ML20112E280

Rev 1 to Calculation PI-NSP-95-002, Conductor Temp in Conduits Wrapped W/One H Darmatt Fire Barrier

ML20112E280
Person / Time
Site:	Prairie Island
Issue date:	10/30/1995
From:	Dech N SARGENT & LUNDY, INC.
To:
Shared Package
ML20112E278	List: ML20112E274 ML20112E280
References
PI-NSP-95-002, PI-NSP-95-002-R01, PI-NSP-95-2, PI-NSP-95-2-R1, NUDOCS 9606050214
Download: ML20112E280 (75)

Text

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Cric. Fcr Conductor Temperature in Conduits Calc. Ns. PI-NSP 95 002 sar cont:5 Lunctv

• Wrapped with 1 Hour Darmatt Fire Barrier Rev.1 Date /c/3a//.f X

Safety Related Non Safety Related Page 1 of 13 Client Northern States Power Prepared bd/

/

Project Prairie Island Units 1 & 2 Reviewed by f[d I<tl b Date I

Proj. No. 8960-08 Equip. No.

Approved by E

Date / $7

/-

L RFVISION RtiMM ARY nnd RFVIFW MEIllOD A.

Ravicinn Rummary Revision 0; First issue; pages 1 through 13 Appendix A; pages Al through A50 Appendix B; pages B1 through B26 Appendix C; pages C1 through C49 Revision 1: Added cables 16407-1 and 15406-1 Pages 1 through 13 Appendix A; pages Al through A62 Appendix B; pages B1 through B26 Appendix C; pages C1 through C49 Appendix 0; pages D1 through D15 l

1 0-9606050214 960529 PDR ADOCK 05000282 F

PDR 4

.d' Cdc. Fer Conductor Tempiratura in Conduits Cds. Ns. PI-NSP 95-002 Eh 8"N""* % W 8V " '

Wrapped with 1 Hour Darmatt Fire Barrier Rev.1 Date J

X Safety Related Non Safety Related Page 2 of 13 Client Northem States Power Prepared by Date Project Prairie island Units 1 & 2 Reviewed by Date Prof. No. 8980-08 Equip. No.

Approved by Date il' RFVIRION RilMM ARY and RFVIFW AFTHOO fenntinnadi I

i B,

MFTHOD OF RFVIFW OA cal Ell! ATION REVIFW CHFCKIIRT l

l TYPF OF cal Elli ATION Hand-Prepared Design Calculation Only i

O Computer Aided Design Calculation Only O

Both hand-Prepared and Computer Aided Design Calculation I

FOR HAND-PREPARED DESIGN CALC FOR COMPUTER AIDED DESIGN CALC lehmek the anntnnrimte itaman Ir hack the annrnnrimta itamm) ji Detailed review of the original O A review to determine if the engineering design and calculation.

analysis computer program (s) used have been validated and documented and that the calculation, regardless of O.

O Review by an alternate, simplified or the program ua 4 contains all the necessary approximate method of calculation.

documentation ru feconstru ti.on at a later date.

(MUST BE PERFORMED)

O Review of a representative sample of repetitive calculations.

O A review to verify that the computer program is suitable to the problem being analyzed.(MUST BE PERFORMED)

O Review of the calculation against a similar calculation previously O A review to determine if the input data as specified for performed.

program execution is consistent with the design input, correctly defines the problem for the computer program algorithm and is sufficiently accurate to produce results within any riumerical limitation of the program.

(MUST BE PERFORMED)

O A review to verify that the results obtained from the !

program are correct and within stated assumptions and ;

limitations of the program and are consistent with the '

?

input.

(MUST BE PERFORMED)

O Validation documentation for temporary changes to listed i programs or developmental programs or unique single application programs shall be reviewed to assure that i

methods used adequately validate the program for the f

intended application.

(WHERE APPLICABLE) i O

A4ad & A qMe Reviewer:

DAre

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Cric. For Conductor Temp:retura in Conduits C:le. No. PI NSP.95 002 s.

Nr'aonck Lundy'"

Wrapped with 1 Hour Darmatt Fire Sarrier Rev.1 Date

'f' X

Safety.Related Non. Safety Related Page 3 of 13 Client Northern States Power Prepared by Date Project Prairie Island Units 1 & 2 Reviewed by Date Proj. No. 8960-08 Equip. No.

Approved by Date

[L TARI P OF rnNTFNIS Ractinn Contants P=a= Na 1.

REVISION SUMM ARY and REVIEW METHOD........................... 1 11.

TA B LE O F C O N TE N TS............................................ 3 Ill.

P U R P O S E/S C O P E............................................... 4 IV.

I N P U T D ATA................................................... 5 V.

A S S U M P TI O N S................................................ 8 VI.

AC C EPTAN CE C RITERI A.......................................... 8 i

Vll.

METHODOLOGY

...............................................9 r

t Vill.

CA LC U LATIO N S a nd R E S U LTS..................................... 10 IX.

COMPARISON of RESULTS with ACCEPTANCE CRITERIA................. 10 l

X.

C O N C LU S I O N S............................................... 1 1 4

l Xll.

R E FE R E N C E S................................................. 1 2 Xill.

A PPE N DI C E S................................................. 1 3 I

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Cils. For Conductor Temper:tura in Conduits Cils. No. PI NSP 95 002 S*Q"k; Lundy * "

Wrapped with 1 Hour Darmatt Fire Barrier Rev.1 Date

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X Safety Related Non Safety Related Page 4 of 13 O

l Client Northern States Power Prepared by Date Project Prairie Island Units 1 & 2 Reviewed by Date

[

i Prol. No. 8980 08 Equip. No.

Approved by Date 111.

PtJRPORF/RCOPE l

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The purpose of this calculation is to determine the conductor temperature in conduits wrapped with 1 hour1.157407e-5 days <br />2.777778e-4 hours <br />1.653439e-6 weeks <br />3.805e-7 months <br /> fire barrier utilizing Darmatt fire wrap material.

The calculation will be based on the conductors carrying their full load current and ambient temperature of 40'C. The calculated conductor temperature is l

compared to the conductor rated temperature of S0"C to determine if the conductor rated temperature is exceeded.

l l

l B.

Renpa 3

,!O The scope of this calculation is limited to calculating the conductors l

temperature wrapped with 1 hour1.157407e-5 days <br />2.777778e-4 hours <br />1.653439e-6 weeks <br />3.805e-7 months <br /> Darmatt fire barrier and compare it to the conductors rated temperature of 90*C for the following cables at Prairie Island l

Power Plant: 12181,121J-1,121J 2,1CA-1228,1EMA 6,1K2-18,1K219, l

1K2-20,1K2-7,1K2 2, 2CA-601, 2EMA 6,16407-1, and 15406-1.

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s Ctic. Fer Conductor Temptrature in Conduits Cals. Ns. PI NSP 95-002

- 1Yh i s I

NT*"8 & W 8V"'

Wrapped with 1 Hour Darmatt Fire Barrier Rev.1 Date i

X Safety Related Non Safety Related Page 5 of 13 O

Client Northern States Power Prepared by Date Project Prairie island Units 1 & 2 Reviewed by Date Proi. No. 8960-08 Equip. No.

Approved by Date IM-INPilT DATA A. The' conduit internal and external diameters based on the conduit nominal diameter sizes are taken from reference Xll.C Conduit Nominal ni.m.,., in inch.m mina in incham Internal Frtarnal Wall Thicken=== in inchan 1.25 1.394 1.660 0.133 2.0 2.083 2.375 0.146 2.5 2.489 2.875 0.193 3.0 3.090 3.500 0.205 3.5 3.570 4.000 0.215 4.0 4.050 4.500 0.225 B. The conductor resistances and diameters are taken from reference Xil.B i

Cahlm Sira Ramintanem nhmm/ft ranebetar nimmmear finehl O

niO 0.00i3 0.12 e

1. 6 0.000513 0.184

1. 2 0.000203 0.292

1. 1/0 0.000128 0.373

1. 4/0 0.0000639 0.528 500 MCM 0.0000275 0.813 i

i i

C. The following conduit and cable data are taken from References Xil.E, Xil.F, and XII.G:

Cable Service Cable Cable Full Conduit Size Load Current Nominal (Amps)

Size -

1218 1 MCC 1KA2 Feeder 13/C #4/0 0

2.5" 121J-1 MCC 1K2 Feeder 13/C 500 MCM 308 3.5" 121J-2 MCC 1K2 Feeder 1-3/C 500 MCM 308 3.5" 1CA 1228 PNL 1EMA Feeder 12/C #6 14.5 3"

3.5" ID" 1EMA 6 RMU 113 Bus 15 Feeder 13/C #10 0

3.5" ID" 1K218 Panel 135 Feeder 13/C #2 24 2"

2"l0' O

1x2 7 13 c"c eema 4 3'e nie0 134 2 io-i i

1 K2-2 12 RHR Pit Sump Pump 13/C #10 3.8 1"ID*

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.=

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Cric. For Conouctor Tempsrstura in Conduits Clic. Ns. PI NSP 95 002

.o Neomw%Lundy"*

Wrapped with 1 Hour Darmatt Fire Barrier Rev.1 Date W

n X

Safety Related Non Safety Related Page 6 of 13 V

Client Northern States Power Prepared by Date Project Prairie island Units 1 & 2 Reviewed by Date Prol. No. 8960-08 Equip. No.

Approved by Date l

. til INEUT NATA fcnntinund)

Cable Service Cable Cable Full Conduit Size Load Current Nominal (Amps)

Size 1K219 Panel 135 Feeder 3-1/C #2 46 1.25" 1 K2-20 MV-32267 1-3/C #10 3.5 1"ID' 2CA-601 Panel 2EMA Feeder 12/C #6 14 3"

3.5" ID" 2EMA-6 RMU 213 Bus Rm 26 Feeder 15/C #12 0

3" 3.5" ID" 16407 1 12 St Pump 1 3/C #2, 5 kV 100 4"

I 154061 Bus 112 1-3/C #4/0,5 kV 102 3"

O

• cables are wrapped in KM1 conduit filled with thermal filler,

" cables are routed in the same 3" conduit and in the same 3.5" ID drop.

D.

The rated conductor temperature is 90*C and ambient temperature is 40*C i

(References Xil.E and Xil.G)

E.

The emissivity of the Darmatt surface is 0.7 (Reference Xil.E)

F.

Tho Darmatt material thermal conductivity is 0.783 BTU in/hr-ft *F (0.0653 BTU /hr-2 ft *F) (Reference Xll.E) i G.

The Stephan Boltzman constant is equal to 0.1714X10 8 Btu /hr-ft *R (Reference 2

4 Xil.D) i H.

The thermal resistivity of the cable insulation, jacket, and overall jacket is 500*C-cm/ watt and 0.50*C.cm/ watt for the armor (Reference XII.A) 1.

The thermal resistivity of a steel conduit wallis 2.08 *C-cm/ watt (Reference XII.A)

J.

The following cable construction data are taken from reference XII.E Cable size insulation Individual Jacket Overall Jacket Armor (inch)

Thickness Thickness Thickness Thickness l

(inch)

(inch)

(imh)

(inch) 13/C #10 0.03

.015 0.06 0.025

=

I C:Ic. Fcr Conductor Temptrature in Conduits C:lc. No. PI-NSP 95-002

/

8'"'Q*" k; Lundvi" Wrapped with 1 Hour Darmatt Fire Barrier Rev.1 Date f

X Safety-Related Non Safety-Related Page 7 of 13 Client Northern States Power Prepared by Date Project Prairie Island Units 1 & 2 Reviewed by Date Proj. No. 8960-08 Equip. No.

Approved by Date l LV INPllT DATA tenntinnaen i

Cable size insulation Individual Jacket Overall Jacket Armor (inch)

Thickness Thickness Thickness Thickness (inch)

(inch)

(inch)

(inch) 1-2/C #6 0.045 0.025 0.08 0.025 13/C #2

-0.045 0.025 0.08 0.025 1 3/C #1/0 0.055 0.03 0.08 0.025 31/C #2 0.062 0.03 3/C #2,5 kV 8/64 5/64 See See assumptions assumptions i

3/C #4/0,5 kV

-8/64 6/64 See See assumptions assumptions O'

5* uCu 0-5 0.240 0.= 5 l

l K.

The Darmatt layer nominal thickness for a 1 hour1.157407e-5 days <br />2.777778e-4 hours <br />1.653439e-6 weeks <br />3.805e-7 months <br /> fire barrier is 1.25" (Reference Xll.E) l L.

The diameter of a 19 strand, #2 AWG conductor (Class C stranding), used for cable 164071, is 5 x 0.0591 = 0.296 inch (Reference Xil.H) i i

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Ctic. Fcr Conductor Temosrature in Conduits C Ic. Ns. Pl.NSP 95-002 Sacceric 4L; L. undy *"

Wrapped with 1 Hour Darmatt Fire Barrier Rev.1 Date

'jY X

Safety Related Non Safety Related Page 8 of 13 O

Client Northern States Power Prepared by Date Project Prairie Island Units 1 & 2 Reviewed by Date

[

Proj. No. 8960-08 Equip. No.

Approvad by Date i

lE ARR11MPTIONS A.

Assumptions Not Requiring Verification

1. The thickness of the armor of cables 16407-1 and 15406-1 is assumed to be i

the same as for the other cables (0.025"). The thickness of the overall Jacket l

is assumed to be that thickness required to fill the space between the inside of the armor and the circumscribed diameter of the three conductors with their insulation and individual jackets. Since minor variations in the overall jacket thickness will not have a major effect on the conductor temperature, this assumption does not require verification.

2. This calculation will consider the main run of conduit as a worst case. Because of their larger surface area, the temperature of an enclosure, such as a pull box, will be lower to dissipate the same amount of heat compared to the main conduit run. Since the temperature rise between the inside of an enclosure or conduit is treated as a film temperature drop at the surface of the cable, a lower enclosure surface temperature will result in lower cable and conductor temperatures. This assumption does not require verification.

!R ACCFPTANCE CRITERIA The conductor temperature when carrying the full load current should not exceed the cable continuous rated temperature of 90*C.

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Calc. Fcr Conductor Tempiratura in Conduits Cals. No. PI-NSP 95 002 1

da saw w r Lundy"*

Wrapped with 1 Hour Darmatt Fire Barrier Rev.1 Date

'7 X

Safety Related Non Safety Related Page 9 of 13

.O Client Northern States Power Prepared by Date Project Prairie Island Units 1 & 2 Reviewed by Date Proj. No. 8960-08 Equip. No.

Approved by Date

Mjt MFTHODat OGY A. Calculate the amount of heat generated by the conductors inside the conduit based on the conductors carrying the fullload current and a conductor resistance at 90*C.

l B. Calculate the amount of heat dissipated by convection and radiation from the outside of i

l the Darmatt wrap based on an ambient temperature of 40*C and a surface temperature j

which will allow the heat dissipated by convection and radiation from the Darmatt layer surface to equal the amount of heat generated by the conductors inside the conduit, j

l C. The Darmatt wrap surface temperature will be calculated iteratively using the MATHCAD computer program until the amount of heat dissipated by convection and radiation from the outside of the Darmatt wrap equals the amount of heat generated by the cable inside the conduit D. The temperature drop due to the conduction of heat through the following layers is i

Oi caicuiated based ea 18 heat 9enerated bv ine condectors inside the conduit aad the l

i thermal resistance of each layer:

i The Darmatt mass from the outside surface of the conduit (for cables in condiut) or

+

the cable jacket (for cables routed without conduit) to the outside surface of the i

Darmatt From the inside surface to the outside surface of the conduit (for cables routed in conduit) l l

Through the air gap between the outside surface of the cable and the inside surface of the conduit (for cables routed in conduit)

• The temperature drop from the metal conductor surface to the cable surface (through i

the conductor insulation, jacket,..etc.)

E. The temperature drop through the Darmatt wrap, the conduit, the air space between the cable surface and the inside surface of the conduit and the metal conductor surface to the cable surface will be added to the Darmatt wrap surface temperature to determine the conductor temperature. This value will then be compared to the conductor rated temperature to determine if the conductor calculated temperature exceeds the conductor rated temperature of 90*C when the conductors carry the fullload current.

l the conductor temperature is not necessary since the loads fed by those cables are only F.

Cables No. 12181,1EMA-6 and 2EMA-6 feed intermittent loads. Therefore, calculating L

energized for a short period of time.

[

C le. Fcr Conductor Tamperstura in Conduits C Ic. No. PI-NSP-95-002

., a N'genggLundy"*

Wrapped with 1 Hour Darmatt Fire Barrier Rev.1 Date 7

X Safety-Related Non Safety Related Page 10 of 13 Client Northern States Power Prepared by Date Project Prairie Island Units 1 & 2 Reviewed by Date Proj. No. 8960 08 Equip. No.

