ML18058B898

Temporary Non-Code Repair for Pipe Leak/Wall Thinning Downstream of Cv 0826,SWS,Line HB-23-16.

ML18058B898
Person / Time
Site:	Palisades
Issue date:	07/01/1993
From:	Bill Rogers CONSUMERS ENERGY CO. (FORMERLY CONSUMERS POWER CO.)
To:
Shared Package
ML18058B895	List: ML18058B894 ML18058B896 ML18058B897 ML18058B898
References
EA-SP-03316-05, EA-SP-03316-05-R00, EA-SP-3316-5, EA-SP-3316-5-R, NUDOCS 9307060318
Download: ML18058B898 (25)

Text

ATTACHMENT 2 Consumers Power Company Pali sades Pl ant Docket 50-255 PROPOSED TEMPORARY NON-CODE REPAIRS EA-SP-03316-05, TEMPORARY NON-CODE REPAIR FOR PIPE LEAK/WALL THINNING DOWNSTREAM OF CV-0826, SERVICE WATER SYSTEM, LINE HB-23-16" July 2, 1993 ( 9307060318 930701 0 PDR ADOCK 05000255 II . P . PDR EA-PALISADES NUCLEAR PLANT ENGINEERING ANALYSIS COVER SHEET rotalNumberotsheets "l,(/;) Title No!'.JL -

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&JI /DF2 5.3 Wall thinning approach:

a) Minimum measured thickness tmeas =0.141 b) Predicted pipe thickness in the next 18 month period .-The average wear rate in the pass 20 years of operation based on the max and min measured thickness.

1.l 2S*t nom -t meas rate =-------20 rate =0.014 inch per year -The predicted pipe thickness based on the average wear rate for the next 18 month period 18 tp :=tmeas--*(rate) 12 tp =0.12 tp is greater than 0.3*tnom =0.113 inch, therefore tp meet the requirement 3410 of Code Case N-480. c) Minimum pipe wall thickness required per the Code Case N-480 c.1) Minimum pipewall thickness required for hoop stress. See Section 5.2 (a) of this calculation tmin =0.053 c.2) Minimum thickness required for axial stress to meet the Code stress limits Section modulus for thin wall pipe: (D _ t)2 Z(t) :=n* *t

• PALISADES NUCLEAR PLANT EA-SP-03316-03 -ANALYSIS CONTINUATION SHEET Rev#OO :::;;;--A (o TC> 6 A-SP---O:S.S/(o

-0*5"° ::s/-1 7-or:-Z --.... ____../ As analysed stresses based on the original section modulus (Ref. 7.3) s 11 : = 926 s 12 B =2242 s l 2D : = s 11 + 2. ( s l 2B -s 11) -Minimum thickness required to meet Eq. 11 stress limit Stress as a function oft calculated from the ratio of the original section modulus and the reduced thickness section modulus. z orig s(t) .= s l Z(t) Solve fort with an initial guess t min =root( s(t) -Sall' t) Sall = 15000 t =0.01 t min =0.022 -Minimum thickness required to meet Eq. 128 stress limit. Solve fort Z orig s(t) := s 12Z(t) t min:= root( s(t) -Sall' t) Sall := 18000 t min =0.045 -Minimum thickness required to meet Eq. 120 stress limit. Solve fort Z orig s(t) = s 12D" Z(t) S all . = 36000 t min =0.036 Therefore, the Code minimum pipe thickness is governed by the pressure hoop stress t min.:= 0.053