICAL SEGMENT =1td (r - d/3) = 0.0144 . Solving for d: d e depth of penetration into cask outer surface d = 0.0884 INCHES c 2 IMPACT AREA PROJECTED = 0.32 IN FORCE = 11.600 LBS 4 ANALYS15 ROARK & YO'JNG - 5th ED TABLE 31 f CASE 9 2 (fuooP)nEMsRANt=0.4p/t 2 (fgoop) BENDING = 2.4p/t e e 2-77 ~ ^ ~ ~ ~ ~

3-I y,h 0.4 RESULTS

6060 est CONSERVATIVE (fM00P) MEMBRANE

(0.875) INNER STL = 1/8" OUTER STL = 3/4" I'

• 12.400 psi (fM00P BEND *

(1.5) As Effective Thickness .g COMBINE I VIELD ". OK CASK BODY 4 1.22 11.600 0.06 IN 0.48 lk y, 6 4 )

4. THICKNESS SMALL 29(10 )(0.75)

~

• .. OK e

.I I 1 2-78 s'

1 e 2.6.8 Comoression The model 14-195 weighs in excess of 11,000 pounds and therefore is not subject to this condition in accordance with 10 CFR 71.71 (c) (9). 2.7 Hypothetical Accident Conditions Not applicable for Model 14-195 2.8 Special Form Not applicable for Model 14-195 2.9 Fuel Rods Not applicable for Model 14-195 2.10 Appendix Table 2-1 Sunnary of Characteristics of Major Cask Components I i l l l 2-79 i i . _ ~ -

t TABLE 2-1 Summary of Characteristics of Major Cask Components (14-195) Item g(2) Component Dimensions Material from Dwa. Cask Walls Outer Shell 3/4" thick A516 (1) 7 Shield Region 2-3/16" thick lead 4 Inner Shell 1/8" thick A304 6 Primary Lid Outer Shell 3/4" thick A516 (I) 2 Shield Region 2-3/16" thick lead 4 Inner Shell 1/4" thick A304 5 Lid OD Approximately 78" Lid ID 26" Primary Bolts 12 at 1-1/4" dia. x 6-1/2" long SAE J 429 19 A490 Gr. 8 Secondary Lid Outer Shell 3/4" thick A516 (1) 8 Shield Region 2-3/16" thick lead 4 Inner Shell 1/8" thick A304 9 Diameter 36' Secondary Bolts 18 at 3/4" dia. x 2' long SAE J429, 12 A307, Gr. 2 l Cask Bottom Guter Shell (baseplate) 3/4" thick A516 (1) 13 i Shield Region 2-3/16" thick lead 4 Inner Shell 1/8" thick A304 24 (1) A516 replaced A36 for all casks fabricated after March 31, 1980. (2) CNSI Drawing 1-189-101 Rev. AF l I 2-80 = -w --,.,-,---.,,---.a.- -n.--

t i 3.0 Thermal Evaluation A thermal analysis was performed which considers the effect of a steady state condition including the following parameters:

1) Ambient Temperature = 130* F

2) Solar heat absorbed = 13,250 btu /hr 3)

Internal heat generation = 30 watts The analysis provided the following results: maximum external temperature = 180* F corresponding internal cask pressure = o.66 atm The highly conservative results will have no deleterious offect on the -ability of the cask to perform its intended function. The details of this analysis are presented on the following pages. f 3-1

t Themal Analysis of CNSI 14-195 Transoort Cask General Assumptions and Analysis Method This analysis will detemine cask temperature under worst-case (highest temperature) conditions. This assumption includes the following parameters: Direct Sunlight (Sumner 42' N latitude) Ambient Air Temperature (T ) = 130' F Internal Heat Load = 30 watts = 102.4 btu /hr Laminar External Convection Conditions Adiabatic Bottom conditions Heat Loads on the Cask Include: Solar Radiation Waste Decay Heat (30 watts) (102.4 btu /hr) Heat is lost from the cask by the following modes: Convection Radiation to the atmosphere The analysis used to detemine the maximum exterior temperature of the ' cask assumes steady state conditions where the heat load on the cask equals the heat lost. I 3-2 .m.,- ~.-m