Approved by Date Mll).

cat Ellt ATIONS nnri RFRUITA Refer to Appendix A for the calculation of the conductor temperature in conduits wrapped with 1 hour1.157407e-5 days <br />2.777778e-4 hours <br />1.653439e-6 weeks <br />3.805e-7 months <br /> fire barrier.

1X, COMPARIMON nf RFRULTR with ACEFPTANEF CRITERIA The following is a comparison between the conductors calculated temperature and the conductor rated temperature:

Cable No.

Cable Size call Conductor Conductor Pass /

Load Rated Calculated Fail Current Temperature Temperature ( C)

(Amps)

( C) 1218-1 1-3/C 4/0 0

90 pass 121J 1 13/C 500 MCM 308 90 77.8 pass 121J-2 13/C 500 MCM 308 90 77.8 pass 1CA 1228 1-2/C #6 14.5 90 42.8 (Conduit) pass 43.7 (Drop) 1 EM A-6 13/C #10 0

90 pass 1K218 13/C #2 24 90 42.8 (Conduit) pass 43.1(Drop) 1K219 31/C #2 46 90 52.9 pass 1K2 7 1-3/C 1/0 134 90 91.8 fail 1K2 2 13/C #10 3.8 90 40.6 pass 1 K2-20 13/C #10 3.5 90 40.5 (Conduit) pass 40.6 (Drop) 2CA-601 1-2/C #6 14 90 42.8 (Conduit) pass 43.7 (Drop) 2EMA-6 15/C #12 0

90 pass f

16407 1 1-3/C #2. 5 kV 100 90 78.6 pass 15406 1 13/C #4/0. 5 kV 102 90 52.1 pass

• Cables.are_.fe.e. ding. intermittent loads..which are.on.ly..erargized for.short period of.. time..

= - - - - - - - - - - - -

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C:lc. Fcr Conductor Temptrsture in Conduits C Ic. Ns. PI-NSP 95-002 sh

%enedL LundV'"

Wrapped with 1 Hour Darmatt Fire Barrier Rev.1 Date

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Safety Related l

Non Safety Related Page 11 of 13 i

O Client Northern States Power Prepared by Date Project Prairie island Units 1 & 2 Reviewed by Date Prol. No. 8960-08 Equip. No.

Approved by Date I

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CONrl llRinNS l

l The conductor temperature for cables No.121J-1,121J 2,1CA-1228,1K2-18,1K2-219,1K2-7,1K2-2,1K2-20, 2CA-601,16407-1, and 15406-1 installed in conduits wrapped with 1 hour1.157407e-5 days <br />2.777778e-4 hours <br />1.653439e-6 weeks <br />3.805e-7 months <br /> fire barrier utilizing Darmatt material were calculated. It was found l,

that the conductor temperatures are below the conductor rated temperature when those conductors carry load current except for cable 1K2-7.

i i,

As of the approval date of the calculation, cables 1K2-20,1K2-2,1K2-7, and 1K2-18 will not be wrapped due to pending rerouting of the cable and Appendix R revisions.

i Should it be decided to wrap cable 1K2-7, additional calculations must be performed to justify the ampacity of this cable.

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I Cric. For Conductor Temptrsture in Conduits Ccic. Ns. PI-NSP-95-002 ihn

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Wrapped with 1 Hour Darmatt Fire Barrier Rev.1 Date X

Safety Related Non Safety-Related Page 12 of 13 Client Northern States Power Prepared by Date i

Project Prairie Island Units 1 & 2 Reviewed by Date Prof. No. 8960-08 Equip. No.

Approved by Date

\\

i XiL REFERFNCES A.

Sargent & Lundy Star.dard ESA-105 " Electrical Engineering Reference for Calculating Conductor Temperature of Power Cables", Rev. 8-4-95. This reference provides the formulas for calculating the temperature drop from the conductor 1

surface to the inside surface of the Darmatt layer.

l B.

Sargent & Lundy Standard ESA-102 " Electrical Engineering Standard for Electrical l

and Physical Characteristics of Class B Cable", Rev. 4-14-93. This reference provided the cables resistances and diameters.

C.

ANSI C80.1-1990, " Standard for Rigid Steel Conduit", Approved August 31,1990.

This reference provided the conduit inside and outside diameters based on the conduit nominal diameter.

r-i D.

Heat Transfer Book, by J. P. Holman, McGraw Hill Book Company, Second Edition 5

(1968). This reference provided Stephan Boltzman constant, and the convection and radiation heat transfer formulas.

E.

Sargent & Lundy Design Information Transmittal (DIT) No. PI-0001-01, dated i

6/21/95. This reference provided information on the cable, Darmatt material,..etc.

F. Sargent & Lundy Design Information Transmittal (DIT) No. PI-0002-00, dated August 25, 1995. This DIT contains drawings giving information on cable routing and construction. Information was taken from the following drawings:

Drawing No.1) 58-RW-C01, Rev. O, dated August 9,1995 i

2) 58-RW-C02, Rev. O, dated August 9,1995 1

3) 58-RW-T, Rev. O, dated August 9,1995

4) 58-CP-C02, Rev. O, dated August 9,1995

5) 59-CP-C01, Rev. O, dated August 9,1995

6) 59-MT-C01, Rev. O, dated July 13,1995 These drawings provided the cable routing and construction.

G.

Sargent & Lundy Design Information Transmittal (DIT) No. PI-0003 01, dated September 20,1995. This DIT provides information on cables 164071 and i

15406 1.

H.

ASTM Standard B8 81, " Standard Specification for Concentric-Lay-Stranded Conductors, Hard, Medium Hard, or Soft filo:empecay.wp6 i

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f C:Ic. Fcr Conductor Tampiratura in Conduits C:ls. Ns. PI-NSP 95 002 sh h aanas Lundy"*

Wrapped with 1 Hour Darmatt Fire Barrier Rev.1 Date F

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Safety Related Non Safety Related Page 13 of 13

• O C,lient Northern States Power Prepared by Date Project Prairie Island Units 1 & 2 Reviewed by Date Proj. No. 8900-08 Equip. No.

Approved by Date j

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X11L APPENDICES Appendix A-Calculation of the Conductor Temperature f_

Appendix B-Design Information Transmittal Pl-000100

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Appendix C-Design Information Transmittal Pl-0002-00 Appendix D-Design Information Transmittal PI-0003 01 i

Cric. For Conductor Tempiratura in Conduits Cric. No. PI-NSP 95-002 g.

Sargem &; Lundy *"

Wrapped with 1 Hour Darmatt Fire Barrier Rev.1 Date 7

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X Safety-Related Non Safety Related Page A1 of A62 O

Client Northern States Power Prepared by Date Project Prairie Island Units 1 & 2 Reviewed by Date Proi. No. 8960-08 Equip. No.

Approved by Date l

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APPENDIX A CALCULATION OF THE CONDUCTOR TEMPERATURE i

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1 CIlc. No.: PI NSP-95 002 Page: A2 of A62 Rev.1 Proj, No.: 8960-008 O

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8, MCC 1K2 FEEDER - CABLE No.121J 1 & 121J-2 (3/C - 500 MCM)

(file: 121J _12.med)

1) Calculation of the Heat GeneretM in the Conduit Icond = 308 i

is the conductor currentin amps m

Rcond = 0.0000275 R

i cond s the conductor resistance at 90 oC in ohms /ft ncond - 3

% is the number of conductors in conduit Q cond = (3.41443) ;n cond)'(I cond) -(Rcond)

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cond s the heat generated in the conduit in Stu/hr-ft,3.41443 is the conversion factor from watt /ft to Stu/hr-ft Q cond = 26.722 O condw * #"cond/lI cond) -(R cond)

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cond s the heat generated in the conduit in watt /ft Q condw = 7.826

2) Total Heat Transferred from the Wranced Conduit Tam.=40 T is the ambient air temperature in C o

am

- 273;1 9 Conversion of temperature to OR in order to calculate the heat transfer

/

Tat = (sTam 2

5 coefficient in Btu /hr-ft.op T = 563.4 T is the ambient air temperature in degrees Rankine ar ar T.,is the surface temperature of the wrapped conduit, this value is iterated T g) = t until the heat dissipated by Darmatt surface is equal to the heat generated inside the conduit T

-W T,is the conductor rated temperature in degrees Celcius er e

tdarmatt - 1.25 t

is the thickness of the Darmatt layer in inches dem Dcondout = 4.0 Dcondout s the outside diameter of the conduit in inches i

Ddannout D condout + 2 tdannatt Ddarmout s the outside diameter of the Darmatt i

layer in inches I) dannout = 6.5 a) Calculation of the Heat Transferred by Convection from the Wracoed Conduit iTm.(t) - Tar) '

h (t) 2 0.273.

h is the heat transfer coefficient of the wrapped conduit in c

e "I

2 Btu /hr ft. oF (Ref. Xil.D, Table 7-4, Horizontal Cylinders) i 12 j

Cric. No.: PI-NSP 95-002 Page: A3 of A62 Rev.1 Proj. No.: 8960-008 O

D darmouti g*,

A,is the area of the wrapped conduit surface for i hour fire 12 2

barrier perlinear ftin ft /ft A

=1.702 w

Q c(t).= h (t) A w (T,w(t) - Tar) O is the heat transferred by convection from the wrappd c

c conduit surface in Stu/hr-ft b) Calculation of the Heat Transferred to the Surroundina by Radl=+% from the WraeH Conduit Surface 1

4 o := 0.171410 Stephan-Boltzman constant in Stu/hr-ft -R4 2

e

= 0.7 Emissnnty of the wrapped conduit surface (Darmatt) w Qr(I)*"'Ew'A w (Tsw(Of - (Tar)

Qr is the heat transferred by radiation to the

'4 surroundings from the wrapped conduit in Btu /hr-ft l

c) Total Heat Transferred by Convection and Rad!=+% from the Wr=eH Co@M Surface Q cr(O Q c(I)

• Q r(t)

Q is the total heat transferred by convection and radiation from the cr wrapped conduit surface to its surroundings t = 550 Giwn Q cond"Q crlO Tsurface - Find (t)

T is the surface temperature of the Darmatt layer, this value is surface iterated until the heat dissipated by the Darmatt surface equal to the Tsurface = 574.201 heat generated by the cable inside the conduit h (Tsurface) =0.571 Q,(Tsurface) = 16.235 Q c(Tsurface) = 10.487 c

l Q cr(Tsurface) = 26.722

3) Temperature Dron Throuah the Darmatt Laver 2

Kdarmattin = 0.783 Kennettois the Darmatt Conductivity in Stu in/hr-ft 9E Kdannattin i

Kdarmatt

• Kerrnattis the Darmatt Conductivity in Stu/hr-ft0E 12 l

Kdarmatt =0.065 Ddarmout = 6.5 Dennout s the outside diameter of the Darmatt layer in inches i

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4 C;Ic. No.: Pl-NSP-95 002 Page: A4 of A62 Rev.1 Proj. No.: 8960-008 1

G I)darmin - Ocondout O

is the inside diameter of the Darmatt in inches or the outside darmin diameter of the conduit

.f R

.in Rdarmatt s the thermal resistance of the i

K

\\l Kl \\ darmattj

'D danmn i Darmatt layer in CR-fthvatts Rdannatt " I I84 dermatt s the temperature drop through the Darmatt material ATdannatt

• 9 cond R darmatt AT i

in degrees Rankine AT darmatt = 31.645

) AT AT is the temperature drop through the Darmatt darmatte AT

=

materialin C o

ATdarmatte = 17.581 i

(O)

4) Temnerature Dron Throuah the Conduit Wall Dconduit :- 3.5 Dconds is the nominal diameter of the conduit in inches Dcondout =4 De is the outside diameter of the conduit in inches tcond -0.215 teond s the conduit wall thickness in inches i

Dcondin - D condout tcond D

is the inside diameter of the conduit in inches condin Dcondin = 3.57 i

Peond s the thermal resistivity of the conduit materialin p

= 2.08 CC-cmAvatt Rcond = 0.00522 p cond n R

i i

cond s the thermal resistance of the conduit in D

\\ condin i oC-ft/ watt,0.00522 is a conversion to ft from em and Rcond =0.001 combination of constants {(1/2n)(1ft/12in)(0.3937in/cm)}

ATconduit

• 9 condw'R cond ATeondun is the temperature drop through the conduit in C o

1 l

AT

=0.01 conduit I

t

C;lc. No.: PI-NSP 95-002 Page: A5 of A62 Rev.1 Proj. No.: 8960-008 O

5) Calculation of the Temnerature drop throuah the Air Space Between the Cable Surface and the inside Surface of the Conduit A' & B' are constants used to determine the thermal resistance between N=32 j

the cable surface and the inside surface of the conduit g,,

Dcable = 2.297 D.w is the diameter of the group of conductors inside the conduit in e

inches determined in section 6 A'

R R,e is the thermal resistance of the air gap between the cable surface and 3e = Dcable

• B, h*@ da & Md h %M R

=1.287 3e AT,;, = Q condw R AT is the temperature drop in the air space between the cable surface 3e air and the it' side surface of the conduit in OC AT

= 10.07 an

6) Calculation of the Temperature Dron from the Metal Conductor Surface to the Surface of the Cable i

Pi s the thermal resistivity of the insulation surrounding one of the p ; = 500 conductor in OC-cm/ watts pj = $00 p is the thermal resistivity of the individual and overall Jacket in j

DC-cm/ watts p 3; = 0.5 p is the thermal resistivity of the armor in CC-cm/ watt q

t =.065 t is the insulation thickness in inches i

t j = 0.0 t is the individual Jacket thickness in inches j

t j = 0.110 t is the overalljacket thickness in inches aj o

t, = 0 025 t,is the armor thickness in inches d = 0.813 d is the diameter of the conductor metal of one conductor in inches dj = d + 2-t; + 2 t; d is the dbmeter over the individual conductor jacket in inches j

d; =0.943

1 l

O Calc. No.: PI NSP-95 002 e

.: As o< 482 n.,

Proj No.: 8960 008

- 3 l

l dj-d+2tj d is the diameter over the insulabon for one conductor in inches i

d ; = 0.943 i

d j4 - 2.15 dj + 2 t j dg s the diameter over the overall Jacket in inches i

3 -

o d j4 =2.247 3

l l

d ju = d j4 - 2 t j d

3 3

o 3iuis the diameter under the overalljacket in inches d ju = 2.027

]

3 l

d

-d;4+2t d

is the cable overall diameter (including the armor) in inches 3

a arm arm darm "2 297 1

i l

I

,'d ;\\

dD (d3joi ld

\\

R j = 0.00522-2-p ; In

+p;in j arm

• 3 p in

+ 3 p 3j'l j

(d j&j, il/

( 3 jut 3

i R;;=1.581 R is the thermal resistance from the metal conductor surface to the surface of the g

cable in OC-fthvatt,0.00522 is a conversion to ft from cm and combination of constants {(1/2x)(1ft/12in)(0.3937in/cm)}.

l Q condw ATcable

• AT is the tempreture drop from the surface of the one metal 3

g conductor to the surface of the cable in0C -

ATcable =4.125 i

l

7) ConductorTemperature The conductor temperature inside the conduit is equal to the temperature drop through the Darmatt l

layer, the conduit, the air space between the cable surface and the inside surface of the conduit, and l

the temperature drop from the metal conductor surface to the surface of the cable plus the Darmatt layer surface temperature ATtotal

• ATdarmatte - ATconduit + ATair + ATcable ATtotal s the totaltemperature drop i

from the conductor surface to the surface of the Darmatt ATtotal "3I 7g3

- surfaceh'5\\

T conductor * [ T

- 273

+ AT T

is the conductor temperature in C O

gogi eonductor Tconductor = 77.786 l

l l

CIlc. No.: Pl-NSP-95-002 Page: A7 of A62 Rev.1 i

Proj. No.: 8960-008 O

1 B, PANEL 135 FEEDER - CABLE No.1K2-18 (1 - 3/C #2)

(file: 1K2_18.med) j s

l

1) cabu'=% of the Heat Generated by the Conductors j

Icond = 24 leend s the conductor currentin amps i

Rcond.= 0.000203 R

i eond s the conductor resistance at 90 oC in ohms /ft cond = 3 n

i eond s the number of conductors in conduit n

Q cond '* (3 4I443)*(ncond)'(I cond) -(R cond)

Ocond s the heat generated in the conduit in i

Stu/hr-ft,3.41443 is the conversion factor from watts /ft to Stu/hr-ft Q cond = 1.198 Q condw * (" cond)'(Icond)lR cond)

G i

eond s the heat generated in the conduit in watt /ft j

Q condw =0.351

2) Total Heat Transferred from the Wi.ssed Cable O

T

= 40 T is the ambient air temperature in OC am 9

Conversion of temperature to *R in order to calculate the heat transfer ar* ham +E)3 2

coefficient in Btu /hr-ft.op T = 563.4 T is the ambient air temperature in degrees Rankine ar ar T is the surface temperature of the wrapped conduit, this value is iterated u

TA2t s

until the heat dissipated by Darmatt surface is equal to the heat generated inside the conduit T,.= 90 e,is the conductor rated temperature in degrees Celsius c

tdarmatt = 1.25 t

is the thickness of the Darmatt layer in inches dannatt da is the outside diameter of the Darrlatt D dannout '= 4 5 layerin inches O

i

C lc. No.: PI-NSP-95-002 i*

Page: A8 of A62 Rev.1 Proj. No.: 8960-008 O

a) Calculation of the Heat Transferred by Convection from the Wrapped Cable l

' (T,w(t) - Tar) '

h (t) = 0.27-h is the heat transfer coefficient of the wrapped conduit in c

3 e

dannout 2

Stu/hr-ft. oF (Ref. XII.D, Table 7-4, Horizental Cylinders)

-t 12

)

• ,,(Ddannout)

' A,is the area of the wrapped conduit surface for 1 hour1.157407e-5 days <br />2.777778e-4 hours <br />1.653439e-6 weeks <br />3.805e-7 months <br /> fire 12

. barrier perlinear ft in ft /ft 2

A

=1.178 w

Q c(O = h (t) A w (T,w(0 - T c

ar) O is the heat transferred by convection from the wrappd c

conduit surfece in Btu /hr-ft b) Ceb4=+M of the Heat Transferred to the Surroundina by Radiation from the WreeW Conduit Surface c := 0.171410'8 Stephan-Boltzman constant in Btu /hr-ft.R4 2

j E, = 0.7 Emissivity of the wrapped conduit surface (Darmatt) l.

