ML20098G350
| ML20098G350 | |
| Person / Time | |
|---|---|
| Site: | Peach Bottom  |
| Issue date: | 09/28/1984 |
| From: | Daltroff S PECO ENERGY CO., (FORMERLY PHILADELPHIA ELECTRIC |
| To: | Stolz J Office of Nuclear Reactor Regulation |
| References | |
| NUDOCS 8410040421 | |
| Download: ML20098G350 (6) | |
Text
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i PHILADELPHIA ELECTRIC COMPANY 2301 MARKET STREET F).O. BOX 8699 PHILADELPHlA. PA.191o1 5H'y,LS %o^i;Um (2m feii88'mber 28, 1984 ELECTRIC PRODUC'lON Docket Nos. 50-277 50-278 Mr. John F. Stolz Operating Reactors Branch #4 Division of Lic9nsing U.S. Nuclear Regulatory Commission Washington, D.C.
20555 SnBJECT:
Peach Bottom Atomic Power Station, Units 2 and 3, Request for Relief of Operating Restrictions on the Purge and Vent Valves
REFERENCE:
Correspondence dated April 24, 1984, S. L. Daltroff (PECo) to J. F. Stolz (NRC)
Dear Mr. Stolz:
This letcer formally transmits design data for the six and eighteen-inch containment purge and vent valves as requested by 'he NRC staff in a September 5, 1984, telephone conversation.
c The data consists of valve actuator torque output calculations as previously reviewed by the NRC's consultants.
It is our understanding that the data was found to be acceptable to the consultant.
This data relates to our request in the referenced correspondence to increase the maximum cllowable open position on the containment purge and vent valves based on planned improvements to valve components.
Should you have any questions regarding this matter, please do not hesitate to contact us.
O O928 Y YY gg00277 3
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R. Blough, Site Inspector k
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Peach Bottom Atomic Power Station Lhits 2 & 3 Calculations for Actual Actuator Torque Output for 6" & 18" Fisher Continental Division Butterfly Valves, 9200 Type Serial Nos. 136937 thru 136954 Provided by:
Bruce D. Hatton Clifford B. Ives & Co., Inc.
Representative of Fisher Controls International, Inc.
Equation for the actual Actuator Torque Output:
g=M&a 6
B - 1.05 Kt)
T 7 S Actual (Net) Torque Output where T
=
g Moment Ann @ linkage M
=
P
= Max. Alr Pressure a
- . Diaphragrr Area @ desired g g = Initial Diaphragm Area a
Initial Spring Cormression Pressure B
=
g 1.05 : Constant
}
Spring Constant K
=
Spring Travel Distance t
=
i.
r-
'N
( Calculation of Actuator Torque Output for the 6" Fisher Butterfly Valves, 9200 Type, S/N 136953 & 136954 656 Size 40 Net Torque Per Degree of Rotaticn TN =-M (Pa -AO - 1.05 Kt)
Spring IL2173 T S Size 40
- M C30a - 99.7(6) - 1.05 335t) 30 Psi Supply
= M (30a - 598.2 - 351t) 6.26 Bench M, a, t from Table 1 2.02 (30 x 86 - 598.2 - 351 x.33) 10 T
=
N 2.02 (1981.8 - 115.83)
=
= 3769.25 2.25 (30 x 78.5 - 598.2 - 351 x.70) 20 T
=
N 2.25 (1756.8 - 245.7)
=
= 3399.97 I
30 T
=
2.40 (30 x 74.5 - 598.2 - 351 x 1.11)
N 2.40 (1636.8 - 389.61)
=
= 2993.25 2.46 (30 x 72.6 - 553.2 - 351 x 1.53) 40 T
=
N 2.46 (1579.8 - 537.33)
=
2565.21
=
50 T
= 2.45 (30 x 72.3 - 598.2 - 351 x 1.96)
N 2.45 (1570.8 - 687.96)
=
= 2162.95 2.37 (30 x 72.5 - 598.2 - 351 x 2.39) 60 T
=
N 2.37 (1576.8 - 838.89)
=
= 1748.84 2.23 (30 x 72.6 - 598.2 - 351 x 2.79) 70 T
=
N 2.23 (1579.8 - 979.29)
=
= 1339.13 2.02 (30 x 72.2 - 598.2 - 351 x 3.16) 80 T
=
N 2.02 (1567.8 - 1109.16)
=
.= 926.45 1.77 (30 x 70.4 - 598.2 - 351 x 3.49) 90 T
=
N
= 1.77 (1513.8 - 1224.99)
= 511.19 0
T
= 1.72 (30 x 99.7 - 598.2)
N
= 4115.61 J
N
- 2.13 (30 x 72.5 - 598.2 - 351 x 2.98) 75 T
=
- 2.13 (1576.8 - 1045.98)
= 1130.64
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'f.. :.'. Calculation of Actuator Torque Output for the 18" Fisher Butterfly Valves, 9200 Type, S/N -136937 thru 136952 656 Size 60 Net Torque Output Spring 1K1628 TN = M (Pa - AT 3B - 1.05 Kt) 30 psi Supply 6.26 Bench
= M (30a - 214.9C6) - 1.05 (610)t) 2.06 (30 x 214.9 - 214.9(6) - 1.05x 610 x 0) 0 T
=
N 2.06 (5157.6)
=
= 10624.65 0
2.41 (30 x 181.5 - 1289.4 - 640.5 x.39) 10 T
=
N 2.41 (4155.6 - 249.79)
=
9413.0
=
2.67 (30 x 171.2 - 1289.4 - 640.5 x.84) 20 T
=
N 2.67 (3846.6 - 538.02)
=
8833.90
=
30 T
= 2.85 (30 x 165.5 - 1289.4 - 640.5 x 1.32)
N 2.85 (3675.6 - 845.46)
=
8065.89
=
2.93 (30 x 164.5 - 1289.4 - 640.5 x 1.82) 40 T
=
N 2.93 (3645.6 - 1165.71)
=
= 7266.07 o
2.92 (30 x 164.2 - 1289.4 - 640.5 x 2.34) 50 T
=
N 2.92 (3636.6 - 1498.77)
=
= 6242.46 2.83 (30 x 164.5 - 1289.4 - 640.5 x 2.84) 60 T
=
N
= 2.83 (3645.6 - 1819.02)
= 5169.22 2.65 (30 x 164.4 - 1289.4 - 640.5 x 3.32) 70 T
=
N 2.65 (3642.6 - 2126.46)
=
4017.77
=
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