), J l 4 I i In' addition, conduction through the cask walls will be considered to determine the temperature difference between the inner and outer surfaces w .of the cask, ' Heat Transfer from the Cask 7 1 J, convection j=hA TEXT - T o ) n From jttat Transfer (4th Ed) by J.P. Holman: "kpproximated h=1.42[4,_TD 1/4 (For vertical cylinders Convection \\L W/M2 oC Laminar Conditions) d Coefficients h = 1.32 [i L J4_T_k 1/4 (For Horizontal Plates, W/M2 oC Heated, Facing Upward, Laminar Conditions) Converting io E6glish Units: I4_1f 1/4 BTU /HR Ft2 oF For Vertical Cylinder h = 0.25 ( L 'l and similarly h = 0.23 1/4 BTU /HR Ft2 of ForhiorizontalPlates I J( Lj e Y

• \\

~ q. 3-3

w -

4. i I.

3 External Surface Areas

Of 02 qr (83)2 = 5410 in2 = 38 ft2 A op = T 4 4 4 2 Asides = 9( DH =,yy (83)(90) = 23470 in2 = 163 f t The Total Heat Loss is the sum of the sides and top: 0.25 (Text - 130)l/4 (163) (Text - 130) + = Q Cony. L 90/12 0.23 (Text - 130)l/4 (38) (Text - 130) 83/12 Radiation cf A otal { (Text 4-T 4) T c{= Where:

f. = 0.8 (assumed for cask)

Cy = 0.17 x 10-8 8TU/hr ft2 og 4 (All Temps in

• R )

4 C{ RAD = 0.8 (0.17 x 10-8) (201) (Text 4 - 590 ) 4 3-4

s Heat Load on the Cask Solar Radiation .. Total Solar Heat Absorbed: -Q=AN Q Si

• Where:

AN= Normal Area (Total) gs1= Solar intensity Surface Absorbtivity c< = (0.8 assumed fo. cask) The total normal area of the cask available for absorption of solar energy is a function of the angle of incindence of the energy, e Atop COS O + Asides Sin e AN Asides (Cross Section) DH = (83)(90) = 7470 in2 = = 52 ft2 38 ft2 A op = T 3-5 s

Data on Solar Intensity is obtained from ORNL-TM-2410: Irradiated Fuel Shipping Cask Design Guide. From this reference, a peak solar insolation of 16,553 BTU /hr is determined. Combining this with the assumed absorptivity for this cask (0.8) yields a solar heat load of 13,250 BTU /hr. Steady State Solution For Steady State: Qin " Cout Cout con + RAD Sin solar + GEN (Converting all temps to

• R) 0.25 (Text - 590)l/4 163 (Text - 590) + 0.23 (Text - 590)l/4(Text - 590)(38) 90/12 83/12

+ 0.8 (0.17 x 10-8)(201)(Text 4 - 590 ) 4 13250 + 102.4 = i l I l { l l 3-6

.t .i. Simplifying Text Let x = 40.75 (x - 590)l/4 (x - 590) + g,74 (x - 590)l/4 (x - 590) 7.5 6.9 4 -+ 2.7 x 10-7 (x4 - 590 ) - 13352 = 0 Evaluating this expression yields: Text = 640' R 5 or Text = 180' F (Based on a ambient temperature of 1300F and maximum solar insolation) l i. I l-i l l l 3-7

t Conductive Heat Transfer Through Cask Walls The following equivalent resistance network is used. 8E0 uter STL R CapPb CapInner STL r c M*, = E uter STL TopInner STL TopPb 0 O M^ O M' a11 al10 uter ST k'a11 Inner STL Pb 0 e M ^- Combining: Rh Rg R3 N 0 O 3-8 -,-.v-.-,, -,., - -. ~, -,., ...g,--,----,,,,,,-.,,,,,,,,,-,_,_p,,,-- --m,y--g.--w,n - -,,, - ~,-,,,..

s t R= H Where thickness, t and area, A are determined from the reference drawing 1-189-101 Rev. AF. Thermal conductivities are: k steel = 25 BTU /hr - ft

• F

~ k lead = 18.6 BTU /hr - it ' F The resulting calculated thermal resistances are tabulated below: Steel Lead Total Ri CAP .0008 .032 .0328 = R2 TOP .0001 .0038 .0039 = WALL .00002 .00006 .000'<8 - R3 R1 R2 R3 REFF = 7.8 x 10-5 R2 R3+R1 R3 + R) R2 = Therefore temperature gradient through cask wall,hT, is: (104.4)(7.8 x 10 -5) REFF AT = = 0.0080F = Therefore the interior of the cask will be at virtually the same temperature as the exterior. 3-9 ,----,,4 ,-.---,r- ,.-,-e.,