Qr(t)=ce A - (T,w(0)4 - (Ter)

Or is the heat transferred by radiation to its w w surroundings from the wrapped conduit in Stu/hr-ft l

l c) Total Heat Transferred by Convection and Radiation from the Wrapped Conduit Surface Q cr(t) = Q c(0 + Q r(t)

Q is the total heat transferred by convection and radiation from the er l

wrapped conduit surface to its surroundings t := 550 Given Q cond"Q cr(I) l l

Tsurface = Find (t)

T is the surface temperature of the Darmatt layer, this value is surface l

iterated until the heat dissipated by the Darmatt surface equal to the Tsurface = 564.253 heat generaw. by the cable inside the conduit h (Tsurface) = 0.332 Q (Tsurface) = 0.864 Q c(Tsurface) =0.333 e

7 s

Q cr(Tsurface) = 1.198 1

{

~_

C Ic. N3.: PI-NSP-95-002 Page: A9 of A62 Rev.1 Proj. No.: 8960-008

3) Temperature Dron Throuah the Darmatt Laver Kdarmattin = 0.783 K

2 darmattinis the Darmatt Conductivity in Stu in/hr-ft - E Kdarmattin Kdarman

• Kdarman is the Darmatt Conductivity in Stu/hr-ft E g

Kdannart =0.065 D dannout = 4.5 D

is the outside diameter of the Darmatt layer in inches dermout Dcable = 1.139 D

is the diameter of the cable in inches enbie R

In R

i darmatt s the thermal resistance of the

""*" = (2 z/ gK darmatti (Dcable /

Darmatt layer in OR-ftMatts Rdarmatt = 3.351 ATdannatt 9 cond Rdannatt ATearman is the temperature drop through the Darmatt material

()

in degrees Rankine ATdarman =4.014 dannanc * [ggj(AT

. 5 AT is the temperature drop through the Darmatt dermette AT darmatt materialin 0C AT darmatte = 2.23

4) Calculation of the Temperature Drop from the Metal Conductor Surface to the Surface of the Cable Pi s the thermal resistivity of the insulation surrounding one of the i

p ;.= 500 conductor in DC-cmMatts pj = 500 p is the thermal resistivity of the individual and overall Jacket in j

CC-cmMatt p3;=0.5 i

p3j s the thermal resistivity of the armor in OC-cmMatt t;r.04$

t, is the insu ation thickness in inches tj = 0.025 t is the individual Jacket thickness in inches 3

t ; = 0.08 t

i q s the overall Jacket thickness in inches o

t, = 0.025 t, is the armor thickness in inches

Calc. No.: PI-NSP-95-002 Page: A10 of A62 Rev.1 i

i Proj. No.: 8960-008 l Q l

d a 0.292 d is the diameter of the conductor metal of one conductor in inches d; = d + 2 tj + 2 ti d is the diameter over the individual conductor jacket in inches j

d; = 0.432 d is the diameter over the insulation for one conductor in inches d;~=d+2t; i

d ; = 0.382 d ;4 = 2.15 dj + 2 t j d

i g s the diameter over the overall Jacket in inches 3

o d;4=1.089 3

i

. d ju = d j4 - 2 t j d )uis the diameter under the overall Jacket in inches i

3 3

o 3

d3ju = 0.929 d

=dj4+2t, d,,, is the cable overall diameter (including the armor) in inches 3

arm darm " l I39

/

[d;\\

(djH fd ;4)

IdarmI 3

h R ;j 0.00522-2dp;In

+ pyin

+ 3 p j in

• 3p3f d ;4 j.

3 R is the thermal resistance from the metal conductor surface to the surface of the R;j = 3.289 g

cable in CC-ft/ watt,0.00522 is a conversion to ft from em and combination of constants ((1/2x) (1ft/12in)(0.3937in/cm)}.

ATcable "

R;;

AT is the tempreture drop from the surface of the one metal g

3 conductor to the surface of the cable in OC ATcable =0.385 l

5) Conductor Temperature The conductor temperature inside the conduit is equal to the temperature drop through the Darmatt layer, the conduit, the air space between the cable surface and the inside surface of the conduit, and the temperature drop from the metal conductor surface to the surface of the cable plus the Darmatt layer surface temperature ATtotal = ATdarmatte cable

• AT ATtotal s the totaltemperature drop i

from the conductor surface to the surface of the Darmatt ATtotal = 2.615 f

Tconductor = Tsurfact

- 273

+ AT T

is the conductor temperature in CC total conductor t

.Tconductor = 43.088 I

l --

.I

4 Clic. No.: PI-NSP-95-002 i.

Page: All of A62 Rev.1 Proj. No.: 8960-008 O

C _ PANEL 135 FEEDER - CABLE No.1K2-19 (31/C #21 (file: 1K2,,19.med)

1) Caha!stian of the Heat Generated in the Conduit Icond = 46 I

i cond s the conductor current in amps Rcond = 0.000203 R

i cond s the conductor resistance at 90 CC in ohms /ft

{

cond a 3 n

i eond s the number of cables in conduit n

Q cond (3 4I443}'(" condhlIcond) (R cond)

O is the heat generated in the conduit in cond Btu /hr-ft, 3.41443 is the conversion factor from Q cond "4 4 watts /ft to Btu /hr-ft 9 condw r ln cond)'(Icond' cond)

O is the heat genereted in the conduit in cond watt /ft Q condw = 1.289

2) Total Heat Transferred from the WreH Conduit Tam.= 40 T is the ambient air temperature in OC am 9

Conversion of temperature to R in order to calculate the heat transfer C

ar

• h am + 2 2

coefficient in Stu/hr-ft.op T = 563.4 T is the ambient air temperature in degrees Rankine ar ar is the surface temperature of the wrapped conduit, this value is iterated Tsw(t) -= t sw until the heat dissipated by Darmati surface is equal to the heat generated l

inside the conduit

?

l l

T

- 90 T is the conductor rated temperature in degrees Celsius cr er tdannatt " 1.25 terrnatt is the thickness of the Darmatt layer in inches D condout - 1.660 O

is the outside diameter of the conduit in inches condout Ddannout - Dcondout

• 2 tdarmatt Derrnout s the outside diameter of the Darmatt i

layer in inches Ddarmout = 4.16

' O l

l I

E C11c. No.: PI-NSP-95-002 Page: A12 of A62 Rev.1 Proj. No.: 8960-008 OO a) Calculation of the Heat Transferred by Convection from the WraDDed Conduit

' (T,wlt) - Tar)*l h (t) = 0.27-h is the heat transfer coefficient of the wrapped condt.it in c

e danmut 2

Btu /hr-ft. oF (Ref. Xil.D, Table 7-4, Horizental Cylinders) i 12

/}

danmut)

A * = x-A,is the area of the wrapped conduit surface for 1 hour1.157407e-5 days <br />2.777778e-4 hours <br />1.653439e-6 weeks <br />3.805e-7 months <br /> fire 12 2

barrier perlinear ftin ft /ft A

=1.089 w

I Qc(t) 4 h (t) Aw (T,(t) - T ar) O is the heat transferred by convection from the wrapped c

3 c

conduit surface in Stu/hr-ft b) Calculation of the Heat Transferred to the Surroundina by Radiation from the Wraaw Conduit Surface AU o := 0.171410'"

Stephan-Bolt 2. man constant in Stu/hr-ft -R4 2

E

= 0.7 Emissivity of the wrapped conduit surface (Darmatt) w Qr(t)>ac A - (Tsw(t))4 - (T,,)4 Qr is the heat transferred by radiation to the w w

~

surrounding from the wrapped conduit in Stu/hr-ft c) Total Heat Transferred by Convection and Radiation from the WraoM Conduit Surface l

Q cr(t) > Q c(O + Q r(t)

Q is the total heat transferred by convection and radiation from the er wrapped conduit surface to its surroundings t = 550 Given Q cond"O cr(t)

Tsurface - Find (t)

T is the surface temperature of the Darmatt layer, this value is surface iterated until the heat dissipated by the Darmatt surface equal to the Tsurface = 566.438 heat generated by the cable inside the conduit 1

h (Tsurface) = 0.465 Q r(Tsurfacc} =2.863 Q c(Tsurface) " I 537 c

9 cr(Tsurfacc)

• 4 4

l, C;lc. No.: PI-NSP 95-002 l

Page: A13 of A62 Rev.1 Proj. No.: 8960-008 O

3) Temoerature Dron Throuah the Darmatt Laver 2

K darmattm = 0.783 K

is the Darmatt Conductivity in Btu in/hr-ft -QE darmattin l

Kdannattin l

Kdarman ^

K i

darmatt s the Darmatt Conductivity in Stu/hr-ft E g

l Kdarmau =0.065 I

Ddannout = 4.16 D

i darmout s the outside diameter of the Darmattlayerininches l

D% -Dcondout D

is the inside diameter of the Darmatt in inches or the outside darmin diameter of the conduit 1

(

1

)

/Ddarmout\\

Rdarmatt "

. K R armattis the thermal resistance of the In l

d g darmattj (Ddannin /

22 hd 5 Whh Rhtt = 2.241 b

AT darmatt *Qcond'R dannatt ATdarmatt s the temperature drop through the Darmatt material i

in degrees Rankine ATdarmau =9.86 AT is the temperature drop through the Darmatt darmatte AT darmatte AT

=

darmatt materialin DC AT darmatte =5.478

4) Temperature Dron Throuah the Conduit Wall Dconduit - 1.25 Dcondur.is the nominal diameter of the conduit in inches Dcondout =1.66 D

IS the outside diameter of the conduit in inches condout tcond. 0.133 teond s the conduit wall thickness in inches i

Dcondin - Dcondout - 2 tcond D

is the inside diameter of the conduit in inches condin Dcondin " I 394 i

Peond s the thermalresistivity of the conduit materialin p

= 2.08 DC-cm/ watt

i Calc. No.: Pl-NSP-95-002 Page: A14 of A62 Rev.1 Proj. No.: 8960-008

.h,-

Rcond = OM22 pcond-in Rcond s the thermal resistance of the conduit in i

condin /

oC-ft/ watt,0.00522 is a conversion to ft from cm and Rcond = 0.002 combination of constants {(1/2x)(ift/12in)(0.3937in/cm)}

ATg = Q condw R cond AT i

conduit s the tempreture drop through the conduit in CC AT conduit = 0.002

5) Calculation of the Temnerature drop throuah the Air Swe St;;;;a the CeW Surface and the inside Surface of the Conduit A,

A' & B' are constants used to determine the thermal resistance between the cable surface and the inside surface of the conduit 9

D je = 0.476 D is the overall diameter of 1/C #2 in inches calculated in section 6 3e Dcable = 2.15 D,

D is the diameter of the 3-1/C #2 inside the conduit in inches g

cable Dcable = 1.023 A'

R Rc is the thermal resistance of the air gap between the cable surface and sc " Dcable

• B.

the inside surface of the conduit in CC-ft/ watt it = 2.637 sc AT,i, = Q condw R ATairis the temperature drop in the air space between the cable surface se and the inside surface of the conduit in OC ATair = 3.398

6) Calculation of the Temperature Drop from the Metal Conductor Surface to the Surface of the Cable p = 500 p;is the thermal resistivity of the insulation surrounding one of the conductor in DC-cm/ watt p = 500 p is the thermal resistivity of the individual and overallJacket in j

CC-cm/ watts p 3j = 50 p3;is the thermal resistivity of the armor in OC-cm/ watts

Cric. No.: Pl-NSP-95-002 Page: A15 of A62 Rev.1 Proj. No.: 8960-008-

[(

i l

t

.062 t, a the insulation thickness in inches t j - 0.03 t is the overall Jacket thickness in inches q

o d := 0.292.

d is the diameter of the conductor metal of one conductor in inches d is the diameter over the insulation for one conductor in inches d =d+2ti i

1 d j =0.416 d, - d + 2 t j d is the cable overall diameter in inches o

d, = 0.476 d is the diameter over the jacket in inches j

dj = d s I

R is the thermal resistance y

from me mew WE R '= 0'00522-(2)- p iIn U

id/ - p } In g,g surface to the surface of the d

cable in DC-ft/ watts,0.00522 is a conversion to ft from cm i

R ;j = 1.848 and combination of l

constants ((1/2x)

(1ft/12in)(0.3937in/cm)}

l ATcable ' 9 condw R ;j AT is the tempreture drop from the surface of the metal conductor g

j to the surface of the cable in DC l

ATcable = 2.381 l

l

7) ConductorTemperature The conductor temperature inside the conduit is equal to the temperature drop through the Darmatt l

!ayer, the conduit, the air space between the cable surface and the inside surface of the conduit, and the temperature drop from the metal conductor surface to the surface of the cable plus the Darmatt -

layer surface temperature i

ATtotal = A Tdannatte - ATconduit + ATair + ATcable ATtotal s the total temperature drop i

from the conductor surface to the surface of the Darmatt ATtotal = 11.259 conductor '((Tsurt' cch - 273

~

5\\

T D

+ AT T

is the conductor temperature in C a

total conductor Tconductor = $2.947

C:Ic. No.: PI-NSP-95-002 Page: A16 of A62 Rev.1 Proj. No.: 8960-008 O

j E MV 32267 - CABLE No.1K2 20 (1 - 3/C #10)

(file:1K2 20 med) l

1) Calculation of the Heat Generated by the Conductors Icond = 3.5 leond s the conductor currentin amps i

l Rcond = 0.0013 R

i cond s the conductor resistance at 90 oC in ohms /ft eond s the nuinber of conductors in conduit i

cond = 3 n

n Q cond.= (3,41443)-(ncond)'(Icond) -(Rcond)

O i

cond s the heat generated in the conduitin Stu/hr-ft,3.41443 is the conversion factor from watts /ft to Btu /hr-ft i

Q cond =0.163 l

9 condw = (ncond)'(I cond) -(R cond)

Ocond s the heat generated in the conduit in i

watt /ft Q condw =0.048 t

2) Total Heat Transferred from the Wrapped Cable f

l Tam ' 40 T is the ambient air temperature in C o

am Tat =/Ti am + 273T 9 Conversion of temperature to CR in order to calculate the heat transfer 2

/5 coefficient in Stu/hr-ft.op l

T = 563.4 T is the ambient air temperature in degrees Rankine ar ar T,,is the surface temperature of the wrapped conduit, this value is iterated TA=t s

l until the heat dissipated by Darmatt surface is equal to the heat generated inside the conduit Tcr = 90 T is the conductor rated temperature in degrees Celsius e7 tdarmatt = 1.25 t

is the thickness of the Darmatt layer in inches darmatt Udarmout s the outside diameter of the Darmatt i

Ddarmout.= 3.5 layerin inches f

u

l C:Ic. No.: PI-NSP-95-002 I.