7 t Evaluation of Internal Pressure The pressure increase inside the cask due to heating is based on the assumption that material containing water is loaded at 70* F and the temperature is later increased to a maximum of 180* F. Partial pressures of wa.ter & air 9 70' F are: ~ Pg = 0.36 psi P, = 14.7 - 0.36 = 14.34 Partial pressures 0170' F are: Pw = 6.0 psi Pa = 14.34 (180 + 460)/(70 + 460) = 18.4 psi The internal pressure increase is: 9.7 = 0.66 ATM 14.7 P = 6.0 + 18.4 = This pressure is well within the design limits of the cask. f f 3-10

l s 4.0 Containment 4.1 Containment Vessel The containment vessel consists of steel-lead-steel composite walls and ends of various thickness as described in Section 1.2 and summarized in Table 2-1. The stainless steel (A304) inner liner which is present on the cask walls, bottom and lid provides an effective barrier between the task contents and the environment. The containtent vessel is fabricated using full penetration welds. Analyses presented in Section 2.0 demonstrate the capability of the overall structure to maintain the integrity of this containment barrier during all hypothesized normal conditions of transport appropriate for a Type A package as specified by 10 CFR 71. Periodic inspection and maintenance performed using approved CNSI procedures ensures that the containment structures continue to perform their intended functions. Containment Penetration and Closures 4.2 Access to the containment is through one of two lids at the top of the container, depending on the type of contents to be loaded. The small diameter secondary lid provides access through a 26 inch diameter penetration through the primary lid for use with high integrity container type cask liners. The secondary lid seals this penetration using eighteen 3/4 inch diameter bolts torqued to 50 + 5 ft-lbs. An elastomer type gasket maintains a positive seal at tnt interface between the primary and secondary lid. The primary lid is removable to provide unobstructed access to the entire cask cavity for the loading of 55 gallon drums or similar approved containers. The primary lid is sealed to the cask body with an elastomer type gasket and twelve li41nch diameter bolts torqued to 200110 f t-lbs. There are no other penetrations through the package containment. i ( k 4-1

.. ~. O } 4 ~ 5.0 Shielding Evaluation i 5.1 Introduction The CNSI 14-195 packaging consists of steel-lead-steel composite walls, lid and bottom which provide the necessary shielding for the various radioactive materials to be shipped within the package. Analyses described in Sections 2.0 and 3.0 have demonstrated the ability of this Prior to each shipment, container'to maintain its shielding integrity. radiation readings are taken to assure compliance with applicable regulations. Analyses are presented on the following pages which evaluate the ~ shielding capability of this package considering the following assumptions: Maximum allowable dose rate shall be 200 mrem / hour on the cask i 1) surface or 10 mrem / hour at two meters from the cask surface, whichever is limiting. The source is modeled as a point source which can exist on any 2). interior cask surface. This is very conservative, as the source is considered to be in contact with all inner cask surfaces at the same time. 5.2 Package System Shielding Analysis I The cask side wall consists of the outer 0.75-inch steel shell surrounding a 2-3/16-inch thickness of lead and an inner wall of l 0.125-inch thick steel. Total material shield thickness is 0.875 inches l of steel and 2.1875 inches of lead. 1 The bottom end of the cask body shielding consists of an outside layer of s 0.75-inch thick steel and a 2-3/16-inch thick lead shield with an inner Total material containment layer thickness of 0.125 inch of steel. shield thickness of the bottom end of the cask is 0.875 inche's of steel i and 2.1875 inches of lead. The outer surface of the top (closure) end of the cask is a 0.75-inch i The internal lead shield thickness is 2-3/16 inches. thick steel plate. The cavity-side of the closure assembly is 0.25 inch thick steel plate. Total material shield thickness is 1.0 inch of steel and 2.1875 inches o The secondary lid shield thickness is the same as the cask bottom lead. and sidewall. \\ I i 5-1 r !i-

l I - 5.2.1 Source Specification Ganna Source - The. cask is to handle non-fuel-bearing reactor components or solid and solidified processed solids. The major ganna radiation source .is assumed to be Co-60 frem stainless steel components to be ^

handled. Since source geometry will vary cor.siderably for this container, the conservative approach for shield design shall be for the analysis to be based upon a point source (shape and volume factors are not taken into account).

Neutron Source There are no sources of neutron radiation in the radioactive materials carried in the CNSI 14-195 Cask. 5.2.2 Model Specification t - The source strength calculations are perfomed using the cask sidewall and bottom thickness for one case, and using the cask lid thickness for the other case. Shield Regional Densities The mass densities for each material are shown in the table below. SHIELD REGIONAL DENSITIES MATERIAL ELEMENT DENSITY (g/cc) Carben Steel Fe 7.86 Lead ~ Pb 11.34 5.2.3 Analysis and Results Cask Sidewall and Bottom The point source is determined as follows: b' S g=KBywm z I 4 5-2 I i g .-._,-..-.m_ -._.-,___.m_.-,,_,.,.-_m_, ,._,,,,,,,,,y.- -... - ~,,, _- - -,.,. -,, - ~ - - - -,,,,,,., - - - -

mz T Where,-9 = Photon Flux, Y cm2 - sec K = Flux to dose conversion = 2.3 x 10-6 R/hr for Co-60 %T So = Equivalent source, [ b) =Tjuj j t B = Buildup Factor a = Distance from source to dose point, cm Through the side or bottom of the cask, the following values are used: Lead: t = 2.1875 in. = 5.56 cm, p/p = 0.0600 y = 0.684 cm-l Steel: t = 0.875 in. = 2.22 cm, p/p = 0.0515 y = 0.415 cm-l Therefore b) = 4.72 The buildup factor is taken for steel to represent the laminated construction. B = 4.6 Two dose rates will be considered: Di = 10 mr/hr, where: a = 2.1875 in. +.875 in + 2 meters = 208 cm 10 which gives, So = 5.76 x 10

and, D2 = 200 mr/hr, where:

a = 3.0625 in. = 7.78 cm 9 which gives, So = 1.6 x 10 5-3

Cask Lid End The Point source is detemined as follows: ~' p = KB ie g Where, p = Photon Flux, - g K = Flux to dose conversion = 2.3 x 10-6 R /k for Co-60 O g So = Equivalent source, b) = Ej4jtj B = Buildup factor a = Distance from source to dose point, cm Through the top of the cask, the following values are used: Lead: t = 2.1875 in. = 5.56 cm, y/p = 0.0600 p = 0.684 cm-l Therefore, b) = 4.86 The buildup factor is taken for steel to represent the laminated shield. 4 B = 4.7 Two dose rates will be considered: Di = 10 mr/hr, where: a = 3.1875 in. + 2 meters = 208 cm 3h 11 which gives, So = 3.3 x 10 D2 = 200 mr/hr, where: a = 3.1875 in. = 8.1 cm which gives, So = 2.0 x 109[ 5-4

6.0 Criticality Evaluation Not applicable for 14-195 packaging i 6-1 9 -..-n -n- ?. - -, -

g.. m ._4a .a .2., m_ ,s_. ..mm m m..m__m_. .,m_-... s..m 7.0 Doeratina Procedure This section generally describes the procedure for loading and unloading of the CNS 14-195 cask. Detailed procedures developed, reviewed, and approved following requirements of the CNSI Q.A. program are issued to authorized users. 7.1 Loadina Procedure'for 55 eallon drums (or for installation of pre-filled liner) 1. Remove and discard the seal wires from the appropriate primary lid bolts. 2. Loosen and remove the twelve 1-1/4 inch diameter bolts that secure the primary lid to the cask body. 3. Using a lif ting sling attached to the three symmetrically located primary lid lifting lugs, lif t the primary lid. 4. Inspect and verify integrity of cover gasket. 5. Lay down lid on a suitable protected surface, treating lid underside as potentially contaminated. 6. Using crane and-suitable riggings, remove pallet (s) and any shoring material from the cask cavity. 7. Visually inspect cask cavity to verify integrity. 8. Load each pallet with a maximum of seven(7)55gallondrums. Shielding effectiveness may be optimized by placing drums with highest surface dose rate near the center of the pallet. 9. Attach crane to the lifting ring of the pallet and carefully lower into cask cavity, use caution to not damage the gasket seating surfaces or inner walls of cask cavity. i

10. Place shoring where appropriate between drums and cask cavity walls to prevent movement during transport.

11. Repeat the loading procedure for the next layer of palletized j

drums. I Note: For pre-filled liners, use crane to lower liner into cask cavity. e I 7-1

v. 12. Inspect and clean the gasket seating surfaces. 13.- Lift.the primary lid onto the cask and position properly using key and keyway.