P;go: A17 of A62 R v.1 Proj. No.: 8960-008 O

l l

a) Calculation of the Heat Transferred by Convection from the Wrapped Cable h (t) = 0.27 l (Tsw(t) - Tar)

i h is the heat transfer coefficient of the wrapped conduitin e

c l

dannout\\

2 Btu /hr-ft. oF (Ref. Xil.D, Table 7-4, Horizental Cylinders)

[ t 12

/

(Ddannout)

A is the area of the wrapped conduit surface for 1 hour1.157407e-5 days <br />2.777778e-4 hours <br />1.653439e-6 weeks <br />3.805e-7 months <br /> fire w

12 barrier per linear ftin ft /ft 2

A = 0.916 w

e ar) O is the heat transferred by convection from the wrappd Q c(0 = h (t) A w(Tsw(0 - T c

conduit surfece in Stu/hr-ft b) Calculation of the Heat Transferred to the Surroundina by Radiation from the Wrapped Conduit Surface c := 0.171410-8 Stephan-Boltzman constant in Stu/hr-ft -R4 2

e, = 0.7 Emissivity of the wrapped conduit surface (Darmatt)

Qr(t)'=oE A - (Tsw(t))# - (Tar)4 Or is the heat transferred by radiation to the w w surrounding from the wrapped conduit in Btu /hr-ft i

i c) Total Heat Transferred by Convection and Radiation from the Wrapped Conduit Surface Q cr(t) Q c(t) + Q r(t)

O is the total heat transferred by convection and radiation from the cr wrapped conduit surface to the surrounding t = $50 Given Q cond"Q cr(t)

Tsurface = Find (t)

T is the surface temperature of the Darmatt layer, this value is surface iterated until the heat dissipated by the Darmatt surface equal to the Tsurface = 563.563 heat generated by the cable inside the conduit h (Tsurface) =0.233 Q r(Tsurface) =0.128 Q c(Tsurface) = 0.035 c

i Qcr(Tsurface) = 0.163 O

l l

Cric. No.: PI-NSP-95-002 Page: A18 of A62 Rev.1 l

Proj. No.: 8960 008 lO

3) Temperature Drop Throuah the Darmatt Laver i

Kdarmattin = 0.783 K

is the Darmatt Conductivity in Btu in/hr-ft2: E darmattin K6rmatts l

Kdarmatt =

K i

darmatt s the Darmatt Conductivity in Stu/hr-ft E 12 Kdarmatt =0.065 Ddarmout = 3.5 D

i darmout s the outside diameter of the Darmatt layer in inches D cable = 0.613 D mis the diameter of the cable in inches e

darmoutI h.D

,/

1 R

i darmatt s the thermal resistance of the O'**", \\2 n/ k Kdarmattl ( Dcable /

l Darmatt layer in OR-ftMatt l

Rdarmatt =4 249 l

ATdarmatt " Q cond R g. matt AT i

darmatt s the temperature drop through the Darmatt material In degrees Rankine AT

= 0.693 darmatt

= ( [M AT is the temperature drop through the Darmatt darmatte A'I' darmatte darmatt g9 ma erialin CC 1

AT darmatte = 0.385 l

4) Calculation of the Temperature Drop from the Metal Conductor Surface to the Surface of the Cable El s the thermal resistivity of the insulation surrounding one of the p ; = 500 l

conductor in OC-cmMatts p; = 500 p is the thermal resistivity of the individual and overall Jacket in j

i oC-cmMatts I

l p 3; = 0.5 p3;is the th,'ons;i;sistivity of the armor in CC-cmMatts t ; '=.03 t, is the insulation thickness in inches tj '= 0.015 1 is the individual Jacket thickness in inches 3

t

= 0.06 t is the overall Jacket thickness in inches aj

l l

C Ic. No.: PI-NSP-95-002 Pzgs:.419 of A62 Rev.1 Proj. No.: 8960-008 O

.kJ t, = 0.025 t, is the armor thickness in inches d = 0.116 d is the diameter of the conductor metal of one conductor in inches d; = d + 2 t;+ 2 t d; is the diameter over the individual conductor jacket in inches d; = 0.206 d~=d+2t d is the diameter over the insulation for one conductor in inches l

i d = 0.176 d j4 = 2.15 d; + 2 t ;

d39 s the diameter over the overallJacket in inches j

i 3

o d ;4 =0.563 3

d ju.= d ;4 - 2 t ;

d 3

3 o

3juis the diameter under the overall Jacket in inches d ju =0.443 3

d d

is the cable overall diameter (including the armor) in inches

=d;4+2t 3

a arm arm d

= 0.613 arm

/

Id (d U 2 p ;In

)

+ p; In j

' + 3 p; In

+ 3 p 3; In i

Id ;4) ld 3

arm R;

0.00522-O

\\

(d/

g ih d

(d jul (d j4j) 3 3

R is the thermal resistance from the metal conductor surface to the surface of the R ;; = 4.876 g

cable in DC-ft/ watts,0.00522 is a conversion to ft from em and combination of constants ((1/2x) (1 ft/12in)(0.3937in/cm)).

AT is the tempreture drop from the surface of the one metal ATcable

R ;;

g 3

conductor to the surface of the cable in DC ATcable =0.078

5) Conductor Temperature e

i The conductor temperature inside the conduit is equal to the temperature drop through the Darmatt l

layer, the conduit, the air space between the cable surface and the inside surface of the conduit, and the temperature drop from the metal conductor surface to the surface of the cable plus the Darmatt layer surface temperature ATtotal = ATdarmatte + ATcable ATtota is the totaltemperature drop from the conductor surface to the surface of the Darmatt ATtotal = 0.463 Tconductor =

Tsurface-

- 273

+ AT T

is the conductor temperature in DC total cwuctor o

V Tconductor = 40.553 l

C;lc. No.: PI-NSP-95-002 Page: A20 of A62 Rev.1 Proj. No.: 8960-008 L 12 RHR PIT SUMP PUMP -CABLE No.1K2-2 (1 3/C #101 (file: 1K2_2.med)

1) Calculation of the Heat Generated by the Conductors Icond = 3.8 l

is the conductor current in amps eone Rcond.= 0.0013 R

is the conductor resistance at 90 oC in ohms /ft cono eond s the number of conductors in conduit i

cond = 3 n

n 9 cond = (3.41443).(ncond)'(I cond) -(Rcond)

O is the heat generated in the conduit in cono Btu /hr-ft,3.41443 is the conversion factor from watts /ft to Btu /hr-ft Q cond = 0.192 Q condw * (" cond)'(Icond) -(Rcond)

Ocond s the heat generated in the conduit in i

watt /ft Q condw = 0.056

2) Total Heat Transferred from the Wracoed Cable O

Tam.=40 T is the ambient air temperature in OC am Tar =(' Tam + 27319 Conversion of temperature to CR in order to calculate the heat transfer 2

/ 5 coefficient in Stu/hr-ft.op T = 563.4 T is the ambient air temperature in degrees Rankine ar ar T.,is the surface temperature of the wrapped conduit, this value is iterated T @;t 8

until the heat dissipated by Darmatt surface is equal to the heat generated inside the conduit T, = 90 T,is the conductor rated temperature in degrees Celsius c

e tdannatt = 1.25 t

is the thickness of the Darmatt layer in inches darmatt D

is the outside diameter of the Darmatt D

-3'5 darmout "I

layer in inches O

C lc. No.: PI-NSP-95-002 Page: A21 of A62 Rev.1 Proj. No.: 8960-008 a) Calculation of the Heat Transferred by Convection from the Wrapped Cable i

h (t) = 0.27 l ',w(t) - Tar)

.iT h is the heat transfer coefficient of the wrapped conduit in l

c e

l l

darmout\\

2 Btu /hr-ft. oF (Ref. Xil.D, Table 7-4, Horizental Cylinders)

(\\

12

/

(D darmout)

A,is the area of the wrapped conduit surface for 1 hour1.157407e-5 days <br />2.777778e-4 hours <br />1.653439e-6 weeks <br />3.805e-7 months <br /> fire 12 barrier per linear ftin ft /ft 2

A = 0.916 w

Q c(O = h (t) A w(Tsw(t) - T ar) O is the heat transferred by convection from the wrappd c

c conduit surfece in Btu /hr-ft j

b) Calculation of the Heat Transferred to the Surroundina by Radiation from the Wrapped Conduit Surface c := 0.171410'8 Stephar-Boltzman constant in Stu/hr-ft.R4 2

e

> 0.7 Emissivity of the wrapped conduit surface (Darmatt) w Q r(t) = o e A - (T,w(t))4 - (Tar)

Qr is the heat transferred by radiation to the w w surrounding from the wrapped conduit in Stu/hr-ft c) Total Hea Transferred by Convection and Radiation from the Wrapped Conduit Surface Q cr(l)

• Q c(t) + Q r(t)

Q is the total heat transferred by convection and radiation from the er wrapped conduit surface to the surrounding l

t=550 Given Q cond"Q cr(O Tsurface = Find (t)

T,g,c,is the surface temperatu.e of the Darmatt layer, this value is iterated until the heat dissipated by the Darmatt surface equal to the Tsurface = 563.591 heat generated by the cable inside the conduit h (Tsurface; = 0.243 Q r(Tsurface) = 0.15 Q c(Tsurface) = 0.042 e

O

'C"'r -) '

l l

C Ic. N3.: PI-NSP-95-002 1

Pzgs: A22 of A62 Rev.1 Proj. No.: 8960-008

3) TemDerature DroD Throuah the Darmatt laver 2

Kdamutttin = 0.783 Kdarmattinis the Darmatt Conductivity in Btu in/hr-ft ng Kdarmatt =

Kdarmattis the Darmatt Conductivity in Stu/br-ft E 12 Kdarmatt =0.065 darmout s the outside diameter of the Darmatt layer in inches i

D darmout = 3.5 D

Dcable = 0.613 Dcaba is the diameter of the cable in inches (D

I I

/

1 darmout Rdarmatt = -

In R

is the thermal resistance of the darmatt 25 Kdarmatt i

cable /

D g

Darmatt layer in *R-ftMatts Rdarmatt =4.249 i

ATdarmatt

• 9 cond-R darmatt ATdarmatt s the temperature drop through the Darmatt material in degrees Rankine i

ATdarmatt = 0.817 l

damate*[g9j5j 0T ATdermatte is the temperature drop through the Darmatt AT daman l

materialin 0C AT

= 0.454 darmatte

4) Calculation of the Temperature Drop from the Metal Conductor Surface to the Surface of the Cable pj is the thermal resistivity of the insulation surrounding one of the conductorin C-cmMatts o

p is the thermal resistivity of the individual and overall Jacket in p; = 500 j

OC-cmMatts p 3; = 0.5 p3;is the thermal resistivity of the armor in CC-cmMatts t

=.03 t, is the insulation thickness in inches t is the individual Jacket thickness in inches t; = 0.015 j

t is the overall Jacket thickness in inches t ; = 0.06 p/

q 4

o

(

I I

Cric. No.: PI NSP-95-002 l

Page: A23 of A62 Rev.1 Proj. No.: 8960-008

(

i

())

q ta = 0.025 t,is the armor thickness in inches d = 0.116 d is the diameter of the conductor metal of one corductor in inches dj = d + 2 tj + 2 t d is the diameter over the individual conductor jacket in inches j

d; = 0.206 '

d =d+2tj d is the diameter over the insulation for one conductor in inches i

d = 0.176 d ;4 = 2.15 dj + 2 t j dg is the diameter over the overall Jacket in inches 3

o d ;g =0.563 3

d 3ju = d ;4 - 2 t ;

d is the diameter under the overallJacket in inches 3

o 3ju d ju =0.443 3

dann '= d ;4 + 2 t d

is the cable overail diameter (including the armor) in inches 3

a arm d

= 0.613 arm

/

Id jj (djH (d ;4) fd I

3 unn R jj = 0.00522 2-p In

+ pyin

+ 3.p in

+3p3f j

j d ;4 j.

3 R is the thermal resistance from the metal conductor surface to the surface of the R jj =4.876 g

cable in C-ft/ watts,0.00522 is a conversion to ft from cm and combination of o

constants ((1/2x) (1 ft/12in)(0.3937in/cm)).

Q condw ATcable "

4g

% is h temme % hm me sudace o% metal con &cw 3

to the surface of the cable in C o

5) Conductor Temperature The conductor temperature inside the conduit is equal to the temperature drop through the Darmatt layer, the conduit, the air space between the cable surface and the inside surface of the cor:duit, and the temperature drop from the metal conductor surface to the surface of the cable plus the Darmatt layer surface temperature ATtotal = ATdarmatte + ATcable AT i

total s the total temperature drop from the conductor surface to the surface of the Darmatt ATtotal = 0.545 i

Tconductor '

Tsurface

- 273

+ AT T

is the conductor temperature in C o

total conductor O

Tconductor = 40.651

C:lc. No.: PI-NSP-95-002 Pags: A24 of A62 Rev.1 Proj. No.: 8960-008 O

E 13 CHG PUMP - CABLE No.1K2-7 f1 -3/C 1/0)

(file: 1K2_7.med)

1) Calculation of the Heat Generated by the Conductors i

Icond

• 134 leond s the conductor currentin amps Rcond.= 0.000128 Rcond s the conductor resistance at 90 oC in ohms /ft i

eond s the number of conductors in conduit i

eg g.= 3 n

n Q cond.1 (3.41443)-(ncond)'(Icond) -(Rcond)

O is the heat generated in the conduit in cond Stu/hr-ft,3.41443 is the conversion factor from watts /ft to Stu/hr-ft Q cog = 23.543 Q condw ' ("cond)'(Icond) -(Rcond)

Ocond s the heat generated in the conduit in i

Watt /ft Q condw = 6.895

-(3 1

V

2) Total Heat Transferred from the WraDDed Cable T

= 40 T is the ambient air temperature in CC am am 1

Tat = (, Tam + 273) 9 Conversion of temperature to CR in order to calculate the heat transfer 2

5 coefficient in Btu!br-ft.op j

T = 563.4 T is the ambient air temperature in degrees Rankine ar ar T,wis the surface temperature of the wrapped conduit, this value is iterated T A =t 8

until the heat dissipated by Darmatt surface is equal to the heat generated inside the conduit Ter. 90 T is the conductor rated temperature in degrees Celsius er tdarmatt.= 1.25 t

is the thickness of the Darmatt layer in inches dannatt is the outside diameter of the Darmatt darmout Ddarmout - 4 5 layerin inches

C:lc. No.: Pi-NSP-95-002 Page: A25 of A62 Rev.1 Proj. No.: 8960-008 O

a) Calculation of the Heat Transferred by Convection from the Wracoed Cable

' (Tgw(t)- T )

ar h (t) = 0.27 h is the heat transfer coefficient of the wrapped conduit in c

e dan n t 2

Btuihr-ft. oF (Ref. Xtl.D Table 7-4, Horizental Cylinders) i 12 A*=x-(Ddannout)

A,is the area of the wrapped conduit surface for i hour fire 12 barrier perlinear ftin ft /ft 2

A

=1.173 w

c ar) O is the heat transferred by convection from the wrappd Q c(t) = h (t) Aw (T,,(O - T c

conduit surfece in Stu/hr-ft b) Calculation of the Heat Transferred to the Surroundina by Radiation from the Wrapped Condud Surface c = 0.171410.s Stephan-Boltzman constant in Stu/hr-ft -R4 2

e, = 0.7 Emissivity of the wrapped conduit surface (Darmatt)

Q r(t) '= O E A - (T,w(t))4 - (Tar)4 Qr is the heat transferred by radiation to the w w surrounding from the wrapped conduit in Stu/hr-ft c) Total Heat Transferred by Convection and Radiation from the Wrapped Conduit Surface Q cr(t) = Q c(O + Q r(t)

O is the total heat transferred by convection and radiation from the cr wrapped conduit surface to the surrounding t'=550 Given Q cond"9 cr(t)

Tsurface Find (t)

T is the surface temperature of the Darmatt layer, this value is surface iterated until the heat dissipated by the Darmatt surface equal to the Tsurface = 576.352 heat generated by the cable inside the conduit h (Tsurface) = 0.655 Q r(Tsurface) = 13.555 Q e(Tsurface) =9.988 e