14. Replace the twelve 1-1/4 inch bolts and torque to 200 1 10 ft-lbs using a star pattern.

15. Install anti-temper seal wires in appropriate bolts. 16. Perform cask survey and verify all requirements are satisfied. 7.2 Loadina Procedure for Liners (for empty liners pre-installed in cask cavity) 1. Remove and discard the seal wires from the appropriate secondary lid bolts. 2. Loosen and remove the eighteen 3/4 inch diameter bolts that secure the secondary lid to the primary lid penetration. 3. Attach a lifting sling to the single center-mounted lug on the secondary lid, and lift the secondary lid. 4. Inspect and verify integrity of cover gasket. 5. Lay down lid on a suitable protected surface, treating lid underside as potentially contaminated. 6. Proceed with filling the liner following appropriate personnel precautions and operational procedures. 7. Inspect and clean the gasket seating surfaces. 8. Lift the secondary lid onto the primary lid and position using indicated alignment marks. g. Replace the, eighteen 3/4 inch bolts and torque to 50 1 5 ft-lbs using a star pattern. 10. Install anti-tamper seal wires in appropriate bolts. 11. Perform cask survey and verify all requirements are satisfied. 7-2 e

7.3 Unloadina Procedure 1. Remove and discard the seal wires from the appropriate primary lid bolts. 2. Loosen and remove the twelve 1-1/4 inch diameter bolts that secure the primary lid to the cask body. 3. Using a lifting sling attached to the three symmetrically located primary lid lif ting lugs, lift the primary lid from the cask. 4. Attach trane and rigging to appropriate lift points on liner or drum pallet. 5. Proceed with removal of all contents from cask cavity. 6. Clean cask interior as required and inspect interior surfaces for integrity. 7. Install new liner or drum pallets in cask. 8. Clean and inspect the gasket sealing surfaces. 9. Lif t the primary lid onto the cask and position properly using key and' keyway.

10. Replace the twelve 1-1/4 inch bolts and torque to 200 10 f t-lbs.

11. Install anti-tamper seal wires in appropriate bolts.

12. Prior to departure from site, ensure that exterior radiation levels are acceptable, and proper placarding is in place.

I T 7-3 ) ~

t = 8.0 Tests and Maintenance CNSI is committed to an ongoing preventative maintenance program for all shipping packages. The CNS model 14-195 package will be subjected to routine and periodic inspections and testsas outlined in this section and CNSI approved procedures. 8.1 Structural Tests Routine. visual examinations will be performed to detect and correct damage or defects significant to package condition. Exterior stencils, nameplates, seals and bolts will be verified in place, and in good condition. Painted surfaces will be inspected to insure acceptability. Any refurbish.aent will be per approved CNSI procedure. Prior to each actual shipment, cask lid alignment marks will be inspected and their placement verified. 8.2 Lid Gasket The lid gaskets will be inspected every loaded shipment, and replaced as necessary. Regardless of inspection results, the gaskets will be replaced every 12 months, if the cask is in use. 8.3 Shieldina No tests are required for shielding perfornance other than normal transportation compliance surveys. 8.4 Thernal No thernal test are required. O I 8-1

l 9.0 Quality Assurance As required by Section 71.101 (Subpart H) of-10CFR71. Chem-Nuclear Systems, Inc. has established a quality assurance program which satisfies the specified criteria. A description of this program was approved on January 23, 1985 by the Chief. Transportation Branch, Division of Fuel Cycle and Material Safety, USNRC. Section 13.2 of the CNSI Quality Assurance Program requires: 1. Transport cask handling and operation shall conform to the written handling and operation procedure for each licensed cask. 2. prior to the shipment of a transport cask all condition of the NRC's Certificate of Compliance (specifications, tests, inspections) shall be satisfied. All required shipping papers shall be prepared and shall accompany the shipment. 3. Quality Assurance located at Barnwell, S.C., is responsible for inspecting all critical cask handling, storage and shipping operations conducted by Barnwell Site Operations. 4. Established safety restrictions concerning handling, storage and shipping shall be included in the handling and operating procedures for transport casks. t ( e 9-1 l ~ -}}