Q cr(Tsurface) = 23.543

CIlc. No.: PI-NSP-95-002 Pigs: A26 cf A62 Rav.1 Proj. No.: 8960-008

3) Temperature Drop Throuah the Darmatt Laver 2

Kdannattin = 0.783 K

is the Darmatt Conductivity in Stu in/hr-ft -QE darmattin Kdarmatt =

Kdarmatt s the Darmatt Conductivityin Stu/hr-ft E i

12 Kdarmatt =0.065 D dannout =4.5 Ddarmout s the outside diameter of the Darmatt layer in inches i

Dcable = 1.377 D.m is the diameter of the cable in inches e

d I

'l dannout R

i U""*", \\2 K),Kdannattf in darmatt s the thermal resistance of the D

i cable /

Darmatt layer in CR-ftMatts Rdarmatt = 2.888 ATdannatt Q cond R darmatt ATdarman is the temperature drop through the Darmatt material i

in degrees Rankine AT

= 68.001 darmatt

=[5(T AT is the temperature drop through the Darmatt darmatte AT U""*"

i9/

materialin CC ATdarmatte " 37 778

4) Calculation of the Temperature Drop from the Metal Conductor Surface to the Surface of the Cable Pi s the thermal resistivity of the insulation surrounding one of the i

p ; = $00 conductor in CC-cmMatts p is the thermal resistivity of the individual and overall Jacket in p;=500 j

CC-emMatts p3j s the thermal resistivity of the armor in 'C-cmMatts i

p 3; = 0.5 t =.055 t, is the insulation thickness in inches t; 0.03 t is the individual Jacket thickness in inches 3

t is the overall Jacket thickness in inches t ; = 0.08 q

o

CIlc. Na.: PI-NSP-95-002 Page: A27 of A62 Rev.1 Proj. No.: 8960-008 O

1 t = 0.025 t,is the armor thickness in inches a

d = 0.373 d is the diameter of the conductor metal of one conductor in inches dj = d + 2 tj + 2 t; d is the diameter over the individual conductor Jacket in inches j

d; = 0.543 d;=d+2t; d is the diameter over the insulation for one conductor in inches i

d ; = 0.483 d ;4 = 2.15 d; + 2.t j d,is the diameter over the overallJacket in inches 3

o 3j d ;4 =1.327 3

d ju = d ;4 - 2 t j d is the diameter under the overall Jacket in inches 3

3 o

3ju d ju = 1.167 3

d

=d;4+2t d

is the cable overall diameter (including the armor) in inches 3

a a

arm darm "I 377

g. g R;j = 0.00522-2 p ; In

I

+ p;In

D'

+ 3 p; In

. + 3 p 3; In I

fd (d

/d3j4)

(d I

arm g

4 (d/

(d;g d ju)

(d j4j j 3

3 R is the thermal resistance from the metal conductor surface to the surface of the R ;; = 2.966 g

cable in C-ft/ watts,0.00522 is a conversion to ft from em and combination of o

constanis {(1/2x) (1 ft/12in)(0.3937in/cm)).

~ Q condw ATcable *

-R ;;

AT is the tempreture drop from the surface of the one metal g

3 conductor to the surface of the cable in C o

ATcable = 6.817

5) Conductor Temperature The conductor temperature inside the conduit is equal to the temperature drop through the Darmatt layer, the conduit, the air space between the cable surface and the inside surface of the conduit, and the temperature drop from the metal conductor surface to the surface of the cable plus the Darmatt layer surface temperature ATtotal = ATdarmatte + ATcable AT i

total s the total temperature drop from the conductor surface to the surface of the Darmatt ATtotal = 44.596 Tconductor =

Tsurface

- 273

+ AT T

is the conductor temperature in C o

total conductor Tconductor "9I 79I

C:lc. No.: PI-NSP-95-002 Page: A28 of A62 Rev.1 Proj. No.: 8960-008

& PANEL 1EMA AND 2EMA FEEDERS - CABLE No.1CA-1228 & 2CA-601 (2/C - #6)

1) Calculation of the Heat Generated in the Conduit We:EMA_12#,CD)

I lea = 14.5 1

is the cable 1CA-1228 current in amps 3c I2ca

• I4 1

is the cable 2CA-601 currentin amps 2ca Rg.= 0.000513 R

is the conductor resistance at 90 oC in ohms /ft m

cond = 2 n

i eond s the number of conductors in conduit n

l 2

Q is the heat generated in the conduit in Q ea = (3.41443)-(ncond)I lea )-(Rcond) 1ca l

h4WCWmhhh watts /ft to Stu/hr-ft Q ;e, =0.737 2

Q is the heat generated in the conduit in Q ca '(3 4I443)'("cond) I Ica ).(Rcond) 2ca 2

Btu /hr-ft. 3.41443 is the conversion factor from watts /ft to Btu /hr-ft Q 2ca =0.737 Q otal '* Q ca + 9 ca t

I 2

O total s the total heat generated in the conduit in l

i Btu /hr-ft Q otal " l 473 t

Q caw " ("cond)'(I lea) -(R cond) 0 is the heat generated in the conduit in I

1 caw watt /ft Q eaw =0.216 l

1 4

Q caw (" cond)'(I2ca) -(R cond) 0 2

1 caw is the heat generated in the conduit in i

l Watt /ft

^

Q 2 caw =0.201 Q otalw

• Q leaw

• Q caw O

is the total heat generated in the conduit in t

2 totalw watt /ft Q otalw =0.417 l

t

2) Total Heat Transferred from the Wrapped conduit i

T

= 40 T is the ambient air temperature in C o

am am Conversion of temperature to CR in order to calculate the heat transfer l

Tar =(' Tam + 273) 9 2

5 coefficient in Btu /hr-ft.op T = 563.4 T is the ambient air temperature in degrees Rankine ar ar i

T,,is the surface temperature of the wrapped conduit, this value is iterated TAat 8

until the heat dissipated by Darmatt surface is equal to the heat generated inside the conduit g,

1 CIlc. No.: PI-NSP-95-002 Prga: A29 of A62 Rev.1 Proj. No.: 8960-008 O

Tcr = 90 T is the conductor rated temperature in degrees Celsius er l

tdarmatt = 1.25 tdarmatt s the thickness of the Darmatt layer in inches i

D condout = 3.5 O

i condout s the outside diameter of the conduit in inches Ddarmout = Dcondout + 2 tdarmatt U

i darmout s the outside diameter of the Darmatt l

layer in inches Ddarmout =6 a) Calculation of the Heat Transferred by Convection from the Wrapped Conduit 1

h (t) = 0.27.

(T,w(t) - T,7) #

h is the heat transfer coefficient of the wrapped conduit in c

e darmout 2

l Btu /hr-ft. oF (Ref. XII.D, Table 7-4, Horizental Cylinders)

\\

12 j

(Ddarmout)

A ls the area of the wrapped conduit surface for i hour fire

, g, 12 barrier perlinear ft in ft /ft 2

A

=1.571 w

Q c(t) = h (t) A w (Tsw(t) - T c

ar) O is the heat transferred by convection from the wrappd c

conduit surfece in Btu /hr-ft b) Calculation of the Heat Transferred to the Surroundina by Radiation from the Wrapped Conduit Surface 4

2 4 l

o = 0.171410 Stephan-Boltzman constant in Stu/hr-ft -R i

e

=0.7 Emissivity of the wrapped conduit surface (Darmatt) sy l

Q r(t) = o e A - (Tsw(t))4 - (Tar)4 Or is the heat transferred by radiation to the w w surrounding from the wrapped conduit in Stu/hr-ft i

I i

(

i

. C:lc. No.: PI-NSP-95-002 Page: A30 of A62 Rev.1 Proj. No.: 8960-008 O

c) Total Heat Transferred by Convection and Radiation from the Wrapped Conduit Surface Q cr(t)

• Q c(t) + Q r(t)

Q is the total heat transferred by convection and radiation from the er wrapped conduit surface to the surrounding t = 550 Given j

Q otal"Q cr(t) t Tsurface = Find (t)

T is the surface temperature of the Darmatt layer, this value is surface iterated until the heat dissipated by the Darmatt surface equal to the Tsurface = 564.205 heat generated by the cable inside the conduit h (Tsurface) = 0.304 Q r(T surface) = 1.088 Q c(Tsurface) = 0.385 c

Q cr(Tsurface) " I 473 l

3) Temperature Dron Throuah the Darmatt Laver 2

Kda2mattin := 0.783 Kdermattinis the Darmatt Conductivity in Stu in/hr-ft -QE o

Kdarmatt =

Kdarman is the Darmatt Conductivity in Stu/hr-ft E Kdarmatt =0.065 Ddarmout =6 Ddarmout s the outside diameter of the Darmatt layer in inches i

4 Ddarmin = Dcondout D

is the bside diameter of the Darmatt in inches or the outside dermin diameter of the conduit 4

R""""=(l-.f 1

\\In damout i

Rdarmatt s the thermalresistance of the j

K D

\\25/ \\ dannatti i darmin I Darmattlayerin R-ft/ watts o

Rdarmatt = 1.315 ATdarmatt

• Q otal R darmatt AT i

darmatt s the temperature drop through the Darmatt material t

in degrees Rankine ATdarman " I 937 damanc = [g9j5j T ATdarmatte is the temperature drop through the Darmatt AT damatt materialin OC AT

=1.076 darmatte

4 CIlc No.: PI-NSP-95-002 Prgs: A31 of A62 Rev.1 Proj. No.: 8960-008

4) Temperature Oroo Throuah the Conduit Wall Dconduit = 3.5 Dconduit s the nominal diameter of the conduit in inches i

condout s the outside diameter of the conduit in inches D condout = 3.5 O

i tcond = 0.215 teone is the conduit wall thickness in inches D condin = D condout - 2 tcond D

is the inside diameter of the conduit in inches eengin D condin = 3.07 i

Peond s the thermal resistivity of the conduit materialin p cog = 2.08 oC-cm/ watt

/Dcondouti Rcog = 0.00522 p cog inl R

i cond s the thermal resistance of the conduit in

( condin i oC-ft/ watt,0.00522 is a conversion to ft from cm and Rcond = 0.001 combination of constants {(1/2x)(ift/12in)(0.3937in/cm)}

J ATconduit Q otalw R cond AT i

O conduit s the tempreture drop through the conduit in C t

V AT

= 5.932 10 conduit

5) Calculation of the Temperature drop throuah the Air Space Between the Cable Surface and the Inside Surface of the Conduit A' & B' are constants used to determine the thermal resistance between A, "

the cable surface and the inside surface of the conduit 9

Dcable

• I 49 D

is the diameter of the group of conductors inside the conduitin eable inches determined in section 6 (two cable 2/C #6)

A' R,e is the thermal resistance of the air gap between the cable surface and R

=

3e D cable + B, the inside surface of the conduit in DC-ft/ watt R

=1.905 3e ATair Q otalw R AT is the temperature drop in the air space between the cable surface t

3e air and the inside surface of the conduit in C o

AT,;, = 0.794 O

Csic. No.: PI-NSP-95-002 l.

Page: A32 of A62 Rev.1 l

Proj. No.: 8960-008 i

l l

l

6) Calculation of the TemDerature Drop from the Metal Conductor Surface to the Surface of the Cable l

Pl s the thermal resistivity of the insulation surrounding one of the i

p =500 conductorin C-cm/ watts o

p; = 500 p is the thermal resistivity of the individual and overall Jacket in j

oC-cm/ watts p 3; = 0.5 p3;is the thermal resistivity of the armor in C-cm/ watts o

t is the insulation thickness in inches t; = 045 g

t is the individual Jacket thicknese in inches tj = 0.025 3

t is the overall Jacket thickness in inches t ; = 0.08 aj o

t, > 0.025 t,is the armor thickness in inches d = 0.184 d is the diameter of the conductor metal of one conductor in inches O

d is the diameter over the individual conductor jacket in inches dj = d + 2 t; + 2 t; j

dj =0.324 dj=d+2t; d,is the diameter over the insulation for one conductor in inches d =0.274 i

d j4 = 1.65 d; + 2 t ;

d,is the diameter over the overall jacket in inches for two 3

o 3j conductors d j4 =0.695 3

d ju = d ;4-2 t ;

d is the diameter under the overall Jacket in inches 3

3 o

3ju d ju =0.535 3

d is the cable overall diameter (including the armor) in inches d

=d;4+2t 3

a arm arm d

= 0.745 arm

'l p ;In

)l + p ;In;))'+ p ; In Id (d

(d jel Idarm\\

3 R ; = 0.00522-

+ p 3; In i dj djg g 3jul d

(d j4 j.

3

,(

g R is the thermal resistance from the metal conductor surface to the surface of the l

R ;j = 2.16 g

cable in C-ft/ watts,0.00522 is a conversion to ft from em and combination of o

constants ((1/2x) (1 ft/12in)(0.3937in/cm)}.

Calc. No.: PI-NSP-95-002 Page: A33 of A62 Rev.1 Proj. No.: 8960-008 (G)

AT lea

• 9 eaw R ;)

AT,is the tempreture drop from the curface of the one metal l

ic conductor to the surface of the cable in OC (cable 1CA-1228)

AT Ica =0.466 AT 2ca

• Q caw-R;;

AT is the tempreture drop from the surface of the one metal 2

2ca conduciviic ta surface of the cable in SC (cable 2CA-601)

AT2ca =0.434

7) Conductor Temperature The conductor temperature inside the conduit is equal to the temperature drop through the Darmatt layer, the conduit, the air space between the cable surface and the inside surface of the conduit, and the temperature drop from the metal conductor surface to the surface of the cable plus the Darmatt layer surface temperature AT ltotal = ATdarmatte + ATconduit + ATair + AT Ica ATitotal s the total temperature drop i

from the conductor surface to the surface of the Darmatt AT ltotal = 2.336 is the conductor conductor _lca =

Tsurface-

- 273

+ AT c nductor_1ca T

ltotal temperature :n SC for cable ICA_1228 Tconductor_lca =42.784 AT2 total = ATdarmatte + ATconduit + ATair + AT 2c3 Ahtotal s the totaltemperature drop i

from the conductor surface to the sudace of the Darmatt AT2 total = 2.305 is the conductor Tsurface

- 273 +AT

• • "C' ' 1 ca T conductor _2ca =

2 total temperature in OC for cable 1CA_601 Tconductor_2ca =42.752

Cdc. No.: PI-NSP-95-002 Page: A34 of A62 Rev.1 Proj. No.: 8960-008

(

L PANEL 1EMA AND 2EMA FEEDERS CABLE No.1CA-1228 & 2CA-601 f 2/C - #6) DROP

1) Calculuion of the Heat Generated in the Conduit

@e:EMA_12D.MCD) 1 Ica = 14.5 1,c, is the cable 1CA-1228 current in amps 1 2ca

• I4 1

is the cable 2CA-601 current in amps 2m Rcond = 0.000513 R

is the conductor resistance at 90 oC in ohms /ft m

cond = 2 n

is the number of conductors in conduit n

m 2

ica is me hat generaW W conMn cond' !! ca ).(Rcond)

Q ca = (3 41443)-(n I

i I

Stu/hr-ft,3.41443 is the conversion factor from watts /ft to Btu /hr-ft Q ca = 0.737 I

2 0

is the heat generated in the conduit in Q ca = (3.41443)-(ncond'bl lea )-(Rcond) 2ca I

Stu/hr-ft,3.41443 is the conversion factor from wans/R to BMr-ft Q ca =0.737 2

Q otal ' Q ea ' Q ca t

l 2

i ototal s the total heat generated in the conduit in Btu /hr-ft Q otal"I 473 t

(

9eaw*("cond)'(I lea) IRcond) 0 is the heat generated in the conduit in l

1 caw watt /ft Q c,, = 0.216 i

9 caw * (econd)'(I 2caj Rcond) 0 is the heat generated in the conduit in 2

1 caw watt /f'.

Q caw =0.201 2

9 otalw

• Q eaw ' O caw O

is the total heat generated in the conduit in t

t 2

totaw watt /ft Q otalw =0.417 t

2) Total Heat Transferred from the WraDDed Conduit T

= 40 T is the ambient air temperature in OC am am am + 273) 9 Conversion of temperature to OR in order to calculate the heat transfer Tar =(sT 2

5 coefficient in Btu /hr-ft.op T = 563.4 T is the ambient air temperature in degrees Rankine ar ar T,wis the surface temperature of the wrapped conduit, this value is iterated

.g.

sw until the heat dissipated by Darmatt surface is equal to the heat generated O

'e ide tse ceedvit

Cric. No.: PI-NSP-95-002 l

Page: A35 of A62 Rev.1 Proj. No.: 8960-008 (3

\\

U T

= 90 T is the conductor rated temperature in degre s Oelsius cr er tdarmatt = 1.25 tearman is the thickness of the Dein att layer ;c oches Dcondout = 3.5 D

is the outside diameter of the conduit in inches eem Ddannout = Dcondout + 2 tdarmatt OW s the outside diameter of the Darmatt i

layer in inches Ddarmout = 6 a) Calculation of the Heat Transferred by Convection from the Wranced Conduit h (t) = 0.27. (T,w(t) - T,,) #

h is the heat transfer coefficient of the wrapped conduit in c

e dannout 2

Btu /hr-ft. oF (Ref. Xil.D, Table 7-4, Horizental Cylinders)

(

12

)

P (D dannout)

A,is the area of the wrapped conduit surface for 1 hour1.157407e-5 days <br />2.777778e-4 hours <br />1.653439e-6 weeks <br />3.805e-7 months <br /> fire 12 2

barrier perlinear ftin ft /ft A

=1.571 w

w(Tsw(t) - Tar) ' O is the heat transferred by convection from the wrapped Q c(t) = h (t) A c

c conduit surfece in Btu /hr-ft b) Calculation of the Heat Transferred to the Surroundina by Radiation from the Wrapped Conduit Surface o = 6.17M.10^ 8 Stephan-Boltzman constant in Btu /hr-ft -R4 2

e, = 0.7 Emissivit, af the wrapped conduit surface (Darmatt)

Qr(l)"'Ew'A w(T,wlt))4 - (Tar)

Or is the heat transferred by radiation to the.

~

surrounding from the wrapped conduit in Stu/hr-ft o

i l.

C:Ic. No.: PI-NSP-95-002 l

Page: A36 of A62 Rev.1 3

Proj. No.: 8960-008 4

1

!O l

1 l

c) Total Heat Transferred by Convection and Radiation from the Wrapped Conduit Surface Q ct(t) = Q c(t) + Q,,t)

O is the total heat transferred by convection and radiation from the cr j

wrapped conduit surface to the surrounding t = 550 Given

)

Q total"9 cr(I)

Tsurface = Find (t)

T,g.c. is the surface temperature of the Darmatt layer, this value is l

Iterated until the heat dissipated by the Darmatt surface equal to the Tsurface =564.205 heat generated by the cable inside the conduit i

h (Tsurface) = 0.304 Q r(Tsurface) = 1.088 Q c(Tsurface) = 0.385 c

9 cr(Tsurface)

• I 473 l

3) Temperature Drop Throuah the Darmatt Laver Kdarmattin = 0.783 Kdermattinis the Darmatt Conductivity in Btu in/hr-ft2:2E A

Kdarmattin i

V Kdarmatt '*

K i

darmatt s the Darmatt Conductivity in Stu/hr-ft E j

g Kdarmatt =0.065 Ddarmout =6 Ddarmout s the outside diameter of the Darmatt layer in inches i

Dcable

• l 49 D

is the diameter of the group of conductors inside the conduit in eable l

inches determined in section 6 (two cable 2/C, #6)

Ddarmm = Dcable D

is the inside diameter of the Darmatt in inches or the outsido darmin diameter of the conduit 1II 1

)

ID I

dannout R

l In R

i darmatt s the thermal resistance of the darman = 2 q K

D g dannattj i darmin i l

g gg, Rdarman "3 398 Tdarmatt

• O otal R dannatt AT i

darmatt s the temperature drop through the Darmatt material t

in degrees Rankine t

darmatt =5.005 AT dannaue = [g9) AT

- 5j-aTearmatte is the temperature drop through the Darmatt AT darmatt M h CC i

ATdarmanc = 2.781

l Calc. No.: Pl-NSP-95-002 Page: A37 of A62 Rev.1 Proj. No.: 8960-008 f3 V

i l

4) Calculation of the Temperature Drop from the Metal Conductor Surface to the Surface of l

the Cable l

El s the thermal resistivity of the insulation surrounding one of the i

= 500 conductorin C-cmAvatts o

l l

p = 500 p is the thermal resistivity of the individual and overallJacket in j

j oC-cmAvatts p 3; = 0.5 p3)is the thermal resishvity of the armor in CC-chtts t;,.045 t is the insulation thickness in inches i

t; = 0.025 t) is the individual Jacket thickness in inches t is the overali jacket thickness in inches t j = 0.08 og o

t, ^ = 0.025 t,is the armor thickness in inches d = 0.184 d is the diameter of the conductor metal of one conductor in inches dj i d + 2 tj-2 t d is the diameter over the individual conductor jacket in inches j

I d; = 0.324 i

d;=d+2t; d is the diameter over the insulation for one conductor in inches i

d ; = 0.274 d ;4 = 1.65 dj - 2 t j d

i 39 s the diameter over the overallJacket in inches for two 3

o conductors d ;4 =0.695 3

d 3ju = d ;4 - 2 t ;

d is the diameter under the overall Jacket in inches 3

o 3Ju d ju =0.535 3

~

l C2ic. No.: PI NSP-95-002 Page: A38 of A62 Rev.1 Proj. No.: 8960-008 i

o darm ' d 3jg + 2 t d

is the cable overall diameter (including the armor) in inches c

arrn d

= 0.745 arm

'I

/d Id))

I pIni;\\

d jg) d 3

arm i R;; a 0.00522-

+ p 3j'I" d ;g j ;

> + p ; In

+p;In

(

d/

dg d jul

\\3 3

R is the thermal resistance from the metal conductor surface to the surface of the R ;; = 2.16 g

cable in C-ft/ watts,0.00522 is a conversion to ft from cm and combination of o

constants ((1/2x) (1 ft/12in)(0.3937in/cm)},

AT,is the tempreture drop from the surface of the one metal AT tea

• 9 eaw R;;

l ic conductor to the surface of the cable in C (cable 1CA-1228) o i

AT ic, = 0.466 2ca 9 caw R ;;

AT is the tempreture drop from the surface of the one metal AT 2

2ca conductor to the surface of the cable in*C (cable 2CA-601)

AT2ca =0.434

5) ConductorTemperature The conductor temperature inside the conduit L equal to the temperature drop through the Darmatt layer, the conduit, the air space between the cable surface and the inside surface of the conduit, and s

the temperature drop from the metal conductor surface to the surface of the cable plus the Darmatt layer surface temperature AT ltotal = ATdarmatte + AT je, AT1 total s the twal temperature drop i

from the conductor surface to the surface of the Daman AT igag = 3.247 T

is the conductor T

- 273

+ AT conductor _1ca T conductor _lca =

surface \\9/

temperature in OC for cable 1CA_1228 iggj Tconductor_lca =43.694 AT2 total = ATdarmatte + AT AT2 total s the total temperature drop i

2ca from the conductor surface to the sWace of the Danan AT2 total = 3.215 b me conMor Tsurface

- 273

+ AT

• • "*' ' 1 ca T conductor _2ca =

2 total temperature in CC for cable ICA_601 Tconductor_2ca = 43.663 0

Cric. No.: PI-NSP-95-002 Page: A39 of A62 Rev.1 Proj. No.: 8960-008 1, PANEL 135 FEEDER CABLE No.1K2-18 (1-3/C #2)(Conduit)

(file: 1K2_18C.med)

1) Calculation of the Heat Generated in the Conduit Icond.= 24 l

is the conductor current in amps eond R cond.= 0.000203 R

is the conductor resistance at 90 OC in ohms /ft eone is the number of cables in conduit ncond.= 3 neano Q cond = (3.41443)-(n cond)'(I cond) -(Rcond)

Ocond s the heat generated in the conduit in i

Btu /hr-ft,3.41443 is the conversion factor from watts /ft to Btu /hr-ft Q cond

• l 198 Q condw * (" cond)'(Icond) -(R cond)

O i

cond s the heat genarated !n the conduit in watt /ft Q condw =0.351

2) Total Heat Transferred from the Wranced Conduit l

T

= 40 T,m is the ambient air temperature in OC am O

9 Conversion of temperature to R in order to calculate the heat transfer C

ar h am + 2 2

coefficient in Stu/hr-ft.op T = 563.4 T.,is the ambient air temperature in degrees Rankine ar T,,is the surface temperature of the wrapped conduit, this value is iterated

.g.

8" until the heat dissipated by Darmatt surface is equal to the heat generated inside the conduit Ter =90 T is the conductor rated temperature in degrees Celsius er tdarmatt = 1.25 t

is the thickness of the Darmatt layer in inches darmatt Dcondout = 2.375 O

is the outside diameter of the conduit in inches condout Ddarmout = D condout + 2 t armatt Ddarmout s the outside diameter of the Darmatt i

layer in inches D darmout =4 875

4 CIlc. No.: PI NSP-95 002 Page: A40 of A62 Rev.1 1

Proj. No.: 8960-008 O

l a) Calculation of the Heat Transferred by Convection from the Wrapped Conduit i

h (t) = 0.27-(T,wlt)- Tar) h is the heat transfer coefficient of the wrapped conduit in i

e e

dannout 2

Btu /hr-ft. oF (Ref. Xil.D, Table 7-4, Horizental Cylinders) i 12

/

,, (Ddarmout)

A is the area of the wrapped conduit surface for i hour fire w

12 barrier perlinear ft in ft /ft 2

A =1.276 w

1 c

ar) O is the heat transferred by convection from the wrappd Q c(t) = h (t) A w(T sw(t) - T c

conduit surfece in Btu /hr-ft b) Calculation of the Heat Transferred to the Surroundina by Radiation from the Wranoed Conduit Surface a = 0.171410'8 Stephan-Boltzman constant in Stu/hr-ft -R4 2

e

=0.7 Emisshnty of the wrapped conduit surface (Darmatt) w Q r(I)

• C'Ew'A. (Tsw(t))4 - (Tar)4 Qr is the heat transferred by radiation to the w

surrounding from the wrapped conduit in Btu /hr-ft c) Total Heat Transferred by Conv.ctic,n and Radiation from the Wrapped Conduit Surface Q cr(t) = Q c(t) + Q r(t) -

O,is the total heat transferred by convection and radiation from the c

wrapped conduit surface to its surroundings t=$$0 Given i

Q cond"Q cr(t)

Tsurface = Find (t)

T,m is the surface temperature of the Darmatt layer, this value is iterated until the heat dissipated by the Darmatt surface is equal to the Tsurface = $64.196 heat generated by the cable inside the conduit h (Tsurface) = 0.319 Q r(Tsurface) = 0.873 Q c(Tsurface) = 0.324 c

9 cr(Tsurface) " I 198 x

w

Cric. No.: PI-NSP-95 002 Page: A41 of A62 Rev.1 Proj. No.: 8960-008 e

3) Temperature Drop Throuah the Darmatt Laver Kdannattin = 0.783 K

is the Darmatt Conductivity in. Btu in/hr-ft9E darmattn Kdannattin Kdarmatt

• Kdam.m is the Darmatt Conductivity in Stu/hr-ft9E g

Kdaatt =0.065 D darmout = 4.875 D

i dermout s the outside diameter of the Darmatt layer in inches Ddarmm = Dcondout Ddarmnis the inside diameter of the Darmatt in inches or the outside diameter of the conduit 1

R In R

i oarmatt s me termal reWame Me

"" = \\1 El(Kdannattl (D darmin /

Darmatt layer in OR-ft/ watts Rdannatt = 1.754 ATdannatt

• Q cond Rd2rmatt AT i

darmatt s the temperature drop through the Darmatt material in degrees Rankine ATdarmatt = 2.101 dannanc = [g9j 5

AT T

dermatte is the temperature drop through the Darmalt AT darmatt materialin CC AT dannatte =1.167

4) Temperature Drop Throuah the Conduit Wall Dconduit = 2.083 D

i eondud s the nominal diameter of the conduit in inches Dcondout "2 375 O

i condout s the outside diameter of the conduit in inches tcond = 0.133 t

i eond s the conduit wall thickness in inches Dcondin = Dcondout - 2 tcond D

is the inside diameter of the conduit in inches eondin Dcondin = 2.109 i

Pcond s the thermal resistivity of the conduit materialin p

= 2.08 CC-cm/ watt O%)

Cric. No.: P!-NSP-95-002 Page: A42 of A62 Rev.1 Proj. No.: 8960-008 Rcond = 0.00522 p cond In R

i eond s the thermal resistance of the conduit in e ndin) oC-ftMatt. 0.00522 is a conversion to ft from em and Rcond = 0.001 combination of constants ((1/2x)(ift/12in)(0.3937in/cm)}

ATcondait

• Q condw R cond AT i

eonduit s the tempreture drop through the conduit in OC f

u i

AT

= 4.524 10" conduit

5) Calculation of the Temperature drop throuah the Air Space Between the Cable Surface and fbe inside Surface of the Conduit A' & B' are constants used to determine the thermal resistance between N = 3.2 the cable surface and the inside surface of the conduit B' = 0.19 D cable

• I 339 O

is the diameter of the cable in inches cable O,

A' R

R,e is the thermal resistance of the air gap between the cable surface and

=

3e Dcable ' B, the inside surface of the conduit in CC-ftMatt R = 2.408 3e AT,;, = Q condw R AT,i,is the temperature drop in the air space between the cable surface se and the inside surface of the conduit in OC AT,;, = 0.845

6) Calculation of the Temperature DroD from the Metal Conductor Surface to the Surface of the Cable Pl s the thermai resistivity of the insulation surrounding one of the i

.= $00 conductor in OC-cmMatt 0; = 500 p is the thermal resistivity of the individual and overall Jacket in j

'C-cmMatt p 3; = 0.5 p3j s the thermal resistivity of the armor in CC-cm/ watt i

Cdc. No.: PI-NSP-95-002 Page: A43 of A62 Rev.1 Proj. No.: 8960-008 O-t ; =.045 t, is the insulation thickness in inches tj = 0.025 tj is the individual Jacket thickness in inches t ; = 0.08 i

tq s the overall Jacket thickness in inches o

t, = 0.025 t is the armor thickness a

d := 0.292 d is the diameter of the conductor metal of one conductor in inches l

d; = d + 2 t; + 2 t dj is the diameter over the individual conductor jacket in inches dj = 0.432 d;=d+2t; d is the diameter over the insulation for one conductor in inches i

d ; = 0.382 d ;4 = 2.15 d; + 2 t j d

i 3J4 s the diameter over the overall Jacket in inches 3

o d;4=1.089 3

d ju d j$ - 2 t j d3Ju ls the diameter under the overall Jacket in inches 3

3 o

d ju =0.929 3

V d

=dj4+2t d

is the cable overall diameter (including the armor) in inches 3

a arm aan darm "I I39 l

d;j + p In ;D (d

(d ;4 1

(d I

3 arm R ;j '= 0.00522 p ; In j

+ 3 p; In'

+ 3 p 3; In ; d j& j j

(

s ill 3 3j,ul g 3 R ;; = 3.289 Rg is the therma resistance from the metal conductor surface to the surface of the cable in 'C-ft/ watt,0.00522 is a conersion to feet from centimenters and the combination of constants {(1/2x)(ift/12in)(0.3937 in/cm)}

AT,g, '=

-R ;;

AT is the tempreture drop from the surface of the metal conductor g

c to the surface of the cable in OC ATcable =0.385 O

i I

Cric. No.: PI-NSP-95 002 Page: A44 of A62 Rev.1 Proj. No.: 8960-008

'O

7) ConductorTemperature The conductor temperature inside the conduit is equal to the temperature drop through the Darmatt layer, the conduit, the air space between the cable surface and the inside surface of the conduit, and the temperature drop from the metal conductor surface to the surface of the cable plus the Darmatt layer surface temperature ATtot:1 = ATdannatte + ATconduit + AT,;,- ATcable ATtota,is the total temperature drop from the conductor surface to the surface of the Darmatt ATtotal = 2.397 l$\\

Tconductor '= T i - 273

+ AT T

is the conductor tempreture in DC surface'(9j total conductor Tconductor

• 42 839 i

{

l l

O I

l l

i I

(

I 1

l O

1 Celc. No.: PI-NSP-95-002 Page: A45 of A62 Rev.1 Proj. No.: 8960-008 J. MV 32267-CABLE No.1K2-20 (13/C #10)(Conduit)

(file: 1K2_20C.med)

1) Calculation of the Heat Generated in the Conduit Icond = 3.5 leond s (Ss conductor current in amps i

Rcond = 0.0013 Rcond s the conductor resistance at 90 oC in ohms /ft i

eond s the number of cables in conduit i

cond = 3 n

n f

Q cond = (3.41443).(ncond)'(I cond) -(R cond)

O i

cond s the heat generated in the conduit in l

Stu/hr-ft,3.41443 is the conversion factor from watts /ft to Btu /hr-ft

(

Q cond = 0.163 l

Q condw

• I"cond)'b cond) (R cond)

O is the heat generated in the conduit in cond l

watt /ft 9 condw = 0.048 l

i

2) Total Heat Transferred from the Wracoed Conduit l

Tam = 40 T is the ambient air temperature in C o

am p

Tar =(T

-273)9 Conversion of temperature to CR in order to calculate the heat transfer 2

am 5

coefficient in 5tu/hr-ft.op T = 563.4 T,,is the ambient air temperature in degrees Rankine ar T,wls the surface temperature of the wrapped conduit, this value is iterated T *W = t 5

until the heat dissipated by Darmatt surface is equal to the heat generated inside the conduit l

l T

= 90 T,is the conductor rated temperature in degrees Celsius er c

tdarmatt = 1.25 t

is the thickness of the Darmatt layer in inches darmatt i

i Dcondout = 1.660 D

is the outs' fe diameter of the conduit in inches condout Ddarmout

• Ocondout

• 2 tdarmatt D

is the outside diameter of the Darmatt darmout layer in inches l

D darmout = 4.16 O

i l

l I

Cric. No.: PI-NSP-95-002 P gs: A46 of A62 R:v.1 Proj. No.: 8960-008 l

l O

l U

l j

a) Calculation of the Heat Transferred bv convection from the WraDDed Conduit ar)I ' '

h is the heat transfer coefficient of the wrapped conduit in

' (T3w(t) - T h (O = 0.27-dannoat![

c 1

e 2

Etu/hr-ft.oF (Ref. XII.D, Table 7-4, Horizontal Cylinders) l l

t 12 j

i (D darmout)

A,is the area of the wrapped conduit surface for i hour fire 12 barrier per linear ft in ft /ft

)

2 A = 1.089 w

l Q c(t) = h (t) A w(T3w(t) - T c

er) O is the heat transferred by convection from the wrappd e

conduit surfece in Stu/hr-ft b) Calculation of the Heat Transferred to the Surroundina by Radiation from the Wrapped Conduit Surface 4

2 o := 0.171410 Stephan-Boltzman constant in 8tu/hr-ft.R4 O

e

=0.7 Emissivity of the wrapped conduit surface (Darmatt) w Q g(t) = o E A - (T,(t))4 - (Tar)

Qr is the heat transferred by radiation to the w w 3

surrounding from the wrapped conduit in Stu/hr-ft c) Total Heat Transferred by Convection and Radiation from the Wrapped Conduit Surface Q ct(0 Q c(t) + Q,(t)

Q is the total heat transferred by convection and radiation from the cr wrapped conduit surface to the surrounding t := $50 Given Q cond"Q crit)

Tsurface = Find (t)

T is the surface temperature of the Darmatt layer, this value is surface iterated until the heat dissipated by the Darmatt surface is equal to the Tsurface = 563.54 heat generated by the cable inside the conduit l

h (Tsurface) = 0.215 Q r(T surface) = 0.13 Q c(T surface) =0.033 c

O Q cr(Tsurface) =0.163 V

l

i I

Calc. No.: PI NSP-95 002 Page: A47 of A62 Rev.1 i

Proj No.: 8960-008 l

o l

V i

i i

3) Temperature DroD Throuah the Darmatt laver l

l Kdannattin = 0.783 K

is the Darmatt Conductivity in Stu in/hr-ft2-QE darmattin Kdarmatt =

Kdarmatt s the Darmatt Conductivityin Stu/br-ft E i

l Kdarmatt =0.065 D darmout =4.16 D

i darmout s the outside diameter of the Darmatt layer in inches Ddarmm = Dcondout O

is the inside diameter of the Darmatt in inches or the outside darmn diameter of the conduit l

R

=

In i

Rdarmatt s the thermalresistance of the darmm f (2 0 '(Kdarmatt/

i D Darmattlayer in OR ft/ watts Rdarmatt = 2.241 ATdarmatt Q cond R darmatt ATdarmatt s the temperature drop through the Darmatt material i

in degrees Rankine AT

= 0.366 darmatt dannaue,[g9j5(

damatt AToarmatte is the temperature drop through the Darmatt 3.g.

materialin C o

ATdarmatte = 0.203

4) Temperature Droo Throuah the Conduit Wall Dconduit

• 1.394 D

i eonduit s the nominal diameter of the conduit in inches Dcondout = 1.66 Ocondout s the outside diameter of the conduit in inches i

tcond = 0.133 teone is the conduit wall thickness in inches D condin = D condout - 2 tcond O

is the inside diameter of the conduit in inches condin Dcondin " I 394 Pcond s the thermal resistivity of the conduit materialin p e nd 2 08 OC-cm/ watt

/~T V

I

j Cric. No.: PI-NSP-95-002 P g2: A48 of A62 Rev.1 Proj. No.: 8960-008 O

Rcond = 0.00522 p condin Rcona is the thermal resistance of the conduit in

\\ c ndin /

oC-ft/ watt. 0.00522 is a conversion to ft from em and Rcond = 0 002 combination of constants ((1/2x)(ift/12in)(0.3937in/cm))

F ATconduit

• 9 condw R cond ATeondun is the temperature drop through the conduit in C l

AT

= 9.059 10 conduit

5) Calculation of the Temperature drop throuah the Air Space Between the Cable Surface and the inside Surface of the Conduj(

A' & B' are constants used to determine the thermal resistance between A,i 3.2 the cable surface and the inside surface of the conduit B' := 0.19 D cable = 0.613 D

is the diameter of the cable in inches eable A'

R R,e is the thermal resistance of the air gap between the cable surface and

=

3e Dcable + B, the inside surface of the conduit in CC-ft/ watt R = 3.985 3e AT,9 = Q condw R AT is the temperature drop in the air space between the cable surface 3e air and the inside surface of the conduit in DC j

AT,, = 0.19

6) Calculation of the Temperature Drop from the Metal Conductor Surface to the Surface of the Cable El s the thermal resistivity of the insulation surrounding one of the

= 500 conductors in CC-cm/ watts p

500 p L o..

ermal resistivity of the individual and overall jacket in j

j OC%m/ watts p3;e0.5 p3;is the thermal resistivity of the armor in C-cm/ watt O

CIlc, No.: PI-NSP-95-002 Page: A49 of A62 Rev.1 Proj, No.: 8960-008 t ; =.03 t is the insulation thickness in inches i

tj = 0.015 tj is the individual Jacket thickness in inches t is the overall Jacket thickness in inches t j = 0.06 q

o t = 0.025 t is the armor thickness 3

a d := 0.116 d is the diameter of the conductor metal of one conductor in inches d; = d + 2 tj + 2 t; dj is the diarneter over the individual conductor Jacket in inches dj = 0.206 d ; '= d + 2 t ;

d is the diameter over the insulation for one conductor in inches i

d = 0.176 g

d j4 = 2.15 dj - 2 t j d

i 3J4 s the diameter over the overall Jacket in inches 3

o d j4 =0.563 3

d ju = d ;4 - 2 t j d3Juis the diameter under the overalljacket in inches 3

3 o

d ju =0.443 3

d

=d;4+2t, d

is the cable overall diameter (including the armor) in inches 3

arm arm d

= 0.613 arm

[l

[dI (d

/darm\\

R;; = 0.0052212 p Ini j ' + p ; In j)) + 3 p;In[d ;4'): - 3 0 ;-Inl l

3 3

'di d

d jui

! d ;4 j.

g jg 1 i 3

3 R ;j = 4.876 Rjj is the therma resistance from the metal conductor surface to the surface of the cable in 'C-ft/ watt,0,00522 is a conersion to feet from centimenters and the combination of constants ((1/2x)(ift/12in)(0.3937 in/cm)}

ATcable =

R ;j AT is the tempreture drop from the surface of the metal conductor g

to the surface of the cable in OC ATable =0.078 rb

l i

C*_lc. No.: PI NSP 95 002 Page: A50 of A62 Rev.1 Proj. No.: 8960-008 O

7) conductor Temperature The conductor temperature inside the conduit is equal to the temperature drop through the Darmatt layer, the conduit, the air space between the cable surface and the inside surface of the conduit and the temperature drop from the metal conductor surface to the surface of the cable plus the Darmatt layer surface temperature ATtotal = ATdannatte - ATconduit

• AT,, + ATcable AT i

total s the total temperature drop from the conductor surface to the surface of the Darmatt ATtotal = 0.471 Tconductor = Tsurface-( - 273

+ AT T

is the conductor temperature in C C

total conductor Tconductor== 40.549 O

l l

1 l

1 C Ic. No.: PI-NSP-95-002 Page: A51 of A62 Rev.1 Proj. No.: 8960-008 1O K 12 S1 PUMP FEEDER - CABLE No. 16407-1 (1-3/C #2,5 kV)

(file: 16407-1.med)

1) Calculation of the Heat Generated in the Conduit Icond = 100

!cond is the conductor currentin amps l

Rcond = 0.000203 R

i cond s the conductor resistance at 90 oC in ohms /ft cond - 3

% is the number of cables in conduit n

O cond ~= (3.41443)-(ncond)'(Icond) lR cond)

O i

cond s the heat generated in the conduit in Stu/hr-ft,3.41443 is the conversion factor from watts /ft to Stu/hr-ft Q cond = 20.794 9 condw ' (" cond)'(Icond)(R cond)

Ocond s the heat generated in the conduit in i

watt /ft l

Q condw = 6.09

2) Total Heat Transferred from the Wr=W Conduit t

Tam = 40 T is the ambient air temperature in C o

am U

am + 273,).9 Conversion of temperature to R in order to calculate the heat transfer C

Tar = (sT 2

5 coefficient in Stu/hr-ft.op T = 563.4 T.,is the ambient air temperature in degrees Rankine ar T.,is the surface temperature of the wrapped conduit, this value is iterated Tm (t) = t until the heat dissipated by Darmatt surface is equal to the heat generated inside the conduit Ter -90 T is the conductor rated temperature in degrees Celsius er tdarmatt - 1.25 t

i w t the thickness of the Darmatt layer in inches 1

Dcondout x 4.500 D

is the outside diameter of the conduit in inches condou l

l Ddarmout - Dcondout + 2 tdarman O

is the outside diameter of the Darmatt darmout layer in inches Ddarmout *7 O

C:lc. No.: PI NSP-95-002 Page: A52 of A62 R:v.1 i

Proj. No.: 8960-008 O

l I

a) Calculation of the Heat Transferred by Convection from the Wrapped Conduit h (t) = 0 27 f (T,w(t)- Tar) h is the heat transfer coefficient of the wrapped conduit in e

e darmout 2

I,

Btu /hr-ft. oF (Ref. Xil.D, Table 7-4, Horizental Cylinders)

( g 12 (Ddarmout)

A,is the area of the wrapped conduit surface for i hour fire 12

. barrier per linear ftin ft /ft 2

A

=1.833 w

Q c(t) = h (t) Aw(Tsw(t) - T c

ar) O is the heat transferred by convection from the wrappd c

conduit surfece in Btu /hr-ft l

l b) Calculation of the Heat Transferred to the Surroundina by Radiation from the Wrapped l

Conduit Surface o = 0.171410~ 8 Stephan-Boltzman constant in Stu/hr ft -R4 2

E

=0.7 Emissivity of the wrapped conduit surface (Darmatt) w Q r(t), o E A - (Tsw(t))4 - (Tar)

Or is the heat transferred by radiation to the w w surrounding from the wrapped conduit in 8ttVhr ft c) Total Heat Transferred by Convection and Radiation from the Wrapped Conduit Surface l

Q cr(t) '= Q c(t) + Q,(t)

O, is de total heat transferred by convection and radiation from the c

wrapped conduit surface to its surroundings t = 550 Given Q cond"9 cr(I) l Tsurface ' Find (t)

T is the surface temperature of the Darmatt layer, this value is surface l

iterated untd the heat dissipated by the Darmatt surface is equal to the Tsurface = 571.514 heat generated by the cable inside the conduit h(Tsurface) = 0.521 Q r(Tsurface) = 13.04 Q c(Tsurface) = 7.753 c

O Qcr(Tsurface) = 20.794

i l

l, C::Ic. No.: PI-NSP-95-002 l

Page: A53 of A62 Rev.1 l

Proj. No.: 8960-008 O

v l

3) Temperature Droo Throuah the Darmatt Laver l

Kdannattin - 0.783 K

is the Darmatt Conductivity in Btu inihr-ft _og 2

darmattin Edarmattm k, darmatt '

K i

darmatt s the Darmatt Conductivity in 8ty/hr-ft0E 12 Kdarmatt =0.065 Ddarmout = 7 Ddarmout s the outside diameter of the Darmattlayer in inches i

Ddannin Dcondout D

is the inside diameter of the Darmatt in inches or the outside damun diameter of the conduit dannouh Rdarmatt

• i

' I" Rdarmatt s the thermal resistance of the 2 K)'\\ darmatt( damun Darmattlayerin R-ft/ watts O

Rdarmatt = 1.078

%)

AT darmatt

• Q cond-R darmatt AT i

darmatt s the temperature drop through the Darmatt material in degrees Rankine AT darmatt = 22.41 5\\

AT is the temperature drop through the Darmatt AT darmatte AT U""""" = 9 /

dannan 1

materialin OC AT htte = 12.45

4) Temperature Droo Throuah the Conduit Wall D conduit - 4 00 Deonduit s the nominal diameter of the conduit in inches i

Dcondout =45 D

i condout s the outside diameter of the conduit in inches tcond - 0 225 teone is the conduit wall thickness in inches Dcondin - Dcondout - 2 tcond D

is the inside diameter of the conduit in inches condin Dcondin = 4.05 Peond s the thermal resistnrity of the conduit materialin i

/^\\

U p "" = 2 08 OC-cm/ watt l

l

l Cdc. No.: PI NSP-95-002 Page: AS4 of A62 Rev.1 l

Proj. No.: 8960-008

!O r

l i

.D condouti Rmnd = 0.00522 p cond n R

i i

i eond s the thermal resistance of the conduit in

condm i oC-ft/ watt,0.00522 is a conversion to ft from cm and Rcond =0.001 combination of constants ((1/2x)(ift/12in)(0.3937in/cm)}

ATconduit " Q condw R cond AT i

D eonduit s the tempreture drop through the conduit in C AT conduit = 0.007 l

5) Calculatum of the Temperature dron throuah the Air Swe Between the Cebb Surface and ths;,ty.e Surface of the Conduit A' & B' are constants used to determine the thermal resistance between A' = 3'2 the cable surface and the inside surface of the conduit B' := 0.19 Dcable ' l.84 D,m is the diameter of the cable in inches e

A' R

R,e is the thermal resistance of the air gap between the cable surface and

=

sc Dcable + B, the inside surface of the conduit in CC-ft/ watt R

=1.576 so AT,i, - Q condw R AT is the temperature drop in the air space between the cable surface sc ar and the inside surface of the conduit in CC AT,i, = 9.6

6) Calculation of the Temperature Drop from the Metal Conductor Surface to the Surface of the Cable i

Pi s the thermal resistivity of the insulation surrounding one of the i

p;=500 l

conductor in CC-cm/ watt p - 500 p is the thermal resistivity of the individual and overall Jackot in O

j j

'C-cm/ watt p 3; = 0.5 pz the thermal resistivity of the armor in CC-cm/ watt is

l Calc. No.: PI-NSP-95-002 Pag:: A55 of A62 R:v.1 Proj. No.: 8960-008 O

l l

d - U.296 d is the diameter of the conductor metal of one conductor in inches 8

t;> -

t, is the insulation thickness in inches 5

tj > -

tj is the individual Jacket thickness in inches l

t is the overallJacket thickness in inches q

l l.

1.84 - 2 0.025 - 2.15-(d + 2-(t ; - t;) }

t ; = 0.14 tj=

o o

t,, 0.025 t isthe armorthickness a

dj id + 2 tj + 2 t; dj is the diameter over the individual conductor jacket in inches d j = 0.702 t

dg>d+2t; d is the diameter over the insulation for one conductor in inches i

d ; = 0.546 l

d j4 - 2.15 d; + 2 t j -

d3J4 s the diameter over the overall jacket in inches i

3 o

d j4 = 1.79 3

d ju - d ;4 - 2 t j d3Ju is the diameter under the overalljacket in inches 3

3 o

d ju = 1.51 3

l dann ' d ;4 + 2 t darm is the cable overall diameter (including the armor) in inches 3

a d

= 1.34 a

i l

Id jdj\\\\

Id;g darm')

p;In ; + p; int d /) 3 p;In 3

R j = 0.00522 2,

+ 3 p 3; In i

+

(d/

(

g 3ju/

d ;4))

d 3

i R ;j = 5.843 R j is the therma resistance from the metal conductor surface to the surface of the i

cable in 'C-ft/ watt,0.00522 is a conersion to fee + from centimenters and the combination of constants ((1/2x)(ift/12in)(0.3937 in/cm))

i-Q condw i-ATeable '

R ;j AT is the tempreture drop from the surfece of the metal conductor g

3

\\/

to the surface of the cable in OC ATcable = 11.86I

l.

Czlc. No.: PI NSP-95 002 Page: A56 of A62 Rev.1 Proj. No.: 8960-008 O

7) Conductor Temperature The conductor temperature inside the conduit is equal to the temperature drop througn the Darmatt layer, the conduit, the air space between the cable surface and the inside surface of the condurt, and the temperature drop from the metal conductor surface to the surface of the cable plus the Darmatt layer surface temperature ATtotal ATdarmatte + ATconduit + ATair

• ATcable AT i

total s the totaltemperature drop from the conductor surface to the ATtotal = 33.917 surface of the Darmatt Tconductor =

Tsurface-

- 273

+ AT T

is the conductor tempreture in C D

total conductor T conductor = 78.425 mN.

I t

i 1

r i

I

Calc. No.: PI-NSP 95-002 Page: A57 of A62 Rev.1 Proj No.: 8960 008 6 12 St PUMP FEEDER - CABLE No.154061 f14/C #4/0. 5 kV)

(file: 15406-1.med)

1) Calculation of the Heat Generated in the Conduit Icond = 102 I

is the conductor currentin amps cond Rcond 2 0.0063910 2 R

i eond s the conductor resistance at 90 oC in ohms /ft ncond + 3 n

i cond s the number of cables in Conduit Q cond (3.41443) lncondI(I cond (R cond) O i

cond s the heat generated in the conduit in Stu/hr-ft,3.41443 is the conversion factor from Q

=6.81 watts /ft to Btu /hr-ft Q condw ' I" condh(I cond'Rcond)

O i

cond s the heat generated in the conduit in watt /ft Q condw "I 994 l

2) Total Hest Transferred from the Wracoed Conduit Tam.: 40 T is the ambient air temperature in SC am Tat =(T

- 273,) 9 Conversion of temperature to CR in order to calculate the heat transfer am 2

5 coefficient in Stu/hr-ft.op T, = 563.4 T is the ambient air temperature in degrees Rankine ar is the surface temperature of the wrapped conduit, this value is iterated T3w(t) = t sw until the heat dissipated by Darmatt surface is equal to the heat generated inside the conduit Ter. 90 T is the conductor rated temperature in degrees Celsius er tdarmatt ' l.25 t

is the thickness of the Darmatt layer in inches darmatt Dcondout 3.500 Deondout s the outside diameter of the conduit in inches i

Ddarmout - Dcondout " 2 Ldannatt O

is the outside diameter of the Darmatt darmout layer in inches Ddammut =6 O

l Cric. Ns.: PI-NSP-95-002 I

Pags: A58 of A62 Rav.1 Proj. No.: 8960-008 G

a) Calculation of the Heat Transferred by Convection from the Wrapped Conduit

' (T,wlt) - T P

ari h (t) = 0.27-h is the heat transfer coefficient of the wrapped conduit in c

e

"" "I '

2 Btu /hr-ft. oF (Ref. Xil.D, Table 7-4, Horizental Cylinders) 12 darmout A ls the area of the wrapped conduit surface for 1 hour1.157407e-5 days <br />2.777778e-4 hours <br />1.653439e-6 weeks <br />3.805e-7 months <br /> fire 4

12 2

barrier perlinear ftin ft /ft A

=1.571 w

Q c(t) = h (t) A w (T,(t) - T ar) O is the heat transferred by convection from the wrappd c

3 c

conduit surfece in Btu /hr-ft b) Calculation of the Heat Transferred to the Surroundina by Radiation from the Wr=M Conduit Surface 0 = 0.171410

Stephan-Boltzman constant in Stu/hr-ft -R4 2

E, = 0.7 Emissivity of the wrapped conduit surface (Darmatt) 4

-T'ar)

Or is the heat transferred by radiation to the w w\\ (Tsw(t)1 Q r(t)' o e A surrounding from the wrapped conduit in Btidhr-ft c) Total Heat Transferred by Convection and Radiation from the Wrapped Conduit Surface Qcr(O^*Oc(O+Qr(O Q is the total heat transferred by convection and radiation from the er wrapped conduit surface to its surroundings t = 550 Given Qcond"9cr(O Tsurface - Find (t)

T,e is the surface temperature of the Darmatt layer, this value is iterated until the heat dissipated by the Darmatt surface is equal to the Tsurface = 566.735 heat generated by the cable inside the conduit h (Tsurface) =0.434 Q r(Tswface) = 4 537 Qc(Tsurface) = 2.273 e

mV Q cr(Tsurface) = 6.81

C :lc. N 3.: Pl NSP-95-002 P go: A59 of A62 Rev.1 e

Proj. No.: 8960-008 O

3) Temperature Droo Throuah the Dannatt laver Kdarmattin = 0.783 Kdumat,,is the Darmatt Conductivity in Btu in/hr-ft.SE 2

Edarmattin k.dannatt '

K i

darmott s the Darmatt Conductivity in Stu/br-ft9E 12 Kdarmatt =0.065 Ddarmout =6 Ddwmout s the outside diameter of the Darmatt layer in inches i

D%Dcondout D

is the inside diameter of the Darmatt in inches or the outside darmin diameter of the conduit dannout R

In R

i dermatt s the thermalresistance of the

=

\\2 nf g'K D

darmattl i darnun /

Darmattlayerin CR-ft/ watts Rdarmatt = 1.315 ATdarmatt

• 9 cond R darmatt AT i

darmatt s the temperature drop through the Darmatt material in degrees Rankine AT darmatt = 8.953

= [$j T AT is the temperature drop through the Darmatt AT darmatte dannatt

\\9/

materialin 0C ATdannatte "4 974

4) Temperature Dron Throuah the Conduit Wal[

Dconduit ' 3.00 D

i conduit s the nominal diameter of the conduit in inches Dcondout = 3.5 D

i eondout s the outside diameter of the conduit in inches tcond - 0.205 t

i eond s the conduit wall thickness in inches Dcondin - Dcondout - 2 tcond D

is the inside diameter of the conduit in inches condin Dcondin = 3.09 p

= 2.08 pg is the thermal resistivity of the conduit materialin CC-cm/ watt

Calc. No.: Pl NSP-95-002 P:g2: A60 of A62 Rev.1 Proj. No.: 8960-008 jDcondout)

Rcond - 0 00522 p cond ni 4

R is the thermal resistance of the conduit in

\\Dcondin) cono oC-ft/ watt. 0.00522 is a conversion to ft l' rom em and Rcond = 0.001 combination of constants ((1/23)(ift/12in)(0.3937in/cm))

ATconduit

• 9 condw Rcond AT i

C eonduit s the tempreture drop through the conduit in C AT conduit **3

5) Calculation of the Temperature dron throuah the Air Seece Between the CeW Surface and the inside Surface of the Conduit A' & B' are constants used to determine the thermal resistance between A' = 3'2 the cable surface and the inside surface of the conduit B':= 0.19 O

Dcable - 2.42 D g is the diameter of the cable in inches e

A' R

R,e is the thermal resistance of the air gap between the cable surface and

=

se Dcable + B, the inside surface of the conduit in DC-ft/ watt R

=1.226 se AT,;, - Q condw'R AT is the temperature drop in the air space between the cable surface sc air and the inside surface of the conduit in OC AT,;, = 2.445

6) Calculation of the Temperature Drop from the Metal Conductor Surface to the Surface of the Cable i

p.= 500 Pl s the thermal resistmty of the insulation surrounding one of the conductor in DC-cm/ watt p

p; - 500 p is the thermal resistivity of the individual and overall Jacket in j

d

'C-cm/ watt p3;=0.5 is pz the thermal resistivity of the armor in CC-cm/ watt

Cric. Ns.: PI-NSP-95-002 Pzgs: A61 of A62 Rsv.1 Proj. No.: 8960-008 1

l d = 0 528 d is the diameter of the conductor metal of one conductor in inches 8

tj'-

t, is the insulation thickness in inches 6

tj = -

tj is the indmdual Jacket thickness in inches t is the overall Jacket thickness in inches q

Dcable - 2 0.025 - 2.15-(d + 2-(t ; + t jj }

tj=

t j = 0.147 o

o t, = 0.025 t isthe armorthickness a

dj := d + 2 tj + 2 t dj is the diameter over the individual conductor jacket in inches dj = 0.966 dj:-d+2t; d n the diameter over the insulat.on for one conductor in inches i

d ; = 0.778

'l d ;4 - 2.15 dj + 2 t j d3J4 s the diameter over the overall Jacket in inches i

3 -

o d ;4 =2.37 3

d ju - d j4 - 2 t j djuis the diameter under the overall Jacket in inches 3

3 n

3 d ju =2.076 3

arm ' d ;4 e 2-t, darm is the cable overall diameter (including the armor) in inches i

d 3

d

= 2.42 arm

/

ldarm l Rjj 000522 2 p;in[d;\\

(djV + 3 p).In[d 3ji) + 3 p 3j Inl d j I

• p -In j

3 R ;j = 4.188 R;j is the therma resistance from the metal conductor surface to the surface of the cable in 'C-ft/ watt. 0.00522 is a conersion to feet from centimenters and the combination of constants ((1/2x)(ift/12in)(0.3937 in/cm)}

l 9 condw l

ATcable '

R;;

AT is the tempreture drop from the surface of the metal conductor g

3 to the surface of the cable in OC ATcable = 2.785

Calc. No.: PI NSP-95-002 i

Prge: A62 of A62 Rsv.1 Proj No.: 8960-008

7) ConductorTemperature The conductor temperature inside the conduit is equal to the temperature drop through the Darmatt layer, the conduit, the air space between the cable surface and the inside surface of the conduit, and the temperature drop from the metal conductor surface to the surface of the cable plus the Darmatt layer surface temperature AT 4 ATdarmatte + ATconduit

• AT,, + ATcable AT otal s the totaltemperature drop t

i total from the conductor surface to the surface of the Darmatt ATtoul = 10.206 Tconductor =

Tsurface'

- 273

+ AT toul Twy is the conductor tempreture in C O

i l

Tconductor = 52.059

\\

l l

l l

i l

i O

(.-

l

,,~,

9 W4pLF CREEK NUCLEAR OPERATING CORPORATION Richard A. Muench Vice President Engineering May 30, 1996 ET 96-0035 U.

S. Nuclear Regulatcry Commission ATTN: Document Control Desk Mail Station P1-137 Nashington, D.

C.

20555 i

Reference:

Letter WO 96-0065, dated April 18, 1996, from O.L. Maynard WCNOC, to USNRC

Subject:

Docket No. 50-482:

Correction to Information for Revision to Technical Specification 3/4.8.1, " Electrical PcJer Systems - A.C. Sources" Gentlemen:

This letter transmits a corrected page as requested in telephone conversations between Mr. Jim Stonc, Nuclear Regulatory Commission and Mr. Steve Wideman, Wolf Creek Nuclear Operating Corporation.

Page 2 of 4 of the Attachment to the Reference, " Insert B," was inadvertently transmitted with information from a9 earlier revision relating to adherence to ASTM Standards.

The Attachment a

to this letter corrects the information and replaces page 2 of 4 of the Attachment to the Reference.

[

The conclusions reached in rhe Safety Evaluation, No Significant Hazards Consideration Determination, and Environmental Impact Determination are not affected by these revised pages.

!t you have any questions concerning this matter, please contact me at h

0 16) 364-9831, extension 4034, or Mr. Terry S. Morrill at extension 8707.

i E

Very truly yours, t

Richard A. Muench RAM /j ra

[

Attachment r-cc:

C.

W.

Allen (KDHE), rj a 0500,07 L.

J.

Callan (NPC), wf>

W.

D.

Johnson (NRC), w/a J.

F.

Ringwald (NRC), w/a J.

C.

Stone (NRC), w/a o Box 411/ Burcngton. KS 66839 / Phone:(316) 364 8831

\\

An Equal Opportunny Enyaer M r HC VET

(

i

4 Atttchnunt to ET 96-0035 Page 1 of 1 INSERT "B" DIESEL FUEL OIL TESTING PROGRAM in accordance with Technical Sp*cification 6.8.4, a Diesel Fuel Oil Testing Program to implement required testing of both new fuel oil and stored fue. 9 Pall be established. For the intent of this specification, new fuel oil shall represent diesel fuel oil that has not been added to the Diesel Fuel Oil Storage Tanks. Once oe fuel oil is added to the Diesel Fuel Oil Storage Tanks, the diesel fuel oil is considered stored fuel oil, and sha[ meet the Technical Specification requirements for stored fuel oil.

Tests listed below cre a means of determining whether new fuel oil is of the appropriate grade and has not been coniaminated with substances that would have an immediate detrimental impact on diesel engine combustion. If results from these tests are within acceptable limits, the new fuel oil may be added to the 6.orage tanks without concem for contaminating the entire volume of fuel oilin the storage tanks. Those tests are to be conducted prior to adding the new fuel to the storage tanks, but in no case is the time between receipt of the new fuel oil and conducting the tests to exceed 30 days. The tests, limits, and applicable ASTM standards being used to evaluate the condition of new fuel oil are:

1.

By sampling new fuel oil in accordance with / STM D4057 prior to addition to storage tanks and:

2.

By verifying in accordance with the tests specified in ASTM D975-81 prior to addition to the storage tanks that the sample has:

a)

An API Gravity of within 0.3 degrees at 60 *F or a specific gravity of within 0.0016 at 60/60 *F, when compared to the supplier's certificate or an absolute specific gravity at 60/60 *F or greater than or equal to 0.83 but less than or equal to 0.89 or an API gravity of greater than or equal to 27 degrees but less tm or egni tc 39 degrees; b)

A kinematic viscruity at 40 ~C of greater than or equal to 1.9 centi. stokes, but less than or equal to 4.1 centistolm sf graity was not determined by comparison with the supplier's certification; c)

A flash roir,i equal to or greater than 125 'F; and d)

A watei and sediment content of less than or equal to 0.05% when tested in accordance with ASTM D1796-83.

Failure to meet any of the above limits is cause for rejecting the new fuel oil, but does not represent a failure to meet the Limiting Condition for Operation of Technical Specification 3.8.1.1, since the new fuel oil has not been added to the diesel fuel oil storage tanks.

Within 30 days following the initial new fuel oil sample, the fuel oil is analyzed to establish that the other properties specified in Table 1 of ASTM D975-81 are met, when tested in accordance with ASTM D975-81, except that the analysis for sulfur may be performed in accordance with ASTM D1552-79, ASTM D2622-82, or ASTM D4294-90. An l

exception to ASTM D129, which is specified in ASTM De7 81, has been taken. ASTM D129 uses a Barium precipitation method for the determination of sulfate after ox,astion has occurred. The use of any wet lab sulfate analysis is acceptable since the determination is made in the aqueous rinse water for the oxidation process. In the event the correct fuel oil properties are not met, Action g provides an additional 30 days from the tim? that it is i

l determined that the correct fuel oil properties are not met to meet the Diesel Fuel Oil Testing Program limits. The additional 30 day period is acceptable because the fuel oil properties of interest, even if they are not within limits, would not have an immediate effect on emergency diesel generator operation. The diesel fuel oil surveillance in l

accordance with the Diesel Fuel Oil Testing Program will ensure the availability of high quality diesel fuel oil for the emergency diesel generators.

At least once every 31 days, a sample of fuel oilis obtained from the storage tanks in accor ance with ASTM D227 -

8 The parGculate contamination is verified to be less than 10 mg/ liter when checked based-on I taccordanj;Le I

wit ASTM D2276-83, Method A. The filter size for the determination of particulate contamination will be 3.0 micron instead of 0.8 micron as specified oy ASTM D2276-83. The filtered amount of diesel fuel oil will be approximately or. '

it when possible. Also, it is acceptable to obtain a field sample for subsequent laboratory testing in lieu of field testing.

Fuel oil degradation during long term storage shows up as an increase ir, particulate, due mostly to oxidation. The presence of particulate does not mean the fuel oil will not bum properly in a diesel engine. The particulate can cause fouling of filters and fuel oil injection equipment which can cause engine failure.

The frequency for performing surveillance on stored fuel oil is based on stored fuel oil d3 gradation trends which indicate that particulate concentration is unlikely to change significantly between surveillances.